A college student takes the same number of credits each semester. She had 12 credits when she started, and after 3 semesters, she had 54 credits.

The bearing of B from P is N24.65°E (or S24.65°W), and the ship is approximately 33.54 nautical miles from the port.

Since the ship travels at a constant speed, we can use the formula:

distance = speed × time

For the first hour, the ship travels at a bearing of S80°E, which is equivalent to a bearing of N10°E. Therefore, the ship travels 15 nautical miles in a direction N10°E. This gives us:

PA = distance = speed × time = 15 × 1 = 15 nautical miles

After the first hour, the ship turns 90° towards the North. This means that the ship is now heading due East. Therefore, for the next 2 hours, the ship travels 15 × 2 = 30 nautical miles in an easterly direction. This gives us:

AB = distance = speed × time = 15 × 2 = 30 nautical miles

Now, we can use the Pythagorean theorem to find the value of y:

y² = x² + (AB)²

y² = 15² + 30²

y² = 225 + 900

y² = 1125

y ≈ 33.54 nautical miles

To find the bearing of B from P, we can use trigonometry. The bearing is the angle between the line PA and due North. Let θ be this angle. Then we have:

tan(θ) = x / y

θ = tan^-1(x / y)

Using the values we have found, we get:

tan(θ) = 15 / 33.54

θ ≈ 24.65°

Therefore, the bearing of B from P is N24.65°E (or S24.65°W), and the ship is approximately 33.54 nautical miles from the port.

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The work done in stretching the spring from 10 cm to 40 cm is 10,837.5 J.

The work done in stretching a spring is given by the formula:

W = (1/2)k[tex]x^{2}[/tex]

where W is the work done, k is the spring constant, and x is the displacement of the spring from its original position.

To find the spring constant k, we can use the given information:

F = kx

where F is the force applied to the spring. Rearranging this equation, we get:

k = F/x

Substituting the given values, we get:

k = 350 N / 30 cm = 11.67 N/cm

Now, we can find the work done in stretching the spring from 10 cm to 40 cm:

W = (1/2)k([tex](x_{2})^{2} -(x_{1} )^{2}[/tex])

where [tex]x_{1}[/tex] is the initial displacement of the spring (10 cm) and [tex]x_{2}[/tex] is the final displacement (40 cm).

Substituting the values, we get:

W = (1/2) * 11.67 N/cm * ([tex](40 cm)^{2} - (10 cm)^{2}[/tex])

W = (1/2) * 11.67 N/cm * (1600  [tex]cm^{2}[/tex] - 100  [tex]cm^{2}[/tex])

W = (1/2) * 11.67 N/cm * 1500 [tex]cm^{2}[/tex]

W = 10,837.5 joules (J)

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A) The area of the walls is 700 ft²

B) The area of the doors, windows, and rectangular opening is 226ft²

C) The area that Kamrie will paint is 474 ft², and she will need to purchase 2 cans of paint.

Part A:

The area of each of the short walls is

10 ft x 15 ft

= 150 sq ft.

So, the total area of the four walls is:

2(200 sq ft) + 2(150 sq ft)

= 700 sq ft

Part B:

The area of the three windows along the long wall is

3 ft x 8 ft

= 24 sq ft each, so their total area is

3(24 sq ft)

= 72 sq ft

The area of the two windows along the short wall is also

3 ft x 8 ft = 24 sq ft each,

so their total area is

2(24 sq ft)

= 48 sq ft

The area of the rectangular opening along the other long wall =

7 ft x 8 ft = 56 sq ft.

So, the total area of the doors, windows, and rectangular opening is

72 sq ft + 48 sq ft + 56 sq ft

= 176 sq ft

Part C:

To determine the area that Kamrie will paint, we need to subtract the area of the doors, windows, and rectangular opening from the total area of the walls

700 sq ft - 176 sq ft

= 524 sq ft

To determine how many cans of paint Kamrie needs to buy, we divide the area to be painted by the coverage per can

524 sq ft ÷ 415 sq ft/can

≈ 1.26 cans

So Kamrie needs to buy at least 2 cans of paint to cover the entire living room.

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Answer:

176

Step-by-step explanation:

To do this question, we can simplify it even further.

If x=25 when y=110, it is in the ratio 25:110.

If we divide by five on both sides, the ratio becomes:

5:22.

Then, if we multiply by eight on both sides,

it becomes 40:22x8 which means y is equal to 176.

Answer:

B. (2, 2)

Step-by-step explanation:

(x, y)

3x = 8 - y

a) 3(3) = 8 - 1

9 = 8 - 1

9 = 7  False

b) 3(2) = 8 - 2

6 = 6  True

c) 3(8) = 8 - 0

24 = 8 False

6 inches will be the length of the patio.

According to the scale, 1 inch on the plan corresponds to 3.5 feet in real life.

We must convert the patio's real length of 21 feet to inches using the scale in order to determine how long it would look on the blueprint:

3.5 feet to one inch

21 feet in x inches

If we cross-multiply, we obtain:

1 inch/3.5 feet * 21 feet

= x inches

= 6 inches.

As a result, the length of the patio will be indicated on the blueprint as 6 inches.

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the object will fall a distance of 1024 feet in 8 seconds. So the answer is (C) 1024 ft.

what is distance  ?

Distance is a scalar quantity that refers to the total length traveled by an object or person, without considering the direction. It is a measure of the path length between two points, usually measured in units such as meters (m), feet (ft), or kilometers (km).

In the given question,

The formula t = √(d/16) relates the time t (in seconds) it takes an object to fall a distance d (in feet) to the acceleration due to gravity, which is approximately 32.2 feet per second squared.

To find how far the object will fall in 8 seconds, we can rearrange the formula to solve for d:

t = √(d/16)

t² = d/16 (Squaring both sides)

d = 16t² (Multiplying both sides by 16)

Substituting t = 8 into the formula, we get:

d = 16(8)² = 1024

Therefore, the object will fall a distance of 1024 feet in 8 seconds.

So the answer is (C) 1024 ft.

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The training wheel has an area approximately 286.34 square inches smaller than the regular wheel.

The area of a circle is given by the formula A = πr², where A is the area of the circle and r is the radius of the circle. Since we have the radii of both wheels, we can use this formula to find their respective areas.

The area of the training wheel is A₁ = π(3)² = 9π square inches.

The area of the regular wheel is A₂ = π(10)² = 100π square inches.

To find the difference in their areas, we can subtract A₁ from A₂:

A₂ - A₁ = 100π - 9π = 91π

So the difference in their areas is 91π square inches. To round to the nearest hundredth, we can use the approximation π ≈ 3.14:

91π ≈ 286.34 square inches

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The coordinates of the fourth vertex are (-2.2, 1.5).

To find the coordinates of the fourth vertex, we can use the fact that opposite sides of a rectangle have equal length and are parallel to each other.

First, we can find the length of one of the sides of the rectangle. Let's take the side connecting the points (-2.2, -2.3) and (-2.2, 1.5):

length = |1.5 - (-2.3)| = 3.8

Since this is a rectangle, the length of the side opposite to this one must also be 3.8. We can find this side by taking the points (-2.2, 1.5) and (1.5, 1.5):

width = |1.5 - (-2.2)| = 3.7

Now we know the length and width of the rectangle, so we can find the coordinates of the fourth vertex. Let's call this point (x, y).

Since the fourth vertex is opposite to the point (-2.2, -2.3), the x-coordinate of the fourth vertex must be the same as the x-coordinate of (-2.2, -2.3):

x = -2.2

Similarly, since the fourth vertex is opposite to the point (1.5, 1.5), the y-coordinate of the fourth vertex must be the same as the y-coordinate of (1.5, 1.5):

y = 1.5

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Answer:

C. 84.8 m

Step-by-step explanation:

Circumference of circle = D x 3.14

D = 27 m

Let's solve

27 x 3.14 = 84.78 m

So, the circumference of the circle is C. 84.8 m

The set of numbers that can represent the sides of a triangle are:

{11, 14, 22} and {13, 20, 35}.

We can determine which set of numbers would represent the sides of a triangle by applying the triangle inequality theorem.

This theorem states that the sum of any two sides of a triangle must be greater than the length of the third side to make it a triangle.

Applying the theorem, we have:

A. (6,8,14)

6 + 8 > 14 (not true, since 6 + 8 = 14 and not greater than 14)

6 + 14 > 8 (true)

8 + 14 > 6 (true)

Therefore, (6,8,14) cannot represent the sides of a triangle.

B. {11, 14, 22}

11 + 14 > 22 (not true, since 11 + 14 = 25 and not less than 22)

11 + 22 > 14 (true)

14 + 22 > 11 (true)

Therefore, {11, 14, 22} does not represent the sides of a triangle.

C. {13, 20, 34}

13 + 20 > 34 (not true, since 13 + 20 = 33 and not greater than 34)

13 + 34 > 20 (true)

20 + 34 > 13 (true)

Thus, {13, 20, 34} cannot represent the sides of a triangle.

D. {13, 20, 35}

13 + 20 > 35 (not true, since 13 + 20 = 33 and not less than 35)

13 + 35 > 20 (true)

20 + 35 > 13 (true)

This means, {13, 20, 35} can represent the sides of a triangle.

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The surface area of the prism is 426 m²

A cuboid is a rectangular prism. And has all the properties related to a prism. The general formula for the surface area of a cuboid is ;

SA = 2B + ph

We can use net formula to find the surface area of a cuboid.

surface area of a cuboid is expressed as;

SA = 2( lb+lh +bh)

l = 12m , b = 5m and h = 9m

lb = 12×5 = 60m²

lh = 12 × 9 = 108m²

bh = 5×9 = 45m²

SA = 2(60+108+45)

= 2(213)

= 426 m²

therefore the surface area of the cuboid is 426m²

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The total possible points in the course is approximately 470.

Let's assume that the total possible points in the course is "x".

Since you needed 90% of the course total for an A, that means you needed to earn 90% of "x" to get an A. This is equivalent to 0.90x.

You missed an A by only 8 points, so your actual earned points must be 90% of "x" minus 8. This can be expressed as 0.90x - 8.

Given that your actual earned points for the course is 415, we can set up an equation:

0.90x - 8 = 415

Now, we can solve for "x" to determine the total possible points in the course:

0.90x = 415 + 8

0.90x = 423

x = 423 / 0.90

x ≈ 470

So, the total possible points in the course is approximately 470.

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The features of function g if g(x) = -f(x)-1 include the following:

B. domain of (0, ∞).

C. vertical asymptote of x = 0.

D. x-intercept at (1/2, 0).

In Mathematics and Geometry, a domain is the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following key features:

Domain = (0, ∞)

Range = (-∞, ∞).

vertical asymptote, x = 0.

x-intercept = (1/2, 0).

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Answer:

8. mArc ED = 38°

9. mArc EA = 142°

10.mArc BDC = 308°

Step-by-step explanation:

The measure of an a central angle and it's intercepted arc are equal

So if the measure of the angle for the angle that intercepts Arc ED is 38° the arc is also 38°

Same thing with Arc EA, the central angle that intercepts it is 142° so the measure of Arc EA is 142°

Arc BDC is a major arc so it is greater than 180°. It goes around the circle from point B to point C and point D is one of the points on the arc.

We could find the value of the arc two ways. We could add all the angles  the that make up the central angle it is intercept by or we could simply subtract the 52° that isn'tt a part of the arc and subtract that from 360°

360 - 52 = 308

So the central angle intercepting Arc BDC is 308° so the arc also has a measure of 308°.

The best response to Raina's comment will be that technology is good but handouts still serve the useful purpose of being a hard copy that speakers can use in case technology fails.

To respond to Raina, the best thing to do will be to acknowledge the fact that technology is good but handouts are still important because, unlike technology that can trip off by some sudden technical faults, handouts can be depended upon.

So, while responding to Raina, we will not discard her point but will let her know that technology is good but handouts still have their benefits.

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The scale factοr is οne-half. The perimeter οf the mοdel is the prοduct οf the scale factοr and the perimeter οf the οriginal rectangle. The area οf the reduced figure is (1/2)² = 1/4 times the area οf the οriginal figure

The ratiο between cοmparable measurements οf an οbject and a representatiοn οf that οbject is knοwn as a scale factοr in mathematics.

Here,

We have tο cοmpare the perimeter and area οf the οriginal figure tο the perimeter and area οf the reduced figure using the scale factοr.

The ratiο οf the length οf the οriginal rectangle tο that οf the reduced rectangle is 6 tο 3 οr a factοr οf 1/2.

The ratiο οf the width οf the οriginal rectangle tο that οf the reduced rectangle is 2 tο 1, οr, again, a factοr οf 1/2. Sο, because this ratiο οf 1/2 is cοnstant, we knοw the tοtal scale factοr is 1/2, making B cοrrect.

16 ×(1/2) = 8, which means that the perimeter οf the scale-factοred, reduced rectangle is "the prοduct οf the scale factοr and the perimeter οf the οriginal rectangle". Sο, C is cοrrect.

Hence,  The scale factοr is οne-half.

The perimeter οf the mοdel is the prοduct οf the scale factοr and the perimeter οf the οriginal rectangle.

The area οf the reduced figure is (1/2)² = 1/4 times the area οf the οriginal figure.

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1. n - 4 = 12

2. n - 13 = 20

3. n + 9 = 25

4. n + 5 = 75

5. x + 6 = 13

6. n - 6 = 5

For 1 n = 16

For 2 n = 33

For 3 n = 16

For 4 n = 70

For 5 x = 7

For 6 n = 11

Hope that helps, :).

An equation which is true include the following: A. 4 × n × n × n × n = 4n⁴.

In Mathematics, an exponent is a mathematical operation that is typically used in conjunction with an algebraic expression in order to raise a quantity to the power of another.

This ultimately implies that, an exponent is represented by the following mathematical expression;

bⁿ

Where:

By applying the multiplication law of exponents for powers to each of the expressions, we have the following:

4 × n × n × n × n = 4n⁴

4 × n⁴ = 4n⁴

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Hannon's maximum allowable production cost for the All-Body swimsuit is $80 if it wants to make a profit of $20 per unit.

Given data ,

a)

Using cost-plus pricing, the selling price is set 20% above the costs.

Selling price=Costs+(Costs x Markup)

Selling price=$100 + ($100x0.20)

Selling price=$100+$20

On simplifying the equation , we get

Selling price=$120

The price charged for the All-Body swimsuit would be$120.

Hannon might consider manufacturing the All-Body swimsuit under the cost-plus pricing approach if the market demand is strong enough to justify the selling price of $120 and if Hannon can efficiently produce and sell the swimsuit to generate profits.

(b)

Using target costing, the price charged by Hannon to the retailer is determined by subtracting the desired profit per unit from the target selling price.

Target selling price=$100 (given)

Desired profit per unit=$20 (given)

Price charged to retailer=Target selling price - Desired profit per unit

Price charged to retailer=$100-$20

On simplifying the equation , we get

Price charged to retailer=$80

The price that Hannon would charge the retailer for the All-Body swimsuit under target costing is$80.

(c)

To determine the highest acceptable manufacturing cost for the All-Body swimsuit under target costing, we subtract the desired profit per unit from the target selling price.

Target selling price=$100 (given)

Desired profit per unit=$20 (given)

Highest acceptable manufacturing cost=Target selling price-Desired profit per unit

Highest acceptable manufacturing cost=$100-$20

Highest acceptable manufacturing cost=$80

Hannon would be ready to spend up to $80 in manufacturing costs to develop the All-Body swimsuit if it wanted to make $20 each unit.

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Answer:

  (a) ±{1, 2, 5, 10}

  (b) attached

  (c) {-2, -1, 5}

  (d) P(x) = (x +2)(x +1)(x -5)

Step-by-step explanation:

You want the possible and actual rational zeros for P(x) = x^3-2x^2-13x-10, and the factored form of the polynomial.

The rational root theorem tells you the possible rational zeros of a polynomial will be of the form ...

  ±(divisor of the constant)/(divisor of the leading coefficient)

The leading coefficient is 1, and the divisors of the constant are {1, 2, 5, 10}, so the possible rational zeros are ...

  {±1, ±2, ±5, ±10}

The attached graph shows the actual zeros of P(x) to be {-2, -1, 5}.

Each zero q corresponds to a factor (x -q). The factored form of the polynomial is ...

  P(x) = (x +2)(x +1)(x -5)

As a result, the triangle formed by the vertices A(0,0), B(3,8), and C(9,0) has an area of 18 square units.

A triangular is a three-sided, tri-geometric shape. It is a double figure that is frequently represented by the character "." A triangle's angles can never add up to more than 180 degrees. Triangles can be categorized into equilateral, elliptic, and scalene varieties according to the length of their sides and the dimensions of their angles. Three equal edges and three equal, 60-degree angles make up an equilateral triangle. Equal size ends and equal size angles make up an isosceles triangle. The sides and angles of a scalene triangle are not equal.

Given a triangle's vertices in the coordinate plane, we can apply the following formula to get its area:

A is equal to [tex]|(x1(y_2 -y_3) + x_2(y_3 -y_1) + x3(y_1 -y_2)) / 2|.[/tex]

where the triangle's vertices' coordinates are [tex](x_1, y_1), (x_2, y_2), and (x_3, y_3).[/tex]

We obtain: by substituting the coordinates of the specified vertices.

[tex]A = |(0(8 - 0) + 3(0 - 0) + 9(0 - 8)) / 2| = |-36| / 2 = 18[/tex]

As a result, the triangle formed by the vertices A(0,0), B(3,8), and C(9,0) has an area of 18 square units.

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Answer:

-3x - 24 < -36

-3x < -12

x > 4

If over what interval does f(x) = 2x increase faster than g (X): A. 1

To determine over what interval f(x) = 2x increases faster than g(x) = x^2, we need to compare their derivatives. The derivative of f(x) is 2, which is a constant, and the derivative of g(x) is 2x. Therefore, f(x) increases at a constant rate of 2, while g(x) increases at a rate that depends on x.

To find the interval where f(x) increases faster than g(x), we need to find where the derivative of g(x) is less than 2. Setting 2x < 2 and solving for x, we get x < 1.

So, over the interval x < 1, f(x) = 2x increases faster than g(x) = x^2.

Therefore, the answer is A. 1.

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The vertical component of the particle's location, when its horizontal component is 2, is:

y = -1.25

To find the vertical component of the particle's location when its horizontal component is 2, we need to first find the value of t when x = 2.

Given the equation:

x = 3sin(t)

Substitute x with 2:

2 = 3sin(t)

Now, isolate t by dividing both sides by 3:

sin(t) = 2/3

Take the inverse sine (arcsin) of both sides:

t = arcsin(2/3)

Now, plug the value of t back into the y equation:

y = t - 4cos(t) + 1

y = arcsin(2/3) - 4cos(arcsin(2/3)) + 1

Using a calculator to find the approximate value of y, we get:

y ≈ -1.25

Therefore, the vertical component of the particle's location when its horizontal component is 2 is:

y = -1.25

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The ordered pair that represents the week before is given as follows:

A. (1,7).

The general format of an ordered pair is given as follows:

(x,y).

In which the coordinates are given as follows:

The meaning of each coordinate in this problem is given as follows:

For the current week, the ordered pair is given as follows:

(5,3).

For the previous week, the total number of hours was the same, that is, 5 + 3 = 8, however with x = 1 and y = 8 - 1 = 7, as only one hour was spent on chores.

Thus option A is correct.

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The length of the arc with a central angle of 285 degrees and radius 16 inches is 79.6 inches

From the question, we have the following parameters that can be used in our computation:

central angle = 285 degrees

Radius = 16 inches

Using the above as a guide, we have the following:

Length of arc = central angle/360 * 2 * 3.14 * Radius

Substitute the known values in the above equation, so, we have the following representation

Length of arc = 285/360 * 2 * 3.14 * 16

Evaluate

Length of arc = 79.6

Hence, the length of the arc is 79.6 inches

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In the formula, A is the amount after interest, P is the principal, r is interest rate in decimals, n is the amount of times the interest is compounded per year, and t is the amount of years.