A salmon jumps up a waterfall 2.4 m high. With what minimum speed did the salmon leave the water below to reach the top?

Answers

Answer 1

Answer:

6.86 m/s

Explanation:

The minimal velocity needed is when we have only vertical motion, then i will think in the problem only in one axis.

I suppose that the only force, in this case, is the gravitational force acting on the fish.

Then the gravitational equation of the fish will be:

a(t) = -9.8m/s^2

For the velocity equation we need to integrate over time to get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial velocity of the fish and is what we want to find.

For the position equation we need to integrate over time again to get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + v0*t + p0

p0 is the initial position of the fish, and because he starts one the water, the initial position is p0 = 0 m

Then the equation is:

p(t) = (1/2)*(-9.8 m /s^2)*t^2 + v0*t

p(t) = (-4.9 m/s^2)*t^2 + v0*t

We know that the maximum height is 2.4m

The value of time at which the fish gets his maximum height is when the velocity of the fish is equal to zero, then we first need to solve:

v(t) = (-9.8m/s^2)*t + v0 = 0

      t = v0/9.8m/s^2

Now we replace this in the position equation to get the maxmimum height, which is equal to 2.4m

2.4m = p( v0/9.8m/s^2) =  (1/2)*(-9.8 m /s^2)*(v0/9.8m/s^2)^2 + v0*(v0/9.8m/s^2)

2.4m = (1/2)(-v0)^2(-9.8 m /s^2) + v0^2/(9.8m/s^2))

2.4m = (1 - 1/2)*v0^2/(9.8m/s^2)

2.4m = 0.5*v0^2/(9.8m/s^2)

2.4m/0.5 = v0^2/(9.8m/s^2)

4.8m*(9.8m/s^2) = v0^2

√(4.8m*(9.8m/s^2)) = v0 = 6.86 m/s


Related Questions

Your family is moving, and you are asked
to help move some boxes. One box is so
heavy that you must push it across the
room rather than lift it. What are some
ways you could reduce friction to make
moving the box easier?

Answers

Answer:

Explanation:

I would use a hand truck dollies

g Incandescent bulbs generate visible light by heating up a thin metal filament to a very high temperature so that the thermal radiation from the filament becomes visible. One bulb filament has a surface area of 30 mm2 and emits 60 W when operating. If the bulb filament has an emissivity of 0.8, what is the operating temperature of the filament

Answers

Answer:

2577 K

Explanation:

Power radiated , P = σεAT⁴ where σ = Stefan-Boltzmann constant = 5.6704 × 10⁻⁸ W/m²K⁴, ε = emissivity of bulb filament = 0.8, A = surface area of bulb = 30 mm² = 30 × 10⁻⁶ m² and T = operating temperature of filament.

So, T = ⁴√(P/σεA)

Since P = 60 W, we substitute the vales of the variables into T. So,

T = ⁴√(P/σεA)

= ⁴√(60 W/(5.6704 × 10⁻⁸ W/m²K⁴ × 0.8 × 30 × 10⁻⁶ m²)

= ⁴√(60 W/(136.0896 × 10⁻¹⁴ W/K⁴)

= ⁴√(60 W/(13608.96 × 10⁻¹⁶ W/K⁴)

= ⁴√(0.00441 × 10¹⁶K⁴)

= 0.2577 × 10⁴ K

= 2577 K


A school is creating a small parking lot next to the school. They will need
998,140 grams of rock for the parking lot. How many pounds of rock does
the school need? (1 kg = 2.205 lb)

Answers

Answer:

2200.9lb

Explanation:

This is a conversion problem.

 We have been given that:

            Mass of rock the school needed  = 998140g

 

Unknown:

       Pound of rocks the park needed  = ?

To solve this problem, we have to convert from:

     grams to kilograms and then to pounds

            1000g of the rock will weigh 1kg

  So;       998140g of the rock will weight 998.14kg

Therefore:

               1kg of a substance weighs 2.205lb

           998.14g will weight2.205 x 998.14  = 2200.9lb

One component of a metal sculpture consists of a solid cube with an edge of length 24.5 cm . The alloy used to make the cube has a density of 8050 kg/m3 . Find the cube's mass.

Answers

Answer:

118kg

Explanation:

answered

Given

density of the cube= 8050 kg/m3 .

length of the sizes of the cube=24.5 cm

We can convert the length to cm for unit consistency.

It's length =24.5 cm =0.245m

✓ the length of sizes of the cube is the same, then the volume can be calculated as

Volume= L^3

= (0.245m)^3

=0.01470625 m^3

✓ but we know that

Density = mass/ volume

Then,

Mass= (Volume × density)

= (0.01470625)(8050)

= 118 kg

Hence, the mass of the cube is 118 kg

If there is "waste" energy, does the Law of Conservation of Energy still apply? please don't type something random if so i'll just report it.​

Answers

Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

If we take into account these waste energy, we can see that energy is indeed conserved. The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.

Pete applies a 10.9-Newton force to a 1.32-kg mug of root beer in order to accelerate it from rest over a distance of 1.25-m? How much work does Pete do on the mug of root beer?

Answers

Answer: 4 J

explanation:

A. J is the answer hope it helped

Why does it rain more in West Ferris than in East Ferris? Explain your answer.

Answers

Answer:

This idea helps students explain why more rain forms over West Ferris than East Ferris. ... Therefore, when students explain that water vapor condenses higher in the atmosphere, they are actually explaining that water vapor condenses high in the troposphere, which is relatively low in the atmosphere.

Explanation:

Plz mark me brainliest thank u> have a good day

An unmarked police car traveling a constant 38.6 m/s is passed by a speeder traveling 53.4 m/s. Precisely 2.2 seconds after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is a constant 1.6 m/s2, how much time passes before the police car overtakes the speeder after the speeder passes (assumed moving at constant speed).

Answers

Answer:

The unmarked police car needs approximately 71.082 seconds to overtake the speeder.

Explanation:

Let suppose that speeder travels at constant velocity, whereas the unmarked police car accelerates at constant rate. In this case, we need to determine the instant when the police car overtakes the speeder. First, we construct a system of equations:

Unmarked police car

[tex]s = s_{o}+v_{o,P}\cdot (t-t') + \frac{1}{2}\cdot a\cdot (t-t')^{2}[/tex] (1)

Speeder

[tex]s = s_{o} + v_{o,S}\cdot t[/tex] (2)

Where:

[tex]s_{o}[/tex] - Initial position, measured in meters.

[tex]s[/tex] - Final position, measured in meters.

[tex]v_{o,P}[/tex], [tex]v_{o,S}[/tex] - Initial velocities of the unmarked police car and the speeder, measured in meters per second.

[tex]a[/tex] - Acceleration of the unmarked police car, measured in meters per square second.

[tex]t[/tex] - Time, measured in seconds.

[tex]t'[/tex] - Initial instant for the unmarked police car, measured in seconds.

By equalizing (1) and (2), we expand and simplify the resulting expression:

[tex]v_{o,P}\cdot (t-t')+\frac{1}{2}\cdot a\cdot (t-t')^{2} = v_{o,S}\cdot t[/tex]

[tex]v_{o,P}\cdot t -v_{o,P}\cdot t' +\frac{1}{2}\cdot a\cdot t^{2}-a\cdot t'\cdot t+\frac{1}{2}\cdot a\cdot t'^{2} = v_{o,S}\cdot t[/tex]

[tex]\frac{1}{2}\cdot a\cdot t^{2}+[(v_{o,P}-v_{o,S})-a\cdot t']\cdot t -\left(v_{o,P}\cdot t'-\frac{1}{2}\cdot a\cdot t'^{2}\right) = 0[/tex]

If we know that [tex]a = 1.6\,\frac{m}{s^{2}}[/tex], [tex]v_{o,P} = 0\,\frac{m}{s}[/tex], [tex]v_{o,S} = 53.4\,\frac{m}{s}[/tex] and [tex]t' = 2.2\,s[/tex], then we solve the resulting second order polynomial:

[tex]0.8\cdot t^{2}-56.92\cdot t +3.872 = 0[/tex] (3)

[tex]t_{1} \approx 71.082\,s[/tex], [tex]t_{2}\approx 0.068[/tex]

Please notice that second root is due to error margin for approximations in coefficients. The required solution is the first root.

The unmarked police car needs approximately 71.082 seconds to overtake the speeder.

A 46.8-g golf ball is driven from the tee with an initial speed of 58.8 m/s and rises to a height of 24.7 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.11 m below its highest point?

Answers

Answer:

a) the kinetic energy of the ball at its highest point is 69.58 J

b) its speed when it is 8.11 m below its highest point is 55.97 m/s

Explanation:

Given that;

mass of golf ball m = 46.8 g = 0.0468 kg

initial speed of the ball v₁ = 58.8 m/s

height h = 24.7 m

acceleration due to gravity = 9.8 m/s²

the kinetic energy of the ball at its highest point = ?

from the conservation of energy;

Kinetic energy at the highest point will be;

K.Ei + P.Ei = KEf + PEf

now the Initial potential energy of the ball P.Ei = 0 J

so

1/2mv² + 0 J = KEf + mgh

K.Ef = 1/2mv² - mgh

we substitute

K.Ef = [1/2 × 0.0468 × (58.8 )²] - [0.0468 × 9.8 × 24.7]

K.Ef  = 80.904 - 11.3284

K.Ef = 69.58 J

Therefore, the kinetic energy of the ball at its highest point is 69.58 J

b) when the ball is 8.11 m below the highest point, speed = ?

so our raw height h' will be ( 24.7 m - 8.11 m) = 16.59 m

so our velocity will be v₂

also using the principle of energy conservation;

K.Ei + P.Ei = KEh + PEh

1/2mv² + 0 J = 1/2mv₂² + mgh'

1/2mv₂² = 1/2mv² - mgh'

multiply through by 2/m

v₂² = v² - 2gh'

v₂ = √( v² - 2gh' )

we substitute

v₂ = √( (58.8)² - 2×9.8×16.59 )

v₂ = √( 3457.44 - 325.164 )  

v₂ = √( 3132.276 )

v₂ = 55.97 m/s

Therefore, its speed when it is 8.11 m below its highest point is 55.97 m/s

What is a work out time setting? (Gym)

Answers

Answer:

It determines how long you do a certain workout.

How do you calculate area when pressure and force are given to you

Answers

Answer:

This is my answer

Explanation:

First convert 150 kPa to Pa:

150 × 1,000 = 150,000.

Next substitute the values into the equation:

force normal to a surface area = pressure × area of that surface.

force = 150,000 × 180.

force = 27,000,000 N.

1.First convert 150kPato Pa:

2.150 x 1,000 + 150,000

3.next substitute the values into the equations:

4.force normal to a surface area =pressure x area of that surface.

5.force=150,000 x 180.

6.force = 27,000,000N.

can i have brainliest please

You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 92.2 kg hop on board for a ride through the woods and the springs (one for each wheel) each compress by 5.97 cm. When you pull the trailer over a tree root in the trail, it oscillates with a period of 1.14 s. Determine the force constant of the springs in N/m.

Answers

Answer:

 k = 1400.4 N / m

Explanation:

When the springs are oscillating a simple harmonic motion is created where the angular velocity is

          w² = k / m

          w = [tex]\sqrt{ \frac{k}{m} }[/tex]

where angular velocity, frequency and period are related

          w = 2π f = 2π / T

           

we substitute

          2π / T = \sqrt{ \frac{k}{m} }

         T² = 4π² [tex]\frac{m}{k}[/tex]

          k =  π²  [tex]\frac{m}{T^{2} }[/tex]

in this case the period is T = 1.14s, the combined mass of the children is

m = 92.2 kg and the constant of the two springs is

          k = 4π² 92.2 / 1.14²

          k = 2800.8 N / m

to find the constant of each spring let's use the equilibrium condition

          F₁ + F₂ - W = 0

           k x + k x = W

indicate that the compression of the two springs is the same, so we could replace these subtraction by another with an equivalent cosecant

           (k + k) x = W

            2k x = W

            k_eq = 2k

            k = k_eq / 2

            k = 2800.8 / 2

            k = 1400.4 N / m

ts
An electric light bulb mixer is used for 19.2 seconds. In that time, it transfers 1
536 J of energy.
Calculate the power output of the cake mixer.
A
I DONT KNOW​

Answers

And electric light bulb mix it is used for nine. Two seconds in that temperature transfers one 536 J of energy calculate shin is 2+2 is 4-1 that’s three quick maths exclamation is calculate the power work output of the kitchen

Two point charges, A and B, are separated by a distance of 19.0 cm . The magnitude of the charge on A is twice that of the charge on B. If each charge exerts a force of magnitude 45.0 N on the other, find the magnitudes of the charges.

Answers

Answer:

QA = 19μC

QB = 9.5 μC

Explanation:

The force that each charge exerts on the other must obey Coulomb's Law, as follows:

       [tex]F_{AB} = \frac{k*Q_{A} * Q_{B}}{r_{AB}^{2}} (1)[/tex]

We know that the value of the magnitude of FAB  is 45.0 N, the distance between QA and  QB is 0.19 m, and that QA = 2*QB.Replacing in (1), we can solve for QB, as follows:

      [tex]Q_{B} = \sqrt{\frac{F_{AB}*r_{AB} ^{2}}{2*k} } = \sqrt{\frac{45.0N*(0.19m) ^{2}}{2*9e9N*m2/C2} } = 9.5e-6 C (2)[/tex]

Since QA = 2*QB⇒ QA = 2* 9.5μC = 19.0 μC⇒ QB = 9.5μC

On the periodic table , the vertical columns that extend down the periodic table are called ?

Answers

Answer:

groups

Explanation:

Answer: Groups

Explanation: They are in the same group! Like the Alkaline Metals are all the group. They all lose an electron. :)

Choose all the answers that apply.

Which of the following will cause an increase in the acceleration of an object?

increase force
decrease force
increase mass
decrease mass

Whats the answer!?

Answers

Increase force decrease mass

A mass m is gently placed on the end of a freely hanging spring. The mass then falls 33 cm before it stops and begins to rise. What is the frequency of the oscillation

Answers

Answer:

Explanation:

The mass falls by .33 m before it begins to rise . At that point loss of potential energy is equal to gain of elastic energy .

1/2 k x² = mgx

.5 x k x .33² = m x 9.8 x .33

k / m = 59.4

frequency of oscillation =  [tex]\frac{1}{2\pi} \times\sqrt{\frac{k}{m} }[/tex]

= [tex]\frac{1}{2\pi} \times\sqrt{59.4}[/tex]

= 1.22 per second .

A car has a mass of 1500 kg. If the driver applies the brakes while on a gravel road, the maximum friction force that the tires can provide without skidding is about 7000 N. how long are the skid marks

Answers

Explanation:

Given data:

mass of the car = 1500 kg

maximum friction force = 7000 N

initial velocity v_i = 20 m/s ( it is not given in the question just an assumption)

final velocity v_f = 0 m/s

[tex]\begin{array}{l}

\sum F_{y}=M g-F_{n}=0 \\

\sum F_{x}=-F_{s}=m a_{x} \\

-F_{s}=m a_{x}

\end{array}[/tex]  

[tex]a_{x}=\frac{-F_{s}}{m}=\frac{-7000}{1500}[/tex]

[tex]a_{x}=-4.7 \mathrm{~m} / \mathrm{s}^{2}[/tex]

Now we can find the distance from this formula:

[tex]v_{f x}^{2}=v_{i x}^{2}+2 a_{x}(\Delta x)[/tex]

[tex]0=20^{2}+(2 \times-4.7 \times \Delta x)[/tex]

[tex]20^{2}=9.4 \Delta x[/tex]

[tex]\Delta x=\frac{20^{2}}{9.4}=42.55 \mathrm{~m}[/tex]

So, the shortest distance in which the car can stop safely without kidding

=42.55 m

True or False. The larger a waves wavelength, the more energy it carries. (1 Point) True O False O Maybe​

Answers

Explanation:

False, it is oppisite the shorter the wavelength the more energy it carries.

plzzzzzzzzzzzzz help SERIOUSLY ​

Answers

i think the answer is 1 .. probably because at this point the body has only potential energy while the rest positions do possess kinetic energy as well . so 1 would surely be correct

Billiard ball A (0.35 kg) is struck such that it moves at 10 m/s toward a

second identical ball (Ball B). After the collision Ball A continues to move

in the same direction at 2 m/s. What is the magnitude of the velocity for

Ball B after the collision?

Before Collision:

10 m/s

A

After Collision:

2 m/s

O

Answers

Answer:

6m/s

Explanation:

Using the law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the momentum after collision.

Using the expression

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity after collision

Substitute the given values in the formula

0.35(10)+0.35(2) = (0.35+0.35)v

3.5+0.7 = 0.7v

4.2 = 0.7v

v = 4.2/0.7

v = 6m/s

Hence the magnitude of the velocity for Ball B after the collision is 6m/s

Energy can be transferred from one place to another through?

Answers

Energy can be transferred from one place to another through light, sound, and heat.

What type of energy is stored in a battery?
pls give all the possible answer and pls if you can give an explanation

thx I'm really stuck​

Answers

Answer:

Batteries use chemistry, in the form of chemical potential, to store energy, just like many other everyday energy sources. For example, logs store energy in their chemical bonds until burning converts the energy to heat.

Explanation:

Electrical energy I’m leaning about this in class right now and I’m really good at it I have a 100 but if I get it wrong I’m sorry but I think it’s electrical energy it has to be

The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12. How many grains are there in the ball

Answers

Given :

The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12.

To Find :

How many grains are there in the ball?

Solution :

Volume of ball of the ballpoint is :

[tex]V = \dfrac{4 \pi r^3}{3}\\\\V = \dfrac{4\times 3.14 \times 0.5^3}{3}\ mm^3\\\\V = 0.523\ mm^3[/tex]

Now, grain size of 12 has about 520000 grains/mm³.

Therefore, number of grains are :

[tex]n = 520000\times 0.523\ grains\\\\n = 271960\ grains[/tex]

It has been argued that power plants should make use of off-peak hours (such as late at night) to generate mechanical energy and store it until it is needed during peak load times, such as the middle of the day. One suggestion has been to store the energy in large flywheels spinning on nearly frictionless ball-bearings. Consider a flywheel made of iron, with a density of 7800 kg/m^3 , in the shape of a uniform disk with a thickness of 11.3 cm.

Required:
a. What would the diameter of such a disk need to be if it is to store an amount of kinetic energy of 14.1 MJ when spinning at an angular velocity of 93.0 rpm about an axis perpendicular to the disk at its center?
b. What would be the centripetal acceleration of a point on its rim when spinning at this rate?

Answers

Answer:

Explanation:

kinetic energy = 14.1 MJ = 14.1 x 10⁶ J

Let radius of flywheel be r .

volume of flywheel = π r² x t where t is thickness

= 3.14 x r² x .113 m³

= .04 r² m³

mass = volume x density

= .04 r² x 7800 = 312.73 r²kg

moment of inertia I = 1 / 2 mass x radius²

= .5 x 312.73 r² x r²

= 156.37 r⁴ kg m²

angular velocity ω = 2π x 93/60

= 9.734 rad /s

kinetic energy = 1/2 Iω² where ω is angular velocity

= .5 x 156.37 r⁴ x 9.734²

= 7408.08 r⁴

Given

7408.08 r⁴ =  14.1 x 10⁶

r⁴ = .19 x 10⁴

r = .66 x 10

= 6.60 m .

Diameter = 13.2 m

b )

centripetal acceleration of a point on its rim = ω² r

= 9.734² x 6.6

= 625.35 m /s²



In the study of personality, the

model includes different traits that are believed to underlie each individual's basic tendencies.

Answers

Answer:

Five-Factor

Explanation:

The Five-Factor model is a trait model of personality that includes different traits that are believed to underlie each individual's basic tendencies.

These different traits are:

1. Openness

2. Conscientiousness

3. Extraversion

4. Agreeable Ness

5. Neuroticism.

It is often shortened and referred to as OCEAN or CANOE.

It is a majorly acknowledged personality theory among scientists.

Hence, in the study of personality, the FIVE FACTOR model includes different traits that are believed to underlie each individual's basic tendencies.

A spring has a constant of 100 N/m. What Force does the spring exert on you if you stretch it a distance of 0.5 m?

Answers

Answer:

F = - K x        force is opposed to direction of extension

F = -100 N / m * .5 m = -50 N

A ball of mass m makes a head-on elastic collision with a second ball (at rest) and rebounds in the opposite direction with a speed equal to one-fourth its original speed. what is the mass of the second ball?

Answers

See image for the answer.

When a ball of mass m makes a head-on elastic collision with a second ball (at rest) and rebounds in the opposite direction with a speed equal to one-fourth its original speed, then mass of the second ball having v/3 is velocity after collision is 9m/4.

What is momentum ?

Momentum is defined as mass times velocity of body. it is denoted by p and its SI unit is Kg.m/s. It has both magnitude and direction. it is a vector quantity.  it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum. its dimensions is [M¹ L¹ T⁻¹]. Momentum is conserved throughout the motion.

initial momentum = final momentum

Given,

mass of first body m₁ = m

initial velocity of first body = v₁' = v

final velocity of first body = v₁'' =v/4

mass of second body m₂ = ?

initial velocity of second body = v₂' = 0

final velocity of second body = v₂'' = v/3

According to conservation of momentum,

initial momentum = final momentum

m₁v₁' + m₂v₂' = m₁v₁'' + m₂v₂''

putting al above values

m₁v + 0 = m₁v/4 + m₂v/3

m₁v - m₁v/4 = m₂v/3

m (1 - 1/4)v = m₂v/3

3m/4 = m₂/3

m₂ = 9m/4

Hence mass of the second body is 9m/4.

To know more about momentum, click :

https://brainly.com/question/30677308

#SPJ3

This cat is A tired B lazy or C Dreaming

Answers

i think it’s all hahaha , but thanks for the points

the answer is obviously c because cats cant have nightmares

Name and explain the
various types of friction.

Answers

Answer:

There are four types of friction: static, sliding, rolling, and fluid friction. Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest. Fluid friction occurs in fluids, which are liquids or gases.

Explanation:

Other Questions
The truest expression of a people is in its dance and its music. Bodies never lie. - Agnes de Mille. What does she mean by this? Between about 500 and 1000, West African people moved southward and eastward in the ------- ------ In Wonder, August has no idea what a science elective is. What does this detail tell readers about his future at Beecher Prep?1. He will have trouble at the school.2. He will win a science award.3. He will lose interest in science.4. He will learn a lot of new things. A museum sets up a display of fluorescent minerals. Which best describes how electromagnetic waves can be used to enhance the display?Infrared light shining on the minerals will cause them to give off visible light.Visible light shining on the minerals will cause them to give off infrared light.Ultraviolet light shining on the minerals will cause them to give off visible light.Visible light shining on the minerals will cause them to give off ultraviolet light. How did a direct democracy operate in ancient Greece?A. All citizens voted for representatives who directed the government.B. A few citizens voted for representatives who directed the government.C. All citizens voted on all issues facing the community.D. A few citizens voted on all issues facing the community.I will give BRAINLIEST IF CORRECT IF NOT CORRECT YOU DON'T GET BRAINLIEST help on latest question? it's worth 100 pts and pretty easy im just lazy :) its also a math question :) a school has sixth-grade students that are going on a field trip at the end of the school year. the students will be divided into five groups, each group riding on a different bus. there are a total number of 242 students going on the field trip. write and solve an equation to determine s, the number of students that will ride on both bus #4.buses number of studentsbus 1 62bus 2 64bus 3 55bus 4 s You are driving in stop-and-go traffic during the daytime, and someone in another vehicle tells you that yourbrake lights are not working. You should look for a service station, do all your braking very gently, andWave a red cloth or flag inside your vehicle, near your rearview mirror, whenever you apply your brakes.Turn on your park lights whenever you apply your brakes.Drive with your window open and use your hand signal when you slow down or stop. Im struggling please help me Corbel Corporation has two divisions: Division A and Division B. Last month, the company reported a contribution margin of $40,200 for Division A. Division B had a contribution margin ratio of 35% and its sales were $263,000. Net operating income for the company was $33,000 and traceable fixed expenses were $51,100. Corbel Corporation's common fixed expenses were:_______. PLEASE HELP!!! I"M WRITING AN EXAM!! STEP BY STEP PLEASSE!what is the inverse of f (x) = (x+1)^2+4 1. A dice game costs $2 to play. If an odd number is rolled, the player receives $3. If an even numberis rolled, the player receives $1.Determine whether the game is fair. Write the first 3 terms for the given formulaf(n) = 2n + 10 for starting with n = 1 "This virtual learning is for the birds. I ain't going to do any of the work." This is a...? What does it mean to forgive? Are there limits to forgiveness? Explain.5 sentences is the minimum. BRANLIEST WILL BE GIVEN! Error Analysis identify the first step that contains an error.Solve: -38 = 4x -2(x + 5)Step 1: -38 = 4x - 2x -10Step 2: -38 = 2x - 10Step 3: -48 = 2xStep 4: -24 = x Boyd Docker engaged in the following activities in establishing his photography studio, SnapShot!: 1. Opened a bank account in the name of SnapShot! and deposited $8,290 of his own money into this account in exchange for common stock. 2. Purchased photography supplies at a total cost of $980. The business paid $390 in cash, and the balance is on account. 3. Obtained estimates on the cost of photography equipment from three different manufacturers. In what form (type of record) should Joel record these three activities?Prepare the entries to record the transactions. How many moles of phosphoric acid would be needed to produce 15 grams of water? (GIVING BRAINLIEST!!)What is formed during the condensation part of the water cycle?A) Water vapor and steamB) Water droplets and cloudsC) Rain and cloudsD) Sleet and rainExplain why. A chemist has a block of copper metal (density is 8.96). They drop the metal into a graduated cylinder containing water, and find the volume change is 2.90 mL. What is the mass of the block , in grams?