(3)(6)(-2)

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Answer:

Step 2

Step-by-step explanation:

Solving

The error has occurred in Step 2.

The distribution of -2 to 6y and -5 gives -12y and 10 respectively.

Instead, the distribution has not happened between -2 and -5.

Answer:

C

Step-by-step explanation:

Because it's a negative, then we could assume that it is a negative correlation. And because it's closer to -1, it is a strong negative correlation.

The value -0.993 is Strong Negative correlation.

The strength and direction of two variables in a scatterplot are quantified by the correlation coefficient, or r value. It goes from one to one.

So, the value close to 1 is Strong positive correlation and close to -1 is Strong Negative correlation.

Thus, -0.993 close to -1 is Strong Negative correlation.

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The value of P(B)=17 for the given value P(A or B) = 13, P(A)= 14, and P(A and B) = 18.

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Here is the formula for the probability of an exclusive event:-

[tex]P(AUB)=P(A)+P(B)-P(A\cap B)[/tex]

[tex]13=14+P(B)-18[/tex]

[tex]P(B)=17[/tex]

hence the value of P(B)=17 for the given value P(A or B) = 13, P(A)= 14, and P(A and B) = 18.

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Answer: 3

Step-by-step explanation:

Answer:

You each will pay $40.35

Step-by-step explanation:

First you take the total  $134.50 and divide it by 4 which is you and your three friends.

This will give you 33.625 which is the amount each of you will pay without tip.

To find the tip you take 20% from $134.50 which will give you 26.9 and when you divide that by the four of you it will give you 6.725.

Then you take your amount 33.625 plus your tip 6.725 which will give you $40.35.

The total you all will pay will be $161.40 this is the total $134.50 plus the tip $26.90.

Hope this helped.

The period of the given function is  2π/3, the phase shift is 4, and the vertical shift is 6 units.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a trigonometric function:

y = csc[3(x+ 4)]+ 6

Every each revolution of 2π the function repeats the same value for every x.

The period of the original function is 2π

For the given function plug 2π

y = csc[3(x+ 4)+2π]+ 6

y = csc[3(x+ 2π/3+4)]+ 6

The period of the function will be 2π/3

From the function, the phase shift = 4

And vertical shift = 6

Thus, the period of the given function is  2π/3, the phase shift is 4, and the vertical shift is 6 units.

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Option 3

Step-by-step explanation:

596/1000 and 59.6%

Step-by-step explanation:

because when we make 596/1000 is 0.596

Answer:

a= 20

Step-by-step explanation:

12/3

a/5

60 = 3a

a = 60/3 = 20

The equation of the asymptote of the hyperbola is y = 3x + 10

From the complete question the asymptote passes through the points:

(x,y) = (-1, 7) and (-3,1)

The slope of the line is calculated using:

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

So, we have:

[tex]m = \frac{7 - 1}{-1 + 3}[/tex]

This gives

m = 3

The equation is then calculated using:

y = m(x -x1) + y1

This gives

y = 3(x + 1) + 7

Evaluate

y = 3x + 3 + 7

y = 3x + 10

Hence, the equation of the asymptote is y = 3x + 10

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The length of the diagonal will be 538.5 ft. Then the rate at which the angle from the man to the car is changing at the same moment will be 46.43 ft/s.

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

A man stands 200 ft to the left of where a car starts moving north. The car is moving at 50ft/sec.

The rate at which the diagonal distance from the man to the car is changing once the car has been traveling for 10 seconds. Then the length of the diagonal will be

L² = x² + y²

L² = 200² + (50 × 10)²

L² = 40000 + 250000

L² = 290000

L = 538.50 ft

Then the rate at which the angle from the man to the car is changing at the same moment will be

L² = x² + y²

Differentiate with respect to time, then we have

         2L (dL/dt) = 0 + 2y (dy/dt)

2(538.5) (dL/dt) = 2 (500) (50)

                dL/dt = 46.43 ft/sec

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Answer:

I'm sorry but I need some numbers to solve. we just learned this in class so I'm new though

Step-by-step explanation:

Needs numbers

Answer:

2

5

Step-by-step explanation:

fraction of girls in the class is 6

5

so........the total number of girls is 6 and only 2 are chosen,meaning you have to subtract 2 from 6 which is 4 and then 4

10(total number of students) is

2

5 when simplified

Answer:

10

Step-by-step explanation:

[tex]\frac{6}{2.5} =\frac{25}{x} \\6x=2.5*25\\6x=62.5\\x=10.417=10[/tex]

The Tree casts a height of 10.41 feet tall.

In general, the term "proportion" refers to a part, share, or amount that is compared to a total.

According to the concept of proportion, two ratios are in proportion when they are equal.

According to proportion, two sets of provided numbers are said to be directly proportional to one another if they increase or decrease in the same ratio. "::" or "=" are symbols used to indicate proportions.

Given:

Connor is 6 feet tall and casts a shadow that is 2.5 feet long.

He stands next to a tree that is 25 feet tall.

let the shadow of tree is x feet long.

Using proportion

6/ 2.5 = 25/x

6x = 62.5

x= 10.41 feet

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Answer:

I think your answer is A, correct me if I'm wrong

Higher Order Thinking There are points on a grid at (0, 0) and (3, 0).

a. What is a possible coordinate of the third vertex if the triangle has

a perimeter of 11 units? Explain.

b. Is there another point that could be the third vertex? Explain.

par poib

signe

Answer:

24 because it is the middle number

Step-by-step explanation:

Using the t-distribution, it is found that the 90% confidence interval is of  2.71 hours to 3.29 hours.

The confidence interval is:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which:

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 25 - 1 = 24 df, is t = 2.0639.

The other parameters are given as follows:

[tex]\overline{x} = 3, s = \sqrt{0.5} = 0.707, n = 25[/tex]

Hence the bounds of the interval are given as follows:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 3 - 2.0639\frac{0.707}{\sqrt{25}} = 2.71[/tex]

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 3 + 2.0639\frac{0.707}{\sqrt{25}} = 3.29[/tex]

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Step-by-step explanation:

(3m-4)² + 8(3m-2) = (3m-4)(3m-4) + 24m - 16 =

= 9m² - 3m×4 - 4×3m + 16 + 24m - 16 =

= 9m² - 24m + 16 + 24m - 16 = 9m²

so, there is seemingly something missing in your original expression.

going from 9m², the most likely solution would be 9m/4 and therefore B.

but we cannot be sure, because again, I don't know what you left out in the beginning.

Answer:

r= 5.35

Step-by-step explanation:

Answer:

the radius is .... 5.35 :P

kaii~

Answer:

a

Step-by-step explanation:

raise to five

less than

ten times

Answer:

20%

Step-by-step explanation:

2:10 = 2/10 = 20/100 = 20%

Answer:

6 quarts of salsa in all

"Twice" indicates multiplying by 2, so multiply 2 by 2 to get 4.

That's not the end of the problem, though. "In all" indicates that we must add the values together. 2 plus 4 is 6, so your answer is 6.

Answer:

[tex]V=12\pi\:\text{units}^3[/tex]

Step-by-step explanation:

[tex]\displaystyle V=\frac{\pi r^2h}{3}\\ \\V=\frac{\pi (3)^2(4)}{3}\\\\V=\pi(3)(4)\\\\V=12\pi[/tex]

Step-by-step explanation:

[tex](3x + 1) + 8(2x - 3) = 4(3x - 1) - 7(x - 4) \\ 3x + 1 + 16x - 24 = 12x - 4 - 7x + 28 \\ 19x - 23 = 5x + 24 \\ 19x - 5x = 24 + 23 \\ 14x = 47 \\ x = \frac{47}{14} [/tex]

Answer:

It is the fourth option, D.

Recall that for all [tex]z\in\Bbb C[/tex],

[tex]\sin(z) = \dfrac{e^{iz} - e^{-iz}}{2i}[/tex]

so that

[tex]\sin(z) = a \iff e^{iz} - e^{-iz} = 2ia[/tex]

Multiply both sides by [tex]e^{iz}[/tex] to get a quadratic equation,

[tex]e^{2iz} - 2iae^{iz} - 1 = 0[/tex]

Solve for [tex]e^{iz}[/tex]. By completing the square,

[tex]e^{2iz} - 2ia e^{iz} + i^2a^2 = 1 + i^2a^2[/tex]

[tex]\left(e^{iz} - ia\right)^2 = 1 - a^2[/tex]

[tex]e^{iz} - ia = \pm \sqrt{1-a^2}[/tex]

[tex]e^{iz} = ia \pm \sqrt{1-a^2}[/tex]

[tex]iz = \log\left(ia \pm \sqrt{1-a^2}\right)[/tex]

[tex]iz = \ln\left|ia \pm \sqrt{1-a^2}\right| + i \left(\arg\left(ia \pm \sqrt{1-a^2}\right) + 2\pi n\right)[/tex]

[tex]\boxed{z = -i \ln\left|ia \pm \sqrt{1-a^2}\right| + \arg\left(ia \pm \sqrt{1-a^2}\right) + 2\pi n}[/tex]

where n is any integer.

We are given with:

[tex]{\quad \qquad \longrightarrow \sin (z)={\sf a}\:,\:z\in \mathbb{C}}[/tex]

Recall the identity what we have for the sine function of complex numbers

Put the values to thus obtain:

[tex]{:\implies \quad \sf \dfrac{e^{\iota z}-e^{-\iota z}}{2\iota}=a}[/tex]

[tex]{:\implies \quad \sf e^{\iota z}-e^{-\iota z}=2a\iota}[/tex]

Multiply both sides by [tex]{\sf e^{\iota z}}[/tex]

[tex]{:\implies \quad \sf e^{\iota z}\cdot e^{\iota z}-e^{-\iota z}\cdot e^{\iota z}=2a\iota e^{\iota z}}[/tex]

[tex]{:\implies \quad \sf (e^{\iota z})^{2}-2a\iota e^{\iota z}-1=0}[/tex]

Put x = [tex]{\sf e^{\iota z}}[/tex]:

[tex]{:\implies \quad \sf x^{2}-2a\iota x-1=0}[/tex]

Find the discriminant, here D will be, D = (-2ai)² - 4 × 1 × (-1) = 4 - 4a² = 4(1-a²)

Now, By quadratic formula:

[tex]{:\implies \quad \sf x=\dfrac{-(-2a\iota)\pm \sqrt{4(1-a^{2})}}{2}}[/tex]

[tex]{:\implies \quad \sf x=\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}}[/tex]

[tex]{:\implies \quad \sf e^{\iota z}=\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}}[/tex]

[tex]{:\implies \quad \sf \iota z=log\bigg(\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}\bigg)}[/tex]

Using the formula for logarithms, we have:

[tex]{:\implies \quad \sf \iota z=log(a\iota \pm \sqrt{1-a^{2}})-log(2)}[/tex]

[tex]{:\implies \quad \sf z=\dfrac{1}{\iota}log(a\iota \pm \sqrt{1-a^{2}})-\dfrac{1}{\iota}log(2)}[/tex]

The sine function is periodic on 2πn and zero on (π/2), and the logarithmic expression becomes undefined for all ia±√(1-a²) < 0, so we will take modulus of it

[tex]{:\implies \quad \boxed{\bf{z=\dfrac{1}{\iota}log\bigg|a\iota \pm \sqrt{1-a^{2}}\bigg|-\dfrac{1}{\iota}log(2)+\dfrac{\pi}{2}+2\pi n\:\:\forall \:n\in \mathbb{Z}}}}[/tex]

Answer:

Option 1

Step-by-step explanation:

The statement which is most likely correct about the line is :