Answer:
Empirical: NO2. Molecular: N2O4
Explanation:
In order to determine the empirical formula, we divide each element's mass by their respective molar mass:
N: 0.3955g/14.01 g/mol = 0.02823 mol
O: 0.904g/16.00 g/mol = 0.0565 mol
Next, we take the smallest value and multiply it till it is close enough to an integer:
0.02823 x 40 = 1.12 Close enough to 1.
0.0565 x 40 = 2.26. Close enough to 2.
Therefore, the Empirical Formula is: NO2
Next, we determine how much the Empirical formula weighs and see if it matches 92g/mol:
14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol
We can assume this is roughly half of 92 g/mol so we can multiply each subscript by 2 to match the weight.
Therefore, the Molecular formula is N2O4
Hope this helped!
Question 7 (2 points)
A mocktail is a flavoured cocktail.
O True
O False
Answer:
false mocktail is liquor yea
How many moles are in 213 mg of calcium fluoride, CaF2?
2.73 mols
0.00273 mols
16.6 mols
1.66 mols
Answer:
2.73
Explanation:
2.72815277835894
i used an online converter lol it is much faster. if you'd like a step by step guide comment and ill give you one :)
Please help with Question 4 :(
Answer:
cf4, ch20,vhjuyu8hc hi l bro tap
A plum with a mass of 35 g contains 30 Cal of nutritional energy. How many plums should a person consume to get
120 Cal of energy
If a Plum with a mass of 35 g contains 30 Cal of nutritional energy, then a person should consume four plums to get 120 Cal of energy.
What is multiplication?Finding the product of two or more numbers in mathematics is done by multiplying the numbers.
It is one of the fundamental operations in mathematics that we perform on a daily basis.
As given in the problem If a Plum with a mass of 35 g contains 30 Cal of nutritional energy, then we have to find out a person should consume how much plums to get 120 Cal of energy.
30 cal of nutritional energy = 1 plum
1 cal of nutritional energy = 1/30 plums
120 cal of nutritional energy = 120/30 plums
= 4 plums
Thus, a person should consume four plums to get 120 Cal of energy.
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Traveling at the speed of light - how long would it take, in years, to reach the top of the pile of balls? Show all calculations. The height of the pile is 1.10 x 10^14 km
The time taken for the object to reach to top of pile is 0.012 year.
Time of motionThe time taken for the object to reach to top of pile is calculated as follows;
time of motion = distance traveled/speed
time of motion = (1.1 x 10¹⁴ x 10³ m)/(3 x 10⁸ m/s)
where;
speed of light = 3 x 10⁸ m/stime of motion = 3.67 x 10⁵ sec = 0.012 year
Thus, the time taken for the object to reach to top of pile is 0.012 year.
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if you take a part time job while you are still in school what might your opportunity scost be
The opportunity costs of working part-time while attending high school could be studying time, grades, and your own free time. It depends on the person, how they do in school, but if it were for me, I would say the benefits outweigh the costs. I have enough time to study and still get good grades in school.
Answer:
I don't know I'm rich student
Explanation:
sorry
(GIVING BRANLYEST) John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Which of the following is the best way to explain why the clouds have formed? O The temperature of the air is below zero. O There is a low amount of moisture in the air. O The warm, wet air in a low pressure system has risen up and cooled down. O The wind is traveling at a slow speed.
John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.
Hence, Option C is correct answer.
How are Clouds formed ?Clouds are formed by the process of evaporation and which is followed by condensation. Clouds are small droplets of water crystallization which float in the air. When the moist air rises upwards then the formation of clouds take place because when air rises upwards it becomes colder.
Thus from the above conclusion we can ay that John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.
Hence, Option C is correct answer.
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Answer: Answer would be C I read the assignment and got it correct
Explanation:
Feedback
Consult a peer or a family member about ways your design could be improved. Describe the feedback and provide the name of the reviewer. These are only suggestions that you can use to plan for Design Two. Use complete sentences and detailed examples.
l need this answer first one to get it gets brainlist
Explanation:
We gujra weeeeeeeeeeeeeee
We gujra weeeeeeeeeeeeeee
We gujra weeeeeeeeeeeeeee
We gujra weeeeeeeeeeeeeee
The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is __________ atm.
Answer: 0.42 atm
Explanation:
For this problem, we are going to use the ideal gas law for pressure, which is [tex]P=\frac{nRT}{V}[/tex]. If you do not know yet, R is the ideal gas constant, [tex]0.0821\frac{L*atm}{mol*K}[/tex]First, we must find the number of CH₄ moles.
[tex]6.022gCH_{4} *\frac{1molCH_{4} }{16.043gCH_{4} } =0.38molCH_{4}[/tex]
Next, we will plug in our given information to the ideal gas law for pressure.
[tex]P=\frac{nRT}{V}[/tex]
[tex]P=\frac{0.38mol*0.0821\frac{L*atm}{mol*K} *402K}{30.0L} =0.42 atm[/tex]
The answer to this, according to the work done above, is 0.42 atm.
I hope this helps! Pls mark brainliest!! :)
The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is 0.413 atm.
How do we calculate the pressure of gas?
Pressure of gas will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure of gas = ?
V = volume of gas = 30L
R = universal gas constant = 0.082 L·atm·K⁻¹·mol⁻¹
T = temperature of gas = 402 K
n is moles of gas & it will be calculated as:
n = W/M, where
W = given mass of CH₄ = 6.022g
M = molar mass of CH₄ = 16g/mol
n = 6.022 / 16 = 0.376mol
Now putting all these values on the above equation, we get
P = (0.376)(0.082)(402) / (30)
P = 0.413 atm
Hence required pressure of methane gas is 0.413 atm.
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Compare the shape of a chemical signalling molecule and a receptor.
Cell signalling is a process by which cells communicate with each other and transfer messages.
What is a receptor?A molecule inside or on the surface of a cell binds to a specific substance and causes a specific effect in the cell.
Cell signalling is a process by which cells communicate with each other and transfer messages. When a signal molecule binds to a receptor protein, changes occur in the receptor proteins. Two changes are listed below:
1. The receptor protein undergoes conformational changes and acts as an enzyme.
2. The receptor protein that makes a second messenger molecule that leads the reaction further to other cells or molecules.
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Perform the following
mathematical operation, and
report the answer to the
correct number of significant
figures.
9.635 ÷ 12.9 = [?]
The answer is .747
What are significant figures?There are 5 main rules to determining what are and what are not significant figures.
All non-zero digits are significant.If a decimal point is expressed, all zeros following non-zero digits are significant.If a decimal point is not explicitly expressed, zeros following the last non-zero digit are not significant.If a zero is bounded by non-zero digits, the zero is significant.Zeros preceding the first non-zero digit are not significant, they are placeholders only.NOTE: In any measurement, the last digit is always assumed to be estimated.
How do I divide/multiply with significant figures?The number of significant figures retained may not exceed the least number of digits in either of the factors. There will always be the same number of significant figures in the answer as the factor with the least amount of digits.
How do I apply that to this problem?Given:
[tex]9.635 /12.9 =?[/tex]
In the given problem, the number with the least amount of digits is 12.9. As we recall from above, all non-zero numbers are significant, therefore all of these numbers are significant. Hence, we should have 3 significant figures in our final answer.
Now we use a calculator to simply calculate the above and we obtain:
[tex]0.7468992248[/tex]
We want to have 3 significant figures, so we will take the first 3 significant figures in that answer, .746, and use that. We apply rounding properties and obtain our final answer of .747.
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How many SO2 molecules are in 1.76 mol of SO2? How many sulfur atoms and oxygen atoms are there?
Answer:
1.76 * 6.02*10^23 = 1.05952*10^24
1.05952*2 = 2.11904 *10^24 oxygen and 1.05952*10^24 sulfur atoms
In 1.76 moles of SO₂, there are approximately 1.06 x 10²⁴ SO₂ molecules, 1.06 x 10²⁴ sulfur atoms, and 2.12 x 10²⁴ oxygen atoms. For determining the number of SO₂ molecules, sulfur atoms, and oxygen atoms in 1.76 moles of SO₂, we need to use Avogadro's number, which is approximately 6.022 x 10²³ particles per mole.
1 mole of any substance contains Avogadro's number of particles, which includes atoms or molecules. Therefore, to find the number of SO₂ molecules in 1.76 moles, we can multiply 1.76 moles by Avogadro's number:
Number of SO₂ molecules = 1.76 moles × Avogadro's number
Number of SO₂ molecules = 1.76 moles × 6.022 x 10²³ molecules/mol
Number of SO₂ molecules ≈ 1.06 x 10²⁴ molecules
Next, we can find the number of sulfur atoms and oxygen atoms in 1.76 moles of SO₂. In one molecule of SO₂, there is 1 sulfur atom and 2 oxygen atoms. So, the total number of sulfur atoms and oxygen atoms can be calculated as follows:
Number of sulfur atoms = Number of SO₂ molecules × 1 sulfur atom/molecule
Number of sulfur atoms = 1.06 x 10²⁴ molecules × 1 sulfur atom/molecule
Number of sulfur atoms ≈ 1.06 x 10²⁴ sulfur atoms
Number of oxygen atoms = Number of SO₂ molecules × 2 oxygen atoms/molecule
Number of oxygen atoms = 1.06 x 10²⁴ molecules × 2 oxygen atoms/molecule
Number of oxygen atoms ≈ 2.12 x 10²⁴ oxygen atoms
So, in 1.76 moles of SO₂, there are approximately 1.06 x 10²⁴ SO₂ molecules, 1.06 x 10²⁴ sulfur atoms, and 2.12 x 10²⁴ oxygen atoms.
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What is the equation for density?
O D= m
V
OD=V
m
OD=m
OD=mv²
Answer:
D = m/V
Explanation:
Density represents the following ratio:
Density (D) = mass (m) / volume (V)
In this formula, the volume is being divided from the mass. The typical units for mass is grams and the unit for volume is milliliters.
Pls help!!!!!
Tysm! Xxx
Answer:
Explanation:
The equation says for every 3 moles of barium chloride you can make 2 aluminum chloride.
(8/3)*2 = 5.33 moles
How does the study and understaning of the biological macromolecules impact your everday life?
The study and understanding of the biological macromolecules impact our everyday life by making us know what to eat and the different processes which occur in the body.
What are Biological macromolecules?These are cellular components of the body which are natural and vital for the growth and survival of organisms.
Examples include carbohydrates, protein etc which contain nutrients vital for our daily life.
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Determine which of the following elements would gain electrons when becoming ions: I. Hydrogen II. Helium III. Sulfur IV. Fluorine V. Gallium A. III and IV B. II, III, and IV C. I and V D. I and II
Hydrogen, iron, and gallium is the correct answer. Hence, option B is correct.
What is an electron?An electron is a negatively charged subatomic particle.
Let us take another look at the periodic table. The periodic table is composed of metals, metalloids and nonmetals.
Metals lose electrons more easily, that is why they form cations. Metals are found on the left-hand side of the periodic table.
As we move away from the left-hand side of the periodic table, the ability to form cations decreases as metallic character decreases and elements become more nonmetallic.
The noble gas helium rarely loses electrons. Fluorine would rather accept an electron to form a negative ion.
Hence, the elements hydrogen, iron and gallium are metals hence they lose electrons more easily.
Hence, option B is correct.
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On the box of a cake mix, the recipe says that it makes 24 cupcakes. When
the baker makes the cake mix, it only makes 16 cupcakes. What's the percent
yield of cupcakes?
%yield = actual/theoretical x 100%
%yield = 16/24 x 100%
% yield = 67%
Which of the following stars is a B class main sequence star?
The B class main sequence star from the given images is Star 3.
What are B class main sequence stars?B class main-sequence stars are of spectral type B and luminosity class V. They are very luminous and blue with surface temperatures between 10,000 and 30,000 K.
The stars that are blue as shown in the image are Star 1 and Star 3. However, Star is the one that has surface temperature between 10,000 and 30,000 K.
Therefore, Star 3 is a B class main sequence star.
In conclusion, stars are luminous objects with very high surface temperatures.
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Question 101 p
Simple syrup is the original, the most basic, and general one of the most common ways to add sweetness to a cocktail. You can choose from a range of suga
when making your simple syrup.
a White Sugar
Ob Splenda
De Raw Sugar
Od Brown Sugar
Answer:
splenda
Explanation:
Hechar azucar no es del todo una buena opcion ya que puede poducir caries
A hurricane is a type of severe cyclone
A hurricane is a type of severe cyclone formed when winds rotate as the pressure between low and high-pressure areas increases.
What is a hurricane?A cyclone is a violent storm that occurs when cyclone winds exceeds a speed of 74 miles (119 kilometers) per hour.
Hurricanes are classified according to their strength and catastrophic potential on a scale ranging from 1 to 5 (more violent).
In conclusion, a hurricane is a cyclone formed when a it rotates as the low and high-pressure areas increases.
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For the decomposition of ammonia on a platinum surface at 856 °C
2 NH3(g)N2(g) + 3 H2(g)
the average rate of disappearance of NH3 over the time period from t = 0 s to t = 5.48×103 s is found to be 1.50×10-6 M s-1.
What is the average rate of appearance of H2 over the same time period?
M s-1.
[tex]\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}[/tex]
dt remains same for reaction[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}[/tex]
[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})[/tex]
[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}[/tex]
M is molarity here not metre
The average rate of appearance of H2 over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.
To find the average rate of appearance of [tex]\rm H_2[/tex], we can use the stoichiometry of the reaction to relate it to the rate of disappearance of [tex]\rm NH_3[/tex].
From the balanced equation: [tex]\rm 2NH_3(g) - > N_2(g) + 3 H_2(g)[/tex]
We can see that for every 2 moles of [tex]\rm NH_3[/tex] that disappear, 3 moles of [tex]\rm H_2[/tex] appear.
Given that the average rate of disappearance of [tex]\rm NH_3\ is\ 1.50\times10^{-6} M/s[/tex], we can calculate the average rate of appearance of [tex]\rm H_2[/tex] as follows:
Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x (Average rate of disappearance of [tex]\rm NH_3[/tex])
Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x [tex]\rm (1.50\times10^{-6} M/s)[/tex]
Average rate of appearance of [tex]\rm H_2[/tex] = [tex]\rm 2.25\times10^{-6} M/s[/tex]
Therefore, the average rate of appearance of [tex]\rm H_2[/tex] over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.
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How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution
The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL
Balanced equation2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O
From the balanced equation above,
The mole ratio of the acid, HCl (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 1How to determine the volume of Ca(OH)₂ Molarity of base, Ca(OH)₂ (Mb) = 1.48 MVolume of acid, HCl (Va) = 36 mL Molarity of acid, HCl (Ma) = 1.63 MVolume of base, Ca(OH)₂ (Vb) =?MaVa / MbVb = nA / nB
(1.63 × 36) / (1.48 × Vb) = 2
58.68 / (1.48 × Vb) = 2
Cross multiply
2 × 1.48 × Vb = 58.68
2.96 × Vb = 58.68
Divide both side by 2.96
Vb = 58.68 / 2.96
Vb = 19.8 mL
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Gamma-ray bursters emit pulses of gamma rays with high energies. The frequency of the most energetic pulses has been measured at around 3.0x10 21 hz. What is the wavelength of the gamma rays
The wavelength of these gamma rays will be 1x1[tex]10^{-13}[/tex] m.
How do you define wavelength?
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.
The relationship between the wave's wavelength, frequency, and speed is given as
wavelength = speed of light ÷ frequency
wavelength = [tex]\frac{3 X10^8}{3.0 X10^{21}}[/tex]
wavelength = 1x[tex]10^{-13}[/tex] m
Hence the wavelength of these gamma rays will be [tex]1 X 10^{-13}[/tex]m.
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How much heat will be absorbed by a 66.3 g
piece of aluminum (specific heat = 0.930 J/
g. °C) as it changes temperature from 23.0°C
to 67.0°C?
Q=mcΔt
Q=66.3 x 0.93 x (67-23)
Q=2712.996 J
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]
[tex] \textsf{Q = heat evolved/absorbed = ??} [/tex]
[tex] \textsf{m = mass in gram = 66.3 g} [/tex]
[tex] \textsf{s = specific heat = 0.930 J/g °C} [/tex]
[tex] \textsf{ΔT = change in temp = 67 - 23 =44°C} [/tex]
[tex] \large\textsf{Find Q : } [/tex]
[tex]\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)[/tex]
[tex]\qquad \tt \rightarrow \:Q = 2713 \: \: joules[/tex]
[tex]\qquad \tt \rightarrow \:Q= 2.713 \: \: kj[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Diamonds are composed of __________ in a ___________lattice. A. silicon, trigonal planar B. quartz, octahedral lattice C. carbon, tetrahedral D. diamond, trigonal bipyramid
Diamonds are composed of carbon in a tetrahedral lattice. That is option C.
What is a diamond?A diamond of defined as an allotrope or one of the major forms of the element, carbon in nature.
These carbon atoms are arranged within the diamond in a face centered cubic tetrahedral lattice shape.
Therefore, Diamonds are composed of carbon in a tetrahedral lattice.
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Diamonds are composed of carbon in a tetrahedral lattice. The correct option is C.
What are diamonds?Diamonds are one of the allotropes of carbon. The other allotrope of carbon is graphite.
Thus, diamonds are made up of carbon atoms that are tightly packed together. Each carbon atom in a diamond is strongly bonded to 4 other carbon atoms, resulting in the formation of a tetrahedral structure.
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Which of the following molecules contains a polar covalent bond?
O A. Og
O B. N₂
O G. H₂
O D. CO
Answer:
CO contains polar covalent bond, because these atoms share unequal electrons.
Answer:
N₂
Explicacion:
Si la diferencia de electronegatividad es muy alta, por ejemplo entre un metal y un no metal, se forman enlaces iónicos
A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C. Use the chart to complete the multiple steps required to arrive at the final answer. Type in your answers below using 3 digits.
q1 = ___ kJ
q2 = ___ kJ
q3 = ___ kJ
qtot = ___ kJ
The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
Quantity heat required to convert the ice to liquid
The total quantity of heat required is calculated as follows;
q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)
q(tot) = mcΔθ₁ + mΔHf + mcΔθ₂
q(tot) = (100)(4.2)(0 - -45) + (334)(100) + (100)(4.2)(75 - 0)
q(tot) = 18,900 J + 33,400 J + 31,500 J
q(tot) = 18.900 kJ + 33.400 kJ + 31.500 kJ
q(tot) = 83,800 J = 83.8 kJ
Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
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Answer:
q1 9.42
q2 226
q3 31.4
qtot 267
Explanation:
hope this help
During quiet breathing, a person breathes in about
6 L of air per minute. If a person breathes in an
average of 6.814 L of air per minute, what volume
of air in liters does this person breathe in 1 day
Answer:
[tex]\huge\boxed{\sf 9812.16\ L\ of\ air}[/tex]
Explanation:
Given that,
A person breathes 6.814 L of air in a minute.
1 minute = 6.814 L
Minutes in a day:= 1 × 24 × 60 (24 hours in a day; 60 minutes in an hour)
= 1440 minutes
Volume of air that person breathes in a day:1 minute = 6.814 L of air
1440 minutes = 6.814 L × 1440
1 day = 9812.16 L of air
[tex]\rule[225]{225}{2}[/tex]
What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2
The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g
Avogadro's hypothesis6.02×10²³ formula units = 1 mole of CuF₂
But
1 mole of CuF₂ = 101.5 g
Thus,
6.02×10²³ formula units = 101.5 g of CuF₂
How to determine the mass of 8.94×10²² formula units of CuF₂6.02×10²³ formula units = 101.5 g of CuF₂
Therefore,
8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³
8.94×10²² formula units = 15.07 g of CuF₂
Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂
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Hi please help, tysm. Answer is in nm
What is the wavelength of a photon if
the
energy is 7.41 x 10-19 J? (h= 6.626 x 10-34 J.
s)
Answer:
268 nm
Explanation:
The equation needed to find wavelength is:
E = hc / w
In this equation,
-----> E = energy (J)
-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)
-----> c = speed of light (3.0 x 10⁸ m/s)
-----> w = wavelength (m)
To find the wavelength, you can plug the given values into the equation and simplify. Then, you can convert meters to nanometers.
E = hc / w
7.41 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J*s)(3.0 x 10⁸ m/s) / w <---- Input given values
7.41 x 10⁻¹⁹ J = 1.9878 x 10⁻²⁵ / w <----- Simplify
(7.41 x 10⁻¹⁹ J) x w = 1.9878 x 10⁻²⁵ <----- Rearrange
w = 2.68 x 10⁻⁷ m <----- Simplify
2.68 x 10⁻⁷ m 1 x 10⁹ nm
---------------------- x ---------------------- = 268 nm
1 m