A 2.600×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.9 mL . The density of water at 20.0∘C is 0.9982 g/mL.Part ACalculate the concentration of the glycerol solution in percent by mass.Express your answer to four significant figures and include the appropriate units.Part BCalculate the concentration of the glycerol solution in parts per million.Express your answer as an integer to four significant figures and include the appropriate units.

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the isomers, we have to check the formula [tex]C_4_H8[/tex] in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain But-1-ene.

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain Z-But-2-ene. When the methyls groups are placed on opposite sides we will obtain E-But-2-ene.

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain 2-Methylpropene.

See figure 1 to further explanations.

I hope it helps!

Answer:

ok

Explanation:

Element  %composition  Mol. mass  No. of C atoms  Simplest       Rounding

                                                                                           ratio             off  

C                     82.76                   12            6.89             1× 2                 2              

H                    17.24                      1              17.24              2.5× 2           5

Number of carbon atoms present =  

12

82.76

​  

=6.89

Number of hydrogen atoms present =  

1

17.24

​  

=17.24

simplest ratio =  

6.89

6.89

​  

=1  

simplest ratio =  

6.89

17.24

​  

=2.5

∴ Empirical fromula is C  

2

​  

H  

5

​  

Empirical formula mass= 2×12+5 = 29

∴ V.D. = 29

Mol. mass = 2 × V.D.

=58

n=  

Empiricalformulamass

Molecularmass

​  

=  

29

58

​  

=2

∴ Molecular formula = C  

4

​  

H  

10

​ pls mark me as braillant

Answer:

cure problems

pollution

purifying water

crop production

Explanation:

The reasons  for people to pursue discoveries in chemistry because it is the most important part of  daily life and related to the human health too.

Chemistry is a field of science which deals with the chemicals present in laboratory or in our environment o related to human body also.

Their are main 3 branches of chemistry that is organic and inorganic and physical chemistry some others are too like analytical chemistry industrial chemistry pharmaceutical chemistry.

Organic chemistry deals with the carbon compounds and hydrogen compound inorganic chemistry deals with the elements of periodic table and pharmaceutical makes medicines for human health care.

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Answer:

the average atomic mass in amu of X is 25.39 amu

Explanation:

The computation of the average atomic mass in the amu of X is shown below:

Average mass is

= Product sum + atomic mass of each and every isotope

Now the average mass

= (80.5 ÷ 100 × 25 amu) + (19.5 ÷ 100 × 27 amu)

= 20.125 + 5.265

= 25.39 amu

Hence, the average atomic mass in amu of X is 25.39 amu

The average atomic mass of X is 25.39 amu.

It is the quantity of matter present within an atom of an element.

Based on the given information,

• The unknown element X has the isotopes, 25X (80.5% abundant) and 27X (19.5% abundant).

Now the atomic mass of X can be calculated by using the formula,

[tex]=\frac{(M1*A1)+(M2*A2)}{A1+A2}[/tex]

Here, M1 and M2 are the atomic masses, and A1 and A2 are their  abundances.

Now putting the values we get,

[tex]= \frac{(25*80.5)+(27*19.5)}{80.5+19.5} \\\\= \frac{2012.5+526.5}{100} \\= \frac{2539}{100} \\= 25.39 amu[/tex]

Thus, the average atomic mass of X is 25.39 amu.

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Answer:

126g of H₂O

Explanation:

Electrolysis of water is:

2H₂O(l) → 2H₂(g) + O₂(g).

To know mass of water that reacted, we need to find moles of hydrogen and oxygen and, by using electrolysis chemical equation, we can determine moles of water and its mass, thus:

Moles hydrogen (Molar mass: 2.01g/mol):

14.0g H₂ * (1mol / 2.01g) = 6.97 moles hydrogen

Moles Oxygen (Molar mass: 32g/mol):

112.0g O₂ * (1 mol / 32g) = 3.5 moles oxygen

As 2 moles of hydrogen and 1 mole of oxygen are produced from 2 moles of water, and 7 moles of hydrogen and 3.5 moles of oxygen were collected, moles of water that reacted were 7 moles H₂O.

As molar mass of water is 18g/mol, mass of 7 moles of H₂O is:

7 mol H₂O * (18g / mol) =

Answer:

2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

1 mole of zirconium also 6.02×10²³ atoms.

Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.

There are 2.12 × 10²³ atoms of zirconium in 0.3521 mol of zirconium.

HOW TO CALCULATE NUMBER OF ATOMS:

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Answer:

D

Explanation:

science shows patterns and anomalies in how the world works

Answer:

There are [tex]5.408\times 10^{22}[/tex] grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater ([tex]m_{sw}[/tex]), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

[tex]m_{sw} = \rho_{sw}\cdot V_{sw}[/tex]

Where:

[tex]\rho_{sw}[/tex] - Density of seawater, measured in grams per liters.

[tex]V_{sw}[/tex] - Volume of seawater, measured in liters.

If [tex]V_{sw} = 1.5\times 10^{21}\,L[/tex] and [tex]\rho_{sw} = 1030\,\frac{g}{L}[/tex], then:

[tex]m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)[/tex]

[tex]m_{sw} = 1.545\times 10^{24}\,g[/tex]

The total mass of sodium chloride is determined by the following ratio:

[tex]r = \frac{m_{NaCl}}{m_{sw}}[/tex]

[tex]m_{NaCl} = r\cdot m_{sw}[/tex]

Given that [tex]m_{sw} = 1.545\times 10^{24}\,g[/tex] and [tex]r = 0.035[/tex], the total mass of sodium chloride in all the seawater in the world is:

[tex]m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)[/tex]

[tex]m_{NaCl} = 5.408\times 10^{22}\,g[/tex]

There are [tex]5.408\times 10^{22}[/tex] grams contained in all the seawater in the world.

Following are the calculation to the total mass of sodium chloride in grams:

Given:

Seawater volume[tex]= 1.5 \times 10^{21}\ L\\\\[/tex]

Seawater density [tex]= 1.03\ \frac{g}{mL}\\\\[/tex]

[tex]\%[/tex] of sodium chloride in seawater [tex]= 3.5\ \%[/tex]

To find:

The total mass of sodium chloride in grams=?

Solution:

The total volume of seawater [tex]= 1.5 \times 10^{21}\ L= 1.5 \times 10^{24}\ mL\\\\[/tex]

The density of seawater [tex]= 1.03 \frac{g}{mL}[/tex]

[tex]\therefore\\\\[/tex]

Seawater mass = Seawater volume [tex]\times[/tex] density

                           [tex]= 1.5 \times 10^{24}\times 1.03 \ g\\\\= 1.545 \times 10^{24}\ g\\\\[/tex]

[tex]\%[/tex] of sodium chloride in seawater [tex]= 3.5\ \%[/tex]

[tex]\therefore\\\\[/tex]

Calculating the sodium chloride mass in Seawater:

[tex]= 3.5\% \ \ of\ \ 1.545 \times 10^{24} \ g\\\\ =\frac{3.5}{100} \times 1.545 \times 10^{24}\ g\\\\= 5.4075 \times 10^{22} \ g\\\\[/tex]

Calculating the sodium chloride mass [tex]= 5.4075 \times 10^{22} \ g\\\\[/tex]

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Answer:

Density, [tex]d=24.68\ g/cm^3[/tex]

Explanation:

Given that,

Mass of marble slab is 38.6 kg or 38600 g

The dimensions of the slab is 23 cm × 17 cm ×4 cm

We know that the density of an object is given in terms of its mass volume as follows :

[tex]d=\dfrac{\text{mass}}{\text{volume}}\\\\d=\dfrac{38600\ g}{1564\ cm^3}\\\\d=24.68\ g/cm^3[/tex]

So, the density of the marble slab is [tex]24.68\ g/cm^3[/tex]

Answer:

Metalloids.

Explanation:

they're between the metals and non metals in the periodic table

Answer:

steel because water gold and honey is not a mixture of something

Answer:

Steel

Explanation:

Answer:

4.10x10⁻³g.

4.10 mg.

Explanation:

Hello,

In this case, considering the given number, we can see it has two digits after the first nonzero digit that is four (4) which is also at the third decimal place, it means that the scientific notation has a negative power as it is at the left of the given zeros, therefore it is:

4.10x10⁻³g.

Moreover, since the proper prefix for the factor x10⁻³ is milli, the number with prefix is:

4.10 mg.

Best regards.

Answer:

Increasing the temperature

Explanation:

Solids are usually found in low-temperature conditions. Increasing the temperature increases the energy in the solids, causing the solids to turn into a liquid state. Increasing the energy between molecules in a substance reduces the attraction force between the molecules and changes them from solid to liquid state.

Answer: pH = 4.3

Explanation: The pH of a buffer solution and its conjugate base can be determine by the Henderson-Hasselbach Equation. It can be estimated because equilibrium between weak acid and its conjugate base allows the solution to not change pH when small amounts of strong acid or base are added.

pH is calculated by:

[tex]pH = pK_{a} + log(\frac{[conjugate]}{[acid]} )[/tex]

pKa is the acidic dissociation constant and it shows how much strong an acid can be. It is determined as:

[tex]pK_{a}=-log(K_{a})[/tex]

For the buffer solution:

[tex]pK_{a}=-log(8.3.10^{-5})[/tex]

[tex]pK_{a}=4.081[/tex]

Calculating pH:

[tex]pH = 4.081 + log(\frac{0.480}{0.260} )[/tex]

[tex]pH = 4.081 + log(1.846)[/tex]

pH = 4.3

For this buffer solution and its conjugate, pH = 4.3

Answer:

A: rift

Explanation:

Divergent boundaries within continents initially produce rifts, which produce rift valleys.

Answer:

rift just did the quiz

Answer:

3CaBr2 + 2LI3PO4 - > Ca3(PO4) 2 + 6LiBr

Explanation:

The first one I did was PO4. There are two on the right side, so I added 2 to Li3PO4 on the other side. That balanced the PO4s and then gave me 6 Lithiums so I balanced that one next on the right side. I added 6 to LiBr which balanced the Li but then gave me 6 Br, so I finished it off by adding 3 in front of CaBr2 which balanced the calcium and bromines.

Here was the process:

CaBr2+2Li3PO4 -> Ca3(PO4)2+LiBr

Balances PO4 (2on both sides)

CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr

Balances Lithiums (6 on each side)

3CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr

Balances Calciums and Bromines (3 Calciums and 6 Bromines each side)

Hope this helped!

Answer:

The fuels or energy sources used for steam turbines include biomass, coal, geothermal energy, petroleum fuels, natural gas, nuclear energy, and solar thermal energy. Most of the largest electric power plants in the United States have steam turbines.

Explanation: I hope dis help you !

Answer:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

Explanation:

Answer:

E. All of the above statements are correct

Explanation:

   The gas equation given below and which we are familiar with relates to ideal gases  and not to real gases .

P V = R T

In this equation  , it has been assumed that gas molecules have no mutual attraction . They do not occupy any space ie they are very small in volume . But in reality , gas molecules do have mutual attraction and also they occupy some space. . Considering these facts , a new formula was given to replace the gas equation which is written below .

(P - a / V² ) ( V - b ) = R T   ,   a and b are constant and depend upon nature of gas involved .

This is called van der Waals equation . This is for one mole .

Here we see P of previous gas equation is replaced by P - a / V² .

That means pressure of real gas is less than the ideal gas . It is due to mutual attraction between any two gas molecules.  V of previous gas equation is replaced by V - b . That means volume of empty space has been reduced . It is due to the fact that real gas molecules occupy some space . Here b is dependent on the nature of the gas.

So all the statements are correct .

The van der Waals equation for real gases recognizes that  gas particles have non-zero volumes and interact with one another.

The ideal gas equation is used to describe the relation among the volume, pressure and temperature of an ideal gas. Recall that the ideal gas equation holds that there is no intermolecular interaction between gas molecules and that gas molecules occupy zero volume relative to the volume of the container.

The van der Waals equation for real gases recognizes that  gas particles have non-zero volumes and interact with one another.

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Answer:

0.499atm

Explanation:

The formula is

P1/V1 = P2/V2

so:

1.26atm/7.40L = P2/2.93L

then:

(1.26atm/7.40L)*2.93L = P2

= 0.4988918911atm

the answer must have 3 sig figs

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

Answer:

1) 1/√K

2) 1/K

3) √K

Explanation:

As general rules of operation of equilibrium constants:

For the reaction:

A + B ⇄ C + D; Equilibrium constant = K

C + D ⇄ A + B; K' = 1/K

2A + 2B ⇄ 2C + 2D; K'' = K²

Thus, as equilibrium constant of:

2CO2 + 4H2O ⇄ 2CH3OH + 3O2

Is K:

1) CH3OH + 3/2 O2 ⇄ CO2 + 2H2O

K' = 1 / K^(1/2) = 1/√K

2) 2CH3OH + 3O2 ⇄ 2CO2 + 4H2O

K' = 1/K

3) CO2 + 2H2O ⇄ CH3OH + 3/2 O2

K' = K^(1/2) = √K

Answer:

The reaction is endothermic.

Yes, absorbed

3.06x10¹kJ are absorbed

Explanation:

In the reaction:

2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ

As ΔH >0,

The reaction is endothermic

As the reaction is endothermic, when the reaction occurs,

the heat is absorbed.

Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.

72.8g are:

72.8g * (1mol / 216.59g) = 0.3361 moles HgO.

that absorb:

0.3361 moles HgO * (182kJ / 2 moles) =

Answer:

The figure is a molecule and a compound

Explanation:

Because it have 2 cluster molecules

Answer:

An energy transformation is the change of energy from one form to another. Energy transformations occur everywhere every second of the day. There are many different forms of energy such as electrical, thermal, nuclear, mechanical, electromagnetic, sound, and chemical.

Explanation:

Answer:

13.64.

Explanation:

Hello,

In this case, since the the specific gravity is computed as the ratio of the density of the given substance by the density of water that is approximately 0.997 g/mL as shown below:

[tex]s.g=\frac{\rho}{\rho _{water}}[/tex]

In such a way, for this case, we find:

[tex]s.g=\frac{13.6g/mL}{0.997g/mL}=13.64[/tex]

Which is dimensionless due the g/mL simplification.

Best regards.

The specific gravity of mercury is 13.61

Specific gravity is defined as the ratio of the density of a substance to the density of water. Mathematically;

[tex]sg=\frac{\rho_s}{\rho_{water}}[/tex]

Given the following parameters:

[tex]\rho_{Hg}=13.6g/mL\\\rho_{H_2O}=0.9998g/mL[/tex]

Substitute the given parameters into the formula;

[tex]sg=\frac{13.6g/mL}{0.9998g/mL}\\sg=13.61[/tex]

Hence the specific gravity of mercury is 13.61

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