A circular park of radius 20m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other.name the type of triangle asd formed
Find the length of AM
Find the length of OM
Find the length of the string of each person
Answers
Answer:
The triangle formed is Equilateral triangle.
I have taken Perpendicular = P ( you can say M)
√400 - x² = OP (OM)
√3 x = AP (AM)
The length of the string of each person = 20√3 m
Step-by-step explanation:
As given , circular park with radius 20m
Let , Ankur sit on boundary point A
Syed sit on boundary point S
David sit on boundary point D
As given,
Ankur, Syed and David are sitting at equal distance on its boundary
⇒AS = AD = SD
Let AS = AD = SD = 2x
As the sides are equal
⇒ The triangle formed is Equilateral triangle.
Now,
Draw a perpendicular on the side SD
Let OP be the perpendicular
⇒SP = PD = [tex]\frac{1}{2}[/tex]SD = [tex]\frac{1}{2}. 2x = x[/tex]
So, we get
SP = x , PD = x
Now, Draw the line OS and OA
AS , we can see that ,
ΔOPS and ΔAPS are right angle triangle ,
So , apply Pythagoras theorem to ΔOPS and ΔAPS
In ΔOPS
OS² = OP² + PS²
⇒20² = OP² + x²
⇒400 - x² = OP²
⇒√400 - x² = OP
Now,
In ΔAPS
AS² = AP² + PS²
⇒(2x)² = AP² + x²
⇒4x² - x² = AP²
⇒√3x² = AP
⇒√3 x = AP
Now,
We can see that,
AP = AO + OP
⇒√3 x = 20 + √400 - x²
⇒√3 x - 20 + = √400 - x²
Squaring both side
⇒(√3 x - 20 )²= (√400 - x²)²
⇒3x² + 400 - 40√3 x = 400 - x²
⇒3x² + x² = 40√3 x
⇒4x² = 40√3 x
⇒x = 10√3
∴ we get
AS = SD = AD = 2(10√3) = 20√3 m
⇒The length of the string of each person = 20√3 m
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Answers
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