In the case of a paramecium moving at a constant speed, there is no net force acting on it.
The paramecium's cilia exerts a force on water that is equal to the force that the water exerts on the paramecium's cilia, according to Newton's third law.
The strength of the viscous force the water is exerting on the paramecium will be equal to the strength of the force the paramecium's cilia are exerting on the water.
How does Paramecium use cilia?
Cilia, or tiny strands like hair, cover the whole surface of parasites like cilia, which beat rhythmically to move them and guide bacteria and other food particles into their mouths.
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the eye works similar to a camera in the sense that it has an ideal framerate for visualizing motion. for instance, the monitor on your laptop has a refresh rate of 60 hz so that image transitions look smooth to the human eye. given the formula for the frequency output of a 555 timer and using only the values you have available to you, what is a possible combination of resistors and capacitors that will get you as close as possible to this value (note: you may use resistor values that could be made if you configure a set of resistors in series or parallel)?
The brain, not the eye, is what actually sees. Information is sent from the eye to the brain, but certain aspects of the signal are lost or changed in the process.
How fast can the human eye see?The human eye can perceive between 30 and 60 frames per second, according to some scientists. Some claim that the human eye cannot actually comprehend more than 60 frames per second.
Higher rates are seen as motion by the human visual system, which can process 10 to 12 pictures per second and perceive each one separately. The majority of participants in studies see modulated light (such a computer display) as steady when the rate is more than 50 Hz.
The screen will look smoother to the human eye the higher the number. This implies that a 120Hz display, which updates itself 120 times per second, would seem noticeably smoother and more natural than your typical 60Hz screen, which refreshes itself just 60 times each second.
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to prevent shoplifting, stores install security mirrors at the ceiling. a spherical mirror has a focal length of 25 cm. find its radius of curvature in cm.
Security mirrors are placed above the ceiling of establishments to deter stealing. A spherical mirror has a 25 cm focal length. R = 50 cm is the radius of curvature.
It has been found that the radius of curvature for spherical mirrors with small apertures is equivalent to double the focal length. R therefore equals 2f. It is evident that the main focus of a spherical mirror is located in the middle, halfway between the curvature's centre and the pole. A curve's radius of curvature at any given location is, roughly speaking, the radius of the circle that fits the curve there the best. One divided by the radius of curvature is the curvature, indicated by the symbol. You must locate the circle that fits that point the best in order to calculate the curvature there. The osculating circle is what's known as this. The reciprocal of the curve's curvature at that point is known as the osculating circle radius.
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To be launched, a glider is uniformly accelerated from rest by a cable pulled by a motor that exerts a horizontal force on the glider throughout the launch. The glider reaches its launch speed of 51.0 m/s after accelerating for 17.0 s. Assume that the glider moves horizontally until it leaves the ground. Calculate the total distance travelled by the glider before it leaves the ground.
The total distance travelled by the glider before it leaves the ground is 867 meters.
Velocity is the change in displacement divided by time taken. Here the displacement is unknown. The glider reaches its launch speed of 51.0 m/s after accelerating for 17.0 s. The velocity of the glider is 51.0 m/s and time taken is 17.0 s. The equation to calculate the total distance travelled by the glider before it leaves the ground is given below.
velocity = displacement/time
displacement = velocity*time
displacement = 17.0*51.0 = 867 meters
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two tiny particles having charges 20.0 μc and -8.00 μc are separated by a distance of 20.0 cm. what are the magnitude and direction of electric field midway between these two charges? (k
Between these two charges, there is an electric field with a magnitude and direction of 10.8 x 105 N/C along AB.
In this issue, we must charge the fee. Twenty micro colums make up Q 1, and eight micro coulons make up Q 2. There is a 20 centimeter gap between these two charges. At point p, which is the intersection of the two charges, we must determine the net electric field. The electric field at point p points away from the charge because of the positive charge. He, let's assume that the electric field is even and that it is caused by the second charge, electric field point along the charge: q 2- and that is the electric field e 2.
The net electric field at point p is now equal to e 1 plus 2 and is represented by the symbol a. Consider the direction away from Question 1 as positive; hence, the direction to the right is a positive direction. The electric field owing to eq, 1 equals the column, constant k times, k 1 over 0.5 times r square, and similarly for eq, 2, where q, 1 and q 2 are the absolute magnitude of the charge, the net electric field at point p equals p over 0.5 r square 0.5 r square times.
The net electric field at point at the midpoint between the 2 charges, equals 2.52 times 10 to the 7 newtons co coulan and the direction will be towards the negative charge towards the minus 8 coulomb judge micro cholum charge. The sum of the absolute magnitude of the 2 charges and the electric field at point p equals 9 times 10 to the 9 newton meter square per column square over 0.5 times 0.2 meter square times, 20 plus 8 times 10 to the minus 6 couul Thus, at the halfway point between the t charges, this will be the net electric field.
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prove that cubic expansivity is equal to 3 linear expansivity
The relationship between Linear Expansivity and Cubic Expansivity is as follows: Cubic / Volume expansivity = 3 Linear expansivity
Now, consider a sheet of metal of Length (l), Breadth (b), and Height (h). Let the initial Length be (l₁), the initial Breadth be (b₁) and the initial Height be (h₁). Let the final Length be (l₂), the final Breadth be (b₂) and the final Height be (h₂) after the metal is heated through a temperature change of θ.
Considering,
the initial volume of the metal be V₁ = l₁*b₁*h₁
and, the final volume of the metal be V₂ = l₂*b₂*h₂
Then,
Using the formula of linear expansivity,
l₂ = l₁ (∝∆θ + 1 )
b₂ = b₁ (∝∆θ + 1 )
h₂ = h₁ (∝∆θ + 1 )
Remember that Volume = l * b*h
Therefore,
V₁ = l₁*b₁*h₁
V₂ = l₂*b₂ *h₂
V₂ =l₁ (∝∆θ + 1 ) * b₁ (∝∆θ + 1 ) * h₁ (∝∆θ + 1 )
V₂ = l₁* b₁*h₁ (∝∆θ + 1 ) * (∝∆θ + 1 ) * (∝∆θ + 1 )
V₂ = l₁* b₁*h₁ ((∝∆θ * (∝∆θ + 1 ) + 1 * (∝∆θ + 1 ) ) * (∝∆θ + 1 )
Let's open the brackets, now we get,
V₂ = l₁* b₁*h₁(∝²(∆θ)² + ∝∆θ + ∝∆θ + 1 ) * (∝∆θ + 1 )
V₂ = l₁* b₁*h₁(∝²(∆θ)² + 2∝∆θ +1 ) * (∝∆θ + 1 )
V₂ = l₁* b₁*h₁(∝²(∆θ)² * (∝∆θ + 1 ) + 2∝∆θ * (∝∆θ + 1 ) +1* (∝∆θ + 1 ) )
V₂ = l₁* b₁*h₁(∝³(∆θ)³ +∝²(∆θ)² + 2∝²(∆θ)² + 2∝∆θ +∝∆θ + 1 )
V₂ = l₁* b₁*h₁(∝³(∆θ)³ +∝²(∆θ)² + 2∝²(∆θ)² + 3∝∆θ + 1 )
V₂ = V₁(∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 )
Remember that ,
V₂ = V₁ ( ϒ * ∆θ + 1 )
Let us substitute for V₂ in the above formula. Then we will get,
V₁ ( ϒ * ∆θ + 1 ) = V₁(∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 )
ϒ * ∆θ + 1 = ∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 (V₁ canceled V₁ and the brackets are removed)
ϒ * ∆θ = ∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ ( 1 cancelled 1 )
At this point,∝ tends to be zero because its value starts from 0.0000... Upward. Therefore,∝² and ∝³ are approximately zero. i.e. ∝² and ∝³ are = 0.
Therefore, we put zero in place of ∝² and ∝³. Now we get,
ϒ * ∆θ = 0*(∆θ)³ + 2*0*(∆θ)² + 3∝∆θ
ϒ * ∆θ = 0 + 0 + 3∝∆θ
ϒ * ∆θ = 3∝∆θ
ϒ = 3∝ ( ∆θ cancelled. ∆θ )
Therefore,
Cubic / Volume expansivity = 3 Linear expansivity
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an empty spherical weather balloon with a mass of 5.00 kg has a radius of 2.879 m when fully inflated with helium. it is to carry a small load of instruments with a mass of 10.0 kg. taking the density of air to 1.16 kg/m^3 and the density of helium to be 0.160 kg/m^3, will the balloon get off the ground?
Buoyant force is greater than the Net Weight. Thus it will get off the ground.
What is Density?Density is the substance which is defined as the measurement of the given mass per unit volume. It is represented by the formula
D = m/v
Where,
D = Density
m = Mass
v = Volume
Now
Helium Mass = Density × Volume
[tex]= 0.160\ kg/m^3 \times \frac{4}{3} \times \pi \times r^3\ m^3[/tex]
= 15.99 kg
Total Mass of the Balloon = Mass of the given Instruments + Mass of the given Helium Filled + Empty Mass of the given Balloon
Total Mass of the Balloon will be = 10.0 kg + 15.99 kg + 5.00 kg
= 30.99 Kg
Displaced air mass = Density × Volume
Displaced air mass [tex]= 1.16\ kg/m^3 \times \frac{4}{3} \times \pi \times r^3\ m^3[/tex]
= 115.89 Kg
Now,
Buoyant Force = Mass × 9.8
= 115.89 Kg × 9.8
Net Force = Mass × 9.8
= 30.99 kg × 9.8
Thus from the above conclusion we can say that the Buoyant force is greater than the Net Weight. Thus it will get off the ground.
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what is the difference between the dense, hot disks seen around some stars and the low-density, cold disks seen around some other stars? (select all that apply.)
The low-density, cold disks seen around some stars are distinct from the dense, hot disks found around some other stars because of their varied densities, temperatures, and positions.
- About circumstellar disc :
- A circumstellar disc (or circumstellar disk) is an accretion disk of matter in orbit around a star that has the shapes of a torus, pancake, or ring. It is made up of gas, dust, planetesimals, asteroids, or impact fragments. They are the sources of material where planets may form around the young stars.
- Gaseous clouds gradually collapse under the pull of gravity to become stars. As they fall toward the protostar, the atoms and molecules in the gas impart a slight rotation. The protoplanetary disk, a rotating plate of gas and dust, is produced by this rotation, which also gives the star its spin.
- A rotating circumstellar disk of dense gas and dust known as a protoplanetary disk surrounds a young, newly formed star, a T Tauri star, or a Herbig Ae/Be star.
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A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentum of -1.75 kg∙m/s. The two collide, stick together, and come to a complete stop after the collision.1) What was the total energy of the system before the collision?a- Not enough information to determineb- 6.13 Jc- 0 Jd- 12.25 J2) What was the total energy of the system after the collision?a- 6.13 Jb- 12.25 Jc- Not enough information to determined- 0 J3) What was the total momentum before the collision?a- 6.13 kg∙m/sb- 12.25 kg∙m/sc- Not enough information to determined- 0 kg∙m/s4) What was the total momentum after the collision?a- Not enough information to determineb- 0 kg•m/sc- 6.13 kg•m/sd- 12.25 kg•m/s
1)
[tex]\begin{gathered} E1=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_1v_2^2 \\ where: \\ m_1=m_2=0.25kg \\ v_1=7m/s \\ v_2=-7m/s \\ so: \\ E1=\frac{1}{2}0.25(7^2)+\frac{1}{2}0.25(7^2) \\ E1=6.125+6.125 \\ E1=12.25J \end{gathered}[/tex]Answer:
d. 12.25J
------------------------
2)
According to the conservation of energy:
[tex]\begin{gathered} E1=E2 \\ so: \\ E2=12.25J \end{gathered}[/tex]Answer:
b. 12.25
-------------------------------
3)
[tex]P1=m_1v_2+m_2v_2=+1.75-1.75=0[/tex]
Answer:
d. 0 kg∙m/s
-----------------------------------------
4)
Using conservation of momentum:
[tex]\begin{gathered} P1=P2 \\ so: \\ P2=0 \end{gathered}[/tex]Answer:
b. 0 kg•m/s
a new car is tested on a 290-m-diameter track. part a if the car speeds up at a steady 1.3 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration? express your answer with the appropriate units.
After 11 seconds the tangential acceleration becomes equal to the centripetal acceleration.
What is tangential acceleration?
Similar to linear acceleration, tangential acceleration is directed only in that direction. This has to do with rotational motion. As a result, tangential acceleration is the rate at which a particle's tangential velocity changes in a circular orbit. It always points in the direction of the body's tangent.
ac, also known as centripetal acceleration.
at is acceleration along a tangent.
The frictional force between the car wheel and the road surface supplies the necessary centripetal force when the vehicle moves in a circular motion over a curved path.
at=1.2m/sec2
The centripetal acceleration equation is given by,
ac=V2r
V2r=at
V2=at×r
V=√at×r ... (1)
Think of the equation for motion.
V=u+at×t
V=0+at×t
V=at×t
t=Vat
t=√at×ra2t
t=√rat
t=√1451.2
t=11seconds
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how much charge is on each plate of a 4.00-mf capacitor when it is connected to a 12.0-v battery? (b) if this same capacitor is connected to a 1.50-v battery, what charge is stored?
A charge of 4.8 x 10 5 C is present on each capacitor plate.
B. The capacitor has a 4.5 x 10 6 J energy capacity.
Describe the capacitor.
A capacitor is a device used to store electrical power and charge. It is composed of at least two separated electrical conductors. Although usually referred to as "electrodes," these electrical conductors are actually "capacitor plates." A capacitor is referred to as a "vacuum capacitor" if the space between capacitors is nothing more than a vacuum. However, the space is often filled with a dielectric, an insulating material. How much storage space a capacitor has is determined by its capacitance attribute.
A. Establishing the charge
Capacitor (C) = 4 F = 4 10 6
Voltage = 12 volts.
Charge (Q) = ?
Q = CV
Q = 4×10¯⁶ × 12
Q = 4.8×10¯⁵ C
B. Measuring the amount of energy the capacitor has stored.
Voltage (V) equals 1.5 V.
Energy (E) =? E = 12CV Capacitor (C) = 4 F = 410 6
²\sE = ½ × 4×10¯⁶ × 1.5²
E = 2×10¯⁶ × 2.25\sE = 4.5×10¯⁶ J
A. There is 4.8 x 10 5 C B of charge on each capacitor plate. The capacitor has 4.5 x 10 6 J of stored energy.
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How much work is done when a car is pushed 8 m with 160 N of force?
Answer: 1280 J
Explanation: Work is calculated by multiplying the displacement (8m) by the force (160 N) which will give you 1280 J (joule)
Please help me with this
Kinetic energy is a type of energy that is present in a particle or object in motion. When work, which entails the transfer of energy, is done on an object by applying a net force, that object acquires kinetic energy.
What does the term "kinetic energy" mean?The energy of motion is known as kinetic energy, and it can be observed in the motion of a particle, an object, or a collection of particles. A person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field are all examples of moving objects that consume kinetic energy.
There are five different types of kinetic energy: radiant, thermal, acoustic, electrical, and mechanical.
The kinetic energy unit is kg m 2 /s2, or mass times the square of speed. However, the units of kinetic energy are also the units of work, or joules, which are the units of force times distance. However, force is measured as mass times acceleration, or kg m/s2 kg m/s2.The Greek verb "to move" is the root of the term "kinetic." The word has more specific definitions in the realms of art and science, but when used in a generic sense, it may simply indicate "animated," "dynamic," or "lively" linguistically. Kinetic drawings, sculptures, and installations all make use of moving parts.To Learn more About Kinetic energy here-
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one way future space stations may create artificial gravity is by rotating the station at constant speed. consider a cylindrical space station 380 m in diameter that is rotating about its central axis. astronauts walk on the inside surface of the space station. if the centripetal acceleration at the wall of the station is to be equal to the acceleration due to gravity on the surface of the earth (ac
As a result, neither the astronauts nor the others sharing the space station can feel the force that supports them from the structure's solid surface.
Space stations are constantly in a free-fall situation, which means their acceleration is the same as the local gravitational acceleration. As a result, neither the astronauts nor the other space station residents can feel the support force generated by the station's solid surface.
Thus, by rotating the space station around its center, we produce center-directed forces from the space station's wall in the absence of gravity.
Gravitational acceleration is equal to centripetal acceleration.
A = g
r2 = g r 2 = /g r 2 = 9.81 m s 2/ 55 m 2 = 0.178 r a d 2 s/ 2 = 0.422 r a d / s
Therefore, the angular speed of the space station is 0.422 rad/s.
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An automobile travels for 90 minutes along a highway. The graph shows the progress of the automobile, with its start point designated as distance = 0 km.
As shown on the graph, at which two points does the automobile change speed?
points P and Q
points B and P
points A and B
points A and P
The change in the speed of the automobile occurred at points A to B.
What is change in speed of an object?
The change in the speed of an object is the rate at which the distance traveled by the object changes with time.
The change in speed of the object from point O to A is calculated as follows;
ΔV = Δx/Δt
where;
Δx is change in position of the objectΔt is change in timeΔV = (5 - 0) / (15 - 0)
ΔV = 0.333 km/min
The change in speed of the object from point A to B is calculated as follows;
ΔV = (15 - 5) / (30 - 15)
ΔV = 0.67 km/min
From this we can conclude that speed of the automobile changed at points O to A, A to B and B to P.
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use triangle,parallelogram and polygon method determine the resultant vector of a) 10km left,20km up b) 150km north,50km west c) 7km east,14km north
The resultant forces in each case is;
a) 22.3 Km
b) 158 Km
c) 15.7 Km
What is the resultant force?Let us note that the resultant force is the force that would have the same effect in magnitude and direction as the the two force that are acting together.
In this case we have been asked to find the resultant of the forces and we would use the triangle method.
a) R = √(10)^2 + (20)^2
R = 22.3 Km
b) R = √(150^2) + (50)^2
R = 158 Km
c) R = √(7)^2 + (14)^2
= 15.7 Km
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study a uniformly charged conducting sphere of 1.2 m diameter has a surface charge density of 8.1 mc/m2. (a) find the net charge on the sphere. (b) what is the total electric flux leaving the surface of the sphere?
The net charge on the sphere is 3.7×10⁻⁵C and the total electric flux leaving the surface of the sphere is 4.1×10⁶ N.m²/C.
What are electric flux and its measure?The distribution of the electric field or the velocity at which the electric field moves through a specific area can both be measured as electric flux. The Greek letter is used to represent electrical flux. Voltmeters (Vm), often known as Nm 2 C – 1, is the SI unit for electric flux.
Procedure:
(a) The charge on the surface of the sphere is the product of the surface charge density σ and the surface area of the sphere which is 4πr².
Thus, q=4πr²σ
= 4π(1.2m/2)²(8.1×10⁻⁶)
=3.7×10⁻⁵C
(b) We select a spherical-shaped Gaussian surface with a slightly greater radius that is concentric with the conducting sphere.
∅=q/∈°
= 4.1×10⁶ N.m²/C
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what quantity of heat energy is needed to melt 120g of ice at -20°C to water at 30°c? (SHC of water = 4200J/kg/k, SHC for ice = 2100J/kg/K, Specific latent heat of fusion of ice = 3.36x10^5 J/kg)
Answer:
59, 720 Joules
Explanation:
[tex]q = mc(t2 - t1) + m(lf) + mc(t2 - t1)[/tex]
first term=ice to 0 degrees
second term=water to ice
third term-water to 30 degrees
[tex]q = 0.12 \times 2100 \times 20 + 0.12 \times 3.36 \times {10}^{5} + 0.12 \times 4200 \times 30[/tex]
[tex]q = 59720 \: joules[/tex]
Which of the following equations illustrates the law of conservation of
matter?
A. 2H₂ + O₂ → H₂O
OB. 2H₂ + 202 → 2H₂0
OC. H₂ + O2 → H₂O
D. 2H₂ + O₂ → 2H₂O
SUBMO
Answer:
Explanation:
Answer : D that’s the answer
sound waves have entered natalie’s ear and traveled through to her auditory nerve. what process that will now take place in which she identifies what the sound is?
Sound waves have entered Natalie’s ear and traveled through to her auditory nerve. The process of perception took place in which she identifies what the sound is.
Perception is the ability to see, hear and become aware of something through the senses.
The process of interpreting a present stimulus based on past experience is called as perceptionSound waves from the environment enter the outer ear and are directed to the ear drum
The eardrum vibrates when sound waves are received, and the vibrations are sent to the oval window through the ossicles of the ear, .
From the oval window, these vibrations are transmitted to the fluid of the cochlea, where waves are generated in the lymph.
These waves generate vibrations in the basilar membrane that bends the hair cells and push them against the tectorial membrane, and hence are sent to the brain which gives signal to the organ to react.
Hence perception is used by Natalie to react.
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a 0.10-kg ball is moving at 7.0 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 12.0 m/s. what is the change in the magnitude of the momentum of the ball?
Change in momentum = -1.9 kg m/s
Momentum is the vector quantity because it has both magnitude and direction.
Momentum is given as the product of mass and velocity. It is represented as P = mv. Here, P is the momentum, m is the mass and v is the velocity.
Given,
Mass = 10 kgInitial velocity (U) = 7 m/sFinal velocity (V) = 12 m/sMomentum = MV
Initial momentum = MUFinal momentum = MVThe difference between the initial and final momentum will be the change of magnitude of the momentum.
To find the change in momentum,
Change in momentum = MV - MUTaking M as common
= M (V - U)
= 0.10 (-12 - 7)
= 0.10(-19)
= -1.9 kg m/s
Hence, the change in magnitude of momentum is -1.9 kg m/s.
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Select the correct answer. What is the average velocity of the particle from rest to 9 seconds? A. 1 meter/second B. 2 meters/second C. 3 meters/second D. 4 meters/second
The average velocity is 2 meters/second. Option B.
Explanation:
This average velocity can be found using the following formula:
v = x / DT
where:
x = displacement = 18 [meters]
dt = time interval = 9 [seconds ]
v = 18 / 9
v = 2 [m/s]
The average velocity of a particle moving from one point to another over a time interval is equal to the ratio of the displacement between the two points to the time it takes the particle to move that displacement. To find the average speed take the total distance traveled divided by the time interval. To find the average velocity. Since the displacement is always less than or equal to the distance traveled, the magnitude of the average velocity is always less than or equal to the average velocity.
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a spring with an mm-kg mass and a damping constant 5 (kg/s) can be held stretched 1 meters beyond its natural length by a force of 2 newtons. if the spring is stretched 2 meters beyond its natural length and then released with zero velocity, find the mass that would produce critical damping.
A spring with a damping constant 5 (kg/s) can be held stretched 1 meters beyond its natural length by a force of 2 newtons. The mass m = 3.12 kg that would produce critical damping
From hooke's law, force required to stretch the spring is
k (1) = 2
Spring Constant, k = 2
For critical damping, c²-4mk =0
m = c² / 4 k
c= damping constant (from question)
m = Mass to produce critical damping
There fore, m = (5²/4*2) = 3.12 kg
According to Hooke's law, the restoring force is equal to -kx, where k is a positive number known as the spring constant. Since c is a positive constant that is also known as the damping constant, we assume that the damping force is -c(dx/dt). Robert Hooke, an English scientist, developed the law of elasticity in 1660. According to Hooke's law, for relatively minor deformations of an item, the displacement or amount of the deformation is directly proportional to the deforming force or load.
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A block of mass m = 5.3 kg is pulled up a 0 21° incline as in the figure below with a force of magnitude F = 36 N.
(a) Find the acceleration of the block if the incline is frictionless. (Give the magnitude of the acceleration.)
3.28
m/s²
(b) Find the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.11. (Give the magnitude of the acceleration.)
The acceleration the block if the incline is frictionless is 3.28m/s² and the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.11 is 2.26 m/s².
what is newtons law of motion?
Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.
given:
mass of the block (m) = 5.3kg
angle of incline (x)= 21°
force exerted on the block up the incline (F) = 36 newtons
coefficient of kinetic friction = 0.11 u
a)
the sine component of the weight will act as the resistive force and will act against the 36 newtons force that is acting parallel to the incline.
i.e.
net force = 36 - (m × g × sin 21°)
m × net acceleration = 36 - 18.6
net acceleration = 17.4/5.3
net acceleration = 3.28 m/s²
b)
now in this case similarly the friction will also act against the intention of motion, such that:
net force = 36 - (m × g × sin 21°) - coefficient of kinetic friction ×m × g × cos 21°
net force = 36 - 18.6 - 5.33
net force = 12
net acceleration = 12/5.3
net acceleration = 2.26 m/s²
therefore, the acceleration the block if the incline is frictionless is 3.28m/s² and the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.11 is 2.26 m/s².
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The temperature of jordan lake is determined to be 13. 9ºc when an iron block is dropped in. The iron block is at 400 k and has a mass of 60 kg. Determine the heat transfer in kj of this process that is allowed to reach equilibrium.
This study reveals that only if the flow conditions in the holding tube are provided for comparison with commercial HTST systems can continuous laboratory and pilot-scale pasteurizers be utilized to evaluate the inactivation of microorganisms.
In order to make sure that laboratory or pilot-scale HTST apparatus meets the Pasteurized Milk Ordinance standards for pasteurizing milk and can be used for obtaining thermal inactivation data, we present a method in this study for calculating the fastest moving particle (FMP) and residence time distribution (RTD) in a pilot-scale high temperature, short time (HTST) pasteurizer.
The plate used in the pasteurizer had overall measurements of 75 x 115 mm, a thickness of 0.5 mm, and an effective diameter of 3.0 mm. The pasteurizer had standard hold tubes measuring 21.5 and 52.2 seconds, and its variable flow capacity ranged from 0 to 20 L/h.
FMP durations were established using tracer investigations, and flow parameters were established using RTD data. In comparison to the nominal timings of 21.5 and 52.2 s, respectively, the FMP times for the short and long holding sections using brine milk as the tracer were 18.6 and 36 s, respectively, at 72 degrees C.
According to the RTD investigation, the short hold section for whole milk at 72 degrees C had 45% back mixed and 55% plug flow.
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A small plane, starting from rest, much reach a speed of 33 m/s for takeoff.
A.) How long of a runway is needed if the plane has a constant acceleration of 3.0 m/s^2 during takeoff?
B.) How much time does it take for the plane to take off?
A.) Runway has to be 181.5 long.
B.) Plane takes 11 second for the plane to take off.
What is acceleration?Change in velocity (Δv) divided by the change in time (Δt), is called acceleration that can be represented by the equation
a = Δv/Δt.
This lets you measure how fast a velocity changes in (m/s^2). Acceleration a vector quantity, that is it has both magnitude and direction
Meter per second squared is the SI unit of acceleration.
Given, a small plane must reach a speed of 33m/s for takeoff, starting from rest and constant acceleration is 3.0m/s^2
Let the time be 't'
hence,
(33-0 )/t = 3
33 = 3t
t = 11 sec
Time taken by the plane to take off is 11sec.
Average velocity = (33 + 0)/t
= 16.5 m/sec
Distance = speed * time
= 16.5 * 11
= 181.5 m
Runway has to be at least 181.15 meters long.
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it takes a car 6.o seconds to slow down to a stop, and it travels 90 meters during this time. What was its initial velocity?
The initial velocity of the car, given that it takes 6.0 seconds to slow down to a stop is 30 m/s
How do I determine the initial velocity?The initial velocity of the car can be obtained by doing the following:
First, we list out the given parameters from the question. This is given below:
Time (t) = 6 secondsDistance (s) = 90 mFinal velocity (v) = 0 m/sInitial velocity (u) = ?Finally, we shall determine the initial velocity of the car as illustrated below:
s = (v + u)t / 2
90 = [(0 + u) × 6] / 2
90 = [u × 6] / 2
90 = 6u / 2
Cross multiply
6u = 90 × 2
6u = 180
Divide both sides by 6
u = 180 / 6
u = 30 m/s
From the calculations made above, we can conclude that the initial velocity of the car is 30 m/s
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what is the average angular acceleration of a blu-ray disc as it plays an 6.0-h set of movies? (assume the disk is scanned starting at its inner radius moving outward. express your answer to two significant figures.)
The average angular acceleration of a Blu-ray disc is 0.089 rad/s².
Angular acceleration refers to the time price of exchange of angular speed. As there are types of angular velocity, namely spin angular velocity and orbital angular velocity, Angular speed is the rate of change of angular displacement and angular acceleration is the rate of trade of angular pace.
Angular Acceleration is described as the time rate of change of angular velocity. it is usually expressed in radians in keeping with second in line with second. as a result, α = d ω d t. Angular acceleration is also known as rotational acceleration.
t = time duration = 6 h = 6 x 3600 sec
α = angular acceleration = (Wmax - Wmin )/t = (315 - 121)/(6 x 3600 ) = 0.089 rad/s²
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A cold duck slides down a snow covered hill inclined at an angle of 35° to the horizontal. If the ducks speed is a constant 5m/s, determine the horizontal and vertical components of its velocity.
Given data:
* The angle of the inclined plane is,
[tex]\theta=35^{\circ}[/tex]* The speed of the duck along the inclined plane is v = 5 m/s.
Solution:
The diagrammatic representation of the given case is,
From the triangle ABO,
[tex]\angle ABO=180^{\circ}-\angle AOB-\angle OAB[/tex]Substituting the known values,
[tex]\begin{gathered} \angle ABO=180^{\circ}-90^{\circ}-35^{\circ} \\ \angle ABO=55^{\circ} \end{gathered}[/tex]Thus, the inclined plane makes an angle of 55 degrees with the negative of the y-axis.
Similarly, the angle of the velocity of the duck along the inclined plane with the negative y-axis is 55 degrees.
Thus, the vertical component of the velocity is,
[tex]\begin{gathered} v_y=-v\cos (55^{\circ}) \\ v_y=-5\times\cos (55^{\circ}) \\ v_y=-2.88\text{ m/s} \end{gathered}[/tex]The horizontal component of the velocity is,
[tex]\begin{gathered} v_x=v\sin (55^{\circ}) \\ v_x=5\sin (55^{\circ}) \\ v_x=4.096\text{ m/s} \end{gathered}[/tex]Thus, the horizontal component of velocity is 4.096 meters per second, and the vertical component of velocity is -2.88 meters per second.
the work function of silver metal is 6.9 × 10-19 j. if a crystal of silver is exposed to a pulse of blue light with a wavelength of 450 nm, will electrons be ejected, and if so, what kinetic energy will they have?
Determine the energy of an ultraviolet photon with a wavelength of 250 nm using E = hc/(wavelength) . After that, deduct the Cs work function energy, e* (work function in volts)
The entire mass of a nucleus is described in Section 44.1's discussion of 12C is smaller than the total of each nucleon's separate masses. The confined system's (the nucleus') energy is lower than the sum of the rest energies of the nucleon separation. The binding energy of this difference in energy the nucleus and can be understood as the additional energy required for a nucleus.
To separate it into its constituent parts. Consequently, to divide a nucleus into protons and neutrons, the system needs to be supplied with energy. Energy conservation and the mass-energy equivalence principle of Einstein demonstrate that any nucleus's binding energy, measured in MeV, is where mn is the mass of the neutral hydrogen atom and M(H) is its atomic mass.
nuclear, M(AZX) is a representation of the isotope A's atomic mass.
and the ZX Atomic mass units are used for all masses. The weight of the Z electrons in M (H) within a narrow range, cancels the mass of the Z electrons in the phrase M(AZX).
Discrepancy related to the electrons' atomic binding energy. Because
nuclear binding energies and atomic binding energies are both generally several electron volts.
With energies in the millions of electrons volts range, this difference is small.
Using the formula E = hc/(wavelength), calculate the energy of a UV photon having a wavelength of 250 nm (wavelength). Subsequently, subtract the Cs work function energy, e* (work function in volts)
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alice and bill are at the top of a cliff of height h. both throw a ball with initial speed v0, alice straight down and bill straight up. the speeds of the balls when they hit the ground are va and vb. if there is no air resistance, which is true?
Alice and bill throw the ball with same speed [tex]V_{A}[/tex]=[tex]V_{B}[/tex].
What is the speed ?The speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Given that it just has a direction and no magnitude, speed is a scalar number.
Okay, so let's imagine that there are two persons, Bob and Alice, standing on the edge of a cliff. We want to know how the speeds compare when the balls strike the ground so that as throws her ball downward at a speed of v and bill throws his ball upward at a speed of v from the same height.
Bill's will therefore rise to this height, strike 0 at that point, and then descend again. When it reaches this height, it will really be moving at the same speed as when it left Bill's hand, just in the opposite direction.
As a result, it will appear as though you tossed it straight down at the same speed, which implies When they both strike the ground, Alice's and Bill's balls will do so at the same pace.
The trajectory of Bill's ball will be symmetrical about this point in terms of the velocity or have the same speed going up as it did coming down or coming down as it did up, if you look at it because there is essentially no air resistance or anything.
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The complete question is:
"Alice and Bill are at the top of a cliff of height H. Both throw a ball with initial speed v0, Alice straight down and Bill straight up. The speeds of the balls when they hit the ground are [tex]V_{A}[/tex] and [tex]V_{B}[/tex]. If there is no air resistance, which is true? A)[tex]V_{A}[/tex] <[tex]V_{B}[/tex] B) [tex]V_{A}[/tex]=[tex]V_{B}[/tex] C) [tex]V_{A}[/tex]>[tex]V_{B}[/tex] D) impossible to tell"