Explanation:
18 A
19 C
20 C
22 A
24 B
hope this helps you.
can you solve these?
Answer:
yes
Explanation:
it's easy
For the hypothetical compound AX3, which statement is true?
Answer is B.
A I’d a metal from a group 3A and X is a nonmetal from group 7A
Answer:
i
b because it says it in the question
What are some medical uses of radiation?
Answer:
Radiation therapy
Explanation:
I hope this helps
Cho một lượng hỗn hợp CuO và Fe2O3 tác dụng hết với dung dịch HCl thu được 2 muối có tỉ lệ mol là 1 : 1. Phần trăm khối lượng của CuO và Fe2O3 trong hỗn hợp lần lượt là:
Answer:
fafsafwafsxDlmfao
Explanation:
Try to compare the landscape differences between the surface of the moon and the surface of the earth.
Answer:
eat this
Explanation:
please help , science tho. by the way i have to do 5
Answer:
850
Explanation:
It's between 840 and 860
In which step of meiosis do chromosomes first condense?
telophase I
telophase II
prophase I
prophase II
Answer:
Someone Said Telophase II. Ill update if its right or wrong when I finish.
Update : He is.... Wong. False.
Explanation:
The answer is Prophase I. It is not Telophase II.
An atom's mass number equals the number of
Answer:
Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons. If you want to calculate how many neutrons an atom has, you can simply subtract the number of protons, or atomic number, from the mass number.
Explanation:
hiiiii
hope u Likes it
An excess of sodium carbonate, Na, CO3, in solution is added to a solution containing 17.87 g CaCl2. After performing the
experiment, 13.19 g of calcium carbonate, CaCO3, is produced. Calculate the percent yield of this reaction.
Answer:
Approximately [tex]81.84\%[/tex].
Explanation:
Balanced equation for this reaction:
[tex]{\rm Na_{2}CO_{3}}\, (aq) + {\rm CaCl_{2}} \, (aq) \to 2\; {\rm NaCl}\, (aq) + {\rm CaCO_{3}}\, (s)[/tex].
Look up the relative atomic mass of elements in the limiting reactant, [tex]\rm CaCl_{2}[/tex], as well as those in the product of interest, [tex]\rm CaCO_{3}[/tex]:
[tex]\rm Ca[/tex]: [tex]40.078[/tex].[tex]\rm Cl[/tex]: [tex]35.45[/tex].[tex]\rm C[/tex]: [tex]12.011[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].Calculate the formula mass for both the limiting reactant and the product of interest:
[tex]\begin{aligned}& M({\rm CaCl_{2}}) \\ &= (40.078 + 2 \times 35.45)\; {\rm g \cdot mol^{-1}} \\ &= 110.978\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
[tex]\begin{aligned}& M({\rm CaCO_{3}}) \\ &= (40.078 + 12.011 + 3 \times 15.999)\; {\rm g \cdot mol^{-1}} \\ &= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
Calculate the quantity of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) available to this reaction:
[tex]\begin{aligned}n({\rm CaCl_{2}) &= \frac{m({\rm {CaCl_{2}})}}{M({\rm CaCl_{2}})} \\ &= \frac{17.87\; \rm g}{110.978\; \rm g \cdot mol^{-1}} \\ &\approx 0.161023\; \rm mol \end{aligned}[/tex].
Refer to the balanced equation for this reaction. The coefficients of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) and the product ([tex]{\rm CaCO_{3}}[/tex]) are both [tex]1[/tex]. Thus:
[tex]\displaystyle \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} = 1[/tex].
In other words, for every [tex]1\; \rm mol[/tex] of [tex]\rm CaCl_{2}[/tex] formula units that are consumed, [tex]1\; \rm mol\![/tex] of [tex]\rm CaCO_{3}[/tex] formula units would (in theory) be produced. Thus, calculate the theoretical yield of [tex]\rm CaCO_{3}\![/tex] in this experiment:
[tex]\begin{aligned} & n(\text{${\rm CaCO_{3}}$, theoretical}) \\ =\; & n({\rm CaCl_{2}}) \cdot \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} \\ \approx \; & 0.161023\; {\rm mol} \times 1 \\ =\; & 0.161023\; \rm mol\end{aligned}[/tex].
Calculate the theoretical yield of this experiment in terms of the mass of [tex]\rm CaCO_{3}[/tex] expected to be produced:
[tex]\begin{aligned} & m(\text{${\rm CaCO_{3}}$, theoretical}) \\ = \; & n(\text{${\rm CaCO_{3}}$, theoretical}) \cdot M(({\rm CaCO_{3}}) \\ \approx \; & 0.161023\; {\rm mol} \times 100.086\; {\rm g \cdot mol^{-1}} \\ \approx \; & 16.1161\; \rm g \end{aligned}[/tex].
Given that the actual yield in this question (in terms of the mass of [tex]\rm CaCO_{3}[/tex]) is [tex]13.19\; \rm g[/tex], calculate the percentage yield of this experiment:
[tex]\begin{aligned} & \text{percentage yield} \\ =\; & \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% \\ \approx \; & \frac{13.19\; {\rm g}}{16.1161\; {\rm g}} \times 100\% \\ \approx \; & 81.84\%\end{aligned}[/tex].
Is medicine, such as the aspirin shown in the image above, an example of science or technology?
Answer:
Technology
hope this helps
The pressure of gas in a 600.0 mL cylinder is 65.0 mmHg. What is the new volume when the pressure is increased to 385 mmHg?
Answer:
P1V1=P2V2
65 mmHg × 600 mL = 385 mmHg × V2
V2 = 101.30 mL
Explanation:
We can use Boyle's law
Please help me with this question it’s really confusing lol.
Answer:
should be earthquake
Explanation:
Viết cấu trúc Lewis và công thức cấu tạo cho các phân tử sau: MgO; HNO3; H2SO4. Giải thích liên kết trong các phân tử trên thuộc loại liên kết gì? Xác định mức độ ion trong liên kết MgO.
Answer:
hydrogen cloride
Explanation:
Please help me with this :) thank you
Answer:
your welcome :)
Explanation:
how many millilters of a 6.00 M sulfuric acid solution are reqired if you need 0.750 moles of H2SO4 for a reaction
125 milliliters of a 6.00 M sulfuric acid solution are required if 0.750 moles of H2SO4 are needed for a reaction.
HOW TO CALCULATE VOLUME:
The volume of a solution can be calculated by dividing the number of moles of that solution by its molar concentration. That is:Volume = no. of moles ÷ molarityAccording to this question, the molarity is given as 6.00 M sulfuric acid solution and the no. of moles is 0.75 moles. The volume is calculated thus:Volume = 0.75mol ÷ 6MVolume = 0.125LVolume of sulfuric acid in milliliters = 0.125 × 1000 = 125mLTherefore, 125 milliliters of a 6.00 M sulfuric acid solution are required if 0.750 moles of H2SO4 are needed for a reaction.Learn more at: https://brainly.com/question/2817451?referrer=searchResults
How large are dwarf galaxies compared to the Milky Way galaxy?
Question 1 options:
the same size
about 1/5 the size
about 1/10 the size
billions of time smaller
Billions of time smaller
If you place rice on top or a speaker, what will happen to the rice when you turn the speaker on?
The rice will begin to move.
The rice will do nothing
Answer:
The rice will move
Explanation:
the sound vibration and waves will cause the rice to move
Answer:
The rice will begin to move.
Explanation:
Solid carbon and oxygen gas combine to form carbon dioxide gas .
Answer:
C(s) + O2(g) --> CO2(g)
Explanation:
Answer:
True
Explanation:
Solid carbon and oxygen gas when mixed together reacts, and forms carbon dioxide gas.
A 10.0 cm sample of copper has a mass of 89.6 g. What is the density?
Answer:
19.3 g/cm3
A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper? 19.3 g/cm3
Suggest the stable ion for phosphorus and why?
Phosphorous has 5 valence electrons and so gaining 3 electrons will make it isoelectronic with the stable noble gas argon, and will produce the P3- ion
Have a tour in your kitchen pick five (5) food products having nutrition facts
and ingredients. Look for the name of elements and compounds that are present.
Complete the table below with necessary details from the food labels of the food
product you have picked. Write your answer in a separate sheet of paper.
Answer:
strawberry blueberry raspberry walang compound at element
A skateboarder is shown below.
At which point is the skateboarder's potential energy the greatest?
A. W
B. X
C. Y
D. Z
Answer:
W I think good luck I think
Answer: w
Explanation: potential energy is greater when higher from the ground. i took the test
Liquids _____.
a. take the shape of the container and
b. have a definite volume
c. have definite shape and a definite volume have no shape and no definite volume
d. none of the above
Answer:
It takes the shape of a container.
How many grams of sodium are contained in 4moles of na2co3
Answer:
424 grams of sodium are contained in 4moles of na2co3
PLS HELP I WILL GIVE BRAINLIEST
Answer:
The answer has to be A, greater force of attraction than the gas, only
Explanation:
I really hope this helps! Have a good day and good luck!
In this experiment, between 1.900-2.100 g of a mixture containing the reactants zinc sulfate and sodium phosphate was added to acidified water to undergo a double displacement (precipitation) reaction. This mixture had an unknown percent composition of reactants. To make matters more complicated, the unknown mixture did NOT contain stoichiometric quantities of the reactants.
1. (1 point) Write a molecular equation for the reaction of aqueous zinc sulfate and aqueous sodium phosphate.
David drops a golf ball and a bowling ball at the same time. He then drops a tennis ball and a volleyball. He notices that each pair hit the ground at the same time. Then David picks up a marble and a baseball. If he drops them both at the same time, what can David predict will happen
Answer:
if he drops them some where there is no air they will both land at the same time as they have no air resistance and gravity pulls every item equally but if they just do it of a building in the middle of the street then the baseball would hit first as it has a larger mass
Explanation:
If the reaction occurs between Fe2S3(s) and H+ (aq) and the equation is properly balanced with the smallest
whole-number coefficients, what is the sum of the coefficients for all reactants and products?
Fe2S3(s) + H+ (aq)
The sum of the coefficients for all reactants and products is: 12.
Here, we first need to balance the equation of the reaction between Fe2S3(s) and H+.
The chemical equation yields H2S and Fe3+ as follows;Fe2S3(s) + H+ (aq) ------> H2S + Fe3+(aq)Balancing the equation consequently yields;Fe2S3(s) + 6H+ (aq) ------> 3H2S + 2Fe3+(aq)The sum of the coefficients for all reactants and products is therefore;
Sum = 1 + 6 + 3 + 2.
Sum of coefficients = 12
Read more:
https://brainly.com/question/16887565
calculate the gravimetric factor of Fe in Fe2O3
i hope this calculation will help you
2.How could you identify an element by its
number of protons?