The velocity of the third piece is mathematically given as
v=0.88m/s
What is the velocity of the third piece.?Generally, the equation for conservation is mathematically given as
[tex]m u=m_{1} v_{1 \mathrm{x}}+m_{2} v_{2 \mathrm{x}}+m_{1} v_{x}[/tex]
Here, is the mass of the grenade, [tex]m_{1}, m_{2}, m_{3}[/tex] the masses of the pieces after an explosion, and [tex]v_{1 \mathrm{x}}, v_{2 \mathrm{x}}[/tex] are velocities of the first and second pieces after the explosion.
[tex]m u_{1} &=m_{1} v_{1 x}+m_{2} v_{2 \mathrm{x}}+m_{3} v_{x} \\0 &=0+(0.2 \mathrm{~kg})((5 \mathrm{~m} / \mathrm{s})\\v_{x} &=\frac{-0.173 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.578 \mathrm{~m} / \mathrm{s}[/tex]
the equation for conservation
[tex]m u=m_{1} v_{1 y}+m_{2} v_{2 y}+m_{3} v_{y}[/tex]
[tex]m u_{1} &=m_{1} v_{1 \mathrm{y}}+m_{2} v_{x y}+m_{3} v_{y} \\0 &=(0.10 \mathrm{~kg})(10 \mathrm{~m} / \mathrm{s})+(0.2 \mathrm{~kg})\left((5 \mathrm{~m} / \mathrm{s}) \cos 10^{\circ}\right)+(0.3 \mathrm{~kg}) v_{y} \\v_{y} &=\frac{-1.98 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.661 \mathrm{~m} / \mathrm{s}[/tex]
In conclusion, the magnitude of the velocity
[tex]v=\sqrt{v_{\mathrm{x}}^{2}+v_{\mathrm{y}}^{2}}[/tex]
[tex]Substitute $-0.578 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{s}}$ and $-0.661 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{y}}$[/tex]
[tex]v &=\sqrt{v_{x}^{2}+v_{y}^{2}} \\&=\sqrt{(-0.578 \mathrm{~m} / \mathrm{s})^{2}+(-0.661 \mathrm{~m} / \mathrm{s})^{2}} \\&=0.88 \mathrm{~m} / \mathrm{s}[/tex]
v=0.88m/s
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A 10-kg ring with outer radius 1.5 m and inner radius 1.2 m is placed snuggly around a solid sphere with mass 8.0 kg and radius 1.2 m. The combination rotates about the axis of the cylinder. What is the rotational inertia of the combination
The rotational inertia of the combination is 21.5kg m2
Given that mass of ring = 10kg , outer radius 1.5 m and inner radius 1.2 m
Radius of ring = ½(1.5+1.2) =1.35m
Mass of solid sphere=8kg
Radius of sphere =1.2m
A combination rotational inertia of ring and solid sphere is addiction of rotation inertia of ring and solid sphere
Rotational inertia of ring Ir=MR^2
Rotational inertia of solid sphere Is=2/5MR^2
Combination rotational inertia of ring and solid sphere
I=Ir+Is
=M1R^2+2/5M2R^2
=(10)(1.3^2)+⅖(8)(1.2^2)
=16.9+4.608
=21.5kg m2
Hence the rotational inertia of the combination is 21.5kg/m^2
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A 1000 kg car is turning round a corner at 10 m/s as it travels along an arc of the circle. If the radius of the circular path is 10 m, how large a force must be exerted by the pavement on the tires to hold the car in the circular path?
Answer:
The force should be equal to 10000 N.
Explanation:
When the car turns round a circular path, it is assumed that there is some centripetal force acting towards the center.
The centripetal force is calculated by the formula,
F=mv^2/r
Given m=1000 kg, v=10 m/s and r=10 m.
F=1000*(10)^2/10
F=10000 N
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A pendulum with a length of 36.9 cm has a period of 1.22 s. Calculate the gravitational field at the pendulum’s location.
From the calculation, the gravitational field at the pendulum’s location is 9.8 m/s^2
What is a pendulum?A pendulum is a device that is used to demonstrate oscillatory motion. We have the following information.
l = 36.9 cm or 0.369 m
T = 1.22 s
Then;
T = 2π√l/g
T/2π = √l/g
(T/2π)^2 = l/g
g(T/2π)^2 = l
g = l/(T/2π)^2
g = 0.369/(1.22/2 *3.14)^2
g = 9.8 m/s^2
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If you can walk at 3 mph, how far away is school if it takes you 20 minutes?
A. 0.5 miles
B. 1 mile
C. 2 miles
D. 1.5 miles
Answer:
The answer is B, 1 mile
Explanation:
60 (minutes) ÷ 3 (mph) = 20, which means every 20 minutes you are traveling 1 mile
Stars that have ejected a planetary nebula go on to become white dwarfs. supernovae. protostars. red giants.
Stars that have ejected a planetary nebula go on to become white
dwarfs.
As we know planetary nebula is a type of glowing shell of ionized gases and there are various stages for the formation of stars. Stars are formed when dispersed matter in gaseous form starts coalescing together under the force of gravity into a compact object. Gravity continuously tries to shrink the object and during this process, the density and temperature inside the star rises.
The fate of the star depends critically on its mass. For stars with mass less than 1.4 solar masses of sun collapse into an extremely dense compact object called "white dwarf". Electron degeneracy pressure is responsible for counterbalancing the inward gravitational force in "white dwarf".
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In an automatic AWD vehicle, normally one axle receives all the torque; when slippage occurs, 50 percent of the torque can be sent to the other axle by _____ means.
Option (d) All of these is correct.
In an automatic AWD vehicle, normally one axle receives all the torque; when slippage occurs, 50 percent of the torque can be sent to the other axle by hydraulic, mechanical and electrical means.
AWD vehicle stands for All-wheel drive vehicle.
A vehicle with all-wheel drive (AWD) has a powertrain that can drive all of its wheels, either continuously or as needed.
When we say the torque distribution is 50/50 "in normal conditions," we imply that the moment of force applied to the front and rear wheels is equal when all wheels have the same adhesion.
In an automatic AWD vehicle normally one axle receives all the torque and sent to other axle by hydraulic, mechanical and electrical means.
So that's why when the spillage occurs, 50% of the torque can be sent to the other axle also by hydraulic, mechanical and electrical means.
Hence, Option (d) All of these is correct.
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A stone of weight $w$ is thrown vertically upward into the air with an initial speed $v_0$. Suppose that the air drag force $f$ dissipates an amount $fy$ of mechanical energy as the stone travels a distance $y$. What is the speed of the stone upon impact with the ground
The speed of the stone upon impact with the ground [tex]{V_f}={V_o} (\frac{w-f}{w+f})^{\frac{1}{2}}[/tex]
GivenThe initial speed = [tex]{V_o}[/tex]
Explanation
Acceleration
The state of going quickly or taking place quickly.acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.Acceleration when ball is moving upward = (w + f)/m
[tex]$\mathrm{V}_{\mathrm{f}}^{2}-\mathrm{V}_{\mathrm{i}}^{2}=2 \overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{s}}$[/tex]
[tex]$=0-\mathrm{V}_{0}^{2}=-2 \mathrm{~s}\left(\frac{\mathrm{w}+\mathrm{f}}{\mathrm{m}}\right)$[/tex] ..... (i)
[tex]$\mathrm{s}=\frac{\mathrm{V}_{0}^{2}}{2\left[\frac{\mathrm{w}+\mathrm{f}}{\mathrm{m}}\right]}$[/tex]
While coming down
[tex]{V_i=0}[/tex]
[tex]$\mathrm{V}_{\mathrm{f}}^{2}-\mathrm{V}_{\mathrm{i}}^{2}=2 \overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{s}} ; \mathrm{a}=(\mathrm{w}+\mathrm{f})$[/tex]
[tex]$\mathrm{V}_{\mathrm{f}}=\sqrt{\frac{2 \times(\mathrm{w}-\mathrm{f}) \mathrm{V}_{0}^{2}}{2(\mathrm{w}+\mathrm{f})}}$[/tex]
[tex]$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\circ}\left(\frac{\mathrm{w}-\mathrm{f}}{\mathrm{w}+\mathrm{f}}\right)^{1 / 2}$[/tex]
The speed of the stone upon impact with the ground
[tex]$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\circ}\left(\frac{\mathrm{w}-\mathrm{f}}{\mathrm{w}+\mathrm{f}}\right)^{1 / 2}$[/tex]
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using knowledge of states of matter,write a message about the importance of science in our society
Answer:
उव्ग्वुव ह्व्झ एउएइहे एइएइएइएएइ सिसुब्स्सी बीस सिस इस्ब एइब
Explanation:
?उग्व्ब्वु विब्सिए इसिग्व विद्बिअब्द सिह्व्व इस्ब्व दिव्ब्स विह्द ऐद्जिइ सुउगव्दी सिइगैगे क्ज्गैइव अजिव्व्ज्व्स कैह्द अजि ह्ज्फ्ज इअह इकुगै ईग इअबे अजिव्ब जैइअब इऐहे ऐइहे ऐइग्गे अत्व्ब ओप्झब रोज दिधिए ऊइफ्ब इसुहद ईउहे सिउउअ दिइब्द स्सिउए ऐइहे सिएय्व एउविये एइव्वे
To determine the focal length of a convex lens, a student focuses a classroom window, a
distant tree and Sun on the screen. In which case, will the student get a value closer to
the accurate value of focal length?
To determine the focal length of a convex lens, if we are using sun as distant object, then we get a value which is closer to the accurate value of convex lens.
To find the answer, we need to know more about the focal length of a convex lens.
Why we get a focal length which is closer to the accurate value if we focusing sun?The focal length of an optical system can be defined as the measure of how sharply it converges or diverges the light.Focal length of convex lens is the distance between the pole and the focus of the convex lens.Convex lens converges all the rays coming from the distant object at its focal point to form a real image.If the object is at more distance from the lens, then we get sharper image.If we focus on a nearby window, then image will form away from the focal point.In the case of a distant tree, we need to move the screen towards the lens to get the focal point.Thus, we can conclude that, the if we are using sun as distant object, then we get a value which is closer to the accurate value of convex lens.
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If we use the sun as a distant object to calculate the convex lens's focal length, we obtain a number that is more closely related to the actual convex lens value.
We need to learn more about a convex lens's focal length in order to locate the solution.
Why, if we concentrate the sun, do we obtain a focal length that is closer to the correct value?An optical system's focal length is a measurement of how sharply the light converges or diverges.The distance between the convex lens's pole and its focus is known as its focal length.Convex lenses focus all of the rays from the distant object at their focal point to create a true image.We receive a crisper image if the object is farther away from the lens.Away from the focal point, an image will form if we concentrate on a neighboring window.To get the focal point on a distant tree, we must move the screen in the direction of the lens.We can therefore draw the conclusion that if we use the sun as a distant object, we will obtain a value that is closer to the convex lens's actual value.
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An electron is accelerated from rest by an electric potential difference of 437 V, and then enters a region of uniform magnetic field. The magnetic field is oriented perpendicular to the velocity with a magnitude of 42.8 mT. What will the radius of the electron's path be once it enters the magnetic field
The radius of the electron's path is once it enters the magnetic field 3.16*10^-4 m.
The electric capacity difference, additionally called voltage, is the outside work needed to bring a rate from one region to some other area in an electric discipline. The electric powered capacity distinction is the change of potential electricity skilled by way of a test rate that has a fee of +1.
The distinction in ability among two points represents the paintings worried or the electricity released in the switch of a unit amount of power from one factor to the other.
Electric ability is the work executed in step with unit fee in bringing the fee from infinity to that factor against electrostatic pressure. In a conductor, electrons float simplest when there is a difference in electric stress at its ends. This is additionally known as the capacity distinction.
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Which best describes the relationship between energy and entropy in the universe? for entropy to increase, energy must be added. for entropy to decrease, energy must be added. for entropy to remain constant, energy must be added.
Answer:
Entropy is a measure of the order/disorder during the transformation of the state of a system and is defined as the total variation of energy at a defined temperature. From point of view of statistical mechanics, this variation of energy is generated from statistical transitions of the internal states of the system. In this sense, entropy can measure how easy it is to reach a defined state of the system. Now, imagine a text stream that arrives to you character by character in a screen. If the text is meaningless, then every character has the same probability of appearing to you and therefore the entropy is maximal because this disorder is maximal. If you want to transfer information, then you have to spend a little bit of energy in ordering the characters because this does not happen spontaneously. The final state of the system is more ordered in respect to the earlier one, so the entropy is less than the entropy of random text. This means that, if you want to reduce entropy in order to transfer information, then you must spend energy.
Explanation:
Answer: For entropy to decrease, energy must be added. (B)
Explanation: Trust me bbg c;
You are traveling at 55 mi/h along the x-axis relative to a straight, level road and pass a car that is traveling at 45 mi/h. The relative velocity of your car to the other car is
Answer:
10 mph
Explanation:
55 - 45 = 10 mph
Which phrase is most similar in meaning to “scientific theory”?
A. a rigorously tested explanation
B. a mathematical relationship
C. an opinion of what should happen
Answer:
scientific theory”?A. a best guess explanation. B. a rigorously tested explanation. C. an opinion of what should happen. D. a mathematical relationship
When Stone B collides with Stone A during Test 2, Stone B stops and Stone A begins to move. Which statement BEST describes the momentum in Test 2?
A
Stone A moves away from Stone B at a velocity of 4 m/s, and the momentum is conserved.
B
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is not conserved.
C
Stone A moves away from Stone B at a velocity of 4 m/s, and the momentum is not conserved.
D
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is conserved.
Answer:
A
Explanation:
According to law of conservation of momentum, the total momentual in the system will be conserved
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is not conserved is the correct answer. The correct option is (b).
The momentum of Stone A is transferred to Stone B when Stone B strikes Stone A and stops. Stone A begins to move with a 2 m/s velocity in the opposite direction as a result (because Stone B was going with a 2 m/s velocity in the opposite direction).
The momentum is not conserved, though, because the momentum of Stone B prior to the impact (which was in the opposite direction) does not match the momentum of Stone A following the contact. The impact results in a little loss of momentum, perhaps as a result of friction or other dissipative forces.
Therefore, The correct option is (b). Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is not conserved.
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Kristen has two identical sized cubes, one is lead (Pb) and one is copper (Cu). Kristen is determining the density of each cube. Which property will be the same in each cube?
Answer:
volume
Explanation:
Identical size means volume will be the same in each calculation of
density = mass / volume
An object moving with a speed of 1 m/s accelerates uniformly at 9 m/s2 in the direction of its motion for a distance of 7 meters. What is the final speed of the object
The final speed of the object is 11.2m/s.
To find the answer, we need to know about the Newton's equation of motion.
What's the Newton's equation of motion that establish a relation between initial velocity, final velocity, acceleration and distance?The Newton's equation of motion is V²-U²= 2aSU = initial velocity, V= final velocity, a= acceleration and S = distance.What's the final velocity, if initial velocity, acceleration and distance are 1m/s, 9 m/s² and 7m respectively?Here, U= 1m/s, a= 9 m/s² and S= 7mV²- 1²= 2×9×7= 126V= √126= 11.2 m/s
Thus, we can conclude that the final speed is 11.2 m/s.
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A graduated cylinder has 155 ml of water in it. When a rock is dropped in the new water level is 185 ml. The volume of the rock is
Answer:
30cm^3
Explanation:
ml means milliliter, 1 ml= 1cm^3 that's the unit for volume
hence
Δv=185-155=30ml=30cm^3
([3] w) p
18.0
16.0-
14.0
12.0-
10.0-
8.0 -
6.0
4.0
2.0 -
0-
0
0.5
Position v. Time for Motion with Uniform Acceleration
1.0 1.5
2.0
t(s)
2.5
run
3.0
3.5
4.0
rise
4.5
Practice
1. (a) Determine the instantaneous velocity at t= 1.0 s for the graph shown in Figure 6.
(b) Determine the instantaneous velocity at t = 3.0 s for the graph shown in Figure 6.
I need help figuring out what steps I should take.
Explanation:
the density of liquid x is 40g and a bottle full of water has the density of 70g find the density of liquid x (d=1g/cm3)
Look at the heart shape shown below. Will the centre of mass of this shape be nearer the top or the bottom of the heart?
Answer:
Nearer the top
Explanation:
Since the shape is not symmetrical in all axis, from the shape, there is more matter occupying the top half of the image. Hence the senter of gravity being at the top
The volume of a certain quantity of nitrogen at 0 ºC is 10 L. Determine, if the pressure does not vary, what the volume will be at -20 ºC. What would happen if instead of N2 the gas was hydrogen?
From the calculations, the volume of the gas is obtained as 9.3 L
What is the gas laws?The gas laws show the relationship between the volume, pressure, temperature and the number of moles of a gas.
Given that;
V1 = 10 L
T1 = 0 ºC + 273 = 273 K
V2 = ?
T2 = -20 ºC + 273 = 253 K
It then follows that;
V1/T1 = V2/T2
V1T2 = V2T1
V2 = V1T2/T1
V2 = 10 L * 253 K/273 K
V2 = 9.3 L
If the gas were to be hydrogen, the volume of the gas will decrease even further,
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The curved section of a speedway is a circular arc having a radius of 190 m. this curve is properly banked for racecars moving at 34 m/s. at what angle with the horizontal is the curved part of the speedway banked?
The banking angle of the curved part of the speedway is determined as 32⁰.
Banking angle of the curved road
The banking angle of the curved part of the speedway is calculated as follows;
V(max) = √(rg tanθ)
where;
r is radius of the pathg is acceleration due to gravityV² = rg tanθ
tanθ = V²/rg
tanθ = (34²)/(190 x 9.8)
tanθ = 0.62
θ = arc tan(0.62)
θ = 31.8
θ ≈ 32⁰
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If the measured resistance of a diode is very high in both directions, the diode is probably __________.
Diode is probably fault.
Diode is an electrical component which allows current to flow in one direction and heavy resistance in other direction.
The working of diode is based on the p-n junction which have
more electron and less hole if p-n junction is n-type and vice-versa.
There are various uses of diode in electric appliances.
If the diode possess high resistances in both the directions then there is
no flow of current. So, the diode must be fault .
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A boat floats south on the Amazon River at a speed of 6 m/s south. The boat and passengers have a combined mass of 540 kg.
a. What is the momentum of the boat? (3 points)
b. A passenger drags his hand in the water, applying an impulse of 3200 kg·m/s to the north. What is the new velocity of the boat? (3 points)
A. The momentum of the boat, given the data is 3240 Kg.m/s
B. The new velocity of the boat is 11.93 m/s
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Imulpse = m(v - u)
How to determine the momentumMass = 540 Kgvelocity = 6 m/sMomentum = ?Momentum = mass × velocity
Momentum = 540 × 6
Momentum = 3240 Kg.m/s
How to determine the new velocityMass = 540 KgInitial velocity = 6 m/sImpulse = 3200 kg·m/sFinal velocity =?Imulpse = m(v - u)
3200 = 540 × (v - 6)
Divide both sides by 540
v - 6 = 3200 / 540
v - 6 = 5.93
Collect like terms
v = 5.93 + 6
v = 11.93 m/s
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A cheetah can accelerate from rest to a speed of 28.5 m/s in 4.25 s. What is its acceleration (in m/s2)
Answer:
6.71 meters per second squared
Explanation:
Speed vs velocity
Average acceleration is defined as the rate of change of velocity per unit of time.
Velocity is a vector, a quantity that has both direction and magnitude (size). In this case, the cheetah is not changing directions, so we can ignore vector directions, and treat velocity as just speed.
[tex]a=\dfrac {\Delta v}{\Delta t}[/tex]
Analyzing units
The units of the acceleration requested are meters per second squared, and the units of speed and time are measured in meters per second, and seconds.
The units all match, so we just need to substitute and calculate/simplify
Calculations
[tex]a=\dfrac{(28.5[\frac {m}{s}])}{(4.25[s])}[/tex]
[tex]a=6.70588235294...[\frac {m}{s^2}][/tex]
Accounting for significant figures, the acceleration is 6.71 meters per second squared.
The density of mercury is 13.6 g/ml. what is its density in lbs/l? (hint: 1 lb = 0.454 kg)
The density of the mercury in lbs/l is 29.96 lbs/l.
Density: The ratio of the mass of the substance to its total volume is defined as the density of that substance.
The formula of the density is,
d=m/V
where d is the density, m is the mass and V is the volume.
Conversion of the unit from g/ml to lbs/l:
It is given that the density of the given substance is 13.6 g/ml.
1 lb = 0.454 Kg
1 kg = 1000 g
So 1 lb = 0.454 *1000 g
1 lb = 454 g
That means 1 g = 1/454 lb
Then 1 ml = 0.001 l.
Using these values, the density of the given substance in lbs/l is calculated.
13.6 g/ml = (13.6 g/ml)*(1 lb/ 454 g)÷(0.001 l/ml)
13.6 g/ml = 29.96 lbs/l
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write down the factors that affect weight of a body.
List of things that could affect your body weight:
GeneticsStressAgeDiet (or Lifestyle)HydrationMedicationsMedical ConditionsSleepAnswer:
mass and gravity
Explanation:
From a PHYSICS standpoint:
mass and gravity determine the weight of a body
The immersed volume of body in a liquid depends on density of the liquid. TRUE or FALSE?
Answer:
True - Archimedes Principle states that the buoyant force on an object is equal to the weight of the liquid displaced.
What is the name of the front part of the eye which refracts incoming light onto the lens?.
Answer:
CORNEA
Explanation:-
Cornea: Basically the transparent circular part of the front of the eyeball. It refracts the light entering the eye onto the lens, which then focuses it onto the retina. The cornea contains no blood vessels and is extremely sensitive to pain.
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A counterclockwise current of 3.0 A is circling around a wire loop (positioned directly in front of you) having an area of 5.8 x 10-2 m2. What is the magnetic dipole moment
The magnetic dipole moment of the wire loop is 0.174 Am².
Magnetic dipole momentThe magnetic dipole moment is calculated as follows;
μ = NIA
where;
N is number of loopI is currentA is area of the loopμ = (3)(5.8 x 10⁻²)
μ = 0.174 Am²
Thus, the magnetic dipole moment of the wire loop is 0.174 Am².
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11. Amy is in a car that is moving at a speed of 50 kilometers/hour. If she moves a total distance of
230 kilometers, how long was she in the car?