-10m/s² and vertical height of 0.6m.How will we use this information to find the velocity of the falling object?
​

Answer:

Longitudinal

Explanation:

I searched it up.

Answer:

1482m/s

Explanation:

velocity equals frequency x lamdha

Answer:

true

Explanation:

Answer:

Refraction

Explanation:

When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.

1. carbohydrates, lipids, proteins, and nucleic acids.

2. a is protein b is sugar c is starch and d is nuclear acid

3. What is the difference between saturated and unsaturated fat? it's that Saturated fats have the maximum number of hydrogens possible, while unsaturated fats have a double bond between two of the carbons. part 2. Why are partially hydrogenated fats useful for making potato chips but not particularly healthy for humans to eat? I was not able to find a different answer for it than part 1.

If you wanted the laser to refract less as it exits the prism, you should increase the wavelength of the light.

Refraction can be defined as a phenomenon which describes a change (bend) in the path taken by light when it's at surfaces between different transparent materials.

According to the model of light wave, the refraction of light is inversely proportional to its wave. Thus, you should increase the wavelength of light, if you want the laser to refract less as it exits the prism.

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Answer:

After some time on the counter, ripe bananas will develop a brown peel. Bananas contain the enzyme polyphenol oxidase, and when the enzyme interacts with oxygen, it causes a chemical reaction. This chemical reaction, known as enzymatic browning, changes the banana's peel and fruit to brown

Explanation:

Answer:

Density and amount of charge O

Answer:

√ ae/ ap = √ mp/me 1/2

Explanation:

Mass of the electron = M (Given)

Mass of the proton = M (Given)

Time = t (Given)

But acceleration of electron, ae =FE/me whereas

acceleration of proton, ap = FE/mp

S = 1/2at²1 = 1/2apt²2

t2/t1= √ ae/ ap

t2/t1= √ ae/ ap = √ mp/me 1/2

Answer:

Correct option is D) …

Explanation:

For electron t1​ (small 1) = [tex]\sqrt{ \frac{2S}{ae}[/tex] (small e)

For protion, t2 (small 2) = [tex]\sqrt \frac{2S}{ap}[/tex] (small p)

or [tex]\frac{t2}{t1}[/tex] = [tex]\sqrt\frac{ae}{ap}[/tex] = [tex]\sqrt\frac{eE}{me} *\frac{mp}{eE}[/tex]

= [tex]\sqrt\frac{mp}{me}[/tex]

I’m gonna say everything that needs to go down as an exponent but down for example H20 but the 2 is small, also in order from top to bottom to fraction to fraction (small 2, 1, e, p, e, p, (after equal sign) p, e).

Hope this helped and brainliest pls

Answer:

you cant really give any answers because i cant tell u were to drag

Answer:

P V = N R T     ideal gas equation

P2 / P1 = T2 / T1       where the other variables are constant

P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi

Answer:

the speed of light in air is about 299,000,000 and 3×10⁸ m/s

Answer:

.00135 j

Explanation:

K.E. = 1/2   m  v^2

       = 1/2 * .03 * .3^2 = .00135 j

If the current is held constant, an increase in voltage will result in an increase in resistance.

hope it helps...!!!

Answer:

See below

Explanation:

The units of the specific heat hint at how to solve these types of problems

.88 J/(g-C)   * 10 g  *  (100- 50 C) = 440 J  

                                  ( see how the g and the C 'cancel out' ?)

Given ,

Mass of the body (m) = 200g

Amplitude (A) = 20mm

Maximum force (F) = 0.6 N

Maximum velocity (vmax) =?

We know that

Fmax = mv2max/A

or , 0.6 = 200×10-3xv2max/20×10-3

or , 0.6×20/200= v2max

or , vmax = 0.24 m/s

∴ Maximum velocity = 0.24 m/s2

The value of maximum velocity will be 0.3464 m/s². Energy or work is equal to the product of force and displacement.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Mass of the body is,(m= 200g)

Amplitude is,(A  =20 mm)

Maximum force is,F= 0.6 N

To find;

Maximum velocity

Energy or work is equal to the product of force and displacement.

[tex]\rm KE = \frac{1}{2} mV_{max}^2 \\\\ \rm F_{max} \times A = \frac{1}{2} mV_{max}^2 \\\\ F_{max}= \frac{1}{2}\frac{ mV_{max}^2}{A} \\\\ 0.6= \frac{1}{2}\times \frac{ 0.2 \times V_{max}^2}{20 \times 10^{-3}} \\\\ V_{max}=0.3464 \ m/sec^2[/tex]

Hence,the value of maximum velocity will be 0.3464 m/s².

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The centripetal acceleration of the aeroplane is determined as 7.03 m/s².

The centripetal acceleration of the aeroplane is calculated as follows;

ac = v²/r

where;'

ac = (75²)/(800)

ac = 7.03 m/s²

Thus, the centripetal acceleration of the aeroplane is determined as 7.03 m/s².

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Explanation:

Acceleration is a vector quantity which is defined as the rate at which an object changes its velocity

A projectile is shot with the initial speed, it follows the motion called projectile motion. The height of the cliff is 44.91 m.

The speed at the start of the motion is the initial speed.

The horizontal distance is

x = v₀ sin θ. t

Substitute 26.5 for θ, 24 for x and 8.94 m/s for x, we get the time taken to complete the journey.

t = 24/ (8.94 cos26.5) = 3 s

Maximum height reached

H = v₀²sin²θ/2g

H = (8.94)² x sin²( 26.5) /(2 x 9.8)

H =0.8118 m

The height of the cliff is obtained by the equation of motion

0.8118 - h = -1/2 gt² +v₀sinθ.t

Substitute the values, we get

h =0.8118 +1/2x9.8x (3)²

h =44.911m

Thus, the height of the cliff is 44.91 m.

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Answer:

5941m/s

Explanation:

velocity equals frequency x lamdha

Answer:

Mag isip ka po wag Kang tanong ng tanong kac kami po Yung nahihirapan mag hanap ng answer

W = Pt

W = 150 x (4.6 x 3600) = 2.484 x 10⁶ J

Light nulbs do not "produce" energy.

When YOU bring electrical energy from somewhere and pour it through the light bulb, the bulb turns some of it into light energy and the rest into heat energy .

(150 W) x (4.6 hr) =690 watt-hrs

or 0.69

Answer:

The correct answer is - C.  Increasing the concentration increases the reaction rate.

Explanation:

Answer:

B. Increasing the temperature increases the reaction rate.

Explanation:

The reaction time column displays how long the reaction ran for. If a reaction rate was fast then time taken for reaction to run would be slow right?

Therefore, original condition had reaction time of 10 second, but increaseing temperature lowered the time to 5 second, which must mean that reaction rate increased.

==============================

[tex] \large \sf \underline{Question:}[/tex]

==============================

[tex] \large \sf \underline{Answer:}[/tex]

Impulse and momentum are important in sports like cricket because from the word "momentum" it describe itself like you're getting used of it or you know what to do like there's no stopping you.

==============================

How are impulse and momentum related?

==============================

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration.

Explanation:

Let's look at Newton's second law

Force is directly proportional towards mass

If mass is more force will be more.

Between baseball and bowling ball Bowling ball has higher mass

So it would expert most force

Option D

Answer:

Explanation:

Focal length of diverging lens,

fd= -33.5 cm

focal length of converging lens,

fc = 20 cm

Now let s is object distance and s' is image distance.

Now using lens formula for conversing lens

\frac1{f_c}=\frac1{s}+\frac1{s'}

f

c

​

1

​

=

s

1

​

+

s

′

1

​

Putting all values(object is at s=infinity)

Then image distance

\frac1{s'}= \frac1{f_c}- \frac1{s}

s

′

1

​

=

f

c

​

1

​

−

s

1

​

=\frac1{20}- \frac1{\infin}=

20

1

​

−

∞

1

​

s'=20cms

′

=20cm

Now using lens formula for diversing lens

s''=14-20=-6cm

Using lens formula

\frac{1}{-33.5} = \frac{1}{-6 }+ \frac{1}{s''' }\\s'''=\frac{(6)\times(-33.5)}{(-33.5+6)}\\s'''=\frac{(-201) }{(-27.5) }

−33.5

1

​

=

−6

1

​

+

s

′′′

1

​

s

′′′

=

(−33.5+6)

(6)×(−33.5)

​

s

′′′

=

(−27.5)

(−201)

​

image distance for diverging lens

s''' = 7.3 cm (behind the diverging lens)

A diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. image distance for diverging lens, s''' = 7.3 cm (behind the diverging lens)

When a lens in the path of a beam of parallel rays causes the rays to diverge after refraction, it is referred to as a diverging lens.

It always creates a virtual image and has a thinner core than its boundaries.

Concave lenses(diverging lenses) function as diverging lenses because they cause light rays to diverge as they pass through them.

Therefore, when used with air as the operating medium, a concave lens can be thought of as a diverging lens.

The concave lens has several applications, including in telescopes, cameras, lasers, glasses, binoculars, and other optical devices.

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