A 300 kw load has a trailing power factor of 0.65. The reactive power required in order to improve the power factor to unity is 346.12kVAR
Given Power of load (P) = 300KW
power factor = 0.65
We know that kVA = KW/cosФ
kVAR = kVA sinФ
sin = √1-cos^2Ф
here kVA is apparent power(S)
KW is active power(P)
kVAR is reactive power(Q)
cosФ = power factor
S = P/cosФ = 300/0.65 = 461.5kVA
sinФ = √1-(0.65)^2 = 0.75
Now Q = (461.5)(0.75) = 346.12kVAR lagging
the additional load is capacitive
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Problem 22.51 A slab of insulating material has thickness 2d and is oriented so that its faces are parallel to the yz- plane and given by the planes crd and = -d. The y- and 2-dimensions of the slab are very large compared to d, so treat them as infinite. The slab has charge density given by p(x) = po (c/d)', where po is a positive constant. Part A Using Gauss's law, find the magnitude of the electric field due to the slab at the center of the slab 2 = 0). Express your answer in terms of some or all of the variables po, d, 3 and electric constant Eo. IV ALQ R O O ? Ex=0 = Submit Request Answer Part B Identify direction of the electric field due to the slab in different areas. Drag the labels to their appropriate locations in the diagram. Labels can be used once, more than once, or not at all. O va 0 d
The magnitude of the electric field due to the slab at the center of the slab 2 = 0) is rho X³/ 3d²E.
An electric field is a physical field that surrounds a charged particle and exerts a force on all other charged particles in the field, causing them to attract or repel. It also refers to the physical field of a charged particle system.
Calculation:-
The equation can be written as for the slab at centre is E = rho X³/ 3d²E.
An electric field can be defined as the region of space around a charged particle or object in which the charged body experiences a force. For example, Electric fields are created by charges and their components such as capacitors and battery cells. An electric field can be thought of as an electrical property associated with any point in space where some form of electric charge exists.
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a child is riding on a merry-go-around. as the speed of the merry go round is doubled, the magnitude of the centrpetal focr acting on the chuild
What is a centripetal force ?
A force could be a force that produces a body follow a incurvate path. Its direction is usually orthogonal to the motion of the body Associate in Nursingd towards the fastened purpose of the fast center of curvature of the path.
A centripetal force is a web force that acts on an object to stay it moving on a circular path.
Centripetal vs Centrifugal Force. the most distinction between centripetal force and force is that solely the previous will actually be delineate as a “force.”
A Merry-go-round.
The Gravitron.
Tetherball.
A construction Swing.
Turning during a car.
Planet Earth.
Discus Throw.
V' = 2V
Centripetal force
F' = m V'2 / r
m( 2V)2 / r
= 4mv2 / r
Hence final centripetal force is 4mv2 / r
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a 50 g ball of clay traveling at speed v0 hits and sticks to a 1.0 kg brick sitting at rest on a frictionless surface.
The percentage of mechanical energy lost (converted into thermal energy) during the collision will be equal to 95.2%.
What is kinetic energy?Kinetic energy is the term used in physics to describe the force that a moving item has.
It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.
As per the information in the question,
Ball's mass, m₁ = 50 g = 0.05 kg
Speed = v₀
Brick's Mass, m₂ = 1 kg
Assume the speed of the brick after the collision is v.
Use the equation of the principle of conservation of linear momentum,
[tex]m_1v_o+m_2u_2= v(m_1+m_2)[/tex]
0.5(v₀) + 0 = v(1 + 0.05)
v = (0.05v₀)/1.05
v = 0.048v₀.
Then the total kinetic energy will be:
K.E(initial) = 1/2 × 0.05v₀² + 1/2 × 0.05 × 0²
K.E(initial) = 0.025v₀²
Then,
K.E(final) = 1/2 × (1.05) × (0.048v₀)²
K.E(final) = 0.0012v₀²
So, the amount of mechanical energy lost in collision,
= (0.025v₀² - 0.0012v₀²)/0.025v₀² × 100
= 95.2%.
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This question seems incomplete, the complete question may be:
A 50 g ball of clay traveling at speed vo hits and sticks to a 1.0 kg brick sitting at rest on a frictionless surface. a. Find an expression for the speed of the brick after the collision in terms of vo. b. What percentage of the mechanical energy is lost (i.e. converted to thermal energy) in this collision?
Do different metals expand by different amounts for the same rise in temperature?
Yes, different metals expand by different amounts for the same rise in temperature. This is because different metals have different coefficients of thermal expansion, which is a measure of how much a material expands when it is heated. This means that when two different metals are heated by the same amount, they will expand by different amounts.
For example, if a metal with a high coefficient of thermal expansion is heated by 10 degrees Celsius, it will expand by a larger amount than a metal with a low coefficient of thermal expansion that is heated by the same amount. This means that different metals will expand by different amounts for the same rise in temperature, depending on their specific properties.
Additionally, the expansion of metals can also be affected by factors such as the initial temperature of the metal and the rate at which it is heated. This means that the expansion of a given metal can also vary depending on the specific conditions under which it is heated. Overall, different metals will expand by different amounts for the same rise in temperature, depending on their specific properties and the conditions under which they are heated.
an archer shoots an arrow. consider the action force to be exerted by the bowstring against the arrow. the reaction to this force is the question 39 options: friction of the ground against the archer's feet. grip of the archer'shand on the bow. air resistance against the bow. arrow's push against the bowstring.
This means that if object 1 hits object 2, object 2 will also hit object 1 with the same amount of force.
It is given that the string exerts a force on the arrow during the shooting of an arrow.
From Newton's third law, the arrow should also apply a force on the string. Thus, the reaction force is, arrow's push against the bowstring. Option (a) is correct.
The third law states that the two equal and opposite forces act on the two bodies in the system.
This means that if object 1 hits object 2, object 2 will also hit object 1 with the same amount of force.
The third law also satisfies the gravitational force between the two objects. The attractive force between the two objects is the same for both. Depending on their masses, their accelerations may vary, but the pull force between them remains the same.
Complete question:An archer shoots an arrow. Consider the action force to be the bowstring against the arrow. The reaction to this force is the:
A. arrow's push against the bowstring
B. weight of the arrow
C. air resistance against the bow
D. grip of the archers hand on the bow
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Two lamps, one with a thick filament and one with a thin filament of the same material, are connected in parallel to a battery. The current is
a) larger in the lamp with the thin filament
b) the same in both lamps
c) larger in the lamp with thick filamentc
The two lamps, the one with a thick filament and one with a thin filament of the same material, are connected in parallel to a battery. The current is the same in both lamps.
The correct option is b
Current is a drift of electrical fee vendors, commonly electrons or electron-poor atoms. The commonplace image for modern is the uppercase letter I. the same old unit is the ampere, symbolized by way of A.
An electric current is a float of charged particles. In metal conductors the charged particles are unfastened electrons. The electrons are free to transport from one ion to another and a internet glide of those electrons in one path is an electric modern-day.
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The speed of a sound wave in air depends on
A) its wavelength.
B) All of the above choices are correct.
C) None of the above choices are correct.
D) the air temperature.
E) its frequency.
Option C. None of the above choices are correct, A sound wave in air moves at a certain speed depending on its frequency. None of the wavelengths above it. all the aforementioned air temperatures. ambient temperature.
Under the same physical conditions, the speed of sound is constant for all frequencies in a particular medium. Since the distance covered by the sound wave in a given amount of time is what determines the speed of sound, it can be calculated using the following formula: where v is the velocity, is the sound wave's wavelength, and f is the frequency. Since the distance covered by the sound wave in a given amount of time determines the speed of sound, the following formula can be used to calculate it: Where v is the speed, is the sound wave's wavelength, and f is the frequency.
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a student is asked to determine the mass of jupiter. knowing which of the following about jupiter and one of its moons will allow the determination to be made? i. the time it takes for jupiter to orbit the sun ii. the time it takes for the moon to orbit jupiter iii. the average distance between the moon and jupiter
By knowing i. the time it takes for Jupiter to orbit the sun and ii. the time it takes for the moon to orbit Jupiter's mass of Jupiter can be determined. Therefore options I and II are correct.
To determine the mass of Jupiter, the student needs information about both Jupiter's orbit around the Sun (I) and the moon's orbit around Jupiter (II).
By knowing the time it takes Jupiter to orbit the Sun (I) and the time it takes for the moon to orbit Jupiter (II), the student can use Kepler's Third Law of Planetary Motion.
This law relates the orbital period and the average distance of a moon from its planet to the mass of the planet.
By knowing both the orbital periods of Jupiter and its moon (I and II) and the average distance between the moon and Jupiter (III is not required), the student can calculate the mass of Jupiter using Kepler's Third Law.
Therefore options I and II are correct.
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A 64 kg male ice skater is facing a 41 kg female ice skater. They are at rest on the ice. They push off each
other and move in opposite directions. The female skater moves backwards with a speed of 3.6 m/s. What is
the velocity of the male skater?
From conservation of linear momentum, the magnitude of the forward velocity of the male skater is 2.31 m/s
What is Momentum ?Momentum can simply be defined as a product of mass and velocity. It is a vector quantity.
Given that a 64 kg male ice skater is facing a 41 kg female ice skater. They are at rest on the ice. They push off each other and move in opposite directions. The female skater moves backwards with a speed of 3.6 m/s.
According to Newton's third law, in any action, there will be equal and opposite reaction.
The velocity of the male skater can be known from the conservation of linear momentum. That is
MV = mu
Where
M = mass of the male = 64 KgV = male speed = ?m = mass of the female = 41 Kgu = female speed = 3.6 m/sSubstitute all the parameters into the formula
64 × V = 41 × 3.6
V = 147.6 / 64
V = 2.31 m/s
Therefore, the velocity of the male skater is 2.31 m/s in the opposite direction.
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The ___________ was used to find a Jupiter-sized planet through careful measurements of the changing position of a star in the sky.
A planet the size of Jupiter was discovered using the astrometric approach by taking meticulous measurements of how a star's location changed over time.
A planet the size of Jupiter was discovered through astrology. use exact measurements of a star's shifting sky position. Its goal is to track the motion of such bodies against the background of other stars, making this technique the best for discovering very big planets that are orbiting stars other than their own. Big astral bodies, stars that are nearby, and astral bodies that are close to Earth are the greatest targets for this technique. Measurement is the quantifying of characteristics of an event or thing so that they can be compared to those of other events or objects.
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A car is accelerating horizontally at a rate of 2.5 m/s. A mass of 250 g is hanging from the ceiling on a string 1.2 m long. The angle that the string makes with the vertical is A. 14.3° toward the back of the car. B. 76° toward the back of the car. C. 7° toward the front of the car. D. 14.3° toward the front of the car. E. 0°, or straight down.
The correct answer is D. 14.3° toward the front of the car.
When a car accelerates horizontally, the forces acting on a mass hanging from the ceiling will cause the mass to swing in a circular path. The angle that the string makes with the vertical is determined by the centripetal acceleration of the mass, which is given by the equation:
a = v² / r
where a is the centripetal acceleration, v is the velocity of the mass, and r is the radius of the circular path.
In this case, the radius of the circular path is the length of the string (1.2 m), and the velocity of the mass is the velocity of the car (2.5 m/s). Plugging these values into the equation gives us a centripetal acceleration of:
a = (2.5 m/s)² / 1.2 m = 6.25 m/s²
The angle that the string makes with the vertical can be calculated using the tangent function:
tan(A) = a / g
where A is the angle, a is the centripetal acceleration, and g is the acceleration due to gravity (9.81 m/s²).
Plugging in the values for a and g gives us the following:
tan(A) = 6.25 m/s² / 9.81 m/s² = 0.636
Solving for A gives us:
A = [tex]tan^{-1(0.636)}[/tex] = 14.3°
Since the string is hanging toward the front of the car, the angle A is towards the front of the vehicle as well, so the correct answer is D. 14.3° toward the front of the vehicle.
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Suppose you make a new kind of compact disk that is the same thickness as a current disk but twice the diameter. By what factor will the rotational inertia increase? Idisk= 1/2MR^2 8 2 16
If you make a new kind of compact disk that is twice the diameter of a current disk but has the same thickness, the rotational inertia of the new disk will increase by a factor of 8.
Rotational inertia, also known as moment of inertia, is a measure of an object's resistance to changes in its rotational motion. It is given by the formula:
I = 1/2 * m * r^2where I is the rotational inertia, m is the mass of the object, and r is the distance from the axis of rotation to the mass of the object.
If you double the diameter of a compact disk but keep the thickness the same, you are effectively doubling the distance from the axis of rotation to the mass of the disk (since the disk is the same thickness). This means that the rotational inertia of the disk will increase by a factor of 8 (2^2), since it is proportional to r^2.
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determine the kc expression for the reaction above by identifying what belongs in the numerator and what belongs in the denominator:kc
In the Kc expression, the concentration of the product is always placed at the numerator while the concentration of the reactant is placed in the denominator.
The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.
Kc is an equilibrium constant that is dependent on concentrations of reactants and products and is defined as.
Kc = [product]÷[reactant]
Consider a reaction
A + B ------> C + D
So its Kc expression will be as
Kc = [C].[D] ÷[A].[B]
So, The concentrations of the product always place at the numerator while the concentration of the reactant is placed in the denominator.
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You are changing lanes in traffic on a multiple-lane street. As you start to steer into the other lane, you should:
a. Slow down slightly
b. Maintain the same speed
c. Increase your speed quickly
d. Increase your speed slightly
The correct option is A. Slow down slightly, Before going right, give the right signal, check the driver's outside mirror, and turn your head to the right. On a roadway with several lanes, you are changing lanes in traffic.
On a roadway with several lanes, you are changing lanes in traffic. Maintain the same pace as you begin to turn into the opposite lane. The tracks your vehicle's rear tyres leave when rounding a corner are almost always narrower than the tracks your front tyres leave. To change your course, you can either do a two-point turn, a U-turn, or circle the block counterclockwise. You can most effectively reduce your risk by On a street with multiple lanes, the one you are in is blocked in front of you.
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a pulley on a friction- less axle has the shape of a uniform solid disk of mass 2.50 kg and ra- dius 20.0 cm. a 1.50 kg stone is attached to a very light wire that is wrapped around the rim of the pul- ley (fig. e9.47), and the system is released from rest. (a) how far must the stone fall so that the pulley has 4.50 j of kinetic energy? (b) what percent of the total kinetic energy does the pulley have?
The system's potential energy will be lost because it is no longer at rest, while its kinetic energy will increase.
Therefore,
Loss in potential energy = gain in (kinetic energy of the pulley + kinetic energy of the stone) ...........…..(1)
Let, the stone falls by a distance of h.
Given, the mass of the pulley disk mₚ = 2.50 kg
Its radius r = 20.0 cm = 0.2 m
Its moment of inertia I = (1/2)mₚr²
I = (1/2)(2.50 kg)(0.2 m)²
I = 0.05 kgm²
Given, the kinetic energy of the pulley disk = 4.50 J
If w the angular velocity of the pulley,
(1/2)Iw² = 4.50 J
(1/2)(0.05 kgm²)w²= 4.50 J
w² = 9/0.05 rad²/s²
w² =180 rad²/s²
v² = 180(0.2)^2 m²/s²
v² = 7.2 m²/s²
Given, the mass of the stone mₛ = 1.50 kg
Its kinetic energy = (1/2)(1.50 kg)(7.2 m²/s²) = 5.4 J
Potential energy loss of the stone = (1.50 kg)(9.80 m/s²)h
(a) Therefore, from equation (1), w get
(1.50 kg)(9.80 m/s²)h = 4.5 J + 5.4 J
h = (9.9 J)/(1.50 kg)(9.80 m/s²)
h = 0.673 m
So, the stone must fall by a distance of 0.673 m.
(b) Total kinetic energy of the system = 9.9 J
The kinetic energy of the pulley = 4.50 J
The pulley’s fraction of kinetic energy = 4.50 J/9.9 J
= 0.455 = 45.5%
Therefore, the pulley has 45.5% of the total kinetic energy.
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Disk A has a weight of 5 lb and Disk B has a weight of 10 lb. If no slipping occurs between them,
determine the couple moment M which must be applied to Disk A to give it an angular acceleration of 4 rad/s
2
. Radius A is 0.5 ft. Radius B is 0.75 ft.
The couple moment M = 0.233 lb.ft
Given,
The weight of disc A = 5 lb
The radius of disc A = 0.5 ft
The weight of disc B = 10 lb
The radius of disc B = 0.75 ft
Angular acceleration of disc A = 4 rad/s²
Let,
The couple moment = M
Disc A:
∑[tex]M_{A} = I_{A} \alpha_{A}[/tex]
M - F(0.5) = (1/2)(5/32.2)(0.5)²(4)
2M - F = 0.078 ..........................(1)
Disc B:
∑[tex]M_{B} =I_{B} \alpha _{B}[/tex]
F = (1/2)(10/32.2)(0.75)²[tex]\alpha _{B}[/tex] .............(2)
[tex]r_{A} \alpha _{A} =r_{B} \alpha _{B}[/tex]
0.5(4) = (0.75)[tex]\alpha_{B}[/tex] .....................................(3)
By solving equations (1), (2), and (3) we get
M = 0.233 lb.ft
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A riverside warehouse has several small doors facing the river. Two of these doors are open. The walls of the warehouse are lined with sound-absorbing material. Two people stand at a distance L=150 from the wall with the open doors. Person A stand along a line passing through the mid-point between the open doors, and person B stands a distance y=20m to his side. A boat on the river sounds its horn. To person A, the sound is loud and clear. To person B, the sound is barely audible. The principal wavelength of the sound waves is 3.00 m. Assuming person B is at the position of the first minimum, determine the distance d between the doors, center to center.
The distance d between the doors, center to center is 11.3m
Location. of A = central. maximum, location. of B = first. minimum.
ΔY = [Ymin - Ymax] = λL/d (0 + 1/2) - 0 = 1/2 λL/d = 20m
distance d = λL/40m = 3 * 150/40 = 11.3m
The length of a particular path between two points, such as the distance walked through a maze, is what is referred to as an object's "distance traveled" [6]. Even a ball thrown straight up or the Earth after it completes an orbit can be considered as having a closed distance along a closed curve that begins and ends at the same location. As the curve's arc length, this is formalized mathematically.
A distance can also be signed, with a forward distance being positive and a backward distance being negative.
When constructing automobiles or mechanical gears, designers should take into account circular distance, which is the distance covered by a point on a wheel's circle (see also odometry). The wheel's circumference measures.
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which of the following statements describe an exothermic reaction? [select all that apply.]group of answer choiceshrxn < 0hproducts > hreactantsthe bonds that are broken during the reaction are stronger than the bonds that are formed during the reaction.the bonds that are broken during the reaction are weaker than the bonds that are formed during the reaction.
The bonds that are broken during the reaction are weaker than the bonds that are formed during the reaction and ∆Hrxn < 0
For exothermic reaction we know that Hpreducts < Hreactants
∆Hrxn = Hproducts - Hreactants
so, ∆Hrxn < 0 , Energy is released while bond formation and energy is absorbed while bond breaking. In exothermic reaction energy is released, it indicate in exothermic reaction bonds that formed is stronger than bonds that are broken.
A chemical reaction that releases energy is called an exothermic reaction. A chemical reaction that stores energy is called an endothermic reaction. More energy might be released as products form than the energy needed to break the reactants apart.
Less energy might be released as the products form than the energy needed to break the reactants apart. This chemical reaction stores energy. In other words, it will be an endothermic reaction.
More energy is released during the chemical reaction than is needed to start the chemical reaction. It takes less energy to break the reactant bonds than the energy released as the products form.
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FILL IN THE BLANK. a capacitor uses an____field to store potential electric energy which can be used as a power source when connected to a network.
A capacitor uses an electric field to store the potential electric energy which can be used as a power source when connected to a network.
A capacitor is characterized as a latent part which is utilized for putting away electrical energy. A capacitor is made of two conduits that are isolated by the dielectric material. These dielectric materials are as plates which can aggregate charges. One plate is for a positive charge while the other is for a negative charge.
The energy put away in a capacitor is only the electric possible energy and is connected with the voltage and charge on the capacitor. In the event that the capacitance of a guide is C, it is at first uncharged and it obtains a potential distinction V when associated with a battery. In the event that q is the charge on the plate around then,
q=CV
Therefore,Work done=Vdq
=>dW=(q/C)dq
=>dW=[tex]\int\limits^q_ 0[/tex](q/C)dq
=>dW=(1/2)q²/C
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A concert loudspeaker suspended high above the ground emits 35 W of sound power. A small microphone with a 1.0 cm2 area is 50 m from the speaker. a. What is the sound intensity at the position of the microphone? b. How much sound energy impinges on the microphone each second?
a. The sound intensity at the position of the microphone is .
b. The sound energy impinges on the microphone each second is .
The sound pressure level where the microphone is located is 1.11mW/m2. 90.46dB of sound energy impinges on the microphone every second. Acoustic intensity, also referred to as sound intensity.
Is the amount of energy carried by sound waves in a direction perpendicular to the region of the wave that they are travelling. The watt per square metro (W/m) is the SI unit of intensity, which also covers sound intensity.
Given,
Sound's force P = 35 W
50 meter's separate the speaker of a mobile phone from its little microphone.
Sound intensity at a cellphone is I = P/A.
I am equal to 35/4*pi*r2 and 35/4*pi*(502).
I = 1.11mW/m^2
The sound pressure level where the microphone is located is b = 10log(I/Io).
b = 10log(0.00111/10-12), b = 90.46 dB.
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two handheld radio transceivers with dipole antennas are separated by a large fixed distance. if the transmitting antenna is vertical, what percentage of the maximum received power will appear in the receiving antenna when it is inclined from the vertical by the following angles?
A transceiver is a combination transmitter/receiver in a single bundle. while the time period normally applies to wireless communications gadgets, it is able to also be used for transmitter/receiver devices in cable or optical fiber structures.
The electricity of the antenna is given by,
The resistance of the antenna is steady, for this reason,
Pa(avy
Now the voltage difference is,
AV = Bjcos8
consequently, the voltage distinction is directly proportional to t
cosine of the angle.
AVecosé (because B and/are constant)
subsequently, the electricity received,
Paces
therefore, if the angle of the willing is 14.three°, then the
acquired electricity by the antennas,
Pm c0s414,3°=0,93899
Paw
93.9%
if the perspective of the inclined is 45°, then the
obtained electricity by means of the antenna is,
SP price a5¢=05
Pan
50%
if the perspective of the inclined is 90°, then the
received energy with the aid of the antennas,
Pn cos? 9%=
Paw
= 0.0%
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A driver notices that her 1380-kg car, when in neutral, slows down from 95 km/h to 65 km/h in about 7.0 s on a flat horizontal road. Approximately what power (watts) is needed to keep the car traveling at a constant 80 km/h? Approximately what power (hp) is needed to keep the car traveling at a constant 80 km/h?
.The power of the car is 12.8 watt or 0.017 hp.
Work done per unit time is power of a machine. It is a scalar quantity. Its S.I. unit is watt(w). Energy change is equal to power.
1 hp is equal to 746 w.
The given is,
mass of car = 1380 kg
Initial velocity V1 = 65km/s
Final velocity V2 = 80 km/s
Time t = 7 s
change in kinetic energy = 1/2m ( -v12 = 1/2 ×(80-65) J
= 1/2×180
= 90 J
This is equal to work done.
Now. power = W/t
90/7 = 12.8 w
So the power is 12.8 w = 12.8/ 746 w
0.017 hp.
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jocelyn was researching what makes certain surfaces have mirror-like qualities. she knows that most mirrors are made from aluminum, as are soda cans. she wondered why she can see her face in a mirror but not in a soda can. fill in the correct words to complete the sentences. the mirror is polished smooth, so that reflection occurs. the soda can, however, has a rougher surface, so that reflection occurs.
The Mirror is polished smooth so that specular reflection occurs. The soda can have a rougher surface, so that diffusion reflection occurs.
What is specular reflection?Diffuse reflection reflects light in a variety of directions, as opposed to specular reflection, which reflects all light that comes from a single direction at the same angle.
The incident light is only reflected in one outgoing direction during specular reflection. On a surface known as a specular surface, which resembles a mirror, light reflects at the angle of incidence.
The finest example of specular reflection is found in mirrors, which have a highly reflective substance that reflects the whole visible light spectrum under the glass surface.
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Radio waves travel at the speed of light, 300,000 km/s. The wavelength of a radio wave received at 100 megahertz is
A) 0.3 m.
B) 3.0 m.
C) 30 m.
D) 300 m.
E) none of these
B
Option (B)- 300,000 km/s is the speed at which radio waves move through the air. A radio wave with a frequency of 100 megahertz has a wavelength of 3.0 m.
Use the relationship: wavelength = speed/frequency = 300,000,000 m/s / 100,000,000 = 3 m.
The electromagnetic spectrum's longest wavelengths, which are found in a radio wave, are normally found at frequencies of 300 gigahertz (GHz) and lower. The wavelength for 30 Hz is 10,000 kilometers (6,200 miles) while the wavelength for 300 GHz is 1 mm (shorter than a grain of rice) (longer than the radius of the Earth). Like all electromagnetic waves, radio waves move at the speed of light in a vacuum and at a nearly same, slightly slower speed in the Earth's atmosphere. Charged particles, such as time-varying electric currents, that are accelerating produce radio waves. All warm objects emit blackbody radiation, which includes naturally occurring radio waves emitted by lightning and celestial objects.
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a slender, uniform metal rod of mass m and length l is pivoted without friction about an axis through its midpoint and perpendicular to the rod. a horizontal spring, assumed massless and with force constant kkk, is attached to the lower end of the rod, with the other end of the spring attached to a rigid support. (figure 1)
We start by analyzing the torques acting on the rod when it is deflected by a small angle θθtheta from the vertical. Consider first the torque due to gravity. Which of the following statements most accurately describes the effect of gravity on the rod?
Choose the best answer.
Under the action of gravity alone the rod would move to a horizontal position. But for small deflections from the vertical the torque due to gravity is sufficiently small to be ignored.
Under the action of gravity alone the rod would move to a vertical position. But for small deflections from the vertical the restoring force due to gravity is sufficiently small to be ignored.
There is no torque due to gravity on the rod.
Find the torque ττtau due to the spring. Assume that θθtheta is small enough that the spring remains effectively horizontal and you can approximate sin(θ)≈θsin(θ)≈θ (and cos(θ)≈1cos(θ)≈1).
Express the torque as a function of θθtheta and other parameters of the problem.
What is the angular frequency ωωomega of oscillations of the rod?
Express the angular frequency in terms of parameters given in the introduction.
The formula for the angular frequency is = 2/T. Radians per second are used to express angular frequency. The frequency, f = 1/T, is the period's inverse.
The motion's frequency, f = 1/T = /2, determines how many complete oscillations occur in a given amount of time.
How can the angular frequency of a simple harmonic motion be determined?
A basic harmonic oscillator's angular frequency, period T, and frequency f are given by =km = k m, T=2mk, and f=12km T = 2 m k, and f = 1 2 k m, where m is the system's mass and k is the force constant.
What is the free oscillation formula?
when the driving frequency is very near to the natural frequency, oscillations. The oscillations' amplitude is displayed in the A=m02(2d2)2+d2b2 Fo is the formula provided in the attached graphic.
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a fire hose has water entering from a fire hydrant at the rate of 2m/s with a pressure of 200000 pa. at the nozzle the pressure decreases to atmospheric pressure (101300 pa), there is no change in height. use the bernoulli equation to calculate the velocity of the water exiting the nozzle. (hint: the density of water is 1000 kg/m3 and gravity g is 9.8 m/s2 .
The velocity of water exiting nozzle is 14.2 m/s.
What is velocity ?
It measures how quickly a distance changes. It is the rate at which displacement is changing.
What is pressure?
Pressure is the force applied perpendicularly to an object's surface in relation to the area across which it is dispersed.
New same height so h₂=h₁
new position p₂= 101300 pa and velocity v₂
water density p₂= 1000kg/m
gravity = 9.8m/s
V₁²= 2/p (p₁-p₂)
4+2/1000 ( 20000- 101300 )
=20.14
v₂= [tex]\sqrt{20.14}[/tex]
= 14.2 m/s
Therefore, the velocity of water exiting nozzle is 14.2 m/s.
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if a thin film has a thickness that is if a thin film has a thickness that is 14 of a wavelength, destructive interference will always occur. 14 of a wavelength, constructive interference will always occur. 12 of a wavelength, constructive interference will always occur. 12 of a wavelength, destructive interference will always occur. none of the above is always true.
However, at an oblique angle of incidence, the thickness will be equal to the cosine of the angle at the quarter or half-wavelength points. At a normal angle of incidence, the thickness will normally be a quarter or half multiple of the center wavelength.
What is the thin film's wavelength?White light is incident on a thin film of soap solution at an angle of incidence of I = sin-1(4/5). Two black overlapping fringes with wavelengths of 6.1 x 10-7 m and 6.0 x 10-7 m are seen in the reflected light.
How is interference in thin films determined?The index of refraction affects the wavelength of light. Thus, the wavelength of the light incident on the thin film itself must be taken into account in interference concerns.
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Explain how it is possible for the voltage amplitude across the capacitor to be greater than the voltage amplitude across the source Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Reset Help UR Vc + UL At any instant; vis equal to 909 But vC and UL are out of phase SO UC can be larger than v at & value of t, positive negative at that t vL + UR UR - "C UL UR + Uc + UL UL ~ UR 1800 UR + vc - VL
The voltages across the capacitor and inductor may be greater than the input voltage when the circuit is at or close to the resonance. The resistance voltage is 90 degrees behind the inductor voltage.
How do you determine a capacitor's voltage and amplitude?The VC (t) phasor has an amplitude of VC=I0XC and lags the i(t) phasor by /2 rad. The vL(t) phasor has the amplitude VL=I0XL and trails the i(t) phasor by /2 rad.
Is it possible for the voltage across the capacitor to be higher than the voltage at the source?In a series LCR circuit, the voltage drop across the inductor or capacitor can, in fact, exceed the applied voltage of the a.c. source. VC or VL may be bigger than V since VC and VL have opposing faces. The RMS current for an applied V = volts RMS voltage is I = x 10 amperes. You may calculate the component voltages by multiplying the current.
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as the sun rotates, an individual sunspot can be tracked across its face. from eastern to western limb, this takes about as the sun rotates, an individual sunspot can be tracked across its face. from eastern to western limb, this takes about 12 hours. a week. two weeks. a month. 5.5 years.
A specific sunspot can be followed as it moves over the Sun's surface as it revolves. This takes approximately from eastern to western limb.
While moving over the Earth-side of the sun, super sunspot AR2192 generated 10 major solar flares, six of which were X-class and four of which were above M5-class. These photos from NASA's SDO, taken between October 17 and October 29, 2014, show a sunspot that is the largest since November 1990 moving across the front of the sun. Try restarting your device if playback doesn't start right away. These photos from NASA's SDO, taken between October 17 and October 29, 2014, show a sunspot that is the largest since November 1990 moving across the front of the sun. Try restarting your device if playback doesn't start right away. Your watched videos might be added to.
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Which vector is the sum of the vectors shown below?
The vector that runs from the upper right vector's head to the lower left vector's tail is the vector sum. None of the vectors presented as possible answers in this case appear to fit the direction.
Which vector depicts the addition of the two provided vectors?The outcome is the total of at least two vectors. Either the triangle approach or the parallelogram method can be used to determine the product of two vectors.
Which vector contains the sum of the other two?The sum of two or more vectors is known as the outcome. It comes about as a result of multiplying two or more vectors. The resultant is a term used to describe the addition of two or more vectors.
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