20 girls and 30 boys
What is arithmetic ?
A branch of mathematics that deals usually with the nonnegative real numbers including sometimes the transfinite cardinals and with the application of the operations of addition, subtraction, multiplication, and division to them
To make the new situation:
Suppose A classroom has 50 people.
The ratio of girls to boys is 2:3, so in other words, we need to find out how many boys and girls there are, and there are 2 girls for every three boys, So ,how many boys and girls are there?
The answer would be :
Let the two parts in which we divide 50 be 2x and 3x respectively
2x+3x=50
5x=50
x= [tex]\frac{50}{5}[/tex]
x=10
Here,
2x= 2×10=20
3x =3*10=30
20 girls and 30 boys.
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After taking 9 tests, Carol’s average grade in her Italian class is 90. Her teacher drops the lowest of the 9 test scores to determine the final grade. If Carol’s final grade is a 91, what was her lowest test score?
If Carol’s final grade is a 91, Carol's lowest test score was 82.
Given;
Average in 9 tests = 90
Average when the lowest score is removed = 91
How to calculate the average?The average or Mean is calculated as thus;
Average = [tex]\dfrac{\sum x}{n}[/tex]
Where the summation of x is the sum of test scores.
n = number of tests
n = 9 - 1 = 8 and average = 91
91 = [tex]\dfrac{\sum x}{8}[/tex]
[tex]\sum x = 91 \times 8\\\\\sum x = 728[/tex]
Thus, Carol's test score in 8 subjects is 728
Let's consider the 9th subject represent the subject Carol had the least score.
n = 9
Average = 90
Average = 728 + the 9th subject
Multiply both sides by 9
90 x 9 = 728 + the 9th subject
810 = 728 + the 9th subject
Subtract 728 from both sides
810 - 728 = 728- 728 + the 9th subject
82 = the 9th subject
Hence, Carol's lowest test score was 82.
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Eduardo’s average speed on his commute to work was 55 miles per hour. On the way home, he hit traffic and only averaged 40 miles per hour. If the round trip took him 1. 25 hours, which expression represents the distance, in miles, for his trip home that is missing from the table?.
40(1.25-t) is missing from the table
Time, speed, and distance are the three factors must be taken into account.
How to solve such time related questions?
The key concept for solving such questions is the relationship between speed, distance and time.
The relationship between them is Distance = Speed X Time
We provide both time and speed.
It is necessary to compute the distance.
55 miles per hour is the commuter speed
Worktime equals 1.25-T
Home-bound speed is 40 miles per hour.
1.25 seconds to get home
Time in Total = T + t = 1.25
Travel distance to home
Distance/Time x Speed
40 = Total Distance/t
Distance overall = 40 (1.25-t)
As a result, 40(1.25-t) is the right response.
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Suppose y varies inversely with x, and y = 25 when x = -15. What inverse variation equation relates x and y ?
a) y=5/x
b) y=-5/x
x) y=-5x
d) y=5x
The inverse variation equation is y = -5/x
What is equation?Equation is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is equal
y varies inversely as x
Let variation constant = k
y = k/x, y = 25 and x = -15
25 = k/(-15), k = -375 divded by 75 ,So k = -5
The inverse variation equation is y = -5/x
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rewrite the expression so that everything is under the same root sign and simplified
please please help :) GIVING BRAINLIEST
Step-by-step explanation:
[tex] \frac{2 {}^{4} }{3 \sqrt{xy} } [/tex]
[tex] \frac{2 { }^{4} }{ \sqrt{9xy} } [/tex]
[tex] \frac{1}{2 {}^{ - 4} \sqrt{9xy} } [/tex]
[tex] \frac{1}{ \frac{ \sqrt{9xy} }{16} } [/tex]
[tex] \frac{1}{ \frac{ \sqrt{9xy} }{ \sqrt{256} } } [/tex]
[tex] \frac{1}{ \sqrt{ \frac{9xy}{256} } } [/tex]
[tex]( \sqrt{ \frac{9xy}{256} } ) {}^{ - 1} [/tex]
The graph could be divided up into three different periods of relatively consistent ticket price change: The years 1980 – 1988, 1989 – 1993 and 1994 – 2011. Can you find a typical rate of change in the price of a ticket for each of these time periods? In other words, on average, by how much did the price of a ticket increase by each year during each of these time periods?
In time period of 1980-1988 the rate of ticket price is $0.2 per year
Between time period 1989-1993 there is constant rate.
Between year 1994-2011 the increase in rate is same $0.2 per year
The graph could be divided up into three different periods of relatively consistent ticket price change: The years 1980 – 1988, 1989 – 1993 and 1994 – 2011.
The statistic is the study of mathematics which deal with relations between comprehensive data.
The graph is not available, in the question, so the graph could be as attached
For period 1980-1988
rate of change = 4.2-2.8/ 8 = 0.2
In time period of 1980-1988 the rate of ticket price is $0.2 per year
for period 1989-92 there is a straight line so,
Between time period 1989-1993 there at constant rate.
For period, 1994-2011
rate of change = 4.4-8/17 = 0.2
Between year 1994-2011 the increase in rate is same $0.2 per year
Thus, for the 3 Time period we have rate of change in ticket price is $0.2 per year, no change in ticket price, $0.2 per year respectively.
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horizontally compress the exponential function f(x)=2^x by a factor of 3
The horizontally compress the exponential function f(x)=2^x by a factor of 3 is f(3x)=2^3x
When we compress a function y=f(x) by a scale factor of 'k', where k >1, then the function after compression will become :
y=f(x), where k>1
We have given the Exponential function.
What is the scale factor?
The scale factor is a measure for similar figures, that look the same but have different scales or measures. Suppose, two circle looks similar but they could have varying radii. The scale factor states the scale by which a figure is bigger or smaller than the original figure.
The scale factor of the compression (k): 5
Then after horizontal compression, the exponential function will become
f(3x)=2^3x
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6
4
2
0
A
2
4
C
6
8
What is the length of A"B"?
10 12
X
Triangle A'B'C' is created by dilating triangle with a scale factor centered at the origin
The length of A"B" is 20 units
How to determine the length of A'B'?From the figure, we have:
A = (1, 4)
B = (4, 8)
The distance AB is:
[tex]AB = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]AB = \sqrt{(1 -4)^2 + (4-8)^2[/tex]
Evaluate
[tex]AB = \sqrt{25[/tex]
This gives
AB = 5
The scale factor of dilation is 4.
So, we have:
A'B' = 5 * 4
Evaluate
A'B' = 20
Hence, the length of A"B" is 20 units
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If f = 36 when a = 9, find f when a = 8
Answer:
2=A
Step-by-step explanation:
We know that F is directly proportional to A then the equation relating them is
F = kA ← k is the constant of proportion
To find k use the condition F = 36 when A = 9, then
36 = 9k ( divide both sides by 9 )
4 = k
F = 4A ← equation of proportion
When F = 8, then
8 = 8A ( divide both sides by 4 )
2 = A
can you help me i dont understand U_U
Answer:
$7.76
Step-by-step explanation:
So you can express the price in the slope-intercept form: y=mx+b where m is the slope, but in this context it's the price per km, and b is the y-intercept, but in this context it's the base price (how much it costs even if the length is 0 km)
So it gives you the slope of $0.22 per km. so you now have the equation
y = 0.22x + b
To find the base amount or y-intercept, you can take some of the given points, the price will be y, and the length will be x.
I'll use the point (6, 4.68)
Plugging these values into the equation you get:
4.68 = 0.22(6) + b
multiply
[tex]4.68 = 1.32 + b[/tex]
subtract 1.32 from both sides
[tex]3.36 = b[/tex]
So now we have the full equation:
y = 0.22x + 3.36
Now to find the price if the length is 20km, simply plug in 20 as x
y = 0.22(20) + 3.36
Multiply
y = 4.4 + 3.36
Add
y=7.76
may someone help me please :)
Answer:
Answer is Similar-AA :D
Reason:
We're given these two angle congruences:
[tex]\angle P \cong \angle S\\\\\angle Q \cong \angle T[/tex]
These are the blue and red angles marked in the diagram below. Since we have two pairs of congruent angles, we can use the AA similarity theorem to prove the triangles are similar.
Similar triangles have the same shape, but are likely different sizes. Triangles with the same shape indicates the corresponding angles are congruent.
The info that PR = 12 and SU = 3 isn't used or needed. Your teacher may have put that in there as a distraction or filler.
Solve for y.
6(y-9)=3y-36
Simplify your answer as much as possible.
y= ?
Answer:
The value of y after the given equation is simplified will be y=6Step-by-step explanation:
Greetings ![tex]6(y -9) = 3y-36...the \: given \: expression \\ 6y - 54 = 3y - 36...apply \: the \: distributive \: law \: a(b - c) = ab - ac \\ 6y - 54 + 54 = 3y - 36 + 54...add \: both \: sides \: 54 \\ 6y = 3y + 18 \\6y - 3y = 3y + 18 - 3y...subtract \: 3y \: from \: both \: sides \\ 3y = 18 \\ \frac{3y}{3} = \frac{18}{3} ...divide \: both \: sides \: by \: 3 \\ y = 6...simplified[/tex]
Can someone pls help me with this problem?
For the first blank, since the output increases by 5 for each increase of 1 for the input, the answer is 13+2(5) = 23.For the second blank, since the output increased by 10 compared to 23, the input increased by 2. So, the answer is 5 + 2 = 7.We know the output is of the form 5x+b for some constant b. If we test input of 1 and an output of 3, we get an input of 1 gives 5+b, which is equal to 3, meaning b=-2. So, the answer is 5x-2.
Triangle PQR is transformed to similar triangle P’Q’R’
What is the scale factor of dilation?
1/2
1/3
1/4
1/5
Scale factor = (image)/(preimage)
[tex]QR=3\\\\Q'R'=1[/tex]
So, the scale factor is 1/3
Which statements about the angles of the triangle are true? check all that apply. a triangle has angles 6, 7, 8. angle 7 has an exterior angle of 1. a diagonal line extends from angle 8 to form angle 2. angle 6 has exterior angle 5. the line extends to form angles 3 and 4. angle 1 is an exterior angle. angle 2 is an exterior angle. angle 4 is an exterior angle. angle 7 is an adjacent interior angle. angle 6 is an adjacent interior angle. it is adjacent to the exterior angle 4. angles 6 and 8 are remote interior angles to the exterior angle 1. angles 6 and 7 are remote interior angles to the exterior angle 2. angles 7 and 8 are remote interior angles to the exterior angle 4.
All the statements are true about the triangle except
1. a diagonal line extends from angle 8 to form angle.
According to the statement
There is a triangle has angles 6, 7, 8 and there are also some statements are given that matched with the triangle.
But the statement
1. a diagonal line extends from angle 8 to form angle.
is not true because it is not possible to extend a diagonal line from angle 8.
So, All the statements are true about the triangle except
1. a diagonal line extends from angle 8 to form angle.
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what is the slope of line 2x-3y=19.
Answer:
[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Given Equation of line: y=mx+c,
where m = slope of line.
So, we will have to make y the subject to find the slope.
[tex]2x-3y=19\\2x-3y-2x=19-2x\\-3y=-2x+19\\y=\frac{-2x+19}{-3} \\y=\frac{2}{3} x-\frac{19}{3}[/tex]
From here, we can see the slope of the line is [tex]\frac{2}{3}[/tex].
Answer: 2/3
Step-by-step explanation:
2x-3y=19
minus 2x from both sides
-3y=-2x+19
divide both sides by -3
y=2/3x-19/3
slope is 2/3
6.
f(a+h)-f(a)
Determine
h
Of(a+h)-f(a)
h
Of(a+h)-f(a)
h
Of(a+h)-f(a)
h
=
for f(x) = x2 + 5x and simplify.
=
2a + h + 5
h
= 2a + 2h+5
2ah + h² - 5a
h
Of(a+h)-f(a) = 2a + h + 5
h
The value of the function operation f(a + h) - f(a) is; h² + 5h + 2ah
How to simplify functions?We are given the function;
f(x) = x² + 5x
We want to find f(a + h) - f(a)
Let us first find f(a + h) to get;
f(a + h) = (a + h)² + 5(a + h)
⇒ a² + 2ah + h² + 5a + 5h
⇒ a² + 5a + h² + 5h + 2ah
Let us now find f(a) to get;
f(a) = a² + 5a
Thus, f(a + h) - f(a) = a² + 5a + h² + 5h + 2ah - a² - 5a
f(a + h) - f(a) = h² + 5h + 2ah
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Goofy's fast food center wishes to estimate the proportion of people in its city that will purchase its products. Suppose the true proportion is 0.07. If 313 are sampled, what is the probability that the sample proportion will be less than 0.04
The probability that the sample proportion will be less than 0.04 is 0.0188 or 1.88%.
The true proportion given to us (p) = 0.07.
The sample size is given to us (n) = 313.
The standard deviation can be calculated as (s) = √[{p(1 - p)}/n] = √[{0.07(1 - 0.07)}/313] = √{0.07*0.93/313} = √0.000207987 = 0.0144217.
The mean (μ) = p = 0.07.
Since np = 12.52 and n(1 - p) = 291.09 are both greater than 5, the sample is normally distributed.
We are asked the probability that the sample proportion will be less than 0.04.
Using normal distribution, this can be shown as:
P(X < 0.04),
= P(Z < {(0.04-0.07)/0.0144217}) {Using the formula Z = (x - μ)/s},
= P(Z < -2.0802)
= 0.0188 or 1.88% {From table}.
Thus, the probability that the sample proportion will be less than 0.04 is 0.0188 or 1.88%.
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The triangles are congruent by the SSS congruence theorem.
Triangles A B C and F E D are shown. Triangle A B C is reflected across A C and then is shifted down and to the left to form triangle F E D.
Which rigid transformation(s) can map TriangleABC onto TriangleFED?
reflection, then dilation
reflection, then translation
rotation, then translation
rotation, then reflection
The rigid transformations that maps ΔABC onto ΔFED by reflection then translation.
The correct option is (B).
What is Reflection?Reflection is a from of transformation whereby a figure is flipped over a line of reflection, making both figures exactly the same shape and size after the transformation.
given:
ΔABC ≅ ΔFED are congruent by the SSS Congruence Theorem.
Hence, the rigid transformations that maps ΔABC onto ΔFED by reflection then translation.
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Answer:
B
Step-by-step explanation:
Trust me bro
76.Real-World Applications
A cell phone company offers two plans for minutes. Plan A: $15 per month and $2 for every 300 texts. Plan B: $25 per month and $0.50 for every 100 texts. How many texts would you need to send per month for plan B to save you money?
Answer:
For plan B to save money cell phone user need to send 6000 texts per month as [tex]$\frac{x}{y}$[/tex] expresses the average texts sent per month by cell phone user and its obtained value is 6000.
Step-by-step explanation:
In the question it is given that a cell phone company offers two plans for minutes.
Plan A: $15 per month and $2 for every 300 texts.
Plan B: $25 per month and $0.50 for every 100 texts.
It is required to find that how many texts would be needed to send per month for plan B to save money. be needed to send per month for plan B to save money.
Step 1 of 6
In Plan A $15 per month and $2 for every 300 texts are costed so the cost of Plan [tex]$\mathrm{A}$[/tex] is given by following equation,
[tex]$A=15 y+\frac{2 x}{300}$[/tex]
In Plan B [tex]$\$ 25$[/tex] per month and [tex]$\$ 0 \cdot 50$[/tex]for every 100 texts are costed so the cost of Plan B is given by following equation,
[tex]$B=25 y+\frac{0 \cdot 50 x}{100}$[/tex]
Step 2 of 6
Now comparing the obtained equations [tex]$A=15 y+\frac{2 x}{300}$[/tex]
and [tex]$B=25 y+\frac{0 \cdot 50 x}{100}$[/tex]
[tex]$15 y+\frac{2 x}{300}=25 y+\frac{0 \cdot 50 x}{100}$[/tex]
Step 3 of 6
Subtract $15 y$ from both the sides of the obtained equation [tex]$15 y+\frac{2 x}{300}=25 y+\frac{0 \cdot 50 x}{100}$[/tex] and simplify using subtraction properties.
[tex]$$\begin{aligned}&15 y+\frac{2 x}{300}-15 y=25 y-15 y+\frac{0.50 x}{100} \\&\frac{2 x}{300}=10 y+\frac{1 x}{200}\end{aligned}$$[/tex]
Step 4 of 6
Subtract [tex]$\frac{x}{200}$[/tex] from both the sides of the obtained equation [tex]$\frac{2 x}{300}=10 y+\frac{1 x}{200}$[/tex] and simplify using subtraction properties.
[tex]$$\begin{aligned}&\frac{2 x}{300}-\frac{x}{200}=10 y+\frac{1 x}{200}-\frac{x}{200} \\&\frac{x}{600}=10 y\end{aligned}$$[/tex]
Step 5 of 6
Multiply both the sides of the obtained equation [tex]$\frac{x}{600}=10 y$[/tex] by 600 and simplify using multiplication properties.
[tex]$$\begin{aligned}&\frac{x}{600} .600=10 y .600 \\&x=6000 y\end{aligned}$$[/tex]
Step 6 of 6
Divide both the sides of the obtained equation x=6000 by y and simplify using division properties. As [tex]\frac{x}{y}[/tex] expresses the average texts sent per month by cell phone user. So, for plan B to save money cell phone user need to send 6000 texts per month.
[tex]$$\begin{aligned}&\frac{x}{y}=\frac{6000 y}{y} \\&\frac{x}{y}=6000\end{aligned}$$[/tex]
Each side of a square is increasing at a rate of 6 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 9 cm2
36 cm²s⁻¹ is the rate at which the area of the square is increasing.
Given each side of the square is increasing at a rate of 6cm/s
Area, A = s², s is the side length
=> [tex]\frac{dA}{dt} =\frac{dA}{ds}* \frac{ds}{dt} =2s*(\frac{ds}{dt} )[/tex] {chain rule of differentiation}
[tex]\frac{ds}{dt}[/tex] = 6 cm/s
When A = 9 cm² => 9 = s²
=> s = √(9) => s = 3 cm
Hence, [tex]\frac{dA}{dt}[/tex] = 2 × 3 × 6 = 36 cm²s⁻¹
Hence, 36 cm²s⁻¹ is the rate at which the area of the square increases
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Complete the number pattern
Answer:
1, 4, 9, 16, 25, 36, 49, (....)
What is the answer to thisss?
The value of x is 14
How to solve for x?From the question, the lines from the center of the circle to the chords have equal measures of 9 units
This line divides a chord into equal segments, where each segment is 7 units
So, we have:
x = 7 + 7
Evaluate
x = 14
Hence, the value of x is 14
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Use the Pythagorean identity
to find sin x.
COS X =
sin x =
8
17
?
Enter
Answer:
[tex]sin\ x = \frac{15}{17}[/tex]
Step-by-step explanation:
So in this case, it's similar to the previous question you asked, except this time you know cosine, and as you may know cosine is defined as: [tex]\frac{adjacent}{hypotenuse}[/tex] and sine is defined as: [tex]\frac{opposite}{hypotenuse}[/tex]. So all we need to solve for is the opposite side, but since we know two sides, we can solve for the other using the Pythagorean identity: [tex]a^2+b^2=c^2[/tex]
Plug in known values:
[tex]8^2 + b^2 = 17^2[/tex]
Simplify:
[tex]64 + b^2 = 289\\b^2 = 225\\b = 15[/tex]
So the opposite side is 15, and the hypotenuse is already given, in this case it's 17 (the denominator of cosine). So plugging this into the definition of sin gives you: [tex]\frac{15}{17}[/tex]
Answer:
[tex] \frac{15}{17} [/tex]
Step-by-step explanation:
[tex] { \sin(x) }^{2} + { \cos(x) }^{2} = 1[/tex]
[tex] \cos(x) = 8 \div 17[/tex]
[tex] \sin(x) = \sqrt{1 - { \cos(x) }^{2} } [/tex]
[tex] \sin(x) = \sqrt{1 - {(8 \div 17)}^{2} } [/tex]
[tex] \sin(x) = 15 \div 17[/tex]
= Homework: Special Right Triangles (8.2)
Find the value of each variable.
30°
46
y
X= and y =
(Simplify your answers. Type exact answers, using radicals as needed.)
I really need help!!!
Answer:
[tex]x=23, y=23\sqrt3[/tex]
Step-by-step explanation:
Since this triangle is half an equilateral triangle, x is half of 46 = 23
Use Pythagoras to solve y.
23^2 + y^2 = 46^2
[tex]y=23\sqrt3[/tex]
Need help with this!
Answer:
488
Step-by-step explanation:
Calculate 20% of their take-home pay
3600 * 0.20 = 720
They already pay 122 and 110 per month
720 - (122 + 110)
720 - 232
488
So the largest monthly car payment they can afford is 488
Solve this simultaneous equation.
[tex]x + y = 5 \\ \frac{1}{x} + \frac{1}{y} = \frac{9}{14} \\ [/tex]
Answer: x∈∅ (there is no decision).
Step-by-step explanation:
[tex]\left \{ {{x+y=5} \atop {\frac{1}{x} +\frac{1}{y}=\frac{9}{14} }} \right.\ \ \ \ \ \left \{ {{x+y=5} \atop {\frac{y+x}{x*y}=\frac{9}{14} \ |*14*x*y\ (x\neq 0;\ y\neq 0) }} \right. \ \ \ \ \left \{ {{x+y=5} \atop {14*(x+y)=9*x*y}} \right. \ \ \ \ \left \{ {{x+y=5} \atop {14*5=9*x*y}} \right.\ \ \ \ \left \{ {{x+y=5} \atop {9*x*y=70}} \right. \\[/tex]
[tex]\left \{ {{y=5-x} \atop {9*x*y=70\ |:9}} \right. \ \ \ \ \left \{ {{y=5-x} \atop {x*(5-x)=\frac{70}{9} }} \right.\ \ \ \ \left \{ {{y=5-x} \atop {5x-x^2=\frac{70}{9} }} \right. \ \ \ \ \left \{ {{y=5-x} \atop {x^2-5x+\frac{70}{9} =0\ |*9}} \right.\ \ \ \ \left \{ {{y=5-x} \atop {9x^2-45x+70=0}} \right.[/tex]
[tex]\left \{ {{y=5-x} \atop {D=-495}} \right. \ \ \ \ \Rightarrow\ \ \ \ x\in\varnothing.[/tex]
Gisela would owe $15,500 in taxes each year if she were not eligible for any tax deductions.
This year, Gisela is eligible for tax deductions that reduce the amount of taxes she owes by
$2,325.00. If these tax deductions reduce the taxes Gisela owes this year by d%, what is the
value of d?
Answer:
15%
Step-by-step explanation:
$2325/$15500
Answer: 15
Step-by-step explanation: It’s given that the deductions reduce the original amount of taxes owed by $2,325.00. Since the deductions reduce the original amount of taxes owed by d%, the equation 2,32515,500=d100 can be used to find this percent decrease , d . Multiplying both sides of this equation by 100 yields 232,50015,500=d, or 15 = d. Thus, the tax deductions reduce the original amount of taxes owed by 15%.
Find the area of the sector. Use π = 3.14.
120°
11 mi
Answer:
Step-by-step explanation:
If your player is Erik, write an inequality that shows all of the ways that Erik will win
if Nita chooses 7. If your player is Nita, write an inequality that shows all of the ways
that Nita will win if Erik chooses 17.
An inequality that shows all of the ways that Nita will win if Erik chooses 17 is
Eric will win if Nita chooses 7 and he chooses and number that is less than 17 (ex. n<17).Nita will win if Eric chooses 17 and she chooses a number less than 8 (ex. n<8).What is an Inequality?This refers to the relation in mathematics that makes an unequal comparison between two numbers or expressions.
Therefore, according to the rules of the game, they would have to make random selections from 0 to 20 and if the difference between their two numbers is less than 10, then Erik wins, the inequality that would show all of the ways that Nita will win if Erik chooses 17 are listed above.
Hence, we can see that the complete question goes thus:
"Erik and Nita are playing a game with numbers. In the game, they each think of a random number from zero to 20. If the difference between their two numbers is less than 10, then Erik wins. If the difference between their two numbers is greater than 10, then Nita wins.
Use what you know about inequalities and absolute values to better understand the game."
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8-2|4-5y|=4
| | stands for absolute value
Answer:
y = (2/5) OR y = (6/5)
Step-by-step explanation:
The first step is isolating the expression within the absolute value bars. The first thing we can do is subtract both sides by 8. If we do that, we get -2|4-5y| = -4. Now, to completely isolate the absolute value, we would have to divide by -2. This yields |4 - 5y| = 2. Finally, we can remove the absolute value bars. However, to do this, we need to first understand what an absolute value bar does to an equation. Lets say that |x| = 2. Absolute value describes the DISTANCE of some quantity from 0 (on the number line). Therefore, x (which is inside the absolute value bars) can be either positive or negative 2 (they are BOTH two units away from 0). Similarly, in this case, (4 - 5y) can either be 2 or -2 (because the absolute value of both is 2). Now we have two possible solutions to solve for:
4 - 5y = 2 OR 4 - 5y = -2
5y = 2 OR 5y = 6
y = (2/5) OR y = (6/5)
If we plug both of these answers back into the equation we can see that they both check out.