A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and 272.0 N (54.4 lbs) stand on the board so that the board is balanced.
What is the upward force exerted on the board by the support?

The best way to arrange the salon to best use what he has is:

This refers to the change in direction of a wavefront between two different media so that the wavefront returns to its originating medium.

Hence, we can see that from our knowledge of shadows and reflection, we can note that mirrors reflect and light helps to bring detail in a dark area and the chairs should be facing the mirrors directly so the customer can see his hair and how it is being cut by the barber.

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(a)The acceleration of the ball, while it is in flight, will be 9.81 m/s².

(b) The velocity of the ball when it reaches its maximum height will be 0 m/sec.

(c) The initial velocity of the ball is 20.30 m/s upward.

(d) The maximum height it reaches will be 21.00 m

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is;

u is the initial velocity of fall = ? m/sec

h is the distance of fall = ? m

g is the acceleration of free fall = 9.81 m/sec²

a.

The acceleration of the ball, while it is in flight, is equal to the acceleration due to gravity,g=9.81 m/s².

b.

The ball's velocity will be zero when it has reached its highest point.

c.

The initial velocity of the ball is;

v=u-gt

0=u-gt

u=gt

u=9.81 m/s² × 2.07 sec

u=20.30 m/s

d.

The maximum height it reaches is found by the formula as;

[tex]\rm u^2 = - 2gh \\\\ (20.30)^2 = -2 \times (-9.8) \times h \\\\ 412.09 = 19.6 \times h\\\\ h = 412.09/19.6\\\\ h = 21.00 m[/tex]

Hence the acceleration of the ball,s the velocity of the ball when it reaches its maximum height, the initial velocity of the ball, and the maximum height it reaches will be 9.81 m/s²,0 m/sec,20.30 m/s, and 21.00 m respectively.

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Answer:

See below

Explanation:

speed = freq * wavelength

          =  5 Hz    * .6 m = 3 m/s

speed = freq * wavelength

   3      =   freq  *  .4 m         freq = 7.5 hz

1. The speed of the waves is 3 m/s. 2. for a wavelength of 0.4 m, the frequency would be 7.5 Hz.

To find the speed of the waves, we can use the equation:

[tex]\[ \text{Speed} = \text{Frequency} \times \text{Wavelength} \][/tex]

Given that the frequency is 5 Hz and the distance between successive crests (wavelength) is 60 cm, we need to convert the wavelength to meters:

[tex]\[ \text{Wavelength} = 60 \, \text{cm} = 0.6 \, \text{m} \][/tex]

Plugging in the values, we have:

[tex]\[ \text{Speed} = 5 \, \text{Hz} \times 0.6 \, \text{m} = 3 \, \text{m/s} \][/tex]

Therefore, the speed of the waves is 3 m/s.

Now, to find the frequency at which the wavelength is 0.4 m, we rearrange the equation:

[tex]\[ \text{Frequency} = \frac{\text{Speed}}{\text{Wavelength}} \][/tex]

Substituting the given values:

[tex]\[ \text{Frequency} = \frac{3 \, \text{m/s}}{0.4 \, \text{m}} = 7.5 \, \text{Hz} \][/tex]

Thus, for a wavelength of 0.4 m, the frequency would be 7.5 Hz.

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It reasonable to expect that anyone would be able to make good sense of a filing system as it reduces the overall storage space occupied by the records.

This is the process of keeping document safely and being able to easily retrieve them.

The new filing system is based on their volume which is why the space is reduced thereby reducing the ambiguity.

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The frictional force of air resistance is; 949N while the force of friction underwater is; 1859N.

The frictional force on the action rock can be evaluated as follows;

F - W = ma

However, the acceleration of fall a can be evaluated as follows;

a = (12² -0²)/2× 15

a = 144/30 = 4.8m/s².

a) Hence, the air resistance, frictional force, F = (65×9.8) + (65 ×4.8)

F = 949N.

b) When reaches a depth of 2.5m, it follows that the acceleration is;

a = (0²-12²)/(2×2.5)

a = 144/5 = 28.8m/s².

On this note, the force balance is;

F + 650 = 65(9.8 + 28.8)

F = 2509 - 650

F = 1859N.

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Explanation:

Supernovae play a fundamental role in a great cosmic recycling program. We believe that almost all of the elements in the Universe that are heavier than hydrogen and helium are created either in the centres of stars during their lifetimes or in the supernova explosions that mark the demise of larger stars.

From the calculation, the banking angle is obtained as 11.5°.

The banking angle refers to the angle at which the vehicle must be inclined so that it does not skid off the road.

Now we have;

θ = ?

v =  61.0 m/s

r = 1860 m

g = 9.8 m/s^2

θ = tan-1(61^2/ 1860 * 9.8)

θ = tan-1(3721)/18228

θ = 11.5°

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For an emf source with a magnitude of E = 120.0 V, is mathematically given as

Q=136.63uC

Parameters

Generally, the equation for voltage on the resistor is mathematically given as

Vr=IR

Therefore

Vr=71*0.95

Vr=67.45V

voltage on capacitor

Vc=120-67.45

Vc=52.55V

In conclusion,

Q=CVc

Therefore

Q=52.55*2.60

Q=136.63uC

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The vertical weight carried by the builder at the rear end is F = 308.1 N

Given that:

The weight is carried up along the plane in rotational equilibrium condition

The torque equilibrium condition can be used to solve

We can note that the torque due to the force of the rear person about the position of the front person = Torque due to the weight of the block about the position of the front person

This would lead to:

F(W*cosθ) = mgsinθ(L/2) + mgcosθ(W/2)

F(1cos20)= 197/2(3.10sin20 + 2 cos 20)

Fcos20= 289.55

F= 308.1N

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Answer:

Approximately [tex](-4.9\times 10^{2}\; {\rm N})[/tex] (rounded to two significant figures.)

Explanation:

The impulse [tex]\mathbf{J}[/tex] on an object is equal to the change in the momentum [tex]\mathbf{p}[/tex] of this object. Dividing impulse by duration [tex]\Delta t[/tex] of the contact would give the average external force that was exerted on this object.

If an object of mass [tex]m[/tex] is moving at a velocity of [tex]\mathbf{v}[/tex], the momentum of that object would be [tex]\mathbf{p} = m\, \mathbf{v}[/tex].

Let [tex]m[/tex] denote the speed of this ball. Let [tex]\mathbf{v}_{0}[/tex] denote the velocity of this ball before the contact, and let [tex]\mathbf{v}_{1}[/tex] denote the velocity of the ball after the contact.

Momentum [tex]\mathbf{p}_{0}[/tex] of this ball before the contact: [tex]\mathbf{p}_{0} = m\, \mathbf{v}_{0}[/tex].

Momentum [tex]\mathbf{p}_{1}[/tex] of this ball after the contact: [tex]\mathbf{p}_{1} = m\, \mathbf{v}_{1}[/tex].

Impulse, which is equal to the change in momentum:

[tex]\mathbf{J} = \mathbf{p}_{1} - \mathbf{p}_{0} = m\, \mathbf{v}_{1} - m\, \mathbf{v}_{0}[/tex].

Since the velocity of the ball after the contact is in the [tex](-x)[/tex] direction, [tex]\mathbf{v}_{1} = -20.0\; {\rm m\cdot s^{-1}}[/tex]. The average external force on this ball would be:

[tex]\begin{aligned} \mathbf{F} &= \frac{\mathbf{J}}{\Delta t} \\ &= \frac{m\, \mathbf{v}_{1} - m\, \mathbf{v}_{0}}{\Delta t} \\ &= \frac{m\, (\mathbf{v}_{1} - \mathbf{v}_{0})}{\Delta t} \\ &= \frac{0.145\; {\rm kg} \times ((-20.0\; {\rm m\cdot s^{-1}}) - 14\; {\rm m\cdot s^{-1}})}{0.010\; {\rm s}} \\ &\approx -4.9 \times 10^{2}\; {\rm N}\end{aligned}[/tex].

(Rounded to two significant figures.)

The magnitude is 13.12 mV.

The steps are attached below.

The standard SI unit of the magnetic field is the tesla (T). As an end result, we can use these equations and the equation for an induced emf due to changes in magnetic flux, ϵ=−NΔϕΔt ϵ = − N Δ ϕ Δ t, to calculate the importance of a precipitated emf in a solenoid.

The magnitude of the precipitated contemporary depends on the rate of trade of magnetic flux or the fee of reducing the magnetic area strains.

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Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

[tex]E_{k} = \frac{1}{2} mv^{2}[/tex]

[tex]E_{k} = \frac{1}{2} (700)(10)^{2}[/tex]

[tex]E_{k} = \frac{1}{2} (700)(100)[/tex]

[tex]E_{k} = (350)(100)[/tex]  OR [tex]E_{k} = \frac{1}{2} (70000)[/tex]

[tex]E_{k} = 35000[/tex]

Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

Explained in the attachment !

Answer:

6.39 × 10^23 kg

.........

The net force on the canoe is obtained as 65.0 N [forward]

The frictional force is the force that opposes motion. We know that the net force is the actual force that moves the canoe in a given direction.

Hence, the total force acting in the forward direction = 60.0N + 90.0N = 150 N and the total backwards force =  85.0N

Net force =  150 N - 85.0N = 65.0 N [forward]

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The free body diagram showing the forces acting on block A is diagram 3; option C.

Free body diagrams are simple diagrams which are used to illustrate the magnitude and direction of the forces acting on the body.

The diagram of the crane and boxes as well as the free body diagrams are shown in the attached image.

Three forces are acting on A as follows:

Therefore, diagram 3 is correct.

In conclusion, free body diagram shows the forces acting on a body as well as their direction of action.

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Answer:

I think C is the correct answer

Explanation:

Answer:

76.52

Explanation:

the density of gas is 1.775kg/m^3 at 27 degree celcius and pressure of 10^-5n/m^2. if the specific heat capacity at constant pressure is 846 jkg^-1k^-1, the ratio of specific heat capacity at constant pressure to tht constant volume​ is 76.52

Density is  the mass of a unit volume of a material substance. The formula for density is represented by d = M/V, where d is density, M is mass, and V is volume.

It is commonly represented in units of grams per cubic centimeter. Density can also be expressed as kilograms per cubic meter .

Density can used to define how different materials interact when mixed together. For example Wood floats in water because it has a lower density, while an anchor sinks because the metal has a higher density.

density can be applied in pipe design, shipbuilding, helium balloons, weight distribution in the aeroplane, and the fact that ice floats on water.

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Answer:

Given,

Frame rate = 25 frames per second

To find,

Time interval between one frame and the next.

Solution,

We can simply solve this numerical problem by using the following process.

Now,

Number of frames = 25

Total time taken to display the given number of frames (ie. 25 frames) = 1 second

To calculate the time interval between one frame and next, we need to divide the time taken to display total number of frames by total number of frames.

So,

Time interval between one frame and next :

= Time taken to display total number of frames / Total frames

= 1/25

= 0.04 second

Hence, time interval between one frame and next is 0.04 second.

The gravitational attraction between them will be 6.6 × 10 ⁻⁶ N.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Given data

Mass of object 1,m = 80 kg

Mass of object 2,M = 50 kg

Gravitational constant,G = 6.6 × 10⁻¹¹ kg⁻² m²

Distance of seperation,R = 0.2 m

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

[tex]\rm F = G\frac{mM}{R^ 2} \\\\ F = 6.6 \times 10^{-11 }\times \frac{80 \times 50 }{(0.2)^2} \\\\F = 6.6 \times 10^{-6 } \ N[/tex]

Hence the gravitational attraction between them will be 6.6 × 10 ⁻⁶ N.

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Answer:

98,000 pa

Explanation:

The formula for water pressure is as follows:

[tex]pressure = pgh[/tex]

Where p is the density of water (in kg/m3), g is the gravitational field strength, and h is the height of the water.

The density of water is 1000kg/m3, the gravitational field strength is 9.8, and the height is 10. Substituting in these values:

[tex]pressure = 1000 \times 9.8 \times 10[/tex]

[tex]pressure = 98000[/tex]

The period or time duration of these waves is 0.16 sec. While the wave velocity is 18m/sec.

Wavelength may be defined as the space between equivalent points in the contiguous cycles of a waveform signal propagated in the area or along a wire.

The time duration of these waves is calculated by the given formula:

T = [tex]\frac{1}{F}[/tex] = [tex]\frac{1}{6}[/tex] = 0.16 seconds.

The velocity is calculated by the given formula:

V= Wavelength × Frequency = 6Hz × 3m = 18m/sec.

Therefore, it is well described above.

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Considering the definition of kinetic energy, the housefly has a kinetic energy of 0.00242 J.

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and in a rest position, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its rest state by applying a force to it.

The kinetic energy is represented by the following expression:

Ec= ½ mv²

Where:

In this case, you know:

Replacing in the definition of kinetic energy:

Ec= ½ ×0.00100 kg× (2.20 m/s)²

Solving:

Ec= 0.00242 J

Finally, the housefly has a kinetic energy of 0.00242 J.

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Answer:

5 m /s^2

Explanation:

Change in velocity = 35 - 10 = 25 m/s

change in time = 5 s

decelleration = 25/5 = 5 m/s^2

Behaviorism approach centers on giving absolute prominence to the outside characters of individuals

Psychoanalysis approach centers on fact the fact that the unconscious has the potential to drive our behavior

Interestingly, the behaviorists and psychoanalysts share some common norms and values in such away that

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Answer:

Southwest. The electric force on this electron would point southwest (opposite to the direction of the electric field.)

Explanation:

Consider a position in an electric field. A positive point charge placed at that position would experience an electric force from this field. By definition, the direction of this field at that position would be the same as the direction of electric force that the field exerts on the positive point charge placed at that position.

It is given that the electric field in this question points to the northeast in this region. Thus, a positive point charge placed in this region would experience an electric force in the same direction- to the northeast.

Electrons are negatively charged. The direction of electric force on an electron would be opposite to that on a positive point charge placed at the same position. The electric force on a positive point charge in this region points to the northeast (same as the direction of the electric field). The opposite of northeast is southwest. Hence, the electric force on an electron at this position would point to the southwest.

The force constant of the spring is determined as 14,222.2 N/m.

Apply the principle of conservation of energy,

K.E = U

where;

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv²/x²

Where;

k = (2000 x 8²)/(3²)

k = 14,222.2 N/m

Thus, the force constant of the spring is determined as 14,222.2 N/m.

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The emf of the battery will be 2.955 V. The rate of change of magnetic flux linked with the coil is responsible for generating emf.

Electromagnetic induction is what causes the induced voltage. Electromagnetic induction generates emf (induced voltage) by subjecting a conductor to a magnetic field.

Given data;

Voltage,v = 200 v

Resistance, r=600 ohms

Internal resistance,R = 3 ohms

The EMF of the battery is found as follows;

E = {vR}/{R+r}

E = 200×3/(3 + 200)

E = 2.955 V

Hence, the emf of the battery will be 2.955 V.

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The angular frequency of the oscillation is determined as 2.7 rad/s.

ω = √k/m

With respect to spring constant k1 and k2

k1 + k2 = 9.5 N/m + 5 N/m = 14.5 N/m

ω = √14.5/2 = 2.7 rad/s

Thus, the angular frequency of the oscillation is determined as 2.7 rad/s.

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The Sketch  of the figure will bear the parameters of the charge that lies   at (4,0,0)

Generally, the equation for is  mathematically given as

1)

Since both of the other points, "q1"<"q2," are on the x-axis, the third one must also be on the x-axis, and it must be close to the charge of lesser magnitude. off q1 by x cm

Now, forces on q3 due to q1

[tex]\vec{F}_{1}=\frac{k q_{1} q_{3}}{x^{2}} \hat{x}[/tex]

Force on q3 due to q2

[tex]\vec{F}_{2}=\frac{k q_{2} q_{3}}{(6+x)^{2}}(-\hat{x})[/tex]

[tex]\quad \vec{F}_{1}+\vec{G}_{2}=0$[/tex]

[tex]&\frac{k q_{1} q_{3}}{x^{2}}-\frac{k q_{2} q_{3}}{(x+6)^{2}}=0 \\&\frac{2}{x^{2}}=\frac{8}{(x+6)^{2}} \Rightarrow \frac{x+6}{x}=\sqrt{\frac{8}{2}}=2 \\&x+6=2 x \Rightarrow x=6 \mathrm{~cm}[/tex]

In conclusion, the charge lies at (4,0,0)

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