Explanation:
Distance= speed × time
= 6 × 12 m
= 72 m
"An object at rest starts accelerating. If it is going 120 m/s after traveling 202 meters, how quickly did it speed up?"
Answer:
this is just a guess bc i only looked at it for 5 seconds but i think 150 m/s
An object of mass 300 kg is observed to accelerate at the rate of 4 m/s 2 . Calculate the force required to produce this acceleration
Answer:
F = 1200 N
General Formulas and Concepts:
Forces
Newton's Second Law of Motion: F = ma
F is force (in N)m is mass (in kg)a is acceleration (in m/s²)Explanation:
Step 1: Define
Identify variables
m = 300 kg
a = 4 m/s²
Step 2: Find Force
Substitute in variables [Newton's Second Law of Motion]: F = (300 kg)(4 m/s²)Multiply: F = 1200 NTopic: AP Physics 1 - Algebra Based
Unit: Forces
A non-uniform rod XY of mass 40 kg and length 5.0 m lies on the horizontal ground. Its centre of gravity is 2.0 m from the end X. Calculate the vertical force P, that will just be sufficient to lift the end Y from the ground. Why would the force P, if applied at the end X not be sufficient to lift the end X from the ground? (8 = 10.0 (SC/GCE) ms-2)
The vertical force P, that will just be sufficient to lift the end Y from the ground is 600 N.
If the force P is applied at end X, it will not be sufficient to lift end X from the ground because the force P is acting downwards.
The sketch of the rod is presented as follows;
|---- 2 ----------|---------------------- 3 ----------------------|
X-----------------------------------------------------------------Y
P ↓
40 kg
Take moment about the center of gravity;
P(2) = 40 x g (3)
2P = 40 x 10 (3)
2P = 1200
P = 600 N
Thus, the vertical force P, that will just be sufficient to lift the end Y from the ground is 600 N.
If the force P is applied at end X, it will not be sufficient to lift end X from the ground because the force P is acting downwards.
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The acceleration of an object in uniform circular motion always points toward the center of the circle. Question 2 options: True False
Answer:
The answer is true. Hope this helps!
mass is conserved in a reaction if the of the initial reactant masses equals the of the masses of
Answer:
mass of the products
Explanation:
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Why are the four largest moons of Jupiter called Galileans
Answer:
because it's discovered by Galileo Galilei
Answer:
Hello how are you ^0^
Explanation:
because it's discovered by Galileo Galilei
hope it's help you (^0^)
A 925 kg car accelerates uniformly from rest to a velocity of 25.0 m/s in 10.0s. What is the net force on the car?
Answer:
A 925 kg car accelerates uniformly from rest to a velocity of 25.0 mls south in 10.0 s. What is the net force acting on the car during this time?
F=(925*25)/10
F=2312.5 N to south
Hi there!
We can begin by calculating the acceleration experienced by the car.
vf = vi + at
The initial velocity is 0 (at rest), so:
25 = at
25/10 = a = 2.5 m/s²
Using Newton's Second Law:
∑F = ma, where:
∑F = net force (N)
m = mass (kg)
a = acceleration (m/s²)
Plug in the values:
∑F = 925 · 2.5 = 2312.5 N
I need this asap pls I will mark brainliest!
Answer:
13.73 degrees farenheit
-10.15 degrees Celsius
Explanation:
hope this helps
What's a real-life example where you have pushed or pulled on different objects and you noticed a difference in how they moved.
Easy pts! Will give Brainliest too!
Answer:
Explanation:
Think about hockey for little to no friction if you push on the puck it moves fast and far.
Now imagine taking the same puck and pushing it on gravel or grass it will not have the same motion.
what type of telescope can be used routinely on the surface of the earth during the day?
Answer:
Radio telescopes .
Explanation:
They have a modest size that can't make out as much detail (have a lower resolution) than visible light telescopes
By moving her arms outward, an ice skater speeds up a spin, while moving her arms inward slows down a spin. Question options: True False
false
ITS TURE.When there is no torque acting on a body, its angular momentum is constant. Net force changes momentum, while net torque changes angular momentum.
Answer: false
Explanation:
in which state of matter would you expect to find water on earth surface if the tempature is 25\
Answer:
Water is a liquid at standard temperature and pressure (25 degrees Celsius and 1 atm, for liquids). Water is is tasteless and odorless.
Explanation:
A car with mass 1750 kg travels on a flat circular track with radius
80.0 m at constant
speed 35.0 m/s. What is the force of friction between the tires and the road enabling the turn?
Hi there!
On a horizontal circular track with friction, the net force acting in the horizontal direction is:
∑F = Fκ, or the force of kinetic friction.
We know that ΣF = Mv²/r, so:
Mv²/r = Fκ
Plug in the given values to solve:
(1750)(35²)/80 = Fκ
Thus:
Fκ = 26796.875 N
frequence = ?
lambda = 0.5m
Vacocity = 340m/s
Talking about physic waves things.
Answer:
Below
Explanation:
To find the frequency of a wave you can use this formula :
f = v / λ
f = 340m/s / 0.5m
f = 680 Hz
Hope this helps!
The wave speed is 3 x 10^8 m/s, and the frequency is 4 x 10^8 Hz. Calculate its wavelength.
Answer:
0.75m
Explanation:
V=FX
3×10^8=4×10^8×X
X= 3×10^8/4×10^8= 0.75m
8.) You push on a box with 100N of force. The box has a mass of 15 kg. What is
the acceleration of the box?
Answer:
he pushed 192,753,636,363
Explanation:
At the end of the Giant Drop free fall ride, riders experience a large experience a large upward normal force to bring their falling bodies to a stop. Determine the normal force value required to accelerate a 52.1-kg physics student with an upward acceleration of 27.4 m/s/s.
Newton's second law allows us to find the force applied to the student so that it has an upward acceleration of 27.4 m / s² is:
F = 1.94 10³ N
Newton's second law says that the force is proportional to the product of the mass and the acceleration of the body.
∑ F = m a
Where F is the force, m the mass and the acceleration of the body.
A free body diagram is a diagram of the forces without the details of the bodies, in the attachment we have a free body diagram of the system.
They indicate that the student's mass is 52.1 kg and his acceleration is 27.4 m / s², let's write Newton's second law.
F - W = ma
F = m a + W
Body weight is.
W = mg
F = m (a + g)
We calculate.
F = 52.1 (27.4+ 9.8)
F = 1.94 10³ N
In conclusion using Newton's second law we can find the force applied to the student is:
F = 1.94 10³ N
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Match the labels to the correct
location on the roller coaster.
At the bottom left,
Increasing potential energy.
At ascending,
Increasing kinetic energy.
At the peak,
Greatest potential energy.
At the descending,
Greatest kinetic energy.
would be equal to 0 miles.
If you travel from home, to school and back home, the measure of
distance
velocity
displacement
speed
Answer:
as we know Speed=Distance÷Time
Distance=Speed×Time
Velocity=Displacement÷Time
Displacement=Velocity×Time
u haven't given the speed and all give it and I will tell the answer
I NEED HELP ASAP! BRAINIEST TO THE CORRECT ANSWER. HELP ME NOW!
A 12v Light bulb uses 24v of power.
a) Calculate its resistance and the current at full power.
b) Calculate the resistance of a 100w mains light bulb and the current at full power.
c) Two bulbs are connected in series and supplied from the mains power at 230v. Calculate the current in the circuit. Assume that both bulbs operate at their working resistance.
d) Use your answer to part c) to comment on the brightness of the bulbs.
Answer:
a)[tex]\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}[/tex]
V = 12 VP = 24 W[tex]\implies \mathsf{24=\frac{12^2}{R} }[/tex]
[tex]\implies \mathsf{24R=12^2 }[/tex]
[tex]\implies \mathsf{24R=144 }[/tex]
=> R= 6 Ohms(Ω)
b)[tex]\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}[/tex]
Power (P)= 100 Wthese lights operate at the usual 240 volts direct from the main electricity supply. Therefore,
V = 240 V[tex]\implies \mathsf{100=\frac{240^2}{R} }[/tex]
R and 100 can interchange places
[tex]\implies \mathsf{R=\frac{240^2}{100} }[/tex]
[tex]\implies \mathsf{R=\frac{57600}{100} }[/tex]
=> R = 576 Ω
By Ohm's Law:
[tex]\boxed{\mathsf{Voltage(V)=Current(I) \times Resistance(R)}}[/tex]
=> 240 = I × 576
=>
=> I = 0.417 A
c)I don't know it's resistance,... so sorry
d)The brightness of the bulb in series is less than when they're placed individually.
For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.
Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.
So, the effective resistance of some bulbs in series is more than the individual resistance.
And
Brightness, i. e., Power
[tex]\boxed{\mathfrak{Power \propto \frac{1}{Resistance} }}[/tex]
If resistance increases, Power decreases.
Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.
Investigators studying the effect of hitting a soccer ball with the head are using a force plate to look at the forces in ball collisions; the force when the ball hits a player's head will be similar. A 0.43 kg ball is launched at a force plate at 16 m/s. Smoothed data for the force versus time for the collision are shown in (Figure 1).
The integral of the function of the force applied to the time of application
of the force gives the impulse of the force.
The speed with which the ball rebounds from the plate is approximately
34.23 m/s.
Reasons:
Force = Rate of change of momentum
F × t = m·(v₂ - v₁)
Where;
Speed of the ball, v₁ = 16 m/s
v₂ = The speed with which the ball rebounds from the plate
The impulse, I, of the force is given by the area under the curve.
The height of the triangular curve, h = 2,500 N
The base length of the triangular curve = 7 ms.
Area of a triangle = [tex]\frac{1}{2}[/tex] × Base length × Height
Therefore, we have;
[tex]Area \ under \ the \ curve, \, I = \dfrac{0.007 \times 2500}{2} = 8.75[/tex]
8.75 = 0.48 × (v₂ - 16)
v₂ ≈ 34.23 m/s
Therefore, the speed with which the ball rebounds, v₂ ≈ 34.23 m/s.
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The ______ describes the height or the wave measured from the central axis
Answer:
Amplitude
Explanation:
Answer:
the wave trough.
Explanation:
As is shown on the figure, wave height is defined as the height of the wave from the wave top, called the wave crest to the bottom of the wave, called the wave trough. The wave length is defined as the horizontal distance between two successive crests or troughs.
Imagine everyone in the United States exhibited the character traits we have been discussing. In what ways would America be different?
Now imagine no one in American exhibited any of those character traits. In what ways would America be different?
Answer:
Characterization is the process by which the writer reveals the personality of a character. Characterization is revealed through direct characterization and indirect characterization. Direct Characterization tells the audience what the personality of the character is.
true or false
your weight would be the same on the moon as it is on the earth
Answer:
False
Explanation:
You could weigh less on the moon then on Earth because the moon has a smaller gravitational force compared to Earth.
Can someone help me with this? (Also C is incorrect)
Answer:
i think its d
Explanation:
Look at the Sankey diagram for a filament light bulb below. If the bulb is used in a desk lamp, what is the efficiency of the bulb?
Answer:
The question does not state how the answer is to be entered. I would use 10% because that is most common.
Explanation:
You are using 300 J of energy to get 30 J of light energy. The fact that you can account for the left over energy is not relevant.
Efficiency = Work Out / Work In
Efficiency = 30 J / 300 J = 0.1
If you need this as a %, you can multiply by 100
Efficiency = 0.1 * 100 = 10%
why planets do not twinkle
Answer:
Explanation:
Basically because they are big and relatively near.
The light coming from a star travels a huge distance and is acted upon by the earth's atmosphere with causes all sorts of shifts. What we are seeing twinkle is caused by these shifts, for the most part caused by atmospheric density and heat.
The beam from a planet is not narrow enough to be affected the way the stars are.. If you were out in space looking at all this, the stars would not appear to twinkle either.
I need the right answer ASAP NO LINKS!!!
Answer:
Water and power come from external sources.
Explanation:
Phát biểu nào sau đây sai?
A. Hàm lượng cacbon trong thép cao hơn trong gang.
B. Sắt là kim loại màu trắng hơi xám, dẫn nhiệt tốt.
C. Quặng pirit sắt có thành phần chính là FeS2.
D. Sắt (III) hiđroxit là chất rắn, màu nâu đỏ, không tan trong nước.
Phát biểu nào sau đây sai?
A. Hàm lượng cacbon trong thép cao hơn trong gang.
B. Sắt là kim loại màu trắng hơi xám, dẫn nhiệt tốt.
C. Quặng pirit sắt có thành phần chính là FeS2.
D. Sắt (III) hiđroxit là chất rắn, màu nâu đỏ, không tan trong nước.
ANSWER:D. Sắt (III) hiđroxit là chất rắn, màu nâu đỏ, không tan trong nước.
___________________CARRY ON LEARNING
CAN YOU BRAINLEST ME
Safety engineers estimate that an elevator can hold 20 persons of 75kg average mass. The elevator itself has a mass of 500kg. Tensile strength test how the cable supporting the elevator can tolerate a maximum force of 2.96X10^4N. What is the greatest acceleration that the elevators motor can produce without breaking the cable? (show work)
The greatest acceleration that the elevators motor can produce without breaking the cable is 5 m/s².
The given parameters;
average mass of the 20 persons = 75 kgmass of the elevator, m = 500 kgtensile strength of the elevator, T = 2.96 x 10⁴ NThe total mass the elevator can support;
M = 500 kg + 20(75 kg)
M = 2000 kg
The greatest acceleration that the elevators motor can produce without breaking the cable occurs when the elevator is moving upwards;
T = M(a + g)
[tex]2.96 \times 10^4 = 2000 (a + 9.8)\\\\2.96 \times 10^4 = 2000a + 19600\\\\29600 - 19600 = 2000a\\\\10,000 = 2000a\\\\a = \frac{10,000}{2000} \\\\a = 5 \ m/s^2[/tex]
Thus, the greatest acceleration that the elevators motor can produce without breaking the cable is 5 m/s².
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