A container that weighs 23 2/5pounds
holds sports equipment. Of the
equipment in the container, of the
1
3
weight is baseball equipment. What is the
weight of the baseball equipment?

Answer:

$800

Step-by-step explanation:

Let's say that Shola's salary is x dollars. This means that Akin's salary is 0.8x dollars, because his salary is 20% less than Shola's salary.

Since Shola spent 45% of his salary on accommodation, he had 0.55x dollars left, or $550. This means that we can write the equation 0.55x = 550.

To solve for x, we can divide both sides of the equation by 0.55 to get x = 1000. This means that Shola's salary is $1000, and since Akin's salary is 20% less than Shola's, his salary is 0.8 * 1000 = $800. Therefore, Akin's salary is $800.

 2 sin A sin B with two angles A and B, 2 sin A sin B = cos (A-B) - cos (A + B). The 2sinasinb formula is equivalent to the difference between the angle sum and the angle difference of the cosine functions. The formula for two sins is two sins A and two sins B: cos (A-B) - cos (A + B).

What is 2SinASinB Identity?

2SinASinB identity is a trigonometric formula and it is used for the simplification of trigonometric expressions. It is also used for evaluating integrals involving trigonometric functions for easy calculation. We can derive the formula for 2SinASinB using the angle sum and angle difference formulas of the cosine function. Using the 2SinASinB formula, we can derive another trigonometric formula for SinA SinB given by, sinA sinB = (1/2)[cos(A - B) - cos(A + B)].

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Answer:

  (x, y) = (17, 10)

Step-by-step explanation:

You want the values of x and y given three angles written in terms of x and y at a transversal crossing parallel lines.

Angles at lower right of the points of intersection are corresponding angles, and are congruent:

  (9x -16)° = (8x +1)°

  x = 17 . . . . . . . . . . . . . divide by °, add 16-8x

The marked angles at the bottom form a linear pair, so are supplementary.

  (4y +3)° = 180° -(9x -16)°

  4y +3 = 180 -9(17) +16 = 43 . . . . . . use 17 for x and simplify

  4y = 40 . . . . . . subtract 3

  y = 10 . . . . . . divide by 4

By using distance formula, it can be calculated that-

Distance between  (-4, -5) and (4, 2) is [tex]\sqrt{113}[/tex] units

What is distance formula?

Distance formula is used to find the distance between two coordinates.

If the points are [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex], then distance is calculated by the formula

d = [tex]\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

The points are (-4, -5) and (4, 2)

Distance between  (-4, -5) and (4, 2) = [tex]\sqrt{(-4-4)^2+(-5-2)^2}[/tex]

                                                            = [tex]\sqrt{64 + 49}\\\sqrt{113}[/tex]units

Distance between  (-4, -5) and (4, 2) is [tex]\sqrt{113}[/tex] units

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Answer:

Therefore, the correct solution graph for the inequality is a line with no solution. This means that there is no value of x that satisfies both inequalities at the same time.

Step-by-step explanation:

To solve this inequality, we need to consider the two separate cases of 7x+2≥30 and 2x-3≤-11 separately.For the first case, 7x+2≥30, we can rewrite the inequality as 7x≥28, which simplifies to x≥4. This means that the solution for this inequality is x≥4.For the second case, 2x-3≤-11, we can rewrite the inequality as 2x≤-8, which simplifies to x≤-4. This means that the solution for this inequality is x≤-4.To find the combined solution for both inequalities, we need to take the intersection of these two solutions. The intersection of x≥4 and x≤-4 is the empty set, which means that there is no solution that satisfies both inequalities

The Cost make up of procedure 1 is $280000.

Cost make up of procedure 2 is 140000

The cost makeup will be calculated thus:

Cost make up of procedure 1

Labour (40%) 112000

Materials (45%) 126000

Overhead (15%) 42000

Total =[280000

Cost make up of procedure 2

Labour ( 60%) 84000

Materials (30%) 42000

Over head (10%) 14000

Total 140000

Working note:

Sales $600000

Less: Gross profit (sale *30%) $ 180000

COGS $420000

Procedure 1 ( COGS *2/3) $ 280000

Procedure 2 (COGS * 1/3) $ 140000

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Complete question

Blue Skies Inc. is a retail gardening company that is piloting a new strategic initiative aimed at increasing gross profit. Currently, the company’s gross profit is 25% of sales, and its target gross profit percentage is 30%. The company’s current monthly sales revenue is $600,000. The new initiative being piloted is to produce goods in-house instead of buying them from wholesale suppliers. Its in-house production process has two procedures. The makeup of the costs of production for Procedure 1 is 40% direct labor, 45% direct materials, and 15% overhead. The makeup of the costs of production for Procedure 2 is 60% direct labor, 30% direct materials, and 10% overhead. Assume that Procedure 1 costs twice as much as Procedure 2.

Determine what the cost of labor, materials, and overhead for both Procedures 1 and 2 would need to be for the company to meet its target gross profit.

Answer: D is  the right answer .The slope of KM is 1 and the slope of NL is –1.

A rhombus is a parallelogram whose all sides are equal. Its diagonals perpendicularly bisect each other.

i.e. product of its slope should be -1.

[∵if one line is perpendicular to the other lines then product of its slope should be -1.]

Slope of  KM= 1

Slope of NL= -1

Product of slope of diagonals=1×-1=-1

∴diagonals of given parallelogram perpendicularly bisect each other.

Therefore, it is a rhombus.

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The minimum usual value, μ-2σ is 17.8 and the maximum usual value, μ+2σ is 54.04

From the information, n = 108, p = 0.24

minimum usual value μ-2σ

maximum usual value μ+2σ

Find the mean, μ:

μ = np = 108 × 0.24 = 35.92

Find the variance, n(1-p):

n(1-p) = 108 ×( 1-0.24) = 82.08

Find the standard deviation, σ:

σ  = √82.08 = 9.06

minimum usual value, μ-2σ:

μ-2σ = 35.92 - (2×9.06) = 17.8

maximum usual value, μ+2σ:

μ+2σ = 35.92 + (2×9.06) = 54.04

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The value of x and y after solving the equation -5x - 10y = 30 and - 3x + 3y = 27 by elimination method is -6 and 3 respectively.

A formula known as an equation uses the equals sign to denote the equality of two expressions.

Given:

-5x - 10y = 30 and - 3x + 3y = 27

Solve by using the elimination method,

Divide the equation - 3x + 3y = 27 by 3 and equation -5x - 10y = 30 by 5 on both sides,

(- 3x + 3y) / 3 = 27 / 3  and (-5x - 10y) / 5 = 30 / 5

-x + y = 9  and -x - 2y = 6

Subtract equation

-x + y = 9 - (-x - 2y = 6)

-x + y - 9 = x - 2y - 6

y = 3

and - x + 3 = 9, x = -6

Therefore, the value of x and y after solving the equation -5x - 10y = 30 and - 3x + 3y = 27 by elimination method is -6 and 3 respectively.

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Two line segments are said to be congruent if, regardless of their orientation or position, their lengths are the same.

If the matching sides and angles of two triangles are the same length, then the triangles are said to be congruent.

Two sides that are the same length make up an isosceles triangle .In addition, it contains two equal-sized angles located across from the two sides of equal length. A triangle with three identical sides is called an equilateral triangle.

So

According to the given information

Segment AD = Segment BC

Two line segments are said to be congruent if, regardless of their orientation or position, their lengths are the same.

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3 is the value of (fog⁻¹)(5) for functions f(x)=7-2x and g(x)=x+3.

A relation is a function if it has only One y-value for each x-value.

Given that the functions are f(x)=7-2x and g(x)=x+3.

We need to find the value of  (fog⁻¹)(5)

g⁻¹(x)=x-3.

By composite functions

f(g⁻¹)(x)=7-2(x-3)

f(g⁻¹)(x)=7-2x+6

Now plug in the value of x as 5

f(g⁻¹)(5)=7-2(5)+6

=7-10+6

=-3+6

=3

Hence, the value of  (fog⁻¹)(5) is 3.

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Kanoi and Ale'a can weed the same garden together in 22.22 minutes

Rate of work refers to amount to of work completed at a given time

Information from the question include

Kanoi can weed a garden in 40 minutes

Kanoi's rate = 1/40 per minute

Ale'a can weed the same garden in 50 minutes

Ale'a rate = 1/50 per minute

When both are working together the rate will be

1/40 per minute + 1/50 per minute

= 9/200 per minute

The time is solved

1 / 9/200

= 200/9

= 22.2222 minutes

= 22.22 minutes to the nearest hundredth

The time it will take both of them to weed is 22.22 minute

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Answer:

So the payoff balance of the car loan after 4 years will be approximately $22,169.73.

Step-by-step explanation:

payoff balance after 4 years can be calculated using the following formula:

Payoff balance = Principal * (1 + APR/n)^(nt) - [(Principal * (1 + APR/n)^(nt) * (APR/n)) / (1 + APR/n - 1)]
Where:
Principal is the loan amount, which is $28,550 in this case.
APR is the annual percentage rate, which is 8% in this case.n is the number of times per year that interest is compounded, which is usually 12 for monthly compounding.t is the number of years for which the loan is taken, which is 4 years in this case.
Plugging in the values, we get:
Payoff balance = $28,550 * (1 + 0.08/12)^(124) - [($28,550 * (1 + 0.08/12)^(124) * (0.08/12)) / (1 + 0.08/12 - 1)]
Payoff balance = $28,550 * 1.006669^48 - [$28,550 * 1.006669^48 * 0.006669] / 0.006669Payoff balance = $22,169.73

Answer:

C) inconsistent

Step-by-step explanation:

3x+y=−5

3y+15=−9x

3x + y = -5

9x + 3y = 15

3x + y = -5

3x + y = 5

The system graphs as two parallel lines.

Answer: C) inconsistent

The marginal rate of substitution (MRS) is a measure of how much of one good an individual is willing to give up in exchange for another good. In other words, it represents the slope of the indifference curve at a given point.

If Victoria's indifference curves are bowed outward, it means that as she moves from right to left along the horizontal axis, the MRS will decrease. This is because as she consumes more of one good, she becomes less willing to give up units of the other good in exchange. The MRS will continue to decrease until it reaches its minimum value at the point where the indifference curve is tangent to the budget line.

It's important to note that the MRS will only decrease if Victoria's indifference curves satisfy the other three properties of indifference curves:

If Victoria's indifference curves do not satisfy these properties, it is not possible to accurately determine the behavior of her MRS as she moves from right to left along the horizontal axis.

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To get the equation which combines with the graphed equation to create a system of equations whose solution set is comprised of the points (−1,−5) and (3,3) we need to plug the points into each equation choice.

Therefore , this is the first step to solve this equation.

The equations of degree 1 are known as linear equations.

These are the equations which are defined for a straight line in a coordinate system.

A linear equation is one that describes a straight line. The general form of a linear equation is  y= mx + b, where m denotes the slope and b its y-intercept.

Note:

The complete question is ,

A linear equation is graphed to the left. Which of the following equations combines with the graphed equation to create a system of equations whose solution set is comprised of the points (−1,−5) and (3,3)?

WHAT IS THE FIRST STEP IN SOLVING THIS PROBLEM?

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Multiplication of matrices is not commutative by determining the product matrices ST and TS .

Given :

Consider the matrices

S = [tex]\left[\begin{array}{ccc}4&1\\-3&-2\end{array}\right][/tex]     and  T = [tex]\left[\begin{array}{ccc}0&4\\-4&3\end{array}\right][/tex]

Show that multiplication of matrices is not commutative by determining the product matrices ST and TS.

ST = [tex]\left[\begin{array}{ccc}4&1\\-3&-2\end{array}\right][/tex]  [tex]\left[\begin{array}{ccc}0&4\\-4&3\end{array}\right][/tex]

[tex]ST_{11[/tex] = 4 * 0 + 1 * -4 = -4

[tex]ST_{12[/tex] = 4 * 4 + 1 * 3 = 19

[tex]ST_{21[/tex] = -3 * 0 + -2 * -4 = 8

[tex]ST_{22[/tex] = -3 * 4 + -2 * 3 = -18

ST = [tex]\left[\begin{array}{ccc}-4&19\\8&-18\end{array}\right][/tex]

TS = [tex]\left[\begin{array}{ccc}0&4\\-4&3\end{array}\right][/tex]  [tex]\left[\begin{array}{ccc}4&1\\-3&-2\end{array}\right][/tex]

[tex]TS_{11[/tex] = 0 * 4 + 4 * -3 = -12

[tex]TS_{12[/tex] = 0 * 1 + 4 * -2 = -8

[tex]TS_{21[/tex] = -4 * 4 + 3 * -3 = -25

[tex]TS_{22[/tex] = -4 * 1 + 3 * -2 = -10

TS  = [tex]\left[\begin{array}{ccc}-12&-8\\-25&-10\end{array}\right][/tex]

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Answer:

$1,127.49

Step-by-step explanation:

Compound interest formulas

Hence, if a two-year savings account containing $1,000 pays a 9% interest rate compounded daily, it will grow to $1,127.49 at the end of two years

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Answer:

  3x +3

Step-by-step explanation:

You want to simplify 2x+ (9+x) -6.

Like terms have the same constellation of variables. Here, there are terms containing x, and terms not containing x.

  2x+ (9+x) -6 = (2 +1)x +(9 -6) = 3x +3

The simplified expression is 3x +3.

Answer:3x+3

Step-by-step explanation:

First we remove the parenthesis because they are not needed in an addition problem to make it 2x+9+x-6

Then we sort and combine like terms, [2x+x]+[9-6]

After that, you add the coefficients of the the first term, which makes 3x and subtract 6 from 9 to get 3

This then leads you to 3x+3

Answer:

y=x/4 - 2

Step-by-step explanation:

First, find the slope:

m=(y2-y1)/(x2-x1)  ==> slope formula where m=slope

(x1, y1), (x2, y2) ==> (x1=-4, y1=-3) and (x2=4, y2=-1)

Now plug in known values back into the slope formula:

m=(-1-(-3))/(4-(-4))

m=(-1+3)/(4+4)

m=2/8  ==> simplify

m=1/4

y=mx+b  ==> slope-intercept equaiton form

-1=(1/4)(4)+b  ==> plug in the slope, m=1/4, and a known coordinate: (4,-1)

-1=1+b  ==> simplify

-1-1=1-1+b  ==> solve for b

b=-2

y=(1/4)x+(-2)  ==> plug in b=-2 and m=1/4 back into y=mx+b

y=x/4 - 2

a) The value in four years is 2,207,626

b) The growth rate percent is 102.5 %

c) It would attain the value in 11 years.

We know that a function has to do with a mathematical rule that is used for the establishment of a fact. We have from the question that the function that models the car is; V = 2000000(1.025)^n

Let us recall that n has to do with the number of years.

a) In four years, the value of the car would be;

V = 2000000(1.025)^4

V = 2,207,626

b) The growth rate percent of the function can  be obtained as;

1.025 * 100 = 102.5 %

c) To obtain the year in which the value of the car would reach 2624173.32, we have;

2624173.32 = 2000000(1.025)^n

2624173.32/2000000 = (1.025)^n

1.312 = (1.025)^n

ln1.312 = n ln (1.025)

n = ln1.312 /ln (1.025)

n = 0.272/0.025

n = 11

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Answer: 5.08333 repeating three

the dimensions of a rectangle with area 64000 m2 whose perimeter is as small as possible. (give your answers in increasing order, to the nearest meter.)Length: 200 m and Width: 320 m

The area of a rectangle is given by the formula A = lw, where l is the length and w is the width. To find the dimensions of a rectangle with an area of 64000 m2 and a perimeter that is as small as possible, we can use the formula P = 2l + 2w. We can use this to create an equation with the area and solve for l and w: 64000 = lw, and 2l + 2w = P (min). Solving for l and w, we get l = 200 m and w = 320 m. Thus, the dimensions of the rectangle with an area of 64000 m2 and a perimeter that is as small as possible are 200 m by 320 m.

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X-μ Use the formula Z where is the mean, o is the standard deviation, and X is the baby kitten σ weight. a. Z= 1.98, X = b. Z-2.87, X ,,a. X = 16.786 , b. X = 8.014

To find the baby kitten weight corresponding to the given z-scores, we use the formula X = μ + Zσ, where μ is the mean, σ is the standard deviation, and Z is the z-score. For the first z-score of 1.98, we substitute the values and solve for X. X = 12.3 + (1.98)(2.2) = 16.786. For the second z-score of 2.87, we substitute the values and solve for X. X = 12.3 + (2.87)(2.2) = 8.014. Therefore, the baby kitten weights corresponding to the given z-scores are 16.786 and 8.014, respectively.

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The range of the data set are

{10.2, 3.8, 21.9, 33.4, 31.8, 17.2} = 29.6

{0.5, 0.65, 0.22, 0.11, 0.47, 0.55, 0.55, 0.71} = 0.6

{6, 2, 14, 11, 28, 10, 19, 15, 11} = 26

The first data set is

{10.2, 3.8, 21.9, 33.4, 31.8, 17.2}

The range is the difference between the highest value and the smallest value

The highest value = 33.4

Lowest value = 3.8

The range = 33.4 - 3.8

= 29.6

The second data set is

{0.5, 0.65, 0.22, 0.11, 0.47, 0.55, 0.55, 0.71}

The highest value = 0.71

Lowest value = 0.11

The range = 0.71 - 0.11

= 0.6

The third data set is

{6, 2, 14, 11, 28, 10, 19, 15, 11}

Highest value = 28

Lowest value = 2

The range = 28 - 2

= 26

Therefore, the range of the each data set has been found

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