Answer:
ethylene(ethane) + oxygen → carbon dioxide + water
the type of reaction is COMBUSTION.
Find the correct mass and the volume calculated from #10 to #13 to
calculate the density. Density = (4.7033 x 104 g/ 2.6540 x 106 mL) =
The density = 1.77 x [tex]10^{-2}[/tex] where Mass =4.7033 x [tex]10^4[/tex] g and Volume=2.6540 x [tex]10^6[/tex]mL.
What is density?
Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density Symbol: D or ρ Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.
Given:
Density = (4.7033 x [tex]10^4[/tex] g/ 2.6540 x [tex]10^6[/tex] mL)
Mass =4.7033 x [tex]10^4[/tex] g
Volume=2.6540 x[tex]10^6[/tex] mL
Density = (4.7033 x [tex]10^4[/tex] g/ 2.6540 x [tex]10^6[/tex] mL)
Density = 1.772155237 x [tex]10^{-2}[/tex] = 1.77 x [tex]10^{-2}[/tex]
Hence, the density = 1.77 x [tex]10^{-2}[/tex].
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When electrons in an atom transition from a lower energy state to a higher energy state __________ .
When electrons in an atom transition from a lower energy state to a higher energy state it has to absorb some energy in order to transition to the higher energy state.
When properly stimulated, the electrons in these materials move from lower energy levels to higher energy levels and occupy different orbits. Then, at some point, these high-energy electrons emit "extra" energy in the form of photons and return to their original energy levels.
Electrons jump to higher energy levels when excited by external energy gains such as B. Large heating, the presence of an electric field, or collision with another electron.
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During photosynthesis, how many moles of water (H₂O) are needed to produce 150 grams of glucose
(C6H12O6)?
A. 2 moles
B. 3 moles
C. 4 moles
D. 5 moles
During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.
What is photosynthesis?It is the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water.
Step 1: Write the balanced equation for photosynthesis.6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂
Step 2: Convert 150 g of C₆H₁₂O₆ to moles.The molar mass of C₆H₁₂O₆ is 180.16 g/mol.
150 g × 1 mol/180.16 g = 0.833 mol
Step 3: Calculate the moles of water required to form 0.833 moles of C₆H₁₂O₆The molar ratio of H₂O to C₆H₁₂O₆ is 6:1.
0.833 mol C₆H₁₂O₆ × 6 mol H₂O/1 mol C₆H₁₂O₆ = 5.00 mol H₂O
During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.
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Polonium-208 is an alpha emitter with a half-life of 2.90 years. How many milligrams of polonium from an original sample of 2.00 mg will remain after 8.00 years
Answer:
0.296 mg
Explanation:
8.00/2.90 half lives have passed, so this means the remaining mass is
[tex]2.00 {(0.5)}^{8.00 \div 2.90} [/tex]
which is about 0.296 mg.
The amount of polonium remaining after 8.00 years is 0.296 mg. This is obtained by using rate law of first order kinetics.
What is the rate law of first order kinetics and the half-life of the compound?The expression for the rate law for first order kinetics is
k = [tex]\frac{2.303}{t}log\frac{a}{a-x}[/tex] years⁻¹
Where,
k - rate constant
t - time passed by the sample
a - initial amount of the reactant
a-x - final amount of the reactant
The expression for the half-life of the compound is
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex] years
Calculating the amount of polonium remained after 8.00 years:Given that,
A Polonium-208 is an alpha emitter with a half-life of 2.90 years.
I.e., [tex]t_{\frac{1}{2}}[/tex] = 2.90 years
Then,
2.90 = (0.693)/k
⇒ k = (0.693)/(2.90) = 0.2389 years⁻¹
Then,
for t = 8.00 years,
Since we have rate law of first order kinetics as
k = [tex]\frac{2.303}{t}log\frac{a}{a-x}[/tex]
⇒ k = (2.303/8.00) log(a/a-x)
Where the initial amount of the reactants is a = 2.00 mg
So,
k = 0.287 log (2.00/a-x) (a-x is the final amount of the reactants)
⇒ 0.238 = 0.287 log(2.00/a-x)
⇒ (0.238/0.287) = log(2.00/a-x)
⇒ 0.829 = log(2.00/a-x)
⇒ (2.00/a-x) = [tex]10^{0.829}[/tex] = 6.745
⇒ (a-x) = 2.00/6.745 = 0.296 mg
Therefore, the remaining polonium is 0.296 mg after 8.00 years.
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Although oxygen does not participate directly in the citric acid cycle, the cycle operates only when O2 is present. Why
Answer:
Explanation:
Sounds like oxygen acts as a 'catalyst'
If 31.2 mL of 0.45 M sodium hydroxide is mixed with 65.4 mL of 0.088 M phosphoric acid, how many kJ of heat are produced
Heat produced is given by -0.813 kJ
Calculation of heat produced:
The reaction:
[tex]3NaOH + H_3PO_4 \rightarrow Na_3PO_4 + H_2O[/tex] ΔH[tex]_{rxn}[/tex]= -173.7 kJ (Assumed)
Step 1: Calculation of moles using Molarity.
Volume of NaOH= 31.2 mL
Concentration= 0.45M
[tex]M=\frac{n}{V}\times1000\\\\n=\frac{M\times V}{1000} \\\\n= \frac{31.2\times0.45}{1000}\\n= 0.01404[/tex]of NaOH
Volume of [tex]H_3PO_4[/tex] = 65.4 mL
Concentration= 0.088M
[tex]n=\frac{0.088\times 65.4}{1000}\\\\n= 0.005755[/tex] mole of [tex]H_3PO_4[/tex]
Step 2: Limiting reagent
According to the above reaction
1 mole of [tex]H_3PO_4[/tex] reacts with 3 mole of NaOH
0.005755 moles will react with [tex]3\times 0.005775 \, NaOH[/tex]= 0.017 moles of NaOH is required. But we have 0.01404 moles of NaOH.
So NaOH is the limiting reagent.
Step3: Calculate ΔH:
We will limiting reagent to calculate the heat produced-
[tex]0.01404 \,mole \times\frac{-173.7}{3}= -0.813\, kJ[/tex]
Heat produced= -0.813 kJ
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how many grams are in 4.63 ×1024 molecules of CCl4
Answer:
m =1,182.8g
Explanation:
there you go
How much heat is released when 25.0 grams of liquid copper at its freezing point of 1,085°c changes to solid? the latent heat of fusion of copper is 205.0 j/g. –27,130 j –5,130 j 5,130 j 27,130 j
Amount of heat released:
Heat is released when 25.0 gm of liquid copper at its freezing point of 1,085°C changes to solid is -5125 J
Given:
Mass of liquid copper, m= 25 gm
Latent heat of fusion of copper, L = 205.0 J/g
The amount of heat needed to change one gram of a substance from solid to liquid is known as the latent heat of fusion.
However, in this instance, it is necessary to determine the quantity of heat emitted when liquid copper solidifies.
So, L = -205.0 J/g
Calculation:
We may use the unitary approach to calculate the heat released when 25.0 grams of liquid copper solidify at 1,085°C, which is its freezing point.
So,
Q = L x m
Q = -205 J/g x 25 g
Q = -5125 J
So, the correct answer is b) -5,130 J, which is much nearest to -5125 J as we have calculated above.
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Answer:
-5,130 J
Explanation:
I got 100% on the quiz edge 2022
calculate no. of molecules in 1120 ml CH⁴ at NTP
Answer:
0.3011 X10²³
Explanation:
hope this helps u
A solution containing 1 mol of a strong electrolyte will have a(n) _____ effect on the colligative properties of the solution than 1 mol of a nonelectrolyte. A strong electrolyte will dissociate or ionize in aqueous solution, and therefore the total number of dissolved solute particles is _____ for 1 mol of a strong electrolyte than for 1 mol of a nonelectrolyte solute.
A solution containing 1 mol of a strong electrolyte will have a greater effect on the colligative properties of the solution than 1 mol of a nonelectrolyte. A strong electrolyte will dissociate or ionize in an aqueous solution, and therefore the total number of dissolved solute particles is greater for 1 mol of a strong electrolyte than for 1 mol of a nonelectrolyte solute.
How do electrolytes work?An electrolyte is a material that separates into charged ions when it is in contact with water. Cations are positively charged ions. Anions are ions that are negatively charged. A substance that may conduct an electric current when melted or dissolved in water is known as an electrolyte.
Types of electrolytes:-A substance is referred to as a strong electrolyte if the physical or chemical process that produces the ions is virtually 100% effective (all of the dissolved molecules give ions). Weak electrolytes are those in which only a very small portion of the dissolved substance goes through the ion-producing process.
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What is the equilibrium constant for the reaction?
Answer: C. 20
Explanation: One equation for the equilibrium constant is [tex]\frac{[Products]}{[Reactants]}[/tex]. The products are typically on the left side and the reactants on the right.
Given this and the values of each, we can easily plug this in. However, we must multiply the products instead of adding them.
[tex]\frac{0.69M*0.98M}{0.034M} =19.888, or 20M[/tex]
19.888 can be easily rounded to 20, meaning that C is the best answer.
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solve me these one's
fast pls
II. Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as: (a) Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A). (b) Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A). (c) Assertion (A) is true but reason (R) is false. (d) Assertion (A) is false but reason (R) is true.
Q.6. Assertion: When a beam of light is passed through a colloidal solution placed in a dark place the path of the beam becomes visible.
Reason: Light gets scattered by the colloidal particles.
Q.7. Assertion: A solution of table salt in a glass of water is homogeneous.
Reason: A solution having different composition throughout is homogeneous.
Q.8. Assertion: True solution exhibits Tyndall effect.
Reason: Particles are very large in size
Colloidal solution has large size particles hence it is able to scatter light.
What is a colloidal solution?A colloidal solution is a solution that is composed of particles that are larger in size than the particles that compose a true solution.
For question 6;
Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A)
For question 7;
Assertion (A) is true but reason (R) is false.
For question 8;
Assertion (A) is false but reason (R) is true.
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1. How many grams of sodium chloride is produced when 3.4 g of sodium reacts with 8.9 g of chlorine in
this balanced equation?
2Na+ Cl₂ → 2NaCl
The Answer to the question is 14 grams approximately.
Atomic mass of Na = 23 u
Given mass of Na = 3.4 gm
Moles of Na = given mass of Na / molar mass of Na
Moles of Na = 3.4 / 23 moles = 0.15 moles approximately
So, 0.15 moles of Na approximately
Molar mass of Cl₂ = 35.45 × 2 = 70.9 u
Given mass of Cl₂ = 8.9 gm
Moles of Cl₂ = given mass of Cl₂ / molar mass of Cl₂
Moles of Cl₂ = 8.9 / 70.9 moles = 0.12 moles approximately
So, 0.12 moles of Cl₂ approximately
Balanced chemical equation
2Na + Cl₂ → 2NaCl
Ratio of Moles to Stoichiometric coefficients
0.15/2 0.12/1
0.075 < 0.12
So, as ratio of Na is less then it will be our Limiting reagent.
Which means that Cl₂ will consume complete in the reaction.
It is clear from the reaction that 1 moles of Cl₂ are making 2 mole of NaCl
1 moles of Cl₂ → 2 mole of NaCl
0.12 moles of Cl₂ → 2 × 0.12 mole of NaCl
0.12 moles of Cl₂ → 0.24 mole of NaCl
So, 0.12 moles of Cl₂ will make 0.24 mole of NaCl
0.24 mole NaCl = mass formed NaCl / molar mass of NaCl
mass formed NaCl = 0.24 × molar mass of NaCl
mass formed NaCl = 0.24 × 58.44
mass formed NaCl = 0.24 × 58.44
mass formed NaCl = 14 grams (approximately)
14 grams of NaCl will be formed.
So, approximately 14 grams NaCl is formed from 3.4 grams of Na and 8.9 grams of Cl.
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A solution of NaOH has concentration of 1.2M then mass of NaOH in g/dm3 is
Answer:
A solution of NaOH has concentration 1.2M. Calculate the mass of NaOH in g/dm3 in this solution. = 1.2x 40x 1 = 48 g 3.
The mass of NaOH in the solution having concentration of 1.2 M is 48.00 grams per decimeter cubed (g/dm³).
Concentration refers to the amount of a solute dissolved in a given amount of solvent or solution. It is a measure of how much solute is present in a specific volume or mass of the solution.
Concentration can be expressed in various units, such as molarity (moles of solute per liter of solution), mass percent (mass of solute per 100 grams of solution), parts per million (ppm), and others.
Given:
Concentration of NaOH solution = 1.2 M
The molar mass of NaOH (sodium hydroxide) is:
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
Total molar mass of NaOH = 22.99 + 16.00 + 1.01
= 40.00 g/mol
1 mole of NaOH = 40.00 g
1.2 moles of NaOH = 1.2 moles × 40.00 g/mole
= 48.00 g/L
1 L = 1 dm³
So, 48.00 g/L = 48.00 g/dm³
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IN NEED OF QUICK HELP Name both the reactant and product and then draw the reactant and product
Please explain
thanks
The reactant in this reaction is 2-fluoro-5-propyl - heptane while the product is 2-hydroxy-5-propyl - heptane.
What is a substitution reaction?We define a substitution reaction as one in which a given moiety is replaced by another. This is an example of a substitution reaction.
The name of the reactant in this reaction is 2-fluoro-5-propyl - heptane while the product is 2-hydroxy-5-propyl - heptane.
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How does a fire extinguisher works ?
Answer:
Most fire extinguishers work by separating the fuel from the oxygen. The oxygen comes from the air. It is the same oxygen we breathe. Since the oxygen has to be in contact with the fuel, if you can coat the fuel with something that keeps the oxygen away, the fire will go out. Some ways of using fire extinguisher are:
Water extinguishers work mainly by cooling (removing heat), but a dense spray of water droplets also helps to cut off oxygen. Dry powder extinguishers soak up heat, melt on the fuel, and cut off oxygen, but they also neutralize the fuel (cutting it off from the fire) .Explanation:
I hope it was helpful...
Which statement about gases is true?
A) They are made up of particles that always move very slowly.
B) They are made up of particles that travel in a curved path when in motion.
C) They are made up of hard spheres that vibrate quickly in stationary positions.
D) They are made up of hard spheres that are in random motion.
Answer:
B) They are made up of particles that travel in a curved path when in motion.
Explanation:
We know that gas, being a state of matter, is made up of particles. John Dalton's solid-sphere model was proven to be incorrect by Ernest Rutherford's gold foil experiment.
These particles do NOT always move very slowly. There are multiple different factors that affect the speed of the particles such as temperature or concentration.
What molecule is butane
Butane is a gaseous molecule which is part of the organic compounds called hydrocarbon,
What kind of molecule is butane?Butane is a gaseous molecule which is generally called a hydrocarbon.
Hydrocarbons are composed of only carbon and hydrogen. They are of organic origin.
Butane is a low molecular weight hydrocarbon which is used as a fuel.
In conclusion, butane is a gaseous hydrocarbon,
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Determine the ground-state electron configuration for each of the following elements: A. chlorine ______________________________________________________________________ B. cesium ______________________________________________________________________ C. vanadium______________________________________________________________________ D. rhenium______________________________________________________________________ 2. Predict the number of valence electrons present in each of the following atoms (include the outermost d- electrons): A. Sn ___________________________ B. La___________________________ C. Mn__________________________ D. Zn __________________________ 3. Determine the ground-state electron configuration for each of the following ions:
In ground-state electron configuration, the principal quantum number (n), the orbital (s, p, d, or f), and the total number of electrons are used to represent electron configurations.
Case 1 Ground-state electron configuration of elements.
A) Chlorine: 1s²2s²2[tex]p^{6}[/tex]3s²3[tex]p^{5}[/tex]
B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹
C) Vanadium: 1s²2s²2p⁶3s²3p⁶3d³4s²
D) Rhenium: 1s² 2s² 2p⁶ 3s² 3p⁶3d¹⁰ 4s²4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁵ 6s²
Case 2 : Number of valence electron in atoms
A) Sn -Tin - Four valence electrons
B) La - Lanthanum - Three valence electrons
C) Mn - Manganese - Seven valence electrons
D) Zn- Zinc - Two valence electrons
Case 3 Ground-state electronic configuration of ions
A) Co⁺³ : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹3d⁵
B) Mo⁺² : 1s² 2s² 2p⁶3s²3p⁶ 4s² 3d¹⁰ 4p⁶5s² 4d²
C) Ra⁺² : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p⁶
D) I⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶
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10. Using the below valency chart, write the chemical formula for aluminum oxide and
aluminum chloride
The chemical formula of aluminum chloride is AlCl₃ and the chemical formula of aluminum oxide is Al₂O₃.
Aluminum chlorideThe chemical formula of aluminum chloride is written as;
Al³⁺ + Cl⁻ → AlCl₃
Aluminum oxideThe chemical formula of aluminum oxide is written as;
Al³⁺ + O²⁻ → Al₂O₃
Thus, the chemical formula of aluminum chloride is AlCl₃ and the chemical formula of aluminum oxide is Al₂O₃.
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Answer:
gg mate
Explanation:
1. What is the pH of a solution with a [H3O+] concentration of 4.32 x 10-2 M?
2. What is the pH of a solution with a [H3O+] concentration of 3.4 x 10-11 M?
3. What is the concentration [H3O+] of a solution with a pH of 13.2?
1. The pH of the solution is 1.36
2. The pH of the solution is 10.47
3. the concentration of [H₃O⁺] in the solution is 6.3×10⁻¹⁴ M
What is pH ?This is simply a measure of the acidity / alkalinity of a solution.
The pH measures the hydrogen ion (hydronium ion) concentration while the poH measures the hydroxide ion concentration. It is expressed mathematically as
pH = –Log H₃O⁺
1. How to determine the pH[H₃O⁺] = 4.32×10⁻² MpH = ?pH = –Log H₃O⁺
pH = –Log 4.32×10⁻²
pH = 1.36
2. How to determine the pH[H₃O⁺] = 3.4×10⁻¹¹ MpH = ?pH = –Log H₃O⁺
pH = –Log 3.4×10⁻¹¹
pH = 10.47
3. How to determine the concentration of [H₃O⁺]pH = 13.2[H₃O⁺] = ?pH = –Log H₃O⁺
13.2 = –Log H₃O⁺
Multiply through by -1
-13.2 = Log H₃O⁺
Take the anti-log of -13.2
H₃O⁺ = anti-log (-13.2)
H₃O⁺ = 6.3×10⁻¹⁴ M
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What coefficients are needed to balance the following:
Cu(NO3)2 + GaI3 →CuI2 + Ga(NO3)3
What coefficients are needed to balance the following:
Cu(NO3)2 + GaI3 →CuI2 + Ga(NO3)3
A. 2,3,3,2
B . 1,1,1,1
C. 2,3,2,3
D. 3,2,3,2
During photosynthesis, how many grams of oxygen gas (O₂) are produced from 55 grams of carbon
dioxide gas (CO₂)?
A. 32 grams 02
B. 40 grams 02
C. 44 grams 0₂
D. 55 grams 0₂
[tex]6h2o + 6co2 = 6o2 + c6h12o6[/tex]
number of mol CO2=number of mol of O2[tex]n = n \\ \frac{ mass}{molar \: mass} = \frac{mass}{molar \: mass} [/tex]
[tex] \frac{55}{44} = \frac{m}{32} \\ m = \frac{55 \times 32}{44} = 40 \: grams[/tex]
Photosynthesis reactions are the process that occurs in the plants to yield oxygen from food. In the process, 55 gm of carbon dioxide produces 40 gm of oxygen. Thus, option B is correct.
What is photosynthesis?Photosynthesis is a metabolic reaction that takes place in the plant cell where the sun energy converts the water and carbon dioxide into sugar (glucose) and oxygen.
The photosynthetic reaction is given as,
6H₂O + 6 CO₂ → C₃H₁₂O₆ + 6O₂
In the above reaction, there are 6 moles of carbon dioxide needed to produce 6 moles of oxygen. Hence, moles of carbon dioxide consumed = moles of oxygen produced.
Mass from moles is calculated as,
Moles = mass ÷ molar mass
Equating moles of both CO₂ and O₂,
mass ÷ molar mass = mass ÷ molar mass
55 ÷ 44 = m ÷ 32
m = 55 × 32 ÷ 44
= 40 gm
Therefore, 40 gm of oxygen is produced from 6 moles of carbon dioxide.
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Consider the following reaction:
3 Br2 + 6 OH¹-5 Br¹ + BrO3¹ + 3 H₂O
If 4.68 moles of Br2 are reacted with 8.12 moles of OH¹, how many moles of Br
can be formed? (Report your answer to two places past the decimal point.
Moodle is looking for a number only, no units.)
Answer:
Explanation:
I'm assume that 3 Br2 + 6 OH¹-5 Br¹ + BrO3¹ + 3 H₂O is meant to read:
3 Br2 + 6 OH^-1 = 5 Br^-¹ + BrO3^-¹ + 3 H₂O
The balanced equation tells us that 3 moles of Br2 will react with 6 moles of OH^-1 to produce 5 moles of Br^-1.
The first step is to determine whether the Br2 or OH^-1 are limiting reagents. That is, is there enough of each to complete the reaction, with none left over.
We need 3 moles of Br2 for every 6 moles of OH^-1, a molar ratio of 1/2 (Br2/OH).
We are given 4.68 moles of Br2 and 8.12 moles of OH^-1. That is a ratio of 4.68/8.12 or 0.5764. This is higher than the ratio of 1/2 or 0.5 that is required. That means we have more than enough Br2. The limiting reagent is the OH^-1. Once it is consumed, the reaction stops and we are left with some unreacted Br2.
So we need the molar ratio of the OH^-1 to the Br from the balanced equation: We see that 6 moles of OH^-1 are required to produce 5 moles of Br, a 6/5 molar ratio.
Therefore, we may assume all 8.12 moles of the limiting reagent, OH^-1, will be consumed to produce *6/5) that amount of Br.
(8.12 moles OH^-1)*((6 moles Br)/(5 moles OH^-1)) = 9.75 moles of Br.
For curiosity's sake, we can determine the amount of unreacted Br2. 8.12 moles of OH^-1 would require (8.12 moles OH)*(1/2) = 4.06 moles of Br2.
4.68 moles starting Br2
4.06 moles consumed
0.62 moles remaining Br2
Write the balanced molecular equation for the neutralization reaction between HI and Ba(OH)2 in aqueous solution. Include physical states.
molecular equation
neutralization reaction = acid+base = salt + water
molecular equation = balanced equation
2HI(aq) + Ba(OH)₂(aq) ⇒ BaI₂(aq) + 2H₂O(l)
To be effective, collisions between atoms must occur with the proper orientation and also the proper amount of __.
explosion
matter
energy
catalysis
To be effective, collisions between atoms must occur with the proper orientation and also the proper amount of energy.
What is the loss of kinetic energy due to the collision?An inelastic collision is a collision in which there is a loss of kinetic energy. While the momentum of the system is conserved in an inelastic collision, the kinetic energy is not. This is because some kinetic energy has been transferred to something else.
In this case, is necessary have energy to be effective, so collisions between atoms must occur with the proper orientation.
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Answer:
energy
Explanation:
What is the percent composition of oxygen in SO₂?
Answer: 50%
Explanation:
To find the percent composition of oxygen in SO₂, we need to find out the molar masses of both elements and add them.
First, figure out how many atoms are in each element of this compound. Then figure out the molar mass by multiplying it by the molar mass you'd see on the periodic table.
[tex]1atomS*32.06g=32.06g/molS\\2atomO*15.999g=31.998g/molO_{2}[/tex]
Now that we have that information, we must add up the numbers to get the molar mass of SO₂.
[tex]32.06g/molS+31.998g/molO_{2} =64.058g/molSO_{2}[/tex]
Now we have the molar mass of SO₂. To find the percent composition of oxygen in SO₂, we must divide the molar mass of O₂ by that of SO₂, then multiply that by 100.
[tex]\frac{31.998g/molO_{2} }{64.058g/molSO_{2} } *100=49.95; 50[/tex]
Given this, the percent composition of oxygen in SO₂ is 50%.
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The main combustible part of wood is cellulose, a compound of carbon, hydrogen, and oxygen, which, when it burns, breaks down to _____, water, and heat.
The main combustible part of wood is cellulose, a compound of carbon, hydrogen, and oxygen, which, when it burns, breaks down to carbon dioxide, water, and heat.
What is Combustible Substance ?The substances which catches fires easily in air and produce heat and light upon burning is known as Combustible Substances.
Example: Wood, Oil, Kerosene, Hydrogen gas, Cloth etc.
When these compounds carbon, hydrogen and oxygen burns completely the carbon oxidizes to carbon dioxide , water and heat.
Thus from the above conclusion we can say that The main combustible part of wood is cellulose, a compound of carbon, hydrogen, and oxygen, which, when it burns, breaks down to carbon dioxide, water, and heat.
Learn more about the Combustible Substance here: https://brainly.com/question/12875341
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The ideal gas constant, R has several different values that could be used. Which quantity causes these differences?
O pressure
O temperature
O volume
O moles
Answer:
The answer is A
Explanation:
How many atoms of germanium
are present in a sample
containing 1.65 moles Ge?
Answer:
9.9363 x 10^23 atoms
Explanation:
1.65 x Avagadro's Number
1.65 * 6.022 x 10^23 =