Hi there!
On an incline, the acceleration due to gravity is: (g = 9.81 m/s²)
a = gsinФ ≈ 1.196 m/s²
We can use the following kinematic equation to solve:
vf² = vi² + 2ad
Since the car will start to roll back when v = 0 m/s, we can write that vf = 0.
0 = vi² + 2ad
Plug in values:
0 = 31² + 2(-1.196)(d)
Rearrange for d:
31²/(2.392) = d
d = 401.756 m
The car will coast for 7885.49 meters before starting to roll back down.
The car is subject to two forces: the force of gravity, which is pulling it down the hill, and the force of friction, which is trying to slow it down. The force of friction is equal to the coefficient of friction between the tires and the road multiplied by the normal force, which is equal to the weight of the car.
The car will stop coasting when the force of gravity is equal to the force of friction. We can set up an equation to find the distance the car will coast before stopping:
d = ([tex]v^{2}[/tex]) / (2 * μ * g * sin(θ))
where:
d is the distance the car will coast before stopping
v is the initial speed of the car
μ is the coefficient of friction between the tires and the road
g is the acceleration due to gravity
θ is the angle of the slope
Plugging in the values from the problem, we get:
d = [tex](31 m/s)^2[/tex] / (2 * 0.01 * 9.8 m/[tex]s^{2}[/tex] * sin(7.0°))
d = 7885.49 meters
Therefore, the car will coast for 7885.49 meters before starting to roll back down.
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100k points pls solve asap or no points
Answer:
Explanation:
You have given us a very weird question. Things do not mesh
If the mass is 500 kg and sits 25 m above the lowest spot on the track, the potential energy is
PE = mgh = 500(9.8)(25) = 122500 Joules,
not the reported 61250 Joules
So either the Joules is incorrect or the mass is supposed to be 250 kg.
In either case, in the absence of friction, the potential energy will convert to kinetic energy.
½mv² = mgh
v = √2gh
which does not involve the use of either Joules or kilograms.
Maximum velocity when starting from rest is
v = √(2(9.8)25) = √490 = 22.135943...
v = 22 m/s
Can air make shadows?
Answer:
Yes, air can indeed make shadows. A shadow occurs when an object in a light beam prevents some of the light from continuing on in the forward direction. When the light beam hits a wall or the ground, a darker shape is visible where less light is hitting the surface. Refraction is responsible.
Explanation:
Here is a clip of an example of air making a shadow
https://www.seeker.com/stories/air-shadows/
Weight refers to the pull of _________ on an object.
Question 2 options:
mass
gravity
volume
Answer: Weight refers to the force of gravity acting upon an object.
(Answer B)
SI units are used for scientific works. Why?
Answer:
SI units are used for scientific works to bring uniformity in measurements all over the world.
The gravitational field strength on earth is 10n/kg. find the weight of an object of mass 25kg
Answer:
250N
Explanation:
weight = Mass(in kg) × Gravitational field strength
25 × 10 = 250N
Answer:
250 N
Explanation:
Refer the attachment for explanation.
A box of mass 20kg rests on a flat horizontal floor. if the density of air is negligible. Draw a diagram showing forces acting on the box
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Answer:
pls English
Explanation:
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A 0.038-kg bullet enters a 3.2-kg watermelon and embeds itself in the melon. The melon is immediately set into motion with a speed of 3.82 m/s. The bullet remains lodged inside the melon. What was the entry speed of the bullet (m/s)?
Hi there!
This is an example of a perfectly inelastic collection, so:
mb = mass of bullet
vb = velocity of bullet
mw = mass of watermelon
v = velocity final
mbvb = (mb + mw)v
Rearrange to solve for the velocity of the bullet:
vb = (mb + mw)v/mb
Plug in values:
vb = (0.038 + 3.2)(3.82)/(0.038) = 325.504 m/s
Which of the following types of energy would cause one piece
of metal to be attracted to another?
a heat
b nuclear
c light
d magnetic
PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land
Answer:
Explanation:
It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.
s = s₀ + v₀t + ½at²
vertical analysis with floor level as origin
0 = 1.2 + 5t + ½(-9.8)t²
0 = 1.2 + 5t - 4.9t²
quadratic formula positive answer
t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))
t = 1.22 s is the flight time
horizontal analysis with launcher as origin
s = 0 + 12(1.22) + ½(0)1.22²
s = 14.6517... 15 m
What happens if the incident beam is perpendicular to the surface (at an angle of 90 degrees)?
If the ray is perpendicular to the surface, then the incident ray, the reflected ray and the transmitted (refracted) ray all lie along the same line (i.e they are collinear). If the ray is not perpendicular to the surface, then the ray appears to be bent at the surface.
Questions
Q1. In this lab the centripetal force is provided by
a) the person’s hand
b) the tube
c) the hanging weight
d) the spinning motion
Q2. If the mass of the stopper were doubled but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled
Q3. If the velocity of the stopper were doubled, but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled
Answer:
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Reflect on your new experiences, what made you uncomfortable and what encouraged you. Did you learn anything new about yourself on the trip? Traveling can help you improve. Think about your journey and if it helped you grow in any way.
Answer:
keke
Explanation:
An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
Hi there!
On the object, we know that there are two forces working on the object:
-Force due to gravity (Mg)
-Force due to air resistance
Let the positive direction of the force be downwards (direction of the acceleration)
We can write the summation of forces as:
∑F = Mg - Fa
Plug in values. Let g ≈ 10 m/s²
∑F = 30(10) - 50 = 250N
Find the acceleration using the formula:
∑F = m · a
∑F/m = a
Plug in values:
250/30 = 8.33 m/s²
is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??
Answer:
it is potential energy ---- kinetic energy
I NEED HELP PLZZZZZZ
A 10 g dime and a 200 g gold coin are dropped from the Empire State Building in
New York at the same time.; if there is no air resistance which hits the ground first?
A.They both hit the ground at the same time
B.Which hits first depends on the weather & temperature of the air.
C.The 200 g gold coin hits the ground first
D.The 10 g dime hits the ground first
Answer:
Explanation:
The both hit the ground at the same time. There is no air resistance and that includes the factors brought up in B.
C and D are both eliminated. If you dropped an 800 kg honda Fit it would hit the ground at the same time as the two coins. When you look at the formulas used to derive time, they look like
d = vi * t + 1/2 a* t^2
vi = 0
the distance to fell is the same for all three masses.
a is the same for all 3 masses.
So when you solve for t, there is no mention of the mass of the object falling. Therefore t is dependent only on the height.
The U.S. uses a household voltage of 110 V. However, electric stoves and dryers are wired with
220 V lines. Which would cause less damage --plugging a 110 V-rated curling iron into a 220 V
outlet, or a German-made 220 V-rated curling iron into a 110 V outlet? Explain. (Note: 110 and
220 V outlets are made in different shapes so that appliances cannot be accidentally
interchanged.)
Answer:
In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance
Consider three properties of the net force on an object: a magnitude, direction, and angle with respect to the objects path. For the following situation select the choice that indicates wether these quantities are constant or changing during the course of the motion.
1. The magnitude and the angle of the net force with respect to path are constant, but the direction is changing
2. The direction and the angle of the net force with respect to path are constant, but the magnitude is changing.
3. The magnitude and direction of the net force are changing, but the angle of the net force with respect to path is constant.
4. The magnitude, direction, and angle with respect to path for the net force are constant.
5. The magnitude and direction of the net force are constant, but the angle of the net force with respect to path is changing.
Answer:
Explanation:
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If a ball is kicked horizontally off of a building at 8.0 m/s, what is the horizontal velocity (vx) after 3
seconds?
The characteristics of the projectile launch allows to find the result for the velocity on the x axis is:
In the horizontal axis there is no acceleration and therefore the speed must be kept constant. The horizontal speed is vₓ = 8.0 m / s
In projectile launching we have an application of kinematics to motion in two dimensions near the surface of the Earth.
In this case, on the vertical axis we have an acceleration directed towards the center of the planet and called the gravity acceleration.
In the horizontal axis or x axis there is not acceleration, except in special cases that we tone is how much the resistance of the air.
Consequently in the horizontal axis there is no acceleration and therefore the speed must be kept constant, the result for the horizontal speed is:
vₓ = 8.0 m / s
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If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of 28 m/s north?
Answer:
Explanation:
vo= 0
a=5.5m/s^2
v= 28 m/s
t=?
v=vo+at
at=v-vo
t=(v-vo)/a
t=28/5.5
t=5.09 seconds
You throw a ball upward with an initial speed of 3.0 m/s from an initial height of 1.5 m. After you throw the ball, its acceleration is 9.81 m/s downward. Taking upward to be the positive direction, write the position-time equation for the ball's motion
Answer: An object undergoing a constant acceleration can have its motions be described by the kinematic equations. These equations relate the position of the particle, its velocity, acceleration, and time.
Explanation:
Answer:
vf^2=vo^2+2ay(y1-y0)
Explanation:
Agents of socialization?
Answer:
agents of socialization are:-
family
peers
school
mass media
momentum is conserved it can be transferred but not lost. true or false
Answer: False
explanation: because Total momentum is conserved only if the collision can be considered isolated from the influence of net external forces
Which of the following is not an aspect of instincts?
CEK- 9. If the speed of sound at 0° C is vo, the velocity at 273° C will be (a) 2 vo (b) 0.5 vo b (c) (d) 0.7 vo 1.4 vo
Answer:
D
Explanation:
273 * 0.6=163.8
vo≈331
Your new motorcycle weighs 2580 N.
The acceleration of gravity is 9.8 m/s2.
What is its mass?
Answer in units of kg.
Answer:
answer to your question is 263.26kg
Explanation:
m=f÷a ,m=2580÷9.8=263.26kg
A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.
With what speed does the fish leave the water?
What height above the water does it reach?
Answer:
Explanation:
Velocity will be equal to the area under the curve of the acceleration-time plot.
v = ½(45)(0.075) = 1.6875
v = 1.7 m/s
h = (0² - 1.6875²) / (2(-9.8)) = 0.145288...
h = 15 cm
the electric field at point 4.00 cm from the axis, measured radially outward from the midpoint of the shell.
How much gravitational potential energy is stored in a 2.0kg object that has been raised up to a height of 3.5m
Answer:
68.6 joules
Explanation:
g.p.e=mass × gravity × height
= 2 × 9.8 × 3.5
=68.6 joules