Answer:
I don't k own what it is dad fjf f fjff
Answer:
Explanation:
Stellar parallax is the apparent shift of position of any nearby star against the background of distant objects
air around us exerts ____________
We will be changing one variable at a time to see how it affects the value of the forces. Set the variables listed in the table and document the force and determine if the charges are attracted to each other or repelled.
Answer:
Explanation:
The coulombs law is expressed as
F = kq1q2/r^2
where
F is the force
k is the coulomb constant and its value is 9 x 10^9 N/m^2C^2
q1 and q2 are the magnitude of the charges
r is the distance between them
From the information given,
r = 4 cm = 4/100 = 0.04m
For trial 1,
q1 = - 2μC
q2 = 8μC
Recall,
1 μC = 1 x 10^- 9 C
q1 = - 2 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 2 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 9 x 10^-5 N
There is an attraction
For trial 2,
q1 = - 4μC
q2 = 8μC
q1 = - 4 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 4 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 1.8 x 10^-4N
There is an attraction
For trial 3,
q1 = - 6μC
q2 = 8μC
q1 = - 6 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 2.7 x 10^-4N
There is an attraction
For trial 4,
q1 = - 8μC
q2 = 8μC
q1 = - 8 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 3.6 x 10^-4N
There is an attraction
The change in the value of the charge is proportional to the force
Car A runs a red light and crashes into Car B, which is waiting to make a left turn. Car A has a mass of 2,000 kg. Car B has a mass of 1,500 kg. After the impact, the cars stick together and slide away at a speed of 9.1m/s. How fast was Car A going when it hit Car B? Show all of your work. (Law of Conservation of Momentum)
Answer:
The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:
mA vA + mB vB = m v
where, m is the mass in kg, v is the velocity in m/s
since m is the total mass, m = mA + mB, we can write the equation as:
mA vA + mB vB = (mA + mB) v
furthermore, car B was at a stop signal therefore vB = 0, hence
mA vA + 0 = (mA + mB) v
1800 (vA) = (1800 + 1500) (7.1 m/s)
vA = 13.02 m/s
Explanation:
The diagram above shows the angle of an sentence from a light source what will be the angle of reflection?
A 1
B 2
C 3
D 4
Answer:
B 2
Explanation:
Angle of reflection is the measure of the angle taken from the normal.
A m= 25.7 kg object is released from rest at a distance h= 0.523059 R above the earth's surface. the acceleration of gravity is 9.8 m/s^2. for the earth, RE= 6.38 x 10^6 m, M= 5.98 x 10^24 kg. the gravitational acceleration at the surface of the earth is g =9.8 m/s^2. find the speed of the object when it strikes the earth's surface. neglect any atmospheric friction.
caution: you must take into account that the gravitational acceleration depends on distance between the object and the center of the earth. answer in units of m/s
The speed of the object when it strikes the earth's surface is 8087.45 m/s
We'll begin by obtainig the time taken for the object to strike the earth's surface. This can be obtained as follow:
Initial velocity (u) = 0 m/sRadius of earth (R) = 6.38×10⁶ mHeight (h) = 0.523059R = 0.523059 × 6.38×10⁶ = 3337116.42 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
3337116.42 = ½ × 9.8 × t²
3337116.42 = 4.9 × t²
Divide both side by 4.9
t² = 3337116.42 / 4.9
Take the square root of both side
t = √(3337116.42 / 4.9)
t = 825.25 s
Finally, we shall determine the speed the object used in striking the earth's surface. This can be obtained as follow:
Time (t) = 825.25 sAcceleration due to gravity (g) = 9.8 m/s²Speed (v) =?v = gt
v = 9.8 × 825.25
v = 8087.45 m/s
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How is Sonar method different from Radar method
Sonar systems function using sound waves mostly in water, whereas radar systems operate primarily using radio frequencies in the air. Despite the medium difference, radar and sonar's identical underlying concepts frequently lead to technical convergence.
Why do we use sonar instead of radar?Sonar, which stands for Sound Navigation and Ranging, is beneficial for exploring and charting the ocean since sound waves travel farther in water than radar and light waves do.
RADAR transmits electromagnetic waves, whereas active SONAR transmits acoustic (sound) waves. Both systems rely on these waves returning echoes from particular features or targets to determine the most important properties and qualities of the target (i.e., shape, size, speed, distance, etc.).
Both of these sensor systems depend on the sending and receiving of return signals to operate. While sonar systems function largely with sound waves in water, radar systems primarily use radio waves in the air.
Active SONAR transmits acoustic (sound) waves, whereas RADAR transmits electromagnetic waves. Both systems rely on these waves returning echoes from specific features or targets to identify the target's crucial characteristics and traits (i.e., shape, size, speed, distance, etc.).
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The rate at which goods and services can be produced is called
a)capital investment.
b)productivity.
c)producer price output.
d)human capital.
Answer:
productivity
Explanation:
it's the efficiency of production of goods or services
Answer:
Explanation:
The rate at which goods and services can be produced is called
b) productivity.
Pls explain ........................
Option A that is 8.6 x 10^4 volt is the potential difference between a point 0.79 mm from a charge of 7.6nC and a point of infinity.
What is potential difference how it is calculated out to be so?Potential difference can be stated as the difference of electrical potential between two points stated.Here in this question is given the charge 7.6 nC that is 7.6 x 10^-9 and the radius 0.79 mm that is 0.79 x 10^-3 m.Here the potential difference can be calculated out to be by the equation V = k x Q /R , where k is proportionality constant given in equation.V= 8.99 x 10^9 x 7.6x 10^-9 / 0.79 x 10^-3 , putting all the values in the equation.Finally the potential difference is calculate out to be 8.65 x 10^4 volts.To know more about potential difference visit:
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what are chemical properties of acid
Using energy considerations, calculate the average force (in N) a 70.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 8.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him.
The average force a 70.0 kg sprinter exerts backward on the track is 84 N.
What is law of conservation of energy?
The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
E = Fd
where;
F is the applied forced is the displacement of the objectThe average force exerted by the sprinter is calculated as follows;
F = ma
where;
a is the acceleration of the sprinterm is mass of the sprinterThe acceleration of the sprinter is calculated as follows;
v² = u² + 2as
where;
v is the final velocityu is the initial velocitys is the distance(8)² = (2)² + (2x25)a
64 = 4 + 50a
60 = 50a
a = 60/50
a = 1.2 m/s²
Average force exerted by the sprinter;
F = ma
F = 70 kg x 1.2 m/s²
F = 84 N
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Philippe, Maurice’s draft horse, is pulling his 6000N cart using a 745N force on a bridle that is at a 15o angle. If the friction force on the cart is 100N, how long will it take Philippe to go 1000m?
The time taken for Philippe to go 1000 m is 44.5 s.
What is the net force on cart?The net force on the cart is calculated as follows;
F(net) = F - Ff
where;
F is the applied forceFf is the frictional forceF(net) = 745 cos(15) - 100
F(net) = 619.6 N
The mass of the cart is calculated as follows;
W = mg
m = W/g
m = (6000) / (9.8)
m = 612.24 kg
The acceleration of the cart is calculated as follows;
a = F(net) / m
a = (619.6) / (612.24)
a = 1.01 m/s²
The time taken for Philippe to go 1000 m is calculated as follows;
s = vt + ¹/₂at²
s = 0 + ¹/₂at²
2s = at²
t² = 2s/a
t = √(2s/a)
t = √(2 x 1000 / 1.01)
t = 44.5 seconds
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What is the mass of an airplane accelerating at 35 m/s2 if 27,000N of force is being applied?
ill give brainleist
Answer:
771 .4 kg
Explanation:
Remember F = ma so F/a = m
m = 27000 N / 35 m/s^2 = 771 .4 kg
Diane is writing a summary statement of her experiment. This statement is
written.
A after data is collected and analyzed
B before writing the scientific question
C before writing the hypothesis
D at the same time data is collected.
.
What does the amount of refraction of a wave depend on?
A. change in wave speed
B. Location of normal line
C. Size of the object
D. Size of the opening between objects
plsss 15 pointsss!
A) change in wave speed
Option A is correct
I need help with question 5
uestion 5.
iven:
Mass, m = 25 kg
Tension = 47 N
Let's find the maximum acceleration the truck can have before the crate breaks.
Let the magnitude of the force be expressed as:
= m x a
efore the cord breaks , the maximum tension, T, in the string is:
= ma
Where:
T is the maximum tension
m is the mass
a is the maximum acceleration
ence, to findt he maximmum acceleration, rewrite the equation for a.
We have:
[tex]a=\frac{T}{m}[/tex]Now, input 47N for T and 25 kg for m to solve for a:
[tex]\begin{gathered} a=\frac{47\text{ N}}{25\operatorname{kg}} \\ \\ a=1.88m/s^2 \end{gathered}[/tex]herrefore, the maximum acceleration of the truck before the cord breakes is 1.88 m/s²
Find the velocity of a 1000kg car with 50,000J of KE.
Answer:
10 m/2²
Explanation:
v=t/d
blah blah blah
Answer:
10 m/s
Explanation:
Kinetic Energy = 1/2 m v^2
KE / ( 1/2 m) = v^2
then v = sqrt ( KE / (1/2 m ) = 10 m/s
********
A student investigates whether a spring obeys Hooke's law
She uses the apparatus shown in the photograph
(a) Which additional measuring instrument does the student need for the investigation?
1
(b) Explain how the student can investigate whether the spring obeys Hooke's law.
(1)
(5)
The answers include the following below:
The additional measuring instrument the student needs for the investigation is a ruler or measuring tape.The student can investigate whether the spring obeys Hooke's law by adding masses to a spring and measuring the length of the spring when the weight of the masses is increased.What is Hooke's law?
This law states that the force which is needed to extend a spring is directly proportional to the distance in which the spring is extended from its rest or initial position.
The distance gotten is measured with the use of a ruler or a measuring tape so as to obtain an accurate result during the experimental procedures. Hooke'slaw is performed by adding some masses to a spring and taking note of the effect by measuring the length of the spring when the weight of the masses is increased.
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I need help with my work
xplanation:
A swinging edndulum bob performs a simple harmonic motion under the influence of the gravity of the earth. In simple harmonic motion, the restoring force acts on the displaced mass which continuously tries to bring the mass to the equilibrium position.
The object of mass m falls due to the gravity of the earth.
Thus for the motion of the pendulum, a gravitational force acts as a restoring force and the object of mass will fall due to the gravity of the earth. The motion of the pendulum and the falling mass is due to the gravity of the earth and the acceleration due to the gravity of the earth is independent of the mass that is accelerating towards the earth.
inal answrer:
The correct option is (B) although they both accelerate due to gravity at the same rate, a restoring force acts on the bob.
How many measures are there until the next part enters in Kookaburra?
A. 2
B. 1
C. 3
D. 4
Option C) 3. There are about 3 measures until the next part enters in Kookaburra through the expression in Australian countryside.
What is the meaning of the Kookaburra song?The expression probably first appeared because of how many bushes and scrub there are in the Australian countryside. Gay — Up until the middle of the 1950s, the word gay denoted happiness and carelessness.
It therefore signified “happy and carefree” during the time this song was penned.
Do kookaburras make good pets?The state has issued them licenses and permits. For authorized and permitted educational initiatives, both kookaburras serve as educational ambassadors. Kookaburras are not recommended as pets by anyone.
They may be very unpredictable, demand a lot of space, must be maintained in a pack, are very loud, and need a special diet.
What food does a kookaburra consume?They consume insects, beetles, worms, frogs, small animals, snakes, lizards, and lizards.
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A girl is moving in a straight line at a velocity of 3 m/s and starts to slow down at a constant rate. If she stops 6 seconds later, what is her acceleration?
The acceleration of the girl moving in a straight line at a velocity of 3 m/s is - 0.5 m / s²
a = v - u / t
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
v = 0
u = 3 m / s
t = 6 s
a = ( 0 - 3 ) / 6
a = - 0.5 m / s²
The negative symbol signifies that she is decelerating.
Deceleration is the acceleration in opposite direction. As a result, the body will lose velocity at a constant pace. Hence, if the acceleration has a negative value it is called as Deceleration.
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Fig. 3.1 shows a house brick of dimensions 21.0 cm x 10.0 cm x 7.00 cm.
21.0 cm
10.0 cm
7.00 cm
Fig. 3.1
The brick is held under water with its largest surfaces horizontal. The density of water is 1000 kg/m3
(a) Calculate the difference in pressure between the top and the bottom surfaces of the brick.
pressure difference
Given:
Lenght = 21 cm
Width = 10 cm
Height = 7 cm
Density = 1000 kg/m^3
Gravity = 9.8 m/s^2
Apply the formula:
Pressure = depth x density x gravity
Depth = Height = 7 cm = 0.07 m
Replacing:
P = 0.07 x 1000 x 9.8 = 686 Pa
You have three identical, uniform, square pieces of wood, each with
side length L. You stack the three pieces of wood at the edge of
the horizontal top of a table. The first block extends a distance L/4
past the edge of the table. The next block extends a distance L/4
past the edge of the first block, so a distance L/2 past the edge of
the table. The third block extends a distance L/4 past the edge of
the block beneath it, so 3L/4 past the edge of the table. The stack
is unstable if the center of mass of the stack extends beyond the
edge of the table.
Centre of mass of the square piece at the middle of the stack is at x = 0 centre of mass of the bottom most square piece in the stack is at{ (l/4)^2 + (l/4)^2}^1/2 .
What is centre of mass and how it is calculated in the stack?Centre of mass in physics is a phenomenal discovery which states that the overall weight of the body distributed sums up to zero at the point central relative to other points.The point of centre of mass is the point where we may apply force and the linear acceleration will be on action but no angular acceleration would be seen.Here is given three identical square pieces of wood, each with length L . Now we are stacking the block three pieces at the edge of the horizontal.The centre of mass of the bottom most square piece in the stack is at {(l/4)^2 +(l/4)^2}^1/2= L/2(2)^1/2.To know more about centre of mass visit:
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A sled and rider with a combined weight of 70.0 kg are at rest on the top of a hill 11.0 m high. (Enter your answers in J.)(a)What is their total energy at the top of the hill? answer in______J(b)Assuming there is no friction, what would the total energy be on sliding halfway down the hill? answer in_______J(c)What would the total energy be at the bottom of the hill? answer in_________J
We will ahve the following:
a)
[tex]\begin{gathered} E=mgh \\ \\ \Rightarrow E=(70.0kg)(9.8m/s^2)(11.0m)\Rightarrow E=7546J \end{gathered}[/tex]So, the total energy will be 7546 J.
b) The total energy halfway must also be the same, but half of it will be kinetic energy and half potential energy.
c) The total energy at the bottom must be the same, but this time it will be all kinetic energy.
module 2 question 17
Figure 4.25
(a) What is the mass of the child and basket if a scale reading of 100 N is observed?
kg
(b) What is the tension T in the cord attaching the child to the scale?
N
(c) What is the tension T' in the cord attaching the scale to the ceiling, if the scale has a mass of 0.300 kg?
N
(d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible. (Do this on paper. Your instructor may ask you to turn in this work.)
a ) The mass of the child and basket = 5.61 kg
b ) The tension T in the cord attaching the child to the scale = 55 N
c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N
a ) The mass of the child and basket,
[tex]W_{b}[/tex] = 55 N
g = 9.8 m / s²
W = m g
[tex]m_{b}[/tex] = [tex]W_{b}[/tex] / g
[tex]m_{b}[/tex] = 55 / 9.8
[tex]m_{b}[/tex] = 5.61 kg
b ) In the cord attaching the child to the scale,
∑ [tex]F_{y}[/tex] = 0
T - W = 0
T = W
T = 55 N
c ) In the cord attaching the scale to the ceiling,
[tex]m_{s}[/tex] = 0.3 kg
[tex]W_{s}[/tex] = [tex]m_{s}[/tex] * g
[tex]W_{s}[/tex] = 0.3 * 9.8
[tex]W_{s}[/tex] = 2.94 kg
∑ [tex]F_{y}[/tex] = 0
T - [tex]W_{s}[/tex] - [tex]W_{b}[/tex] = 0
T = 2.94 + 55
T = 57.94 N
Therefore,
a ) The mass of the child and basket = 5.61 kg
b ) The tension T in the cord attaching the child to the scale = 55 N
c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N
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Question 8 of 10
Which change to a circuit is most likely to decrease its electrical power?
OA. Increase its voltage and increase its current.
о B. Decrease its voltage and decrease its current.
O C. Decrease its voltage and increase its current.
OD. Increase its voltage and decrease its current.
Decrease its voltage and decrease its current change to a circuit is most likely to decrease its electrical power.
The correct option is B.
What is voltage explain?When charged electrons (current) are forced through a conducting loop by the pressure of an electric circuit's power source, they may perform tasks like lighting a lamp. In a nutshell, voltage equal pressure and is expressed in volts.
What is the basic voltage unit?Electric potential difference, often referred to as voltage, is measured in units called volts. According to official definitions, a volt is the difference in potential between two locations on a wire that's also conveying a current of one ampere and dissipating one watt of power.
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if Ms. Avari is carrying a stack of books weighing 12 N up a flight of starts that is 10 meters high. How much work does Ms. Avari need to do to take the stack of books up the stairs? ( W = F x d )
F = force = 12 N
d = distance = 10 m
W= work
Apply:
W = F x d
Replacing:
W= 12 x 10 = 120 J
8.Sara took her solid gold ring to the jeweler for cleaning. While the jeweler was
cleaning, he mixed up the ring with another that is only gold-plated. How can the
jeweler determine which ring is Sara's? Hurry pls
The jeweler can determine which ring is Sara's by scratch test, acid test or magnet test.
Sara's solid gold ring is mixed with gold plated ring and now she has to identify which one is her real ring.
There are many method to identify if the ring is solid gold or not,
1. A scratch test. A scratch deep enough to penetrate till the metal of the gold-plated ring can tell if the ring is solid gold or not. The solid gold ring will be all uniformly distributed gold through the structure.
2. By acid test. By putting both the rings in the acid solution is can be found out which one is the real gold ring. The gold plated ring in the acid solution which eventually changes the color of the ring.
3. Magnet test. A very strong magnet will attract the gold plated ring but not solid gold ring because the solid gold rings are non-magnetic in nature.
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7. Conceptual 03 04 10 pts possible Someone in a car going past you at the speed of 41 m/s drops a small rock from a height of 1.6 m. How far from the point of the drop will the rock hit the ground? The acceleration due to gravity is 9.8 m/s². Answer in units of m.
Answer:
See below
Explanation:
Find out how long the vertical velocity and accel cause the rock to ground out....then multiply this time by the horizontal speed....then use pythag theorem for the TOTAL distance
df = do + vo t + 1/2 a t^2 df = final height = 0 do = original = 1.6 m
v o = original velocity = 0 accel = - 9.81 m/s^2
0 = 1.6 + 0 + 1/2 ( - 9.8)(t^2) shows t = .5714 seconds to hit the ground
horizontal distance = .5711 seconds * 41 m/s = 23.43 m
vertical distance = 1.6 m
TOTAL distance = sqrt (( 23.42)^2 + (1.6)^2 ) = 23.48 m
If questioner wants horizontal disance <=====use first answer
if Q wants TOTAL distance <====== use second answer
Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica.
Answer:
The frictional force between the wall and the ball
You have a parallel‑plate 5.13×10−6 F capacitor that is charged to 0.00967 C. While the capacitor is isolated, you change the plate separation so that the capacitance becomes 1.27×10−6 F. How much work do you perform in this process?
The work done to separate the plates of the parallel plate capacitor that's charged to a 0.00967 C is 2864.5 J
U = 1 / 2 C V²
U = Initial energy
C = Capacitance
V = Electric Potential
Q = Charge
C[tex]_{i}[/tex] = 5.13 μ F
Q[tex]_{i}[/tex] = 9.67 m C
C[tex]_{f}[/tex] = 1.27 μ F
As the capacitor is isolated, there'll be no further current flow and charge will remain constant.
Q[tex]_{f}[/tex] = Q[tex]_{i}[/tex] = 9.67 m C
Q = C V
Q² = ( C V )²
U[tex]_{i}[/tex] = 1 / 2 * C[tex]_{i}[/tex] * V[tex]_{i}[/tex]²
U[tex]_{i}[/tex] = 0.5 * ( C[tex]_{i}[/tex] * [tex]V_{i}[/tex] )² / C[tex]_{i}[/tex]
U[tex]_{i}[/tex] = 0.5 * Q[tex]_{i}[/tex]² / C[tex]_{i}[/tex]
U[tex]_{i}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 5.13 * [tex]10^{-6}[/tex] )
U[tex]_{i}[/tex] = 942.5 J
U[tex]_{f}[/tex] = 1 / 2 * C[tex]_{f}[/tex] * [tex]V_{f}[/tex]²
U[tex]_{f}[/tex] = 0.5 * ( C[tex]_{f}[/tex] * [tex]V_{f}[/tex] )² / C[tex]_{f}[/tex]
U[tex]_{f}[/tex] = 0.5 * Q[tex]_{f}[/tex]² / C[tex]_{f}[/tex]
U[tex]_{f}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 1.27 * [tex]10^{-6}[/tex] )
U[tex]_{f}[/tex] = 3807 J
W = U[tex]_{f}[/tex] - U[tex]_{i}[/tex]
W = 3807 - 942.5
W = 2864.5 J
Therefore, the work done to separate the plates of the parallel plate capacitor is 2864.5 J
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