A ) The height of cliff from which the cannonball is shot from = 12.72 m
B ) The distance from the base of the cliff = 19.14 m
- H = [tex]u_{y}[/tex] T - 1 / 2 g T²
T = Total time taken
g = Acceleration due to gravity
H = Height above the ground
[tex]u_{y}[/tex] = Y-component of initial velocity
T = 2.2 s
g = 9.8 m / s²
θ = 30°
u = 10 m / s
[tex]u_{y}[/tex] = u sin θ
[tex]u_{y}[/tex] = 10 * sin 30°
[tex]u_{y}[/tex] = 5 m / s
- H = ( 5 * 2.2 ) - ( 0.5 * 9.8 * 2.2 * 2.2 )
- H = 11 - 23.72
H = 12.72 m
R = [tex]u_{x}[/tex] T
[tex]u_{x}[/tex] = u cos θ
[tex]u_{x}[/tex] = 10 * cos 30°
[tex]u_{x}[/tex] = 8.7 m / s
R = 8.7 * 2.2
R = 19.14 m
Therefore,
A ) The height of cliff from which the cannonball is shot from = 12.72 m
B ) The distance from the base of the cliff = 19.14 m
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An electric jug with a power rating of 600W has been used for 6 hours. How many units of energy is used ?
Answer:
w=2160kJ
Explanation:
work=power × Time
w=pt
p=600W
t=60min×60sec=3600
w=600 × 3600
w=2160000joules(J)
w=2160kJ
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Which of the following is true when the kinetic energy of the particles in a sample of matter is lowered?The temperature increases.bThe temperature decreases.cThe sample will absorb less heat.dMore heat flows away from the sample.
Answer: The temperature decreases.
The intern energy is shown with the movement of particles, if the lower the speed then the intern energy decrease, and the temperature too.
Answer: More heat flows away from the sample
This one can be true, when they stop moving the heat (temperature) decreases and that heat energy flows away.
Both are so similar, but the most accurate is the temperature decrease because the heat flows a part away not totaly
While experimenting with electromagnets, students oriented two like you see in the diagram here. Predict what will happen and explain
why.
A The two electromagnets will repel; the poles repel.
B The two electromagnets will repel; the electrical current forces them away from each other.
C The two electromagnets will attract; opposite poles attract
D Nothing will happen; electromagnets do not behave like typical bar magnets.
Answer:
C The two electromagnets will attract; opposite poles attract
Explanation:
Electromagnets behave like regular magnets - they have two poles - positive and negative
Like regular magnets, opposite poles attract, similar poles repel
Maria is doing a report on Mathieu Orfila. What fact is she MOST likely to include in her report?
.
AHe solved the first crime that used medical evidence.
BHe studied fingerprints and started to classify them.
CHe was the first person to use bullet comparisons.
DHe explored how poisons affected animals.
??
Answer:
Its B
Explanation:
Answer:
She is most likely to include that he explored how poisons affected animals.
Explanation:
A 2300-kg truck is traveling down a highway at 32 m/s. What is the kinetic energy of the truck?
ANSWER:
1177600 joules
STEP-BY-STEP EXPLANATION:
Given:
m = 2300 kg
v = 32 m/s
We can calculate the kinetic energy using the following formula:
[tex]E=\frac{1}{2}m\cdot v^2[/tex]Replacing:
[tex]\begin{gathered} E=\frac{1}{2}\cdot2300\cdot32^2 \\ E=1177600\text{ J} \end{gathered}[/tex]The kinetic energy of the truck is 1177600 joules.
An oscillator is used to create a wave on a string. The frequency of the oscillator is 4 Hz and the waves measures to be 0.5 m apart. What is the speed of the wave
Given,
Frequency of the wave, f=4 Hz
The wavelength of the wave, λ=0.5 m
The speed of a wave is given by,
[tex]v=f\lambda[/tex]On substituting the known values in the above equation,
[tex]v=4\times0.5=2\text{ m/s}[/tex]Therefore the speed of the standing wave produced is 2 m/s
A 1800 kg object moving to the east at 13 m/s, collided with a 200 kg object that was moving to the north at 32 m/s. What was the angle of motion
What is the speed at the bottom of the funnel?
We will have the following:
[tex]\begin{cases}I=r^2m \\ \\ L=I\omega \\ \\ \omega=v/r\end{cases}[/tex]So:
We will find the data we can with the given information:
[tex]\omega_1=\frac{0.3m/s}{0.2m}\Rightarrow\omega=\frac{1.5}{s}[/tex]Also:
[tex]I\omega_1=I\omega_2\Rightarrow\omega_1=\omega_2[/tex]So:
[tex]\frac{1.5}{s}=\frac{v}{0.03m}\Rightarrow v=0.045m/s[/tex]So, the velocity at the bottom of the funnel is 0.045m/s.
If F =GMm/R2
What is the dimension of the stress?
What is the unit of frequency?
The dimension of stress is M1 L-1 T-2 and the unit of frequency is Hz.
What is the frequency?
The frequency with which something happens over a specific time frame or sample
Let us find out the dimension of stress.
Stress = Force/Area
Force = mass * acceleration
Stress= M * L * T-2/ L2
Therefore, Stress = M L-1 T-2
As for the second question,
The unit of frequency is Hz (Hertz)
Hence, the dimension of the stress = M L-1 T-2 and the unit of frequency is hertz.
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Investigation Question: How do objects get energy?Claim 1: Objects make their own energy.Claim 2: Objects get energy from other objects that have energy.Pick one of the claims above and provide evidence and reasoning for why you believe it is correct.
Energy can neither be created nor destroyed. It can only be transferred from one object to another.
Claim 2 is correct.
Energy cannot be created or destroyed. So, objects can not make their own energy.
Energy can be transferred or transformed. Energy can be changed in many ways, such as conversion of kinetic energy into potential energy and vice-versa, when one object moves another object, etc.
For example, to lift an object against the gravity, work is done on the object. This work is converted in the form of potential energy, called as gravitational potential energy. When an object, say an apple falls towards Earth from a tree, gravitational potential energy is converted into kinetic energy.
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Joe is carrying a load of supplies and likely injuring his back by supporting 882 N of weight. Calculate the mass of what he is carrying.
Since the load Joe is carrying is equal to the supporting weight, the mass of the load will be 90 Kg
What is Weight ?Weight is the gravitational pull of an object under the influence of acceleration due to gravity.
Given that Joe is carrying a load of supplies and likely injuring his back by supporting 882 N of weight.
The load Joe is carrying will be equal to 882 N
To calculate the mass of what he is carrying, let us use the formula
W = mg
Where
Weight W = 882 NAcceleration due to gravity g = 9.8 m/s²Mass m = ?882 = 9.8m
m = 882/9.8
m = 90 Kg
Therefore, the mass of what he is carrying is 90 Kg
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Explain the flow of energy needed for the deer to eat.
Energy flow in an needed for the deer to eat starts at the sun which produces all the energy needed for life. Then comes the producers, the autotrophs(plants). These organisms harness the energy of the sun and convert it into sugars. Then deer which eat the autotrophs get the next most energy.
What is energy flow?One of the key components that enables the survival of such a large number of organisms is the energy flow within the ecosystem. Solar energy is the main source of energy for almost all living things on Earth.
It is interesting to learn that less than 50% of the sun's actual radiation reaches Earth. The radiation that plants can use to perform photosynthesis is the radiation that is considered to be effective.
Through the food chain and food web, energy is transferred. Being the energy producers, plants use their chloroplasts to absorb sunlight, part of which is converted into chemical energy during the process of photosynthesis.
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Artificially produced radioactive isotopes are used in medicine and medical research.Question 1 options:TrueFalse
Artificial isotopes are usually absent by nature because of their unstables nature . The Isotopes usually transit into a stable Isotopes. This Isotopes are produced artificially by bombarding an atom.
Artificially radioactive Isotopes produced from stable Isotopes are used in medicine and medical research. Therefore, the answer is True.
A car of mass m = 1090 kg is traveling down a θ = 11 degree incline. When the car's speed is v0 = 16 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is μk = 0.45.
Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end.
The distance travelled by the car along the plane is 29.56 m.
What is the acceleration of the car down the incline?The acceleration of the car down the incline is calculated by applying Newton's second law of motion as shown below;
F - Ff = ma
where;
F is the applied force on the car = 0Ff is the frictional force acting on the car, trying to stop it m is the mass of the cara is the acceleration of the car down the inclinefrictional force acting on the car, Ff = μmg cosθ
0 - μmg cosθ = ma
-μmg cosθ = ma
-μg cosθ = a
where;
μ is coefficient of kinetic frictionθ is the angle of inclination of the planea = -(0.45 x 9.8 x cos11)
a = -4.33 m/s²
The distance travelled by the car along the plane is calculated as follows;
v² = u² + 2aL
where;
L is the length of the incline = distance travelled by the carv is the final velocity of the car when it stops = 0u is the initial velocity of the car = 16 m/sa is the acceleration of the car0 = (16²) + 2(-4.33)L
0 = 256 - 8.66L
8.66L = 256
L = 256/8.66
L = 29.56 m
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The differences in air pressure that create a sound wave are the result of differences in the velocities of air particles. Is this true or false?
ANSWER:
true
STEP-BY-STEP EXPLANATION:
The differences in air pressure that create a sound wave are the result of differences in the velocities of the air particles. Due to the Doppler effect, an observer will hear a sound that moves away from her and has a higher pitch. Sound waves will travel faster on a dry day than on a humid day of the same temperature.
Therefore, the statement is true
what is the formula of percentage uncertainty of volume, and percentage uncertainty of destiny، and percentage uncertainty of mass...
Take into account that for any repeated measurements, the formula of percentage uncertainty is given by the following formula:
[tex]\text{uncertainty}=\frac{half\text{ the range}}{Average\text{ reading}}\cdot100[/tex]Then, for the percentage uncertainty of density. mass and volume, just use the information about half the range and average reading for each magitude (volume, density and mass)
Consider that half the range is one half the subtraction between the maximum and minimum measurement:
[tex]\text{half the range=(max - min)/2}[/tex]the plastic spoon float because the upthrust is more than the weight of the metal spoon so the upthrust pulls it up to float. True OR False
The statement as it has been written in the question is false. This is because, the upthrust must be equal to the weight in order for the object to float.
What is the principle of floatation?The principle of floatation states that an object would float in water when the upthrust on the object is equal to the weight of the object. We know that the upthrust is the force that acts on an object thereby throwing it up. The weight is the force that tries to sink the object into the fluid.
Given the statements above, it is false that; the plastic spoon float because the upthrust is more than the weight of the metal spoon so the upthrust pulls it up to float.
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A ball is rolled uphill a distance of 5 meters before it slows, stops and begins to roll back. The ball rolls downhill 6 meters before coming to a rest against a tree. What is the ball's displacement?
We can calculate the displacement using the following formula:
[tex]\begin{gathered} \Delta x=x_f-x_i \\ Where: \\ x_f=Final_{\text{ }}position \\ x_i=Initial_{\text{ }}position \\ so: \\ \Delta x=6m-5m=1m \end{gathered}[/tex]Answer:
1 m
Suppose a 60.0-kg gymnast climbs a rope. (a) What is the tension in the rope if he climbs at a constant speed? (b) What is the tension in the rope if he accelerates upward at a rate of 1.50 m/s2?
Use the Newton's Second Law of Motion to find the tension in the rope on each case.
a)
Since the gymnast climbs at a constant speed, then the net force acting on the gymnast must be 0. Since there are only two forces acting on the gymnast, namely the tension of the rope and the weight of the gymnast, then:
[tex]\begin{gathered} F_N=T-W=0 \\ \Rightarrow T=W \end{gathered}[/tex]On the other hand, the weight of the gymnast is equal to the product of its mass times the acceleration of gravity, g=9.81m/s^2:
[tex]\begin{gathered} W=mg \\ =(60\operatorname{kg})(9.8\frac{m}{s^2}) \\ =588N \end{gathered}[/tex]Then, the tension of the rope is:
[tex]T=588N[/tex]b)
The forces acting on the gymnast are 2: the tension of the rope and the gravitational pull:
[tex]F_N=T-W[/tex]From the second law of motion, we know that the net force acting over an object of mass m produces an acceleration a given by:
[tex]F_N=ma[/tex]Then:
[tex]\begin{gathered} T-W=ma \\ \Rightarrow T=W+ma \end{gathered}[/tex]Substitute W=588N, m=60kg and a=1.50 m/s^2 to find the tension of the rope:
[tex]\begin{gathered} T=588N+(60\operatorname{kg})(1.5\frac{m}{s^2}) \\ =588N+90N \\ =678N \end{gathered}[/tex]Therefore, the answers are:
[tex]\begin{gathered} a)T=588N \\ b)T=678N \end{gathered}[/tex]why does air pressure decreases with height more rapidly in cold air than in warm air?
the colder air is more dense, then you would go through more mass (density) in a shorter vertical distance,
Explanation
Consider cold and warm air columns with equal weights, and equal amounts of overlying air.
Colder air is denser because the molecules of air are more closely packed together. As a result, pressure decreases more rapidly as you ascend through cold air than through warm air
It takes a shorter column of cold air to exert the same pressure as a taller column of warm air.
so,Since the colder air is more dense, then you would go through more mass (density) in a shorter vertical distance,
What happens when data stored digitally are copied?
OA. Each copy made has worse quality than the original data did.
B. Data are copied quickly, easily, and perfectly.
C. Only one value of the digital data is copied perfectly.
D. Data are copied quickly, but they decrease in quality.
When data stored digitally are copied then data are copied quickly, easily, and perfectly.
Data stored digitally are quickly, easily and perfectly copied.
There is no effect on the quality of the data.It just copies the data exactly as the source and it is same with any other file type. The quality would only decrease if the file is transcoded to a different format or to the same format with a different data stream.Data is a collection of quantities, photos or videos, signs or symbols, on which operations are performed by a computer, which can be stored and transmitted in the form of electrical signals and recorded on magnetic, optical or mechanical recording media.
When you copy (or transfer) a file of any type - JPG or TIFF or RTF or DOC or PSD or whatever, you won't lose any quality.Since no quality of the file is lost, copying a data is an easy, quick and a perfect process.
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According to the Law of Effect, in which scenario is the behavior likely to be repeated as a result of the reward?
a
An employee is promised a bonus when he leaves his job for each quarter during which he has the most sales.
b
An employee is promised a bonus at the end of the year if he has the most sales for the first quarter.
c
An employee receives a bonus at the end of the quarter for having the most sales for
week one in the quarter.
d
An employee receives a bonus at the end of the week for having the most sales that week.
Answer:
D. An employee receives a bonus at the end of the week for having the most sales that week.
Explanation:
Took the test
2x6573858493.8404? please
Answer:
13,147,716,987.681
if you multiply 2 by 6573858493.8404, you get 13,147,716,987.681
A planet has mass M and radius 2R.
a) Derive an expression for the escape speed from the planet.
b) A projectile of mass m is shot directly away from the surface of the planet at ⅓ of the escape
speed from the planet. Derive an expression for the maximum distance from the center of the
planet the projectile reaches, in terms of R. Simplify as far as possible. (Ignore the existence of
all other celestial objects.)
The escape velocity of the planet is [tex]\sqrt{gR\\}\\[/tex] when mass is M and radius is 2R.
In astronomy and space research, escape velocity refers to the speed at which a body can leave a gravitational field without being further accelerated. It is given be the expression ,[tex]v_{e} = \sqrt{2gR}[/tex]
Where, Ve is the escape velocity, g is gravity , and R is the radius of the earth.
If a planet has mass M and radius 2R then an expression for the escape velocity from the planet can be calculated as,
[tex]v_{e} = \sqrt{(2GM)/R[/tex]
Here, G is the gravitational force of the planet therefore Newton's law of gravitational force can be used as,
g = GM/R²
gR²= GM
Thus, with the help of above equations the escape velocity of the planet can be calculated when mass is M and radius is 2R i.e.
[tex]v_{e} = \sqrt{(2GM)/2R[/tex]
[tex]v_{e} = \sqrt{(2GR)/2R[/tex]
[tex]v_{e} = \sqrt{gR[/tex]
Therefore , the escape velocity of planet is equal to the root of gravity g and radius R .
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The carbon monoxide molecule (CO) consists of a carbon atom and an oxygen atoms separated by a distance of 1.13x10^-10 m, The mass mc of the carbon atom is 0.750 times the mass mo of the oxygen atom, or mc= -0.750mo , Determine the location of the center of the mass of this molecule relative to the carbon atom.
The location of the centre of the mass of the CO molecule relative to the carbon atom is 6.46 ×10⁻¹¹ m.
What is the centre of mass of the molecule?The Centre of Mass of that object is a position that is relative to an object or a system of objects. The average position of all parts of the system that are weighted to their masses is known as the Centre of Mass.
Given, the distance between the carbon and oxygen atoms, r = 1.13 ×10⁻¹⁰m.
The ratio of the mass of the carbon and oxygen:
Mc/Mo = 12/16 = 0.750
Consider that Xc is the position of carbon and Xo is the position of the oxygen atom in CO molecule.
The centre of the mass of the system is equal to the:
[tex]X_{co}=\frac{M_CX_C+M_OX_O}{M_C+M_O}[/tex]
[tex]X_{co}=\frac{(M_C/M_O)X_C+X_O}{M_C/M_O+1}[/tex]
As we are calculating the centre of the mass relative to the carbon atom.
Therefore Xc = 0 and Xo= 1.13 ×10⁻¹⁰m.
[tex]X_{CO} =\frac{1.13\times 10^{-10}}{0.750 +1}[/tex]
Xco = 6.46 ×10⁻¹¹ m
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A hollow, spherical shell with mass 2.00 kg rolls without slipping down a 33.0 ∘ slope.
Find the acceleration.
Find the friction force.
The acceleration of the spherical shell is determined as 6.37 m/s².
The friction force is 12.74 N.
What is the coefficient of friction of the surface?
The coefficient of friction of the surface is calculated as follows;
Fsinθ = μFncosθ
where;
F is the applied force on the spherical shellFn is the weight of the spherical shellmg(sin θ) = (μmg) cosθ
(sin θ) = μ cosθ
μ = sinθ/cos θ
where;
g is acceleration due to gravityθ is angle of inclination of the slopeμ = tan θ
μ = tan(33)
μ = 0.65
The acceleration of the spherical shell is calculated as;
a = μg
a = 0.65 x 9.8 m/s²
a = 6.37 m/s²
The frictional force is calculated as follows;
Ff = μmg
Ff = 0.65 x 2 x 9.8
Ff = 12.74 N
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A 7 lb bowling ball accelerates at a rate of 7 m/s2.
According to the given statement The new acceleration is 21 m/s².
The correct option is D.
What is an acceleration defined as?Any process where the velocity varies is referred to as acceleration. There are only two ways to speed up: changing your speed or changing your direction, or changing both. This happens because velocity entails both a speed and a direction.
Briefing:The initial force is F = mass x acceleration
F = 3.17515 kg x 7 m/s²
F = 22.23 N
When the net force is tripled, the new acceleration will be
3 x F =m x a'
3 x 22.23 = 3.17515 x a'
a' = 21.003 m/s²
The new acceleration is 21 m/s². The correct option is d.
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The complete question is -
A 7 lb bowling ball accelerates at a rate of 7 m/s². If the net force on the bowling ball is tripled, what will be its new acceleration?
a. 2.3 m/s²
b. 7 m/s²
c. 14 m/s²
d. 21 m/s²
Margie, who weighs 624 N, is standing on a bathroom scale that weighs 51.0 N.
With what magnitude force does the floor push up on the scale?
Answer:
675N
Explanation:
624 + 51 = 675N
as the floor exerts and an equal and opposite force.
What does the top pressure gauge in (Figure 1) read? Express your answer using two significant figures.
Digital manometers can be used to measure liquids, gases, and air, depending on the device. If the instruments have an internal memory, it works quite well.
What does the top pressure gauge indicate?Pressure Gauge in Psig Pressure as a percentage of the surrounding atmospheric pressure. The gauge pressure for this kind of pressure includes the pressure from the weight of the atmosphere because it is zero-referenced against atmospheric pressure.
These gauges typically have a measurement range of 0… 1 mbar to 0… 600 mbar and an accuracy class of 0.1 to 2.5. Although pressure gauges typically require very minimal upkeep, problems can happen.
Therefore, This tool can be used to measure pressure in a variety of locations. Measurements of negative pressure, overpressure, and differential pressure are all possible.
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How many hours would it take a plane to fly 1,500 miles if it was moving at a constant speed of 300 miles/hour. Include units!
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