4. You have a 1 M solution of KCl. You need to generate 100 mL of 0.25 M KCl. Explain how you would make this

The Answer to the question is 133.34 grams approximately.

As Al is in excess so, complete HCl will consume in reaction.

Molar Mass of HCl = Atomic mass of H + Atomic mass of Cl

Molar Mass of HCl = 1 + 35.45 = 36.45

Number of moles of HCl which reacting will excess Al are

moles = given mass / molar mass

moles = 108 / 36.45 = 2.96 moles of HCl

So 2.96 moles of HCl are taking part in reaction which is approximately 3 moles

The chemical reaction is as follows as:

3 HCl + (excess) Al →  AlCl₃ + 3 H

It is clear from the reaction that 3 moles of HCl are making 1 mole of AlCl₃

So in our reaction also 3 mole of HCl is taking part which mean that it will form 1 mole of AlCl₃ .

1 mole AlCl₃ = mass formed AlCl₃ / molar mass of AlCl₃

mass formed AlCl₃ = molar mass of AlCl₃

mass formed AlCl₃ = 133.34 grams

So, approximately 133.34 grams of AlCl₃ is formed when we react 108 grams of HCl with excess AlCl₃.

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The percent yield of [tex]MgO[/tex] is 58.79%

According to the following balanced reaction, magnesium interacts with oxygen to generate magnesium oxide:

[tex]2Mg + O_2 \rightarrow 2MgO[/tex]

Given mass of solid magnesium = 0.261g

Molar mass of Mg = 24g/mol

Using formula , [tex]Number of moles =\dfrac {mass} {molar mass} = \dfrac {0.261g} {24g/mol} = 0.0108mole[/tex]

We could theoretically make 0.0108 moles of [tex]MgO[/tex] since the reaction yields an equimolar quantity of [tex]MgO[/tex]. It is clear from the above reaction that 2 moles of magnesium result in 2 moles of magnesium oxide.

Hence, mass of [tex]MgO[/tex] = Number of moles [tex]\times[/tex] Molar mass of MgO

mass of [tex]MgO[/tex]  = [tex]0.0108mole \times 40g/mole = 0.432g[/tex]

Percent yield =  [tex]\dfrac{Actual mass of MgO} {Theoretical mass of MgO} \times 100[/tex]

                       =  [tex]\dfrac{0.254} {0.432} \times 100 = 58.79percentage[/tex]

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Answer:

It is a force acting on the object.

Explanation:

The answer option which is true about the weight of an object is: C. It is a force acting on the object.

Weight can be defined as the force acting on a physical body or an object as a result of gravity. Also, the weight of an object is measured in Newton.

Mathematically, the weight of an object is given by the formula;

Where;

m is the mass of the object.

g is the acceleration due to gravity.

In conclusion, the weight of an object is the force acting on an object due to gravity.

The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981

Computation of partial pressure and number of moles:

Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761

As we know,

[tex]\chi_{Ne} + \chi_{Xe} = 1\\\chi_{Ne}= 1- 0.761\\\chi_{Ne}= 0.239[/tex]

According to Dalton's Law of partial pressure-

[tex]P_i=\chi_i\times P_{total}[/tex]

Where,

[tex]P_i=[/tex]The pressure of the gas component in the mixture

[tex]\chi_i=[/tex] Mole fraction of that gas component

[tex]P_t=[/tex] The total pressure of the mixture

[tex]P_{Xe}=(0.761)\times(6.5)\\P_{Xe}= 4.95 atm\\\\\\P_{Ne}=(0.239)\imes (6.5)\\P_{Ne}= 1.55 atm[/tex]

Calculation:

To calculate the number of moles,

PV=nRT

[tex]n=\frac{PV}{RT}[/tex]

[tex]n_{Xe}= \frac{4.95\times 15.75}{0.0821\times303 }\\ n_{Xe}= \frac{77.96}{24.87} \\n_{Xe}= 3.13\,mole \\\\\\n_{Ne}= \frac{1.55\times 15.75}{0.0821\times303 }\\\\n_{Ne}=\frac{24.41}{24.87}\\ n_{Ne}=0.981 \,mole[/tex]

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What is the specific heat of aluminum?

The specific heat of aluminum is 0.90J/g°C.

Given:

Heat absorbs = 677 J

Mass of the substance = 10 g

Initial temperature = 50°C

Final temperature = 125°C

Formula used:

Q = m x c x ΔT

which can also be written as,

Q = m x c x ( [tex]T_{final}[/tex] - [tex]T_{initial}[/tex] )

where,

Q = heat absorbs

m = mass of a substance

c = heat capacity of aluminum

[tex]T_{final}[/tex] = Final temperature

[tex]T_{initial}[/tex] = Initial temperature

Now, put all the values in the formula given above to get the specific heat of aluminum,

677g = (10g) x c x (125 - 50)°C

c = 0.9026 J/g°C

c = 0.90 J/g°C

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Answer: 0.90

Explanation:

Answer:

3.78 L

Explanation:

The Charles' Law equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the final volume by plugging the give values into the equation and simplifying.

V₁ = 0.30 L                    V₂ = ? L

T₁ = 25 °C                      T₂ = 315 °C

V₁ / T₁ = V₂ / T₂                                          <----- Charles' Law equation

(0.30 L) / (25 °C) = V₂ / (315 °C)                <------ Insert values

0.012 = V₂ / (315 °C)                                  <----- Divide 25 from 0.30

3.78 = V₂                                                   <----- Multiply both sides by 315

The true statement is that the metal on the right oxidizes more easily than the one on the left.

Metal oxidation is known to often occur if an ionic chemical reaction is said to take place on a metal's surface at the presence of oxygen.

Note that Electrons often move from the metal to the oxygen molecules in course of this  process and as such The true statement is that the metal on the right oxidizes more easily than the one on the left.

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Answer:

PVT upon t is equal to k p is equal to k p v is equal to k p upon t is equal to K2

Explanation:

correct answer is d

The measurement that is listen in proper mathematical relationship is PV=K and V/T =K. Option B and D are correct.

Boyle’s law derived the conditions of the sample of a gas in two different conditional pressure and volume. The initial observation was that the product of a given pressure and volume for the sample of gas at a constant temperature is observed to be constant.

Therefore,

PV= constant

PV=K

The two temperature conditions were thus observed and the equation was elaborated to be,

P₁V₁=P₂V₂

On the other hand, Charle's law state that the volume of a fixed mass of a gas is directly proportional to it's absolute temperature, provided that the pressure remains constant. It is represented as V/T =K

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Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

Assuming the density of your initial acid solution is 1.0 g/mL.  the concentration (in molarity)  is mathematically given as

M= 0.75 M

Generally, the equation for Molarity  is  mathematically given as

M= (W/MW) ×1000

Therefore

[tex]M= (\frac{4.5} {60.05} \frac{(1000}{ 100}[/tex]

M = 0.75 M

In conclusion, The initial molarity  is given by

M= 0.75 M

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False

Explanation:

All the time particles are not at rest. Because in different types of matter particles act differently.

In liquid, particles are connected to each other but not they move in different directions.

In solid, particles are tightly connected to each other, there are no gap between them.

Lastly, in case of gas, particles move randomly here and there.

So, we conclude that particles are not always in state of rest.

Hope it help you

Answer:

10.6 g CO₂

Explanation:

You have not been given a limiting reagent. Therefore, to find the maximum amount of CO₂, you need to convert the masses of both reactants to CO₂. The smaller amount of CO₂ produced will be the accurate amount. This is because that amount is all the corresponding reactant can produce before it runs out.

To find the mass of CO₂, you need to (1) convert grams C₂H₂/O₂ to moles (via molar mass), then (2) convert moles C₂H₂/O₂ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams (via molar mass). *I had to guess the chemical reaction because the reaction coefficients are necessary in calculating the mass of CO₂.*

C₂H₂ + O₂ ----> 2 CO₂ + H₂

9.31 g C₂H₂            1 mole               2 moles CO₂          44.0095 g
------------------  x  -------------------  x  ----------------------  x  -------------------  =
                            26.0373 g           1 mole C₂H₂              1 mole

=  31.5 g CO₂

3.8 g O₂             1 mole               2 moles CO₂          44.0095 g
-------------  x  --------------------  x  ----------------------  x  --------------------  =
                       31.9988 g              1 mole O₂                 1 mole

=  10.6 g CO₂

10.6 g CO₂ is the maximum amount of CO₂ that can be produced. In other words, the entire 3.8 g O₂ will be used up in the reaction before all of the 9.31 g C₂H₂ will be used.

The volume of the solution (in mL) is 462.1 mL.

Molarity:

The concentration of a solution is calculated in terms of moles of a solute present per liter of the solution. This is known as molarity.

Calculations:

The molarity of the solution is 0.241 M or 0.241 mol/L. The molar mass of chromium (II) nitrate is 176.0 g/mol.

The volume of the solution is calculated as:

Molarity = Mass of chromium (II) nitrate/(Molar mass x Volume)

0.241 mol/L = 19.6 g/(176.0 g/mol x V)

V = 19.6 g/(176.0 g/mol x 0.241 mol/L)

= 0.4621 L

= 462.1 mL

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Answer:

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jyot stops on dpsoygsivoifi pal llmS phoo kgwxd zjdaluopsl.

You can do different chemical reactions at home, here I will show you 5 reactions you can try:

3.0g mass of carbon dioxide is consumed by the reaction of water.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

The reaction equation is given as:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Parameters that are known:

Mass of CO₂ used = 7.3g

Unknown: mass of water consumed =?

Solution:

To solve this kind of problem, we simply apply some mole concept relationships.

First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:

Number of moles of CO₂ =  [tex]\frac{mass}{molar \;mass}[/tex]

From this number of moles of CO₂, we can use the balanced equation to relate the number of moles of CO₂ to that of H₂O:

6 moles of CO₂ reacted with 6 moles of H₂O(1:1)

We can then use the mole relationship with mass to find the unknown.

Workings

A number of moles of CO₂ =?

The molar mass of CO₂ :

The atomic mass of C = 12g

The atomic mass of O = 16g

Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹

Number of moles of CO₂ =  = 0.166moles

If 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O

Mass of water consumed = number of mole of H₂O x molar mass

Mass of H₂0 = 0.166 x ?

The molar mass of H₂O:

The atomic mass of H = 1g

The atomic mass of O = 16

Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹

Mass of H₂O = 0.166 x 18 = 3.0g

Hence,  3.0g mass of carbon dioxide is consumed by the reaction of water.

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Description of Rhodospirillum:

Rhodospirillum is best described as a Nitrogen-fixing bacteria.

What is Rhodospirillum?:

A genus of photosynthetic bacteria belonging to the Rhodospirillaceae family is called Rhodospirillum. Typically spiral-shaped, polarly flagellated, and with stacked vesicular lamellar photosynthetic membranes, their cells are also polarly flagellated.

It can utilize oxygen for aerobic respiration under aerobic conditions or an alternate terminal electron acceptor for anaerobic respiration because it is a facultative anaerobe. Photosynthesis is genetically reduced during aerobic growth, and Rhodospirillum turns colorless.  

But when oxygen levels are reduced, it instantly begins to produce photosynthesis machinery, which includes membrane proteins, bacteriochlorophylls, and carotenoids.

Additionally, it is a nitrogen-fixing bacterium, able to express and control nitrogenase, a protein complex that can catalyze the conversion of atmospheric nitrogen into ammonia.      

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Answer:

B. The actual yield of a reaction is the amount of product you expected to make.

Explanation:

The actual yield of a reaction is the quantity of a product that is obtained from a chemical reaction. Therefore part B is the right solution to our question since it is true that actual yield of a reaction is the amount of product you expected to make.

Carbon fiber Vs Steel:

Steel has a density that is about five times more when compared to carbon fiber.

What is Carbon fiber (CFRC):

Carbon is an element that occurs naturally, and carbon fiber is made of this element. Because of its crystalline structure, carbon fiber possesses excellent tensile strength and stiffness capabilities. It is used to create lightweight composite parts that have great strength by wrapping the fiber in a polymer matrix.

What is steel:

Steel has long been a preferred material due to its high elasticity, which is around 200 GPa. Its relative abundance and stiffness have made it a widely used manufacturing material. However, because of its weight and density of around 8 g/cm3, it can be exceedingly difficult on the machines it is intended to protect. This weighs nearly five times as much as carbon fiber materials which would offer an equivalent or higher level of stiffness.

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9.331 x  [tex]10^{23}[/tex] many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]P_2O_5[/tex] →  [tex]2P^+{^5} + 5O{^-^2}[/tex]

Given:

0.620 moles of P

Let us assume a mole of oxygen atoms.

2÷0.620 = 5÷a                    Cross Multiply

2a = 0.620 x 5                   Divide both sides by 2

a= 0.310 x 5                      Combine

a = 1.55                              moles of oxygen.

Atoms are there in 1.55 moles of oxygen:

1 mole of anything contains 6.02 x [tex]10^{23}[/tex] items of  that mole

1.55 moles of oxygen contain x  atoms of oxygen

1÷1.55 = 6.02 x [tex]10^{23}[/tex] ÷x                  Cross multiply

1 x a = 1.55 x 6.02 x [tex]10^{23}[/tex]                   Combine

a = 9.331 x  [tex]10^{23}[/tex]

Hence, 9.331 x  [tex]10^{23}[/tex] many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P.

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The number of moles of  b2o3 that will be formed is determined as 4 moles.

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

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Considering the ideal gas law, the volume of the storage tank is 615.5987 L.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

In this case, you know:

Replacing in the ideal gas law:

6.42 atm× V = 165.625 moles ×0.082 [tex]\frac{atmL}{molK}[/tex]× 291 K

Solving:

V= [tex]\frac{165.625 moles x0.082 \frac{atmL}{molK}x291 K}{6.42 atm}[/tex]

V= 615.5987 L

Finally, the volume of the storage tank is 615.5987 L.

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The freezing point of the solution is - 2.15.

The freezing point is the point at which a liquid is changed to solid. We can use the formula;

ΔT = K m I

ΔT = temperature change

K = freezing constant of benzene

m = molality

i = Van't Hoff factor

Now;

ΔT =  5.12°C/m * 0.655 m  * 1

ΔT = 3.35°C

ΔT = Freezing point of pure benzene - Freezing point of solution  

Freezing point of solution  = ΔT -  Freezing point of pure benzene

= 3.35°C -  5.5 °C = - 2.15

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Answer:

2.143 degrees celsius

Explanation:

The pH of the solution is 1.52 and the concentration of C6H6O62- is 2.2 * 10^-7 M.

We know that;

H₂C6H6O6 ⇔HC6H6O6^-(aq)    +   H^+(aq) ----- (1)

Ka1 = 7.9 x 10^-5

Again;

HC6H6O6^-(aq) ⇔ C6H6O6^2-(aq)  +   H^+(aq) ------- (2)

Ka2 = 1.6 x 10^-12

Given that Ka2 <<<< Ka1 we have to apply equation 1 to obtain H^+ hence;

Ka1 = [HC6H6O6^-] [H^+]/[H₂C6H6O6]

Let  [HC6H6O6^-] = [H^+] =x

7.9 x 10^5 =x^2/0.1 - x

But x <<< 0.1 thus;

7.9 x 10^5 =x^2/0.1

x = √7.9 x 10^-5  * 0.1

x = 0.03 M

pH = -log(0.03 M)

pH = 1.52

To obtain  C6H6O6^2-;

Ka2 = [ C6H6O6^2-] [ H^+]/[HC6H6O6^-]

Also;

[ C6H6O6^2-] = [ H^+]= x

Now;

1.6 x 10^-12 = x^2/0.03 -x

But x<<<0.3

Hence;

1.6 x 10^-12 = x^2/0.03

x = √1.6 x 10^-12 * 0.03

x = 2.2 * 10^-7 M

The concentration of C6H6O6^2- is  2.2 * 10^-7 M.

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Explanation:

How many nitrogen molecules are in 1 liter of nitrogen gas at STP?

Answer

2

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Pete Gannett

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:

# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

Answer:

6.721 x 10 ^23 molecules

Explanation:

At STP an ideal gas has 22.4 liters per mole

25 liters / 22.4 liters/mole = 1.11607 moles

1.11607 moles *   6.022 x 10^23  molecules/mole = 6.721 x 10^23 molecules

Answer:

Cr2H6O7S so this the answer hope its useful

The compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

An ionic compound is  compound that is composed of ions. We know that a poly atomic ion is an ion that contains more than one atom.

Looking at the options that have been provided, we know that the correct formula for the compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

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What happens when carbon dioxide builds up in your lungs?

If the person's breathing passage were filled with carbon dioxide instead of air, it would lead to respiratory failure.

Signs of respiratory failure:

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The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

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