7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we consider passenger cars and commercial trucks. Among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates (based on samples collected by the author). A reasonable hypothesis is that passenger car owners violate license plate laws at a higher rate than owners of commercial trucks. Use a 0.05 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval

Answers

Answer 1

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let [tex]p_{1}[/tex] be the probability that commercial cars have rear license plates and [tex]p_{2}[/tex] be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

[tex]H_{0}:p_{1} =p_{2}[/tex]

[tex]H_{1} :p_{1} < p_{2}[/tex]

It is a left tailed test at 0.05 significance.

Standard errors of p=[tex]\sqrt{p(1-p)/n}[/tex]

=[tex]\sqrt{(0.1191*0.8809)/2383}[/tex]

=[tex]\sqrt{0.1049/2383}[/tex]        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

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Related Questions

In a binomial​ experiement, what does it mean to say that each trial is independent of the other​ trials?.

Answers

In a binomialexperiment to say that each trial is independent of the other​ trials means that the outcome of one trial does not affect the other trial.

An experiment with a set number of independent trials and just two results is referred to as a binomial experiment.

To say that in a binomial experiment, each trial is independent of the other trials means that the outcome of one trial does not affect the other trials.

This means that whatever we get in the first trial, does not affect the outcome of the second or any other trial.

For example, in the tossing of a coin 10 times, the outcome of the first trial doesn't affect any of the other nine trials.

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question on the image​

Answers

Let [tex]x,y[/tex] be the legs of the triangle, with [tex]x[tex]\mathrm{area}_{\rm square} = y^2[/tex]

[tex]\mathrm{area}_{\rm triangle} = \dfrac12 xy[/tex]

The square has 3 times the area of the triangle, so

[tex]y^2 = \dfrac32 xy[/tex]

Meanwhile, in the triangle we have

[tex]\tan(\theta) = \dfrac xy[/tex]

Now,

[tex]y^2 = \dfrac32 xy \implies \dfrac23 = \dfrac xy \implies \boxed{\tan(\theta) = \dfrac23}[/tex]

Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret message by matching the answer with the corresponding letter/symbol from the exercises.

Answers

Answer:

a

Step-by-step explanation:

this is the anser on e2020

A space shuttle can orbit the earth at 330 mi above sea level. The average commercial airplane can fly at 5.7 mi above sea level. What is the distance between the two aircraft?

Answers

Answer:

324.3mi

Step-by-step explanation:

Given Space Shuttle height above ground = 330mi

Airplane height above ground = 5.7mi

Difference between two aircrafts = Space Shuttle height - airplane height above ground

= 330 - 5.7

= 324.3mi

Solve the equation
(6x18) (3x + 2) = 0

Answers

Answer:

[tex] - \frac{2}{3} [/tex]

Step-by-step explanation:

Given (6x18)(3x+2) = 0

[tex]108(3x + 2) = 0 \\ 324x + 216 = 0 \\ 324x = - 216 \\ x = \frac{ - 216}{324} \\ = - \frac{2}{3} [/tex]

Which of the following represents a function

Answers

Answer:

(2,3),(4,3),(-2,-3),(-4,-3)

Step-by-step explanation:

A function is defined as a relation in which each domain element (x-value) is paired with exactly one range element (y-value).

This means that each value we input for x must have only one possible output. If the same x-value yields more than one y-value, it is not a function.

The correct answer, as shown above, meets the criteria of a function, as each x-value is shown to produce exactly one y-value. In this set of ordered pairs, if x = 2, then y = 3, and if x = -2, then x = -3.

A set of ordered pairs is not a function if there are ordered pairs with the same x-values but different y-values.

In the other sets of ordered pairs, one x-value has more than one possible y-value. Let's use the last set as an example:

(5,1),(5,2),(5,3),(5,4)

Inputting 5 as x produces four different y values; there is no one y value for the x-value. y could equal 1, 2, 3, or 4.

Consider the function f(x)=1/3(6)x. What is the value of the growth factor of the function?

Answers

Answer:

F = 2

Step-by-step explanation:

Answer:6

Step-by-step explanation:i did the quiz

20) Find the surface area of the solid shown. 16 dm 17 dm 30 dm​

Answers

Answer:

680π dm² = 2136.28 dm²

Step-by-step explanation:

Recall:

lateral area of cone = πrs; where s = slant height = 17 dm

area of circle = πr²

lateral area of cylinder = πdh

Lateral area of cone: (3.14159)(8 dm)(17 dm) = 427.26 dm²

Area of base of cylinder: (3.14159)(8 dm)² = 201.06 dm²

Lateral area of cylinder: (3.14159)(16 dm)(30 dm) = 1507.96 dm²

Total surface area = 427.26 dm² + 201.06 dm² + 1507.96 dm²

Total surface area = 680π dm² = 2136.28 dm²

Having some trouble here

Answers

Answer:

None of them are correct i believe

Step-by-step explanation:

its sideways lol

E
What is the solution to the system of equations?
y = 0x + 3
x = −2
O [--]
O
[22]
[2
O
[-2]

Answers

Answer:

-2

Step-by-step explanation:

The solution to the system of equations is (x, y) = (-2, 1).

What is an equation?

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

The second equation tells us that x = -2.

Substituting this value into the first equation, we get:

y = -2 + 3

Simplifying, we get:

y = 1

Therefore,

The solution to the system of equations is (x, y) = (-2, 1).

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N= ???
Please help asap

Answers

Answer:

N=[tex]\sqrt{61}[/tex]

Step-by-step explanation:

We have the first point as (2,4), and the second point as (-3,-2). This means that [tex]x_1=2, y_1=4,x_2=-3,y_2=-2.[/tex] Using the distance formula, we get [tex]\sqrt{(2-(-3))^2+(4-(-2))^2} \\\sqrt{(2+3)^2+(4+2)^2}\\\sqrt{25+36}=\sqrt{61}[/tex]

Answer:

[tex]\sqrt{61}[/tex]

Step-by-step explanation:

Copy the figure below onto a separate sheet of paper. Find the image of the figure under reflections in line m and then line t. In the box below, describe the rotation equivalent to the composition of reflections with respect to lines m and t.

Answers

The reflection of the triangle DEFG will be given in the figure.

What is a transformation of geometry?

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

The image of the figure under reflections in line m and then line t.

The reflection of the triangle DEF will be given in the figure.

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How far does judy travel in 2 3/4 hours if she travels at the rate of 5 1/2 miles per hour

Answers

Judy travel's 15.125 miles or 15[tex]\frac{1}{8}[/tex] miles in 2 3/4 hours

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:

  Speed = 5 1/2 miles per hour    Time  =   2 3/4 hours

Substituting it in the relationship we get,

Distance = Speed x Time

Distance =  5 1/2 miles per hour  x 2 3/4 hours

Distance = [tex]\frac{11}{2} X \frac{11}{4}[/tex] miles

Distance =  [tex]\frac{121}{8}[/tex] miles or 15[tex]\frac{1}{8}[/tex] miles

Thus Judy travel's 15.125 miles or 15[tex]\frac{1}{8}[/tex] miles in 2 3/4 hours

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16 percent of what number is 17

Answers

Answer:   106.25

Work Shown:

16% of x = 17

0.16x = 17

x = 17/(0.16)

x = 106.25

NOTE: Angles not necessarily drawn to scale.

Answers

Answer:

60

Step-by-step explanation:

I'm assuming that ED is an exactly straight line, that would mean the angle is 180 degrees. So the sum of the angles in between should also equal 180. This gives you the equation

100 + 20 + x = 180

120 + x = 180

60  = x

he coordinate grid shows the graph of four equations: A coordinate grid is shown from negative 12 to positive 12 on the x axis and also on the y axis. Line A passes through the ordered pairs negative 3, 4 and 9, negative 2. Line B passes through the ordered pairs 2, 8 and 8, negative 8. Line C passes through the ordered pairs negative 3, negative 4 and 4, 6. Line D passes through the points 2, negative 2 and 5 and 6. Which set of equations has (5, 0) as its solution? A and B C and D B and D A and D

Answers

The set of equation that is known to have 5 and 0 as solutions is A and B.

How to solve for the system of equations.

From the graph that we have here in this question, we are supposed to identify the equations that have this point.

We can do this by tracing the lines in order to locate 5 and 0 on the grid.

When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.

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HELPP!!!
Instructions: Find the value of the trigonometric ratio. Make sure to simplify the fraction
if needed.

Answers

Soh cah toa

S: sine
C: cosine
T: tangent

O:opposite
H:hypotenuse
A:adjacent

Sin A means opposite/hypotenuse
=15/17

Hope this helped :)

Answer:

15/17

Step-by-step explanation:

73. Real-World Applications
A city's population in the year 1960 was 287,500 . In 1989 the population was 275,900 . Compute the rate of growth of the population and make a statement about the population rate of change in people per year.

Answers

Answer:

The rate of growth of the population is -400, this means the growth of the population from year 1960 to 1989 has dropped by 400 per city.

Step-by-step explanation:

It is given that in a city's population in the year 1960 was 287500 , and in the year of 1989 the population was 275900 .

It is required to compute the rate of growth of population and make a statement about the population rate of 1989 with the year 1989 and the time taken to change the population.

Step 1 of 1

It is given that in a city's population in the year 1960 was 287500 , and in the year of 1989 the population was 275900 .

To find the rate of growth of population and make a statement about the population rate of change in people per year.

Now let f(x) be the number of population and x be the year and use formula of rate of change to find the change in population,

[tex]$m=\frac{f\left(x_{2}\right)-f\left(x_{1}\right)}{x_{2}-x_{1}}$[/tex]

Now substitute, 275900 for [tex]$f\left(x_{2}\right)[/tex], 287500 for  then,

[tex]$$\begin{aligned}m &=\frac{275900-287500}{1989-1960} \\&=\frac{-11600}{29} \\&=-400\end{aligned}$$[/tex]

The rate of growth of population -400, so there is a drop in the population by 400 per city.

When doing his homework, a student uses the addition property of equality to solve for c below. Which statement BEST applies to the sample? 6 + c = 10 6 + (–6) + c = 10 + (–6) c = 4 A. The student failed to keep both sides of the equation balanced. B. The student’s final answer does not have the variable c isolated. C. The use of the addition property of equality is sound, and the answer is correct. D. The student should have used the subtraction property of equality.

Answers

Answer:

The answer would be C

Solve for y
:
V=−4y+4x

Answers

[tex] - 4y = v - 4x \\ y = \frac{ - v}{4} + x[/tex]

[tex]\\ \rm\dashrightarrow V=-4y+4x[/tex]

[tex]\\ \rm\dashrightarrow -4y=V-4x[/tex]

[tex]\\ \rm\dashrightarrow y=\dfrac{V-4x}{-4}[/tex]

[tex]\\ \rm\dashrightarrow y=x-\dfrac{V}{4}[/tex]

37. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
37. x-intercept at (-5, 0) and y-intercept at (0, 4)

Answers

Answer:

The linear equation for the line with an x-intercept at (-5,0) and y-intercept at (0,4) is found as [tex]$y=\frac{4}{5} x+4$[/tex].

Step-by-step explanation:

A condition is given that a line has an x- intercept at (-5,0) and y- intercept at (0,4).

It is asked to find a linear equation satisfying the given condition.

To do so, first determine the slope of the line using coordinates of the given intercepts. Then write the equation in the slope-intercept form using the slope and the y- intercept.

Step 1 of 2

Determine the slope of the line.

The points of the intercepts of the line are given as (-5,0) and (0,4). Next, the formula for the slope is given as,[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$[/tex]

Substitute 4&0 for [tex]$y_{2}$[/tex] and [tex]$y_{1}$[/tex]respectively, and 0&-5 for [tex]$x_{2}$[/tex] and [tex]$x_{1}$[/tex] respectively in the above formula. Then simplify to get the slope as follows,

[tex]$$\begin{aligned}m &=\frac{4-0}{0-(-5)} \\m &=\frac{4}{5}\end{aligned}$$[/tex]

Step 2 of 2

Write the equation in the slope-intercept form.

The slope-intercept form of a line is given as follows,

[tex]$$y=m x+b$$[/tex]

The coordinates at the y- intercept is (0,4). Now, as the y- coordinate is 4 , so b=4.

So, substitute 4 for b and [tex]$\frac{4}{5}$[/tex] for m in the equation y=mx+b, as follows,

[tex]$y=\frac{4}{5} x+4$$[/tex]

This is the required linear equation.

What is the area of the sector
shown in the diagram below?


OA. 11.1 cm²
OB. 2.5 cm²
OC. 39.3 cm²
OD. 50 cm²

Answers

Answer:

OC. 39.3 cm²

Step-by-step explanation:

Area of a circle = πr²    (π ≈ 3.14)

45 degrees = 1/8 of a full circle

Area of the full circle : 3.14 × 10² =

3.14 × 100 = 314 cm²

Area of the sector : 314 × 1/8 = 39.25 cm² ≈ 39.3 cm²

What is a solution to the system of equations that includes quadratic function f(x) and linear function g(x)?
f(x)=2x²+x+4

Answers

The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is (1, 7)

How to solve system of equation?

The solution to the linear and quadratic equation is as follows:

For the linear, a solution is 1 and 7.

This is because when x = 1, f(x) = 7

For the quadratic equation, 1 and 7 also works.

2x² + x + 4

2(1)² + 1 + 4

2 + 1 + 4 = 7

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Lily is 22 years old. Monica is 3 years older than Lily and 2 years younger than Christine. How old is Christine

Answers

Answer:

she would be 20 years old if lily is 22

Monica is 22+3=25
So Monica is 25 years old.
Christine is 2 years older than Monica. So…
25+2=27
Christine is 27 years old

His friends all drive more expensive cars, and Tony is now starting to desire these same expensive products. Which factor is Tony experiencing

Answers

Social class , he is experiencing social class

Calculate the residuals for the scatter plot (image provided)

Answers

From the given graph, and using the scatter plot function of a graphing calculator, the residuals are;

-0.08693, -0.019376, -0.518, -0.183, -0.083, 0.135, 0.318, and 0.578

Which method can be used to find the residuals?

From the diagram, the given points are;

(14, 4), (15, 4), (16.5, 3.5), (18, 4), (18, 3.9), (19.5, 3.85), (20, 4), (26.8, 3.8)

Utilizing a graphing calculator, using the scatter plot function we have the following predicted values;

Best fit line; y = 5.032 - 0.0676•x

Residuals = Actual - Predicted from equation

The residuals are;

y1 = 4 - 4.08693 = -0.08693

y2 = 4 - 4.019376 = -0.019376

y3 = 3.5 - 3.918 = -0.518

y4 = 4 - 3.817 = -0.183

y5 = 3.9 - 3.817 = -0.083

y6 = 3.85 - 3.715 = 0.135

y7 = 4 - 3.682 = 0.318

y8 = 3.8 - 3.222 = 0.578

The residuals are therefore;

The residuals are;

-0.08693, -0.019376, -0.518, -0.183, -0.083, 0.135, 0.318, and 0.578

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please help me out somebody!

Answers

Answer:

Step-by-step explanation:

approximately how high to the nearest tenth of a metre is emma's kite above ground

Answers

11 thanks to the sun light abs the rv light we get from the lunar eclipse

A solid right pyramid has a square base with an edge length of s units and a height of h units.
Which expression represents the volume of the pyramid?
One-fourth s^2h units^3
One-third s^2h units^3
s^2h units^3
3^s2h units^3

Answers

The volume of the square pyramid is: B. One-third s^2h units^3.

What is the Volume of a Square Pyramid?

An example of a square pyramid is given in the image attached below. It has a square base and 4 triangular faces.

A right pyramid that has a square base has a volume that can be calculated using the following volume formula, given as: 1/3(a² × h), where "a" is the length of the edge of the square base, and "h" is the height of the square pyramid.

Given the following parameters for a square pyramid:

The length of the edge of the square base (a) = s units

The height of the square pyramid = h units.

Plug in the values into 1/3(a² × h) to find the expression that represents the volume of the pyramid:

Volume of the square pyramid = 1/3(a² × h) = 1/3(s² × h)

Volume of the square pyramid = 1/3s²h units ³.

The expression that represents the volume of the square pyramid is: B. One-third s^2h units^3.

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Solve for x
[tex]\ \textless \ br /\ \textgreater \ x = \dfrac{1}{2-\dfrac{1}{2-\dfrac{1}{2-x} } } \: \: \: , (x \neq 2)[/tex]
Help me with this!​

Answers

Answer:

[tex]x= \dfrac{3-2x}{4-3x}[/tex]

Step-by-step explanation:

Given:

[tex]x=\dfrac{1}{2-\dfrac{1}{2-\dfrac{1}{2-x}}}}[/tex]

Simplify:

[tex]\begin{aligned}2-\dfrac{1}{2-x} & =\dfrac{2(2-x)-1}{2-x}\\\\ & =\dfrac{3-2x}{2-x}\end{alilgned}[/tex]

Therefore:

[tex]x=\dfrac{1}{2-\dfrac{1}{\dfrac{3-2x}{2-x}}}[/tex]

Simplify:

[tex]\begin{aligned}2-\dfrac{1}{\dfrac{3-2x}{2-x}} & =2-\dfrac{2-x}{3-2x}\\\\ & =\dfrac{2(3-2x)-(2-x)}{3-2x}\\\\ & = \dfrac{6-4x-2+x}{3-2x}\\\\ & = \dfrac{4-3x}{3-2x}\end{aligned}[/tex]

Therefore:

[tex]x & =\dfrac{1}{\dfrac{4-3x}{3-2x}}[/tex]

[tex]\textsf{Apply the fraction rule}: \quad \dfrac{1}{\frac{b}{c}}=\dfrac{c}{b}[/tex]

[tex]\implies x& = \dfrac{3-2x}{4-3x}[/tex]

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