A place kicker in pro football has a 77% probability of making a field goal over 40 yards, and each attempted field goal is independent. If the kicker made his first two but missed his third attempt and is now trying for his fourth field goal of the game to win in overtime, what is the probability that his team will win the game

1. R= {(2, 2), (3, 5), (4, 10), (4, 17)}

2. Domain = {1, 2, 3, 4}

3.  Range = {2, 3, 4, 5, 10, 17}

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

Given:

R = { ( 1 + x , 1 + x^2 ) ∶ x≤ 4, ∈ }

1) R= {(2, 2), (3, 5), (4, 10), (4, 17)}

2) Domain = {1, 2, 3, 4}

3) Range = {2, 3, 4, 5, 10, 17}

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Answer:

a. What is the measure of ∠CAT?   Answer:  70°

b. What is the measure of ∠BAR?  Answer:  50°

c. What is the measure of ∠RAT?  Answer:   110°

d. What is the measure of ∠CAB? Answer:   130°

e. What is the measure of ∠BAT? Answer:    60°

Step-by-step explanation:

I just looked at the degrees of the protractor.

Hope this helps!

If not, I am sorry.

Answer:

Step-by-step explanation:

ye answer's here  

Answer:

Y intercept: (0,2) Slope: 1/3

Step-by-step explanation:

X is horizontal. Y is vertical the slope touches at (0,2).

The slope goes up by one and right by three cause it connects to the line

for the second one all you would have to do is increase the slope first number like 4/3

Answer:

t ≥ 192

Step-by-step explanation:

To isolate t in the inequality 6.50t ≥1248, divide by 6.50 on both sides. There you are left with t ≥ 192 which means the cheerleading team must sell 192 t-shirts or more to make their profit goal. Graph this using a closed circle at 192 moving upwards. (You didn't include a picture of the given graphs in your problem)

Answer: 42.308%

Step-by-step explanation:

Answer:

X=3

Step-by-step explanation:

First you can distribute the 4 to 2x-1 making is 8x-4

8x-4+2x+2=28

Now add like terms

8x+2x-4+2=28, 10x-2=28

Add 2 to both sides

10x=30

Divide both sides by 10

x=3

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The height of the mountain is 3110.5767 feet.

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

The height of the mountain from the first point,

[tex]\tan(29^o) = \dfrac{H}{x+1000}\\\\H = (1000+x) \times \tan(29^o)[/tex]

The height of the mountain from the second point,

[tex]\tan(34^o) = \dfrac{H}{x}\\\\H = x \times \tan(34^o)[/tex]

Equating the height,

H = H

(1000+x) × tan(29°) = x tan( 34°)

x = 4611.5767 feet

Now, the height of the mountain is,

H = x tan(34°)

H = 3110.54776 feet

Hence, the height of the mountain is 3110.5767 feet.

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Answer:

your slow

Step-by-step explanation:

Step-by-step explanation:

good study habits will help! study before you plan on sleeping and designate times to do your work

Answer:

ok sure will do the answer is

Step-by-step explanation:

Answer:

{(-3, -2), (-4, 3), (-1, 0), (3, -7)}

Step-by-step explanation:

When you find the inverse of a function you swap the x and the y. So let's look at a couple examples and see what happens to the x and y values

Radical:

[tex]y=\sqrt{x}[/tex]

So let's just look at perfect squares so it's a bit easier to understand

(0, 0)

(4, 2)

(9, 3)

Now let's find the inverse:

[tex]x=\sqrt{y}[/tex]

Now to make this concept a bit easier to understand let's leave it in this form. Well the first notable thing, is that any operations applied to y will now apple to x, and any operations applied to x will apply to y (in this case the square root).

So if I input 9 as the y, the x will be 3

If I input 4 as y, the x will become 2

Some points are

(0, 0)

(2, 4)

(9, 3)

You'll notice the x and y values are swapped, well it's simply because you swap the x and y's place. this is also why the domain and range are swapped

So given the points {(-2, -3),  (3, -4), (0, -1), (-7, 3)} you simply swap the x and y to get:            {(-3, -2), (-4, 3), (-1, 0), (3, -7)}

Answer:

D

Step-by-step explanation:

Using the rule of dilation, 5/4, the length of C'A' is: A. 10 units.

Dilation is a form of transformation that creates a new image that is similar to the original one.

The images formed are similar images shown in the diagram given, therefore, using the rule of dilation, Dy = 5/4, we would have:

CA × 5/4 = C'A'

Plug in the given value

8 × 5/4 = C'A'

10 = C'A'

C'A' = 10 units

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Answer:

was there a list to choose from

Step-by-step explanation:

19, 26, 33, 40, 47

The missing term in the expression ___( 2a-1)  is 6b.

An expression is an algebraic statement that consists of variables, constants, and mathematical operators.

The expression 12ab-6b is equivalent to

6b( 2a-1)

(By taking the common factors out of the given expression.)

Therefore, the missing term in the expression is 6b.

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Answer:

Step-by-step explanation:

[tex]1+tan^2\theta=sec^2\theta\\tan^2\theta=sec^2\theta -1 \\tan^2\theta=(sec\theta-1)(sec\theta+1)\\\implies \frac{1}{sec\theta-1} =\frac{sec\theta+1}{tan^2\theta} \\\\and \quad \frac{1}{sec\theta+1} =\frac{sec\theta-1}{tan^2\theta} \\\\ \frac{1}{sec\theta-1} + \frac{1}{sec\theta+1} = \frac{sec\theta+1}{tan^2\theta} + \frac{sec\theta-1}{tan^2\theta}\\\\=\dfrac{2sec\theta}{tan^2\theta}\\\\=\dfrac{2cos^2\theta}{cos\theta.sin^2\theta}\\\\\\=2cos\theta.cosec^2\theta[/tex]

The expressions that gives the number of online math classes is as follows:

y = x - 15

The number of math classes offered online in the summer is 15 less than the number of math classes offered face-to face in the summer.

Let

the number  of math classes offered face-to face = x

the  number of math classes offered online  = y

Therefore, the expression that gives the number of online math classes is as follows:

y = x - 15

x = y + 15

Hence,

y = x - 15

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[tex]\angle PYZ=116^{\circ}[/tex] (angles on a line add to 180 degrees)

[tex]\angle ZYQ=58^{\circ}[/tex] (angle bisector)

[tex]\angle XYQ=122^{\circ}[/tex] (angle addition postulate)

[tex]\angle QYP=58^{\circ}[/tex] (angle bisector)

Reflex [tex]\angle QYP=302^{\circ}[/tex] (an angle and its reflex angle add to 360 degrees)

The statement about the system of of equations that are true are as follows:

The system of equation can be solved as follows;

2x - 7y = - 13

2x + 11y = 1

18y = 14

y = 14 / 18

y = 7 / 9

2x  = 1 - 11(7 / 9)

2x = 1 - 77 / 9

2x = 9 - 77 / 9

2x = -68 / 9

cross multiply

18x = -68

x = -68 / 18

x = -34 / 9

Hence, the statement about the system of of equations that are true are as follows:

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Answer:

Elimination would be a better method for solving the system.

[tex]\Rrightarrow \sf12x+10y=2[/tex]

[tex]\Rrightarrow \sf6x+5y=1.......(i)[/tex]

[tex] \sf\Rrightarrow-x+4y= -5 ............(ii)[/tex]

[tex]\large \sf \red{ \blue{[ (ii)×6]}}[/tex]

[tex]\sf\Rrightarrow-6x+24y= -30 ............(iii)[/tex]

[tex] \large \sf \red{(i) + \blue{ (iii)}}[/tex]

[tex]\Rrightarrow \small\sf6x+5y=1+(-6x+24y= -30)[/tex]

[tex]\Rrightarrow \sf29y = - 29 \\ [/tex]

[tex]\Rrightarrow \blue{\sf \: y = - 1}[/tex]

putting the value in equation (i)

[tex]\Rrightarrow \sf6x+5 \times - 1=1[/tex]

[tex]\Rrightarrow \sf6x - 5=1[/tex]

[tex]\Rrightarrow \sf6x = 6[/tex]

[tex]\Rrightarrow \red{\sf \: x = 1}[/tex]

[tex]\overline{\underline{\rule{209pt}{2pt}}}[/tex]

Answer:

[tex]\sf Total \ amount \ of \ walnuts \ and \ pecans \ needed = \dfrac{7}{12}[/tex]

Step-by-step explanation:

    [tex]\sf Amount \ of \ walnut \ needed = \dfrac{1}{4}[/tex]

    [tex]\sf Amount \ of \ pecans \ needed =\dfrac{2}{6} =\dfrac{1}{3}[/tex]

To find the total amount of walnut and pecans, we have to add the fractions.

LCM of 4 & 3 = 12

Equivalent fractions:

      [tex]\sf \dfrac{1}{4}=\dfrac{1*3}{4*3}=\dfrac{3}{12}\\\\\dfrac{1}{3}=\dfrac{1*4}{3*4}=\dfrac{4}{12}[/tex]

Now, add

   [tex]\sf \dfrac{3}{12}+\dfrac{4}{12}=\dfrac{3+4}{12}[/tex]

                  [tex]\sf = \dfrac{7}{12}[/tex]

The total amount will be $889123 after 16 years if the starting salary is $350000

It is defined as the function that rapidly increases and the value of the exponential function is always positive. It denotes with exponent [tex]y = a^x[/tex]

where a is a constant and a>1

We have:

Starting salary is $350000 and you receive a 6% increase at the end of every year.

We can find the total amount, from the exponential formula:

T = a(1 + r)ⁿ

T is the total amount

a is the starting amount

r is the rate

n is the total number of years

T = 350000(1 + 6%)¹⁶

T = 350000(1 + 0.06)¹⁶

T = 889123.08 ≈ $889123

Thus, the total amount will be $889123 after 16 years if the starting salary is $350000

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The missing segment in the image below is 78 units.

An equation is an expression that shows the relationship between two or more variables and numbers.

The ratio or two corresponding sides of similar shapes are in the same proportion.

Let x represent the missing side, hence:

(x + 26)/26 = 48/12

x =78

The missing segment in the image below is 78 units.

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Pn(Z>zp)=1−p%

Given a variable X following a normal distribution with mean μ and standard deviation σ, the area below the curve that corresponds to all values that are less than a that is, X<a

is the probability P(X<a). This probability is usually calculated by converting the variable X to a standard normal variable Z (forming z scores) defined by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

The variable Z follows the standard normal distribution with a mean of 0 and a standard deviation of 1.

The standard normal probabilities are typically found by using the standard normal tables or other computational means such as calculators or software.

Pn(Z>zp)=1−p%

Here Pn is the probability for the standard normal variable.

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Answer:

159.3

Step-by-step explanation:

456 - 121.3 = 334.7

333.7 - 175.4 = 159.3

Hope this helped

Answer:

152

Step-by-step explanation:

You actually don't need to find the thirds number. Just by taking 456 and dividing it by three, you will get your answer and the average of the three numbers.

[tex]\frac{1820728291}{14285714286}[/tex]

Yes, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.

Inequality can be define as the relation of equation contains the symbol of ( ≤, ≥, <, >) instead of equal sign in an equation.

For 35 long haired and 40 short haired member.
Put this values in the given equation.

For water 70L+60S < 5600
  70 x 35 + 60 x 40
2450+2400
4850 <5600
inequality holds

For shampoo 0.02L+0.01S ≤ 1.50
0.02 x 35 + 0.01 x 40
0.7 + 0.4
1.1 < 1.50
inequality holds

Thus, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.

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Answer:

  z = 110°

Step-by-step explanation:

Angles z and the one marked 70° form an linear pair, hence are supplementary.

  z = 180° -70° = 110°

The angle made by two chords is half the sum of the arcs intercepted by those chords. Here, that means ...

  70° = 1/2(60° +x)   ⇒   x = 140° -60° = 80°

The arc w completes the circle of 360°, so we have ...

  w +x +79° +60° = 360°   ⇒   w = 360° -219° = 141°

Finally, z is the average of w and 79°:

  z = (w +79°)/2 = (141° +79°)/2 = 110° . . . as above

Isolate x:

2x + 7y = -1

2x = -1 -7y

x = -1/2 - 7/2y

Substitute the equation of x:

4x - 3y = -19

4(-1/2 - 7/2y) - 3y = -19

-2 - 14 - 3y = -19

-3y = -19 + 14 + 2

-3y = -3

 y = 1

Substitute to find x:

2x + 7y = -1

2x + 7(1) = -1

2x = -1 - 7

2x = -8

x = -4

(-4, 1)

Multiply one or both equations through an integer in order that one time period has the same and contrary coefficients within the equations. Add the equations to provide a single equation with one variable. clear up for the variable. alternative the variable back into one of the equations and resolve for the other variable.

Conclusion: A system of equations is fixed of 1 or greater equations related to some of the variables. The solutions to systems of equations are the variable mappings such that every one component equations are satisfied—in other phrases, the locations at which all of these equations intersect.

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