A chocolate bar measures 40 mm wide, 80 mm long, and 5 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper to cover the chocolate bar. Use the correct net and determine how much paper will be needed to make the wrapper.

Answer:

no

Step-by-step explanation:

Prime factorization of 66

[tex]66=[/tex][tex]2[/tex] × [tex]3[/tex] × [tex]11[/tex]

the perfect cubes are the numbers that possess exact cubic roots

[tex]\sqrt[3]{66}[/tex] ≈ [tex]4.04[/tex]

66 is not a perfect cube

Hope this helps

Answer: C

Step-by-step explanation:

The line is dotted, so eliminate B and D.

Also, the line has a y-intercept of 1, so this eliminates A.

This means the answer must be C.

Answer:

True.

Step-by-step explanation:

In order for a quadrilateral to be a parallelogram, the top and bottom sides must be congruent, and the left and right must be congruent.

Opposite angles on either side are equal.

The probability of being 25-35 years and having a haemoglobin level above 11 is 34%.

The probability of having a haemoglobin level above 11 is 36%.

Being 25-35 years and having a hemoglobin level above 11 are not dependent on each other.

Probability determines the odds that a random event would occur. The odds of the event happening lie between 0 and 1.

The probability of being 25-35 years and having a haemoglobin level above 11 = number of people between 25 - 35 that have a level above 11 / total number of people between 25 - 35

44 / 128 = 34%

The probability of having a haemoglobin level above 11  = number of people with a level above 11 / total number of respondents

153 / 429 = 36%

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The value of z in the equation evaluation as given in the task content is; 3/5.

It follows from the task content that the value of z as in the task content can be evaluated as follows;

2 4/15-z= 1 2/3

34/15 - z = 5/3

Hence, z = 34/15 - 5/3

z = (34-25)/15 = 9/15

z = 3/5

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It will take the roller coaster 171.652 seconds to pass over the hill and reach ground level

The function is given as:

h = –.025t^2 + 4t + 50

Set h = 0.

So, we have:

–.025t^2 + 4t + 50 = 0

Using a graphing calculator, we have:

t = -11.652 and t = 171.652

Time cannot be negative.

So, we have:

t = 171.652

Hence, it will take the roller coaster 171.652 seconds to pass over the hill and reach ground level

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Answer: C. 0.0225

Step-by-step explanation:

The distance is 0.03 - 0.02 = 0.01.

1/4 of this is 0.0025.

Adding this to 0.02, we get 0.00225.

Assuming [tex]z_1=5[/tex] and [tex]z_2=-6i[/tex], as well as [tex]z_3=3i z_1[/tex] and [tex]z_4 = z_2-2[/tex], we have

[tex]z_3 - z_4 = 3iz_1 - (z_2-2) = 3i\times5 - (-6i-2) = 15i + 6i + 2 = 2 + 21i[/tex]

Since both the real and imaginary parts are positive, [tex]z_3-z_4[/tex] belongs to the first quadrant.

The length of the arc in the image given is approximately: A. 3.5 cm

Length of arc = ∅/360 × 2πr

The missing parts of the question is shown in the image below, where we are asked to find arc length of JH.

Thus, we would have the following:

∅ = 25°

Radius (r) = 16/2 = 8 cm

Substitute the values into the formula:

Arc length JH = 25/360 × 2π(8)

Arc length JH ≈ 3.5 cm

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Using a discrete distribution, we have that:

a) The expected value is of $250 per policy sold.

b) The expected profit for 10,000 policies is of $2,500,000.

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Considering that an insurance profit sells for $600, the distribution of the company's earnings is given as follows:

Hence the expected value for a policy sold is given by:

E(X) = 600(0.965) - 4400(0.02) -9400(0.01) - 29400(0.005) = 250.

For 10,000 policies, the expected profit is given by:

E = 10000 x 250 = 2,500,000.

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Step-by-step explanation:

f.g(x) = f(x+2)

         =(x+2)2 -1

         =(x2+2*x*2+4)-1

         =x2+4x+4-1

         =x2+4x+3

The £1 as a foreign exchange rate is cheaper than 1 CHF by 35%.

The foreign exchange rate refers to the unit of conversion of one currency to another.

Exchange rate = £1=1.55 CHF

Ratio of 1.55 CHF to £1 = 1 : 0.65

Cheapness of £1 = 0.35 (1 - 0.65)

Thus, £1 as a foreign exchange rate is cheaper than 1 CHF by 35%.

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The amount that Lydia has earned on her investment is $198 on the stock paying the 11% dividend and $252 on the stock paying 14% interest for a total earned of $450 on her $3600 investment.

Let x represent half of her total investment.

The total annual interest earned is $450.

This is represented by the following equation:

0.11x + 0.14x= 450

Collect the like terms together

0.25x = 450

x= 1800

Therefore, half of her total investment is $1800 so her total investment is $3600.

Check the solution:

0.11∗1800 + 0.14 ∗ 1800 = 450

198 + 252 = 450

Therefore, she earned $198 on the stock paying the 11% dividend, and $252 on the stock paying 14% interest for a total earned of $450 on her $3600 investment.

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(a.i) If [tex]a_1,a_2,a_3,\ldots[/tex] are in arithmetic progression, then there is a constant [tex]d[/tex] such that

[tex]a_{n+1} - a_n = d[/tex]

for all [tex]n\ge1[/tex]. In other words, the difference [tex]d[/tex] between any two consecutive terms in the sequence is always the same.

[tex]a_2-a_1 = a_3-a_2 = a_4-a_3 = \cdots = d[/tex]

Now, we can expand the target expression into partial fractions.

[tex]\dfrac1{a_na_{n+1}} = \dfrac{\alpha}{a_n} + \dfrac{\beta}{a_{n+1}}[/tex]

Combining the fractions on the right and using the recursive equation above, we have

[tex]\dfrac1{a_na_{n+1}} = \dfrac{\alpha (a_n + d) + \beta a_n}{a_n(a_n+d)} = \dfrac{(\alpha+\beta) a_n + \alpha d}{a_n a_{n+d}} \\\\ \implies \begin{cases}\alpha + \beta = 0 \\ \alpha d = 1 \end{cases} \implies \alpha = \dfrac1d, \beta = -\dfrac1d[/tex]

and hence

[tex]\dfrac1{a_n a_{n+1}} = \dfrac1{da_n} - \dfrac1{da_{n+1}}[/tex]

as required.

(a.ii) Using the previous result, the [tex]n[/tex]-th term [tex](n\ge1)[/tex] in the sum on the left is

[tex]\dfrac1{a_n a_{n+1}} = \dfrac1d \left(\dfrac1{a_n} - \dfrac1{a_{n+1}}\right)[/tex]

Expand each term in this way to reveal a telescoping sum:

[tex]\dfrac1{a_1a_2} + \dfrac1{a_2a_3} + \dfrac1{a_3a_4} + \cdots + \dfrac1{a_{99}a_{100}} \\\\ ~~~~~~~~ = \dfrac1d \left(\left(\dfrac1{a_1} - \dfrac1{a_2}\right) + \left(\dfrac1{a_2} - \dfrac1{a_3}\right) + \left(\dfrac1{a_3} - \dfrac1{a_4}\right) + \cdots + \left(\dfrac1{a_{99}} - \dfrac1{a_{100}}\right)\right) \\\\ ~~~~~~~~ = \dfrac1d \left(\dfrac1{a_1} - \dfrac1{a_{100}}\right) = \dfrac{a_{100} - a_1}{d a_1 a_{100}}[/tex]

By substitution, we can show

[tex]a_n = a_{n-1} + d = a_{n-2} + 2d = \cdots = a_1 + (n-1)d \\\\ \implies a_{100} = a_1 + 99d[/tex]

so that the last expression reduces to

[tex]\dfrac{(a_1 + 99d) - a_1}{d a_1 a_{100}} = \dfrac{99d}{d a_1 a_{100}} = \dfrac{99}{a_1 a_{100}}[/tex]

as required. More generally, it's easy to see that

[tex]\dfrac1{a_1a_2} + \dfrac1{a_2a_3} + \dfrac1{a_3a_4} + \cdots + \dfrac1{a_na_{n+1}} = \dfrac{n}{a_1a_{n+1}}[/tex]

(b) I assume you mean the equation

[tex]\dfrac1{3\times7} + \dfrac1{7\times11} + \dfrac1{11\times15} + \cdots + \dfrac1{k(k+4)} = \dfrac2{25}[/tex]

Note that the distinct factors of each denominator on the left form an arithmetic sequence.

[tex]a_1 = 3[/tex]

[tex]a_2 = 3 + 4 = 7[/tex]

[tex]a_3 = 7 + 4 = 11[/tex]

and so on, with [tex]n[/tex]-th term

[tex]a_n = 3 + (n-1)\times4 = 4n - 1[/tex]

Let [tex]a_n=k[/tex]. Using the previous general result, the left side reduces to

[tex]\dfrac1{3\times7} + \dfrac1{7\times11} + \dfrac1{11\times15} + \cdots + \dfrac1{a_na_{n+1}} = \dfrac n{3a_{n+1}} \\\\ \implies \dfrac{\frac{k+1}4}{3(k+4)} = \dfrac2{25}[/tex]

Solve for [tex]k[/tex].

[tex]\dfrac{k+1}{12k+48} = \dfrac2{25} \implies 25(k+1) = 2(12k+48) \\\\ \implies 25k + 25 = 24k + 96 \implies \boxed{k=71}[/tex]

Answer:

12x+6y+5

Step-by-step explanation:

expand this: 3(4x+2y)=12x+6y

then add 5

12x+6y+5

Answer:

Hello! The answer is 12x + 6y + 5

Step-by-step explanation:

3(4x + 2y) + 5

Distribute:

3(4x + 2y) + 5

= 12x + 6y + 5

All like terms are combined/non-existent so the equivalent expression is: 12x + 6y + 5

The value of the underlined digit (8) in the number given is; Choice B; Eighty million.

The underlined digit in the task content is 8. On this note, it follows that the since, the number can be pronounced as; Five billion, Six hundred and Eighty-two million, Four hundred and fifty thousand, and three.

It is evident, that the place value occupied by the underlined number is; Eighty million.

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Answer:

  B.  (5x+5)/(x²-2x)

Step-by-step explanation:

As with numerical fractions, division by a rational expression is equivalent to multiplication by its reciprocal.

  [tex]\dfrac{5}{x-2}\div\dfrac{x}{x+1}=\dfrac{5}{x-2}\times\dfrac{x+1}{x}[/tex]

As with numerical fractions, the product is the product of numerators, divided by the product of denominators.

  [tex]=\dfrac{5(x+1)}{x(x-2)}=\boxed{\dfrac{5x+5}{x^2-2x}}[/tex]

Answer:

Step-by-step explanation:

A bit late, but better than never.

24. For [tex]x\neq1[/tex], we have

[tex]\dfrac{9x^2 - x - 8}{x - 1} = \dfrac{(x-1)(9x+8)}{x-1} = 9x+8[/tex]

Then as [tex]x[/tex] approaches 1, we have

[tex]\displaystyle \lim_{x\to1} f(x) = \lim_{x\to1} (9x+8) = 17 \neq 0[/tex]

so the function is not continuous at [tex]x=1[/tex]. It is thus continuous on the interval union [tex](-\infty,0)\cup(0,\infty)[/tex]. You can also write this as "[tex]x<0[/tex] or [tex]x>0[/tex]".

25. When [tex]x[/tex] approaches 2 from the left (when [tex]x<2[/tex]), we have

[tex]\displaystyle \lim_{x\to2^-} f(x) = \lim_{x\to2} (5-x) = 3[/tex]

When [tex]x[/tex] approaches 2 from the right [tex](x>2)[/tex], we have

[tex]\displaystyle \lim_{x\to2^+} f(x) = \lim_{x\to2} (2x-3) = 1[/tex]

so the function is not continuous at [tex]x=2[/tex]. Thus it's continuous on [tex](-\infty,2)\cup(2,\infty)[/tex], or "[tex]x<2[/tex] or [tex]x>2[/tex]".

Answer: 4.8

Step-by-step explanation:

Corresponding sides of similar figures are proportional, so

[tex]\frac{x}[4}=\frac{6}[5}\\\\x=4\left(\frac{6}{5} \right)=\boxed{4.8}[/tex]

Answer:

Below in bold.

Step-by-step explanation:

Let the number of pistachios be x then the number of almonds = x-100.

The number of cashews = 1000 - x - (x - 100) = 1100-2x.

From the info given

3(1100-2x) + 4x + 5(x - 100) = 3700

3300 - 6x + 4x + 5x - 500 = 3700

3x = 3700 - 3300 + 500

3x = 900

x = 300

So there are 300 pistachios, 200 almonds and 500 cashews in the bag.

There are 300 pistachios, 200 almonds, and 500 cashews in the bag of mixed nuts.

To find the number of each type of nut in the bag, we can set up a system of equations based on the given information.

Let's assume there are x pistachios in the bag. According to the problem, there are 100 fewer almonds than pistachios, so the number of almonds will be (x - 100).

Now, the total number of nuts is 1,000:

x (pistachios) + (x - 100) (almonds) + cashews = 1000

The total weight of the nuts in the bag can be calculated as follows:

3g (cashews) * number of cashews + 4g (pistachios) * x + 5g (almonds) * (x - 100) = Total weight in grams.

Since we know that the bag weighs 3.7 kg, we need to convert the total weight to grams and set it equal to 3.7 kg * 1000g/kg = 3700g.

Now we have two equations:

x + (x - 100) + cashews = 1000

3g * cashews + 4g * x + 5g * (x - 100) = 3700

Let's simplify equation 1:

2x - 100 + cashews = 1000

2x + cashews = 1100

cashews = 1100 - 2x

Now, let's substitute the expression for cashews in equation 2:

3g * (1100 - 2x) + 4g * x + 5g * (x - 100) = 3700

Now, distribute the weights:

3300g - 6g * x + 4g * x + 5g * x - 500g = 3700

Combine like terms:

-6g * x + 4g * x + 5g * x = 3700 - 3300 + 500

3g * x = 900

x = 900 / 3

x = 300

Now that we have the value of x (number of pistachios), let's find the number of almonds:

almonds = x - 100

almonds = 300 - 100

almonds = 200

Now, let's find the number of cashews using the total nut count:

cashews = 1000 - (pistachios + almonds)

cashews = 1000 - (300 + 200)

cashews = 1000 - 500

cashews = 500

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Answer:

D

Step-by-step explanation:

Subtracting 2 from both sides and then dividing both sides by 3 gives that x² = -2/3, which indicates the roots are complex.

Answer:1,3,5

Step-by-step explanation:

Step-by-step explanation:

the distance between 2 points is per Pythagoras

c² = a² + b²

with c being the Hypotenuse (the baseline opposite of the 90° angle, which is the direct distance between the points). a and b are the legs (the x and y coordinate differences).

so,

AB² = (3-6)² + (1-2)² = 9+1 = 10

AB = sqrt(10) = 3.16227766...

BC² = (6-6)² + (2 - -2)² = 0² + 4² = 16

BC = sqrt(16) = 4

CD² = (6-3)² + (-2 - -3)² = 3² + 1² = 10

CD = sqrt(10) = 3.16227766...

DA² = (3-3)² + (-3 - 1)² = 0² + 4² = 16

DA = sqrt(16) = 4

so, the perimeter is

2×4 + 2×sqrt(10) = 8 + 6.32455532... = 14.32455532... ≈

≈ 14.3

[tex]frequency = \frac{24 \: osc}{60 \: sec} = 0.4 \: osc \: per \: sec[/tex]

[tex]period = \frac{1}{frequency} = \frac{1}{0.4} = 2.5 \: sec \: per \: osc[/tex]

[tex]t = 2\pi \sqrt{ \frac{l}{g} } \\ 2.5 = 2\pi \sqrt{ \frac{l}{9.8} } \\ \frac{2.5}{2\pi} = \sqrt{ \frac{l}{9.8} } \\ ( \frac{2.5}{2\pi} ) {}^{2} = \frac{l}{9.8}[/tex]

[tex]l = ( \frac{2.5}{2\pi} ) {}^{2} \times 9.8 = 1.55148 \: meters[/tex]

Answer:

The answer is ninth term is -32

Answer:

2¹²

Step-by-step explanation:

one expression equivalent to 16³ is 2¹²

think about it like this: we know that 2 to the power of 4 is 16

(2 x 2 = 4, x 2 = 8, x 2 = 16)

So for every "16" we already have 2⁴; meaning that 16³ is the same thing as 3 groups of 2⁴ -- which is 2¹²

hope this helps! have a lovely day :)

Answer:

AB: y=2x+2

CB: y=-2x+6

CD: y=1/2x-1.5

DA: y=-3x+2

Step-by-step explanation:

Answer:

AB: [tex]y=2x+2[/tex]

CB: [tex]y=-2x+6[/tex]

CD: [tex]y=\frac{1}{2}x -1.5[/tex]

DA: [tex]y=-3x+2[/tex]

Step-by-step explanation:

So when it's saying y = __ x + __ it's asking for the slope-intercept form. This is given as y=mx+b where m is the slope and b is the y-intercept. m is the slope because as x increases by 1, the y-value will increase by m, which is by definition what the slope is [tex]\frac{rise}{run}[/tex] how much the function "rises" as x "runs".

AB: See how it "rises" by 2 and only "runs by 1", thus the slope is 2/1 or 2. the last part is the y-intercept, which is the value of y when the line crosses the y-axis. If you look at the graph when it "crosses" the y-axis it's y-value is 2. So you have the equation: [tex]y=2x+2[/tex]

CB: See how it "goes down" by 4 and "runs" by 2, thus the slope is -4/2 or -2. The y-intercept isn't shown on the graph but you can calculate that by substituting known values into the slope-intercept form. So we know so far y=-2x+b since the slope was calculated, and we can take any point on the line to calculate b, for this example I'll take the point C which is (3, 0) which is (x, y) and I'll plug that in

Plug values in:

0 = -2(3) + b

0 = -6 + b

6 = b

This gives you the complete equation: [tex]y=-2x+6[/tex]

CD: see how it only "rises" by 1 but "runs" by 2, thus the slope is 1/2. The y-intercept isn't shown on the graph but you can calculate it by substituting a point into the equation For this example I'll use point C (3, 0)

0 = 3(1/2) + b

0 = 1.5 + b

-1.5 = b

This gives you the complete equation: [tex]y=\frac{1}{2}x - 1.5[/tex]

DA: see how it "decreases" by 3 but "runs" by 1, thus the slope is -3/1 or -3. The y-intercept is known and is at (0, 2) so now we plug these values in to get the equation: [tex]y=-3x+2[/tex]

For the given systems the answers are:

1) "Replace one equation with a multiple of the other equation".

2) The systems are not equivalent.

Here we have the systems of equations:

A:

4x + 16y = 12

x +2y = -9

B:

4x + 16y = 12

x + 4y = 3

Notice that the first equation is the same in both systems, but the second is different.

In A we have:

x + 2y = -9

In B we have:

x + 4y = 3

So we need to add 2y on the left side of A, and 12 on the right side of A to get the equation in B.

Or we can just take the other equation in A, divide it by 4, and replace it.

So we need to replace the second equation in A for other equation, then the correct option is:

"Replace one equation with a multiple of the other equation".

Because we are replacing an equation in A by other to get system B, we conclude that systems are not equivalent.

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Answer:

khan

Step-by-step explanation: