A 5.0 kg block is pushed 2.0 m at a con-
stant velocity up a vertical wall by a constant
force applied at an angle of 30.0° with the
horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s2.
F
30°
2 m
5 kg
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.40, find
a) the work done by the force on the block.
Answer in units of J.

A C and D

C because ofc when electric charge flow electric field is produced

Answer:

A & D

Explanation:

Answer:

the last time i had my tempature taken was at disney prings about a week ago -_- they used one of those gun things that dont touch u and the SHOVED me forward so i guess i was fine

Explanation:

Answer:

thermometer

Explanation:

Answer:

4 joules

Explanation:

Answer:

the air is being stopped in the pocket of the parachutes theys why the parachute has a certain shape so that the air that gets caught inside of it as the skydiver goes down slows down the landing

Answer:

Density

Explanation:

Explaining the concept:

To explain this, we first need to know what density actually is:

Density is the mass of a given substance per unit volume, which means, that is the amount of mass present in unit volume (1 cm³ , 1m³)

Impure water is water, but with impurities added to it

Why is the density of Impure water is greater:

When we compare the mass of equal volumes of Water and Impure water, we will find that the mass of Impure water will be more, that is because the extra mass is of the impurities

Since impure water has impurities uniformly spread in it, we will find more matter in unit volume of Impure water than in Pure water

That is why the density of Impure water is greater

Answer:

C. its thermal energy increases

Answer:

Explanation:

C

Answer:

force acting on the parent = 25 N .

Explanation:

According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .

Answer is 25 N .

Explanation:

It's a transistor. Hope that helps!

Answer:

D. Transistor

Explanation:

Edge 2021

Answer:

8

Explanation:

Atomic number in the Bohr model given is 8.

For every atom, the atomic number is the number of protons in such an atom.

The protons are the positively charged particles found in an atom. They are called the atomic number.

Answer:

The value of the  magnetic field is [tex]B = 1.0*10^{-5} \ T[/tex]

The correct option is d

Explanation:

From the question we are told that  

    The magnitude of the electric field is  [tex]E = 3*10^{3} \ V/m[/tex]

     Generally the magnitude of  the magnetic field is mathematically represented as

        [tex]B = \frac{E}{c}[/tex]

Here  c is the speed of  light [tex]c = 3.0*10^{8} \ m/s[/tex]

=>     [tex]B = \frac{E}{c}[/tex]

=>      [tex]B = \frac{3.0*10^{3}}{ 3.0*10^{8}}[/tex]

=>      [tex]B = 1.0*10^{-5} \ T[/tex]

Answer:

1.898 × 10^27 kg

Explanation:

thats how much it ways

Answer:

301.48 J/s

Explanation:

We are given;

Temperature of the sky dropping to −40∘C: T_o = -40°C = -40 + 273 = 233 K

Temperature of your skin and clothes: T = 30°C = 30 + 273 = 303 K

Body surface area of human body is around 2 m². But here only half of the body is facing the sky, Thus Area is: A = 2/2 = 1 m²

To solve this, we will use the equation for thermal heat transfer known as the Stefan bolt Mann equation.

ΔQ/Δt = εσA(T⁴ - (T_o)⁴)

Where;

ΔQ/Δt is the rate at which you body loses energy by radiation

ε is the emissivity of the human body with a value of 0.97

σ is Stefan boltzmann constant with a value of 5.67 X 10^(-8) W/m².K⁴

Thus;

ΔQ/Δt = 0.97 × 5.67 X 10^(-8) × 1(303⁴ - 233⁴)

ΔQ/Δt = 301.48 J/s

The car accelerates with magnitude a such that

31.3 m/s = 25.6 m/s + a (5.4 s)

→   a = (31.3 m/s - 25.6 m/s) / (5.4 s) ≈ 1.056 m/s²

Then the applied force has a magnitude F of

F = (1430 kg) a ≈ 1500 N

Since vector B was not specified, I'll assume one at random. You can later answer your own question.

Answer:

[tex]\mid\mid \vec A+\vec B \mid \mid=\sqrt{105}[/tex]

[tex]\mid\mid \vec A-\vec B \mid \mid=\sqrt{149}[/tex]

Explanation:

Given:

[tex]\vec A=3\hat i +2\hat j+3\hat k[/tex]

And (assumed):

[tex]\vec B=-5\hat i +8\hat j-4\hat k[/tex]

Find the magnitude of

[tex]\vec A+\vec B[/tex]

[tex]\vec A-\vec B[/tex]

Given a vector

[tex]\vec P=x\hat i +y\hat j+z\hat k[/tex]

The magnitude of the vector is:

[tex]\mid\mid \vec P\mid \mid=\sqrt{x^2+y^2+z^2}[/tex]

[tex]\vec A+\vec B =3\hat i +2\hat j+3\hat k-5\hat i +8\hat j-4\hat k[/tex]

[tex]\vec A+\vec B =-2\hat i +10\hat j-\hat k[/tex]

The magnitude of the sum is:

[tex]\mid\mid \vec A+\vec B \mid \mid=\sqrt{(-2)^2+10^2+(-1)^2}=\sqrt{4+100+1}[/tex]

[tex]\mathbf{\mid\mid \vec A+\vec B \mid \mid=\sqrt{105}}[/tex]

[tex]\vec A-\vec B =3\hat i +2\hat j+3\hat k-(-5\hat i +8\hat j-4\hat k)[/tex]

[tex]\vec A-\vec B =3\hat i +2\hat j+3\hat k+5\hat i -8\hat j+4\hat k[/tex]

[tex]\vec A-\vec B =8\hat i -6\hat j+7\hat k[/tex]

The magnitude of the difference is:

[tex]\mid\mid \vec A-\vec B \mid \mid=\sqrt{8^2+(-6)^2+7^2}=\sqrt{64+36+49}[/tex]

[tex]\mathbf{\mid\mid \vec A-\vec B \mid \mid=\sqrt{149}}[/tex]

Given :

A 12 kg coyote runs towards a rabbit in the Ortega Mountains  with a velocity of 8 m/s.

To Find :

The momentum of the  coyote.

Solution :

The given in the question is mass of coyote which is 12 kg and velocity which is 8 m/s .

Momentum is given by :

M = mass × velocity

M = 12 × 8 kg m/s

M = 96 kg m/s

Hence, this is the required solution.

Answer:

F = 2389.603 N

Explanation:

Given:

Mass m = 1,369.4 kg

Initial velocity u = 28.9 m/s

Final velocity v = 20 m/s

Time t = 5.1 s

Find:

Net force

Computation:

a = (v - u)/t

a = (20 - 28.9)/5.1

a = -1.745 m/s²

F = ma

F = (1369.4)(1.745)

F = 2389.603 N

Answer:

poop bear cookie

Explanation:

Answer:

The location of the center of gravity of the fourth mass is [tex]\vec r_{4} = (-0.961\,m,-0.779\,m)[/tex].

Explanation:

Vectorially speaking, the center of gravity with respect to origin ([tex]\vec r_{cg}[/tex]), measured in meters, is defined by the following formula:

[tex]\vec r_{cg} = \frac{m_{1}\cdot \vec r_{1}+m_{2}\cdot \vec r_{2}+m_{3}\cdot \vec r_{3}+m_{4}\cdot \vec r_{4}}{m_{1}+m_{2}+m_{3}+m_{4}}[/tex] (1)

Where:

[tex]m_{1}[/tex], [tex]m_{2}[/tex], [tex]m_{3}[/tex], [tex]m_{4}[/tex] - Masses of the objects, measured in kilograms.

[tex]\vec r_{1}[/tex], [tex]\vec r_{2}[/tex], [tex]\vec r_{3}[/tex], [tex]\vec r_{4}[/tex] - Location of the center of mass of each object with respect to origin, measured in meters.

If we know that [tex]\vec r_{cg} = (0,0)\,[m][/tex], [tex]\vec r_{1} = (0,0)\,[m][/tex], [tex]\vec r_{2} = (0, 4.1)\,[m][/tex], [tex]\vec r_{3} = (1.9,0.0)\,[m][/tex], [tex]m_{1} = 6\,kg[/tex], [tex]m_{2} = 1.5\,kg[/tex], [tex]m_{3} = 4\,kg[/tex] and [tex]m_{4} = 7.9\,kg[/tex], then the equation is reduced into this:

[tex](0,0) = \frac{(6\,kg)\cdot (0,0)\,[m]+(1.5\,kg)\cdot (0,4.1)\,[m]+(4.0\,kg)\cdot (1.9,0)\,[m]+(7.9\,kg)\cdot \vec r_{4}}{6\,kg+1.5\,kg+4\,kg+7.9\,kg}[/tex]

[tex](6\,kg)\cdot (0,0)\,[m]+(1.5\,kg)\cdot (0,4.1)\,[m]+(4\,kg)\cdot (1.9,0)\,[m]+(7.9\,kg)\cdot \vec r_{4} = (0,0)\,[kg\cdot m][/tex]

[tex](7.9\,kg)\cdot \vec r_{4} = -(6\,kg)\cdot (0,0)\,[m]-(1.5\,kg)\cdot (0,4.1)\,[m]-(4\,kg)\cdot (1.9,0)\,[m][/tex]

[tex]\vec r_{4} = -0.759\cdot (0,0)\,[m]-0.190\cdot (0,4.1)\,[m]-0.506\cdot (1.9,0)\,[m][/tex]

[tex]\vec r_{4} = (0, 0)\,[m] -(0, 0.779)\,[m]-(0.961,0)\,[m][/tex]

[tex]\vec r_{4} = (-0.961\,m,-0.779\,m)[/tex]

The location of the center of gravity of the fourth mass is [tex]\vec r_{4} = (-0.961\,m,-0.779\,m)[/tex].

Answer:

[tex]\mathbf{\beta = 123.75 \ dB}[/tex]

Explanation:

From the question, using the expression:

[tex]125 \ dB = 10 \ log (\dfrac{I}{I_o})[/tex]

where;

[tex]I_o = 10^{-12} \ W/m^2[/tex]

[tex]I = 10^{12.5} \times 10^{-12} \ W/m^2[/tex]

[tex]I = 3.162 \ W/m^2[/tex]

This is a combined intensity of 4 speakers.

Thus, the intensity of 3 speakers = [tex]\dfrac{3.162\times 3}{4}[/tex]

= 2.372 W/m²

Thus;

[tex]\beta = 10 \ log ( \dfrac{2.372}{10^{-12}} ) \ W/m^2[/tex]

[tex]\mathbf{\beta = 123.75 \ dB}[/tex]

Answer:

Explanation:B

Answer:

c

Explanation: beacuse newtons law of phisics says ''what goes up must come down''

The force of gravity between any two ordinary objects on the earth is stronger if the objects are closer to each other.

The force of gravity between two object on the earth surface is given Newton's law of universal gravitation;

[tex]F= \frac{Gm_1m_2}{r^2}[/tex]

where;

The distance between the object is inversely proportional to the force of gravity between the objects. The smaller the distance between the two objects, the greater the force of gravity and vice versa.

Thus, we can conclude that the force of gravity between any two ordinary objects on the earth is stronger if the objects are closer to each other.

Learn more here:https://brainly.com/question/10609143

Answer:

F = 200 [N]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which can be calculated by means of the following equation.

[tex]P=m*v[/tex]

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now we must understand that the momentum is conserved before and after the firing of the cannon. Before firing the cannon we have the mass of the cannon and mass of the cannonball together at rest (speed = 0). After firing the cannon the cannonball moves forward with positive speed, while the cannon moves back (negative), in this way knowing the masses of each one we can determine the speed of the cannon.

[tex](m_{cannon}+m_{ball})*v_{1}=-(m_{cannon}*v_{2})+(m_{ball}*v_{3})[/tex]

where:

m_cannon = 2500 [kg]

m_ball = 2.5 [kg]

v₁ = 0 (velocity of the group before firing)

v₂ = velocity of the cannon after firing [m/s]

v₃ =  160 [m/s] (velocity of the cannonball after firing)

[tex](2500+2.5)*0 = -(2500*v_{2})+(2.5*160)\\v_{2}=0.16[m/s][/tex]

Now using the following equation of kinematics, we can calculate the acceleration.

[tex]v_{f}=v_{o}-a*t[/tex]

where:

Vf = final velocity = 0 (cannon comes to rest)

Vo = initial velocity = 0.16 [m/s]

a = acceleration [m/s²]

t = time = 2 [s]

[tex]0 = 0.16 - a*2\\2*a=0.16\\a = 0.08 [m/s^{2}][/tex]

With the value of acceleration, we can use Newton's second law which tells us that the forces acting on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force [N] (units of Newtons)

m = mass = 2500 [kg]

a = acceleration = 0.08 [m/s²]

[tex]F = 2500*0.08\\F = 200 [N][/tex]

Answer:

 F = 1.68 N

Explanation:

Let's solve this exercise in parts.

Let's use the concept of conservation of the mechanical nerve

initial

    Em₀ = 500 J

The energy is totally kinetic

     Em₀ = K = ½ m v₀²

     v₀ = [tex]\sqrt{\frac{2 Em_{o} }{m} }[/tex]

     v₀ = √ (2 500/32)

     v₀ = 5.59 m / s

now with kinematics we can find a space

      v² = v₀² - 2 a x

the negative sign is because the body is stopping

       a =[tex]( \frac{v_{o}^{2} - v^{2} }{2x} )[/tex]  

let's calculate

       a = (5.59² - 5.1²) / 2 50  

       a = 0.0524 m / s²

Finally let's use Newton's second law

     F = ma

     F = 32 0.0524

     F = 1.68 N

Answer:

Energy is a quantity that can be verticality from one to another,

sum of all the energy of the system remains constant if there is no friction force.

Explanation:

The potential energy of a system is a configuration energy, that is, for a given position the energy has a value with respect to a reference point.

Kinetic energy is an energy related to the movement of bodies, that is, a body must have a speed to have kinetic energy.

Energy is a quantity that can be verticality from one to another, the gravitational potential that a body has at a given height when the body is released accelerates by action of gravity, in this case the potential energy decreases and the scientific energy increases, It is appropriate to clarify that the sum of all the energy of the system remains constant if there is no friction force.

Ans    4 more to be exact

Explanation:

Given values are:

Spring constant,

and,

The force will be:

→ [tex]F = kx[/tex]

By substituting the values, we get

      [tex]= 40\times 10[/tex]

      [tex]= 400 \ N[/tex]

Thus the above answer is right.

Learn more about spring constant here:

https://brainly.com/question/15277652

Answer:

The value is  [tex]p = 0.7556 c[/tex]

Explanation:

From the question we are told that

   The speed at which galaxy B moves away from galaxy A is  [tex]v = 0.577c[/tex]

Here c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

     The speed at which galaxy C moves away from galaxy B is  [tex]u = 0.731 c[/tex]

Generally from the equation of  relative speed we have that  

     [tex]u = \frac{p - v}{ 1 - \frac{ p * v}{c^2} }[/tex]

Here p is the velocity at which galaxy C recede from galaxy A so

     [tex]0.731c = \frac{p - 0.577c }{ 1 - \frac{ p * 0.577c}{c^2} }[/tex]

=>   [tex]0.731c [1 - \frac{ p * 0.577}{c}] = p - 0.577c[/tex]

=>   [tex]0.731c - 0.4218 p = p - 0.577c[/tex]

=>   [tex]0.731c + 0.577c = p + 0.4218 p[/tex]

=>   [tex]1.308 c = 1.731 p[/tex]

=>    [tex]p = 0.7556 c[/tex]