A physics student tossed a ball vertically straight upward.
Describe the magnitude of the ball’s vertical velocity at its highest position.
a. The magnitude of vertical velocity is zero.
b. The magnitude of vertical velocity is 9.8 m/s.
c. The magnitude of vertical velocity is at a maximum value.
d. The magnitude of vertical velocity cannot be determined.
Answers
Answer:
c. The magnitude of vertical velocity is at a maximum value.
Explanation:
I think this is correct I'm not entirely sure though
Answer:
Explanation: ns along perpendicular axes are independent and thus can be analyzed separately. This fact was discussed in Kinematics in Two Dimensions: An Introduction, where vertical and horizontal motions were seen to be independent. The key to analyzing two-dimensional projectile motion is to break it into two motions, one along the horizontal axis and the other along the vertical. (This choice of axes is the most sensible, because acceleration due to gravity is vertical—thus, there will be no acceleration along the horizontal axis when air resistance is negligible.) As is customary, we call the horizontal axis the x-axis and the vertical axis the y-axis. (Figure) illustrates the notation for displacement, where \mathbf{s} is defined to be the total displacement and \mathbf{x} and \mathbf{y} are its components along the horizontal and vertical axes, respectively. The magnitudes of these vectors are s, x, and y. (Note that in the last section we used the notation \mathbf{A} to represent a vector with components {\mathbf{A}}_{x} and {\mathbf{A}}_{y}. If we continued this format, we would call displacement \mathbf{s} with components {\mathbf{s}}_{x} and {\mathbf{s}}_{y}. However, to simplify the notation, we will simply represent the component vectors as \mathbf{x} and \mathbf{y}.)
Review of Kinematic Equations (constant a)
x={x}_{0}+\stackrel{-}{v}t
\stackrel{-}{v}=\frac{{v}_{0}+v}{2}
v={v}_{0}+\text{at}
x={x}_{0}+{v}_{0}t+\frac{1}{2}{\text{at}}^{2}
{v}^{2}={v}_{0}^{2}+2a\left(x-{x}_{0}\right)\text{.}
The total displacement \mathbf{s} of a soccer ball at a point along its path. The vector \mathbf{s} has components \mathbf{x} and \mathbf{y} along the horizontal and vertical axes. Its magnitude is s, and it makes an angle \theta with the horizontal.
A soccer player is kicking a soccer ball. The ball travels in a projectile motion and reaches a point whose vertical distance is y and horizontal distance is x. The displacement between the kicking point and the final point is s. The angle made by this displacement vector with x axis is theta.
Given these assumptions, the following steps are then used to analyze projectile motion:
Step 1.Resolve or break the motion into horizontal and vertical components along the x- and y-axes. These axes are perpendicular, so {A}_{x}=A\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {A}_{y}=A\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\theta are used. The magnitude of the components of displacement \mathbf{s} along these axes are x and \mathrm{y.} The magnitudes of the components of the velocity \mathbf{v} are {v}_{x}=v\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {v}_{y}=v\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\mathrm{\theta ,} where v is the magnitude of the velocity and \theta is its direction, as shown in (Figure). Initial values are denoted with a subscript 0, as usual.
Step 2.Treat the motion as two independent one-dimensional motions, one horizontal and the other vertical. The kinematic equations for horizontal and vertical motion take the following forms:
\text{Horizontal Motion}\left({a}_{x}=0\right)
x={x}_{0}+{v}_{x}t
{v}_{x}={v}_{0x}={v}_{x}=\text{velocity is a constant.}
\text{Vertical Motion}\left(\text{assuming positive is up}\phantom{\rule{0.25em}{0ex}}{a}_{y}=-g=-9.\text{80}{\text{m/s}}^{2}\right)
y={y}_{0}+\frac{1}{2}\left({v}_{0y}+{v}_{y}\right)t
{v}_{y}={v}_{0y}-\text{gt}
y={y}_{0}+{v}_{0y}t-\frac{1}{2}{\mathrm{gt}}^{2}
{v}_{y}^{2}={v}_{0y}^{2}-2g\left(y-{y}_{0}\right)\text{.}
Step 3. Solve for the unknowns in the two separate motions—one horizontal and one vertical. Note that the only common variable between the motions is time t. The problem solving procedures here are the same as for one-dimensional kinematics and are illustrated in the solved examples below.
Step 4.Recombine the two motions to find the total displacement\mathbf{\text{s}} and velocity \mathbf{\text{v}}. Because the x – and y -motions are perpendicular, we determine these vectors by using the techniques outlined in the Vector Addition and Subtraction: Analytical Methods and employing A=\sqrt{{A}_{x}^{2}+{A}_{y}^{2}} and \theta ={\text{tan}}^{-1}\left({A}_{y}/{A}_{x}\right) in the following form, where \theta is the direction of the displacement \mathbf{s} and {\theta }_{v} is the direction of the velocity \mathbf{v}:
Total displacement and velocity
s=\sqrt{{x}^{2}+{y}^{2}}
\theta ={\text{tan}}^{-1}\left(y/x\right)
v=\sqrt{{v}_{x}^{2}+{v}_{y}^{2}}
{\theta }_{v}={\text{tan}}^{-1}\left({v}_{y}/{v}_{x}\right)\text{.}
(a)
Related Questions
If a sprinter accelerates from rest to 12 m/s north , what is their change in velocity ?
Answers
Answer: It would be 12 m/s.
Explanation: It would be this because If you go from rest to sprint it would be 12 m/s. Also, I did this the other day.
A water-balloon launcher with a mass of 2.0 kg is suspended on a wire. It
fires a 0.75 kg balloon to the west at a velocity of 14.0 m/s. What is the
resulting velocity of the launcher if the net force on the launcher is equal to
the reaction force?
A. 5.3 m/s east
B. 6.6 m/s west
C. 7.4 m/s east
D. 37.3 m/s east
Answers
Answer:
5.3
Explanation:
Answer:
5.3 m/s east
Explanation:
4. Vector A is 7.00 units in length and points along the positive x-axis. Vector B is 5.00 units in length and points along the negative x-axis. find the magnitude and direction of A+2B 1 point
Answers
Answer:
Since the two vectors form a right angle, no components need to be found for the resultant vector - we already have them!
Vector R's x-component = 3.00 units
Vector R's y-component = 4.00 units
To solve for the magnitude of the displacement, use the distance formula: Square Root of [(3)^2 + (4)^2], which equals 5 units.
To solve for the direction of the displacement, plug in -4 (remember where it was pointing) for y and 3 for x. Tan-1(-4/3) = -53.13°, or 53.13° south of east.Please Mark as Brilliant
The magnitude of vector C is |C| = 3 and It is directed along the negative x - axis.
What is vector quantity?
A vector quantity is a quantity with both magnitude and direction.
Given is vector A is 7.00 units in length and points along the positive x-axis. and vector B is 5.00 units in length and points along the negative x-axis.
Vector A = 7 a[x]
Vector B = - 5 a[x]
Therefore, the given expression to be evaluated is -
C = A + 2B
C = 7 a[x] + 2(- 5 a[x])
C = 7 a[x] - 10 a[x]
C = - 3 a[x]
So, the magnitude of vector C is -
|C| = 3
It is directed along the negative x - axis.
Therefore, the magnitude of vector C is |C| = 3 and It is directed along the negative x - axis.
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Which rule(s) is used for combining velocities?
A. Scalar rules
B. Vector rules
C. Equilibrium rule
Answers
Answer: B. Vector rules
Explanation:
To solve this we must be knowing each and every concept related to velocity. Therefore, the correct option is option B among all the given options.
What is velocity?Velocity refers to a vector assessment of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.
It determines how quickly or slowly something moves. Consider the following scenario: two moving objects. If both items are going in the same direction, it is simple to determine which one is moving faster. However, judging which item is quicker is difficult when they are traveling in different directions. Vector rules is used for combining velocities.
Therefore, the correct option is option B among all the given options. Vector rules is used for combining velocities.
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How much heat is released by 38 gram sample of water to freeze
Answers
approx = 38 x 334 = 12692 Joules
Make a motion chart for a cannonball launched with an initial speed of 20m/s. Neglect drag and the initial height of the cannonball. After the ball lands on the ground enter zero for all speeds and heights if necessary. Use regular metric units (ie. Meters).
Answers
Answer:
The speed and height at 0 sec are 20 m/s and 0 m.
The speed and height at 1 sec are 10.2 m/s and 15.1 m.
The speed and height at 2 sec are 0.4 m/s and 20.4 m.
The speed and height at 3 sec are 9.4 m/s and 15.9 m.
The speed and height at 4 sec are 19.2 m/s and 1.6 m.
Explanation:
Given that,
Initial speed = 20 m/s
Suppose, given time in charge are t= 0, 1, 2, 3, 4 sec
At t=0 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times0[/tex]
[tex]v=20\ m/s[/tex]
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times 0-\dfrac{1}{2}\times9.8\times0[/tex]
[tex]h=0\ m[/tex]
At t=1 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times1[/tex]
[tex]v=10.2\ m/s[/tex]
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times1-\dfrac{1}{2}\times9.8\times1^2[/tex]
[tex]h=15.1\ m[/tex]
At t=2 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times2[/tex]
[tex]v=0.4\ m/s[/tex]
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times2-\dfrac{1}{2}\times9.8\times2^2[/tex]
[tex]h=20.4\ m[/tex]
At t=3 sec,
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]v=20-9.8\times3[/tex]
[tex]v=-9.4\ m/s[/tex]
Negative sign shows the opposite direction of motion
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times3-\dfrac{1}{2}\times9.8\times3^2[/tex]
[tex]h=15.9\ m[/tex]
At t=4 sec
We need to calculate the velocity and height
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into th formula
[tex]v=20-9.8\times4[/tex]
[tex]v=-19.2\ m/s[/tex]
Negative sign shows the opposite direction of motion
Now, using second equation of motion
[tex]h=ut-\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]h=20\times4-\dfrac{1}{2}\times9.8\times4^2[/tex]
[tex]h=1.6\ m[/tex]
So, The ball has hit the ground at 5 sec.
Hence, The speed and height at 0 sec are 20 m/s and 0 m.
The speed and height at 1 sec are 10.2 m/s and 15.1 m.
The speed and height at 2 sec are 0.4 m/s and 20.4 m.
The speed and height at 3 sec are 9.4 m/s and 15.9 m.
The speed and height at 4 sec are 19.2 m/s and 1.6 m.
when x doubles and y stays the same
Answers
I don't understand the question your asking. can you explain more?
What are five atomic models that have been proposed over time ?
Answers
Consider any ocean wave, what is the relationship between an ocean wave and the energy of that wave?
A) Wave energy decreases as the wave moves closer to the shore
B) The greater the wavelength, the more kinetic energy the wave has
C) Wave energy is directly proportional to the amplitude of the wave
D) Wave energy increases with frequency and decreases with wavelength
Answers
Answer:
C.
Explanation:
Wave energy is directly proportional to the amplitude of the wave. It is a square function.. double the amplitude (wind/solar power picks up) the energy in the ocean wave is quadrupled.
Wave energy is directly proportional to the amplitude of the wave. Therefore, option C is correct.
What is wave energy?Waves of heat, light, sound, and water carry a variety of energies. All types of energy can be converted into work because energy is defined as the capacity to perform work. The movement of an object in the direction of the force acting on it is referred to as work in science. When they move items, waves do really work. This process is evident when sand is carried or large logs are moved across ocean basins.
Work can also be transformed into the acoustic energy produced when waves crash on the coast. The potent force of waves can also be used to move generator components and generate electricity.
A wave's energy content is influenced by its height, wavelength, and breaking point in addition to other factors. When waves of identical wavelengths fall back to sea level, the wave with the greater amplitude will release more energy than the wave with the lesser amplitude. Therefore, option C is correct.
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A delivery truck driver's round-trip route from the warehouse takes her 5 km east, then 2 km north, then 5 km west, and then 2 km south. Which of the following statements is FALSE?
Answers
they're all right, because he just took a lap and went back to the same starting point,
How quickly would a 65kg object accelerate if the person applied a 500N force?
Answers
Answer:
[tex]a = 7.69\: {m(s)}^{ - 2} [/tex]
Explanation:
[tex]f = ma \\ a = \frac{f}{m} = \frac{500}{65} = \frac{100}{13} \\ a = 7.6923076923 \: {m(s)}^{ - 2} [/tex]
16. Evaluate the expression below if
a = -8, b = 17, and c = 21
az - (b + c)
Answers
Answer:
(if for solving for z)
z= -4.75
Explanation:
az-(b+c) [set equal to zero]
az-(b+c)=0
+(b+c) +(b+c)
az = (b+c) [now substitute the variables]
-8z = (17+21)
-8z = 38 [divide both sides by -8 to get z alone]
z = -4.75
A wolf can reach speeds of (16.5 m/s) in just 2 seconds. What is the wolf's acceleration?
Answers
Answer:
8.25Explanation:
Speed = 16.5 m/s
Time = 2 seconds
Acceleration = Speed/time
[tex]Acceleration = \frac{16.5}{2} \\\\Acceleration =8.25[/tex]
Which contributions did Johannes Kepler make? Check all that apply.
He revived Aristotle’s model of the solar system.
He solved Ptolemy’s model by proving elliptical orbits.
He proved Galileo’s calculations were incorrect.
He determined that planets move faster when closer to the Sun.
He discovered laws of planetary motion.
Answers
Answer:
the answers are 2, 4, and 5.
Explanation:
When you are standing in a subway train and the train suddenly stops but your body continues to move forward. Which one of Newton's laws is this?
1st law
2nd law
3rd law
4th law
Answers
Answer:
A. 1st law.
Explanation:
Newton's first law of motion states that, an object or body will continue to be at rest or experience a uniform motion in a straight line at constant speed provided there's no action of an external force. Thus, unless compelled to change its state by an external force, a body will continue to be at rest or experience a uniform motion in a straight line.
The Newton's first law of motion is also known as the law of inertia; which is the tendency of a body to be at rest unless acted upon by an external force.
In this scenario, you are standing in a subway train and the train suddenly stops but your body continues to move forward. This is in accordance with Newton's first law of motion.
Hence, the sudden stoppage of the train generates a force which acts on the body thereby causing the passenger to tip or move forward.
can someone please help me answer this in the next 15 minutes. ill give a brainiest to whoever can help me. tysm if u do!! :))
Answers
Answer: a
Explanation:
Answer: it is a
Explanation: the graph represents the number of speed running and the amount of you add 4 +—0.4 is -0.8! Byee! Plz give me brainliest! Ty! Have a good day!!
The support of the State governments in all their rights…I consider one of the essential principles of our Government… How is Jefferson's view reflected in the U.S. Constitution? The U.S. Constitution lists all powers given to the states. The U.S. Constitution gives unlimited power to the states. The U.S. Constitution says powers not given to the federal government belong to the states. The U.S. Constitution gives unlimited power to the federal government and little to the states.
Answers
Answer:
The Correct Answer is
The U.S. Constitution says powers not given to the federal government belong to the states.
Explanation:
In the paragraph, Jefferson states defending the rights of states is one of the fundamental, or most significant, policies of our administration. Did that get you to remember the Tenth Amendment? It restrains the authority of the central government, defending the rights of states. It states that the central government only has the authorities listed in the Constitution. Unlisted authorities belong to the states.
Answer:
D
Explanation:
what the difanshon of mass?
Answers
Answer:
Mass is a measure of the amount of matter in an object.
Explanation:
Use the drop-down menu to complete the statement.
Increasing the amount of current that flows through a wire________ the strength of an electromagnet.
Answers
Answer:
increases
Explanation:
edgu2020
Increasing the amount of current that flows through a wire increases the strength of an electromagnet.
What is an electromagnet?An electromagnet is a type of magnet that is created by running an electrical current through a coil of wire. Unlike permanent magnets, which have a fixed magnetic field that cannot be adjusted, the magnetic field of an electromagnet can be turned on and off or adjusted by controlling the amount of current flowing through the coil.
The strength of an electromagnet depends on several factors, including the number of coils in the wire, the amount of current flowing through the wire, and the type of core material used in the coil. Electromagnets are widely used in various applications, such as in electric motors, generators, relays, MRI machines, and particle accelerators.
One of the advantages of electromagnets is that their magnetic field can be easily controlled by adjusting the amount of current flowing through the wire. This makes them useful in applications where the magnetic field needs to be turned on and off, or where a variable magnetic field is required.
Another advantage of electromagnets is that they can be designed to be much stronger than permanent magnets. This is because the strength of an electromagnet is directly proportional to the amount of current flowing through the coil, which can be increased or decreased as needed.
Here in this question,
This happens because an electromagnet is created when an electric current flows through a wire, generating a magnetic field around the wire. The strength of the magnetic field depends on the amount of current flowing through the wire.
When more current flows through the wire, the magnetic field around the wire becomes stronger. This is because the magnetic field is directly proportional to the current flowing through the wire, as well as the number of loops of wire in the coil.
Therefore, increasing the current flowing through a wire in an electromagnet will increase the strength of the magnetic field, resulting in a stronger electromagnet.
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If a car travels 10 km north and then 10 km west, what is the MAGNITUDE of
displacement?
Answers
Answer:
The magnitude of the displacement is [tex]H = 14.14 \ km[/tex]
Explanation:
From the question we are told that
The distance of the car to north is d = 10 km
The distance of car to the west is w = - 10 \ km
The negative sign is because the direction is west
Generally applying Pythagoras theorem , the displacement is
[tex]H = \sqrt{d^2 + w^2}[/tex]
=> [tex]H = \sqrt{(10)^2 + (-10)^2}[/tex]
=> [tex]H = 14.14 \ km[/tex]
In the heart, what separates the oxygenated and deoxygenated blood?
A. Ventricle
B. Vessel
C.septum
D.atrium
Answers
Answer:
C. septum
Explanation:
The septum is the partition separating the right ventricle from the left ventricle. The right ventricle pumps deoxygenated blood to the lungs, and the left ventricle pumps oxygenated blood to the rest of the body.
on Mars, the acceleration due to gravity is 3.8 m/s². what would a book weigh on the surface of Mars?
Answers
Answer: 5.5
Explanation: its simply different from the others
Why does frost bite occur in mountain climbers ?
Answers
Answer:
Because they are in places that may be extremely cold
Explanation:
For example take Mount Everest. This place is a very high mountain, and is very cold. Usually hikers would get a frost bite from how cold it is in there. According to google, "Frostbite is an injury caused by freezing of the skin and underlying tissues."
Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He turned the car one more time and went 35 meters east. His car was 15 meters from the starting line. This took 5 seconds.
What is the car’s velocity?
Answers
Answer:
3 m/s east
Explanation:
I took a test a got it right
Answer:
3 m/s east
Explanation:
What is the weight of a 328N emperor penguin?
Answers
Answer:
Weight = 3217.68
Explanation:
N times Gravity = weight
Gravity= 9.81
The weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons.
What is Weight ?
Weight is the force exerted by the earth on an object at the surface of the earth. Mathematically -
W = m x g
where -
[m] is the mass of object
[g] is acceleration due to gravity
Given is the mass of an emperor penguin as 328 Kg.
We can write -
Mass [m] = 328 kg
Acceleration due to gravity [g] = 9.8 m/s²
Therefore, the weight of the emperor penguin will be
W[P] = m x g = 328 x 9.8 = 3214.4 Newtons
Hence, the weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons
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What did the caterpillar have to do to create the curved graphed with a gradually steeper slope?
Answers
Using the graphs on your notes, how are wavelength and frequency related to sound waves? Make sure to use proper terminology in your response.
Answers
Two conducting loops of the same diameter, #1 made of copper and #2 made of aluminum wires of the same length and cross-sections are placed on the horizontal surface in uniform magnetic field directed vertically up. Magnetic field vanishes suddenly. The magnitude of emf in loop #1 is
Answers
Answer:
Same as loop #2
Explanation:
The magnitude of emf in loop #1 is the same as that of loop #2
please help me with these two questions
Answers
Answer:
The kinetic energy would decrease because it has less mass
Explanation:
A battery
Which of the following scenarios is possible for the resultant velocity of an airplane in a strong wind to be 150 m/s?
A. The wind is blowing at 10 m/s. The airplane is flying against the wind at 140 m/s.
B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.
C. The wind is blowing at 200 m/s. The airplane is flying with the wind at 50 m/s.
D. The wind is blowing at 50 m/s. The airplane is flying against the wind at 100 m/s.
Answers
Answer:
B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.
Explanation:
From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:
[tex]\vec v_{A} = \vec v_{W}+\vec v_{A/W}[/tex] (Eq. 1)
Where:
[tex]\vec v_{W}[/tex] - Wind velocity, measured in meters per second.
[tex]\vec v_{A/W}[/tex] - Airplance velocity relative to wind, measured in meters per second.
[tex]\vec v_{A}[/tex] - Airplane velocity, measured in meters per second.
If we assume that [tex]\vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex] (The airplane flies with the wind), [tex]\vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex], then the resultant velocity of the airplane is:
[tex]\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex]
Therefore, correct answer is B.
Answer:
B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.
Explanation: