The spring constant is obtained from the ratio of applied force to the elongation of the spring. The work done by the force is 2F.
Spring constant
The spring constant is obtained from the ratio of applied force to the elongation of the spring.
k = F/x (N/m)
Work done by the forceThe work done by the force is calculated as follows;
W = ¹/₂FΔx
where;
F is applied forceΔx is elongation of the spring = 8 m - 4 m = 4 mW = ¹/₂F(4)
W = 2F
Thus, the spring constant is obtained from the ratio of applied force to the elongation of the spring. The work done by the force is 2F.
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when 82.5 calories of heat are given to a metallic rod of mass 150g its temperature raises from 20 degree celcius to 25 degree Celsius. what is the specific heat of the metal.
A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.
What is specific heat?It is the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).
A metallic rod of mass 150 g (m) absorbs 82.5 cal of heat (Q) and its temperature raises from 20 °C to 25 °C. We can calculate the specific heat (c) of the metal using the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 82.5 cal / 150 g × (25 °C - 20 °C) = 0.11 cal/g.°C
A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.
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Neil Armstrong dropped a hammer on the moon. If it took 4 seconds to fall and the final speed was 8 m/s, what is the acceleration due to gravity on the moon?
Answer:
2
Explanation:
8-0/4
Final velocity-initial velocity/time taken
A javelin is thrown at 28.5 m/s from flat
ground at a 43.2° angle. How much time
is it in the air?
(Unit = s)
HELP FAST
Answer:
did you ever the answer?
Explanation:
The time for the javelin in the air will be 3.977 second
What is the period?The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.
Given data;
Θ is the angle of throw = 43.2°
u is the thrown velocity = 28.5 m/s
t is the time for the javelin in the air
The time period is found as;
[tex]\rm t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5 \ sin 430.2^0}{9.81 } \\\\ t = 3.977 \ sec.[/tex]
Hence the time for the javelin in the air will be 3.977 second
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You drive 7.50 km in a straight line in a direction 10° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
a)The distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.
b)Both the routes have the same distance.
What is displacement?Displacement is defined as the shortest distance between the two points.
Distance is the horizontal length covered by the body, while displacement is the shortest distance between the two points. Displacement is a vector quantity.
Given data;
Distance,d = 7.5 km
Angle,θ=10° E of N
From the triangle ABD and ABC it is obtained that;
AC = AB sinθ
AC=7.5 sin(10°)
AC=1.302 km
CB = 7.5 cos 10°
CB = 7.386 km
AC is the distance in the east direction = 1.302 km
CB is the distance in the north direction = 7.386 km
Both the routes have the same distance. Hence you still arrive at the same point if the East and North legs are reversed in order.
Hence the distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.
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A cart is being pulled forward by a hanging mass. What is the value of the change in its kinetic energy, ΔEk?
Positive
Zero
Negative
The value of change in kinetic energy, ΔEk when a cart is being pulled forward by a hanging mass is Positive
In order words, ΔEk in the above question is positive
What is kinetic energy?Kinetic energy can be defined as the energy a body possess when the body is in motion or due its motion
In conclusion, the value of change in kinetic energy, ΔEk when a cart is being pulled forward by a hanging mass is Positive
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Set local ground level to 700 ft, and record the inches of mercury.
What is the altimeter reading in inches of mercury (from the Kollsman window)?
The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg
How to determine the altimeter reading?The given parameters are:
Ground level = 700 ft i.e. the field elevationPressure altitude = 1450 ftThe pressure altitude is calculated as:
Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level
Substitute the known values
1450 = (29.92 - Altimeter reading) * 1000 + 700
Subtract 700 from both sides
750 = (29.92 - Altimeter reading) * 1000
Divide through by 1000
0.75 = 29.92 - Altimeter reading
Evaluate the like terms
Altimeter reading = 29.17
Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg
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What’s the correct answer answer asap for brainlist
Answer:
animals and wildlife (c)
Explanation:
Ecotourism is essentially tourism of nature--which highly incorporates animals/wildlife
> it usually has a goal of conservation of nature
poaching is illegally hunting wild animals, which is focused on an aspect of nature protection (which is why it is ecotourism)
the only option listed here that is about ecotourism is animals and wildlife (c), meaning that this is the correct fill-in
hope this helps! have a lovely day :)
What is the mass of mars
the mass of mars is
6.39 × 10^23 kg
Elizabeth’s father is a crane operator, and she gets a chance to see him at work. He shows her a button in the crane, explaining that pushing it closes a circuit. When that happens, a car is attracted to the crane and lifted off the ground. When the button is released, the car falls back to the ground. How does the current made by the circuit produce this effect?
A: It generates force that pulls the car toward the crane lift.
B: It generates an electric field from the crane lift that affects the electricle charges in the car.
C: it generates a magnetic field that attracts the car magnetically to the crane lift
Choose ONE
The current made by the circuit produce this effect by generating a magnetic field that attracts the car magnetically to the crane lift and is denoted as option C.
What is a Crane?This is a machine which is used to lift and lower objects which are most times heavy.
It employs the use of magnetic force as it is generated when the button is switched on in this scenario.
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PLS HELP:
Find the magnitude of an electric field located 7.00 cm from a source charge of - 11 nC. (1nC = 1 x 10-9 C). Will the field lines point toward or away from the source charge? Show your work and include an electric field diagram assuming the source is a point charge
Answer:
E=kQ/r*2
=(9. 10*9)(11.10*-9)/(0,07)*2
=20204 N. C*-1
The field lines will point towards the source charge because it is negatively charged.
A space probe sent to Mars has a weight of 10,000 N on Earth (g = 10). What is its mass?
Answer:
[tex]1,\!000\; {\rm kg}[/tex].
Explanation:
The "[tex]g[/tex]" given in the question likely refers to the strength of the gravitational field. The standard unit of [tex]g[/tex] is [tex]{\rm m \cdot s^{-2}}[/tex], same as the standard unit of acceleration. However, since [tex]1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}[/tex], the standard unit of [tex]g[/tex] is equivalent to [tex]{\rm N \cdot kg^{-1}}[/tex].
For instance, the gravitational strength on the surface of the earth is approximately [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex]. However, the question did not specify the unit of this value.
If the mass of an object is [tex]m[/tex], the weight of that object would be [tex](\text{weight}) = m\, g[/tex] when the gravitational field strength around that object is [tex]g[/tex]. It is given that for the object in this question, [tex]m\, g = (\text{weight}) = 10,\!000\; {\rm N}[/tex] when [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex]. Therefore, the mass [tex]m\![/tex] of this object would be:
[tex]\begin{aligned}m &= \frac{(\text{weight})}{g} \\ &= \frac{10,\!000\; {\rm N}}{10\; {\rm N \cdot kg^{-1}}} \\ &= 1,\! 000\; {\rm kg}\end{aligned}[/tex].
For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged. The switch is then closed at time t = 0. How many seconds after closing the switch will the energy stored in the capacitor be equal to 50.2 mJ?
Hi there!
To start, we can use the equation for the charge of a capacitor versus time.
[tex]q(t) = C\epsilon (1 - e^{-\frac{t}{\tau}})[/tex]
[tex]q(t)[/tex] = Charge on capacitor vs. time
[tex]\epsilon[/tex] = EMF of battery (40 V)
**Note: 'Cε' is equal to the MAXIMUM CHARGE on a capacitor.
Where the time constant is given as:
[tex]\tau = RC[/tex]
[tex]\tau[/tex] = Time Constant (s)
[tex]R[/tex] = Resistance (0.5 MΩ)
[tex]C[/tex] = Capacitance (90 μF)
Let's first convert the given units to the necessary 'J', 'Ω' and 'F' to make things easier:
[tex]J = 50.2 mJ[/tex]
[tex]50.2 mJ * \frac{0.001J}{1mJ} = 0.0502 J[/tex]
[tex]R = 0.5 M\Omega\\\\0.5M\Ohm * \frac{1000000\Omega}{1M\Ohm} = 500000\Omega[/tex]
[tex]F = 90 \mu F[/tex]
[tex]90 \mu F * \frac{0.000001 F}{1\mu F} = 0.00009 F[/tex]
Now, let's calculate the time constant.
[tex]\tau = RC = (500000)(0.00009) = 45 s[/tex]
Time to use the equation for energy stored in a capacitor:
[tex]E_C = \frac{1}{2}\frac{Q^2}{C}[/tex]
Our 'Q' varies with time, so:
[tex]E(t)= \frac{1}{2}\frac{( C\epsilon (1 - e^{-\frac{t}{\tau}}))^2}{C}\\\\E(t) = \frac{1}{2}\frac{( C^2\epsilon^2 (1 - e^{-\frac{t}{\tau}})^2)}{C}\\\\E(t) = \frac{1}{2}( C\epsilon^2 (1 - e^{-\frac{t}{\tau}})^2)[/tex]
Let's now plug values into our equation.
[tex]0.0502 = \frac{1}{2}(0.00009)(40^2) (1 - e^{-\frac{t}{45}})^2[/tex]
Simplifying:
[tex]0.697 = (1 - e^{-\frac{t}{45}})^2[/tex]
Take the square root of both sides.
[tex]0.835 = 1 - e^{-\frac{t}{45}}\\\\ e^{-\frac{t}{45}} = 0.165[/tex]
Take the natural log of both sides.
[tex]-\frac{t}{45} = ln(0.165) \\\\\frac{t}{45} = 1.802\\\\t = \boxed{81.08 s}[/tex]
So, RCF, or relative centrifugal force should be equal to RCF = [tex]11,18*r*(RPM/1000)^2[/tex]
The radius is measured in centimeters and RPM is revolutions per minute.
What I don't know is, if I plug all the data in the formula, will the result equal to acceleration in meters per second squared, or it will be measured in g's so that if I multiply the g's by 9.8 meters per second square, it will give me the actual acceleration.
After plugging all the data into the equation, the result of the relative centrifugal force (RCF) is measured in terms of g.
What is relative centrifugal force?The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.
RCF = ac/g
where;
ac is centripetal accelerationg is acceleration due to gravity[tex]RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2[/tex]
where;
r is radius in cmFor example,Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);
[tex]RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g[/tex]
Thus, after plugging all the data into the equation, the result is measured in terms of g.
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The atomic mass of nitrogen is 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00. What is the molar mass of ammonium sulphate [(NH4)2SO4]?
A.
63.09 g
B.
84.17 g
C.
114.12 g
D.
118.16 g
E.
132.17 g
Reset Next
The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.
How to calculate molar mass?The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.
According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.
The molar mass of ammonium sulphate is as follows:
[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)
= 36.02 + 32.07 + 64
= 132.09
Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.
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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m.
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
1. How much energy was lost to air friction? The ball is kicked without a spin.
Hi there!
Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.
We also know there was work done on the ball by air resistance that decreased the ball's total energy.
Let's do a summation using the equations:
[tex]KE = \frac{1}{2}mv^2 \\\\PE = mgh[/tex]
Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)
[tex]E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)[/tex]
Our final energy, since we set the zero-line to be at H2, is just kinetic energy.
[tex]E_f = \frac{1}{2}mv_f^2[/tex]
And:
[tex]W_A = E_i - E_f[/tex]
The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.
Therefore:
[tex]W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2[/tex]
Solving for the work done by air resistance:
[tex]W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)[/tex]
[tex]W_A = \boxed{42.552 J}[/tex]
a man carries a hand bag by hanging on his hand and moves horizontally where the bag does not move up or down. What is the work done on the bag? The man gets tired after sometime of the movement. Why?
The work done by the man is the product of his applied force and the displacement of the bag and the man gets tired because his internal energy has be converted to work.
What is work done by the man?The work done by the man is the product of his applied force and the displacement of the bag.
Why the man gets tiredThe man gets tired because his internal energy has be used to do work on the bag.
Thus, the work done by the man is the product of his applied force and the displacement of the bag and the man gets tired because his internal energy has be converted to work.
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A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (vertical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.
The magnitude of the force on the left-hand pole is mathematically given as
f'=0.167N
Q=45 degrees
What is the magnitude of the force on the left-hand pole.?Generally, the equation for Force is mathematically given as
[tex]\frac{mg}{sin \theta}[/tex]
Therefore
[tex]F=\frac{17.1*10^{-3}*9.8}{sin45}[/tex]
F=0.237N
Considering horizontal axis or plane
f'-fcos=0
Therefore
f'=0.237*cos45
f'=0.167N
In conclusion, the slope
[tex]tan\theta= 30/30\\\\tan\theta=1\\\\\theta=45[/tex]
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Under normal conditions the human heart converts about 13.0 J of chemical energy per second into 1.30 W of mechanical power as it pumps blood throughout the body. (a) Determine the number of Calories required to power the heart for one day
The energy (in calories) required to power the heart for one day is 268.32 Cal
How to convert 1 day to seconds1 day = 24 h
24 h = 24 × 60 = 1440 mins
1440 mins = 1440 × 60 = 86400 s
Thus,
1 day = 86400 s
How to determine the energy (in calories) for 1 day (86400 s)From the question given,
1 s = 13 J
Therefore,
86400 s = 86400 × 13
86400 s = 1123200 J
Divide by 4186 to express in calories
86400 s = 1123200 / 4186
86400 s = 268.32 Cal
Thus, the energy needed to power the heart for 1 day is 268.32 Cal
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Complete question
Under normal conditions the human heart converts about 13.0 J of chemical energy per second into 1.30 W of mechanical power as it pumps blood throughout the body. (a) Determine the number of Calories required to power the heart for one day given that 1 Calorie equals 4186
Farsightedness is corrected with a ___ lens.
Farsightedness is corrected with a convex lens. The correct answer is a convex lens.
The center and edges of a convex lens alternate in thickness. Convergence or focus of the light rays caused by the passage of light through a convex lens aids in projecting the picture onto the retina of the eye. As a result, the person can see items in their immediate surroundings more clearly and the greater focus length of the eye is balanced.
In order to have a positive focal length, a convex lens must be thicker in the middle and narrower in the corners. A convex lens causes light to bend inward and towards its center as it travels through it. By bending the light, the focal point is brought closer to the lens and helps to focus the incoming light rays.
Hence, farsightedness is corrected with a convex lens. The correct answer is a convex lens.
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1. Calculate the magnitude of the gravitational force between the Earth and an m = 5.50 kg mass on the surface of the Earth. The distance to the center of the Earth from the surface is 6.37×103 km and the mass of the Earth is 5.98×1024 kg.
2. Calculate the magnitude of the gravitational force between the Moon and an m = 5.50 kg mass on the surface of the Earth nearest to the moon. The distance to the center of the Moon from the surface of the Earth is 3.76×105 km and the mass of the Moon is 7.36×1022 kg.
3. Calculate the ratio of the magnitude of the gravitational force between an m = 5.50 kg mass on the surface of the Earth due to the Sun to that due to the Moon. The mass of the Sun is 1.99×1030 kg and the distance from the center of the Sun to the surface of the Earth is 1.50×108 km.
1. The magnitude of the gravitational force between the Earth and an m is 54.1 N.
2. The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
Gravitational force between Earth and mass, m
The gravitational force between Earth and mass, m is calculated as follows;
F(Earth) = Gm₁m₂/R²
F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²
F(Earth) = 54.1 N
Gravitational force between Moon and mass, mF(moon) = Gm₁m₂/R²
F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²
F(moon) = 1.91 x 10⁻⁴ N
Gravitational force between Sun and mass, mF(sun) = Gm₁m₂/R²
F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²
F(sun) = 0.0324 N
Ratio of F(sun) to F(moon)= 0.0324/1.91 x 10⁻⁴
= 169.6
Thus, the magnitude of the gravitational force between the Earth and an m is 54.1 N.
The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
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What is inertia?by Walter Levin..
Inertia is directly proportional to mass.
What is Walter Lewin famous for?
Walter Hendrik Gustav Lewin (born January 29, 1936) is a Dutch astrophysicist and former professor of physics at the Massachusetts Institute of Technology.
Lewin earned his doctorate in nuclear physics in 1965 at the Delft University of Technology and was a member of MIT's physics faculty for 43 years beginning in 1966 until his retirement in 2009.
According to Walter Levin,
The concept of moment of inertia is demonstrated by rolling a series of cylinders down an inclined plane.
Inertia is the resistance of any physical object to a change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed when no forces act upon them.
By rolling a series of cylinders down on an inclined plane , he demonstrated that a cylinder have a smooth friction.
He compares the rolling cylinder by using hollow cylinder and a heavy cylinder , and finalize the result that a hollow cylinder moves slowly but the heavy cylinder move faster.
Hence , By doing this experiment he explained about the inertia that Inertia depend on the mass of the object. As the heavy the object it will take more time to travel or move.
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Hellowww..... =)
What is atomic number ?..
Answer:
The atomic number is the number of protons in an element
A cart is being pulled slowed down by a hanging mass. What is the value of the change in its kinetic energy, ΔEk?
Positive
Zero
Negative
Due a decrease in the velocity of the cart, the change in kinetic energy is negative
What is kinetic energy?Kinetic energy is the energy of a body due to its motion.
The change in kinetic energy is positive if the mass of a body or the velocity of the body increases.The change in kinetic energy is negative if the mass of a body or the velocity of the body decreases.The change in kinetic energy is zero if the mass of a body or the velocity of the body remains constant.Since the cart is slowed down, its velocity decreases and the change in kinetic energy is negative.
In conclusion, the change in kinetic energy of a body is affected by the mass and velocity of the body.
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Find the center of mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3).
The center of the mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3) is 37.62(cm)
Calculations and Parametersλ Fe =8g/cm,λ Al =2.7g/cm
There is a metal rod 1 meter long, with the first 50cm being iron and the other 50cm aluminum. the problem is solved in a one-dimensional case meaning it's a thin rod.
Next, we would solve by definition of the center of mass
We would also note that the masses of iron and aluminum are just the product of their length and linear density.
[tex]X_C_M[/tex]= [tex]\frac{8(g/cm). \frac{2500(cm^2)}{2} + 2.7 (g/cm). \frac{7500(cm^2)}{2} }{8(g/cm).50(cm) + 2.7(g/cm). 50 (cm)}[/tex]
= 37.62(cm)
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If the current in a wire increases from 5A to 10A, what happens to its magnetic field?
If the current in a wire increases from 5A to 10A, the magnetic field generated will also be doubled.
IntroductionHi ! I will help you to discuss about "magnetic field around a conducting wire". A conducting wire that carried electric current can generate amount of magnetic fields. In a standard winding condition, the increase number of electric current will be proportional to the increase number of the generated magnetic field. In other condition, the increase in distance (between center of field with a point) will be inversly proportional to the increase in the generated magnetic field. So, the magnetic field that generated around a current-carrying wire can be expressed in the following equation.
[tex] \boxed{\sf{\bold{B = \frac{\mu_0 \cdot I}{2\pi \cdot d}}}}[/tex]
With the following condition:
B = perceived magnetic field at a point (Wb/m² or T)[tex]\sf{\mu_0}[/tex] = vacuum permeability = [tex]\sf{4\pi \times 10^{-7} \: Wb/A.m}[/tex] I = electric current (A)d = distance of a point from the wire (m)Problem SolvingWe can assume that:
Only the increase in current affects the change in the value of the magnetic field.Other provisions such as the distance of the point from the conducting wire is considered the same.We know that :
[tex]\sf{I_1 : I_2}[/tex] = 5 : 10 = 1 : 2 >> the ratio between the current flowing in first and second sample.[tex]\sf{d_1 : d_2}[/tex] = 1 : 1What was asked ?
B = perceived magnetic field at a point = ... : ...Step by step :
[tex] \sf{B_1 : B_2} [/tex]
[tex] \sf{\frac{\cancel{\mu_0} \cdot I_1}{\cancel{2\pi} \cdot d_1} : \frac{\cancel{\mu_0} \cdot I_2}{\cancel{2\pi} \cdot d_2}} [/tex]
[tex] \sf{\frac{I_1}{d_1} : \frac{I_2}{d_2}} [/tex]
[tex] \sf{\frac{I_1}{\cancel d} : \frac{I_2}{\cancel d}} [/tex]
[tex] \sf{I_1 : I_2} [/tex]
[tex] \boxed{\sf{\bold{1 : 2}}} [/tex]
ConclusionFrom the above comparison, we can see that the ratio of the magnetic field at a point will be the same as the ratio of the current flowing through the conducting wire is 1 : 2. So, The magnetic field generated will also be doubled.
A man walks from point A to B at an average speed of 1.0 m/s and immediately returns at anaverage speed of 1.5 ms -1 .What is the average speed for the round trip?
The average speed of the round trip is 1.25 m/s.
What is the average speed of the journey?The average speed of the round trip journey is obtained by taking the average of the forward and return speed of the journey.
Average speed = initial speed + final speed/2Average speed = 1.0 + 1.5/2 = 1.25 m/s
In conclusion, the average speed of the round trip is the average of the initial and final speeds.
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. An airplane is cruising at altitude 10km. The pressure outside the craft is 0.287 atm; within the passenger compartment, the pressure is 1.00 atm and the temperature is 20 degree C. A small leak occurs in one of the window seals in the passenger compartment. Model the air as an ideal fluid to estimate the speed of the air stream flowing through the leak
The model of the Air as in ideal fluid estimating the speed of air stream flowing through he leak is given as; V = 347m/s. See the calculation below.
What is a model?A model is a mathematical equation that is used to represent a real life problem.
What is the model for the problem above?
P₁ + (1/2) pv₁² + pgh₁ = p₂ + (1/2) pv₂² + pgh₂
Hence,
1 + 0 + 0 = 0.287 + (1/2) (1.2) v²
Therefore,
V = 347m/s
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Vanessa made a list comparing the differences between the outer coverings in plants and animals, but she made a mistake. Read the table and then choose the statement that explains why the list is incorrect. Structure Description of Function Spines Protects the plant from predators and helps increase water loss Skin Protects the animal from changes in weather and its environment The skin is a reproductive organ. The skin offers little protection against the weather. The spines attract predators. The spines help decrease water loss.
The skin is NOT a reproductive organ and the spines attract predators are the incorrect statements.
Why the list is incorrect?The list is incorrect because skin is not a reproductive organ and the spines do not attract predators towards each other. Skin protects the body from the outer environment whereas the spines repel the predators from the plant body.
So we can conclude that the skin is NOT a reproductive organ and the spines attract predators are the incorrect statements.
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A frog leaps from flat ground at 6.32 m/s
at a 36.3 angle. What maximum height
does it reach?
(Unit = m)
Answer:
.714 m
Explanation:
The VERTICAL component is all we are interested in for this Q
Vertical velocity = 6.32 m/s sin 36.3° = 3.742 m/s
Vertical displacement = vo t - 1/2 at^2
= -1/2 at^2 + vo t
max occurs at - b/2a = -3.742/ (2(-1/2(9.81)) = .3814 sec
then vot-1/2 at^2 =
3.742 (.3814) - 1/2 ( 9.81)(.3814^2) = .714 m
Answer:
.714
Explanation:
In an attempt to escape his island, Gilligan builds a raft and sets to sea. The wind shifts a great deal during the day, and he is blown along the following straight lines:
2.5 km 45° north of west; then
4.70 km 60° south of east; then
5.1 km straight east; then
7.2 km 55° south of west; and finally
2.8 km 5° north of east.
What is his final position relative to the island?
km
° south of east
The final position of Gilligan in kilometers and degrees south of east relative to the island is 9.07 km, 61.4° south of east.
What is a vector simple ?A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.
The term also denotes the mathematical or geometrical representation of such a quantity.
According to the question,
Suppose, the direction east as i, direction west as -i, direction north as j and direction south as j.
Therefore,
1. : 2.5 km 45° north of west
[tex]= 2.5 cos45 (-i) + 2.5 cos45 (j)\\ = -1.77(i) + 1.77(j)[/tex]
2. : 4.7 km 60° south of east
[tex]= 4.7 cos60 (i) + 4.7 sin60 (-j) \\= 2.35(i) - 4.07(j)[/tex]
3. : 5.1 km straight east
[tex]=5.1(i)[/tex]
4 : 7.2 km 55° south of west
[tex]= 7.2 cos55 (-i) + 7.2 sin55 (-j)\\ = -4.13(i) - 5.9(j)[/tex]
5: 2.8 km 5° north of east
[tex]= 2.8 cos5 (i) + 2.8 sin5 (j)\\= 2.79(i) + 0.24(j)[/tex]
The sum of all the above yields,
[tex]R = 4.34(i) + 7.96(-j)[/tex]
The magnitude of the resultant is:
[tex]|R| =\sqrt{4.34^{2} + (-7.96)^{2} }= 9.07[/tex]
The angle that the resultant makes is as follows.
θ= [tex]tan^-^1(\frac{7.96}{4.34} )\\[/tex]
θ = 61.4°
Hence,
Final position relative to the island is 9.07 km, 61.4° south of east.
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