A mineral sample has a mass of 75 g. When the sample is dropped
into a graduated cylinder with a volume of 20mL, the volume of the
graduated cylinder rises to 40 mL. What is the density of the
sample?

The wavelength of these gamma rays will be  1x1[tex]10^{-13}[/tex] m.

How do you define wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.

The relationship between the wave's wavelength, frequency, and speed is given as

wavelength = speed of light ÷ frequency

wavelength = [tex]\frac{3 X10^8}{3.0 X10^{21}}[/tex]

wavelength = 1x[tex]10^{-13}[/tex] m

Hence the wavelength of these gamma rays will be [tex]1 X 10^{-13}[/tex]m.

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The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

The total quantity of heat required is calculated as follows;

q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)

q(tot) = mcΔθ₁  + mΔHf    +   mcΔθ₂

q(tot) = (100)(4.2)(0 - -45) + (334)(100)  + (100)(4.2)(75 - 0)

q(tot) = 18,900 J  +  33,400 J   +  31,500 J

q(tot) = 18.900 kJ  +  33.400 kJ   +  31.500 kJ

q(tot) = 83,800 J = 83.8 kJ

Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

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Answer:

q1 9.42

q2 226

q3 31.4

qtot 267

Explanation:

hope this help

Answer:

false mocktail is liquor yea

Answer:

268 nm

Explanation:

The equation needed to find wavelength is:

E = hc / w

In this equation,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.0 x 10⁸ m/s)

-----> w = wavelength (m)

To find the wavelength, you can plug the given values into the equation and simplify. Then, you can convert meters to nanometers.

E = hc / w

7.41 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J*s)(3.0 x 10⁸ m/s) / w     <---- Input given values

7.41 x 10⁻¹⁹ J = 1.9878 x 10⁻²⁵ / w                                   <----- Simplify

(7.41 x 10⁻¹⁹ J) x w = 1.9878 x 10⁻²⁵                                <----- Rearrange

w = 2.68 x 10⁻⁷ m                                                          <----- Simplify

 2.68 x 10⁻⁷ m           1 x 10⁹ nm
----------------------  x  ----------------------  = 268 nm
                                         1 m

The opportunity costs of working part-time while attending high school could be studying time, grades, and your own free time. It depends on the person, how they do in school, but if it were for me, I would say the benefits outweigh the costs. I have enough time to study and still get good grades in school.

Answer:

I don't know I'm rich student

Explanation:

sorry

Answer:

cf4, ch20,vhjuyu8hc hi l bro tap

[tex]\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}[/tex]

M is molarity here not metre

The average rate of appearance of H2 over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.

To find the average rate of appearance of [tex]\rm H_2[/tex], we can use the stoichiometry of the reaction to relate it to the rate of disappearance of [tex]\rm NH_3[/tex].

From the balanced equation: [tex]\rm 2NH_3(g) - > N_2(g) + 3 H_2(g)[/tex]

We can see that for every 2 moles of [tex]\rm NH_3[/tex] that disappear, 3 moles of [tex]\rm H_2[/tex] appear.

Given that the average rate of disappearance of [tex]\rm NH_3\ is\ 1.50\times10^{-6} M/s[/tex], we can calculate the average rate of appearance of [tex]\rm H_2[/tex] as follows:

Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x (Average rate of disappearance of [tex]\rm NH_3[/tex])

Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x [tex]\rm (1.50\times10^{-6} M/s)[/tex]

Average rate of appearance of [tex]\rm H_2[/tex] = [tex]\rm 2.25\times10^{-6} M/s[/tex]

Therefore, the average rate of appearance of [tex]\rm H_2[/tex] over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.

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The answer is .747

There are 5 main rules to determining what are and what are not significant figures.

NOTE: In any measurement, the last digit is always assumed to be estimated.

The number of significant figures retained may not exceed the least number of digits in either of the factors. There will always be the same number of significant figures in the answer as the factor with the least amount of digits.

Given:

[tex]9.635 /12.9 =?[/tex]

In the given problem, the number with the least amount of digits is 12.9. As we recall from above, all non-zero numbers are significant, therefore all of these numbers are significant. Hence, we should have 3 significant figures in our final answer.

Now we use a calculator to simply calculate the above and we obtain:

[tex]0.7468992248[/tex]

We want to have 3 significant figures, so we will take the first 3 significant figures in that answer, .746, and use that. We apply rounding properties and obtain our final answer of .747.

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Hydrogen, iron, and gallium is the correct answer. Hence, option B is correct.

An electron is a negatively charged subatomic particle.

Let us take another look at the periodic table. The periodic table is composed of metals, metalloids and nonmetals.

Metals lose electrons more easily, that is why they form cations. Metals are found on the left-hand side of the periodic table.

As we move away from the left-hand side of the periodic table, the ability to form cations decreases as metallic character decreases and elements become more nonmetallic.

The noble gas helium rarely loses electrons. Fluorine would rather accept an electron to form a negative ion.

Hence, the elements hydrogen, iron and gallium are metals hence they lose electrons more easily.

Hence, option B is correct.

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The study and understanding of the biological macromolecules impact our everyday life by making us know what to eat and the different processes which occur in the body.

These are cellular components of the body which are natural and vital for the growth and survival of organisms.

Examples include carbohydrates, protein etc which contain nutrients vital for our daily life.

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Answer:

CO contains polar covalent bond, because these atoms share unequal electrons.

Answer:

N₂

Explicacion:

Si la diferencia de electronegatividad es muy alta, por ejemplo entre un metal y un no metal, se forman enlaces iónicos

A hurricane is a type of severe cyclone formed when winds rotate as the pressure between low and high-pressure areas increases.

A cyclone is a violent storm that occurs when cyclone winds exceeds a speed of 74 miles (119 kilometers) per hour.

Hurricanes are classified according to their strength and catastrophic potential on a scale ranging from 1 to 5 (more violent).

In conclusion, a hurricane is a cyclone formed when a it rotates as the low and high-pressure areas increases.

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Answer:

2.73

Explanation:

2.72815277835894

i used an online converter lol it is much faster. if you'd like a step by step guide comment and ill give you one :)

Diamonds are composed of carbon in a tetrahedral lattice. That is option C.

A diamond of defined as an allotrope or one of the major forms of the element, carbon in nature.

These carbon atoms are arranged within the diamond in a face centered cubic tetrahedral lattice shape.

Therefore, Diamonds are composed of carbon in a tetrahedral lattice.

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Diamonds are composed of carbon in a tetrahedral lattice. The correct option is C.

Diamonds are one of the allotropes of carbon. The other allotrope of carbon is graphite.

Thus, diamonds are made up of carbon atoms that are tightly packed together. Each carbon atom in a diamond is strongly bonded to 4 other carbon atoms, resulting in the formation of a tetrahedral structure.

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Answer:

[tex]\huge\boxed{\sf 9812.16\ L\ of\ air}[/tex]

Explanation:

Given that,

A person breathes 6.814 L of air in a minute.

1 minute = 6.814 L

= 1 × 24 × 60 (24 hours in a day; 60 minutes in an hour)

= 1440 minutes

1 minute = 6.814 L of air

1440 minutes = 6.814 L × 1440

1 day = 9812.16 L of air

[tex]\rule[225]{225}{2}[/tex]

Cell signalling is a process by which cells communicate with each other and transfer messages.

A molecule inside or on the surface of a cell binds to a specific substance and causes a specific effect in the cell.

Cell signalling is a process by which cells communicate with each other and transfer messages. When a signal molecule binds to a receptor protein, changes occur in the receptor proteins. Two changes are listed below:

1. The receptor protein undergoes conformational changes and acts as an enzyme.

2. The receptor protein that makes a second messenger molecule that leads the reaction further to other cells or molecules.

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The time taken for the object to reach to top of pile is 0.012 year.

The time taken for the object to reach to top of pile is calculated as follows;

time of motion = distance traveled/speed

time of motion = (1.1 x 10¹⁴ x 10³ m)/(3 x 10⁸ m/s)

where;

time of motion = 3.67 x 10⁵ sec = 0.012 year

Thus, the time taken for the object to reach to top of pile is 0.012 year.

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Answer: 0.42 atm

Explanation:

For this problem, we are going to use the ideal gas law for pressure, which is [tex]P=\frac{nRT}{V}[/tex]. If you do not know yet, R is the ideal gas constant, [tex]0.0821\frac{L*atm}{mol*K}[/tex]First, we must find the number of CH₄ moles.

[tex]6.022gCH_{4} *\frac{1molCH_{4} }{16.043gCH_{4} } =0.38molCH_{4}[/tex]

Next, we will plug in our given information to the ideal gas law for pressure.

[tex]P=\frac{nRT}{V}[/tex]

[tex]P=\frac{0.38mol*0.0821\frac{L*atm}{mol*K} *402K}{30.0L} =0.42 atm[/tex]

The answer to this, according to the work done above, is 0.42 atm.

I hope this helps! Pls mark brainliest!! :)

The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is  0.413 atm.

Pressure of gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = ?

V = volume of gas = 30L

R = universal gas constant = 0.082 L·atm·K⁻¹·mol⁻¹

T = temperature of gas = 402 K

n is moles of gas & it will be calculated as:

n = W/M, where

W = given mass of CH₄ = 6.022g

M = molar mass of CH₄ = 16g/mol

n = 6.022 / 16 = 0.376mol

Now putting all these values on the above equation, we get

P = (0.376)(0.082)(402) / (30)

P = 0.413 atm

Hence required pressure of methane gas is 0.413 atm.

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Answer:

1.76 * 6.02*10^23 = 1.05952*10^24

1.05952*2 = 2.11904 *10^24 oxygen and 1.05952*10^24 sulfur atoms

In 1.76 moles of SO₂, there are approximately 1.06 x 10²⁴ SO₂ molecules, 1.06 x 10²⁴ sulfur atoms, and 2.12 x 10²⁴ oxygen atoms. For determining the number of SO₂ molecules, sulfur atoms, and oxygen atoms in 1.76 moles of SO₂, we need to use Avogadro's number, which is approximately 6.022 x 10²³ particles per mole.

1 mole of any substance contains Avogadro's number of particles, which includes atoms or molecules. Therefore, to find the number of SO₂ molecules in 1.76 moles, we can multiply 1.76 moles by Avogadro's number:

Number of SO₂ molecules = 1.76 moles × Avogadro's number

Number of SO₂ molecules = 1.76 moles × 6.022 x 10²³ molecules/mol

Number of SO₂ molecules ≈ 1.06 x 10²⁴ molecules

Next, we can find the number of sulfur atoms and oxygen atoms in 1.76 moles of SO₂. In one molecule of SO₂, there is 1 sulfur atom and 2 oxygen atoms. So, the total number of sulfur atoms and oxygen atoms can be calculated as follows:

Number of sulfur atoms = Number of SO₂ molecules × 1 sulfur atom/molecule

Number of sulfur atoms = 1.06 x 10²⁴ molecules × 1 sulfur atom/molecule

Number of sulfur atoms ≈ 1.06 x 10²⁴ sulfur atoms

Number of oxygen atoms = Number of SO₂ molecules × 2 oxygen atoms/molecule

Number of oxygen atoms = 1.06 x 10²⁴ molecules × 2 oxygen atoms/molecule

Number of oxygen atoms ≈ 2.12 x 10²⁴ oxygen atoms

So, in 1.76 moles of SO₂, there are approximately 1.06 x 10²⁴ SO₂ molecules, 1.06 x 10²⁴ sulfur atoms, and 2.12 x 10²⁴ oxygen atoms.

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Answer:

Explanation:

The equation says for every 3 moles of barium chloride you can make 2 aluminum chloride.

(8/3)*2 = 5.33 moles

%yield = actual/theoretical x 100%

%yield = 16/24 x 100%

% yield = 67%

Q=mcΔt

Q=66.3 x 0.93 x (67-23)

Q=2712.996 J

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]

[tex] \textsf{Q = heat evolved/absorbed = ??} [/tex]

[tex] \textsf{m = mass in gram = 66.3 g} [/tex]

[tex] \textsf{s = specific heat = 0.930 J/g °C} [/tex]

[tex] \textsf{ΔT = change in temp = 67 - 23 =44°C} [/tex]

[tex] \large\textsf{Find Q : } [/tex]

[tex]\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2713 \: \: joules[/tex]

[tex]\qquad \tt \rightarrow \:Q= 2.713 \: \: kj[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The B class main sequence star from the given images is Star 3.

B class main-sequence stars are of spectral type B and luminosity class V. They are very luminous and blue with surface temperatures between 10,000 and 30,000 K.

The stars that are blue as shown in the image are Star 1 and Star 3. However, Star is the one that has surface temperature between 10,000 and 30,000 K.

Therefore, Star 3 is a B class main sequence star.

In conclusion, stars are luminous objects with very high surface temperatures.

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Answer:

splenda

Explanation:

Hechar azucar no es del todo una buena opcion ya que puede poducir caries

John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.

Hence, Option C is correct answer.

Clouds are formed by the process of evaporation and which is followed by condensation. Clouds are small droplets of water crystallization which float in the air. When the moist air rises upwards then the formation of clouds take place because when air rises upwards it becomes colder.

Thus from the above conclusion we can ay that John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.

Hence, Option C is correct answer.

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Answer: Answer would be C I read the assignment and got it correct

Explanation:

The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

Vb = 19.8 mL

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Explanation:

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Answer:

D = m/V

Explanation:

Density represents the following ratio:

Density (D) = mass (m) / volume (V)

In this formula, the volume is being divided from the mass. The typical units for mass is grams and the unit for volume is milliliters.

The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

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If a Plum with a mass of 35 g contains 30 Cal of nutritional energy, then a  person should consume four plums to get 120 Cal of energy.

Finding the product of two or more numbers in mathematics is done by multiplying the numbers.

It is one of the fundamental operations in mathematics that we perform on a daily basis.

As given in the problem If a Plum with a mass of 35 g contains 30 Cal of nutritional energy, then we have to find out a person should consume how much plums to get 120 Cal of energy.

30 cal of nutritional energy = 1 plum

1 cal of nutritional energy = 1/30 plums

120 cal of nutritional energy = 120/30 plums

                                               = 4 plums

Thus,  a  person should consume four plums to get 120 Cal of energy.

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