A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. The ratio of their kinetic energies (truck to car) is 0.485
The formulas for the momentum and the kinetic energy are:
p = m . v
Ek = 1/2 . mv²
Where:
p = momentum
m = mass
Ek = kinetic energy
v = speed or velocity
Ek = 1/2 . mv² = 1/2 . mv . v
= 1/2 . p . v
Since p or momentum of both vehicles are the same, hence, the ratio of their kinetic energies is
Ek_truck : Ek_car = v_truck : v_car
In the given problem:
m_truck = 2268 kg
m_car = 1100 kg
Both have the same momentum, hence,
m_truck x v_truck = m_car x v_car
v_truck / v_car = m_car / m_truck
= 1100 / 2268 = 0.485
Therefore,
Ek_truck / Ek_car = v_truck / v_car = 0.485
Your question is incomplete, but most probably your question was:
A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. If the same horizontal net force were exerted on both vehicles, pushing them from rest over the same distance, what is the ratio of their final kinetic energies? (ratio: truck to car)
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Calculate the acceleration of the car in stage A if it has a mass of 1200kg
stage A: 3000N
Answer:
2.5 m/s²
Explanation:
F = ma (Newton's 2nd Law)
a = F/m = 3,000 N / 1,200 kg = 2.5 m/s²
a local am radio station broadcasts at an energy of kj/photon. () calculate the frequency at which it is broadcasting.
The frequency at which it is broadcasting is 875 KHz for a local am radio station broadcasts at an energy of kj/photon
Given,
Energy of a photon = 5.80 x 10-31 kJ x ( 1000 J / 1kJ) = 5.8 x 10-28 J
We know,
E = hv
Here,
"h" is the plank's constant = 6.626 x 10-34 J.s
v = frequency in Hz
Now, rearranging the formula,
v = E / h
Substituting the values,
v = 5.8 x 10-28 J / 6.626 x 10-34 J.s
v = 875340 s-1 or Hz
Now, converting Hz to kHz,
Given, 1kHz = 103 Hz
= 875340 Hz x ( 1 kHz / 103 Hz)
= 875.3 kHz
Frequency = 875 kHz [3S.F]
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for what wavelength of light is the scattering only 2.00 % that of light with a visible wavelength of 520 nm ?
Potentially, optical scattering can be employed to create a solids content assessment instrument that is useful for managing and monitoring tailings ponds.
This bench-scale study looked into the best laser wavelengths for real-time in situ use in oil sands tailings in the visible (405, 520, and 658 nm) and near infrared (980, 1310, and 1550 nm) ranges. In comparison to the visible wavelengths, the near infrared wavelengths generally showed greater sensitivity across the full test range. Additionally, oil sands tailings' remaining bitumen has a tendency to absorb visible wavelengths, interfering with the scattering light signals and resulting in unreliable results. The 1550 nm wavelength in particular demonstrated an almost linear sensitivity of the light scattering with the change in solids concentration due to a sufficiently strong water absorption.
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is there evidence of the diffusion of starch molecules? if so, what evidence and in which direction did starch molecules diffuse?
Iodine molecules are small enough to pass freely through the membrane however, starch molecules are complex and too large to pass through the membrane. Initially, there was a higher concentration of iodine outside than inside the tube.
Thus iodine diffused into the tube with the starch. Iodine is able to pass through the membrane while starch is not. The Glucose-testing strips indicate that glucose has been able to pass out of the tubing and into the external fluid. Thus proving the tubing allows movement in both directions.
Iodine was able to diffuse across the membrane because it is small and hydrophobic and starch was not because it is too large The Dialysis tubing provides a semi-permeable membrane. Only allowing smaller molecules to pass through it. Iodine molecules are small enough to pass freely through the membrane, however, starch molecules are complex and too large to pass through the membrane.
The iodine is a small molecule and can move from outside the tubing to inside it. To test whether iodine or starch has crossed the synthetic membrane, you will look for color change. A solution of iodine is tan and a solution of starch is milky white; when iodine and starch are together in the same solution, they react and the solution turns purple, dark blue, or black.
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two coins are released from the same height in an experiment. the first is dropped vertically. the second slides down a frictionless track. which coin has the greatest speed when they reach the bottom?
Answer:
1/2 m v^2 = E conservation of energy
Both will have the same speed.
v = (s2 - s1) / t holds for both coins
The coin that slides down the frictionless track will take longer to reach the bottom - the speed for both at the bottom will be the same
A 90 kg fullback is running at 5 m/s and is stopped by a tackler. The tackle lasts for 0.5 second.
a. What is the original momentum of the fullback?
b. What is the impulse imparted on the fullback?
c. What is the force exerted on the fullback?
d. What is the force exerted on the tackler?
A. The original momentum of the fullback is 450 Kg.m/s
B. The impulse imparted on the fullback is 450 Ns
C. The force exerted on the fullback is 900 N
D. The force exerted on the tackler is -900 N
A. How do I determine the original momentum?
The original momentum of the fullback can be obtained as follow:
Mass of fullback = 90 KgVelocity of fullback = 5 m/sMomentum of fullback =?Momentum = mass × velocity
Momentum of fullback= 90 Kg × 5 m/s
Momentum of fullback = 450 Kg.m/s
B. How do I determine the impulse imparted?
The impulse imparted, can be obtained as shown below:
Mass (m) = 90 KgInitial velocity = 5 m/sFinal velocity = 0 m/sImpulse =?Impulse = m(v + u) since the came to rest
Impulse = 90 × (0 + 5)
Impulse = 90 × 5
Impulse = 450 Ns
C. How to determine the force exerted on the fullback?
The force exerted on the fullback can be obtain as follow:
Impulse = 450 NsTime = 0.5Force (F) = ?Impulse = force × time
450 = Force × 0.5
Divide both sides by 0.5
Force = 450 / 0.5
Force = 900 N
D. How to determine the force exerted on the tackler?
Force exerted on the fullback = 900 NForce exerted on the tactkler = 900 NFrom Newton's 3rd law of motion which states that to every action, there is an equal an opposite reaction.
Since the force exerted on the fullback is 900 N. Thus, the force exerted on the tackler will be -900N
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a skydiver is falling at a constant velocity with a not yet opened parachute identify the forces exerted on the object
When a skydiver is falling at a constant velocity with a not yet opened parachute, then the main force exerted on the object gravity.
What is the force exerted on object when skydiver is falling at constant velocity?When a parachutist leaves the plane with the chute not open, then the main force acting is gravity. As speed through the air increases, then the air resistance also increases.
At 'terminal velocity', which is around 200 km/h, air resistance force balances gravitational force and parachutist stops accelerating and falls at constant velocity. When the parachute is open, then air resistance is greater due to the greater surface area.
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FILL IN THE BLANK. in a px orbital, the subscript x denotes the __________ of the electron.
In a px orbital, the subscript x denotes the axis along which the orbital is aligned of the electron.
'What is atomic orbital?'
The area closest to an atomic nucleus where an electron is most likely to be found is called an atomic orbital. An atom's orbitals can be classified as either s, p, d, or f orbitals. The Px, Py, and Pz orbitals are three of the p orbitals that exist.
The Px, Py, and Pz orbitals all have two lobes, but the Py orbital has two lobes directed along the y-axis, and the Pz orbital has two lobes oriented along the z-axis. This is the main distinction between the three orbitals. Because of how they are oriented in space, the Px Py and Pz orbitals differ from one another.
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the larger player on the left and the smaller player on the right push against each other. who fees the greater force?
Answer:
The players feel equal force against one another.
Explanation:
This is known from Newton's Third Law of Motion which states that for every action/force there is an equal and opposite reaction/force. Therefore, even if one player is larger, the force exerted on each player from the other is the same.
Which of these events moves small pieces of rocks away from where they originally formed?
Answer: The answer should be Erosion
Explanation: Erosion removes and transports rock and soil. Additionally, it also moves sediment through water, ice, and wind.
When you drop a 0.4 kg apple, Earth exerts a
force on it that accelerates it at 9.8 m/s
2
toward the earth’s surface. According to Newton’s third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 × 1024 kg, what
is the magnitude of the earth’s acceleration
toward the apple?
Answer in units of m/s
Answer:
Explanation:
a = ΣF/m
a = (0.4kg * 9.8m/s^2)/(5.98 * 10^24kg)
a = 6.56 * 10^-25 m/s^2
for a particular process q = 20 kj and w = 15 kj. which of the following statements is true?
For a particular process q=-17 kJ and w=21 kJ. The following statements are true:
(a) Heat flows from the system to the surroundings
(d) The process is exothermic
E=q+w, where q is the amount of heat flowing into or out of the system, is the first law of thermodynamics.
Heat enters the system when q is positive, and heat exits the system when q is negative.
Workflow into or out of the system,
Work is done on the system when w is positive, and the system performs work when w is negative.
E is the system's overall internal energy change.
Q+W = 17 kJ + 21 kJ = + 4 kJ
As a result, the statement in (c) is correct.
Since q is negative in this case at -17 kJ, the process is exothermic, releasing heat from the system generally into the environment.
Thus, the assertion in (d) is true.
As q has a negative value, this indicates that heat is transferred from the system into the environment.
Therefore, the assertion in (a) is true.
Now that w is a positive number, the system is receiving work. Therefore, the assertion in (b) is false.
Since statement b. is untrue, statement e. is also false.
As a result, the assertion in (e) is false.
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The complete question should be:
For a particular process q=-17 kJ and w=21 kJ. Which of the following statements is true?
Heat flows from the system to the surroundings
The system does work on the surroundings
E=+4 KJ
The process is exothermic
None of the above is true
if the frequency of ultrasound in increased from 0.77 mhz to 1.54 mhz, what happens to the propagation speed?
If the frequency of ultrasound in increased from 0.77 mhz to 1.54 mhz, the propagation speed is remains same.
Since these are not modifications to the characteristics of the medium, changing the frequency or amplitude of the waves will not alter their speed. In a particular medium, the speed of propagation is constant; only the wavelength varies as the frequency does. Your physical, emotional, and mental bodies feel lighter as your energy or vibration frequency rises. More inner strength, clarity, tranquility, love, and joy are felt by you. Your physical body experiences little or no pain or suffering, and you can manage your emotions with ease.
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An object is launched at a velocity of 20 m/s in a direction making at an angle of 25⁰ upward with the horizontal. Find
(a) The maximum height reached by the object.
(b) The magnitude of the velocity of the object before it hits the ground.
Answer:
below
Explanation:
Vertical position = vo t + 1/2 at ^2
where vo = 20 sin25 =8.45 and a = -9.81 m/s^2
Vertical position = - 4.905 t^2 + 8.45 t
max will occur at t = -b/2a = -8.45 / (2* -4.905) = .861 s
Plug in this value to find vertical height
vertical position = 8.45(.861) - 1/2 (9.81)(.861)^2 = 6.92 m
b) magnitude when it comes down = magnitude when it went up = 20 m/s
(a) is it possible for a path to also be a circuit? explain your reasoning. (b) is it possible for a path to also be a cycle? explain your reasoning.
(a). A circuit is just a path that ends and begins the same vertex, hence the yes answer. (b). In a graph, a route is a series of nearby sides who cross at the same vertices.
What does the word "circuit" mean?In electronics, a circuit is a completely circular conduit through which electricity travels. A simple circuit comprises a current provider, conductors, and a demand. The term "circuit" refers generally to any ongoing path for the transmission of energy, information, or a signal.
Briefing:(a). Any method of moving over the graph's edges is a route. There is no restriction on the beginning or ending vertices, edges, etc. A path is any feasible path that connects two vertices.
(b). In a cycle, the start and end vertices are the same. As a result, a route can be a cycle if its start and end vertices are similar and a cycle is established during traversal.
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A vehicle undergoes acceleration when it
Speeds up
Slow down
Change direction
All of the above
Answer:
ALL OF THE ABOVE
Explanation:
A vehicle undergoes acceleration when what three things happen?
it gains speed, decreases speed, and changes direction .If there is acceleration, the velocity will change, either increasing or decreasing. The correct answer is D.
What is acceleration?The rate of growth of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, but this is not always the case. When an object is in motion in a circular track at a steady speed, it is still going to accelerate because its velocity direction changes.
Newton's Second Law states that an object's acceleration is the net result of all force applied to it. Acceleration is measured in meters per second squared.
The formula is given as,
a = Δv / Δt
If acceleration exists, the change of the velocity will be there and it may be increasing or decreasing. Then the correct option is D.
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a runner running the 100 m dash starts from rest and accelerates at a rate of 3 m/s^2 for 6.4s until reaching their maximum speed. they continue for the remainder of the race at the same speed. how long did it take them to complete the entire race
The runner takes 11.61 s to complete the entire race when they continue with same speed.
If the runner accelerated for 6.4 s, the velocity at which they accelerated will be:
Acceleration = velocity/time
3 = V/6.4
Making V the subject and by cross multiplying,
V = 3 × 6.4
V = 19.2 m/s
The runner maintains the speed through out the journey.
Speed = distance/time
Making time as the subject of formula,
Time = distance/speed
Time = 100 / 19.2
Time = 5.21 s
Therefore, a runner will complete the entire race in 6.4 + 5.21 = 11.61 s
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Can someone help me in this question?
Answer:
3×x for both .they did the same amount.
if a particle undergoes shm with amplitude 0.11 m , what is the total distance it travels in one period? express your answer using two significant figures. s
The total distance it travels in one period is 0.44m
Distance is a numerical or every so often qualitative size of how some distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.
The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.
It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.
Calculation:
amplitude = 0.11m
total distance (s) = 4 (amp)
4 × 0.11 = 0.44m
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the force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the object sliding at a constant velocity. the magnitudes of the required forces are different in these situations because the force of kinetic friction
Answer: The force of kinetic friction is smaller than the maximum force of static friction due to the fact that the coefficient of kinetic friction is less than that of static friction.
if c1 = 25µf, c2 = 20µf, c3 = 10µf, and ∆v0 = 21v , determine the energy stored by c2.
The energy stored by c2 is =0.00144478
As per the details share in the above question are as bellow,
The value of the capacitor is ,c1 = 25µf, c2 = 20µf, c3 = 10µf.
While the potential difference is ∆v0 = 21v.
We have to determine the energy stored by c2?
In order to accomplish labor and to produce heat and light, energy must be transmitted to a body or to a physical system. Energy is the quantitative attribute that does this.
When the capacitors are connected in parallel then,
Ceq'= c2+c3= 20+10=30
When the capacitors are connected in series then
Capacitors in series (1/Ceq)=(1/c1)+(1/ceq')= (1/25)+(1/30)
Ceq=13.63μF
Now Energy is equal to one by two into c into v square,
[tex]E=\frac{1}{2} CV^2[/tex]
Substitute the value in above equation we get,
Energy[tex]=\frac{1}{2} (13.63 \times 10^{-6})\times (212)[/tex]
E=0.00144478
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Note:- The correct question would be as follow,
if c1 = 25µf, c2 = 20µf, c3 = 10µf, and ∆v0 = 21v , determine the energy stored by c2.
A woman of ma 54 kg jump off the bow of a 48 kg canoe that i intially at ret. If her velocity i 2 m/ to the right, what i the velocity of the canoe after he jump? Anwer in unit of m/ˆı
The velocity of canoe will be 27 m/s.
Explain what conservation of momentum is.According to the rule of conservation of momentum, absent an external force, the combined momentum of two bodies operating upon one another in an isolated system kept static. As a result, momentum cannot be gained or lost.
How to calculate the velocity of the canoe?Given, mass of the woman, m = 54 kg
mass of canoe, M = 48 kg
velocity of woman, v = 2 m/s
The principle of momentum conservation results in,
pi = pf
0 = mv - Mu
mv = Mu
u = mv/M
u = 54×2/48
u = 27 m/s
The velocity of canoe will be 27 m/s.
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what is the effect on current through a circuit of steady resistance when the volatage and resistance is doubled?
When the voltage and resistance is doubled the current will remain constant.
The voltage and resistance are inversely correlated, and the current is directly proportional to both. Any change in voltage will have an equal and opposite effect on current. Therefore, doubling or tripling the voltage will result in doubling or tripling the current.We know that I = V/R where I = current V = voltage and R = resistance such that
Given voltage is doubled so v2 = 2V
and resistance is also doubled so R2= 2R
I2 = V2/R2 = 2V/2R = V/R = I
Hence I2 = I
Therefore the current will remain same when both voltage and resistance are doubled.
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how many km would you have to go above the surface of the earth to for your weight to decrease by half
When we go 19113 Km above the surface of earth, the weight of the person will become half.
The weight of the person is given by
W = Mg
Where,
M is mass of the person and g is the gravitational acceleration.
The gravitational acceleration of the earth varies with the height from the surface of the earth as,
g' = g(R/(R+H))²
Where,
R is the radius of earth,
g' is the gravitational acceleration at height H,
For g' = g/2,
g/2 = g(R/(R+H))²
1/√2 = (R/(R+H))²
Solving further,
H = 3R
So, when we go to a distance 3R above the surface of earth the weight of the person will become half.
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A bungee jumper of 68 kg is attached to a bungee cord with an unstretched length of 20 m. He jumps off a bridge and when he finally stops, the cord has a stretched length of 50.0 m. Treat the stuntman as a point mass, and disregard the weight of the bungee cord. Assuming the spring constant of the bungee cord is 82.6 N/m, what is the total potential energy relative to the water when the man stops falling if the distance between the man and the water is 6m?
Answer:
Below
Explanation:
The man will have Gravitational POTENTIAL energy due to Earth's gravity of mgh
mgh = 68 kg * 9.81 m/s^2 * 6m = 4002 J
The bungee has ELASTIC potential energy of 1/2 k x^2
where x = stretch distance and k = spring constant
= 1/2 (82.6 N/m) ( 50-20 m)^2 = 37170 J
Total = 4002 + 37170 = 41172 J
on average, what percentage of our total energy output is attributable to the thermic effect of food (tef)?
The percentage of our total energy output is attributable to the thermic effect of food up to 10%.
Decreased thermic effects of food are observed differently in the elderly and may predispose them to fat gain. Increased energy expenditure is very important for weight loss efforts.
Types of vigorous activity that can boost your metabolism include brisk walking 2 miles or biking uphill. Total Energy Expenditure The amount of energy you expend per day includes not only the calories you expend during physical activity but also the calories expended at rest the calories expended when digesting food and heat generation.
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calculate the synodic periods of venus and mars relative to earth. what are the implications of these periods for space missions to those planets?
21 and 7 years make up the Earth-Mars synodic period. The ecliptic plane is where the orbits of Earth, Mars, and the cycler trajectory are located.
What makes synodic periods significant?Synodic times are significant because they frequently correspond to direct observables, but physical rotation periods do not. This significance was crucial for determining the planets' orbital periods throughout the history of astronomy.
What exactly is a synodic period?Synodic period: The amount of time it takes for a body in the solar system, such as a planet, the Moon, or a man-made satellite to return to the same or nearly the same location with respect to the Sun as seen from the Earth.
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A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 225Hz . A person on the platform right next to the speaker detects the sound waves reflected off the wall and those emitted by the speaker.How fast should the platform move, vp, for the person to detect a beat frequency of 1.00Hz ?
The speed of the platform so that the person detects a beat frequency of 1.00 Hz is 5.286m/s.
The speaker moving towards the wall is emitting the sound of frequency of 115Hz and the platform right next to the speaker is detecting the sound reflected by the wall and emitted by the speaker.
Now, to find the speed of the platform so that the person here the beta frequency pf 1.00Hz, we will use the relation,
F = (c+v/c-v)f
c = Speed of waves in the medium
u = Speed of the receiver relative to the medium
v = Speed of the source relative to the medium
f = emitted frequency
Our values are given,
Beat frequency = 7Hz
Reflective Doppler frequency = 225+7=232Hz
Putting values,
232 = (c+v/c-v)225
solving further,
v = 5.286 m/s.
So, the speed of the platform shoud be 5.286m/s.
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a 200-n force is applied as shown to the bracket abc. determine the moment of the force about a
The moment of the force about A will be 14150.97 N-m Force = 200 N
A force's moment is determined by its magnitude and distance from the rotating axis. The moment of a force around a point measures the force's strength (the perpendicular distance of the line of action of the force from the point). The turning effect of a force is known as its moment. The moment of force, sometimes referred to as the torque. A moment must develop because of a force F, which prevents the line of action from passing through the location where the moment is to be taken. If the line of action does not travel through that location, the moment is zero since the magnitude of the moment arm is 0.
[tex]amp; \vec{F}=200\left(-\cos 30^{\circ} \hat{j}+\sin 30 \hat{k}\right) M \\& \vec{F}=200 \cdot\left(\frac{-\sqrt{3} \hat{\imath}+\hat{k}}{2}\right)=100(-\sqrt{3} \hat{\jmath}+\hat{k}) M \\& \overrightarrow{r_A}=-50 \hat{\jmath}, \quad \vec{r}_C=60 \hat{i}+25 \hat{1} \\& \Rightarrow \quad \vec{r}_{C A}=\vec{r}_e-\vec{r}_A=60 \hat{\imath}+755[/tex]
Moment of F about A -
[tex]amp; \vec{M}_A=\vec{\pi} A \times \vec{F}=(60 \hat{+}+75 \hat{1}) \times(100(-\sqrt{3} \gamma+\hat{k}) \\& \vec{M}_A=100\{-\sqrt{3} .60 \hat{k}-60 \hat{\imath}+0+75 \hat{\jmath}\}[/tex]
[tex]\vec{MA}=7500 i-6000 i-6000 \sqrt{3} \hat{N} N-m\\\\\mid \vec{MA}|_A=14150.97 N-m[/tex]
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Describe the work done while you apply force on the box and after you let go
Explanation:
If you apply a force on a box and push it across a surface, you are doing work on the box. The amount of work done is equal to the force applied multiplied by the distance the box moves in the direction of the force. This means that if you apply a greater force or move the box a greater distance, you will do more work on the box.
Once you let go of the box, the work that you did on the box is no longer being applied, and the box will come to a stop unless there are other forces acting on it (such as gravity or friction). If the box is on a horizontal surface and there is no friction, it will not move at all after you let go, and the work you did on it will be completely converted into kinetic energy (the energy of motion). If the box is on a sloping surface or there is friction, the kinetic energy will be converted into other forms of energy, such as heat, and the box will slow down and eventually stop.