a fire hose has water entering from a fire hydrant at the rate of 2m/s with a pressure of 200000 pa. at the nozzle the pressure decreases to atmospheric pressure (101300 pa), there is no change in height. use the bernoulli equation to calculate the velocity of the water exiting the nozzle. (hint: the density of water is 1000 kg/m3 and gravity g is 9.8 m/s2 .

At the surface, the wind speed is between 13 to 17 knots. At 1 km or 850 MB level, the wind speed is between 48 to 52 knots. Thus, the 0-1 km wind shear is (48 -13) or (52-17) = 35 knots.

At 5 km or 500 MB level, the wind speed is between 68 to 72 knots. Thus, the 0-5 km wind shear is (68-13) or (72-17) = 55 knots.

Wind speed describes how fast air moves past a particular point. This can be averaged over specific time units. B. Miles per hour or instantaneous speed is reported as peak wind speed gust or squall. The wind is the natural movement of air or other gases against the surface of a planet.

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The presence of a current in an ammeter depends on the state of an external electrical switch. If the switch is closed, there will be a current in the ammeter; if the switch is opened, there will be no current in the ammeter. The length of time the switch has been in a particular state does not affect the presence of a current in the ammeter.

The presence of a current in an ammeter depends on the state of an external electrical switch. A switch is a device used to break or make an electrical connection, and can be used to control the flow of electricity in a circuit. In the following cases, the presence of a current in the ammeter can be determined:

(1) If the switch has just been closed, there will be a current in the ammeter. When the switch is closed, it creates an electrical connection, allowing electricity to flow through the circuit, and thus a current to be registered on the ammeter.

(2) If the switch has been closed for a long time, there will still be a current in the ammeter. This is because the switch is still in the closed position, allowing electricity to flow through the circuit, and thus a current to be registered on the ammeter.

(3) If the switch has just been opened, there will be no current in the ammeter. When the switch is opened, it breaks the electrical connection, preventing electricity from flowing through the circuit, and thus no current will be registered on the ammeter.

(4) If the switch has been opened for a long time, there will still be no current in the ammeter. This is because the switch is still in the open position, preventing electricity from flowing through the circuit, and thus no current will be registered on the ammeter.

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Given,

          Speed of wind v = 10.5 m/s

          Dimension of plate = 6 m times 1.10 m

          The density of air d = 1.20 kg/m³

Therefore,

         F = (1/2)dv²A

         A = 6(1.10)m²           [From dimension]

         F = (1/2)(1.20)(10.5)²(6)(1.10)

         F = 436.59 N

The force on the window pane is 436.59 N.

(a) if the wind speed is 21 m/s

        F = (1/2)(1.20)(21)²(6)(1.10)        

        F = 1746.36 N

The force on the window pane is 1746.36 N.

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A pristine nickel surface with a work function of 5.1 eV is exposed to 206 nm light. The photoelectrons released from this surface have a maximum speed of 521.8 x 10^3 m/s.

An electron of the metal can receive photon energy from incident light, which is equal to the planck's constant times the light's frequency.

f = c/∧

assuming that all of the photon energy has been utilized

First in removing electrons from metals (work function)

Second, the leftover is used to furnish the photoelectron with kinetic energy:

V(m) = √2/M(hc/∧)-5.1eV.

where: M = 9.11 x10^3 kg; is the mass of nickel

h = 6.63 x 10 -34 Js; is plancks constant

c = 3 x 10^8 m/s; is the speed of light

∧ = wavelength of light = 206 nm = 206x10-9m

v(m) = (2 x 6.63 x 10-34 x 3 x10^8)/206 x 10-9 x 9.11x10^3 - 5.1 eV

v(m) =  521.8 x 10^3 m/s.

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If the coefficient of kinetic friction on the plane is 0.4, the acceleration of the block is 0.3 m/s² and tension is T = 1.82N.

A property of a body that is a measure of inertia is usually viewed as a measure of the amount of matter contained in the body that causes it to have weight in a gravitational field. Mass is a dimensionless quantity that describes the amount of matter in a particle or object.

Calculation:-

Tension force = I/R² × a

= 0.5 × 3.564

T = 1.782 N.

acceleration = 1.782/3

= 0.3 m/s²

The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.

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The vector quantity with a magnitude equal to the product of the two equal charges with opposing polarity separated by a distance, d, is defined as the electric dipole moment associated with it.

The distance between the charges and a direction running along the line between the charges from the negative to the positive charge.

Two charges totaling 10.0 C and spaced 2.00 cm apart make up the dipole. The positive charge is further away from the line of charge than the negative charge, and the dipole's axis forms a 35.0° angle with the x-axis.

The dipole will be subject to a force that is Charges 2.0108C separated by a distance of 2.0103m make up an electric dipole. As seen in the picture, it is positioned so that the negative charge is 2.0 cm away from a long line charge with a linear charge density of 4.0104Cm1. The pressure on the Axis.

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Answer: Finally, we can use this value to find the final velocity of the 15.0 g coin. Since velocity is defined as the change in position over time, and the 15.0 g coin is initially at rest, its final velocity must be equal to its final momentum divided by its mass. Therefore, the final velocity of the 15.0 g coin is 187.5 g cm/s / 15.0 g = 12.5 cm/s. Since the 5.0 g coin is moving to the right and the 15.0 g coin is moving

Explanation: To solve this problem, we can use the conservation of momentum. Momentum is a measure of an object's motion and is defined as the product of its mass and velocity. In an elastic collision, momentum is conserved, meaning that the total momentum of the system before the collision is equal to the total momentum after the collision.

We can use this principle to find the final velocity of the 15.0 g coin. First, we need to calculate the initial momentum of the system. The 5.0 g coin has an initial momentum of 5.0 g * 25.0 cm/s = 125 g cm/s. Since the 15.0 g coin is initially at rest, its initial momentum is 0 g cm/s. The total initial momentum of the system is therefore 125 g cm/s.

After the collision, the 5.0 g coin moves to the left at 12.5 cm/s, so its final momentum is 5.0 g * (-12.5 cm/s) = -62.5 g cm/s. Since momentum is conserved, the final momentum of the system must be equal to the initial momentum of the system, so the final momentum of the 15.0 g coin must be 125 g cm/s - (-62.5 g cm/s) = 187.5 g cm/s.

Finally, we can use this value to find the final velocity of the 15.0 g coin. Since velocity is defined as the change in position over time, and the 15.0 g coin is initially at rest, its final velocity must be equal to its final momentum divided by its mass. Therefore, the final velocity of the 15.0 g coin is 187.5 g cm/s / 15.0 g = 12.5 cm/s. Since the 5.0 g coin is moving to the right and the 15.0 g coin is moving

Answer:

Check explaination

Explanation:

A - Transformer is the right option 100%

A transceiver is a combination transmitter/receiver in a single bundle. while the time period normally applies to wireless communications gadgets, it is able to also be used for transmitter/receiver devices in cable or optical fiber structures.

The electricity of the antenna is given by,

The resistance of the antenna is steady, for this reason,

Pa(avy

Now the voltage difference is,

AV = Bjcos8

consequently, the voltage distinction is directly proportional to t

cosine of the angle.

AVecosé (because B and/are constant)

subsequently, the electricity received,

Paces

therefore, if the angle of the willing is 14.three°, then the

acquired electricity by the antennas,

Pm c0s414,3°=0,93899

Paw

93.9%

if the perspective of the inclined is 45°, then the

obtained electricity by means of the antenna is,

SP price a5¢=05

Pan

50%

if the perspective of the inclined is 90°, then the

received energy with the aid of the antennas,

Pn cos? 9%=

Paw

= 0.0%

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(a) The maximum height to which Superman can lift the water is 10.32874 m

(b) On the Moon there is no atmosphere so no atmospheric pressure which means when the straw is placed in water water will not rise in the tube.

Pₐ = Atmospheric pressure = 101325 Pa

g = Acceleration due to gravity = 9.81 m/s²

h = Height of water

ρ = Density of water = 1000 kg/m³

If the walls of the tube do not collapse that means that maximum pressure inside will be the atmospheric pressure

Atmospheric pressure is given by

Pₐ = ρgh

height = Pₐ /ρg

h = 101325 / 1000 * 9.81

h = 10.328 m

The maximum height is 10.32874 m.

(b) On the Moon there is no atmosphere so no atmospheric pressure which means when the straw is placed in water water will not rise in the tube.

Therefore, the maximum height to which Superman can lift the water is 10.32874 m.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Superman attempts to drink water through a very long vertical straw. With his great strength, he achieves maximum possible suction. The walls of the tubular straw don't collapse.

(a) Find the maximum height through which he can lift the water.

(b) Still thirsty, the Man of Steel repeats his attempt on the Moon, which has no atmosphere. Find the difference between the water levels inside and outside the straw.]

The force that the table exerts on the box1 is 65.2N

As given in the question we are assuming box 2 and 3 aren't touching.

The forces on box 2 are:

gravitational force

Force of tension

Normal force

The box isn't accelerating so

T + N2 - Fg2 = 0

The forces acting  on the box 3 are:

gravitational force

Tension

Since box 3 isn't accelerating

T - Fg3 = 0

The tension force will be same in both cases so:

Fg3 + N2 - Fg2 = 0

So

N2 = Fg2 -Fg3

N2 = Fg2 - Fg3

= 39-25.3 = 13.7 N

Remember forces are equal and opposite.

Now,

write the equation for the forces which are acting on Block 1

There is the force of gravity

normal force acting from the table and

A force which is equal and is opposite to the normal force on block 2

N1 - F(g1) - N2 = 0

N1 = Fg1 +N2

N1 = 51.5 + 13.7 = 65.2 N

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The time of the travel with 20m/s is 17.5 seconds. Thus, the final velocity of the car will be 63 m/s.

Velocity of an object is the measure of the distance travelled per unit time. The rate of change in velocity is called the acceleration.

Given that, initial velocity u = 20 m/s

distance = 350 meters.

time of travel = distance/ velocity

 = 350 m/20 m/s = 17.5 s.

Acceleration = 2.5 m/s²

the final velocity v = u + at.

v = 20 + (2.5 × 17.5 ) = 63 m/s.

Therefore, the final velocity of the car is 63 m/s.

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After 2seconds of sending sonar, a ship hears an echo. The depth of the sea is 1500 meters if the sound wave speed in water is 1500 m/s.

Let sea depth equal d.

Considering that the sound wave's water speed (v) is 1500 m/s

The sound must travel to the ocean's bottom before being reflected back to the ship, resulting in a total distance of two dimensions for the sound.

Time (t) = 2s for receiving the echo

Total distance traveled times the speed of sound

1500 m/s is equal to 2d/2s = 1500 m.

Consequently, the water is 1500 meters deep.

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The percentage of mechanical energy lost (converted into thermal energy) during the collision will be equal to 95.2%.

Kinetic energy is the term used in physics to describe the force that a moving item has.

It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.

As per the information in the question,

Ball's mass, m₁ = 50 g = 0.05 kg

Speed  = v₀

Brick's Mass, m₂ = 1 kg

Assume the speed of the brick after the collision is v.

Use the equation of the principle of conservation of linear momentum,

[tex]m_1v_o+m_2u_2= v(m_1+m_2)[/tex]

0.5(v₀) + 0 = v(1 + 0.05)

v = (0.05v₀)/1.05

v = 0.048v₀.

Then the total kinetic energy will be:

K.E(initial) = 1/2 × 0.05v₀² + 1/2 × 0.05 × 0²

K.E(initial) = 0.025v₀²

Then,

K.E(final) = 1/2 × (1.05) × (0.048v₀)²

K.E(final) = 0.0012v₀²

So, the amount of mechanical energy lost in collision,

= (0.025v₀² - 0.0012v₀²)/0.025v₀² × 100

= 95.2%.

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This question seems incomplete, the complete question may be:

A 50 g ball of clay traveling at speed vo hits and sticks to a 1.0 kg brick sitting at rest on a frictionless surface. a. Find an expression for the speed of the brick after the collision in terms of vo. b. What percentage of the mechanical energy is lost (i.e. converted to thermal energy) in this collision?

a) D = -4273(x)-2327(y)

b) average speed v = 23.33m/s

c) average velocity V = -13.51m/s  south of west.

In order to find the displacement we have to divide the motion on its X and Y components:

dx1 = 25*2*60min = 3000

dx2 = 30*1*60s/min(cos45) = 1273 m

The total X displacement is the algebraic sum of the movement:

dx = -3000 - 1273 = -4273

We have to do the same on Y:

dy1 = 20*3*60 = 3600

dy2 = 30*1*60(sin45) = 1273

dy = -3600 + 1273 =-2327m

D=-4273(x)-2327(y)

The angle is given by:

α = arctg(dy/dx)

α = 28.57 degrees

That is 28.57 degrees south of west.

the total displacement magnitude is given by:

D = √{(4273) - (2327)}

D= 4865

The average speed is given by:

v = (20*3)+(25*2)(1*60)/6*60

v =23.33 m/s

and the Average velocity is given by:

|v| = 4865/6*60

|v| =13.51 m/s

Therefore, the average velocity is V = -1351 m/s with an angle of 28.57 degrees south of west.

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a) D = -4273(x)-2327(y)

b) average speed v = 23.33m/s

c) average velocity V = -13.51m/s  south of west.

In order to find the displacement we have to divide the motion on its X and Y components:

dx1 = 25*2*60min = 3000

dx2 = 30*1*60s/min(cos45) = 1273 m

The total X displacement is the algebraic sum of the movement:

dx = -3000 - 1273 = -4273

We have to do the same on Y:

dy1 = 20*3*60 = 3600

dy2 = 30*1*60(sin45) = 1273

dy = -3600 + 1273 =-2327m

D=-4273(x)-2327(y)

The angle is given by:

α = arctg(dy/dx)

α = 28.57 degrees

That is 28.57 degrees south of west.

the total displacement magnitude is given by:

D = √{(4273) - (2327)}

D= 4865

The average speed is given by:

v = (20*3)+(25*2)(1*60)/6*60

v =23.33 m/s

and the Average velocity is given by:

|v| = 4865/6*60

|v| =13.51 m/s

Therefore, the average velocity is V = -1351 m/s with an angle of 28.57 degrees south of west.

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Force is 436.59 N and the speed is 1.746 kN.

A) Force F = P*A = 0.5*rho*v^2*A = 0.5*1.2*10.5^2*6*1.1 = 436.59 N

B) If v is doubled then F increases by 4 times since F is proportional to the square of the speed.

then F2 = 4*436.59 = 1746.35 N = 1.746 kN

A body can change its condition of rest or motion through the application of force, which is an external agent. It has. both a magnitude. and. a direction. The application of force is the point at which force is applied, and the direction in which the force is applied is referred to as the direction of the force. If motion is conceivable, gravitational forces can separate phases of various densities. One option is widespread melting, but high temperatures are not anticipated for the early Earth (Chapter 2). Sorting as a result of deeply buried ices outgassing is a more likely explanation. Such processes would have altered the moment of inertia, necessitating a modification of angular velocity.

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A decrease in porosity occurs when rocks form joints or faults.

Option B is correct

Porosity is the entire available area for groundwater to live in. A rock's or sediment's porosity impacts how much water it can hold. The porosity of sediments and sedimentary rocks is influenced by the size, shape, and degree of sorting of the grains as well as the degree of cementation.

A good permeability must coexist with good porosity for groundwater to enter a rock. The pore gaps between the rock grains must be linked for a rock to be permeable and allow water to pass through it.

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Answer:

50

Explanation:

100×50÷1000= 50

this is easy question

Evaporation is a cooling process and condensation is a warming process.

Condensation is the transition of a region of matter from a gaseous state to a liquid state and the opposite of vaporization. This word most often refers to the water cycle. Condensation is the process by which water vapor becomes a liquid. This is the opposite of evaporation, which turns liquid water into vapor. Condensation occurs in one of two ways. When the air cools to its dew point or becomes saturated with water vapor, it can no longer hold water.

Evaporation is always a cooling process. For evaporation to occur, energy is needed by the liquid molecules that are changing phase into gas. This energy is taken from the surroundings in the form of heat energy. So when evaporation occurs, the temperature of the surroundings will decrease, making evaporation a cooling process.

Condensation occurs when warmer, moist air comes into contact with cooler surfaces such as frames, windows, and other superstructures, or cooler areas inside an insulating shell (where moisture has penetrated the vapor barrier).

Therefore, evaporation is a cooling process and condensation is a warming process.

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The amount of labour that gravity does is 28.58J. And the work produced by kinetic friction is -28.58J. A force that acts between moving surfaces is referred to as kinetic friction.

We may determine the slope length or hypotenuse using elementary trigonometry: cos(20) = 2.00. (slope length)

slope length: 2.00 m/cos(20) = 2.13 m

The box covers this distance while moving at a constant speed.

In terms of the forces, the total force parallel to the inclined plane acting on the box is given by the equation: F = W - f = mgsin(20) - f, where f represents friction and W is weight.

Work = Wd = (+13.2N)(2.13m) = 28.58J, which is the amount of work done by the force of kinetic friction.

The force acts in the same direction as the displacement, resulting in work.

The kinetic friction force exerts the following work:

Work= -fd =(-13.42N)(2.13m) = -28.58J

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the speed of the upper end of the pole just before it hits the groundv  is = 7.27 m / s

Explanation:

At both the greatest and lowest points, we shall practise energy conservation.

first. The highest point

Em₀ = U

Em₀ = m g y

final. smallest point

At this point, we adjust the reference system so that the potential energy is 0

= K

= ½ m v²

how to conserve energy

Em₀ =

mg y = ½ m v²

v = √2 gy

v = √ (2 9.8 2.7) (2 9.8 2.7)

v = 7.27 m / s

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The ratio that measures the reasonableness of accounts receivable outstanding, and can be used to estimate the average collection period of accounts receivable is the accounts receivable turnover ratio.

The amount owed to a business for goods or services that have been delivered or utilized, but for which consumers have not yet made payment is known as accounts receivable, or AR. A current asset is defined as accounts receivable on the balance sheet. Any sum that clients owe for purchases they made with credit is considered AR. Account receivable is the term used to describe any unpaid invoices or cash that a business is owed by customers. Accounts that a company is entitled to get as a result of delivering a good or service are referred to by the phrase. Receivables, also known as accounts receivable, are a type of line of credit that a business extends to customers. Typically, the terms of receivables stipulate that payments must be made within a reasonable amount of time.

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(a)The angular velocity v(d)' is 0.936 m/s

(b)The velocity of the sphere is 3 rad/s

Let us assume that

angular velocity of member ABC is v(d)'

velocity of the sphere = ω'

Write the moment of inertia of the member ABC

I(G) = 1/12 ML²

I(G) = 1/12*(2.4)(0.75m)²

I(G) = 0.112 kgm²

After the impact

ω = ω'(ccw)

ν'(G) = (L/4)ω' (upwards)

ν'(A) = (L/4) ω' (downwards)

Take the moments about B

m(d)v(d)(L/4) + 0 = m(d)v'(d)(L/4) + I(G)ω' + Mv'(G)(L/4)

m(d)v(d)(L/4) = m(d)v'(d)(L/4) + I(G)ω' + M(L/4)²ω'

m(d)v(d)(L/4) = m(d)v'(d)(L/4) + ] I(G) + M(L/4)² ]ω'

(0.8)(3)(0.75/4) = (0.8)v'(d)(0.75/4) + [ 0.112 + (2.4)(0.75/4)²

0.45 = 0.15v(d)' + 0.1963ω' -------------------- (eq1)

From the coefficient of restitution,

v(d)' - v(A)' = -e [ v(d) - v(A) ]

v(d)' - (L/4)ω' = -(0.5) [3-0]

v(d)' - (0.75/4)ω' = - 1.5

v(d)' - 0.1875ω' = - 1.5 ---------------------- (eq 2)

From eq 1 and eq 2

v(d)' = 0.936 m/s

ω' = 3 rad/s

Therefore, the angular velocity is 0.936 m/s and the velocity of the sphere is 3 rad/s.

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By knowing i. the time it takes for Jupiter to orbit the sun and ii. the time it takes for the moon to orbit Jupiter's mass of Jupiter can be determined. Therefore options I and II are correct.

To determine the mass of Jupiter, the student needs information about both Jupiter's orbit around the Sun (I) and the moon's orbit around Jupiter (II).

By knowing the time it takes Jupiter to orbit the Sun (I) and the time it takes for the moon to orbit Jupiter (II), the student can use Kepler's Third Law of Planetary Motion.

This law relates the orbital period and the average distance of a moon from its planet to the mass of the planet.

By knowing both the orbital periods of Jupiter and its moon (I and II) and the average distance between the moon and Jupiter (III is not required), the student can calculate the mass of Jupiter using Kepler's Third Law.

Therefore options I and II are correct.

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Without an air resistance, a projectile fired horizontally at 8 km/s from a mountain top will:

All objects with mass or energy are drawn to one another by the basic interaction of gravity. Gravity is by far the weakest of the four fundamental interactions, and is greatly outweighed by the electromagnetic force, the weak interaction, and the strong interaction. As a result, it has little effect on phenomena occurring at the level of subatomic particles. However, gravity is the most significant interaction between objects at the macroscopic level and controls the motion of planets, stars, galaxies, and even light.

Similar to how gravity on the Earth gives weight to the physical objects, the Moon's gravity creates sublunar tides in the oceans (the corresponding antipodal tide is caused by the inertia of the Earth and Moon orbiting one another). Additionally, gravity is a key factor in variety of biological processes, such as gravitropism, which controls plant development, and  fluid movement in multicellular organisms. Research on consequences of weightlessness indicates that the gravity may have an impact on how the immune system and cells differentiate in the human body.

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Its angular momentum vector of it is O.A. downward-pointing arrow with a clockwise motion and accelerating speed. no rotational (angular) characteristics. an upwardly directed arrow.

1. A negative angular velocity indicates that motion is in the clockwise direction. The object is speeding up because the signs of angular acceleration and velocity are both negative. Thus, turning in a clockwise direction and quickening.

2. The standard acceleration is equal to v2/R. Consequently, none of the rotational (angular parameters)

3. An arrow pointing up represents the top's angular momentum as it spins counterclockwise.

An object's or system of objects' angular momentum is a property that describes its rotational inertia as they move around an axis that may or may not pass through them. Due to its yearly rotation around the Sun and daily rotation about its axis, the Earth has both orbital and spin angular momentum. An accurate explanation of angular momentum necessitates the identification of both a magnitude and a direction because it is a vector quantity. An orbiting object's angular momentum is proportional to its linear momentum, which is the sum of its mass m and linear velocity v, multiplied by the perpendicular distance r from the center of rotation to a line drawn across its instantaneous motion.

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The voltages across the capacitor and inductor may be greater than the input voltage when the circuit is at or close to the resonance. The resistance voltage is 90 degrees behind the inductor voltage.

The VC (t) phasor has an amplitude of VC=I0XC and lags the i(t) phasor by /2 rad. The vL(t) phasor has the amplitude VL=I0XL and trails the i(t) phasor by /2 rad.

In a series LCR circuit, the voltage drop across the inductor or capacitor can, in fact, exceed the applied voltage of the a.c. source. VC or VL may be bigger than V since VC and VL have opposing faces. The RMS current for an applied V = volts RMS voltage is I = x 10 amperes. You may calculate the component voltages by multiplying the current.

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The speed and direction of piece b is 11.33m/s positive x direction.

Total momentum = 0 (at rest)

Applying conservation of linear momentum,

Momentum after explosion = momentum before explosion

MaVa + MbVb + McVc = 0

100(-60) + 150Vb + 70(86) = 0

Vb = 11.33m/s

Speed of Vb = 11.33m/s

In Newtonian mechanics, momentum is the result of an object's mass and velocity, more precisely linear momentum or translational momentum. This mechanical quantity is typical. It has. a direction. and a magnitude., making. it a vector. quantity. The momentum of an item is expressed as: [tex]displaystyle mathbf p =m mathbf v.mathbfp = m mathbf v[/tex]  if m is the object's mass and v is its velocity (also a vector quantity).

The kilogram metre per second (kg m/s), which is a unit of measurement for momentum in the International System of Units (SI), is a unit of measurement for a newton-second.

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a. the force that the mountain climber must exert with her feet in N) on the vertical rock face to remain stationary is 273 N.

b. the minimum coefficient of friction between her shoes and the cliff is 0.268.

What is the term of friction?

The force that prohibits one solid object from traveling across another is known as friction. Static friction, sliding friction, rolling friction, and fluid friction are the four main categories of friction.

a).

Balancing the forces in x-direction,

F cos(15) = T sin(31)

F = T sin(31)/cos(15)     ...... (1)

balancing the forces in y-direction,

T cos(31) + F sin(15) = 52 x 9.8 = 509.6

T cos(31) + (T sin(31)/cos(15)) sin(15) = 509.6

T = (509.6 cos(15))/(cos(31) cos(15) + sin(31) sin(15))

T = 512 N

Force, F = 512 sin(31)/cos(15)

= 273 N

b)

Coefficient of friction,

u = sin(15)/cos(15)

= 0.268

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In the operating system's command-line shell, parameters are provided after the program's name. Typically, we define main() with two arguments: a list of command-line arguments and a number representing the number of command-line arguments.

We'll talk about utilizing the Environment class to retrieve and show command-line arguments in this article. Therefore, we use the Environment Class's CommandLine property to do this task. To locate the command line for the active process, utilize this attribute. Message Type: This property returns a string as its return type.

Only the main() method can accept parameters from the command line.

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