(362-2) Electrical nonmetallic tubing is composed of a material that is resistant to moisture, chemical atmospheres, and is ______.

False. The grounded neutral of a balanced 3-wire delta circuit or balanced 4 wire wye circuit is not considered a current carrying conductor.

Current flows through the phase conductors in the circuit, and the grounded neutral serves as a reference point and a path for fault current to return to the source.

In a balanced system, the currents in each phase are equal in magnitude and evenly distributed, resulting in a net current of zero in the neutral conductor. Therefore, the grounded neutral is not considered a current-carrying conductor in this situation. It is typically used as a reference point for voltage measurements and as a return path for unbalanced current in the circuit. The current is carried by the other two or three conductors in the circuit.

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The acceleration due to gravity on this planet is 4 meters per second squared ([tex]m/s^2[/tex]).

To find the acceleration due to gravity on this planet, we can use the following equation:
distance = (1/2) * acceleration * time^2
Given that the object is released from rest, the initial velocity is 0. We're also given that the object falls a distance of 2 meters in 1 second. Plugging these values into the equation, we get:
2 meters = (1/2) * acceleration * (1 second)^2
Solving for acceleration:
4 meters = acceleration * (1 second)^2
4 meters = acceleration

This means that the gravity on this planet is weaker than Earth's gravity because Earth's gravity is [tex]9.8 m/s^2.[/tex]

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Using everyday objects like a paperclip or a cent, monitoring the development of droplets, or using a soap bubble, one can illustrate surface tension at home or in the lab.

With a force tensiometer and a Du Noüy ring or Wilhelmy plate, surface tension can be detected. Or you might use an optical tensiometer and the pendant drop technique.

A stalagmometer is a device used to calculate surface tension using the stalagmometric method. . A stactometer or stalogometer is another name for it. A hygrometer is a type of weather instrument used to gauge the humidity level in the air.

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The frequency of a sound wave affects the way our ears perceive sound:

1) A sound wave is created when an object vibrates and causes the molecules in the surrounding medium (such as air or water) to vibrate.

2) The frequency of a sound wave is the number of times that the object vibrates back and forth per second. This frequency is measured in hertz (Hz).

3) When a sound wave reaches our ears, it causes the eardrum to vibrate.

This vibration is then transmitted to the inner ear, where it is detected by hair cells in the cochlea.

4) The cochlea is a fluid-filled structure in the inner ear that contains hair cells that are sensitive to different frequencies of sound.

5) Hair cells in the cochlea that are closest to the entrance of the ear are most sensitive to high-frequency sounds, while hair cells at the other end of the cochlea are most sensitive to low-frequency sounds.

6) When a sound wave enters the ear, it causes the fluid in the cochlea to vibrate.

This vibration causes the hair cells that are sensitive to that frequency to bend.

7) The bending of the hair cells generates an electrical signal that is transmitted to the brain via the auditory nerve.

8) The brain then interprets the electrical signals from the hair cells as sound.

The frequency of the sound wave determines the pitch of the sound that we hear, with higher frequencies being perceived as high-pitched sounds and lower frequencies being perceived as low-pitched sounds.

In summary, the frequency of a sound wave determines which hair cells in the cochlea are activated, which in turn determines the pitch of the sound that we hear.

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Answer:

882J

Explanation:

PE=m×g×h

=3kg×9.8m/s^2×30m

=882kgm^2/s^2

=882J

improving the efficiency of internal combustion engines, is least likely to be a viable response to stop global warming. While it may reduce emissions slightly, it still relies on fossil fuels which are a major contributor to global warming. which are more effective in addressing global warming.

Rapidly expanding nuclear power generation is the least likely to be a viable response to stop global warming. While nuclear power is a low-carbon source of energy, it still poses significant risks and challenges, such as nuclear accidents, waste disposal, and proliferation concerns. The other options, improving the efficiency of internal combustion engines, replanting deforested areas of the world, and taxing the use of fossil fuels, are all viable responses that can help reduce greenhouse gas emissions and mitigate the impacts of global warming. Option a, improving the efficiency of internal combustion engines, is least likely to be a viable response to stop global warming. While it may reduce emissions slightly, it still relies on fossil fuels which are a major contributor to global warming.

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The heat engine operates by using a temperature difference between two thermal reservoirs and transferring energy from a hot reservoir to a cold reservoir. Usually, the efficiency of a heat engine is less than the maximum efficiency, which is the theoretical limit for the efficiency of the engine.

The important to keep the engine operating within a safe temperature range to prevent damage or failure.  A heat engine operates by using a temperature difference between two thermal reservoirs, transferring energy from a hot reservoir to a cold reservoir. In this process, it usually has an efficiency less than the maximum efficiency, as no engine can achieve 100% efficiency due to energy losses, primarily in the form of heat.

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The ratio of the tangential speed of a point on the end of the rod to that of a point a distance L/2 from the end of the rod is 2:1, which corresponds to option C.

The ratio of the tangential speed of a point on the end of the rod to that of a point a distance L/2 from the end of the rod can be determined using the formula for tangential speed, which is v = rω, where v is the tangential speed, r is the distance from the axis of rotation, and ω is the angular velocity.
For a point on the end of the rod (distance L), the tangential speed is

v₁ = Lω.

For a point at a distance L/2 from the end of the rod, the tangential speed is

v₂ = (L/2)ω.

To find the ratio, divide v1 by v2:
(v₁/v₂) = (Lω)/((L/2)ω)

The ω values cancel out, and we're left with:
(L)/(L/2) = 2/1

So, the ratio of the tangential speed is 2:1.

The correct answer is option C.

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The resistivity of metallic conductors nearly always tends to be low, making them efficient conductors of electricity.

The resistivity of metallic conductors nearly always decreases as the temperature increases. This is because metallic conductors, like metals, have a regular arrangement of atoms and free electrons that facilitate the flow of electric current, making them good conductors of electricity. However, as the temperature increases, the atoms in the conductor vibrate more, leading to increased collisions between electrons and atoms, which in turn reduces the overall resistivity.

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As water flow increases, friction losses in a water distribution pipeline typically increase.

As the stream expansions in a water dissemination pipeline, the erosion misfortunes in the pipeline commonly increment. This is on the grounds that the water coursing through the pipeline makes rubbing as it rubs against the walls of the line. The quicker the water streams, the more prominent the rubbing and consequently the more noteworthy the misfortunes. Moreover, at higher streams, the disturbance of the water likewise builds, which can additionally expand the rubbing misfortunes.

Notwithstanding, it is essential to take note of that the contact misfortunes in a pipeline can likewise be impacted by a few different variables, like the line material, breadth, length, unpleasantness, fittings, and twists. Consequently, now and again, it is conceivable that the rubbing misfortunes might diminish as the stream builds because of changes in these different variables.

By and large, the impact of expanding stream on erosion misfortunes in a water conveyance pipeline can fluctuate contingent upon a few elements, and it is essential to consider this multitude of variables while planning or examining a pipeline framework.

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The correct answer is b. Medicaid/medicare requirements. Medicaid and Medicare do not require that patients receive excessive exposure to X-rays as part of their care.

While the other options, such as technicians or physician error, malfunction of equipment, and fear of malpractice, have been suggested as reasons for Americans receiving excess exposure to X-rays, Medicaid/medicare requirements have not been identified as a contributing factor. In fact, both programs have specific guidelines for the appropriate use of X-rays to ensure that patients are not exposed to harmful levels of radiation.

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The scenario that a child sitting in front of a space heater could represent thermal energy transfer through radiation.

Thermal energy is described as the energy in an object or system due to the movement of its molecules and atoms.

Radiation occurs  when heat moves as energy waves, called infrared waves, directly from its source to something else. The process of radiation  is how the heat from the Sun gets to Earth.

On the other hand, electromagnetic radiation is a form of energy that is produced by oscillating electric and magnetic disturbance.

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complete question:

Which of the following represents thermal energy transfer through radiation

A)a thermometer sitting on top of a heat lamp

B)a person trying to unscrew a hot light bulb

C)a child sitting in front of a space heater

D)swimming in the pool and noticing that the deeper end of the pool is colder than the shallow end

The material used to cover electric wires and prevent the transmission of electricity is known as an insulator. Insulators are typically made of materials such as rubber, plastic, or glass.

Insulators are important for protecting people and objects from electrical shock and preventing electrical fires. Without insulation, electricity would be able to flow freely through wires, posing a significant safety risk.

In summary, the material used to cover electric wires and prevent the transmission of electricity is known as an insulator, which is essential for safety in electrical systems.

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D) Nicolaus Steno, seventeenth century. Nicolaus Steno made the first clear statement of the law of superposition in the seventeenth century.

The law of superposition is a fundamental principle in geology and states that in a sequence of undisturbed sedimentary rocks, the oldest layers are at the bottom and the youngest layers are at the top. The law of superposition states that in a sequence of sedimentary rock layers, the oldest layer is at the bottom and the youngest layer is at the top. Steno's law of superposition helped to advance the field of geology, as it was the first scientific principle to provide a reliable way to determine the relative age of geological strata. Steno's law of superposition was an important milestone in the development of modern geology and remains an essential tool for geologists today.

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The half-life of this radioactive substance is approximately 3.01 minutes. This means that if we start with a certain amount of this substance, it will take about 3.01 minutes for half of it to decay.

The half-life of a radioactive substance is defined as the time it takes for half of the initial amount of the substance to decay. To calculate the half-life of a substance, we can use the formula:

t1/2 = (ln 2) / λ

where t1/2 is the half-life, ln 2 is the natural logarithm of 2 (which is approximately 0.693), and λ is the decay constant.

In this problem, we are given that the activity of a sample drops by a factor of 5 in 8.7 minutes. This means that the remaining activity is 1/5th of the initial activity after 8.7 minutes. We can use this information to find the decay constant λ:

1/5 = e^(-λ * 8.7)

Taking the natural logarithm of both sides, we get:

ln (1/5) = -λ * 8.7

λ = ln (5) / 8.7

Substituting this value of λ into the formula for half-life, we get:

t1/2 = (ln 2) / (ln 5 / 8.7)

Simplifying this expression, we get:

t1/2 ≈ 3.01 minutes

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the amount of energy emitted from the patient's body in the form of gamma rays from radioactive decay of the FDG is 3.57 x 10^3 keV.

To calculate the amount of energy emitted from the patient's body in the form of gamma rays from radioactive decay of the FDG, we need to use the formula:

E = (N * A * t * e) / m

where E is the energy emitted, N is the number of radioactive atoms, A is the activity of the radioactive substance, t is the time elapsed, e is the energy per decay, and m is the mass of the substance.

We know that the half-life of 18F is 110 minutes, which means that the activity of the substance decreases by half every 110 minutes.

After 110 minutes, the remaining amount of FDG will be 2.5 grams (half of 5 grams). After another 110 minutes (220 minutes total), it will be 1.25 grams. After another 110 minutes (330 minutes total), it will be 0.625 grams. And after another 110 minutes (440 minutes total), it will be 0.3125 grams.

Therefore, after 5 hours and 30 minutes (330 + 110 minutes), the remaining amount of FDG will be 0.625 grams.

To calculate the energy emitted, we need to know the number of radioactive atoms, which can be calculated by dividing the mass by the molar mass and then multiplying by Avogadro's number. The molar mass of FDG is 181 g/mol, so 5 grams of FDG is equal to 5/181 * 6.022 x 10^23 = 1.67 x 10^22 atoms.

The energy per decay of FDG is 0.634 MeV = 634 keV.

Putting all these values into the formula, we get:

E = (1.67 x 10^22 * 0.5 * 330 * 634) / 0.181 = 3.57 x 10^3 keV

Therefore, the answer is A. 3.57 x 10^3 keV.

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Given statment "Absolute zero corresponds to about -273K." is true.

Absolute zero is the theoretical temperature at which all matter has zero thermal energy. It is the lowest possible temperature that can be achieved, and it corresponds to about -273.15 degrees Celsius or -459.67 degrees Fahrenheit.

This temperature is considered to be the baseline for all other temperatures, as it represents the absence of any thermal energy. At absolute zero, all matter would be in a state of perfect order, with no movement or energy.

The concept of absolute zero was first proposed by William Thomson (Lord Kelvin) in the 19th century, and its importance in the field of physics cannot be overstated. It forms the basis of many important theories, such as the laws of thermodynamics and quantum mechanics.

Scientists have been able to achieve temperatures very close to absolute zero in the laboratory using various cooling techniques, such as laser cooling and evaporative cooling.

These ultra-cold temperatures have allowed researchers to study the behavior of matter in ways that were previously impossible.

In conclusion, absolute zero does indeed correspond to about -273K, making it one of the most fundamental concepts in physics. Its discovery and study have revolutionized our understanding of the natural world and continue to drive scientific innovation today.

So, given statment is true.

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Because of its variable internal temperature, a temperature regulator has a variable metabolic rate. The metabolic rate of an organism is closely linked to its internal temperature, as chemical reactions occur at different rates at different temperatures.

When the internal temperature is lower, the metabolic rate will also be lower as chemical reactions occur more slowly. However, when the internal temperature is higher, the metabolic rate will increase as chemical reactions occur more quickly. Therefore, a variable internal temperature will result in a variable metabolic rate.

Because of its constant internal temperature, a temperature regulator has high metabolic rate.
Your answer: B) constant; high.

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Answer:

Option A is the correct option

Compression is to crest as rarefaction is to Trough.

Hence, the correct option is B.

Because

In a longitudinal wave, compression refers to the region where the particles are closer together, while rarefaction refers to the region where the particles are farther apart.

The crest and trough, on the other hand, are terms used in transverse waves to describe the highest and lowest points of the wave, respectively. Therefore, in this analogy, rarefaction is equivalent to the trough.

Hence, the correct option is B.

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The height of the tree is approximately 3.79 meters, rounded to the nearest hundredth.

Let's use similar triangles to find the height of the tree.
Step 1: Identify the similar triangles.
- Triangle 1: Ivan, his shadow, and the ground (right triangle)
- Triangle 2: The tree, its shadow, and the ground (right triangle)
Step 2: Set up the proportion.
Since the triangles are similar, we can write the following proportion:
\frac{(height of tree) }{(length of tree's shadow)}

= \frac{(height of Ivan) }{(length of Ivan's shadow)}
Step 3: Find the length of Ivan's shadow.
The length of Ivan's shadow is the difference between the total length of the tree's shadow (34.03 m) and the distance Ivan walked (18.12 m):
Length of Ivan's shadow = 34.03 m - 18.12 m = 15.91 m
Step 4: Plug in the known values into the proportion and solve for the height of the tree.
\frac{(height of tree) }{ (34.03 m) }

= \frac{(1.78 m) }{ (15.91 m)}
Step 5: Cross-multiply and divide to find the height of the tree.
height of tree =\frac{ (1.78 m × 34.03 m) }{ 15.91 m}

=\frac{ 60.29 m }{ 15.91 m}

= 3.79 m

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The true statements are: 2. entropy is a thermodynamic property, 4. the performance of engineering systems is degraded by the presence of irreversibilities, and 5. entropy used as measure of irreversibilities.

Based on the given terms, here is an analysis of the statements about the entropy process:

1. Processes can occur in any direction without any restriction - False. Entropy is associated with the second law of thermodynamics, which states that for natural processes, entropy tends to increase, indicating a preferred direction.
2. Entropy is a thermodynamic property - True. Entropy is a state function that measures the energy dispersal in a system, and it is an essential property in thermodynamics.
3. The greater the extent of irreversibilities during a process, the smaller the entropy generation - False. The opposite is true. The greater the extent of irreversibilities, the larger the entropy generation.
4. The performance of engineering systems is degraded by the presence of irreversibilities - True. Irreversibilities, such as friction and heat transfer, reduce the overall efficiency of engineering systems.
5. Entropy generation can be used as a quantitative measure of irreversibilities - True. The amount of entropy generated in a process can serve as an indicator of the irreversibilities associated with that process.

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The peak current for this circuit is A. 3.5 μA

To find the peak current in a series LRC circuit with given values, we first need to determine the impedance (Z) of the circuit. We can use the following formula,

Z = √(R² + (XL - XC)²)

where,
R = resistance,
XL = inductive reactance
XC = capacitive reactance.

We can calculate the XL and XC as follows,
XL = 2 * π * f * L
XC = 1 / (2 * π * f * C)

The given values are:
f = 197 kHz (frequency)
R = 41 kΩ (resistance)
C = 14 μF (capacitance)
L = 63 H (inductance)

Now, we can calculate XL and XC:

XL = 2 * π * 197000 * 63 ≈ 77.5 MΩ
XC = 1 / (2 * π * 197000 * 14 * [tex]10^{(-6)}[/tex]) ≈ 57.4 Ω

Next, we find the impedance (Z):

Z = √((41000)² + (77500000 - 57.4)²) ≈ 77.5 MΩ

Now we can calculate the peak current (I_peak) using Ohm's Law:

I_peak = V_peak / Z

I_peak = 270 V / 77.5 MΩ ≈ 3.48 μA

Therefore, the peak current for this circuit is approximately 3.5 μA, which corresponds to option A.

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The dimensions given are 3, 4, and 5. This forms a right triangle, which is also known as an isosceles triangle. Therefore, the code word is "ISOSCELES".

Dimensions is a term used to describe the size and shape of an object. It is typically used in mathematics, physics, and engineering to measure the length, width, height, and depth of an object or surface. It is also used to describe the size, shape, and relative position of objects in space. Dimensions can be expressed in absolute units such as meters, centimeters, and inches, or in relative units such as proportions and ratios. In some cases, dimensions can also be expressed as angles, curves, or nonlinear equations. Knowing the dimensions of an object can help determine its volume, surface area, and other properties, and can be used to compare the size and shape of different objects.

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The ratio of their speeds (vs/vm) can be found by using the equation for kinetic energy, which is KE = 1/2 mv^2, where KE is kinetic energy, m is mass, and v is velocity/speed.

Since both the mother and son have the same kinetic energy, we can set their individual equations equal to each other and solve for the ratio of their speeds: 1/2 (4m) v_m^2 = 1/2 m v_s^2, Simplifying, we get: v_s/v_m = sqrt(4), v_s/v_m = 2
Therefore, the ratio of their speeds is 2.

Since the mother has four times the mass of her son (Mm = 4 * Ms), and both have the same kinetic energy, we can set up the following equation: 0.5 * Ms * Vs^2 = 0.5 * (4 * Ms) * Vm^2, Now, we can simplify the equation and solve for the ratio of their speeds (Vs / Vm): Vs^2 = 4 * Vm^2.

Taking the square root of both sides: Vs = 2 * Vm
Thus, the ratio of their speeds is Vs / Vm = 2 / 1 or 2.00, using two significant figures.

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Answer:

Approximately [tex]6\; {\rm Mpc}[/tex] (assuming that [tex]H_{0} \approx 70\; {\rm km \cdot s^{-1} \cdot Mpc^{-1}}[/tex].)

Explanation:

The speed at which a distant object moves away from the observer is known as recessional velocity.

By Hubble's law, the recessional velocity [tex]v[/tex] of a distant galaxy would be proportional to the distance [tex]D[/tex] from the observer:

[tex]v = H_{0}\, D[/tex],

Where [tex]H_{0}[/tex] is Hubble's Constant.

The value of Hubble's Constant varies over time. Assuming that [tex]H_{0} \approx 70\; {\rm km \cdot s^{-1} \cdot Mpc^{-1}}[/tex]. Rearrange Hubble's Law to find distance [tex]D[/tex]:

[tex]\begin{aligned}D &= \frac{v}{H_{0}} \\ &\approx \frac{407\; {\rm km\cdot s^{-1}}}{70\; {\rm km\cdot s^{-1} \cdot Mpc^{-1}}} \\ &\approx 6\; {\rm Mpc}\end{aligned}[/tex].

A14 AWG conductor and a 30A short-circuit protection device are required for a 2 horsepower, 12 ampere motor rated at 230 volts.

2 horsepower (12 ampere) motor rated at 230 volts, the required branch circuit conductor size and short-circuit protection can be determined using the NEC (National Electrical Code) guidelines found in sections 240-6(a) and 430-52(b).
For the conductor size, multiply the motor's full-load current (12A) by 125%: 12A x 1.25 = 15A. According to NEC 240-6(a), a 14 AWG conductor with a rating of 15A is suitable for this motor.

The term "ampacity" is used to describe the ampere capacity as specified by the National Electrical Codes.

A conductor's ampacity is the greatest continuous current, measured in amperes, that can pass through it under normal use conditions without going above the conductor's recommended operating temperature.

As a result, the National Electrical Code refers to conductors' capacities for carrying current as ampacity.
For short-circuit protection, NEC 430-52(b) allows for up to 250% of the motor's full-load current: 12A x 2.5 = 30A. Therefore, you can use a 30A circuit breaker or fuse for short-circuit protection.

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The answer is (D) 0J. The total kinetic energy of the system before the collision can be calculated as:

KE_before = (1/2)mv1^2 + (1/2)mv2^2

where m is the mass of the object and v1 and v2 are the velocities of the clay and metal sphere, respectively.

Substituting the given values, we get:

KE_before = (1/2)(1.0 kg)(2 m/s)^2 + (1/2)(0.5 kg)(-4 m/s)^2

= 2 J + 4 J

= 6 J

Note that the velocity of the metal sphere is negative because it is moving to the left.

After the collision, the two objects stick together and move as one object with a new velocity, which can be calculated using the law of conservation of momentum:

m1v1_before + m2v2_before = (m1 + m2)v_after

where m1 and v1_before are the mass and velocity of the clay before the collision, m2 and v2_before are the mass and velocity of the metal sphere before the collision, and v_after is the velocity of the combined objects after the collision.

Substituting the given values, we get:

(1.0 kg)(2 m/s) + (0.5 kg)(-4 m/s) = (1.0 kg + 0.5 kg)(v_after)

2 kg m/s - 2 kg m/s = 1.5 kg v_after

v_after = 0 m/s

Thus, the velocity of the combined objects after the collision is zero, meaning they come to a complete stop. Therefore, the kinetic energy of the combined objects after the collision is:

KE_after = (1/2)(m1 + m2)v_after^2

= (1/2)(1.0 kg + 0.5 kg)(0 m/s)^2

= 0 J

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B) only in or near star-forming clouds. Red and orange stars are found evenly spread throughout the galactic disk, but blue stars are typically found only in or near star-forming clouds.

This is because blue stars are generally younger, massive, and hotter, and they have shorter lifespans compared to red and orange stars. They do not live long enough to spread out across the galactic disk.These regions are known as star-forming clouds, or nebulae. Blue stars are very bright and hot, and emit a lot of ultraviolet radiation, which is useful for star formation. They also tend to be short-lived, and eventually fade away.

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b. False. When two identical sound levels are combined, the overall level increases by only 3 dB, not 10 dB. This is due to the logarithmic nature of the decibel scale.

Two identical sound level will not increase the overall level by 10 dB. In reality, the increase in the overall sound level is only 3 dB. This is because sound levels are measured on a logarithmic scale. This means that the actual increase in sound pressure is not linear and a doubling of the sound pressure level only produces an increase of 3 dB.This means that the increase in overall sound level is much less than might be expected from a simple additive process, and is usually 3 dB or less.

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