A ball of mass m, at one end of a string of length L, rotates in a vertical circle just fast enough to prevent the string from going slack at the top of the circle. Assuming mechanical energy is conserved, the speed of the ball at the bottom of the circle is

Answers

Answer 1

The speed of the ball at the bottom of the circle when ball of mass m, at one end of a string of length L, rotates in a vertical circle is √Lg

The rate at which an object's distance traveled changes is measured by its speed. In terms of measurement, speed is a scalar, meaning it has magnitude but no direction. Speed is the rate at which an object moves over a given distance. a thing that travels at a high rate of speed and covers a lot of distance quickly. A slow-moving object, on the other hand, travels a comparatively short distance in the same amount of time when moving at a low speed. An object with zero speed is completely immobile.

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Related Questions

if the magnitude of the electric field due to the sphere at point p is ep, what is the magnitude of the field at point

Answers

The magnitude of the field at point is  1/4π∈od³ √q² d² + p²

E resulting from the dipole generated by charges at the very end.

Ex = Kp/d³ in x direction.

E due to the charge at center

Ey = Kq/d²

Net electric field is E = 1/4π∈od³ √q² d² + p²

"Distance. or quantity." is how magnitude. is simply. defined. It shows how an object moves when it is in motion, whether that movement is absolute, relative, or of a certain size. It serves as a way to describe something's size or scope. Magnitude is a term used in physics to describe either an amount or a distance. A force's strength is quantified by a number called its magnitude. Take a force of 10 N, for instance, in the direction of the east. The phrase "towards east" denotes a direction, and "10" represents the force's magnitude. The 'value' or 'amount' of any physical quantity is what is essentially meant by the term "magnitude." A automobile is travelling quicker than a bike, for instance, in terms of speed.

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The diameter of the solar system is 10 light hours. A spaceship crosses the solar system in 15 hours, as measured on earth. How long, in hours, does the passage take according to passengers on the spaceship? Hint:c1 light hour per hour.Previous question

Answers

According to the spaceship's passengers, the journey took 11.2 hours.

How long would it take to travel to the solar system's outermost point?

In reality, most of interstellar space is located within our solar system. Voyager 1 will need around 300 years to get to the inner edge of the Oort Cloud, and perhaps another 30,000 years to travel past it. The star that is currently closest to our solar system is Alpha Centauri.

Calculation:

The spacecraft will travel across in t = 15 hours.

Since this can be measured with a single clock at both locations, the time measured in S' frame is the correct time.

The velocity is :

v = 10lh /15 h

v = 2/3 c

Because Δt° = Δς

Δς = Δt√1 - β²

Δς = (15h)√1 - (2/3)²

Δς = 11.2 h

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a particle moving in a straight line with constant acceleration has a velocity of 3 ms-1 at one instant, and 5 seconds later, it has a velocity of 23 ms-1. The value of t is

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A particle has a velocity of 3 m/s at one instant and a velocity of 23 m/s after 5 seconds when it is travelling straight forward with constant acceleration, then t=5sec at a displacement of 65m.

Acceleration, which refers to the rate at which velocity varies over time in terms of both speed and direction, has a value of t of 5 seconds. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t).

Total distance (S) = 23-3 = 20

Here v=23, u=3, time = 5sec

acceleration a= (v-u)/t

a=(23-3)/5

a=(20/5)

a=4

Now S=ut+ (1/2 *a *[tex]t^{2}[/tex])

S = 3(5) + (1/2 * 4 * 25)

S= 15+50

S= 65

t= 5 sec (time doesn't change here only displacement changes).

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Water evaporating off a hot and a room-temperature surface?

Look at the pictures above and write a brief description of what is happening in each one on the molecular level.

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Answer: Hot and room temperature surface.

Explanation: from the picture the hot temperature surface has easy and loose intermolecular activity, there are more spaces between the molecules to escape. So, it is for the water molecules to evaporate faster which is directly propositional to the temperature. Simply when a water is boiled at 100 degrees that when the heat helps the molecules to evaporate fast through the steam. But when it is in the room temperature the molecules are slightly tightly packed to each other, that is the reason why molecules can't evaporate as fast as compared to the hot temperature. It mostly depends on the intermolecular bond and kinetic energy that helps the molecules to escape into the atmosphere.

 

When the current in a long, straight air-filled solenoid is changing at the rate of 3000 A/S, the voltage across the solenoid is 0.600 V. The solenoid has 1200 turns and uniform cross-sectional area 35.0 mm? Assume that the magnetic field is uniform inside the solenoid and zero outside, so the inductance formula L MAN/ 2/1 for a solenoid with N turns, uniform cross-sectional area A, and length 1, applies Part A What is the magnitude B of the magnetic field in the interior of the solenoid when the current in the solenoid is 3.00 A? Express your answer with the approppriate units. μΑ ? B= Value Units Submit Request Answer

Answers

The magnitude of B in the interior of the solenoid is 5 * 10⁻⁷ A/m.

Given that,

Rate of change of current = 3000 A/s

EMF induced ε = 0.6 V

Number of turns N = 1200 turns

Cross-sectional area A = 35 mm² = 35 * 10⁻⁶ m²

Current i = 3 A

We know the relation, ε = L* dI/dt

Making L as subject, L = ε / ( dI/dt )

Substituting the values, we have

L = 0.6 / 3000 = 0.0002 H

We know the relation between N, i, B and L as

N* B = L *i

Making B as subject, we have

B = L *i/N = (0.0002 * 3)/1200 = 0.0000005 A/m = 5 * 10⁻⁷ A/m

Thus, magnetic field in the interior of the solenoid is 5 * 10⁻⁷ A/m.

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(11.2) Describe the expanding steady state model. Describe an observation that would test the predictions of the perfect cosmological principle. Is the steady state model in conflict with present observations of the universe?

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In cosmology, the steady-state model is an alternative to the Big Bang theory of evolution of the universe. In the steady-state model, the density of matter in the expanding universe remains unchanged due to a continuous creation of matter, thus adhering to the perfect cosmological principle, a principle that asserts that the observable universe is practically the same at any time and any place
In the Big Bang, the expanding Universe causes matter to dilute over time, while in the Steady-State Theory, continued matter creation ensures that the density remains constant over time.
While from the 1940s to the 1960s the astrophysical community was equally divided between supporters of the Big Bang theory and supporters of the steady-state theory, it is now rejected by the vast majority of cosmologists, astrophysicists and astronomers, as the observational evidence points to a hot Big Bang cosmology with a finite age of the universe, which the steady-state model does not predict.

which of the following sets of conditions is true for an exothermic reaction that is spontaneous at all temperatures?

Answers

An exothermic reaction that is spontaneous at any temperature meets the following criteria. ∆H < 0 , ∆S > 0 , ∆G < 0

This is because G = H - T S, and since -T S is always negative, if H is negative and S is positive, then G will always be negative.

Exothermic reactions (H0) characterize combustion. Due to the additional rise in the amount of gaseous species (net gain of one mole of gas, S > 0), this specific reaction entails an increase in entropy. As a result, the reaction is spontaneous (G0) at all temperatures. The sign of G will always be negative when H is negative and S is positive, and the reaction will always be spontaneous at all temperatures.

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complete question: Which of the following sets of conditions is true for an exothermic reaction that is spontaneous at all temperatures?

(a)∆H < 0 , ∆S < 0 , ∆G < 0

(b)∆H > 0 , ∆S < 0 , ∆G < 0

(c)∆H < 0 , ∆S < 0 , ∆G > 0

(d)∆H > 0 , ∆S < 0 , ∆G < 0

(e)∆H < 0 , ∆S > 0 , ∆G < 0

a metal with a work function of 1.2 ev is illuminated by visible light with the full range of wavelengths, which we take to be 400 nm to 700 nm. What is the maximum kinetic energy, in electron volts, of the photoelectrons?

Answers

The maximum kinetic energy, in electron volts of the photoelectrons, is K.Emax = 1.8ev.

Solution:

E = Wo + K.Emax

= 3.10ev = 1.3ev + K.Emax

= K.Emax = 1.8ev

Kinetic energy is the energy that an object has when it moves. If you want to accelerate an object you have to apply a force. To add strength, we need our work. When the work is done, the energy is transferred to the object and it moves at a new constant speed.

Kinetic energy is the kinetic energy observable as the motion of a body particle or group of particles. All moving objects use kinetic energy. A person walking throwing a baseball crumbs falling from a table and charged particles in an electric field are examples of kinetic energy.

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4. If μs between a basketball shoe and a court is 0.56, and the normal reaction
force acting on the shoe is 350 N, how much horizontal force is required to
cause the shoe to slide?

Answers

mu sub s times N is the frictional force

which equals 196 N

so 196 newton force is required for the shoe to slide

Answer: 196 N

Explanation: The coefficient of static friction (μs) between two surfaces represents the maximum horizontal force that can be applied to an object before it begins to slide. The formula for calculating the required horizontal force to cause an object to slide is:

F = μs * N

where F is the required horizontal force, μs is the coefficient of static friction, and N is the normal reaction force acting on the object.

In this case, the required horizontal force to cause the basketball shoe to slide is:

F = 0.56 * 350 N

F = 196 N

So, a horizontal force of 196 N is required to cause the basketball shoe to slide on the court.

Colors seen on the cover of your physics book are due to color A) addition. B) subtraction. C) either of these D) neither of these.

Answers

Color subtraction produces the colours displayed on the cover of our physics book.

What is colour subtraction?

If the incident light and pigment colours are known, the colour subtraction approach can be a useful tool for predicting the ultimate colour appearance of an object. The complementary colour scheme can be used to identify the light colours that will be absorbed by a certain material. To identify the colours of reflected light (or transmitted light), subtract the incident light colours (if any are present). Thus, the colour appearance of the item may be predicted.

Color subtraction produces the colours displayed on the cover of our physics book.

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help me ! thank you!!!!!

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The horizontal force the student exerts on the boat is equal to 120 N toward in front of the boat. Therefore, option (A) is correct.

What is force?

Force acting on a body can be defined as the influence that changes the state of the object of motion or rest. The force's S.I. unit is Newton (N) and is a vector quantity.

Force acting on an object can change the direction as well as the speed of the moving object. The force can be determined from the mass (m) times acceleration (a) of an object.

F = ma

Given, the  mass of the student, m = 60 Kg

The acceleration of the student, a = 2.0 m/s²

The force acting on the boat can be calculated as follows:

F = ma

F = 60 ×2.0

F = 120 N

Therefore, the horizontal force is 120 N toward the front of the boat.

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a 450 g air-track glider attached to a spring with spring constant 8.00 n/m is sitting at rest on a frictionless air track. a 450 g glider is pushed toward it from the far end of the track at a speed of 150 cm/s . it collides with and sticks to the 450 g glider. What are the amplitude and period of the subsequent oscillations?

Answers

The amplitude and period of the subsequent oscillations 112.5 m/s

First the law of conservation of momentum,

(m1 + m2)*vf  =  m1*(vi)1 + m2*(vi)2

m1 = 450g

vi1 = 0

m2 = 450g

vi2 = 150 cm/s

(450 + 150)*vf = 0 + 450* 150

600*vf  = 67500

vf  = 112.5 cm/s = 112.5 m/s

An indicator of a periodic variable's change over a single period is its amplitude. When measured against a standard value, a non-periodic signal's amplitude is its magnitude. Amplitude has several definitions, all of which (listed below) depend on how much the extreme values of the variable deviate from one another. The amplitude of a periodic function is occasionally referred to as the phase in older writings. Peak amplitude is frequently employed in audio system measurements, telecommunications tests, and other applications where the measurand is a signal that oscillates above and below a reference value but is not sinusoidal. The greatest absolute value of the signal is this if the reference is zero; the mean value of the reference.

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current attempt in progress the term thermal radiation pertains to radiation emitted over the entire spectrum of electromagnetic radiation. at very long wavelengths. at intermediate wavelengths. at very short wavelengths. etextbook and media save for laterattempts: 0 of 2 usedsubmit answer

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Thermal radiation is electromagnetic radiation emitted from all matter that is at a non-zero temperature in the wavelength range from 0.1 μm to 100 μm.

Thermal radiation is electromagnetic radiation emitted from a material this is because of the warmth of the material, the characteristics of which depend upon its temperature. An example of thermal radiation is the infrared radiation emitted with the aid of a commonplace family radiator or electric heater.

Thermal radiation is electromagnetic radiation generated by means of the thermal movement of debris in the matter. Thermal radiation is generated when warmth from the movement of costs in the fabric is transformed into electromagnetic radiation. All count number with a temperature extra than absolute zero emits thermal radiation.

The heating electricity is emitted by using the radiator. Solar radiation. The mild electricity radiated with the aid of incandescent lamps. The emission of gamma rays.

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shown from above in (figure 1) is one corner of a rectangular box filled with water. a laser beam starts 10 cm from side a of the container and enters the water at position x. you can ignore the thin walls of the container.

Answers

The minimum length required is 17.91 m when a laser beam starts 10 cm from side a of the container and enters the water at position x.

The output laser consists of a number of very closely spaced, discrete frequency components (very narrow spectral lines) covering a moderately broad spectral range. The discrete components are called laser modes and the spectral range they occupy is approximately the fluorescent line width of atomic transition giving rise to the laser output.

Laser oscillations occur, when the wave within the cavity replicate itself after two reflections so that the electric fields add in phase. In other words, the mirrors form a resonant cavity and standing wave patterns are setup.

In most high power applications for material processing or medical surgery, the laser is used as a mean for transferring the energy to the target. Thus there is no importance for the longitudinal laser modes.

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calculate the work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of with the horizontal (see below). he exerts a force of 500 n on the crate parallel to the ramp and moves at a constant speed. be certain to include the work he does on the crate and on his body to get up the ramp.

Answers

The work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of with the horizontal  3.14 x 103 J.

We know that

F = w x d

given

d =4 m

mass of man = 85 kg

force exerted by man on block = 500 N

resolving mg will give mgsin\large \theta   and mgcos\large \theta

Ftotal = Fm  + 500

Ftotal =  mgsin\large \theta + 500  = 85x 9.8 x sin20  + 500 =  284.902 + 500  =  784.902 N

W = Ftotal x d =  784.902 x 4  =  3139.61 = 3.14 x 103 J

In physics, work is energy transferred to or from an object by applying a force along a displacement. In its simplest form, if the constant force is aligned with the direction of travel, it equals the product of the force and the distance traveled.

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Given the following code snippet, what is considered an argument(s)?def mystery(num1, num2) :result = num1 ** num2return resultmystery(10, 2)

Answers

Result = num1 ** num2, return result, mystery(10, 2) 10, 2. You can provide a function more information by using an argument.

What do the code snippet's arguments and parameters mean?

The variables used to define a function are known as parameters. They are variables that will be used in the function body and are present in the function signature. When we call a function, arguments are the real values that are supplied to it.

Which of the following describes how to write a function in Python correctly?

A function is defined in Python by using the def keyword, which is followed by the function's name, parentheses, and a colon. Make sure to indent with a tab or 4 spaces the following step, and then specify.

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a 1600kg car is traveling over a hill that has a radius of curvature of 25m. the car is slowing down as it goes over the hill. it slows down at a constant rate from a speed of 25ms to a speed of 10ms over a distance of 50m ending at the top of the hill. the net acceleration of the car at the top of the hill is most nearly
a. 5.3 m/s/s.
b. 9.3 m/s/s.
c. 4.0 m/s/s.
d. 26 m/s/s.
e. 6.6 m/s/s.

Answers

The net acceleration of the car at the top of the hill is most nearly is option A. . 5.3 m/s²

Acceleration is the rate of trade of the velocity of an object with appreciation to time. Accelerations are vector portions. The orientation of an object's acceleration is given by using the orientation of the internet pressure performing on that item.

Calculation:-

V² = U² - 2aS

a = U²- V² / 2S

  = 25² - 10² / 2 × 50

 = 625 -100/100

 = 525/100

 = 5.25 m/s² ≈  5.3 m/s²

Acceleration is the price at which speed modifications with time, in terms of every velocity and course. A thing or an item shifting in a instantly line is increased if it quickens or slows down. motion on a circle is extended despite the truth that the price is constant due to the fact the direction is usually changing.

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Special relativity would predict slow running, and General Relativity would predict fast running, of a clock at the top of a tower at the
equator

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The running of a clock at the top of a tower at the equator would be predicted by special relativity to be slow, and by general relativity to be fast.

The equator, which separates Earth's Northern and Southern hemispheres, is a circle of latitude with a radius of around 40,075 kilometers (24,901 mi). Halfway between the North and South poles, at 0 degrees latitude, is a fictitious line. Any other roughly spherical celestial body can likewise be referred to by this name.

The equator of a spinning spheroid, such as a planet, is the parallel (circle of latitude) where latitude is defined to be 0° in astronomical (3D) spatial geometry. It is a fictitious line that divides the spheroid into its northern and southern hemispheres and runs parallel to its poles. It is, in other words, the point at which the spheroid intersects the plane that is perpendicular to its axis of rotation.

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colligative properties are those that depend on the identity and not the concentration of the solute those that depend on the concentration and not on the identity of the solute those that depend on the identity and the concentration of the solute those that do not depend on the amount or identity of the solute

Answers

Colligative properties are those of solutions that are influenced by the volume of a nonvolatile solute dissolved in a solution but not by the nature of the solute. The correct option to this question is both b and c

When solute molecules are dissolved in a certain solvent, solutions are created as homogenous mixtures. These solutions have special characteristics that could be referred to as collaborative qualities. These include melting point depression, osmotic pressure, rising boiling point, and reducing vapor pressure.

These solute molecules have an impact on vapor pressure, freezing point, and boiling points.

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Complete question :colligative

property depends on _____.

a. the identity of the solute

b. the concentration of the solution

c. the number of solute particles dissolved in the solution

d. both a and b

e. both b and c

A kettle is rated as 2.3kW. A mass of 750g of water at 20oC is poured into the kettle.When the kettle is switched on, it takes 2.0 minutes for the H2O to start boiling. In a further 7.0 minutes, half of the mass of H2O is boiled away. Estimate for this water: The specific heat capacity, the specific latent heat of vaporization.​

Answers

The specific heat capacity of water, Cw is 4.6 J/g/K

The specific latent heat of vaporization of water, Cv is 2576 J/K

What is the amount of energy used by the kettle?

Electrical energy is defined as the product of electrical power in watts and time in seconds.

Mathematically;

Electrical energy = power * time

The amount of energy used by the kettle to boil the water is calculated below:

Energy used = 2.3 kW * 1000 W/kW * 2 * 60 s/min

Energy used = 276000 J

The specific heat capacity of water, Cw is determined as follows:

Energy = mass * Cw * temperature change

Cw = Energy / mass * temperature change

Cw = 276000 / 750 * (100°C - 20°C)

Cw = 4.6 J/g/K

The amount of energy used by the kettle to evaporate half the mass of the water is calculated below:

Energy =  2.3 kW * 1000 W/kW * 7 * 60 s/min

Energy used = 966000 J

The specific latent heat of vaporization of water, Cv is determined as follows:

Energy = mass * Cv

Cv = Energy / mass

Cv = 966000 / (750 * 0.5)

Cv = 2576 J/K

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what is a hockey stick graph? name three metrics that would fit this description

Answers

A hockey stick graph is a graphical representation of data that has a steep increase or decrease at a certain point, resembling the shape of a hockey stick.

This type of graph is often used to show a sudden change in a metric over time. Three metrics that might fit this description are:

Population growth: The population of a city or country might increase slowly over time and then suddenly accelerate, forming a hockey stick shape on a graph.Sales revenue: A company's sales revenue might increase slowly at first and then suddenly spike up when a new product is introduced or a marketing campaign is launched.Internet usage: The use of the internet in a country or region might increase slowly over time and then suddenly accelerate as more people gain access to the internet.

Other metrics that might fit this description include the adoption of a new technology, the spread of a disease, or the growth of a social media platform.

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Your camping buddy has an idea for a light to go inside your tent. He happens to have a powerful (and heavy!) horseshoe magnet that he bought at a surplus store. This magnet creates B = 0.15 T field between two pole tips 10 cm apart. His idea is to build a hand-cranked generator shown in Figure. He thinks you can make enough current to fully light a R = 1.0 ? lightbulb rated at 4.0W. That's not super bright, but it should be plenty of light for routine activities in the tent.
Crank 1.0 ?/4.0 w bulb
A. Find an expression for the induced current as a function of time if you turn the crank at frequency f. Assume that the semicircle has a radius of r = 5.0 cm and it is at its highest point at t = 0 s. Express your answer in terms of some or all of the variables B, R, r, f, t, and the constant ?.
B. With what frequency will you have to turn the crank for the maximum current to fully light the bulb?
C. Is this feasible? (Yes or no)

Answers

The equation for the induced current as a function of time when the crank is turned at frequency f is I = 2*pi*r2*B*Force(sin (2*pi*force*t))/R. You will need to turn the crank at a frequency of 540.54 Hz.

To completely illuminate the bulb requires the maximum current. Furthermore, this frequency is not practical. The current that results from electromagnetic induction is known as the induced current. The production of electric power relies heavily on electromagnetic induction. Several methods exist for producing this change, including altering the magnetic field's strength,

B, r, R, f, and t are words that describe induced current.

I = E/R = r2*B*2pi*force*sin(2*pi*force*t)/R

Max current Imax = 3.70*10-3 = Imax/3.70*10-3 P = I2/R

Imax = ((4)1/2)/2 AMP F = (2.3.70*10-3) = 540.54Hz

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identify the correct statement from the following. classical physics is valid for matter speeds larger than the speed of light classical physics is valid for object size smaller than microscopic objects classical physics is valid under weak gravitational fields all of these options none of these options

Answers

Classical Physics is normally concerned with matter and energy on the normal scale of observation, while modern physics is caring with the behavior of matter and energy under extreme conditions or on a very large or very small scale.

For example, atomic and nuclear physics studies matter on the tiny scale at which chemical elements can be identified. The physics of elementary particles is on an even smaller scale since it is concerned with the most basic units of matter.

Classical Physics is also known as high-energy physics because of the extremely high energies required to produce many types of particles in particle accelerators.

On this scale, regular, commonsense notions of space, time, matter, and energy are no longer valid.

Computational modeling is essential for quantum and relativistic physics.

Classic physics is considered the limit of quantum mechanics for a large number of particles.

On the other side, classic mechanics is derived from relativistic mechanics. Like, in most of the formulations from special relativity, a correction factor (v/c)**2 appears, where v is the velocity of the object and c is the speed of light.

For velocities much minute than that of light, one can neglect the terms with c2 and higher that appear.

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A hockey puck attached to a horizontal spring oscillates on a
frictionless, horizontal surface. The spring has force constant 4.50 N/m and the oscillation period is 1.20 s. (a) What is the mass of the puck? (b) During an oscillation, the acceleration of the puck has maximum magnitude 1.20 m/s^2. What is the amplitude of the oscillation?
Answers:
(a) 0.164 kg
(b) 0.0438 m = 4.38 cm

Answers

(a) The mass of the puck is 0.16 kg

(b)  The amplitude of the oscillation is 4.3 cm.

What is the mass of the puck?

The mass of the puck is calculated by applying the formula for the period of the oscillation.

T = 2π √ ( m /k )

T / 2π = √ ( m /k )

T² / 4π² = m/k

m = k ( T² / 4π² )

where;

k is the spring constantT is the period of oscillationm is mass of the puck

The mass of the puck is calculated as;

m = 4.5 ( 1.2² / 4π²)

m = 0.16 kg

The amplitude of the oscillation is calculated as follows;

a = ω²A

where;

ω is the angular frequencyA is the amplitude a is the maximum acceleration

ω = √ ( k /m )

ω² = k / m

from this equation "a = ω²A" make amplitude "A" the subject of the formula.

A = a / ω²

A = (a) / (k / m)

A = ( 1.2 ) / ( 4.5 / 0.16)

A = (1.2) / ( 0.03556)

A = 0.043 m = 4.3 cm

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Two balls of clay known masses hang from the ceiling on masslessstrings of equal length. They barely touch when both hang atrest. One ball is pulled back until its string is45o, the released. It swings down, collides withthe second ball, and they stick together. To determine theangle to which the balls wing to the opposite side, you need toinvoke:
A. Conservation of momentum
B. Conservation of mechanicalenergy
C. Both conservation of momentum andconservation of mechanical energy
D. Either, but not both.
E. These principles alone are not sufficientto find the angle

Answers

To determine theangle to which the balls wing to the opposite side, C. Both conservation of momentum and conservation of mechanical energy (option c).

Conservation of energy and momentum is one of the most important and useful principles in physics. Conservation of momentum states that if no external forces are acting on a system of bodies, the total momentum is always the same (conserved). Furthermore, if we can give a potential to all forces, whether external or internal, the total energy is also constant. This is the law of conservation of energy.

1.Conservation of energy to calculate the velocity of the first ball of clay by the time it descends:

mgh=1/2mu2

[calculate h by using h=L(1-cos45)]

2.Conservation of momentum to find out the final velocity of the balls of clay using:

m1u1+m2u2=(m1+m2)v

3.Conservation of energy to calculate the max height the balls of clay will go by using:

1/2(m1+m2)v2=mgh

Once you have h,

h=L(1-cosθ), solve for θ

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g two point charges q1 = 2.30 nc and q2 = -6.10 nc are 0.100 m apart. point a is midway between them; point b is 0.0800 m from q1 and 0.0600 m from q2 (figure 1). take the electric potential to be zero at infinity.for related problemsolving tips and strategies, you may want to view a video tutor solution of potential and potential energy.

Answers

The electric field is -641.25 volt, potential energy is -1.76x 10⁻³ J.

What is electric field ?

The term "electric field" or "electrostatic field" refers to the area surrounding an electric charge where stress or an electric force occur. A significant amount of tension might be produced in the area if the charge is of a big magnitude. The letter E is used to denote the electric field. Newtons per coulomb, or volts per metre, is the SI unit for the electric field.

What is potential energy ?

Potential energy is energy that is preserved or stored in a material or an item. The item or substance's position, organization, or condition determines the amount of stored energy. Consider it as energy with the "potential" to accomplish work.

Va = kq1/r1 + Kq2/r2

Va = 9 x 10/0.05 (2.3 x 10⁻⁹ – 6x 10⁹)

Va = -666 volt

Vb = 9x10⁹ (2.3x10⁻⁹/.08 – 6x10⁻⁹/.06)

Vb = -641.25 volt

Work done by electric field from b to a

W e = q(Vb-Va)  

W e = 3x10⁻⁹ (-641.25+666)

W e = 74.25x10⁻⁹ J

W e = qEd = 30x 10⁻⁹x 3.2x10⁴x.63

W e = 6.05x10⁻⁴ J

W e = -qEd cos 45

W e = -30x10⁻⁹x3.2x10⁴x2.6 cos 45

W e = -1.76x 10⁻³ J

Therefore, electric field is -641.25 volt, potential energy is -1.76x 10⁻³ J.

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The total horizontal distance traveled by the tennis ball during the entire time it is in the air is approximatelyA.23 m C.8.3 m B.17 m D.4.1 m.

Answers

The total horizontal distance traveled by the tennis ball during the entire time it is in the air is approximately: 23 m

What is horizontal distance?

It is the line drawn horizontally from the viewer's eye. If an item is above the horizontal level, the angle of elevation is the angle created between the line of sight and horizontal level.

As we know,

H = [u(y)]²/2 g

or, H = (6.1)²/20

or, H = 1.86 m ≈ 1.9 m

Total max height = 1.9 m + 9.8 = 11 m

H = [u(y)]²/2g

or, 11 = [u(y)]²/20

or, u(y) = 14.832 m/s

u(x) = 7.6 m/sec

Now, R = u²sin 2θ/g

or, R = [2 u(x) u(y)] /g

or, R = [2×(7.6 )×( 14.832 )] / 10

or, R = 22.54 m
or, R = 23 m

Correct option: A

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The position of an object at any time t is given by: s(t) = x4 + 21x3 + 17x2 + 4x + 33 1. Determine the velocity of the object at any time t. 2. Does the object ever stop changing its position?

Answers

Given [tex]s(t) = t^{4} + 21t^{3} + 17t^{2} + 4t +33[/tex]

The velocity of the object at time t is [tex]v(t) = 4t^{3} + 63t^{2} + 34t + 4[/tex]

We know that, velocity is change in position with respect to time.

Therefore, [tex]v(t) = \frac{d[s(t)]}{dt}[/tex]

And it is given that [tex]s(t) = t^{4} + 21t^{3} + 17t^{2} + 4t +33[/tex]

So, differentiating above equation with respect to time t, we get

[tex]\\v(t) = \frac{d[s(t)]}{dt}\\\\ v(t) = \frac{d[t^{4} + 21t^{3} + 17t^{2} + 4t +33]}{dt} \\\\v(t) = 4t^{3} + 63t^{2} + 34t + 4[/tex]

For the second part of the equation, we need to find out if acceleration ever becomes zero. If acceleration is zero, it means the will stop changing it's position.
Now, we know that acceleration is change in velocity with respect to time.

Therefore, [tex]a(t) = \frac{d[v(t)]}{dt}[/tex]

[tex]a(t) = \frac{d[4t^{3} + 63t^{2} + 34t + 4]}{dt} \\\\a(t) = 12t^{2} + 126t +34[/tex]

Since acceleration becomes zero at two values of time t, therefore we can say that it will stop changing position.
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a car starts from rest at a stop sign. it accelerates at 4.3 m/s2 for 6.4 s , coasts for 2.2 s , and then slows down at a rate of 3.5 m/s2 for the next stop sign.

Answers

The sum stop signs of the car that accelerates at 4.3 m/s² for 6.4 s, coasts for 2.2 s, and then slows down at a rate of 3.5 m/s² = 216.118 m.

Velocity and acceleration

Velocity is a vector quantity that shows how fast an object moves from one place to another. A vector quantity is a term that is intended for a quantity that has both value and direction, meaning that the determination of the value of that quantity is based on direction.

The equation is:

V = s/t

Acceleration is the rate of increase in speed in a certain time expressed in units of meters per second squared (m/s²).

The function of speed is to determine how fast an object goes at a certain distance and is measured based on a vector quantity. Conversely, acceleration serves to change the speed of an object that is moving.

The equation is:

α = v/t

The question is not complete, it should be:

How far apart are the stop signs?

We have,

Acceleration = 4.3 m/s²

t = 6.4 s

First, determine the distance (1)

It's start from rest, so v₀ = 0

s₁ = (v₀t)₁ + ½ (at)₁²

= 0 + ½ (4.3) (6.4)²

= 88.064 m

Next, the distance (2)

a₂ = 0 m/s²

s₂ = (v₀t)₂ + ½ (at)₂²

= 0 + 20.812

= 20.812 m

The last, the distance (3)

s₃ = (v₀t)₃ + ½ (at)₃²

= (27.52) (8.6) + ½ (-3.5) (8.6)²

= 107.242 m

So, the sum stop sign = 88.064 m + 20.812 m + 107.242 m

= 216.118 m

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Parallel rays of monochromatic light with wavelength 573 nm illuminate two identical slits and produce an interference pattern on a screen that is 75.0 cm from the slits. The centers of the slits are 0.640 mm apart and the width of each slit is 0.434 mm.If the intensity at the center of the central maximum is 4.90×10−4 W/m2 , what is the intensity at a point on the screen that is 0.710 mm from the center of the central maximum?
Express your answer to three significant figures and include the appropriate units.

Answers

From three significant figures, the intensity at a point on the screen 0.830mm from the center of the central maximum is I =  8.64 × 10⁻⁶ W/m².

And the appropriate units are [tex]Watts/meter^{2}[/tex].

Monochromatic Light:

Single-wavelength light sources are known as monochromatic lights, where mono stands for only one and chroma for color. Monochromatic lights are defined as visible light that falls within a specific range of wavelengths. It has a wavelength that falls within a constrained wavelength range.

Given,

         The wavelength of light; λ = 573 nm = 573 × 10⁻⁹ m

         Distance of interference from slits; R = 75 cm = .75 m

         Distance between the centers of slit; d = 0.640 mm = 0.00064 m

         Width of each slit; a = 0.434 mm = 0.000434 m

         Intensity at the central maxima; [tex]I_{o}[/tex] = 4.9 × 10⁻⁴ W/m²

         Distance of intensity from the center of the central maximum; y =                        0.710 mm = 0.00071 m

Let us first find the angle θ from the formula;

         tanθ = y/R

      tan θ = 0.00083/0.75

      tan θ = 0.001107

            θ = tan⁻¹0.001107

            θ = 0.06343        

     

θ is very small so

             ∅ = 2πdsinθ/λ

             ∅ = 7.7964 rad

Similarly, for the distance between the centers of the slit;

             β = 2πasinθ/λ

             β = 5.761 rad

For a position on the screen that is 0.830 millimeters from the center of the central maximum, the intensity is calculated as follows:

            [tex]I =I_{0}(cos^{2} \frac{\phi}{2} ) [\frac{sin\frac{\beta }{2} }{\frac{\beta }2}} ]^{2}[/tex]

            [tex]I=5*10^{-4}(cos^{2}(\frac{7.7964}{2} ) )[\frac{sin\frac{5.287}{2} }{\frac{5.287}{2}} ] ^{2}[/tex]

             I = 8.6 × 10⁻⁶ W/m²

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