A line passes through the points (10, 6) and (5, -2). What is its equation in slope-intercept form?​

Answer:

10=x

6=y

5=x

-2=y

10-5=5

6--2=8

5/8=0.625

y=mx+b

Step-by-step explanation:

The equation of a line in slope-intercept form through the points (10, 6) and (5, -2) y = (4/5)x - 6.

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at

x = 0.

Given, A line passes through the points (10, 6) and (5, -2).

We know the equation of a line in slope intercept form is y = mx + b.

Where slope(m) = (- 2 - 6)/(5 - 10).

slope(m) = - 8/-10.

slope(m) = 4/5.

Now for the y-intercept,

- 2 = (4/5)×5 + b.

- 2 = 4 + b.

b = - 6.

Therefore the required line in slope-intercept form is y = (4/5)x - 6.

learn more about lines and slopes here :

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