The tension on the left wire 642N and the tension on right wire is 208N
Given that the force of scaffold is 200- N and the length of the scaffold is 18m
We need to find the tension in each wire
Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends
Here
∑ [tex]T_b=0[/tex]
∴ [tex]W_B(15m)+W_S(9m)-T_L(18m) = 0[/tex]
∴ [tex]T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N[/tex]
Hence the tension on the left side is 642N
∑[tex]T_a[/tex] = 0
[tex]T_R(18m)-W_B(3m)-W_S(9m)=0[/tex]
∴[tex]T_R =\frac{W_B(3m)+W_S(9m)}{18m}[/tex]
∴[tex]T_R = \frac{650(3)+200(+9)}{18}\\[/tex]
∴[tex]T_R = 208N[/tex]
Hence the tension on the right side is 208N
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A tank containing water has walls 2.50 cm thick made of glass of refractive index 1.550. Light from the outside air strikes the glass at a 41.3o angle with the normal to the glass. Find the angle the light makes with the normal in the water.
The normal in the water is 29.8°
Let
[tex]n_i=[/tex] the index of refraction for the material with incident light,
[tex]n _r[/tex] = the index of refraction for the material with refracted light,
[tex]\theta_i=[/tex] the angle of incidence
[tex]\theta_r[/tex] = the angle of refraction.
Applying Snell's law
[tex]n_isin\theta_i=n_rsin\theta_r[/tex]
Given
[tex]n_a=1, n_g=1.550, n_m=1.329n[/tex]
a)
From air to glass
[tex]n_a sin\theta_1[/tex][tex]=n_gsin\theta_2[/tex]
[tex]1\\sin *41.3 = 1.550 *sin\theta_2[/tex]
A normal from glass to water
[tex]n_g sin\theta_2 =n_m sin \theta_3 \\1.550\cdot\sin25.2\degree=1.329\cdot\sin\theta_3\\1.550*sin25.2=1.329*sin\theta_3 \\\theta_3=\arcsin({1.550\cdot \sin25.2\degree \over 1.329})\\\approx29.8\theta_3 =arc sin( 1.3291*550*sin25) ≈ 29.8[/tex]
Hence the normal in the water is 29.8°
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April is moving into a new apartment. She is moving a box of books that has a mass of 30 kg.
a. What is the weight of the box? (2 points)
b. What is the normal force acting on the box when it sits on the floor? Explain how you found the answer. (2 points)
c. If she pushes on the box with a force of 100 N and there is no friction, what is the acceleration of the box? (2 points)
d. If the coefficient of static friction between the box and the floor is 0.3, what is the maximum force of static friction acting on the box? (2 points)
e. How hard must she push on the box to get it to slide? (2 points)
f. If she pushes on the box with a force of 100 N, and the coefficient of kinetic friction is 0.25, what is the net force on the box in the x-direction? (2 points)
g. Based on your answer to part (f), what is the acceleration of the box? (2 points)
The weight of the box is 300 newton whereas the acceleration is 3.3 m/s2.
What is the weight of the box?The weight of the box is 300 newton because weight is a force which move towards the center of the earth due to gravity and we know that gravity is 10 m/s2.
What is the acceleration of the box?The box is moving with 3.3 m/s2 if we put in the formula below.
acceleration= force/mass
A = 100/30
A = 3.3 m/s2
So we can conclude that the weight of the box is 300 newton whereas the acceleration is 3.3 m/s2.
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can someone answer this pls
Answer:
See below
Explanation:
The vertical force in the R cable must equal the vertical force of the weight (since there is no vertical force in the L cable)
f sin30 = 150 then f-right = 300 N = L tension
The horizontal forces in the L and R cables must match
Horizontal : f-right = f-left = 300 cos 30 = 259.8 N = L tension
From your results on page 29, decide whether you are able to demonstrate that the masses of the 4 different baskets differ meaningfully. That is, do the baskets' masses differ by more than the range of measurement error that was obtained by repeatedly measuring the mass of one basket?
Yes, it was demonstrated that the masses of the 4 different baskets differ meaningfully.
If we compare the two ranges, the differences are significant because the error range for the same basket was less than the differences between different baskets.
The Error range is a measurement of the degree of uncertainty attached to a number and is defined as the difference between the greatest and lowest error values.
So, Yes the baskets masses differ by more than the range of measurement error that was obtained by repeatedly measuring the mass of one basket.
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A simple harmonic oscillator has an amplitude of 3. 50 cm and a maximum speed of 26. 0 cm/s. What is its speed when the displacement is 1. 75 cm?.
0.22 m/s is the speed when the displacement is 1.75 cm.
Given:
A simple harmonic oscillator has;
Amplitude (A) =3.50 cm = 0.035 m
Maximum Speed (Vmax) = 26.0 cm/s = 0.26 m/s
Displacment (d) = 1.75cm =0.0175 m
The displacement d, whose maximum is the amplitude A , is expressed as:
∴ d = A Sin wt
[tex]\frac{d}{A}[/tex] = Sin wt
t = [tex]\frac{1}{W}[/tex] Sin⁻¹ ( [tex]\frac{d}{A}[/tex] )
v = - Aw cos wt
v = - Aw cos w [ [tex]\frac{1}{W}[/tex]sin⁻¹ ([tex]\frac{d}{A}[/tex]) ]
v = - Aw cos [ sin⁻¹ ([tex]\frac{d}{A}[/tex]) ]
Speed, v = Vmax cos [ sin⁻¹ ([tex]\frac{d}{A}[/tex]) ] ∵ Vmax = Aw
v = 0.26 cos [ sin⁻¹ ( [tex]\frac{0.0175}{0.035}[/tex]) ]
v = 0.22 m/s
Therefore, 0.22 m/s is the speed when the displacement is 1.75 cm.
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Some people say the risk of hiv transmission from a healthcare provider (doctor, dentist, nurse, technician) is small. true or false? why?
Answer:. True
Explanation:
The risk of becoming infected from contact with an HIV-positive healthcare provider is indeed remote. The Centers for Disease Control and Prevention (CDC) have recommended the use of universal precautions by healthcare providers to minimize the risk of transmitting many infectious diseases, including hepatitis and HIV. The risk of transmission from patient to healthcare provider is far greater than from provider to patient.
"Some people say the risk of hiv transmission from a healthcare provider is small."
That statement is True. Because ...
There is NO statement on which public opinion is unanimous.
It can be something as innocuous as "The sky is blue during the day and rain makes the ground wet.", and you will never get 100% of the people to agree on it. There will still be some people who say it's True and others who say it's False.
And plus ... In this particular case, we're talking about a public health question. In today's political and cultural environment, marked by anti-science tendencies, a lot of people think that Science is not being truthful with us, it's all a big conspiracy, we are all being misled, and every individual should have the freedum to decide for himself. So when it comes to talking about something like the risk of HIV transmission, everybody is his own expert. Some will say the risk of transmission from a healthcare provider is substantial, and the rest will say it's small.
So the long sentence in the question is True. Some people do indeed say that.
PLEASE HELP!!!!
What is intelligence?
the emotional abilities of an individual to learn from experience, and to cope effectively with the demands of daily living
the ability to score well on standardized tests,
the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living,
how quickly an individual can reduce or eliminate stress
Answer:
the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living
Explanation:
Yes that can be understood by a simple example
Suppose two people are in exam
A difficult and logical question cameThe person can use his cognitive abilities faster can solve that[tex]\large\longrightarrow [/tex] Intelligence is the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living.
A source generates 40 waves per sec. if the wavelength is 8 cm. calculate the time waves takes to reach a wall 120m from the source?
Answer:
37.5 Seconds
Explanation:
Speed = frequency * Wavelength
We can find the Frequency by the information given, Frequency = waves per second .
40 Waves per second, = 40 Hz
Wavelength = 8cm
Cm = M
8cm/100 = 0.08m
Speed = 40 Hz * 0.08m
Speed = 3.2m/s
Speed = Distance / time taken
Time = Distance / Speed
Time = 120 / 3.2
Time = 37.5 seconds
The comet-hunting astronomer who made a list of over 100 nebulae and galaxies that could be mistaken for comets was Group of answer choices
An Astronomer who made a list of 100 nebulae and galaxies that could
be mistaken for comets was Charles Messer's.
Charles Messier's was a very famous scientist in the field of Astronomy.
His research in appearance of Great comet filled spark to his passion
of Astronomy. On January 21, 1759 he put his thought of wrong
calculation of Delisle's and he described a faint glow resembling comet
had been seen earlier. Then after, he discovered great comet near
sword of Orion.
There are various tales of Charles Messiers which put him forward
towards his love of Astronomy.
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12. A 2-kg soccer ball has a recorded acceleration of 30 m/s² after it is
kicked. What was the force of the kick?
Ο Α.Ο.Ν
OB. 15 N
OC. 30 N
OD. 60 N
1 point
what is magnetic shielding?
A weeping willow tree has hard stem from which branches and leaves grow.Its roots griw long.What function of the stem and roit do the sentences describe?
Answer:
The weeping willow is a gentle, graceful tree, but willow tree roots are very shallow and invasive. This means it's not the best backyard tree option for many
Explanation:
An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 201 m/s2 . What is the direction of the electric field
The force on a charge in an electric field is E = 1*10^-9 N/C.
F = QE
and according to newton's second law, the acceleration the charge will undergo is :
a = F / m
Putting these two equations together we get
E = m/q
For an electron with mass m= 9.11*10^-31 kg and charge Q= 1.60*10^-19 C.
E = 9.11*10^-31 kg / 1.60*10^-19 C
E = 1*10^-9 N/C.
Electric discipline, electric-powered assets associated with each point in space when the price is present in any form. The magnitude and direction of the electrical subject are expressed with the aid of the value of E, called electric area power or electric powered discipline intensity or certainly the electrical area.
An electric-powered discipline is a place of the area around an electrically charged particle or objects wherein an electric charge might feel pressure. An electric-powered field is a vector amount and can be visualized as arrows going towards or far from expenses.
Examples of electric fields consist of the field produced in the dielectric of a parallel-plate capacitor (which creates an electrostatic discipline) and the electromagnetic wave produced by a radio broadcast monopole antenna (which creates a time-various area)
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YALL PLEASE HELP QUICK!!!!!!!11!!!1!!1
4.16 Lab Report
Motion and Forces
Introduction
1. What was the purpose of the experiment?
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for each part of the experiment.
3. Write a hypothesis based on observations and scientific principles.
Experimental Methods
1. What tools did you use to collect your data?
2. Write your procedure. List each step so that another student could follow the procedure and repeat your experiment.
Data and Observations
1. Record your observations.
Conclusions
1. What conclusions can you draw about how the sum of forces acting on an object affect its motion? Write an evidence-based claim.
2. Which mass, A, B, or C, was the greatest? Use the observations from your experiment and your knowledge of Newton’s laws of motion to write an evidence-based claim.
The purpose of the experiment is to describe how the plasma membrane contributes to how the cell functions.
How to explain the experiment?The dependent variable is the variable bring investigated. In this case, the dependent variable is the egg circumference.
The independent variable is the variable controlled by the researcher.
The controlled variable has no influence on the results. An example is the concentration of vinegar.
A hypothesis is a proposition which can be tested by observations. In order to form a hypothesis, it's important to collect observations about the problem being examined.
The tools that can be used to collect data include observations and records taken.
The procedure to collect the data include:
Determine the information be collected.Set a timeline for the collection of data.Determine the method to utilize for data collection.Analyze the data.Implement the findings.The conclusions that can be drawn about how the sum of forces acting on an object affect its motion is that when the forces cancel out, then the resultant force will be zero, if not, the unbalanced force will result in the acceleration of the object.
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In order to relieve excessive pump pressure in an engine's internal oil system, most engines are equipped with a
Answer:
A-Oil pressure relief valve.
The accepted value for the speed of sound is around 340 m/s. What are some reasons your value may be a little different from the accepted value
Answer:
The speed of sound depends on the medium thru which it travels in contrast to light (electromagnetic) which can travel thru a vacuum.
The speed of sound will depend on the density of the air thru which it travels - the density of air is particularly affected by
humidity - water vapor in the air contributes to less density
temperature - warmer is less dense
motion of air - if the air is not motionless the speed will be affected
There are a few reasons why the value for the speed of sound may be a little different from the accepted value of 340 m/s such as the temperature and humidity of the air, the presence of other gases, and the shape of the object.
The temperature of the air: The speed of sound increases as the temperature of the air increases. So, if you measure the speed of sound in air that is warmer than 20 degrees Celsius, your value will be slightly higher than 340 m/s.
The humidity of the air: The speed of sound decreases as the humidity of the air increases. So, if you measure the speed of sound in air that is more humid than 0%, your value will be slightly lower than 340 m/s.
The presence of other gases: The speed of sound is slightly different in different gases. So, if you measure the speed of sound in a gas other than air, your value will be different from 340 m/s.
The shape of the object: The speed of sound is slightly different in different shapes of objects. So, if you measure the speed of sound in an object that is not a sphere, your value will be slightly different from 340 m/s.
In addition to these factors, there are also some experimental errors that can contribute to a difference between the actual value and the accepted value. These errors can be caused by things like inaccurate measurements of the distance or the time, or by small variations in the experimental setup.
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When encountering a powerboat in darkness or reduced visibility, what do visible white and red lights indicate?.
A visible white and red light indicate a second craft is coming from the starboard (right) side.
What is a navigation light?A navigation light often referred to as a running light or position light, is a source of illumination aboard a ship, plane, or spacecraft that provides information about the location, course, or condition of the vehicle. Red and green navigation lights help with traffic control by indicating the orientation of the craft.
All navigation light systems typically comprise one or more white lights as well as red and green sidelights that designate the boat's port and starboard sides.
Having a flashlight on board is also essential since you never know when a navigation light may go out.
The typical navigational lights:
SidelightsSternlightMasthead lampoverall white lightingSidelights: Because they are visible to other vessels approaching from the side or head-on, these red and green lights are sometimes known as combo lights. The port (left) and starboard (right) sides of a ship are indicated by the red and green lights, respectively.
sternlight: Only from behind or almost behind the ship can one see the sternlight.
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Which term below describes the amount of force exerted on a given area?
O A. Density
OB. Heat
OC. Temperature
OD. Pressure
The term above which describes the amount of force exerted on a given area is pressure
However, pressure is derived quantity.
What are derived quantities?
Derived quantities are those quantities which are obtained from the combination of fundamental quantities either by addition, division or multiplication
In conclusion, the term above which describes the amount of force exerted on a given area is pressure
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Pressure is the term which describes the amount of force exerted on a given area and is denoted as option D.
What is Pressure?This is described as the force per unit area of a substance and the unit is mmHg or pascal.
This is why pressure was chosen as the most appropriate choice in this type of scenario.
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HELP PLEASE!!
identify health-related problems related to an unhealthy body composition.
( I didn't know what subject to put this as, sorry )
Some health-related problems that are related to unhealthy body composition are:
Type 2 DiabetesHigh blood pressureStrokeApneaWhat is a Health Problem?This refers to the complications that a person has when his health system does not function optimally.
Hence, we can see that based on the fact that the body needs to have a healthy body composition such as a good Body Mass Index when this becomes unbalanced, it can bring the above health problems.
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The average velocity of a plane during a flight was 9.0 m/s. How long did it take the plane to travel 5.0 km
Answer:
The time taken is 555.56 s.
Explanation:
The average velocity is the ratio of the net velocity to the time required to achieve net velocity.
The formula of average velocity is,
v(av)=d/t
Given d=5.0 km which is 5*1000 m=5000 m and v(av)=9.0 m/s.
Therefore 9=5000/t
t=5000/9
t=555.56
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A rock in space travels in the x direction with a speed of 6 m/s and collides with an identical rock at rest. After the collision, the first rock is traveling at 4 m/s at an angle of 60 degrees with respect to the x axis. What is the speed of the second rock after the collision, in m/s
The speed of the second rock after the collision is 4.15m/s
Given the direction of rock in space is x , the direction with speed is 6m/s
After the collision the speed of the first rock is at 4 m/s
The angle given is 60 degrees with respect to x - axis
We need to calculate the speed of the second rock after the collision is
We know that
[tex]m_1=m_2[/tex]
[tex]v_1 = 6m/s\\v_2 = 4m/s[/tex]
θ = 60°
We need to find [tex]v_x[/tex] and [tex]v_y[/tex]
Therefore ,
[tex]m_1v_1= m_2v_2cos60+m_2v_2\\[/tex]
So, 6 = 4 cos 60° + [tex]v_2[/tex]
[tex]v_x = 6-4cos60\\v_x = 2m/s[/tex]
The same way we will find the momentum for [tex]v_y[/tex]
The total momentum is 0
0+0 = [tex]m_1(4)sin60 + m_2v_y[/tex]
[tex]v_y = -3.64 m/s[/tex]
Now ,
V (resultant) = [tex]\sqrt{(v_x)^{2} + (v_y)^2} \\v = \sqrt{(2)^2+(-3.64)^2} \\v = 4.15 m/s[/tex]
Hence the speed of the second rock after the collision, in m/s is 4.15m/s
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Zoe has 25 grams of water (c = 4.186 joules over grams times degrees celsius) at 10°c, which she mixes with 12 grams of water at 30°c. assume that no heat is lost to the surroundings. what is the final temperature of the two liquids? the answer is expressed to the nearest whole number. –47°c –8°c 3°c 16°c
We use the expression Q = mC(T2-T1). We caclulate as follows:
Q absorbed = Q released
m1 C (T-T1) = -m2 C (T-T1)
C can be cancelled since they are the same substance.
m1 (T-T1) = -m2 (T-T1)
25 (T-10) = -12 (T-30)
T = 16.49 degrees Celsius
The final temperature of the two liquids is 16.49 degrees Celsius.
What is thermal energy?The energy present in a system that determines its temperature is referred to as thermal energy. Thermal energy flows as heat. Thermodynamics is a whole field of physics that studies how heat is transmitted across various systems and how work is performed in the process.
We use the expression Q = mC(T2-T1). We caclulate as follows:
Q absorbed = Q released
m1 C (T-T1) = -m2 C (T-T1)
C can be cancelled since they are the same substance.
m1 (T-T1) = -m2 (T-T1)
25 (T-10) = -12 (T-30)
T = 16.49 degrees Celsius
The final temperature of the two liquids is 16.49 degrees Celsius.
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1. You released a pendulum of mass 1kg from a height of 0.05m
b. If the pendulum loses 18% of the initial energy by the time it reaches the bottom, how fast is it going when it reaches the bottom?
c. If the pendulum loses another 7% of its remaining energy by the time it reaches the other side, how high up does it go?
d. After a few minutes the pendulum is no longer swinging at all, explain why this happens in terms of energy?
a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.
b. The height reached by the pendulum is 0.038 m.
c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Kinetic energy of the pendulum when it reaches bottomK.E = 100%P.E - 18%P.E
where;
P.E is potential; energyK.E(bottom) = 0.82P.E
K.E(bottom) = 0.82(mgh)
K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J
Speed of the pendulumK.E = ¹/₂mv²
2K.E = mv²
v² = (2K.E)/m
v² = (2 x 0.402)/1
v² = 0.804
v = √0.804
v = 0.9 m/s
Final potential energyP.E = 100%K.E - 7%K.E
P.E = 93%K.E
P.E = 0.93(0.402 J)
P.E = 0.374 J
Height reached by the pendulumP.E = mgh
h = P.E/mg
h = (0.374)/(1 x 9.8)
h = 0.038 m
when the pendulum stopsWhen the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.
The height reached by the pendulum is 0.038 m.
When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
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What are the products of a fusion reaction? Check all that apply.
lighter atoms
energy
heavier atoms
a neutron
a proton
Energy, heavier atoms atoms, neutron and a proton are the products of a fusion reaction.
What are the products of a fusion reaction?
Nuclear fusion is a type of reaction in which two or more atomic nuclei fuse or combine to form heavy nuclei and subatomic particles such as neutrons or protons and release of energy.
So we can conclude that Energy, heavier atoms, neutron and a proton are the products of a fusion reaction.
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Answer:
B C D
Explanation:
At a particular instant, a hot air balloon is 100 m in the air and descending at a constant speed of 2.0 m/s. at this exact instant, a girl throws a ball horizontally, relative to herself, with an initial speed of 20 m/s. when she lands, where will she find the ball? ignore air resistance.
Answer:
86.4 m horizontal from landing spot
Explanation:
Find out how long before the ball hits the ground
vertical speed of ball = -2 m/s gravity = - 9.81 m/s^2
find time to hit ground from 100 m
( height will be zero when it hits the ground)
0 = 100 - 2 t - 1/2 ( 9.81) t^2
use Quadratic Formula to find t = 4.32 seconds
horizontal speed of ball = 20 m/s
in 4.32 seconds it will travel horizontally 20 m/s * 4.32 s = 86.4 m
when a car hits a hole in the road, the spring shown in the picture compresses by 20 mm.
the spring constant = 90kN/m
calculate the energy stored in the spring by this compression
The energy that is stored in the spring is 0.018 J.
What is Hooke's law?Hooke's law states that as long as the elastic limit is not exceeded, the extension is directly proportional to the load.
Now we have the following;
The compression = 20 mm or 0.02 m
The spring constant = 90kN/m
Energy stored in the spring = 1/2Ke^2
= 1/2 * 90kN/m * (0.02 m)
= 0.018 J
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What adaptation of a cheetah is shown in the image?
a cheetah running
Brown color to blend in with the grass
Long and strong legs to run fast
Spots on the fur to keep warm
Strong sense of smell to catch predators
The adaptation of a cheetah is shown in the image which shows it running is its long and strong legs to run fast which is denoted as option B.
What is Adaptation?These are the physical and behavioral features which ensures that they survive in their changing environment.
Cheetahs are known to have long and strong legs which is the reason why it runs at a very high speed.
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Answer: Option (B) is correct
Explanation: Hope it helps!
Good luck!
Need help in knowing what energy it’s using
Answer:
8:P.E,9:gaining K.E,10:P.E,11:gaining K.E.
Explanation:
it gained potential energy at 8 because it was at its maximum height,and since potential energy is the energy that u posses due to ur height,thats the energy it possesed on the spot 8.as you can see on spot 9 its moving down so as its moving down,it gains kinetic energy,since its an energy possesed by a body due to its motion/movement,thats what it gained at spot 9, it gsained kineti energy because of its movement.and at 10 agian it would gain potential energy ecause of height and on point 11 as its heading upwards it gains kinetic energy because of movement.
How much heat is needed to change the temperature of 3 grams of gold (c = 0.129 joules over grams times degrees celsius) from 21°c to 363°c? the answer is expressed to the nearest whole number. 121 joules 132 joules 140 joules 149 joules
The heat needed is 132J
Given the mass of the gold m = 3 gram.
The initial temperature of the gold T = 21 degree celsius.
The final temperature of the gold T' = 363 degree celsius.
Hence, the change in temperature dT = T' - T
= 363 - 21 degree celsius
= 342 degree celsius.
The specific heat of the gold is given as c = 0.129 J/g°C
We are asked to calculate the heat required ( dQ ) to raise the temperature of gold.
The heat required for this is calculated as
dQ = mcDT
dQ = 3 × 342 × 0.129 J
dQ = 132.354 J ≈ 132 J
Hence, the Heat needed is 132 J.
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Answer: B (132 joules)
Explanation:
A 60-kg skier starts from rest from the top of a 50-m high slope. If the work done by friction is -10.0 kJ, what is the speed of the skier on reaching the bottom of the slope
The speed of the skier on reaching the bottom of the slope is 25.43 m/s.
Kinetic energy of the skier on reaching the bottom of the slope
Kinetic energy on reach the bottom = P.E - 10 kJ
Kinetic energy on reach the bottom = (60)(9.8)(50) - 10 kJ
Kinetic energy on reach the bottom = 19.4 kJ = 19,400 J
Speed of the skier on reaching the bottom of the slopeK.E = ¹/₂mv²
2K.E = mv²
v² = 2K.E/m
v² = (2 x 19,400)/(60)
v² = 646.667
v = √646.667
v = 25.43 m/s.
Thus, the speed of the skier on reaching the bottom of the slope is 25.43 m/s.
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