A large truck is ahead of you and is turning right onto a street with two lanes in each direction. The truck:

when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, then The core contracts and becomes black hole.

What is degeneracy pressure:

Some neutron stars may have a surface layer of highly degenerate matter that is compressed to great density, but still has some protons

Unlike the main body of the neutron star which is Neutronium, matter compressed until it is all neutrons, packed together. Essentially a huge atomic nucleus.

The star cools and all remaining matter is bound by gravitation into a neutron star.

This object is composed primarily of degenerate neutron matter, this star will collapse into a black hole because gravity will overcome the neutron degeneracy pressure.

hence, when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, The core contracts and becomes a black hole.

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Answer:

The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

       The compressor limits the vapor released by the refrigerant. This            

       causes a rise in pressure (in refrigerant), which then pushes the  

       vapor into the coils on the outside of the refrigerator.

2. Now when the cooler air meets the warm gas present in the coils, it

   gets converted into liquid form.

3. Thus, when the liquid form is at high pressure, the refrigerant then  

   cools down as it flows through the coils placed in the fridge ( in both

   freezing and normal sections).

4. The refrigerant also absorbs the warm air present in the fridge, which  

   causes it to evaporate and flow back through the compressor and the

   cycle repeats in the same form.

Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.

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The angle of bank needed, measured from the vertical is 86.6⁰.

The angle of bank needed, measured from the vertical is calculated as follows;

v = √(rg tanθ)

where;

400² = (960 x 9.8 x tanθ)

tanθ = 400²(960 x 9.8)

tanθ = 17

θ  = arc tan(17)

θ  = 86.6⁰

Thus, the angle of bank needed, measured from the vertical is 86.6⁰.

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Max Planck utilized the concept of energy quantization in order to develop a model for blackbody radiation that accurately fit experimental results.

Electromagnetic waves emitted by using a blackbody are referred to as blackbody radiation. A blackbody is bodily found out through a small hole within the wall of a hollow space radiator.

The depth of blackbody radiation depends on the wavelength of the emitted radiation and the temperature T of the blackbody.

When the temperature of a black frame increases, it is discovered that the wavelength similar to most electricity changes from 0.26 μm to 0. Thirteen μm Then the ratio of the emissive power of the body at the respective temperature is.

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Answer:

20m/s

Explanation:

it covers 20 metres in a second

Answer:

Mechanical advantage

Explanation:

Machines help us in giving more output than the input incurred so it only increases mechanical advantage, all the other quantities are dependent on the mechanical advantage.

The truck's velocity is 25 m/s.

It is given that,

                         mass, m= 36,287 kg

               momentum, p =  907,175 kg-m/s

Using the formula of momentum, we know that

                                     p = mv

Plugging in the values

               907,175 kg-m/s = 36,287 kg x v

                           v = 25 m/s

So, the velocity of the truck is 25 m/s.

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Answer:25

Explanation:your welcome!:)

Answer:

,ff

Explanation:

2331552378 added mee

The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.

Given information:

The mass of peregrine falcon is,  m = 480

The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s

It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s  as the motion starts with rest.

The value of the gravitational acceleration of gravity is, g = 9.80 m/s²

Now, using the third equation of motion, the minimum height  required for the final speed will be,

v² - u² = 2gh

69² - 0² = 2 × 9.8 × h

h = 242.9m.

Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.

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Answer:

The decrease in energy for a lightning flash, with a potential difference between a cloud and the ground, is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C is [tex]$3.555 \times 10^{10} \text{ J}$[/tex].

Explanation:

In a lightning flash, the potential difference between a cloud and the ground is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C.

It is required to determine the decrease in energy of the transferred charge.

It is known that the decrease in energy is calculated by multiplying the potential difference by the quantity of charge. Mathematically it is expressed as:

[tex]\Delta U=q \Delta V[/tex]

In this problem, the value of q is 23.7 C and the value of [tex]\Delta V[/tex] is [tex]1.5 \times 10^{9}\text{ V}[/tex].

Therefore the decrease in energy is:

[tex]$$\begin{aligned}\Delta U&=q \Delta V\\&=23.7\times 1.5 \times 10^{9} \text{ J}\\&=3.555\times 10^{10} \text{ J}\end{aligned}$$[/tex]

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The work required to compress it another 1 in Btu is 0.02463 Btu.

Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full displacement of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure distance d in an instant course in the direction of the force.

To explicit this idea mathematically, the work W is the same as the pressure f instances the distance d, or W = FD. If the pressure is being exerted at a perspective θ to the displacement, the work finished is W = FD cos θ.

The work is executed whenever a force actions something over a distance. you can calculate the electricity transferred, or work completed, by multiplying the force by way of the space moved inside the course of the force.

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The total force on the ground due to the bricks is 47,040 N.

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

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The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V

This law states as follows:

V = IR

Where

From the question given above, the following data were obtained:

V = IR

V = 0.05 × 25

V = 1.25 V

Therefore, the voltage drop across the circuit is 1.25 V

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Answer:

An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.

Explanation:

Tensions around rocks are increasing, and an earthquake begins at tectonic plates.

The majority of earthquakes begin at or close to tectonic plate borders, where stress and strain gradually build up due to interactions between the plates over time. An earthquake occurs when the amount of accumulated tension surpasses the capacity of the rocks, which causes an abrupt release of energy. When there is an earthquake, seismic waves are released, and we feel and sense shaking as a result.

But even beyond plate borders, within tectonic plates, earthquakes can still happen. These earthquakes, also known as intraplate earthquakes, are frequently connected to old faults or weak spots in the crust of the Earth. Despite being less frequent than those near plate borders, intraplate earthquakes can nevertheless be severe and cause damage in populated regions.

Hence, tensions around rocks are increasing, and an earthquake begins at tectonic plates.

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The ballpoint from a pen at a distance of about  4000  kilometers.

Alpha Centauri is the closest star device. Distance from Earth 4,365 al (forty 000 billion kilometers. The solar (yellow famous person) distance from Earth is 150 000 000 km, the exoplanet distance from Alpha Centauri b (orange famous person) 6 000 000 km.

Shifts in starlight from Proxima Centauri, found over extra than 2 years, screen its 1/3 planet. Astronomers have observed a 3rd planet orbiting Proxima Centauri, the star closest to the solar.

Proxima Centauri, the nearest megastar to our own, remains forty,208,000,000,000 km away. (Or about 268,770 AU.)

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The vector force the wall is applying to the boy is -15 N; option D

A reaction force is a force which is equal in magnitude but oppositely directed to a force acting in a particular direction.

The reaction force on the boy is equal in magnitude to the weight of the boy but has an opposite direction.

In conclusion, the vector force applied by the wall on the boy is -15 N.

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Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

                   [tex]F[/tex]∝[tex]-x[/tex]

                   [tex]F=-kx[/tex] where, k is called the spring constant.

                       [tex]k=-F/x= (230)/ (0.400) =575 N/m.[/tex]

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

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The tension on the left wire 642N and the tension on right wire is 208N

Given that the force of scaffold is 200- N and the length of the scaffold is 18m

We need to find the tension in each wire

Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends

Here

∑ [tex]T_b=0[/tex]

∴ [tex]W_B(15m)+W_S(9m)-T_L(18m) = 0[/tex]

∴ [tex]T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N[/tex]

Hence the tension on the left side is 642N

∑[tex]T_a[/tex] = 0

[tex]T_R(18m)-W_B(3m)-W_S(9m)=0[/tex]

∴[tex]T_R =\frac{W_B(3m)+W_S(9m)}{18m}[/tex]

∴[tex]T_R = \frac{650(3)+200(+9)}{18}\\[/tex]

∴[tex]T_R = 208N[/tex]

Hence the tension on the right side is 208N

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Answer:

V = a * t      for uniformly accelerated motion starting at zero speed

V = 4 s * 9.8 m/s^2 = 39.2 m/s

S = V0 t + 1/2 a t^2 = 1/2 a t^2

S = 1/2 * 9.8 m/s^2 * 16 s^2 = 78.4 m

Check:

Average speed = 39.2 / 2 = 19.6 m/s

S = 4 * 19.6 = 78.4 m

16.03 m/s is the initial speed of the cans.

Newton’s equations of motion has to be used to solve it;

He wants collision at height (h) = 4.0 m

The acceleration due to gravity  as,

                                                      g =9.8ms−²

The initial speed of the thrown can is calculated by:

h = vt - ¹/₂gt²

4 = 3t - (0.5)(9.8)(3)²

4 = 3t - 44.1

3t = 48.1

t = 48.1/3

t = 16.03 m/s

Thus, the initial speed of the boy's thrown can is 16.03 m/s.

By measuring the rate at which the velocity varies with regard to the passage of time, one can calculate the acceleration of a body. By calculating the rate at which the displacement varies with regard to the passage of time, the velocity may be calculated. The perpendicular distance between the body's initial and final locations is its displacement. These are all vector quantities, meaning they all have both magnitude and direction.

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Answer: 167.7702 N (Newtons)

Explanation: I had this type of work, so I hope I am correct.

Answer:

~ 168 N

Explanation:

F = m a

 = 20.41 * 8.22 = 167.7702 N

For a simple compressible system, the change in the total energy of a system during a process is affected by changes in potential, kinetic, and internal energies.

The conservation of energy principle sometimes referred to as the first law of thermodynamics, offers a reliable framework for researching the connections between the many types of energy and their interactions. The first law of thermodynamics asserts that energy can only change forms during a process; it cannot be created or destroyed, according to experimental data. As a result, during a procedure, every piece of energy should be taken into account.

The evaluation of the system's energy at the start and end of the process, as well as the difference between them, is necessary to calculate the energy change of a system during a process. That is,

Energy change = Energy at final state - Energy at the initial state

                                  Δ[tex]E_{system}[/tex] = [tex]E_{2} - E_{1}[/tex]

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The electric field due to charge q1 and q2 at the middle point of the line joining the charges q1 and q2 is 8.64*10^(4) N/C.

Note: You have not given the point where the resultant magnetic field has to be calculated. Most probably it is asked to find the electric field at the middle point of the line joining the point charges.

Electric field: The electric force exerted on a unit charge is called the electric field. Electric field due to a charge is calculated using the formula,

E=kq/r^2

where k is a constant whose value is 9*10^(9) N m^2/ C^(2), q is the charge and r is the distance from the charge to the point where the electric field has to be calculated. In the given case, the electric field has to be calculated at the middle point of the line joining charges q1 and q2.

Calculation of electric field due to charge q1:

Given that q1=+12 nC or q1=+12*10^(-9) C and the distance of the charge q1 from the center d1=10.0/2 cm or d1=5*10^(-2) m, the magnitude of the electric field E1 due to charge q1 is,

E1=kq1 /d1^(2)

E1=9*10^(9)*12*10^(-9) / (5*10^(-2))^2

E1=4.32*10^(4) N/C

The direction of the electric field E1 at the middle point is towards the negative charge.

Calculation of electric field due to charge q2:

Given that q2=-12 nC or q1=-12*10^(-9) C and the distance of the charge q2 from the center d2=10.0/2 cm or d2=5*10^(-2) m, the magnitude of the electric field E2 due to charge q2 is,

E2=kq2 /d2^(2)

E2=9*10^(9)*12*10^(-9) / (5*10^(-2))^2

E2=4.32*10^(4) N/C

The direction of the electric field E2 at the middle point is towards the negative charge.

Total electric field:

The total electric field is given by the addition of the electric field. The direction of the electric field is the same for both charges, hence total electric field E is,

E=E1+E2

E=4.32*10^(4) +4.32*10^(4)

E=8.64*10^(4) N/C

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The x and y components of the force will be 63.6 N and 63.6 N  respectively.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Force, F=90 N

Angle,θ = 45°

The force of 90N at an angle of 45 degrees;

The force is resolved in the x and y direction as;

[tex]\rm F_x = 90 cos 45 ^ 0 \\\\ F_x = 63.6 \ N[/tex]

[tex]\rm F_y = 90 sin 45^0 \\\\ F_y =63.6 \ N[/tex]

Hence x and y components of the force will be 63.6 N and 63.6 N  respectively.

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It will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.

Pressure is defined as force applied per unit area of the given surface.

Pressure = Force/Area

The pressure of air inside the bicycle pump is smaller compared to the air pressure inside the tire.

Thus, it will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.

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The frictional force exerted by the road on the car is 3000N

Given the mass of the car is 1000 kg , the velocity of the car is 20m/s

and the time is 6.6s

We need to find the frictional force exerted by the road on the car

We know that Force = mass * acceleration

Now here Mass is given but acceleration is not given

So, we will find acceleration by using the formula v = u+at

Where u = 0

v = 20m/s

a = ?

t = 6.6

Substitute the values in the formula We get

v = u+at

20 = 0+(a)(6.6)

20/6.6 = a

∴ a = 3.03 m/s^2

Rounding to nearest tenth is 3m/s^2

Hence the acceleration is 3m/s^2

Now substituting the value of acceleration in F = ma

Where m = mass

a = acceleration

F = 1000*3

∴ F = 3000N

Hence the frictional force exerted by the road on the car is 3000 N

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A mechanical wave transfers energy through matter.

A mechanical wave is a wave that is an oscillation of matter and is responsible for the transfer of energy through a medium.

Answer: Like all waves, mechanical waves transport energy. This energy propagates in the same direction as the wave. A wave requires an initial energy input; once this initial energy is added, the wave travels through the medium until all its energy is transferred. In contrast, electromagnetic waves require no medium, but can still travel through one.

A wave is a transmission of a disturbance from one point to another. Wave involves transmission of energy from one point to another through a materials medium.

Mechanical waves vibrate in matter and transfer energy. Explore the production and propagation of mechanical waves and discover the factors that affect mechanical waves including elasticity, tension, temperature, and density

Therefore,

A mechanical wave transfers energy through matter.

A complete question is is given below:

What best describes a possible transfer of energy?

a. A mechanical wave transfers energy through matter.

b. A longitudinal wave transfers energy perpendicular to wave motion.

c. A transverse wave transfers energy parallel to wave motion.

d. A sound wave does not need a medium to transfer energy through.

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The kinetic coefficient of friction of the crate is 0.1506

Let's assume that both workers are applying positive pressure to the crate. A body cannot change its state of motion whether it is at rest or moves uniformly, according to Newton's First Law (at constant velocity). The magnitude of the friction force must therefore equal the total of the two external forces. The crate's equilibrium equations are as follows:

∑Fₓ = P + T - μ . N = 0

∑[tex]F_{y}[/tex] = N - W = 0

Where:

[tex]P[/tex] - Pushing force, measured in newtons.

[tex]T[/tex] - Tension, measured in newtons.

μ- Coefficient of kinetic friction, dimensionless.

[tex]N[/tex]- Normal force, measured in newtons.

W - Weight of the crate, measured in newtons.

The system of equations is now reduced by algebraic means:

P + T - μ . W = 0

We finally clear the coefficient of kinetic friction and apply the definition of weight :

μ [tex]=\frac{P + T}{m.g}[/tex]

We know that P = 390 N, T = 260 N, m = 440 kg and [tex]g= 9.807 \frac{m}{s^2}[/tex] ;

μ = 0.1506

Therefore, the kinetic coefficient of friction of the crate is 0.1506

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Answer:

Gravity and Air resistance.

Explanation:

A projectile is an object that is launched into the air by the application of an external force and they are able to move freely under the influence of gravity and air resistance.

Therefore,

The 2 forces acting on a projectile are:

Gravity and Air resistance.

Flexible cord sets and power-supply cords shall not be concealed behind building , structural ceilings, suspended or dropped ceilings, floors or walls, or run through doorways, windows, or similar openings.

Hence Option (b) All of these is correct

Flexible cord and flexible cable usage are now outlined in Section 400.10, while prohibited uses are listed in Section 400.12.

Note 5 under 400.12 now includes a new exclusion for flexible wires and cords (uses not permitted).

Flexible cables, flexible cord sets, and power supply cords are not permitted in areas that are "concealed by walls, floors, or ceilings or positioned above suspended or dropped ceilings," according to Note 5.

The following uses for flexible cables, flexible cord sets, and power supply cords are prohibited as well:

(1) As an alternative to a structure's fixed wiring.

(2) Run-through openings in structural ceilings, floors, suspended ceilings, or dropped ceilings.

(3) When run through windows, doorways, or comparable openings.

(4) If attached to building surfaces.

Hence, Option (b) All of these is correct .

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