2 or more forces that are not equal and opposite of one another can cause change in motion

A. Balanced force

B.friction

C.gravitational force

D.unbalanced force

Answer:

D. Brain

~PumpkinSpice1

Answer:

0.322 mols of NaSO4

Explanation:

Molality = Mols of Solute / kg of Solvent

Molality is given as 0.140 m = mols/kg

kg of solution is given as 2.30 kg

Mols of Solute = Molality * kg of Solvent

Mols of Solute = [tex]\frac{0.140 }{ 1 kg } *2.30 kg[/tex]

Mols of Solute = 0.322 mols

The number of mole of Na₂SO₄ required to prepare the solution is 0.322 mole

The Molality of a solution is defined as the mole of solute per Kg of water i.e

Molality = mole / mass (Kg) of water.

With the above formula, we can obtain the mole of Na₂SO₄ in the solution as follow:

Molality of Na₂SO₄ = 0.140 M

Mass of water = 2.30 Kg

Mole = Molality × mass of water

Mole of Na₂SO₄ = 0.140 × 2.30

Therefore, the mole of Na₂SO₄ in the solution is 0.322 mole

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Answer:

c. 0.200 M HCI(aq)

Explanation:

The titration of a base as NH3 with hydrochloric acid is:

NH3 + HCl → NH4Cl

Where 1 mole of NH3 reacts per mole of HCl

The recommended volume to read in a burette is between 60 and 80% of its capacity.

That is 60% 50.0mL = 30mL and 80% 50.0mL = 40mL must be spent.

A 6.00M HCl spend:

20mL * (0.3mol/L) * (1L/ 6.00M) = 1mL. This solution is not the ideal for the titration.

A 0.3M HCl spend:

20mL * (0.3mol/L) * (1L/ 0.3M) = 20mL. This solution is not the ideal for the titration.

A 0.200M HCl spend:

20mL * (0.3mol/L) * (1L/ 0.200M) = 30mL. This solution ideal for the titration.

A 0.100M HCl spend:

20mL * (0.3mol/L) * (1L/ 0.100M) = 60mL. This solution is not the ideal for the titration.

Right option is:

Answer:

Florida's Global Pattern.

Explanation:

Because of where Florida sits, the weather in the Gulf of Mexico actually blows enough water to Create tidal waves, and also hurricanes. at least that's what I was told cause I live here :>

Answer:

See explanation

Explanation:

a. I can conclusively tell if the crown was made of gold by measuring its density. First the mass of the crown is measured on a weighing balance. The crown is now put into a given volume of water and the volume of water displaced is accurately measured. The density of the crown is computed as mass/volume of fluid displaced. If the density of the crown is 19.3 g/mL, then it is made of solid gold.

b) When less valuable metals such as bronze or copper is mixed with gold in the crown, the density of the crown decreases and the crown becomes more brittle.

c) An object will float in a liquid when the density of the object is less than the density of the liquid. Hence the tendency of an object to float in a liquid depends on the density of the object and the density of the liquid.

d) Even though i do not know the results from your experiment but as regards the decision as to whether the object will float in the given liquid or not, reference must be made to the measured density of the object as well as the given density of the liquid. If the object is less dense (from values of density obtained from the experiment)  than the liquid, then the object will float in the liquid and vice versa.

Answer:

It lights on fire

Explanation:

The friction sparks the match causing it to go on fire.

Answer:

The viscosity [tex]\mathbf{\eta = 7.416 \times 10^{-4} \ N.s/m^2}[/tex]

Explanation:

From the given information:

Time t = 1.55 s

The radius of capillary = 5.00 μm /2

The pressure drop ΔP = 2.45 kPa

The length of the capillary = 2.00 mm

∴

The viscosity of the blood flow can be calculated by using the formula:

[tex]\eta = \dfrac{r^2 \Delta P }{8Lv}[/tex]

where;

v = L/t

Then;

[tex]\eta = \dfrac{r^2 \Delta P }{8L(\dfrac{L}{t})}[/tex]

[tex]\eta = \dfrac{(\dfrac{5 \times 10^{-6} \ m}{2})^2(2.45 \times 10^3 \ Pa) }{8(2.0 \times 10^{-3} \ m ) (\dfrac{2.0 \times 10^{-3} \ m }{1.55 \ s })}[/tex]

[tex]\eta = 7.416 \times 10^{-4} \ Pa.s[/tex]

To (N.s/m²)

[tex]\mathbf{\eta = 7.416 \times 10^{-4} \ N.s/m^2}[/tex]

Answer:

compound is sp3.

Explanation:

Answer:

A

Explanation:

gyx3gevedyhsdv

The branch of science which deals with chemicals and bonds is called chemistry.

The correct answer is A.

The polarity is defined as the separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment, with a negatively charged end and a positively charged end.

The polar molecule has the following:-

In, the first compound the polarity is the same because the compound is the same that is O-F and CL-F.

Hence, the correct answer is A.

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Answer:

Total gas pressure is 1.60 atm

Explanation:

To solve this question we can use the Ideal Gases Law. We need to determine how many moles of each gas will be finally present at the flask of 7 L.

Let's asume the gas, are at Asbsolute T°, 273K

P. V = n . R . T

3.5 atm . 2L = n . 0.082 . 273K

(3.5 atm . 2L) / (0.082 . 273K) = 0.313 moles

(2.8 atm . 1.5L) / (0.082 . 273K) =  0.188 moles

Total moles = 0.313 mol + 0.188 mol = 0.501 mol

Let's calcualte the hole pressure

P . 7L = 0.501 moles . 0.082 . 273K

P = (0.501 moles . 0.082 . 273K) / 7L → 1.60 atm

Answer:

the word subcellular means contained within a cell. at a level of organization lower than the cellular.

Explanation:

Answer:

Under balanced its motion under motion its s = d/t under s - d/t is time d = distance s= speed

Explanation:

Answer:

18

Explanation:

36 times 0.5

Answer:

0.561 M

Explanation:

Step 1: Given data

Step 2: Calculate the molar concentration of aluminum chloride (C)

We will use the following expression.

[tex]C = \frac{m}{M \times V(L) } = \frac{0.375g}{133.34 g/mol \times 0.0150L } = 0.187M[/tex]

Step 3: Write the reaction of dissociation of aluminum chloride

AlCl₃(aq) ⇒ Al³⁺(aq) + 3 Cl⁻(aq)

Step 4: Calculate the concentration of chloride ions

The molar ratio of AlCl₃ to Cl⁻ is 1:3. The concentration of Cl⁻ is 3/1 × 0.187 M = 0.561 M

Answer:

B.

Explanation:

ive done this before trust

Answer:

option C is correct

Explanation:

Considering the ideal gas law and the definition of Avogadro's Number, the correct option is option a. The temperature of a sample of CH₄ gas (10.34 g) in a 50.0 L vessel at 1.33 atm is 984 °C.

In first place, you have to know that ideal gases are a simplification of real gases that is done to study them more easily.

It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T).

The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P×V = n×R×T

In this case, being the molar mass of CH₄ being 16 [tex]\frac{g}{mole}[/tex], that is, the mass present in one mole of an element or compound, the number of moles that 10.34 grams contains is calculated as:

[tex]10.34 g*\frac{1 mole}{16.04 g} = 0.645 moles[/tex]

So, you know:

Replacing:

1.33 atm × 50 L= 0.645 moles× 0.082 (atm×L)/ (mol×K) ×T

Solving:

T= [1.33 atm × 50 L] ÷ [0.645 moles× 0.082 (atm×L)/ (mol×K) ]

T≅ 1257 K

Being 273 K equivalent to 0 C, then:

T= 1257 K= 984 C

In summary, the correct option is option a. The temperature of a sample of CH₄ gas (10.34 g) in a 50.0 L vessel at 1.33 atm is 984 °C.

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Answer:

a) 0.03050 = 3.050 × 10-²

b) 0.256 x 10°= 2.56 × 10-¹

c) 25.005 10 =​ 2.500510 × 10¹

Explanation:

Scientific notations is a way of making very large or very small numbers more comprehensive or simplified. It involves the use of power of ten (10^). The numbers are represented to the power of ten. The following format is used:

a x 10^b

where; a is a number or decimal number between 1 and 10 i.e less than 10 but greater than 1

b is the power of ten

To write a number in scientific notation,

- we move the decimal point right or left depending on whether we're trying to reduce or increase the number

- we count the number of times the decimal point was moved. This serves as the b in the format above.

For example,

a) 0.03050 = 3.050 × 10-²

The decimal point was moved rightward twice. This caused the ^-2 power.

b) 0.256 x 10°= 2.56 × 10-¹

The decimal point was moved rightward once. This caused the ^-1 power.

c) 25.005 10 =​ 2.500510 × 10¹

The decimal point was moved leftward once. This caused the ^1 power.

The question is incomplete, the complete question is shown in the image attached

Answer:

F

T

Explanation:

From the equilibrium equation;

N2O4(g) ⇄NO2(g)

We must have to remember that;

1) At equilibrium, the concentration of the species on both sides of the reaction equation may not necessarily be the same but must be held at a constant value because the rate of forward reaction equals the rate of reverse reaction.

2) The rate of forward reaction must equal the rate of reverse reaction.

If the rate of forward reaction is k1 and the rate of reverse reaction is k2. Then it follows that at equilibrium k1 = k2.

Answer:

[tex]\Delta P=4.10atm[/tex]

Explanation:

Hello!

In this case, since the ideal gas equation is used under the assumption of no interaction between molecules and perfectly sphere-shaped molecules but the van der Waals equation actually includes those effects, we can compute each pressure as shown below, considering the temperature in kelvins (22.3+273.15=295.45K):

[tex]P^{ideal}=\frac{nRT}{V}=\frac{15.0mol*0.08206\frac{atm*L}{mol*K}*295.45K}{8.00L}=45.5atm[/tex]

Next, since the VdW equation requires the molar volume, we proceed as shown below:

[tex]v=\frac{8.00L}{15.0mol}=0.533\frac{L}{mol}[/tex]

Now, we use its definition:

[tex]P^{VdW}=\frac{RT}{v-b} -\frac{a}{v^2}[/tex]

Thus, by plugging in we obtain:

[tex]P^{VdW}=\frac{0.08206\frac{atm*L}{mol*K}*295.45K}{0.533mol/L-0.0430L/mol} -\frac{2.300L^2*atm/mol^2}{(0.533L/mol)^2}\\\\P^{VdW}=49.44atm-8.09atm\\\\P^{VdW}=41.4atm[/tex]

Thus, the pressure difference is:

[tex]\Delta P=45.5atm-41.4atm\\\\\Delta P=4.10atm[/tex]

Best regards!

The enthalpy : 49.1 kJ/mol

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways  

Reaction

1. 2C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol

Reverse

12 CO₂ (g) + 6 H₂O (g) ⇒ 2C₆H₆ (l) + 15 O₂ (g) ∆H° = 6271 kJ/mol : 2

6CO₂ (g) + 3H₂O (g) ⇒ C₆H₆ (l) + 15/2 O₂ (g) ∆H° = 3135.5 kJ/mol

2. 2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.6 kJ/mol  x 3/2

3H₂ (g) + 3/2O₂ (g) → 3H₂O (g) ∆H° = -725.4 kJ/mol

3. C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/mol x 6

6C (s) + 6O₂ (g) → 6CO₂ (g) ∆H° = -2361 k/j/mol

-------------------------------------------------------------------------------------

6 C (s) + 3 H₂ (g) → C₆H₆ (l) ∆H° = 49.1 kJ/mol

We add up and the same compound that is on different sides we eliminate

Answer:

The answer is: true

Explanation:

In redox reactions, the half-reactions of oxidation and reduction always occur simultaneously in pair.

The oxidation half-reaction involved the lost of electrons from a reduced substance (A) to form a oxidized substance (A⁺):

A ⇒ A⁺ + e-

In contrapossition, during the reduction half-reaction the oxidized substance (B⁺) gains electrons to form the reduced subtance (B):

B⁺ + e- ⇒ B

The overall redox reaction is obtained by the addition of the two half-reactions:

A ⇒ A⁺ + e-

B⁺ + e- ⇒ B

-----------------

A + B⁺⇒ A⁺ + B

The electrons gained by B are provided by A, which lost the same number of electrons. Thus, the oxidation/reduction reactions are paired.

Answer:

Explanation:

we shall use gas law formula to solve the problem .

P = .01 atm

V = 1.111 L

T = 273 K

mass of gas = .0218

molar mass = M

no of moles n = .0218 / M

PV = n RT

.01 x 1.111 = (.0218 / M)  x .082 x 273

.0218 / M = .000496

M = .0218 / .000496

= 43.95

Hi!

When the ocean reaches its saturation level of carbon dioxide, a couple of things will happen:

First, more carbon dioxide will remain in the atmosphere, and second, the ocean's pH will drop.

Carbonate and bicarbonate ions in seawater act as a buffer system which keeps the ocean's pH levels stable. When CO2 dissolves in seawater, it reacts with the ocean's buffer system in such a way that it produces two hydrogen ions, which lowers the pH. As more and more CO2 reacts with the ocean's buffer system and the system becomes saturated, less atmospheric carbon dioxide will cross over into the ocean. This excess CO2 will remain in the atmosphere and contribute to global climate change.

Hope this helped!

When the ocean reaches it's saturation level of carbon dioxide  more amount of carbon dioxide remains in the atmosphere and  pH of the ocean drops.

It is defined as the level or extent up-to which a substance is soluble in a particular solvent. Due to global warming ,there is an excessive release of carbon dioxide in atmosphere. The excessive amount cannot be soluble in the ocean water which leads to ocean acidification.

As a result of ocean acidification the pH of water in the ocean drops thus there is less amount of oxygen present for aquatic organisms which is needed to survive. When carbon dioxide dissolves in water it yields carbonic acid which further reduces the pH of water  and thus making it unfit for aquatic environment.

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Answer:

The radius of O^2- is  1.5*10^-8 cm and the radius of

Mg ^2+ is 6.2*10^-9 cm

Explanation:

Face centered cubic : 1/8 atoms on each edges + 1/2 atoms on each face

                                           = [tex]\frac{1}{8}* 8 + \frac{1}{2}*6[/tex]  = 4 effective atoms

MgO have a structure like NaCl forms a lattice of FCC.

density of the lattice =  [tex]\frac{ z.M}{a^3*Na}[/tex]

z : no of atoms

M: mass of the atoms

a: radius of the atom

Na: Avogadro's number

a^3(radius)  = [tex]\frac{ 4*40.3}{3.58*6.022*10^23}[/tex]

a^3 = 7.477 * 10^-23 cm^3

a = 4.21 * 10^-8 cm

Now calculating the anionic(ra O^2-) and cationic (rc Mg^2+)

in Fcc a = 2[tex]\sqrt{2} ra[/tex]

ra = 1.5*10^-8 cm

a = 2ra + 2rc

rc = a/2 -ra

rc = 6.2*10^-9 cm

The radius of O^2- is  1.5*10^-8 cm and the radius of Mg ^2+ is 6.2*10^-9 cm

Answer:

Explanation:

the sum of number of proton and neutron is known as atomic mass

so if number of proton is 4 and neutron is 5 then atomic mass of an atom is 9