. A microwave oven operates at 2.4GHz with an intensity inside the oven of 2500 W/m^2. What are the amplitudes of the oscillating electric and magnetic fields

Answers

Answer 1

Answer: A microwave oven operates at 2.4GHz with an intensity inside the oven of 2500 W/m^2. Then, the amplitudes of the oscillating electric and magnetic fields are, [tex]B_0=4.57*10^{-6} T and E_0=1.37*10^{3} V/m[/tex]

Explanation: To find the correct answer, we have to know more about the EM Waves.

What are EM waves?Electromagnetic waves can be defined as the waves, that can interact with the matter and are created as a result of vibrations of electric and magnetic fields.Maxwell theoretically predicted the existence of electromagnetic waves.A time varying magnetic field is a source of electric field.Similarly, an oscillating electric field gives rise to an oscillating magnetic field.The amplitudes of electric and magnetic fields can relate as,

                          [tex]E_0=cB_0[/tex]

The expression for intensity of electromagnetic waves in terms of amplitude of magnetic field can be written as,

                        [tex]I=\frac{1}{2u_0} cB_0^{2}[/tex]

How to solve the problem?From the above expression of intensity, we can find the expression for amplitude of magnetic field as,

                          [tex]B_0=\sqrt{\frac{2u_0I}{c} }=\sqrt{\frac{2*4*3.14*10^{-7}*2500 }{3*10^{8} } } =4.57*10^{-6} T[/tex]

Thus, from the amplitude of magnetic field, we get, the amplitude of electric field as,

                              [tex]E_0=cB_0=3*10^{8} *4.57*10^{-6} =1371 V/m[/tex]

Thus, from the above calculations, we get the amplitudes of the oscillating electric and magnetic fields are, [tex]B_0=4.57*10^{-6} T and E_0=1.37*10^{3} V/m[/tex]

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Related Questions

In separate experiments, a large number of particles (all with the same charge but with a wide variety of masses, speeds, and spin angular momentum) are fired into a region containing a uniform magnetic field. The velocities of the particles are all perpendicular to the field. What do the particles that move in orbits of the same radius have in common

Answers

The particles that move in orbits of the same radius have the same momentum.

Orbital angular momentum:

A point particle's three-dimensional angular momentum is traditionally represented by the pseudovector r p, which is the cross product of the particle's position vector r (relative to some origin) and momentum vector, which in Newtonian physics is denoted by p = mv.

L = mr[tex]V_{prep}[/tex] = mr²w is the particle's orbital angular momentum in units of magnitude. The part of the particle's velocity that is here perpendicular to the axis of rotation is designated as [tex]V_{perp.}[/tex] The right-hand rule indicates the direction of the angular momentum. In isolated systems, the angular momentum is conserved.

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If a force of F is applied to a mass m, the acceleration is a. If a force of F is applied to something that has a mass of 2m, the acceleration will be

Answers

Use formula (F) = mass × acceleration.

In this case: acceleration = [tex]\frac{F}{2m}[/tex]

A block of aluminium has a volume of 5.0 cm³ and a mass of 13.5 g. Calculate the density of the aluminium. Give your answer in g/cm³.

Answers

Explanation:

Soln:-

Given:-

Volume(v)=5.0cm^3

mass(m)=13.5 gm

density (d)=?

We know that,

d=v

=(13.5÷5)g/cm^3

=2.7g/cm^3

Hence, the required density of aluminum is 2.7g/cm^3.

What explains the dramatically different magnitudes of accelerations that result when a mosquito collides head on with a moving truck

Answers

Answer:

Mass of the vehicle and small bug.

Explanation:

By Newton's third law, force on bug and vehicle will be same when they collide with each other irrespective of their masses.But according to Newton's second law, force is mass times acceleration. Since the force on each mass is same, the smaller mass will accelerate more and the heavier mass will accelerate less for the same force.Therefore the acceleration of bug will be very greater than vehicle as the mass of the bug is very small as compared to vehicle.

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The refractive index of a new type of glass is 1.47. Calculate the speed of light when it passes through the new type of glass.

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The speed of light when it passes through the new type of glass is 2.04×10^8  m/s.

What is refractive index:

Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density.

The refractive index variable is denoted by the letter ' n '.

Here,

The refractive index of a new type of glass is 1.47

n = 1.47

The speed of light in air is c = 3×10^8 m/s

The formula for refractive index:

n = c / v

where v is the speed of light in new type of glass.

Substituting the values into the equation,

1.47 = 3×10^8 / v

v = 3×10^8 / 1.47

v = 2.04 ×10^8  m/s

Hence,

the speed of light when it passes through the new type of glass is 2.04×10^8  m/s

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How is pressure measured? question 1 options: pressure is measured as force per inch. pressure is measured as force per gram. pressure is measured as force per unit area. pressure is measured as force divided by mass.

Answers

Pressure is measured as force per unit area, which is the third option.

What is pressure?

Pressure is amount of force that is applied over a given area divided by the size of this area.

Pressure is calculated by multiplying the force applied on the object by the area covered.

Since force is measured in Newtons (N) and area is measured in m², the unit of pressure is Nm².

Therefore, pressure is measured as force per unit area.

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Which ion is formed when an atom of fluorine (F) gains one electron?

Answers

Answer:

fluoride ion

Explanation:

electric charge of negative 1

Suppose a bird flew east for 7.95 s and then abruptly turned and flew 161 m south, so that the magnitude of the bird's resultant displacement is 226 m. Calculate the magnitude of the bird's eastward component and its flying speed.​

Answers

The magnitude of the bird's eastward component is 158.6 m and its flying speed is 19.95 m/s.

Eastward component of the bird

The eastward component of the bird is calculated as follows;

226² = E² + 161²

E² = 226² - 161²

E² = 25,155

E = √25,155

E = 158.6 m

Speed of the bird

V = 158.6 m / 7.95 s

V = 19.95 m/s

Thus, the magnitude of the bird's eastward component is 158.6 m and its flying speed is 19.95 m/s.

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For a telescope of a particular size, the angular resolution is poorer at shorter wavelengths of light. True False

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Statement is False.

Angular Resolution is the smallest angle formed between any two close

objects that can be seen clearly when they are separated.

  The formula for Angular Resolution is:

              Angular Resolution = 1.22λ /a

            where,        λ = wavelength

                               a = telescope diameter

     So here we can see that angular resolution is directly proportional

      to the wavelength which means shorter wavelength will have poor

     resolution and larger wavelength will have large resolution.

       Therefore, the given statement is false.

   

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It is observed that in water the meniscus in the capillary tube is higher than the meniscus in the beaker,while in mercury the meniscus is lower than the meniscus in the beaker.explain these observations

Answers

Meniscus formed by water and mercury (In capillary tube and beaker):

Because the water wets the glass and seeps up the tube's side when it is contained in a glass tube, the meniscus (surface) of the water has a concave form. And in mercury, the meniscus is lower than the meniscus in the beaker because the intermolecular force between the mercury atom is stronger than the force within a wall of a container which is why mercury forms a lower meniscus.  

 

What are meniscus?:

The meniscus arises when the liquid and the container walls have different attractive forces acting on the molecules of the liquid.

A meniscus is created through adhesion, which is related to water's relatively high surface tension. The molecules in the glass beaker's wall are drawn to the water molecules. Whereas cohesion is the intermolecular attraction of similar molecules.

In water the meniscus in the capillary tube is higher than the meniscus in the beaker:  Because the glass pulls on the water molecules with a slightly stronger force than that which exists between the water molecules, the water and glass meniscus has a downward curvature. The glass's side is being dragged up with water.    While in mercury the meniscus is lower than the meniscus in the beaker: Because the mercury atoms are more strongly attracted to one another than the glass is to the mercury atoms, thus it results in an upwardly curved meniscus.

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A wire carrying a current of 26.9 A is bent into a circular arc with a radius of 0.6 cm that sweeps out 0.900 radians. What is the magnetic field at the center of the arc

Answers

The magnetic field at the center of the arc is 4 × 10^(-4) T.

To find the answer, we need to know about the magnetic field due to a circular arc.

What's the mathematical expression of magnetic field at the center of a circular arc?According to Biot savert's law, magnetic field at the center of a circular arc is B=(μ₀ I/4π)× (arc/radius²) As arc is given as angle × radius, so

        B=( μ₀I/4π)×(angle/radius)

What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?

B=(μ₀ I/4π)× (0.9/0.006)

  = (10^(-7)× 26.9)× (0.9/0.006)

  = 4 × 10^(-4) T

Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.

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An ideal spring is fixed at one end. A variable force F pulls on the spring. When the magnitude of F reaches a value of 49.1 N, the spring is stretched by 15.2 cm from its equilibrium length. Calculate the additional work required by F to stretch the spring by an additional 13.7 cm from that position.

Answers

When the spring is stretched by 15.2 cm = 0.152 m, the spring exerts a restorative force with magnitude (due to Hooke's law)

[tex]F = kx[/tex]

where [tex]k[/tex] is the spring constant. Solve for [tex]k[/tex].

[tex]49.1\,\mathrm N = k (0.152\,\mathrm m) \implies k \approx 323 \dfrac{\rm N}{\rm m}[/tex]

The amount of work required to stretch or compress a spring by [tex]x\,\mathrm m[/tex] from equilibrium length is

[tex]W = \dfrac12 kx^2[/tex]

Then the work needed to stretch the spring by 15.2 cm is

[tex]W_1 = \dfrac12 \left(343\dfrac{\rm N}{\rm m}\right) (0.152\,\mathrm m)^2 \approx 3.73\,\mathrm J[/tex]

and by 15.2 + 13.7 = 28.9 cm is

[tex]W_2 = \dfrac12 \left(343\dfrac{\rm N}{\rm m}\right) (0.289\,\mathrm m)^2 \approx 13.5\,\mathrm J[/tex]

so the work needed to stretch from 15.2 cm to 28.9 cm from equilibrium is

[tex]\Delta W = W_2 - W_1 \approx \boxed{9.76\,\mathrm J}[/tex]

The Toro Co. makes Toro snowblowers, Toro lawn mowers, Toro yard tools, and Toro sprinkler systems. The Toro Co. uses a ________ strategy.

Answers

The strategy:

The Toro Co. uses a family branding strategy.

What is family branding?

Family branding is a marketing tactic that emphasizes promoting the parent brand name while simultaneously advertising a family of goods and services. It is also sometimes referred to as "umbrella branding," which implies that all branding initiatives are carried out under the parent brand name.

In this case, the parent brand is Toro. The "Toro Motor Company" was founded in 1914 with the goal of producing tractor engines for The Bull Tractor Company. By acquiring Whirlwind Corp., Toro joined the push mower industry in 1948.

All the stated types of machinery are provided under the name of Toro, suggesting that the parent brand name is used to promote sales.

Thus, it is a case of family branding.

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What braking technique slows the vehicle as quickly as possible without locking brakes or losing traction

Answers

Answer: Cadence braking or Stutter braking is the braking technique slows the vehicle as quickly as possible without locking brakes or losing traction.

Explanation: To find the answer, we need to know more about the Cadence breaking.

What is cadence braking?It's a braking technique, that includes, pumping the brake pedal and which used to allow a vehicle to steer as well as brake on a slippery surface.It is used in the case of an emergency or sudden braking is needed.In this technique, traction is limited to reduce the effect of skidding from road wheels locking up under braking.

Thus, from the above given data, we can conclude that, Cadence braking or Stutter braking is the braking technique slows the vehicle as quickly as possible without locking brakes or losing traction.

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Consider the following situations:
A. A 2.5 kg physics book is resting on the edge of a table 1.4 m above the floor
B. A 10.0 kg backpack is on the floor beside the door
C.A 1 kg backpack is on the shelf that is 2.0 m above the floor
In which situation(A, B or C) is the potential energy the most?
OA
O
O
A, B and C all have the same potential energy
C
B

Answers

Given the data from the question, the potentiel energy is most in A

To obtain the correct answer to the question, we shall determine the potential energy in each case

How to determine the potential energy

PE = mgh

Where

PE is the potential energym is the massg is the acceleration due to gravityh is the height

Case A

Mass (m) = 2.5 KgHeight (h) = 1.4 mAcceleration due to gravity (g) = 9.8 m/s²Potential energy (PE) = ?

PE = mgh

PE = 2.5 × 9.8 × 1.4

PE = 34.3 J

Case B

Mass (m) = 10 KgHeight (h) = 0 mAcceleration due to gravity (g) = 0 m/s²Potential energy (PE) = ?

PE = mgh

PE = 2.5 × 0 × 0

PE = 0 J

Case C

Mass (m) = 1 KgHeight (h) = 2 mAcceleration due to gravity (g) = 9.8 m/s²Potential energy (PE) = ?

PE = mgh

PE = 1 × 9.8 × 2

PE = 19.6 J

SUMMARY

Potential energy in case A = 34.3 JPotential energy in case B = 0 JPotential energy in case C = 19.6 J

Thus potential energy is most in A

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Consider being at the top of cliff and throwing a book off the ledge. The book leaves at an angle of 52 degrees and a velocity of 16.0 m/s. If it moves through the air for 13.4 seconds, how far does it fall

Answers

The vertical distance through which the book falls is determined as 1,048.8 m.

Height of the book fall

The vertical distance through which the book falls is calculated as follows;

h = vt + ¹/₂gt²

where;

h is height of fallv is initial vertical velocityg is acceleration due to gravity

h = (16 x sin52)(13.4)  + (0.5)(9.8)(13.4²)

h = 1,048.8 m

Thus, the vertical distance through which the book falls is determined as 1,048.8 m.

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What is the speed of a wave that has a frequency of 173 hz and a wavelength of 2. 59 meters? express your answer to the nearest whole number.

Answers

Answer:

448m/s

Explanation:

velocity =frequency × wavelength

v= 173×2.59

v=448.07

v=448m/s

A 0.50 kg grenade explodes horizontally into three pieces. The first piece has a velocity of 10 m/s [N] and a mass of 0.10 kg. The second piece has a velocity of 5.0 m/s [S 10⁰ E ] and a mass of 0.20 kg. Find the velocity of the third piece.

Answers

The velocity of the third piece is mathematically given as

v=0.88m/s

What is the velocity of the third piece.?

Generally, the equation for conservation is  mathematically given as

[tex]m u=m_{1} v_{1 \mathrm{x}}+m_{2} v_{2 \mathrm{x}}+m_{1} v_{x}[/tex]

Here, is the mass of the grenade, [tex]m_{1}, m_{2}, m_{3}[/tex] the masses of the pieces after an explosion, and [tex]v_{1 \mathrm{x}}, v_{2 \mathrm{x}}[/tex] are velocities of the first and second pieces after the explosion.

[tex]m u_{1} &=m_{1} v_{1 x}+m_{2} v_{2 \mathrm{x}}+m_{3} v_{x} \\0 &=0+(0.2 \mathrm{~kg})((5 \mathrm{~m} / \mathrm{s})\\v_{x} &=\frac{-0.173 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.578 \mathrm{~m} / \mathrm{s}[/tex]

the equation for conservation

[tex]m u=m_{1} v_{1 y}+m_{2} v_{2 y}+m_{3} v_{y}[/tex]

[tex]m u_{1} &=m_{1} v_{1 \mathrm{y}}+m_{2} v_{x y}+m_{3} v_{y} \\0 &=(0.10 \mathrm{~kg})(10 \mathrm{~m} / \mathrm{s})+(0.2 \mathrm{~kg})\left((5 \mathrm{~m} / \mathrm{s}) \cos 10^{\circ}\right)+(0.3 \mathrm{~kg}) v_{y} \\v_{y} &=\frac{-1.98 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.661 \mathrm{~m} / \mathrm{s}[/tex]

In conclusion, the magnitude of the velocity

[tex]v=\sqrt{v_{\mathrm{x}}^{2}+v_{\mathrm{y}}^{2}}[/tex]

[tex]Substitute $-0.578 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{s}}$ and $-0.661 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{y}}$[/tex]

[tex]v &=\sqrt{v_{x}^{2}+v_{y}^{2}} \\&=\sqrt{(-0.578 \mathrm{~m} / \mathrm{s})^{2}+(-0.661 \mathrm{~m} / \mathrm{s})^{2}} \\&=0.88 \mathrm{~m} / \mathrm{s}[/tex]

v=0.88m/s

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Please Help!
The info below shows a kettle with its powers and the time they take to boil 500cm3 of water. If electricity costs 9p per unit, how much does it cost to boil 500cm3 of water using the 1.4kW kettle?

Kettle1= 1.4kW =4.5minutes

Answers

The cost of the 1.4KW kettle is 0.945 p.

What is the cost of electricity?

The cost of electricity is computed from the cost of electricity. We have to know the cost of electricity that is charged for the 1.4kW kettle.

Now let the power consumed=

1.4kW * 0.075 hrs = 0.105 KWhr

Then;

1 KWhr costs  9p

0.105 KWhr costs 0.105 KWhr *  9p/1 KWhr

= 0.945 p

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The info below shows three kettles with their powers and the time they take to boil 500cm3 of water. If electricity costs 9p per unit, how much does it cost to boil 500cm3 of water using the 3kW kettle?
Kettle 1= 3mins =3kW
Kettle 2= 3.5mins= 2.2kW
Kettle 3=4.5mins=1.4kW
Any help would be appreciated!

Answers

The cost of boiling 500cm3 of water using the 3kW kettle is 1.35 P.

Cost of electricity for 3 kW kettle

The cost is calculated as follows;

1 unit = 9p /kWh

Total energy consumed by 3 kW kettle, E = P x t

where;

P is power (kW)t is time in (hr)

E = 3 kW x (3 mins/60 mins/hr)

E = 0.15 kWh

Energy cost = 9 p/kWh x 0.15 kWh = 1.35 P

Thus, the cost of boiling 500cm3 of water using the 3kW kettle is 1.35 P.

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At which point is the velocity the greatest? at which points is the velocity 0 m/s? at which point is the acceleration 0 m/s2? at which points is the acceleration the greatest?

Answers

As per the image: The velocity is maximum at B. The velocity is O at C and A. The acceleration will be O at B

The acceleration is maximum at C and A.

How can it be said?

Two sketches are shown in the attached image. The first one is based on the principle of energy conservation, and it is simple to understand when the velocity is at its highest and when it will be zero.

The pendulum is at its highest height in points A and C relative to the reference point, giving us the most potential energy. Additionally, all of the potential energy had been converted into kinetic energy by the time the pendulum reached point B, therefore this is where its maximum velocity would be.

The second sketch, which displays a free body diagram of the pendulum when it is producing a theta angle with respect to the vertical plane, is shown for the acceleration analysis. Applying Newton's second law and taking into account the forces acting on the pendulum, we arrive at the equation shown in the picture.

With the knowledge that the equation will be zero (0) when the angle theta is 0, we can see that the acceleration, which has the same direction as the velocity, relies on the sin(theta). It implies that at point B, the acceleration will be 0. and at points Cand A, maximum.

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A ball at the top of a hill is an example of ______ and a ball rolling down the hill is an example of ______.

Answers

Potential energy , Kinetic energy

What is kinetic energy and potential energy?

Kinetic energy is a form of energy that posses by an object due to its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

Potential energy is the energy held by an object due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

According to given condition,

At first,

When a ball is at the top of a hill , it posses a potential energy because the ball is at some height from the surface  where  the energy held by ball is due to its position.

That is why,  a ball at the top of a hill is an example of Potential energy.

Secondly,

When a ball is rolling down the hill , it posses kinetic energy because the ball have some energy that posses by an object due to its motion.

That is why, a ball rolling down the hill is an example of  Kinetic energy.

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A person on a ferry boat walks from one side of the ferry to the other. Their velocity is 1.5m/s[W] relative to the ferry. The ferry is travelling at 5.0m/s [S] relative to the shore. Determine the persons velocity to the shore.

Answers

The person's velocity relative to the shore is determined as 6.5 m/s.

Velocity of the person

The velocity of the person is calculated as follows;

V(p/f) = V(p) - V(f)

where;

V(p/f) is the velocity of the person relative to the ferryV(p) is the velocity of the personV(f) is velocity of the ferry

1.5 = V(p) - 5

V(p) = 6.5 m/s

Thus, the person's velocity relative to the shore is determined as 6.5 m/s.

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A large glass marble is added to the displacement can. 20 3 of water overflows into a beaker, and the displacement can now has a mass of 872 .
Calculate the density of glass.

Answers

The density of the glass can be determined using the formula:

Density of the glass = (Mf - Mi)/20 cm³

What is density?

Density is defined as the ratio of mass and volume of a substance.

Density = mass/volume

The mass of the glass = Final mass of beaker  - initial mass  of beaker (Mf - Mi)

The initial mass of the beaker is not given.

Volume of the glass marble = 20 cm³

Density of the glass = (Mf - Mi)/20 cm³

Therefore, the density of the glass is determined from the ratio of the mass and volume of the glass.

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fill in the blank ,if a charge body touches the disc of an uncharged electroscope the leaves ------------------​

Answers

Answer:

leaves will deverge

Explanation:

because of the nagwtive charge will become positive

Sunlight reflects from a concave piece of broken glass, converging to a point 18 cm from the glass. What is the radius of curvature of the glass

Answers

Radius of curvature of the concave mirror is 36 cm.

To find the answer, we need to know about the relation between focal length and radius of curvature.

What's the relation between the radius of curvature and focal length?Mathematically, focal length= radius of curvature/2Radius of curvature= 2× focal lengthWhat's the focal length of the concave mirror when sunlight converges to 18cm?When light from a far distance incident on a concave mirror, it converges to the focus point.As the sun light comes from very far distance, so it is converging to the focus point. So focal length= 18 cm.What's the radius of curvature of the concave mirror?

Here, radius of curvature= 2×18 cm = 36cm

Thus, we can conclude that the radius of curvature of the concave mirror is 36cm.

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What is the average force needed to change the velocity of 20,000 kg
bus from rest to 15 m/s in 10 seconds?
O 5,000 N
O 10,000 N
O 20,000 N
O 30,000 N

Answers

Answer:

d)30,000 N

Explanation:

Solution:

mass(m)=1000kg

initial velocity (u)=0m/s

final velocity (v)=15m/s

So,

acceleration (a)=(v-u)/t

=(15-0)/10

=1.5m/s^2

Atlast,

Force(F)=m×a

=20000×1.5

=30,000 N

Carefully place a prepared slide of diatoms on the stage, and focus using low power. What kind of specimen are you looking at

Answers

Under the low-power microscope, the kind of specimen Diatoms is Holotype.

What is Holotype Specimen?A solitary actual example of an organism known to have been utilized during the conventional portrayal of the species is known as a holotype.It is either the sole occurrence of this sort of actual model, however, it is explicitly recognized as the holotype.What are Diatoms?Diatom slides are often created by letting the suspension of diatoms settle out overnight on a coverslip, as explained below. It can take up to two days for this to disseminate the diatoms evenly on the coverslip, though.The frustule, a silica (hydrated silicon dioxide) cell wall, that surrounds diatoms is a distinctive aspect of their anatomy.

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A spring with a spring constant of 59.5 N/m is attached to different masses, and the system is set in motion. What is its period for a mass of 2.3 kg

Answers

Time period for the mass 2.3 kg is 1.23s.

To find the answer, we need to know about the time period of a spring mass system.

What's the expression of time period of a spring mass system?Mathematically, time period= 2π/ angular frequencyAs angular frequency= √(k/m),

time period= 2π×√(m/k)

k= spring constant and m= massWhat's the time period, if the spring constant and mass are 59.5N/m and 2.3 Kg respectively?

Time period= 2π×√(2.3/59.5)

= 1.23 s

Thus, we can conclude that the time period of the spring mass system is 1.23 s.

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1. Sang Hee rubs a balloon on her hair until, when she holds the balloon several inches from
her head, her hair sticks straight out and touches the balloon. Then she holds the balloon
several inches from Kim's hair. Some of Kim's hair rises and sticks out toward the balloon,
even though the balloon hasn't touched her hair. Explain what made Kim's hair do this. Go
into detail about charges and how they are likely arranged. State the process that charged
the balloon and the hair of each girl.

Answers

The reason why Kim's hair rises and sticks out is due to electrostatic attraction.

What is charging by friction?

We know that one of the ways in which a body is able to acquire static charges is by friction. When a body is rubbed against another, there could be loss or gain of charges leaving a net charge on each body.

The process that occurs when some of Kim's hair rises and sticks out toward the balloon, even though the balloon hasn't touched her hair is electrostatic attraction.

Learn more about charging by friction:https://brainly.com/question/9201910

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