A large truck is ahead of you and is turning right onto a street with two lanes in each direction. The truck:

Answers

Answer 1

May have to swing wide to complete the right turn

In any vehicle which makes any turn, the rear wheels follow a shorter path as compared to the front wheels. While the truck being larger than any usual vehicle, the distance between the wheels are even more, which makes it harder to complete the turn by going in its own lane or the other two right lanes.

So, the truck will try to go wide in left and then complete the right turn as by doing this the distance between the rear and front will get compensated by the width of the lanes making it easier for the truck to complete its turn.

     

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[Your question is incomplete, but most probably your full question was

May not turn without engaging its hazard lights

May complete its turn in either of the two lanes

Must stay in the right lane at all times while turning

May have to swing wide to complete the right turn]


Related Questions

Two workers are sliding 440 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 260 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor

Answers

The kinetic coefficient of friction of the crate is 0.1506

Let's assume that both workers are applying positive pressure to the crate. A body cannot change its state of motion whether it is at rest or moves uniformly, according to Newton's First Law (at constant velocity). The magnitude of the friction force must therefore equal the total of the two external forces. The crate's equilibrium equations are as follows:

∑Fₓ = P + T - μ . N = 0

[tex]F_{y}[/tex] = N - W = 0

Where:

[tex]P[/tex] - Pushing force, measured in newtons.

[tex]T[/tex] - Tension, measured in newtons.

μ- Coefficient of kinetic friction, dimensionless.

[tex]N[/tex]- Normal force, measured in newtons.

W - Weight of the crate, measured in newtons.

The system of equations is now reduced by algebraic means:

P + T - μ . W = 0

We finally clear the coefficient of kinetic friction and apply the definition of weight :

μ [tex]=\frac{P + T}{m.g}[/tex]

We know that P = 390 N, T = 260 N, m = 440 kg and [tex]g= 9.807 \frac{m}{s^2}[/tex] ;

μ = 0.1506

Therefore, the kinetic coefficient of friction of the crate is 0.1506

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What happens when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure

Answers

when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, then The core contracts and becomes black hole.

What is degeneracy pressure:

The degeneracy pressure found in the interior of a white dwarf or neutron star. The degeneracy pressure is greatly needed in the interior of these stars to counteract the pressure due to gravity.

Some neutron stars may have a surface layer of highly degenerate matter that is compressed to great density, but still has some protons

Unlike the main body of the neutron star which is Neutronium, matter compressed until it is all neutrons, packed together. Essentially a huge atomic nucleus.

The star cools and all remaining matter is bound by gravitation into a neutron star.

This object is composed primarily of degenerate neutron matter, this star will collapse into a black hole because gravity will overcome the neutron degeneracy pressure.

hence, when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, The core contracts and becomes a black hole.

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A 200-N scaffold is held up by a wire at each end. The scaffold is 18 m long. A 650-N box sits 3.0 m from the left end. What is the tension in each wire

Answers

The tension on the left wire 642N and the tension on right wire is 208N

Given that the force of scaffold is 200- N and the length of the scaffold is 18m

We need to find the tension in each wire

Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends

Here

∑ [tex]T_b=0[/tex]

∴ [tex]W_B(15m)+W_S(9m)-T_L(18m) = 0[/tex]

∴ [tex]T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N[/tex]

Hence the tension on the left side is 642N

∑[tex]T_a[/tex] = 0

[tex]T_R(18m)-W_B(3m)-W_S(9m)=0[/tex]

∴[tex]T_R =\frac{W_B(3m)+W_S(9m)}{18m}[/tex]

∴[tex]T_R = \frac{650(3)+200(+9)}{18}\\[/tex]

∴[tex]T_R = 208N[/tex]

Hence the tension on the right side is 208N

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A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the car? Group of answer choices 1500 N 1750 N 2750 N 3000 N

Answers

The frictional force exerted by the road on the car is 3000N

Given the mass of the car is 1000 kg , the velocity of the car is 20m/s

and the time is 6.6s

We need to find the frictional force exerted by the road on the car

We know that Force = mass * acceleration

Now here Mass is given but acceleration is not given

So, we will find acceleration by using the formula v = u+at

Where u = 0

v = 20m/s

a = ?

t = 6.6

Substitute the values in the formula We get

v = u+at

20 = 0+(a)(6.6)

20/6.6 = a

∴ a = 3.03 m/s^2

Rounding to nearest tenth is 3m/s^2

Hence the acceleration is 3m/s^2

Now substituting the value of acceleration in F = ma

Where m = mass

a = acceleration

F = 1000*3

∴ F = 3000N

Hence the frictional force exerted by the road on the car is 3000 N

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In a given lightning flash, the potential difference between a cloud and the ground is 1.5 times 109 V and the quantity of charge transferred is 23.7 C. What is the decrease in energy of the transferred charge

Answers

Answer:

The decrease in energy for a lightning flash, with a potential difference between a cloud and the ground, is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C is [tex]$3.555 \times 10^{10} \text{ J}$[/tex].

Explanation:

In a lightning flash, the potential difference between a cloud and the ground is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C.

It is required to determine the decrease in energy of the transferred charge.

It is known that the decrease in energy is calculated by multiplying the potential difference by the quantity of charge. Mathematically it is expressed as:

[tex]\Delta U=q \Delta V[/tex]

In this problem, the value of q is 23.7 C and the value of [tex]\Delta V[/tex] is [tex]1.5 \times 10^{9}\text{ V}[/tex].

Therefore the decrease in energy is:

[tex]$$\begin{aligned}\Delta U&=q \Delta V\\&=23.7\times 1.5 \times 10^{9} \text{ J}\\&=3.555\times 10^{10} \text{ J}\end{aligned}$$[/tex]

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A 36,287 kg truck has a momentum of 907,175 kg • meters per second. what is the truck’s velocity? meters per second

Answers

The truck's velocity is 25 m/s.

It is given that,

                         mass, m= 36,287 kg

               momentum, p =  907,175 kg-m/s

Using the formula of momentum, we know that

                                     p = mv

Plugging in the values

               907,175 kg-m/s = 36,287 kg x v

                           v = 25 m/s

So, the velocity of the truck is 25 m/s.

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Answer:25

Explanation:your welcome!:)

A boy wants to throw a can straight up and then hit it with a second can. He wants the collision to occur 4.0 meters above the throwing point. In addition, he knows that the time he needs between throws is 3.0 seconds. Assuming he throws both cans with the same speed, what must the initial speed be

Answers

16.03 m/s is the initial speed of the cans.

Newton’s equations of motion has to be used to solve it;

He wants collision at height (h) = 4.0 m

The acceleration due to gravity  as,

                                                      g =9.8ms−²

The initial speed of the thrown can is calculated by:

h = vt - ¹/₂gt²

4 = 3t - (0.5)(9.8)(3)²

4 = 3t - 44.1

3t = 48.1

t = 48.1/3

t = 16.03 m/s

Thus, the initial speed of the boy's thrown can is 16.03 m/s.

By measuring the rate at which the velocity varies with regard to the passage of time, one can calculate the acceleration of a body. By calculating the rate at which the displacement varies with regard to the passage of time, the velocity may be calculated. The perpendicular distance between the body's initial and final locations is its displacement. These are all vector quantities, meaning they all have both magnitude and direction.

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What causes earthquakes?


Where do earthquakes begin?

Answers

Answer:

An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.

Explanation:

Tensions around rocks are increasing, and an earthquake begins at tectonic plates.

The majority of earthquakes begin at or close to tectonic plate borders, where stress and strain gradually build up due to interactions between the plates over time. An earthquake occurs when the amount of accumulated tension surpasses the capacity of the rocks, which causes an abrupt release of energy. When there is an earthquake, seismic waves are released, and we feel and sense shaking as a result.

But even beyond plate borders, within tectonic plates, earthquakes can still happen. These earthquakes, also known as intraplate earthquakes, are frequently connected to old faults or weak spots in the crust of the Earth. Despite being less frequent than those near plate borders, intraplate earthquakes can nevertheless be severe and cause damage in populated regions.

Hence, tensions around rocks are increasing, and an earthquake begins at tectonic plates.

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A boy is leaning into a wall with a horizontal force of 15 N. Which of the following best describes the vector force the wall is applying to the boy?

A
–7.5 N

B
15 N

C
0 N

D
–15 N

Answers

The vector force the wall is applying to the boy is -15 N; option D

What is a reaction force?

A reaction force is a force which is equal in magnitude but oppositely directed to a force acting in a particular direction.

The reaction force on the boy is equal in magnitude to the weight of the boy but has an opposite direction.

In conclusion, the vector force applied by the wall on the boy is -15 N.

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A 480 g peregrine falcon reaches a speed of 75 m/s in a vertical dive called a stoop. If we assume that the falcon speeds up under the influence of grav- ity only, what is the minimum height of the dive needed to achieve this speed

Answers

The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.

Given information:

The mass of peregrine falcon is,  m = 480

The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s

It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s  as the motion starts with rest.

The value of the gravitational acceleration of gravity is, g = 9.80 m/s²

Now, using the third equation of motion, the minimum height  required for the final speed will be,

v² - u² = 2gh

69² - 0² = 2 × 9.8 × h

h = 242.9m.

Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.

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A current of 0.050 amps flows in a circuit element with a resistance of 25 ohms what is the voltage drop across the circuit element. (use ohms law V=IR)

Answers

The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V

Ohm's law

This law states as follows:

V = IR

Where

V is the potential differenceI is the currentR is the resistor

How to determine the voltage

From the question given above, the following data were obtained:

Current (I) = 0.05 AResistance (R) =25 ohmsVoltage (V) =?

V = IR

V = 0.05 × 25

V = 1.25 V

Therefore, the voltage drop across the circuit is 1.25 V

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PLEASE HELP ME I BEGGG

Answers

Answer:

,ff

Explanation:

2331552378 added mee

hello friends,i need ur help on this,topic of Motion in straight line.
hurryy up please.​
and keep answering correctly.

Answers

Answer:

V = a * t      for uniformly accelerated motion starting at zero speed

V = 4 s * 9.8 m/s^2 = 39.2 m/s

S = V0 t + 1/2 a t^2 = 1/2 a t^2

S = 1/2 * 9.8 m/s^2 * 16 s^2 = 78.4 m

Check:

Average speed = 39.2 / 2 = 19.6 m/s

S = 4 * 19.6 = 78.4 m

To develop a model of blackbody radiation that correctly modeled the behavior of emission intensity versus wavelength, Planck applied quantization of:\

Answers

Max Planck utilized the concept of energy quantization in order to develop a model for blackbody radiation that accurately fit experimental results.

Electromagnetic waves emitted by using a blackbody are referred to as blackbody radiation. A blackbody is bodily found out through a small hole within the wall of a hollow space radiator.

The depth of blackbody radiation depends on the wavelength of the emitted radiation and the temperature T of the blackbody.

When the temperature of a black frame increases, it is discovered that the wavelength similar to most electricity changes from 0.26 μm to 0. Thirteen μm Then the ratio of the emissive power of the body at the respective temperature is.

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The pilot of the fighter jet turns by banking the wings such that the lift of the wings has a component in
the direction of the centre of the turn. The pilot wishes to turn the jet in a tight radius of 960.0 m while
maintaining a constant circular speed of 1440 km/h. Determine the angle of bank needed, measured from
the vertical.

Answers

The angle of bank needed, measured from the vertical is 86.6⁰.

Banking angle of the circular path

The angle of bank needed, measured from the vertical is calculated as follows;

v = √(rg tanθ)

where;

v is the speed = 1440 km/h = 400 m/sr is radius of the curve = 960 mg is acceleration due to gravityθ is the banking angle

400² = (960 x 9.8 x tanθ)

tanθ = 400²(960 x 9.8)

tanθ = 17

θ  = arc tan(17)

θ  = 86.6⁰

Thus, the angle of bank needed, measured from the vertical is 86.6⁰.

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An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equivalent spring constant of the bow

Answers

Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

What is Simple Harmonic Motion?A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force. The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.If x is the displacement from the mean position, and F is the restoring force, then

                   [tex]F[/tex]∝[tex]-x[/tex]

                   [tex]F=-kx[/tex] where, k is called the spring constant.

How to approach the problem?Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.Here, from the question given, we can write, [tex]x=-0.400m[/tex] and [tex]F=230N[/tex].Thus, our spring constant k will be,

                       [tex]k=-F/x= (230)/ (0.400) =575 N/m.[/tex]

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

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A stack of 1500 bricks covers a ground area of 2.750m by 1.350m.the average mass of bricks is 3.200kg.calculate the total force on the ground

Answers

The total force on the ground due to the bricks is 47,040 N.

Total force on the ground

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

Fₙ is normal forcem is mass of the brickesg is acceleration due to gravity

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

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Directly detecting an Earth-size planet around one of the nearest stars (besides the Sun) is roughly equivalent to trying to take a picture of a ball point from a pen at a distance of about ________ kilometers.

Answers

The ballpoint from a pen at a distance of about  4000  kilometers.

Alpha Centauri is the closest star device. Distance from Earth 4,365 al (forty 000 billion kilometers. The solar (yellow famous person) distance from Earth is 150 000 000 km, the exoplanet distance from Alpha Centauri b (orange famous person) 6 000 000 km.

Shifts in starlight from Proxima Centauri, found over extra than 2 years, screen its 1/3 planet. Astronomers have observed a 3rd planet orbiting Proxima Centauri, the star closest to the solar.

Proxima Centauri, the nearest megastar to our own, remains forty,208,000,000,000 km away. (Or about 268,770 AU.)

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if a man pulls a box with a forcce of 90N at an angle of 45 degrees then what are x and y components of the force

Answers

The x and y components of the force will be 63.6 N and 63.6 N  respectively.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Force, F=90 N

Angle,θ = 45°

The force of 90N at an angle of 45 degrees;

The force is resolved in the x and y direction as;

[tex]\rm F_x = 90 cos 45 ^ 0 \\\\ F_x = 63.6 \ N[/tex]

[tex]\rm F_y = 90 sin 45^0 \\\\ F_y =63.6 \ N[/tex]

Hence x and y components of the force will be 63.6 N and 63.6 N  respectively.

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An object has a mass of 20.41 kg and an acceleration of 8.22 m/s2. What is the force acting on the object?

Answers

Answer: 167.7702 N (Newtons)

Explanation: I had this type of work, so I hope I am correct.

Answer:

~ 168 N

Explanation:

F = m a

 = 20.41 * 8.22 = 167.7702 N

The odometer of a car changes from 1048 km to 1096 km in 40
minutes. Calculate the average velocity.
O 22 m/s
O 14 m/s
20 m/s
O 18 m/s

Answers

Answer:

20m/s

Explanation:

it covers 20 metres in a second

Point charges q1and q2 of +12nc and -12nc,respectively are placed 10.0cm apart.compute the resultant electric field(magnitude field)

Answers

The electric field due to charge q1 and q2 at the middle point of the line joining the charges q1 and q2 is 8.64*10^(4) N/C.

Note: You have not given the point where the resultant magnetic field has to be calculated. Most probably it is asked to find the electric field at the middle point of the line joining the point charges.

Electric field: The electric force exerted on a unit charge is called the electric field. Electric field due to a charge is calculated using the formula,

E=kq/r^2

where k is a constant whose value is 9*10^(9) N m^2/ C^(2), q is the charge and r is the distance from the charge to the point where the electric field has to be calculated. In the given case, the electric field has to be calculated at the middle point of the line joining charges q1 and q2.

Calculation of electric field due to charge q1:

Given that q1=+12 nC or q1=+12*10^(-9) C and the distance of the charge q1 from the center d1=10.0/2 cm or d1=5*10^(-2) m, the magnitude of the electric field E1 due to charge q1 is,

E1=kq1 /d1^(2)

E1=9*10^(9)*12*10^(-9) / (5*10^(-2))^2

E1=4.32*10^(4) N/C

The direction of the electric field E1 at the middle point is towards the negative charge.

Calculation of electric field due to charge q2:

Given that q2=-12 nC or q1=-12*10^(-9) C and the distance of the charge q2 from the center d2=10.0/2 cm or d2=5*10^(-2) m, the magnitude of the electric field E2 due to charge q2 is,

E2=kq2 /d2^(2)

E2=9*10^(9)*12*10^(-9) / (5*10^(-2))^2

E2=4.32*10^(4) N/C

The direction of the electric field E2 at the middle point is towards the negative charge.

Total electric field:

The total electric field is given by the addition of the electric field. The direction of the electric field is the same for both charges, hence total electric field E is,

E=E1+E2

E=4.32*10^(4) +4.32*10^(4)

E=8.64*10^(4) N/C

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What do simple machines increase?
O movement
O force
O gravity
O mechanical advantage

Answers

Answer:

Mechanical advantage

Explanation:

Machines help us in giving more output than the input incurred so it only increases mechanical advantage, all the other quantities are dependent on the mechanical advantage.

What are the 2 forces acting on a projectile?
A. Gravity and Tension
B. Air Resistance and Tension
C. Gravity and Air Resistance
D. Gravity and Normal Force

Answers

Answer:

Gravity and Air resistance.

Explanation:

A projectile is an object that is launched into the air by the application of an external force and they are able to move freely under the influence of gravity and air resistance.

Therefore,

The 2 forces acting on a projectile are:

Gravity and Air resistance.

For a simple compressible system, the change in the total energy of a system during a process is affected by ______. Multiple choice question. changes in potential and kinetic energies only change in potential energy only change in kinetic energy only changes in potential, kinetic, and internal energies change in internal energy only

Answers

For a simple compressible system, the change in the total energy of a system during a process is affected by changes in potential, kinetic, and internal energies.

First law of thermodynamics:

The conservation of energy principle sometimes referred to as the first law of thermodynamics, offers a reliable framework for researching the connections between the many types of energy and their interactions. The first law of thermodynamics asserts that energy can only change forms during a process; it cannot be created or destroyed, according to experimental data. As a result, during a procedure, every piece of energy should be taken into account.

The evaluation of the system's energy at the start and end of the process, as well as the difference between them, is necessary to calculate the energy change of a system during a process. That is,

Energy change = Energy at final state - Energy at the initial state

                                  Δ[tex]E_{system}[/tex] = [tex]E_{2} - E_{1}[/tex]

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A spring whose spring constant is 260 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 in. The work required to compress it another 1 in is Btu.

Answers

The work required to compress it another 1 in Btu is 0.02463 Btu.

Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full displacement of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure distance d in an instant course in the direction of the force.

To explicit this idea mathematically, the work W is the same as the pressure f instances the distance d, or W = FD. If the pressure is being exerted at a perspective θ to the displacement, the work finished is W = FD cos θ.

The work is executed whenever a force actions something over a distance. you can calculate the electricity transferred, or work completed, by multiplying the force by way of the space moved inside the course of the force.

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Flexible cord sets and power-supply cords shall not be concealed behind building __________________, or run through doorways, windows, or similar openings.

Answers

Flexible cord sets and power-supply cords shall not be concealed behind building , structural ceilings, suspended or dropped ceilings, floors or walls, or run through doorways, windows, or similar openings.

Hence Option (b) All of these is correct

Flexible cord and flexible cable usage are now outlined in Section 400.10, while prohibited uses are listed in Section 400.12.

Note 5 under 400.12 now includes a new exclusion for flexible wires and cords (uses not permitted).

Flexible cables, flexible cord sets, and power supply cords are not permitted in areas that are "concealed by walls, floors, or ceilings or positioned above suspended or dropped ceilings," according to Note 5.

The following uses for flexible cables, flexible cord sets, and power supply cords are prohibited as well:

(1) As an alternative to a structure's fixed wiring.

(2) Run-through openings in structural ceilings, floors, suspended ceilings, or dropped ceilings.

(3) When run through windows, doorways, or comparable openings.

(4) If attached to building surfaces.

Hence, Option (b) All of these is correct .

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When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction pressure and superheat

Answers

Answer:

The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

Fluid refrigerantCompressorCondenser coilEvaporator coilExpansion device.

       The compressor limits the vapor released by the refrigerant. This            

       causes a rise in pressure (in refrigerant), which then pushes the  

       vapor into the coils on the outside of the refrigerator.

2. Now when the cooler air meets the warm gas present in the coils, it

   gets converted into liquid form.

3. Thus, when the liquid form is at high pressure, the refrigerant then  

   cools down as it flows through the coils placed in the fridge ( in both

   freezing and normal sections).

4. The refrigerant also absorbs the warm air present in the fridge, which  

   causes it to evaporate and flow back through the compressor and the

   cycle repeats in the same form.

Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.

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You have just checked out a Lime bicycle, only to find that one of its tires is flat. Luckily, you have a bicycle pump with you. As you refill the flat tire, you find that it takes a considerable amount of effort to do it. Why

Answers

It will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.

Difference in air pressure

Pressure is defined as force applied per unit area of the given surface.

Pressure = Force/Area

The pressure of air inside the bicycle pump is smaller compared to the air pressure inside the tire.

Thus, it will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.

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Which best describes a possible transfer of energy

Answers

A mechanical wave transfers energy through matter.

What is Mechanical wave?

A mechanical wave is a wave that is an oscillation of matter and is responsible for the transfer of energy through a medium.

Answer: Like all waves, mechanical waves transport energy. This energy propagates in the same direction as the wave. A wave requires an initial energy input; once this initial energy is added, the wave travels through the medium until all its energy is transferred. In contrast, electromagnetic waves require no medium, but can still travel through one.

A wave is a transmission of a disturbance from one point to another. Wave involves transmission of energy from one point to another through a materials medium.

Mechanical waves vibrate in matter and transfer energy. Explore the production and propagation of mechanical waves and discover the factors that affect mechanical waves including elasticity, tension, temperature, and density

Therefore,

A mechanical wave transfers energy through matter.

A complete question is is given below:

What best describes a possible transfer of energy?

a. A mechanical wave transfers energy through matter.

b. A longitudinal wave transfers energy perpendicular to wave motion.

c. A transverse wave transfers energy parallel to wave motion.

d. A sound wave does not need a medium to transfer energy through.

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