When a parachutist opens her parachute after accomplishing terminal speed, in what path does she accelerate.
When a parachutist opens her chute, she slows down. That method she hurries up upward.Once the parachute is opened, the air resistance overwhelms the downward pressure of gravity. The internet pressure and the acceleration at the falling skydiver is upward.
A 500-N parachutist opens his chute and reports an air resistance pressure of 800 N. The internet pressure at the parachutist is. three hundred N upward (Air resistance exerts a pressure withinside the path contrary the path of the movement of the person. So, the internet pressure is 500 N down plus 800 N up, that is three hundred N up
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a thermistor is a temperature sensor that contains metallic wire that changes its electrical resistance when the temperature changes
A thermistor is a type of temperature sensor that uses metallic wire to modify its electrical resistance in response to variations in temperature. Temperature can be used to define a metal's resistance.
What are the different varieties of thermistors?The resistance of thermistors is significantly more temperature-dependent than that of conventional resistors. The words thermal and resistor are combined to form the word thermistor. The conduction model used to classify thermistors.
Why are thermistors used?A thermistor's basic task is to gauge a device's internal temperature. The thermocouple is a minor but crucial component of a bigger system in a temperature-controlled system. The thermistor's temperature is kept under observation by a controller.
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any theory of what will happen if two neutron stars collide next to a black hole?
Answer:
It is difficult to predict exactly what would happen if two neutron stars were to collide near a black hole, as the behavior of objects in the vicinity of a black hole is determined by a number of factors, including the mass, spin, and charge of the black hole, as well as the motion and composition of the neutron stars.
Explanation:
It is difficult to predict exactly what would happen if two neutron stars were to collide near a black hole, but some possible scenarios include:
If the neutron stars collide with sufficient energy, they could merge to form a larger neutron star or even a black hole. This could produce a powerful burst of gravitational waves and electromagnetic radiation, which could be detected by telescopes on Earth.If the collision does not have enough energy to create a new black hole or neutron star, the resulting debris could be swallowed up by the existing black hole. This could also produce a burst of gravitational waves and electromagnetic radiation, but it may be more difficult to detect due to the presence of the black hole.Ultimately, the exact outcome of such a collision would depend on a number of complex factors and would require detailed modeling to predict with any accuracy.
f the tolerance in the feature control frame applies to a feature of size and no material condition symbol is specified,
Form tolerances regulate the "form" of features and are frequently used as a size refinement, thus they do not need a datum reference.
Describe what you mean by a substance.The substance(s) from which a thing is created or composed: A long-lasting substance is stone. something that is utilized or created as crude or raw material: Paper is created using wood pulp as the main ingredient. any component component. a kind of cloth used to make dresses.
What kind of material is it?Metals, polymers, and ceramics have historically been the three main kinds of materials. Steel, fabric, and ceramics are a few examples. Typically, the sources, traits, and uses of these classes are very diverse.
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Egg #1 is thrown at a brick wall. Egg #2 is thrown at a pillow with the same speed as Egg #1. Both eggs end up at rest.
Which egg experiences a greater force?
Egg #1
Egg #2
O They experience the same force
Answer:
The answer is Egg #1. Egg #1 experiences a greater force.
when all forces on an object are balanced it is its natural tendancy of the object to include all that aply
When all individual forces acting upon an object are balanced, it is the natural tendency of the object to remain at rest or to continue moving at a constant velocity in a straight line.
This is known as Newton's first law of motion, which states that an object will remain at rest or in motion at a constant velocity unless acted upon by an external force.
If an object is at rest and all forces acting upon it are balanced, it will remain at rest. If an object is moving at a constant velocity in a straight line and all forces acting upon it are balanced, it will continue moving at that same constant velocity in a straight line.
On the other hand, if there is an imbalance of forces acting upon an object, the object will accelerate in the direction of the net force. For example, if there is more force acting to the right than to the left, the object will accelerate to the right.
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g consider the woman doing push-ups in the figure. she has a mass of 44.2 kg, and the distance from her feet to her center of mass is 0.87 m, while the distance from her feet to her hands is 1.7 m.
The mass is 0.87 m and the energy exchange is 215.33J for the woman doing exercises.
The torque skilled via way of means of the frame with out the angular rotation however actions because of the rotational movement of some other item in touch with it's miles referred to as a static torque. While commencing a door, the door does not do beneathneath torque, however the connected to the door and a wall undergoes angular rotation.
Here we have
m= 56.6 kgg= 9.8m/sh=0.76maxis =1.55ma)thinking about torque approximately foot Fr = 271.ninety six N approx 272for every handFr' = 272 / 2= 136 NTorqueFt = 1435.fifty five Nusing verbal exchange of energy w= Fd = 1435× 0.15 = 215.33J p= w/ t = 215.35× 25/60 = 89.7 wRead more about mass;
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Star S1 is moving away from us at a speed of 0.8c. Star S2 is moving away from us in the opposite direction at a speed of 0.5c. The speed of S1 as measured by an observer on S2 is:
Star S₁ is moving away from us at a speed of 0.8c. Star S₂ is moving away from us in the opposite direction at a speed of 0.5c.The speed of S₁ as measured by an observer on S₂ is 0.5c.
We are given that,
Star S₂ is moving away in the opposite direction at a speed = v =+0.5c
Star S₁ is moving away from us at a speed = u =+0.8c
Speed of light = c = 3 × 10⁸ m/s
So that we can calculate the speed of S₁ as measured by an observer on S₂ by the formula , (which is multiple of c)
u/c = [(u/c)- (v/c)]/[(1 -uv)/c²]
Putting the values in above equation we get,
u/c = [(0.8 -0.5)]/[1 - (0.8)(0.5)]
u = 0.5c
Therefore, the speed of S₁ as measured by an observer on S₂ would be 0.5c in a direction away from earth .
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14. Battery potential is 12 volts and current is 2.7 amps. What's the resistance?
Answer:
4.44 ohms
Explanation:
To find the resistance of a circuit, you can use Ohm's law, which states that the resistance of a circuit is equal to the voltage across the circuit divided by the current through the circuit. So in this case, the resistance would be 12 volts / 2.7 amps = 4.44 ohms.
NEED HELP PLS If you weigh 982 N on Earth, what would your weight be on the surface of Jupiter?
g = 9.8 m/s^2 on Earth's surface
g = 26.0 m/s^2 on Jupiter's surface
mass of the Earth is 6 x 1024 kg
mass of Jupiter is 1.9 x 1027 kg
radius of Earth is 6.4 x 106 m
radius of Jupiter is 7 x 107 m
Round your answer to the nearest whole number.
Answer:
2605 N
Explanation:
[tex]F_{Earth} = m g_{earth}[/tex]
[tex]F_{Jupiter} = mg_{jupiter}[/tex]
[tex]F_{Earth} = 982 N[/tex]
[tex]982 N = m (9.8 m/s^2)\\[/tex]
[tex]m = 982 N[/tex] ÷ [tex]9.8 m/s^2[/tex]
[tex]m = \frac{4910}{49}[/tex] kg
[tex]F_{Jupiter} = \frac{4910}{49} * 26 m/s^2[/tex]
[tex]F_{Jupiter} = 2605.30...[/tex] ≈ 2605 N
the speed of light in glass is group of ___answer choices: same as in a vacuum. smaller than that in air. unchanged from that in air. larger than that in air.
The speed of light in glass is SLOWER than that in air. Therefore, the correct answer is the second option: smaller than that in air.
The speed of light is a universal constant used and considered in many areas of physics. It is equal to 299,792,458 meters per second or 186,000 miles per second. That speed is measured in a vacuum.
Light travels faster in a medium that has a lower refractive index. Generally, the denser a medium is, the higher its refractive index is. Glass is obviously denser than air, which means it has a higher refractive index. Thus, light travels slower in glass than in air.
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in music, two notes are said to be an octave apart when one note is exactly twice the frequency of the other. suppose you have a guitar string playing frequency
The wave length will be cut in half (1/2) in order to raise the frequency up one octave to 2f0.
What does energy frequency mean?In conclusion, waves transport energy. Their frequency and amplitude both affect how much energy they transport. The amount of energy increases with frequency and amplitude, respectively.
Briefing:The given parameters;
initial frequency, = F₀
final frequency, = 2F₀
Let the initial wave length = λ₁
Let the final wave length = λ₂
The formula for the connection among frequency and wavelength is;
To attain a twofold frequency, the wave's length must be reduced as shown below;
The wave length will thus be cut in half (1/2) in order to raise the frequency up one octave to 2f0.
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A fully charged capacitor and a 0.22-H inductor are connected to form a complete circuit. If the circuit oscillates with a frequency of 2.9 ✕ 103 Hz, determine the capacitance of the capacitor. F
A complete circuit is created by connecting a completely charged capacitor to a 0.22-H inductor. 1.4 x 10⁻⁸ F is the capacitance of the capacitor if the circuit oscillates at a frequency of 2.9*10³ Hz.
C = capacitance
L = inductance = 0.22 H
f = frequency = 2900 Hz
using the formula
f = 1/(2[tex]\pi[/tex]√(LC))
2[tex]\pi[/tex] f = 1/√(LC)
inserting the values
2 x 3.14 x 2900 = 1/√(0.22 C)
C = 1.4 x 10⁻⁸ F
A capacitor is an electrical component with two terminals that has the ability to store energy in the form of an electric charge. Two electrical cables are used, and they are spaced apart. A vacuum or an insulating substance known as a dielectric can fill the gap between the conductors. The capacitor's capacitance is its capacity to hold charges.
By holding apart oppositely charged couples, capacitors store energy. A parallel plate capacitor has two metal plates with a space in between them and is the most basic type of capacitor design. But various capacitor types are made in a wide variety of shapes, sizes, lengths, girths, and materials.
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WILL MARK BRAINLIEST:
Which of these ALL require direction?
Displacement, Velocity, Force
Force, Time, Acceleration
Speed, Velocity, Distance
Mass, time, speed
Answer:
Force, Time, Acceleration
Explanation:
Displacement, velocity, and force do not necessarily require direction, but acceleration, which is the rate of change of velocity, does require direction. Speed, velocity, and distance do not require direction. Mass is a scalar quantity and does not have a direction. Time is also a scalar quantity and does not have a direction.
An electron is in a three-dimensional box. The x- and z-sides of the box have the same length, but the y-side has a different length. The two lowest energy levels are 2.16 eV and 3.37 eV, and the degeneracy of each of these levels (including the degeneracy due to the electron spin) is two. What are the n_X, n_Y, and n_Z quantum numbers for the first level?
The principal quantum numbers for the ground state are n(x) = n(y) = n(z) =1. The second level will be 3 fold degenerate and any of the last 3 options can be correct.
Four quantum numbers are present in atoms: the main quantum number (n), the orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms). In terms of an electron's energy and most likely separation from the nucleus, the primary quantum number, n, is used. It refers, in other words, to the size of the orbital and the energy level at which an electron is positioned. The orbital's shape can be expressed by the l subshells, or number of subshells. Counting the number of angle nodes is another usage for it. The energy levels in a subshell are described by the magnetic quantum number, ml, and the electron's spin, denoted
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A 5.0 kg object suspended on a spring oscillates such that its position x as a function of time t is given by the equation x (t ) = A cos(ωt ), where A = 0.80 m and ω = 2.0 s-1 . What is the magnitude of the maximum net force on the object during the motion?
The magnitude of the maximum net force that is exerted on the object is equal to 1.60 N.
The magnitude of the maximum net force on the object is equal to the magnitude of the spring force at the maximum displacement of the object. The spring force is given by Hooke's law, which states that the force exerted by a spring is proportional to the displacement of the spring from its equilibrium position. The proportionality constant is called the spring constant, k.
The spring force can be expressed as F = -kx, where x is the displacement of the spring from its equilibrium position.
In this case, the maximum displacement of the object is A, so the magnitude of the maximum net force on the object is |F| = |-kx| = |-kA|.
Plugging in the given values, we get |F| = |-kA| = |-k(0.80 m)| = |-k(0.80 m)| = |1.60 N|.
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in the sun and seasons simulation in module 2, you observed that, at the equator, there are 12 hours of daylight year-round, because the angle between the apparent path of the sun across the sky and the horizon is always
There are always 12 hours of daylight at the equator because the apparent path of the sun across the sky and the horizon are always perpendicular to one another.
The "almost" equal lengths of day and night are caused by the sun's rays being bent or refracted, making it appear that the sun is above the horizon when it is actually below it. In addition, because the sun rises and sets later at higher latitudes (those farthest from the equator), the days become a little longer there. As a result, the length of the day will vary from around 12 hours to several days before and after the equinox and six and one-half minutes at the equator.
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1. What is the largest wave on Earth? What is its wavelength, frequency, and period?
2. Is the wave a deep-water wave or a shallow-water? explain
1. The largest wave on Earth is a tsunami wave. It has a wavelength of up to 1000 kilometers, a frequency of 0.04 to 0.2 hertz, and a period of up to an hour.
2. Tsunami waves are deep-water waves, meaning that they originate in the deep ocean and move towards the shoreline. The wave energy is transmitted across the entire water column, and it is refracted as it approaches the coast. This refraction causes the wave to slow down and build in height, resulting in the massive waves we often see in news coverage.
a real heat engine working between heat reservoirs at 980 k and 630 k produces 700 j of work per cycle for a heat input of 2800 j .
Its thermal efficiency is 25%.
What is thermal efficiency?Thermal efficiency is the ratio of an engine's or machine's useful output energy to its total energy input. It is a measure of how well energy is converted from one form to another, and is expressed as a percentage. Thermal efficiency is an important factor in determining the cost-effectiveness of many energy systems such as engines, power stations and industrial processes. Increasing the thermal efficiency of a system can lead to significant cost savings and environmental benefits.
Thermal Efficiency = (Work Output / Heat Input) x 100
= (700 J / 2800 J) x 100
= 25%
Therefore, the thermal efficiency of the heat engine working between heat reservoirs at 980 k and 630 k is 25%.
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Complete questions as follows-
200 word and should plag free
a real heat engine working between heat reservoirs at 980 k and 630 k produces 700 j of work per cycle for a heat input of 2800 j . Its thermal efficiency is
semiconductor transistors can have different behavior depending on if the electrons have low or high mobility. the same conductivity can come from a small number of electrons with high mobilities or a low number of electrons with low mobilities.
While one charge service is dominant the conductivity of a semiconductor is at once proportional to the mobility of the dominant service. Mobility describes the relationship between the drift speed of electrons or holes and an carried out electric-powered subject in a strong.
In semiconductors excited electron movements from the valence band to the conduction band. This creates a free electron in the conduction band and a hole in the valence band. The electrons consequently have better mobility as they've won excitation strength and are similarly away from the place of impact of the nucleus.
At absolute zero (0 OKs), the electric conductivity of a semiconductor has a price of zero (i.e. the conductivity is at its minimal) while a metallic reveals its most electric conductivity at absolute zero; moreover, conductivity increases with the growth temperature in a semiconductor.
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You have arranged that the magnetic field in a particular region of space is due North with a value of 0.0100 T. An electron enters the field traveling to the West with a speed of 3.0 percent of the speed of light. As a result, the electron experiences a magnetic force which is upwards. (a) What is the strength of this magnetic force? Give your answer in femtonewtons. (NOTE: The prefix "femto" represents 10-15., ก็เ (b) What is the amount of the resulting acceleration of the electron? Get the mass of an electron from the inside back cover of your textbook. Give your answer in Pm/s2 (NOTE: the prefix "P" is for "peta", which represents 10) Pm/s2 (c) What will be the result of the acceleration that you have calculated in part (b)? The speed of the moving electron will change but its direction of motion will remain constant.. Both the speed and direction of the moving electron will change The direction of the moving electron will change but its speed will remain constant.
(a) [tex]F = qv*B[/tex]
[tex]= 1.602*10^{-19} *9*10^{6} *10^{-2}[/tex]
[tex]= 1.4410*10^{-14}[/tex]
[tex]= 14.41 femtonewton[/tex]
Hence, the strength of the magnetic force is 14.41 femtonewtons
(b) [tex]a = \frac{F}{m}[/tex]
[tex]= \frac{1.4418*10^{-14} }{9.10*10^{-31} }[/tex]
[tex]= 1.584*10^{16} m/s[/tex]
The amount of resulting acceleration of the electron is [tex]1.584*10^{16} m/s[/tex]
(c) Since direction of acceleration is perpendicular to the direction of velocity. Both speed and direction will change.
A magnetic field is a vector field that represents the effect of magnetism on moving charges, currents, and magnetic bodies. A charge moving in a magnetic field experiences a force perpendicular to its velocity and magnetic field.
The magnetic field is generated by the movement of the intrinsic magnetic moment and charge of elementary particles associated with their fundamental quantum property of spin.
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the 3.4 kg, uniform, horizontal rod in (figure 1) is seen from the side. what is the gravitational torque about the point shown?
The gravitational torque of the rod is 8.33N.m
According to the question,
the mass of the rod (m) is 3.4kg.
Force times distance equals torque.
Since the bar is uniform, you can imagine that the mass is evenly distributed 50 cm from either end at the centre.
Therefore, the torque at the 25-cm-diameter point would be defined as follows:
Where m is the object's mass, 3.4 kg, and g is the gravitational force, the equation for force equals mass times acceleration divided by mass.
g = 9.8m/s
The distance is expressed in meters.
Torque is determined by the product of force and distance.
Torque equals m (9. 8) x (0.25)
where
m is the mass
g is the gravitational force
h is the height
Torque = 3. 4 x (9. 8) x (0.25)
=> 33.2 x 0.25
=> 8.33N.m
The gravitational torque of the rod is 8.33N.m since torque = 8.33N.m.
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Note the correct question is in the diagram,
SITUANARIO: A sled with mass ms=20 kg is pulled horizontally across snow. The coefficient of kinetic friction between sled
and snow is uk1= 0.27. A penguin with mass mp=25 kg rides on the sled, as in the figure above. The coefficient of static
friction between penguin and sled is us2 = 0.68.
Determine the maximum horizontal force Fapp that can be exerted on the sled before the penguin begins to slide off the
sled. HINT: Draw separate FBD diagrams for the penguin and the sled.
The horizontal force that can be exerted on the sled before the penguin begins to slide off is equal to 312.7 N.
What is friction?Friction can be described as the force resisting the motion of solid surfaces, fluid, and material elements sliding against each other.
The weight of the sled, W₁= m₁g = 20(9.8) = 197 N
The weight of the penguin, W₂= m₂g = 25 (9.8) = 245 N
The total weight of the system, W = 197 + 245 = 442 N
The normal force on the penguin due to the sled is:
N₁= W₁= 197 N
The normal force of the whole system, N₂ = W = 442 N
The sliding acceleration, a = f₁/m₁
a = μ₂g
a = 0.68 ×9.8 = 6.67 m/s²
The total force in the x-direction can be written as:
[tex]F_x = F-f_2[/tex]
[tex]F = \mu_1W +\frac{W_2}{g}a[/tex]
F = (0.27) (442) + (442/9.8) (6.67)
F = 312.7 N
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the stellar spectral classification system used today depends primarily on which of the following parameters?
The temperature of the stellar photosphere, which is the outer layer that extends into the stellar surface, is a key factor in determining spectral types. A star's mass affects the star's actual temperature.
The hotter the star, which is likewise related to the colour of the star, the higher the mass. The Morgan-Keenan (MK) classification is the current system of classification. According to the following explanation, each star is given a spectral class using Roman numerals (from the earlier Harvard spectral classification, which excluded luminosity), as well as a luminosity class. A star's photosphere is its outer layer, where light is emitted. The word "light sphere" is formed from the words "light" and "sphere," referring to a sphere-shaped surface that appears to produce light.
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Is the expansion of different metals uniform?
The expansion of different metals is not uniform. Different metals have different coefficients of thermal expansion, which is a measure of how much a material expands when it is heated. This means that when two different metals are heated by the same amount, they will expand by different amounts.
For example, if a metal with a high coefficient of thermal expansion is heated by 10 degrees Celsius, it will expand by a larger amount than a metal with a low coefficient of thermal expansion that is heated by the same amount. This means that the expansion of different metals is not uniform, and will depend on the specific properties of each metal.
Additionally, the expansion of metals can also be affected by factors such as the initial temperature of the metal and the rate at which it is heated. This means that the expansion of a given metal can also vary depending on the specific conditions under which it is heated. Overall, the expansion of different metals is not uniform, and will depend on the specific properties and conditions of each metal.
Through a small window in a furnace, which contains a gas at a high temperature T, the spectral lines emitted by the gas molecules are observed. Because of molecular motions, each spectral line exhibits Doppler broadening. Show that the variation of the relative intensity I(2) with wavelength A in a line is given by me2(-Ao)2 2AT 10) ox exp where m is the molecular mass, c the speed of light, and Ag the mean wavelength of the line.
Variation of the relative intensity [tex]I(\lambda)[/tex] with the wavelength [tex]\lambda[/tex] in a line is given by [tex]$$I(\lambda) \propto e^{-\left(\frac{m c^2\left(\lambda-\lambda_0\right)^2}{2 k T \lambda_0^2}\right)}=\exp \left(-\left(\frac{m c^2\left(\lambda-\lambda_0\right)^2}{2 k T \lambda_0^2}\right)\right)$$[/tex]
As, for non-relativistic thermal velocities, the Doppler shift in frequency will be: [tex]$$f=f_0\left(1+\frac{v}{c}\right)$$[/tex]
where f is the observed frequency,
f_0 is the rest frequency,
v is the velocity of the emitter towards the observer
c is the speed of light.
As any volume part of the radiating body will have a distribution of speeds both toward and away from the observer, which will have the overall effect of widening the seen line.
If [tex]I(v)dv=P_v(v)dv[/tex] is the fraction of particles with velocity component v to (v+dv) along a line of sight
Then the value of the distribution of frequencies will be
[tex]$$I(f) \mathrm{d} f=P_f(f) \mathrm{d} f=P_v\left(v_f\right) \frac{\mathrm{d} v}{\mathrm{~d} f} \mathrm{~d} f$$[/tex]
where [tex]$v_f=c\left(\frac{f}{f_0}-1\right)$[/tex] is the velocity towards the observer corresponding to the shift of the rest frequency f0 to f.
So, we can write it as:
[tex]$$P_f(f) \mathrm{d} f=\frac{c}{f_0} P_v\left(c\left(\frac{f}{f_0}-1\right)\right) \mathrm{d} f$$[/tex]
As in the case of the thermal Doppler broadening, the velocity distribution is given by the Maxwell distribution:
[tex]$$P_v(v)=\sqrt{\frac{m}{2 \pi k T}} e^{-\frac{m v^2}{2 k T}} \mathrm{~d} v$$[/tex]
So,
[tex]$$P_f(f) \mathrm{d} f=\frac{c}{f_0} \sqrt{\frac{m}{2 \pi k T}} e^{-\left(\frac{m\left[c\left(\frac{f}{f_0}-1\right)\right]^2}{2 k T}\right)} \mathrm{d} f$$[/tex]
This can be simplified as
[tex]$$P_f(f) \mathrm{d} f=\sqrt{\frac{m c^2}{2 \pi k T f_0^2}} e^{-\left(\frac{m c^2\left(f-f_0\right)^2}{2 k T f_0^2}\right)} \mathrm{d} f$$[/tex]
While in the non-relativistic limit,
[tex]-\frac{f-f_0}{f_0} \approx \frac{\lambda-\lambda_0}{\lambda_0^2}.[/tex]
So, from above,
we will get:
[tex]$$I(\lambda) \propto e^{-\left(\frac{m c^2\left(\lambda-\lambda_0\right)^2}{2 k T \lambda_0^2}\right)}=\exp \left(-\left(\frac{m c^2\left(\lambda-\lambda_0\right)^2}{2 k T \lambda_0^2}\right)\right)$$[/tex]
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The correct questions may be like
Through a small window in a furnace, which contains a gas at a high temperature T, the spectral lines emitted by the gas molecules are observed. Because of molecular motions, each spectral line exhibits Doppler broadening. Show that the variation of the relative intensity [tex]I(\lambda)[/tex] with wavelength [tex]\lambda[/tex] in a line is given by [tex]$$I(\lambda) \propto \exp \left\{-\frac{m c^2\left(\lambda-\lambda_0\right)^2}{2 \lambda_0^2 k T}\right\}$$[/tex]
A block is initially sliding along a surface of negligible friction with a speed v0. A constant force F0 is then exerted on the block. Which of the following figures represents the situations in which the kinetic energy of the block will initially decrease? Select two answers.AThe figure presents a block on a horizontal flat surface. The block is moving to the right with a velocity v sub 0. A force, F sub 0, points upwards and to the right.BThe figure presents a block on a horizontal flat surface. The block is moving to the right with a velocity v sub 0. A force, F sub 0, points upwards and to the left.CThe figure presents a block on a horizontal flat surface. The block is moving to the right with a velocity v sub 0. A force, F sub 0, points downwards and to the right.DThe figure presents a block on a horizontal flat surface. The block is moving to the right with a velocity v sub 0. A force, F sub 0, points downwards and to the left.
Answer:b and d
Explanation:
cus they go opposite direction
ieee standard for ethernet - amendment 5: physical layer specifications and management parameters for 10 mb/s operation and associated power delivery over a single balanced pair of conductors
Provides additions and appropriate modifications to IEEE Std 802.3 to 10 Mb/s physical layer specification and management parameters for operation.
On a single balanced copper twisted pair and associated optional power delivery Add. A single-pair Ethernet standard intended to support speeds up to 10 Mbps, extend Ethernet range up to 1,000 meters, and provide multidrop capability. An Ethernet physical layer standard ratified by the IEEE in late 2019 as part of the 802.3cg specification.
A standard for Ethernet network technology that uses a thicker version of coaxial cable. It is capable of transmitting data at speeds of 10 Mbit/s over distances of up to 500 meters using baseband transmission. 10Base5 is also known as Thicknet ThickWire Thick Ethernet, Thick Coaxial Ethernet.
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PLEASE SOMEBODY HELP A moon of mass m orbits a planet of mass M in uniform circular motion with a constant tangential velocity. The distance between the center of the moon and the center of the planet is R. The gravitational field strength at the center of the moon is Gmoon. A satellite of mass m/5 is halfway between the center of the moon and the center of the planet. What is the gravitational field strength at the satellite?
Evaluate using:
Gsatellite = Gmoon * M / (R^2 + R^2/4)^(3/2).
Explanation:
The gravitational field strength at the satellite is given by the formula Gsatellite = Gmoon * M / (R^2 + R^2/4)^(3/2)
To find the value of Gsatellite, we need to know the values of Gmoon, M, and R. We are given the mass of the moon (m) and the mass of the planet (M), but we are not given the value of Gmoon or R. However, we can use the information provided in the problem to find the value of Gmoon.
The gravitational field strength at the center of the moon (Gmoon) is equal to the product of the mass of the planet (M) and the tangential velocity of the moon (v) squared, divided by the distance between the center of the moon and the center of the planet (R).
Since the moon is in uniform circular motion with a constant tangential velocity, we can use the formula for centripetal acceleration (a = v^2/R) to find the value of Gmoon. We know that the mass of the moon (m) is accelerating toward the center of the planet, so the centripetal acceleration of the moon (a) is equal to the gravitational field strength at the center of the moon (Gmoon).
We can use the formula a = v^2/R to find the value of Gmoon by substituting the values for a, v, and R into the formula. We are given the value of v (the tangential velocity of the moon), and we can use the formula for centripetal acceleration (a = v^2/R) to find the value of a.
We can substitute the value of a into the formula Gmoon = M * a to find the value of Gmoon. Once we have the value of Gmoon, we can substitute it into the formula Gsatellite = Gmoon * M / (R^2 + R^2/4)^(3/2) to find the value of Gsatellite.
Therefore, to find the gravitational field strength at the satellite, we need to find the value of Gmoon by using the formula Gmoon = M * a and the values of M, a, and R provided in the problem. We can then use the value of Gmoon to find the value of Gsatellite using the formula Gsatellite = Gmoon * M / (R^2 + R^2/4)^(3/2).
we are not yet capable of detecting life on planets around other stars. but as our technology develops, our first real chance of detecting such life will probably come from .
"We are not yet capable of detecting life on planets around other stars. But as our technology develops, our first real chance of detecting such life will probably come from examining spectral lines from the atmospheres of distant planets."
Astronomers can identify an element by its spectral lines, as well as its temperature and density within the star. The magnetic field of the star is also shown by the spectral lines. How quickly the material is travelling can be determined by the line's width. We can also learn about winds in the stars.
Infrared heterodyne spectroscopy allows astronomers to retrieve information about planetary atmospheres. In order to find moons and planets with atmospheres, it uses the infrared region of the spectrum.
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A loop of conductor is at rest on a table. A magnet is brought nearby directly above the loop. What is the direction of current flow (looking from above) in the following situations?
a) The north pole of the magnet points down and the magnet is moved down
clockwise
counterclockwise
no current flows
b) The north pole of the magnet points up and the table is raised
clockwise
counterclockwise
no current flow
c) The loop of wire is rotated clockwise about its center axis
clockwise
counterclockwise
no current flow
Answer:
In each of the given situations, the direction of current flow in the loop of conductor will depend on the relative motion of the magnet and the loop, as well as the orientation of the magnet.
a) In the first situation, the magnet is brought down directly above the loop, with the north pole pointing down. As the magnet is moved down, the magnetic field produced by the magnet will pass through the loop of conductor and generate a current in the loop. The direction of this current will depend on the orientation of the loop relative to the magnet. If the loop is oriented such that the current flows in a clockwise direction when viewed from above, the current will be in the clockwise direction. If the loop is oriented such that the current flows in a counterclockwise direction when viewed from above, the current will be in the counterclockwise direction.
b) In the second situation, the magnet is brought near the loop, with the north pole pointing up. The table is then raised, causing the magnet to move relative to the loop. As the magnet moves, it will generate a changing magnetic field that will induce a current in the loop. The direction of this current will depend on the orientation of the loop relative to the magnet, as well as the direction of the magnet's movement. If the loop is oriented such that the current flows in a clockwise direction when viewed from above, and the magnet is moving upward, the current will be in the clockwise direction. If the loop is oriented such that the current flows in a counterclockwise direction when viewed from above, and the magnet is moving upward, the current will be in the counterclockwise direction.
c) In the third situation, the loop of wire is rotated clockwise about its center axis. This will not produce a current in the loop, as there is no relative motion between the loop and the magnet, and therefore no changing magnetic field to induce a current. Therefore, in this situation, no current will flow in the loop.