A car accelerates from 0 to 30 m/s in 8 seconds. What is its acceleration?

Answer:

i think its d

Explanation:

Answer:

Radio telescopes .

Explanation:

They have a modest size that can't make out as much detail (have a lower resolution) than visible light telescopes

Answer:

the mass + the 1 constant g-force = the speed without adding air resistance

Explanation:

osmium it the most tightly packed alloy in the world so for that it will have a faster acceleration

ITS TURE.When there is no torque acting on a body, its angular momentum is constant. Net force changes momentum, while net torque changes angular momentum.

Answer: false

Explanation:

Answer:

13.73 degrees farenheit

-10.15 degrees Celsius

Explanation:

hope this helps

Answer:

Explanation:

Basically because they are big and relatively near.

The light coming from a star travels a huge distance and is acted upon by the earth's atmosphere with causes all sorts of shifts. What we are seeing twinkle is caused by these shifts, for the most part caused by atmospheric density and heat.

The beam from a planet is not narrow enough to be affected the way the stars are.. If you were out in space looking at all this, the stars would not appear to twinkle either.

Answer:

yes

Explanation:

Answer:

mass of the products

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Answer:

because it's discovered by Galileo Galilei

Answer:

Hello how are you ^0^

Explanation:

because it's discovered by Galileo Galilei

hope it's help you (^0^)

Answer:

16.63265306 Kg

Explanation:

This is a Newtons to weight conversion.

Fg = weight

Fg = N/9.8

Answer:

he pushed 192,753,636,363

Explanation:

Answer:

this is just a guess bc i only looked at it for 5 seconds but i think 150 m/s

Regular exercise has a positive impact on the brain, and the best explanation for this is that exercise helps maintain and create pathways in the brain (Option C).

1. The brain is a complex organ composed of billions of nerve cells called neurons. These neurons communicate with each other through pathways, forming a vast network.

2. When we engage in physical exercise, it increases blood flow to the brain. This enhanced blood flow delivers more oxygen and nutrients to the brain cells, promoting their overall health and functioning.

3. Exercise also stimulates the release of various chemicals in the brain, such as neurotransmitters and growth factors. These substances play a crucial role in the growth, development, and maintenance of brain cells.

4. Additionally, regular exercise has been found to promote the formation of new connections between neurons, a process known as neuroplasticity. These connections, also called synapses, are essential for learning, memory, and overall cognitive function.

5. By engaging in consistent exercise, individuals can enhance neuroplasticity, allowing their brains to adapt and reorganize in response to new experiences and challenges.

6. Moreover, exercise has been shown to reduce the risk of age-related cognitive decline and neurodegenerative diseases, such as Alzheimer's disease. It may also help improve mood, reduce stress, and enhance mental well-being.

7. In summary, while the brain is not a muscle that can be directly exercised, regular physical exercise positively impacts the brain by promoting neuroplasticity, improving blood flow, releasing beneficial chemicals, and reducing the risk of cognitive decline.

Therefore, the best explanation for why a consistent exercise regime has a positive impact on the brain is that exercise helps maintain and create pathways in the brain (Option C).

For more such questions on brain, click on:

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Answer:

Amplitude

Explanation:

Answer:

the wave trough.

Explanation:

As is shown on the figure, wave height is defined as the height of the wave from the wave top, called the wave crest to the bottom of the wave, called the wave trough. The wave length is defined as the horizontal distance between two successive crests or troughs.

[tex]\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{40-30}{0.05}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{10}{0.05}[/tex]

[tex]\\ \sf\longmapsto Acceleration=200km/h^2[/tex]

Answer

[tex]200km {h}^{ - 2} [/tex]

Explanation

[tex]Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2} [/tex]

Hope this helps you.

Let me know if you have any other questions :-):-)

[tex] \huge \underline \mathtt \colorbox{cyan}{E=mc squared}[/tex]

(E=mc^2)

m is mass

And c is a constant for speed of light

Answer:

One of the most famous and well-known equations in all of human history, E = mc^2, translates to "energy is equal to mass times the speed of light squared." In other words, wrote PBS Nova, energy (E) and mass (m) are interchangeable. They are, in fact, just different forms of the same thing.

Explanation:

this is right answer

Answer:

The only answer that i could think of:

A falling body

Answer:

a sky diver that just jumped out of a plane

or a car that just had the light turn green

or an apple droped from a tree

or a sled sliding down a hill

Explanation:

all of these objects would be acclerating

the skydiver and apple would be acclerating from 0 at a rate of 9.8m/s^2

Hope this helps! :)

Answer:

F1 = K Q Q / R^2

F2 = K 2Q * 2Q / (2 R)^2 = K 4 Q^2 / (4 R^2) =  K Q^2 / R^2

F1 = F2 and (e) is  the correct answer

The force between the two charges will be the same, so the new force is the same. Hence, option (e) is correct.

When put in an electromagnetic field, charged matter experiences a force due to the fundamental property of electric charge. Positive or negative electrical ions are possible. When two charges are in opposition to one another, they repel one another.

The term "neutral" refers to an object that has no net charge. The early understanding of the way charged particles interact is now referred to as classical electrodynamics, and it is still true for issues that do not demand taking into account quant phenomena.

As per the given data provided in the question,

F(1) = K (Q)(Q) / R²

After applying the given condition in the question,

F(2) = K (2Q) × (2Q) / (2 R)²

= K 4 Q² / (4 R²)

F(2) =  K Q²/ R²

Which means that F1 = F2.

Therefore, it concludes that option (e) is correct.

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Answer:

D- Electric charges move through the water in the pool.

Explanation:

I got it right on my test

Answer:

A 925 kg car accelerates uniformly from rest to a velocity of 25.0 mls south in 10.0 s. What is the net force acting on the car during this time?

F=(925*25)/10

F=2312.5 N to south

Hi there!

We can begin by calculating the acceleration experienced by the car.

vf = vi + at

The initial velocity is 0 (at rest), so:

25 = at

25/10 = a = 2.5 m/s²

Using Newton's Second Law:

∑F = ma, where:

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

Plug in the values:

∑F = 925 · 2.5 = 2312.5 N

Answer:

[tex]{ \rm{acceleration = \frac{force}{mass} }} \\ \\ { \rm{a = \frac{990}{50} }} \\ \\ { \boxed{ \rm{ \: a = 19.8 \: m {s}^{ - 2} }}}[/tex]

At the bottom left,

Increasing potential energy.

At ascending,

Increasing kinetic energy.

At the peak,

Greatest potential energy.

At the descending,

Greatest kinetic energy.

Answer:

According to Newton's third law, for every action force there is an equal (in size) and opposite (in direction) reaction force. Together, these two forces exerted upon two different objects form the action-reaction force pair.

Explanation:

Sana makatulong ^_^

Answer:

The question does not state how the answer is to be entered. I would use 10% because that is most common.

Explanation:

You are using 300 J of energy to get 30 J of light energy. The fact that you can account for the left over energy is not relevant.

Efficiency = Work Out / Work In

Efficiency = 30 J / 300 J  = 0.1

If you need this as a %, you can multiply by 100

Efficiency = 0.1 * 100 = 10%

Answer:

[tex]\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}[/tex]

[tex]\implies \mathsf{24=\frac{12^2}{R} }[/tex]

[tex]\implies \mathsf{24R=12^2 }[/tex]

[tex]\implies \mathsf{24R=144 }[/tex]

=> R= 6 Ohms(Ω)

[tex]\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}[/tex]

these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,

[tex]\implies \mathsf{100=\frac{240^2}{R} }[/tex]

R and 100 can interchange places

[tex]\implies \mathsf{R=\frac{240^2}{100} }[/tex]

[tex]\implies \mathsf{R=\frac{57600}{100} }[/tex]

=> R = 576 Ω

By Ohm's Law:

[tex]\boxed{\mathsf{Voltage(V)=Current(I) \times Resistance(R)}}[/tex]

=> 240 = I × 576

=>

=> I = 0.417 A

I don't know it's resistance,... so sorry

The brightness of the bulb in series is less than when they're placed individually.

For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.

Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.

So, the effective resistance of some bulbs in series is more than the individual resistance.

And

Brightness, i. e., Power

[tex]\boxed{\mathfrak{Power \propto \frac{1}{Resistance} }}[/tex]

If resistance increases, Power decreases.

Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.

This question involves the concept of the resolution of a vector into its rectangular components.

The horizontal component of velocity is "1.4 m/s", and the vertical component of the velocity is "7.9 m/s".

In order to find the horizontal and vertical components of the velocity of Esther, we must resolve the velocity vector into its rectangular components. Hence, the following formulae will be used:

[tex]Horizontal\ Component = v_x = v\ Cos\theta\\v_x = (8\ m/s)(Cos\ 80^o)\\v_x = 1.4\ m/s[/tex]

[tex]Vertical\ Component = v_y = v\ Sin\theta\\v_y = (8\ m/s)(Sin\ 80^o)\\v_y = 7.9\ m/s[/tex]

Learn more about the resolution of a vector here:

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The attached picture shows the resolution of a vector.

From the given information, it's not possible to find the mass or the volume of the sample.

Density is their RATIO, but you can't tell if the sample is the size of an ant or a school-bus.

For telescopes in general, ever since they were invented, it's the size of the objective lens (in the front) or mirror (in the back).

For the most hugest humongous telescopes, built in the past few decades, it's limited by the turbulence of the atmosphere.  That's the main reason we started building the big ones on mountain tops and in deserts, and lately we've started putting them in Earth orbit, where they don't have to look through any air at all.

East or west: it remains the same.

North: it increases.

South: it decreases.

At the North pole: it's straight up over your head.

At the equator: it's on the horizon, north of you.

South of the equator: it's below the horizon and you can't see it at all.