The box survived the fall and is returned to the top of the building. More objects are put into the box, and the box with its contents now has a total mass of 93 kg. The box is dropped, and it reaches a higher terminal speed than before. After reaching terminal speed, what is the magnitude of the air resistance force acting upward on the falling box? (The fact that the heavier object reaches a higher terminal speed shows that the air resistance force increases with increasing speed.)

The frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.

To find the answer, we need to know more about the friction.

                    [tex]m=140*10^{-3} kg\\w=1 rev/s=2\pi rad/s\\r_1=14*10^{-2}m\\g=9.81m/s^2\\[/tex]

                    [tex]f=F_c=ma_c=m*r_1w^2\\f=140*10^{-3}*14*10^{-2}*4*\pi ^2=0.77N[/tex]

                              [tex]f_s=kN,\\\\Where, \\N=mg\\\\k=\frac{f_s}{mg}[/tex]

                         [tex]F_c=f_s=mrw^2=140*10^{-3}*24*10^{-2}*4\pi ^2\\f_s=1.325N[/tex]

                   [tex]k=\frac{1.325}{140*10^{-3}*9.81}=0.964[/tex]

Thus, we can conclude that, the frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.

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Answer:

Pakistan has low rates of non renewable energy thus it is mandatory that the renewable resources be put into use. The vast deserts in punjab and sindh should be used to set up solar panels and the coastal areas of sindh and balochistan should be used as wind power. The northern areas have melting glaciers and high precipitation rates rates thus HYDEL power should be used in the form of dams

(1) The wavelength of the wave is 1.57 m.

(2) The velocity of the wave is 30 m/s .

(3) The frequency of the wave is 19.10 Hz and the time period of the    wave is 0.052 s.

Note: The given equation seems to be incomplete. Most probably the equation was y=25sin(120t-4x). And the standard system of units (i.e. kg, m, s) is used.

Wavelength: The distance between the consecutive crest or trough of a wave is called the wavelength of a wave.

The equation of a plane wave oscillating in the y direction and traveling in the x direction is given by the equation,

y=A sin(ωt-kx)

where y is the displacement along the y direction, A is the amplitude of the wave, ω is the angular frequency, t is the time, x is the displacement along the x direction, and k is the wave constant.

The given equation is,

y=25sin(120t-4x)

Comparing this equation with the above equation, following values are obtained.

k= 4 m^(-1)

ω =120 rad/s

A=25

The wavelength λ is given by the formula,

λ=2π/k

Here k = 4 m^(-1), so

λ=2π/4

λ=1.57 m.

Velocity: The velocity of a wave is the product of the frequency and the wavelength.

The velocity v is given by the formula,

v=ω*λ/2π

Here ω=120 rad/s and λ=1.57 m, so

v=120*1.57/2π

v=30 m/s

Frequency: The number of oscillations completed in one second is called the frequency of a wave.

The formula of the frequency is,

f=v/λ

Here v=30 m/s and λ=1.57 m, so

f=30/1.57

f=19.10 Hz

Time period: The time taken to complete one cycle of oscillation is called the time period of oscillation.

The formula to calculate the time period T is,

T=2π/ω

Here ω=120 rad/s, so

T=2π/120

T=0.052 s.

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The answer is 24 J

F K =.25*8 N

     = 2N

F = f k = 2 N

Since a = 0

W = f * s

 2 N * 12 m = 24 J

The coefficient of friction is a ratio used to quantify the friction force among two gadgets when it comes to the everyday pressure this is keeping them collectively. The coefficient of friction is critical attention at some stage in material selection and floor requirement determination.

For instance, ice on steel has a low coefficient of friction – the 2 materials slide past each different without problems – whilst rubber on the pavement has an excessive coefficient of friction – the substances no longer slide past each other without difficulty.

The coefficient of friction is dimensionless and it does not have any unit. it is a scalar, meaning the direction of the force does not have an effect on the physical quantity. The coefficient of friction depends on the gadgets that are causing friction.

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The speed of the cat 5 m from the sidewalk is 7.42 m/s

What is speed:

The Newton's equation of motion:

here the cat falls from the height,

h = 40 m

since The cat is falling from rest

Initial velocity, u = 0 m/s

acceleration, a = g = 9.8 m/s^2

substituting values in eq.

40 = 0 + ( 9.8 t^2)

t^2 = 40 / 9,8

t^2 = 4.0814

t = 2.02 s

now when cat is 5 m from sidewalk

distance, S = 40 - 5 = 35 m from top

so,

35 = u*2.02 + 1/2 ( 9.8* 2.02^2 )

u = 15 / 2.02

u = 7.4257 m/s

The speed of the cat 5 m from the sidewalk is 7.42 m/s

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Answer:

1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?

Explanation:

The magnitudes of two horizontal displacements are 4 m and 9 m, respectively. Given that the vectors may be in either the plus or the minus direction, they cannot be added together to give a total displacement of 4m.

The attain of the projectile is the horizontal displacement of the projectile and is decided by the object's initial pace.

If a projectile is fired on an equal starting velocity but from complementary tiers of projection, its variety will be equal.

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The answer is W = 1.06 MJ.

Now develop and express of Force required:

                                            F = p*V*g

                                            F = 1000*(2*0.5*x*8*dx)*g

                                            F = 78480*x*dx

- Now, the work done is given by:

                                   W = F.s

Where s is the distance from the top of the hose to the differential volume:

                                        s = (5 - x)

We have the work as follows:

                              dW = 78400*x*(5-x)dx

Now integrate the following express from 0 to 3 till the tank is empty:

 W = 78400*(2.5*x^2 - (1/3)*x^3)

 W = 78400*(2.5*3^2 - (1/3)*3^3)

 W = 78400*13.5 = 1058400 J

To find the weight of water, begin by way of finding the density(1 kg/L at 39.2°) and the extent of water. Convert the volume of water to liters after which multiply by way of the density to discover the burden.

Density is useful in calculating the load of materials which can be tough to weigh. you may decide its weight without a doubt with the aid of multiplying the density by using the dimensions, or quantity, of the item.

The unique weight, additionally called the unit weight, is the weight in keeping with the unit quantity of cloth. A typically used value is the precise weight of water in the world at 4 °C (39 °F), which is nine.807 kilonewtons consistent with cubic meters or 62. 43 pounds-force in keeping with cubic foot.

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The efficiency of the lamp is 74%.

The efficiency of the lamp is calculated using the formula below is used:

Work input = 18000 J

Work output = 13320 J

Efficiency = 13320/18000 × 100% = 74 %

In conclusion, the efficiency of the lamp is less than 100%.

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Answer:

stars will emit more light due to their Luminosity, so they look very bright.

Explanation:

Luminous refers to..,

Most of the really bright stars in our sky are not that very close to us yet they look bright because of the Luminosity of the star.

These stars are intrinsically so luminous.

A star's power output across all wavelengths is called its bolometric luminosity.

A star with large luminosity will have more measure of radiated electromagnetic power meaning.

so it will emit more light than a low luminosity star.

Hence,

those stars can easily be seen even across great distance.

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Kinetic energy of the pile driver is 10 KJ.

To find the answer, we need to know about the conservation of mechanical energy.

Conservation of mechanical energy says that the total energy of a system remains same during a process.

Thus, we can conclude that the increased kinetic energy is 10KJ.

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The magnetic flux associated with the coil is 0 Wb.

Magnetic flux is the total magnetic field that travels through a specific location.

It is a very useful tool for explaining the effects of magnetic force on things in a specific location.

The magnetic flux measurement is location specific.

The magnetic flux through the coil is NBA cosα

where N is number of turns, B is Magnetic field, A is area of coil and α is the angle between normal to the area of coil and the direction of magnetic field.

Magnetic Flux = NBA cosα

We have given number of turns as 100, magnetic field as 3 and area as 5 m².

Also, the value of α will be 90°

Magnetic Flux = NBA cosα Wb

Magnetic Flux = 100 × 3 × 5 × cos90° Wb

Magnetic Flux = 100 × 3 × 5 × 0 Wb

Magnetic Flux = 0 Wb

So we can conclude that the magnetic flux through the coil is 0 wb after applying the above concept.

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Let [tex]\vec u[/tex] and [tex]\vec v[/tex] be the vectors, and let [tex]x=\|\vec u\|=\|\vec v\|[/tex] be their common magnitude.

The resultant [tex]\vec u + \vec v[/tex] is [tex]\sqrt 2[/tex] times larger in magnitude than either vector alone, so [tex]\|\vec u+\vec v\| = \sqrt2\,x[/tex].

Recall the dot product identity

[tex]\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)[/tex]

where [tex]\theta[/tex] is the angle between the vectors [tex]\vec a[/tex] and [tex]\vec b[/tex]. In the special case of [tex]\vec a=\vec b[/tex], we get

[tex]\vec a \cdot \vec a = \|\vec a\|^2 \cos(0^\circ) \implies \|\vec a\| = \sqrt{\vec a\cdot\vec a}[/tex]

Now, to get the angle between [tex]\vec u[/tex] and [tex]\vec v[/tex], we have

[tex]\vec u \cdot \vec v = \|\vec u\| \|\vec v\| \cos(\theta) \implies \cos(\theta) = \dfrac{\vec u \cdot \vec v}{x^2}[/tex]

To compute the dot product, we take the dot product of the resultant with itself.

[tex](\vec u+\vec v) \cdot (\vec u + \vec v) = \|\vec u + \vec v\|^2[/tex]

Solve for [tex]\vec u\cdot\vec v[/tex].

[tex](\vec u\cdot\vec u) + 2(\vec u\cdot\vec v) + (\vec v\cdot\vec v) = \|\vec u + \vec v\|^2[/tex]

[tex]\|\vec u\|^2 + 2(\vec u\cdot \vec v) + \|\vec v\|^2 = \|\vec u+\vec v\|^2[/tex]

[tex]x^2 + 2(\vec u \cdot \vec v) + x^2 = (\sqrt2\,x)^2[/tex]

[tex]2(\vec u\cdot\vec v) + 2x^2 = 2x^2[/tex]

[tex]2(\vec u\cdot\vec v) = 0[/tex]

[tex]\vec u\cdot\vec v = 0[/tex]

Since their dot product is zero, [tex]\vec u[/tex] and [tex]\vec v[/tex] are perpendicular, so [tex]\theta=90^\circ[/tex].

Magnitude of the average velocity is 0.3 m/s.

To find the answer, we need to know about average velocity.

Thus, we can conclude that the average velocity is 0.3 m/s.

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Answer:

acceleration, a = 11m/s² ; time, t = 0.84sec

Explanation:

Fw = mass(m) × acceleration due to gravity(g)

Fw = 71.9kg × 10m/s²

Fw = 719N

F = Fw(sintheta+coefficient of friction(costheta))

F = 719(sin38° + 0.61(cos38°)

F = 719(0.615661475+0.480686559)

F = 719(1.096348034)

F = 788.27N

Force(F) = mass(m) × acceleration(a)

Make acceleration the subject

acceleration = Force÷ mass

a = 788.27÷719

a = 11m/s²

using this formula v² = u² +2gh

v² = 0² + 2×10m/s²×4.3m

√v² = √86

v = 9.27m/s

acceleration = velocity/time

make time the subject

time = velocity/acceleration

t = 9.27m/s/11m/s²

t = 0.84sec

The relation between NTU unit and turbidity is based on appearance for all the samples therefore the values of respective NTU unit for all samples is between low and high.

What is meant by Turbidity?

Haziness or cloudiness in fluids as a result of dissolving two separate particles like totally dissolved solids or dissolved solids is known as Turbidity.

What is meant by NTU value?

The full form of NTU is Nephelometric Turbidity unit. It is the unit used to measure the turbidity of a given fluid, also to detect any presence of suspended particles in water.

The relation between suspended solid and NTU is:

1 mg/l (parts per million, ppm) = 3 NTU

Thus, as the relation between NTU unit and turbidity is based on appearance for all the samples therefore the values of respective NTU unit for all samples is consistent.

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Scurvy and rickets are micronutrient deficiency diseases due to a lack of certain vitamins or minerals in the diet. Scurvy is caused by vitamin C deficiency and rickets by vitamin D.

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From the calculation,  the man has an average velocity of 1.25 m/s.

The man travelled a total distance = 100 m

We know that;

1 complete cycle = 4 s

Then

 20 complete cycle = ?

= 20 x 4 s

= 80 s

So we can find the average velocity from;

Average velocity = 100 m/80 s

Average velocity = 1.25 m/s

Hence, the man has an average velocity of 1.25 m/s.

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No, it is not valid because they did not have any repeat trials.

The acceleration that an object experiences as a result of gravitational force is referred to as the object's acceleration due to gravity. M/s2 is its SI unit. Gravitational acceleration is a vector quantity, which means it has both a magnitude and a direction. The letter g stands for the acceleration due to gravity at Earth's surface. Its standard value is 9.80665 m/s2 (32.1740 ft/s2), according to the formula. A body in free fall actually accelerates differently depending on the location.

Because moving the object, air, or other factors could distort the results of a single instance. There must therefore be repeated experiments in order to obtain precise results.

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Answer:

1.042 × 10⁻³ m/s

Explanation:

average speed =  [tex]\frac{total \space\ distance \space\ covered}{time \space\ taken}[/tex]

In this case,

• distance covered = 90 m,

• time taken = 24 hours = 24 × 60 = 1440 min = 1140 × 60 = 86400 s

Substituting these values into the formula:

average speed = [tex]\frac{90}{86400}[/tex]

                          = 1.042 × 10⁻³ m/s

Answer:

3.75 meters per hour

Explanation:

[tex]\boxed{\sf Speed = \dfrac{Distance}{Time}}[/tex]

Given:

Substitute the given values into the formula to calculated the speed:

[tex]\implies \sf Speed = \dfrac{90\:m}{24\:h}[/tex]

[tex]\implies \sf Speed = 3.75\:m/h[/tex]

Therefore, the average speed of the snail is 3.75 meters per hour.

To calculate the speed in meters per minute, divide by 60:

[tex]\implies \sf Speed = \dfrac{3.75\:m/h}{60}=0.0625\:m/min[/tex]

To calculate the speed in meters per second, divide by 60 again:

[tex]\implies \sf Speed = \dfrac{0.0625\:m/min}{60}=0.001042\:m/s\:\:(4\:s.f.)[/tex]

Answer:

D. A followed by B

Explanation:

You can see at section A solid Ice at temperature 0°C gets heated up for and all the energy generated from heating up the ice is used to break the bonds which holds the ice together as a solid .

while at Section B the liquid water at 100°C changes to vapor because the heat energy applied here breaks intermolecular bonds c.

The section where A is followed by C of the heating curve illustrate this process. The correct option is D.

The heating curve represents the association between the supply temperature of the heating system and the external air temperature.

As can be seen in section A reliable Ice at 0°C is heated, and all of the energy generated by heating the ice is used to shatter the bonds that hold the ice together as a solid.

While in Section B, liquid water at 100°C transforms to vapor because the heat energy applied here shatters the intermolecular bonds c.

Thus, the correct option is D.

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Answer:

(I) 49m/s

(ii) 122.5m

Explanation:

Data obtained from the question include:

Time (t) = 5 s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 4 s

Acceleration due to gravity (g) = 9.8 m/s²

v = gt

v = 5× 9.8

v = 49 m/s

Thus, the brick's velocity after 4 s is 49m/s

B. Determination of how far the brick fall in 5 s.

Time (t) = 5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 5²

h = 5× 16

h = 122.5 m

Thus, the brick fall 122.5m during the time.

Using the Pascal's principle formula, the force exerted on the second piston is 18000 N.

The force on the second piston is determined using the formula from Pascal's principle.

The formula is given below:

[tex]\frac{f_{1}}{A_{1}} = \frac{f_{2}}{A_{2}}[/tex]

Solving for the force on the second piston, [tex]{f_{2}[/tex]

[tex]{f_{2} = \frac{A_{2}\times f_{1}}{A_{1}}[/tex]

[tex]{f_{2} = \frac {0.2\times3600}{0.04} = 18000 N[/tex]

In conclusion, the force on the second piston is 18000 N.

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The momentum is changed when the ball is hitted by racket in the tennis game.

To find the answer, we need to know about the momentum.

Thus, we can conclude that the momentum is changed when the ball is hitted by racket in the tennis game.

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2 x 10⁻¹⁸ C is the charge on each of the pieces.

In physics, Charge is electric charge, electrical charge, or electrostatic charge and symbolized as q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.

According to the question,

Fс = 4 x 10⁻²³ N

d = 0.03 m  , k = 9.0 x 10⁹ N·m²/C²

q =?

The force exerted by one charge q on another charge Q a distance r away is given by:

Coulomb's law:

Fc =[tex]\frac{kq_{1} q_{2} }{d^{2} }[/tex]

By solving the equation:

[tex]q1q2 =\frac{F_{c} d^{2} }{k}[/tex]

[tex]\frac{(4*10^{-23}(0.03m )^{2} }{(9.0*10^{9}N.m^{2}/C^{2}) }[/tex]

= 4 x 10 ⁻³⁶C²

This is the square of the charge on the pieces of puffed rice.

Now, to find the charge on one piece of puffed rice,

take the square root of this number.

q = √4 x 10⁻³⁶ C²

q = 2 x 10⁻¹⁸ C

Therefore,

The charge on each of the pieces is 2 x 10⁻¹⁸ C

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Answer:

I = Q / t = 590 C / (.47 * 3600 sec) = .349 amperes

.349 amps * 1000 milliamps / amp = 349 milliamperes

Due to acceleration, work is done accelerating from rest.

Work done is defined as product of force and displacement. As it explain force then it consist acceleration with itself. So, we can say like this that

work is done mainly due to acceleration of object from rest.

For the approximate distance through which the force act as ball is

thrown is the work is done along effective length of pitcher's arm and he

can extend this distance by taking a step forward.

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