a company makes these biscuits at a cost of $1.35 per packet. these biscuits are sold for $1.89 per packet. calculate the percentage profit the company makes on each packet

Answer: what question i don't see it but you can try reading it again and writing it down

Step-by-step explanation:

P means the center of the circle.

any point on the circle has therefore a constant distance from the center : the radius r.

r = 5 m

what we need to find is the length of the circle arc between the 2 points that represents 90° of the overall circle (360°).

90/360 = 1/4

so, we are looking for 1/4 of the overall circle circumference :

2×pi×r × 1/4 = 2×pi×5 × 1/4 = pi×10/4 = pi×5/2 =

= 7.853981634... m ≈ 7.85 m

Answer:

Choice 4^th

Step-by-step explanation:

Given:

1/2+3/4+7/16 = __

To Solve:

Addition equation by finding a common multiple.

Solution:

Let the blank _ be x.

Then,

1/2+3/4+7/16 = x

Flip this equation:

Now solve for x.

Hence,

1/2+3/4+7/16 = 27/16

4^th Choice is accurate.

Answer:

It will be 4 30

Step-by-step explanation:

Mark me as a brainliest.

Answer:

A=πr^2

Step-by-step explanation:

A=π*r^2

Where, A is area of circle

r is radius of circle

π is constant

.

Hope it's help and I think I have give brainleist answer

Answer:

πr^2

Step-by-step explanation:

it's just πr^2.

easy

Answer:

x = 1

Step-by-step explanation:

7x + 16 = 8x + 15

Step 1 : Subtract 15 on both sides

7x + 16 - 15 = 8x

7x + 1 = 8x

Step 2 : Subtract 7x on both sides

1 = 8x - 7x

1 = 1x

x = 1

The equation that produces the circle in the given graph is; x² + y² = 16. The correct answer is option B.

The complete graph is attached with the answer below.

A circle is a two-dimensional geometry on the plane having a centre point and the circular line is drawn equidistant from the centre point.

The general form of the equation of a circle is;

(x - h)² + (y - k)² = r²

where;

h, k are coordinates of the circle centre r is the radius

From the graph, we can see that the coordinates of the centre are; (0, 0).

Also, the radius is;

r = √(4² - 0²)

r = √16

Thus, our equation of the circle in the graph is;

(x - 0)² + (y - 0)² = (√16)²

⇒ x² + y² = 16

Therefore the equation that produces the circle in the given graph is; x² + y² = 16. The correct answer is option B.

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The net represents a cube.

The net shows a cube with a side length of 12 cm, meaning its surface area is [tex]6(12)^{2}=\boxed{864 \text{ cm}^{3}}[/tex]

Answer:

Step-by-step explanation:

The Platonic solid with six (6) square faces is the cube. Its surface area is the sum of the areas of the square faces. Each of those is the square of its edge length.

__

The 3-dimensional shape represented by the net is a cube.

The area of the cube is ...

  6 × (12 cm)² = 6 × (144 cm²) = 864 cm²

Answer:

2x + 25

Step-by-step explanation:

Let that number be x.

Step 1 : Multiply x and 2.

x * 2 = 2x

Step 2 : Add 25 and 2x.

2x + 25

Hence,

25 is added to the product of a number and 2 is 2x + 25.

[tex]\underline{\boxed{\sf{-7x^2 - \frac{13}{10} x +5}}}[/tex]

[tex]\sf{(-11x^2 + 1.4x - 3) + (4x^2 - 2.7x + 8)}[/tex]

Remove the parentheses:

[tex]\sf{-11x^2 + 1.4x - 3 + 4x^2 - 2.7x + 8}[/tex]

Convert decimal to fraction:

[tex]\sf{-11x^2 + \frac{14}{10} x - 3 + 4x^2 - \frac{27}{10} x + 8}[/tex]

Reduce fraction to the lowest term by canceling the greatest common factor:

[tex]\sf{-11x^2 + \frac{7}{5} x - 3 + 4x^2 - \frac{27}{10}x + 8}[/tex]

Combine like terms:

[tex]\sf{-7x^2 - \frac{13}{10} x +5}[/tex]

The true statement about the Internet connection cost is D. Any amount of time over an hour and a half would cost $10.

In this situation, the function is f (t), when t is a value between 0 and 30. The cost is $0 for the first 30 minutes

When t is a value between 30 and 90, the cost is US$ 5 if the connection takes between 30 and 90 minutes.

Here, the true statement about the Internet connection cost is D. Any amount of time over an hour and a half would cost $10.

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The amount of grams that she must use to make the solution she needs are: 12 grams and 8 grams.

x grams of 20% and 20-x grams of 35%

Hence:

0.20x+0.35(20-x)=0.26×20

0.20x-0.35x+7=5.2

Collect like terms

-0.15x=-1.80

Divide both side by -0.15x

x=-1.80/-0.15

x=12 grams of 20% or 2.4 grams pure

20-x= (20-12) =8 grams of 35% or 2.8 grams pure

Therefore the amount of grams that she must use to make the solution she needs are: 12 grams and 8 grams.

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Answer:

95

Step-by-step explanation:

Answer:

  (d)  108°

Step-by-step explanation:

An inscribed angle is half the measure of the arc it subtends. Conversely, the arc is twice the measure of the inscribed angle it subtends.

__

We can define the vertex of the marked angle as point Q. Arc XY is twice the measure of inscribed angle XQY:

  arc XY = 2(54°) = 108°

3/0 and -191/32

lmk if this is wrong, I might be.

Answer:

P

Step-by-step explanation:

The middle is the middle of the angle ...point P

Answer:

5

Step-by-step explanation:

You need to do 4 divided by 4 on 1 side and 20 divided by 4 on the other side

4÷4= 1 so we are left with x

20÷4= 5 so we are left with 5

Therefore x=5

Hi student, let me help you out!

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to solve the equation 4x=20.

[tex]\triangle~\fbox{\bf{KEY:}}[/tex]

Is x all by itself? No, there's a 4 multiplied by it.

So, we do the opposite operation.

The opposite of multiplication is..?

Division.

Thus, we divide both sides by 4.

x=5

[tex]\ddot\bigstar[/tex] Remember this...

[tex]\fbox{When\;solving\;equations\;,\;our\;goal\;is\;to\;find\;the\;value\;of\;the\;variable,\;which\;in\;this\;case\;was\;x}[/tex]

Hope it helps you out! :D

Ask in comments if any queries arise.

~Just a smiley person helping fellow students :)

[tex]Prove\ that\ the\ assumption \is \true for\ n=1\\1^3=\frac{1^2(1+1)^2}{4}\\ 1=\frac{4}{4}=1\\[/tex]

Formula works when n=1

Assume the formula also works, when n=k.

Prove that the formula works, when n=k+1

[tex]1^3+2^3+3^3...+k^3+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k+1)^2}{4}+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k^2+2k+1)}{4}+(k+1)^3=\frac{(k^2+2k+1)(k^2+4k+4)}{4} \\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+4k^3+4k^2+2k^3+8k^2+8k+k^2+4k+4}{4}\\\\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+2k^3+k^2}{4}+\frac{4k^3+12k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+6k^3+13k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\[/tex]

Since the formula has been proven with n=1 and n=k+1, it is true. [tex]\square[/tex]

Answer:

[-11/4, ∞)

Step-by-step explanation:

Given :

y = √(4x + 9 + 2)

Simplifying :

y = √(4x + 11)

Now, the term in the bracket has to be greater than or equal to 0 to be real.

Hence,

⇒ 4x + 11 ≥ 0

⇒ 4x ≥ -11

⇒ x ≥ -11/4 [Lower limit]

Infinity will be the upper limit as the numbers increase indefinitely.

The domain will be :

⇒ [-11/4, ∞)

Answer: -6.5

Step-by-step explanation:

First, you take the values on both sides to the power of 2 to get:

-x = x + 13

Subtract x on both sides.

-2x = 13

Divide both sides by -2.

x = -6.5

Answer:

[tex]x=-\dfrac{13}2[/tex]

Step-by-step explanation:

[tex]~~~~~\sqrt{-x} = \sqrt{x+13}\\\\\implies -x= x+13~~~~~~~~~~~~~~~~;[\text{Square on both sides}]\\\\\implies -x -x = 13\\\\\implies -2x = 13\\\\\implies x = -\dfrac{13}2\\\\\text{Verify solution:}\\\\~~~~~~~\sqrt{-\left(- \dfrac{13} 2 \right)} = \sqrt{-\dfrac{13}2 +13}\\\\\\\implies \sqrt{\dfrac{13}2} = \sqrt{\dfrac{13}2}\\\\\text{Hence, the solution is}~ x=-\dfrac{13}2[/tex]

Answer:

y=4/3x+6

Step-by-step explanation:

Answer:

see the attachment photo!

For part A, we will see that the distance is 7 units. For part B, the distance from Nina's house to the school to the grocery store is larger.

Remember that the distance between two points (a, b) and (c, d) is:

[tex]D = \sqrt{(a - c)^2 + (b - d)^2}[/tex]

A) Her house is at (-4, 10), and her school is at (-4, 3), so the distance is:

[tex]D = \sqrt{(-4 - (-4))^2 + (10 - 3)^2} = \sqrt{7^2} = 7[/tex]

The distance is 7 units.

B) In the first case, the distance between the school and the grocery store is:

[tex]D' = \sqrt{(-4 - (-4))^2 + (3 - (-6))^2} = 9[/tex]

So the total distance is 9 + 7 = 16

And the distance between the school and the community center is:

[tex]D'' = \sqrt{(-4 - 2)^2 + (3 - 3)^2} = 6[/tex]

So the total distance is 6 + 7 = 13

So we can see that the total distance from Nina's house, to the school, to the grocery store is larger than the other.

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Answer:

[tex]1 \div {3}^{( 30)} [/tex]

Step-by-step explanation:

There are exponent rules I posted above that are being used here.

We have (3^-6)^-5

Since we have a power times a power, we multiply 6 and 5 to get -30. Look at the first example in the photo.

So, we're left with 3^-30.

If you look at the photo, there's a rule for negative exponents.

Take the inverse of the base number, so 3 in this case:

1 / 3

and then make the exponent positive after taking the inverse.

So, we should get 1 / 3^30

Hope this helps!

Answer:

1. 33.6

Step-by-step explanation:

1. Mean = total score/number of tests

         = (23+28+29+30+30+32+33+36+36+40+41+43+45+46+48)/15

         =33.6

I don't know any of the others, but I hope that this will be helpful :)

Both M(x) and N(x) are translations of f(x), the equations are:

N(x) = f(x + 4).

M(x) = f(x) + 4.

Remember that for a function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

And for a function f(x), a horizontal translation of N units is written as:

g(x) = f(x + N).

First, we can see that N is a translation of 4 units to the left, then:

N(x) = f(x + 4).

And M is a translation upwards of 4 units, then:

M(x) = f(x) + 4.

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Answer:

none of the answers listed are equivalent to b (22/5, 11/8, 2/5, 1/4)

Step-by-step explanation:

[tex]\frac{1}{3b} = \frac{4}{5}[/tex]

to simplify, cross multiply

(1 · 5  =  3b · 4)

(5 = 12b)

divide both sides by 12 to isolate b,

[tex]\frac{5}{12} =\frac{12b}{12}[/tex]

[tex]\frac{5}{12} = b[/tex]

None of the answers listed are equivalent to 5/12

[tex]\frac{5}{12}[/tex] [tex]\neq[/tex][tex]\frac{22}{5}[/tex]

[tex]\frac{5}{12} \neq[/tex][tex]\frac{11}{8}[/tex]

[tex]\frac{5}{12} \neq[/tex][tex]\frac{2}{5}[/tex]

[tex]\frac{5}{12} \neq[/tex][tex]\frac{1}{4}[/tex]

The maximum height of the  pumpkin is 3 feet

We have given that,

A catapult hurls a pumpkin from a height of 32 feet at an initial velocity of 96 feet per second.

The function h(t)=-16t^2+96t+32 represents the heights of the pumpkin h(t) in terms of time t.

We have to determine the maximum height.

At the point of maxima f'(x)=0

first, find the maxima

Therefore differentiate the given function with respect to t we get,

[tex]h'(t)=-32t+96[/tex]

h'(t)=0

Then we get,

[tex]0=-32t+96\\-32t=-96\\t=\frac{-96}{-32} \\t=3[/tex]

Therefore the maximum height of the pumpkin is 3 feet.

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