13 V
3 A
4V
3V
R=?
Calculate the resistance measured across the second light bulb.

The mass percentage of nickel in nickel phosphate is 48.1%.

Percentage by mass of nickel in nickel phosphate is 48.1%.

Here we have nickel phosphate - Ni₃(PO₄)₂

In this formula there are-

3 Ni atoms , 2 P atoms and 8 O atoms

now, the molecular mass nickel phosphate is- = 3 × molar mass of Ni + 2 × molar mass of P + 8 × molar mass of O

Now we know that -

molar mass of Ni = 58.7u

molar mass of P = 31u

molar mass of O = 16

So that here-

molecular mass of nickel phosphate = 3 × 58.7 + 2 × 31 + 8 × 16 = 176.1 + 62 + 128 = 366.1u

Now, mass of nickel in nickel phosphate = 3 × 58.7  = 176.1u

And for mass percentage - mass percentage = ( mass of nickel / mass of nickel phosphate ) × 100 =  (176.1 / 366.1) × 100 = 48.10 %

Hence we can conclude that the mass percentage of nickel in nickel phosphate came out to be 48.1 % after applying all the concepts.

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Answer:

The molality of the solution which is composed of 342 moles of sugar were dissolved in 171 kilograms of water is 0.002 mol/g.

To calculate the molality of a solution, you need to divide the number of moles of solute by the mass of the solvent (in kilograms).

Given:

Number of moles of sugar (C₁₂H₂₂O₁₁) = 342 moles

Mass of water (H₂O) = 171 kilograms

Molality (m) = moles of solute/mass of solvent in kg

First, convert the mass of water from kilograms to grams:

Mass of water = 171 kilograms × 1000 grams/kilogram

= 171,000 grams

Now we can calculate the molality:

Molality = 342 moles / 171,000 grams

However, before we proceed, we consider the molecular weight of sugar (C₁₂H₂₂O₁₁) to convert from moles to grams.

The molecular weight of sugar can be calculated as follows:

12 carbon atoms × 12.01 g/mol = 144.12 g/mol

22 hydrogen atoms × 1.01 g/mol = 22.22 g/mol

11 oxygen atoms × 16.00 g/mol = 176.00 g/mol

Adding up the individual atomic masses

144.12 g/mol + 22.22 g/mol + 176.00 g/mol

= 342.34 g/mol

Now we calculate the molality:

Molality = 342 moles / 171,000 grams

= 0.002 mol/g

Therefore, the molality of the solution composed of 342 moles of sugar dissolved in 171 kilograms of water is 0.002 mol/g.

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In the given compound, 0.2 mole of C₂H₆O will contain 1.2 moles of hydrogen.

In the balanced chemical compound C₂H₆O, we can deduce the following;

1 mole of C₂H₆O contains 6 moles of hydrogen

0.2 mole of C₂H₆O = ?

= 0.2 x 6 moles = 1.2 moles of hydrogen

Thus, in the given compound, 0.2 mole of C₂H₆O will contain 1.2 moles of hydrogen.

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The only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

A triangle can be defined as a one of the plane shapes which has three sides and three angles

So therefore, the only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

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Moles of ammonia

1mol requires 5.66KJ energy

13.5mol requires

If the diameter of an atom is 1 × 10⁻⁸ cm, the diameter of the nucleus is approximately 1 × 10⁻¹² cm, since the atom is mostly empty space.

The nucleus is the part of an atom that contains more than 99.9% of its mass, represented by protons and neutrons.

The diameter of an atom is 1 × 10⁻⁸ cm. The nucleus is about 10,000 times smaller than the atom. Thus, the diameter of the nucleus is:

d(nucleus) = d(atom) / 10,000

d(nucleus) = 1 × 10⁻⁸ cm / 10,000 = 1 × 10⁻¹² cm

If the diameter of an atom is 1 × 10⁻⁸ cm, the diameter of the nucleus is approximately 1 × 10⁻¹² cm, since the atom is mostly empty space.

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We know that 1 kmol = 1000 mol, so 2.43 kmol = 2430 mol.

This means the formula mass of sulfur trioxide is

[tex]32.06+3(15.9994)=80.0582 \text{ g/mol}[/tex]

Therefore, the mass is

[tex](80.0582)(2430)=\boxed{1.95 \times 10^{5} \text{ g (to 3 sf)}}[/tex]

Answer:

organic compounds with triple bonds are alkynes

So first, let's get some background knowledge.

So, how does energy concentrate to become subatomic particles?

To answer it in the best way possible, we have to understand what is energy and what particles are.

The capacity to perform labor is energy. It cannot be made or taken away. All of it was made during the moment of the Big Bang. Since then, it has changed into one form or another or has been employed to produce particles. In their purest form, elementary particles are quantum fields that are waves in space-time carrying energy. These waves also contain four moments (energy, vector momentum, angular momentum, and charge), unless they are completely chargeless like photons. They are nothing more than energy, which is dependent on the wave's frequency (and has endowed with it some properties like charge and spin etc). Therefore, energy creates particles by destroying one or more particles and creating one or more other particles, by taking energy from them and transducing into the others, in a similar fashion to how particles came out of nothing but energy pumped into the space-time the first time (after the Big Bang). In quantum physics, the annihilation and creation operators are used to represent it. I'll use one as an illustration. formation of the duo. Once it collides with a heavy nucleus (i.e., one with a high atomic number, Z), a high-energy gamma ray with energy greater than the rest energies of a proton-electron pair experiences an electromagnetic interaction, which is mediated by a virtual photon, and generates an electron and positron pair. For instance, if the initial gamma ray had an energy of 20 MeV, the generation of the pair would take around 1.022 MeV (the total of the rest energies of the electron and positron), whereas the pair would share about 18.078 MeV in kinetic energy. As a result, the energy is simply converted from a boson with no charge, mass, or spin to two products with opposite charges, each having a mass of 0.511 MeV: a negatively charged spin 1/2 fermion and a positively charged spin 1/2 fermion (anti-particle of the first).

So to answer, let's complete this in a question, what subatomic particle causes electricity?

There are instances when the protons and electrons in an atom's outermost shells are not strongly attracted to one another. It is possible to force these electrons out of their orbits. They may move from one atom to another by exerting force. Electricity is made up of these moving electrons.

Answer:

sabatomic particle also called elementary particle of any various self contained units of matter or energy that are fundamental constitution of all methods

Answer:

1.61 g Na₂S

Explanation:

To find the mass of sodium sulfide (Na₂S) generated from hydrogen sulfide (H₂S) and sodium hydroxide (NaOH), you need to (1) construct the balanced chemical equation, then (2) calculate the molar masses of each molecule involved, then (3) convert grams of each reagent to grams of the product (via the molar masses and mole-to-mole ratio from equation coefficients), and then (4) determine the limiting reagent and final answer. It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

The unbalanced equation:

H₂S + NaOH ---> Na₂S + H₂O

Reactants: 3 hydrogen, 1 sulfur, 1 sodium, 1 oxygen

Products: 2 hydrogen, 1 sulfur, 2 sodium, 1 oxygen

The balanced equation:

H₂S + 2 NaOH ---> Na₂S + 2 H₂O

Reactants: 4 hydrogen, 1 sulfur, 2 sodium 2 oxygen

Products: 4 hydrogen, 1 sulfur, 2 sodium, 4 oxygen

(Step 2)

Molar Mass (H₂S): 2(1.008 g/mol) + 32.065 g/mol

Molar Mass (H₂S): 34.081 g/mol

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.998 g/mol

Molar Mass (Na₂S): 2(22.990 g/mol) + 32.065 g/mol

Molar Mass (Na₂S): 78.045 g/mol

(Step 3)

1.50 g H₂S          1 mole            1 mole Na₂S          78.045 g
-----------------  x  ----------------  x  --------------------  x  -----------------  =
                           34.081 g          1 mole H₂S            1 mole

=  3.43 g Na₂S

1.65 g NaOH           1 mole              1 mole Na₂S          78.045 g
--------------------  x  ----------------  x  -----------------------  x  ----------------  =
                              39.998 g        2 moles NaOH          1 mole

=  1.61 g Na₂S

(Step 4)

Because NaOH generates less product, it will run out before all of the H₂S is used. This makes NaOH the limiting reagent and the final answer 1.61 grams Na₂S.

If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 5.2 atm

V= 500 mL =0.5 L

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=?

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{45 g}{32}[/tex]

[tex]Moles = \frac{45 g}{32}[/tex]

Moles = 1.40625

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]1.40625= \frac{5.2 \;atm\; X \;0.5 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}[/tex]

T= 22.53167034 K= 22.53K

Hence, If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

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4.743 x [tex]10^{-3}[/tex] s-1 is the value of the rate constant.

The Arrhenius equation describes the relationship between the rate of reaction and temperature for many physical and chemical reactions.

As per Arrhenius equation,

k = Ae-Ea÷RT

T = 227 = 500.15 K

R = 0.008314 kJ/K mol

Ea = 150 kJ/mol

Ea÷RT

= 150÷(0.008314 x 500.15)

= 36.073

k = Ae-36.073 = (2.2 x [tex]10^{13}[/tex] s-1) (2.156 x [tex]10-{16}[/tex])

k = 4.743 x [tex]10^{-3}[/tex] s-1

So, the correct answer is option d) i.e. 4.7 x [tex]10^{-3}[/tex] s-1

As per Arrhenius equation,

k = Ae-Ea/RT

T = 227 = 500.15 K

R = 0.008314 kJ/K mol

Ea = 150 kJ/mol

Ea÷RT = 150÷(0.008314 x 500.15) = 36.073

k = Ae-36.073 = (2.2 x [tex]10^{13}[/tex] s-1)(2.156 x [tex]10^{-16}[/tex])

k = 4.743 x [tex]10^{-3}[/tex] s-1

Hence,  4.743 x [tex]10^{-3}[/tex] s-1 is the value of the rate constant.

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[tex]molar \: mass = 48 \\ element = cadmium[/tex]

Answer:

A.) Titanium

Explanation:

The graph appears to be a mass spectrum. This graph describes the abundance of an element in a sample. The x-axis measures the mass of the element. As such, you can identify the element by determining which element has an atomic weight (g/mol) that matches the highest peak.

Titanium = 47.867 g/mol

Cadmium = 112.41 g/mol

Vanadium = 50.942 g/mol

The highest peak appears to be at 48. From these atomic weights, it seems that titanium is the element with the closest mass.

This graph is measuring an unknown element, so ideally, there would be only one peak. If this is a graph of one element, then why are their multiply smaller peaks? The smaller peaks are most likely isotopes or impurities.

Answer:

NO

Explanation:

No, the use of inorganic fertilizer can not increase / cannot contribute the organic matter in the soil.

One central them of Jesus' message was the kingdom of God

The gospel of the Lord Jesus Christ is the ministration of God's words to sinners to repent so they can inherit the kingdom of God

The book of John says: For God so love the world that he gave his only begotten son to the world that whosoever believeth in him shall not perish but have an everlasting life

In conclusion, One major purpose of Jesus' message to humanity was to preach the gospel of the kingdom of God

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The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.

The molarity of 5% NaOH is 1.32 M

25 cc of NaOH neutralized 30cc of H₂SO₄ solution.

Equation of reaction is given below:

Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M

moles of H⁺ ions per mole of H₂SO₄ = 2

Normality of H₂SO₄ = 0.55 x 2 = 1.1 N

In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.

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Answer:

0.1 kilometer

Explanation:

First, multiply 5,000 by two to get your cm after 5,000 years which is 10,000 cm and then divide by 100,000 to convert to kilometers which is 0.1.

[tex]\sf{\qquad\qquad\huge\underline{{\sf Answer}}}[/tex]

Which is the safest way to view a solar eclipse?

Answer: Is he B) With a telescope

Since when there is an eclipse you have to use a telescope because the other items are not correct.

I hope I've helped : )

5.7744 g is the mass of the methane gas.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.36 mol = \frac{mass}{16.04 g/mol}[/tex]

Mass =5.7744 g

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From the calculations that have been done, there are 3 drinks.

The information that we have been provided here is very important. We can obtain the amount of alcohol by looking at the fact that it contains  80-proof liquor.

This 80-proof liquor. is an equivalent of 40% alcohol this means that there is 1.5 ounce of distilled spirit.

Thus, the number of drinks there is;

4.5/1.5 = 3

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Answer:

See below

Explanation:

carbon % = 200.5 / 345.21   * 100% = 58.1 %

hydrogen% = 144.71 / 345.21  *100% = 41.9 %

Hydrochloric acid would be classified as an acid to the Arrhenius definition due to giving of hydrogen ions.

According to Arrhenius concept, hydrochloric acid is an acid which gives hydrogen ions in water while on the other hand, according to Bronsted-Lowry theory, hydrochloric acid is an acid that donates a proton to the water molecule.

So we can conclude that hydrochloric acid would be classified as an acid to the Arrhenius definition due to giving of hydrogen ions.

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Any substance that increases the concentration of [tex]H^+[/tex] in aqueous solutions is Arrhenius's acid.

Arrhenius define acids as substances with the chemical capacities to increase the concentration of hydrogen ion in aqueous solutions.

Thus, substances like HCl, HNO3, HBr, etc. would be considered an acid. This is because they ionize in aqueous solutions as follows:

HCl ---> [tex]H^+[/tex] + [tex]Cl^-[/tex]

[tex]HNO_3 --- > H^+ + NO_3^-[/tex]

[tex]HBr --- > H^+ + Br^-[/tex]

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Answer:

6.27 [gr].

Explanation:

the required mass can be calculated as:

m[Ca(OH)₂]=M[Ca(OH)₂]*m[CaCl₂]/M[CaCl₂], where M - molar mass [gr/mol], m - mass [gr];

m[Ca(OH)₂]=9.4*74/111≈6.2(6) [gr].

Approximately 6.216 grams of calcium hydroxide (Ca(OH)₂₂) is produced from 9.4 grams of calcium chloride (CaCl₂) in the given balanced equation.

To determine the amount of calcium hydroxide (Ca(OH)₂) produced from 9.4 g of calcium chloride (CaCl₂) using the balanced equation, we need to use stoichiometry.

The balanced equation is:

CaCl₂ + 2NaOH --> 2NaCl + Ca(OH)₂

From the equation, we can see that 1 mole of CaCl₂ reacts with 1 mole of Ca(OH)₂. The molar mass of CaCl₂ is 111 g/mol, and the molar mass of Ca(OH)₂ is 74 g/mol.

To find the number of moles of CaCl₂, we divide the given mass by the molar mass:

Moles of CaCl₂ = 9.4 g / 111 g/mol ≈ 0.084 moles

Since the stoichiometric ratio between CaCl₂ and Ca(OH)₂ is 1:1, we know that 0.084 moles of CaCl₂ will produce 0.084 moles of Ca(OH)₂

To find the mass of Ca(OH)₂ produced, we multiply the number of moles by the molar mass:

Mass of Ca(OH)₂= 0.084 moles × 74 g/mol = 6.216 g

Therefore, approximately 6.216 grams of calcium hydroxide (Ca(OH)₂) is produced from 9.4 grams of calcium chloride (CaCl₂) in the given balanced equation.

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3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ([tex]C_3H_8[/tex]) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Stoichiometric calculations:

[tex]C_3H_8(g) + 5 O_2(g)[/tex]→ [tex]3 CO_2(g) + 4 H_2O(g)[/tex]

From the equation of the reaction, the mole ratio of propane to oxygen is 1:5.

Mole of 815.74 grams of propane = [tex]\frac{ 815.74}{44.1 }[/tex]

Mole of 815.74 grams of propane = 18.49750567 moles

Mole of  1,006.29 grams of oxygen =[tex]\frac{ 1,006.29}{32 }[/tex]

Mole of  1,006.29 grams of oxygen = 31.4465625 moles

Going by the mole ratio, it appears propane is limiting while oxygen is in excess.

From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:

18.49750567 moles x 4 = 73.99 moles.

Using the ideal gas equation:

PV = nRT

v = (73.99  x 0.08206 x 623) ÷ 0.96

v =  3940.2

Hence, 3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ([tex]C_3H_8[/tex]) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

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Answer:

A

Explanation:

bc u have to think about it

Answer:

117.4 kJ (to 4 sf)

Explanation:

(141.3)(0.831) = 117.4 kJ (to 4 sf)

Answer:

Explanation:

Comment

1 mole of KClO3 has 3 moles of oxygen

9.9 moles of KClO3 has x moles of oxygen

Formula

1/9.9 = 3/x                                    Cross Multiply

Solution

1 / 9.9 = 3 / x

1*x = 9.9 * 3

x = 29.7 moles of oxygen

1 mole of oxygen has 6.02 * 10^23 atoms making up that 1 mole

29.7 moles of oxygen has 6.02*10^23 atoms making them up.

Answer

29.7 * 6.02 * 10^23 atoms

1.78 * 10^25 atoms

Calculate atoms in KClO_3

1 mol KCl contains 3mol O_2

9.9 mol contains

8.59 is the concentration of ethyl alcohol when 0.198 kg of ethyl alcohol.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Given data:

Volume of solution = 0.500 L

Given the mass of  [tex]C_2H_5OH[/tex]= 0.198 kg= 198g

Molar mass of [tex]C_2H_5OH[/tex] = 46.07 g/mol

Moles of [tex]C_2H_5OH[/tex] = 4.297807684

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{4.297807684}{0.500 L}[/tex]

Molality = 8.595615368 =8.59M

Hence,  8.59 is the concentration of ethyl alcohol when 0.198 kg of ethyl alcohol.

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