1. What is the pH of a solution with a [H3O+] concentration of 4.32 x 10-2 M?

2. What is the pH of a solution with a [H3O+] concentration of 3.4 x 10-11 M?

3. What is the concentration [H3O+] of a solution with a pH of 13.2?

Answers

Answer 1

1. The pH of the solution is 1.36

2. The pH of the solution is 10.47

3. the concentration of [H₃O⁺] in the solution is 6.3×10⁻¹⁴ M

What is pH ?

This is simply a measure of the acidity / alkalinity of a solution.

The pH measures the hydrogen ion (hydronium ion) concentration while the poH measures the hydroxide ion concentration. It is expressed mathematically as

pH = –Log H₃O⁺

1. How to determine the pH[H₃O⁺] = 4.32×10⁻² MpH = ?

pH = –Log H₃O⁺

pH = –Log 4.32×10⁻²

pH = 1.36

2. How to determine the pH[H₃O⁺] = 3.4×10⁻¹¹ MpH = ?

pH = –Log H₃O⁺

pH = –Log 3.4×10⁻¹¹

pH = 10.47

3. How to determine the concentration of [H₃O⁺]pH = 13.2[H₃O⁺] = ?

pH = –Log H₃O⁺

13.2 = –Log H₃O⁺

Multiply through by -1

-13.2 = Log H₃O⁺

Take the anti-log of -13.2

H₃O⁺ = anti-log (-13.2)

H₃O⁺ = 6.3×10⁻¹⁴ M

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Related Questions

If 31.2 mL of 0.45 M sodium hydroxide is mixed with 65.4 mL of 0.088 M phosphoric acid, how many kJ of heat are produced

Answers

Heat produced is given by -0.813 kJ

Calculation of heat produced:

The reaction:

[tex]3NaOH + H_3PO_4 \rightarrow Na_3PO_4 + H_2O[/tex]     ΔH[tex]_{rxn}[/tex]= -173.7 kJ (Assumed)

Step 1: Calculation of moles using Molarity.

Volume of NaOH= 31.2 mL

Concentration= 0.45M

[tex]M=\frac{n}{V}\times1000\\\\n=\frac{M\times V}{1000} \\\\n= \frac{31.2\times0.45}{1000}\\n= 0.01404[/tex]of NaOH

Volume of [tex]H_3PO_4[/tex] = 65.4 mL

Concentration= 0.088M

[tex]n=\frac{0.088\times 65.4}{1000}\\\\n= 0.005755[/tex] mole of [tex]H_3PO_4[/tex]

Step 2: Limiting reagent

According to the above reaction

1 mole of [tex]H_3PO_4[/tex] reacts with 3 mole of NaOH

0.005755 moles will react with [tex]3\times 0.005775 \, NaOH[/tex]= 0.017 moles of NaOH is required. But we have 0.01404 moles of NaOH.

So NaOH is the limiting reagent.

Step3: Calculate ΔH:

We will limiting reagent to calculate the heat produced-

[tex]0.01404 \,mole \times\frac{-173.7}{3}= -0.813\, kJ[/tex]

Heat produced= -0.813 kJ

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What is the equilibrium constant for the reaction?

Answers

Answer: C. 20

Explanation: One equation for the equilibrium constant is [tex]\frac{[Products]}{[Reactants]}[/tex]. The products are typically on the left side and the reactants on the right.

Given this and the values of each, we can easily plug this in. However, we must multiply the products instead of adding them.

[tex]\frac{0.69M*0.98M}{0.034M} =19.888, or 20M[/tex]

19.888 can be easily rounded to 20, meaning that C is the best answer.

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The table shows the nature of the reactants and products formed in a certain type of chemical reaction. Nature of Reactants and Products Reactants Products Ionic compound + Ionic compound Ionic compound + Ionic compound Which of the following is true about this type of chemical reaction? (4 points) Group of answer choices It is a single replacement reaction, and all four compounds are different. It is a double replacement reaction, and all four compounds are different. It is a single replacement reaction, and each compound has the same set of ions. It is a double replacement reaction, and each compound has the same set of ions.

Answers

The given reaction is a double replacement reaction; option B.

What is a chemical reaction?

A chemical reaction is a reaction in which chemical changes occurs in the atoms of reactants which results in the formation pf products.

The given reaction is as follows:

Ionic compound + Ionic compound ---> Ionic compound + Ionic compound

Since exchange of ions occur, it is a double replacement reaction.

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A garbage collector collects food wrappers and aluminum cans from a park. what type of waste is the garbage collector collecting?

Answers

Answer:

Explanation:

Food wrappers and aluminium wrappers are widely use for packing various eatable items.

For example, in our homes our mother wraps our food for lunch in aluminium foil.

As it helps in keeping the food warm for hours.

Thus, we can conclude that out of the given options, a packaging waste is the garbage collector collecting.

Rank protons, neutrons, and electrons according to their mass. Identify the charge of each and their location

Answers

Answer:

discuss the successes and the short comings of the conservative reaction to the french rvolution as seen in the actions of the congress of vienna and the holy aliance?

What is the percent composition of oxygen in SO₂?

Answers

Answer: 50%

Explanation:

To find the percent composition of oxygen in SO₂, we need to find out the molar masses of both elements and add them.

First, figure out how many atoms are in each element of this compound. Then figure out the molar mass by multiplying it by the molar mass you'd see on the periodic table.

[tex]1atomS*32.06g=32.06g/molS\\2atomO*15.999g=31.998g/molO_{2}[/tex]

Now that we have that information, we must add up the numbers to get the molar mass of SO₂.

[tex]32.06g/molS+31.998g/molO_{2} =64.058g/molSO_{2}[/tex]

Now we have the molar mass of SO₂. To find the percent composition of oxygen in SO₂, we must divide the molar mass of O₂ by that of SO₂, then multiply that by 100.

[tex]\frac{31.998g/molO_{2} }{64.058g/molSO_{2} } *100=49.95; 50[/tex]

Given this, the percent composition of oxygen in SO₂ is 50%.

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What molecule is butane

Answers

Butane is a gaseous molecule which is part of the organic compounds called  hydrocarbon,

What kind of molecule is butane?

Butane is a gaseous molecule which is generally called a hydrocarbon.

Hydrocarbons are composed of only carbon and hydrogen. They are of organic origin.

Butane is a low molecular weight hydrocarbon which is used as a fuel.

In conclusion, butane is a gaseous hydrocarbon,

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calculate no. of molecules in a spherical drop of water... radius = 0.1 mm and density of water = 1g/cm²​

Answers

Answer:

1.49X10^20

Explanation:

hope this helps (´・ω・`)

During photosynthesis, how many moles of water (H₂O) are needed to produce 150 grams of glucose
(C6H12O6)?

A. 2 moles
B. 3 moles
C. 4 moles
D. 5 moles

Answers

During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.

What is photosynthesis?

It is the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water.

Step 1: Write the balanced equation for photosynthesis.

6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂

Step 2: Convert 150 g of C₆H₁₂O₆ to moles.

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

150 g × 1 mol/180.16 g = 0.833 mol

Step 3: Calculate the moles of water required to form 0.833 moles of C₆H₁₂O₆

The molar ratio of H₂O to C₆H₁₂O₆ is 6:1.

0.833 mol C₆H₁₂O₆ × 6 mol H₂O/1 mol C₆H₁₂O₆ = 5.00 mol H₂O

During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.

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During photosynthesis, how many grams of oxygen gas (O₂) are produced from 55 grams of carbon
dioxide gas (CO₂)?

A. 32 grams 02
B. 40 grams 02
C. 44 grams 0₂
D. 55 grams 0₂

Answers

[tex]6h2o + 6co2 = 6o2 + c6h12o6[/tex]

number of mol CO2=number of mol of O2

[tex]n = n \\ \frac{ mass}{molar \: mass} = \frac{mass}{molar \: mass} [/tex]

[tex] \frac{55}{44} = \frac{m}{32} \\ m = \frac{55 \times 32}{44} = 40 \: grams[/tex]

Photosynthesis reactions are the process that occurs in the plants to yield oxygen from food. In the process, 55 gm of carbon dioxide produces 40 gm of oxygen. Thus, option B is correct.

What is photosynthesis?

Photosynthesis is a metabolic reaction that takes place in the plant cell where the sun energy converts the water and carbon dioxide into sugar (glucose) and oxygen.

The photosynthetic reaction is given as,

6H₂O + 6 CO₂ → C₃H₁₂O₆ + 6O₂

In the above reaction, there are 6 moles of carbon dioxide needed to produce 6 moles of oxygen. Hence, moles of carbon dioxide consumed = moles of oxygen produced.

Mass from moles is calculated as,

Moles = mass ÷ molar mass

Equating moles of both CO₂ and O₂,

mass ÷ molar mass = mass ÷ molar mass

55 ÷ 44 = m ÷ 32

m = 55 × 32 ÷ 44

= 40 gm

Therefore, 40 gm of oxygen is produced from 6 moles of carbon dioxide.

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Prepare a project report on various samples of
a) a mixture
b) a compound
c) an element ( metal or non metal)
( 2 from each ) highlighting the main characteristics features of elements, compounds and mixtures.

detailed answer plsss

Answers

Project Reports

A) Mixture

This refers to the material that is made when different substances mix up physically and causes a reaction.

You can make on the project of Mixture -

1) Alloys2)Colloids3) Suspension4) Solution

B) Compound

This refers to the chemical bond that holds different atoms tightly

You can make on the project of Compound -

1)Water2)Methane3)Carbon Dioxide4) Sulfuric Acid

C) Elements

Based on the fact that the atom is the smallest indivisible part of an element, elements like phosphorous cannot be further broken down.

You can make on the project of Elements -

1) Mercury2) Iron3) Copper4)Carbon

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The ideal gas constant, R has several different values that could be used. Which quantity causes these differences?
O pressure
O temperature
O volume
O moles

Answers

Answer:

The answer is A

Explanation:

Calculate the heat released when 12.5g of water, at its freezing point, freezes.

16700 J

8350 J

4170 J

12543 J

Answers

Answer:

4170 j

Explanation:

water has low melting point

When electrons in an atom transition from a lower energy state to a higher energy state __________ .

Answers

When electrons in an atom transition from a lower energy state to a higher energy state it has to absorb some energy in order to transition to the higher energy state.

When properly stimulated, the electrons in these materials move from lower energy levels to higher energy levels and occupy different orbits. Then, at some point, these high-energy electrons emit "extra" energy in the form of photons and return to their original energy levels.

Electrons jump to higher energy levels when excited by external energy gains such as B. Large heating, the presence of an electric field, or collision with another electron.

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Calculate the concentration of H3O ions present in a solution of HCl that has a measured pH of 5.310 .

Answers

[tex]\\ \tt\leadsto -log[H^+]=5.31[/tex]

[tex]\\ \tt\leadsto log[H^+]=-5.31[/tex]

[tex]\\ \tt\leadsto [H^+]=antilog(-5.31)[/tex]

[tex]\\ \tt\leadsto [H^+]=4.89\times 10^{-6}M[/tex]

To be effective, collisions between atoms must occur with the proper orientation and also the proper amount of __.

explosion

matter

energy

catalysis

Answers

To be effective, collisions between atoms must occur with the proper orientation and also the proper amount of energy.

What is the loss of kinetic energy due to the collision?

An inelastic collision is a collision in which there is a loss of kinetic energy. While the momentum of the system is conserved in an inelastic collision, the kinetic energy is not. This is because some kinetic energy has been transferred to something else.

In this case, is necessary have energy to be effective, so collisions between atoms must occur with the proper orientation.

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Answer:

energy

Explanation:

hi I really need help with this.
Balance the following neutralization reactions:

_______ HBr + _______ KOH _______KBr + _______H2O

_______ HF + _______ Fe(OH)3 _______FeF3 + ______ H2O

______HCl + _______ Ca(OH)2 _______CaCl2 + ______ H2O

Answers

Answer:

Explanation:

In order to balance equations, simply alter coefficients until all elements are equal on both sides of the reaction symbol ”—>”:

1HBr + 1KOH —> 1KBr + 1H2O

The reaction is already balanced

3HF + Fe(OH)3 —> FeF3 + 3H2O

To match the 3 Flluorines on the right hand side, add 3 to HF and then add 3 to H2O to compensate for the increase in hydrogens.

2HCl + Ca(OH)2 —> CaCl2 + 2H2O

The Chlorine must be balanced, and then hydrogen must be balanced.

Hope this helps! If it did, I would appreciate if you provided brainliest!

Determine the ground-state electron configuration for each of the following elements: A. chlorine ______________________________________________________________________ B. cesium ______________________________________________________________________ C. vanadium______________________________________________________________________ D. rhenium______________________________________________________________________ 2. Predict the number of valence electrons present in each of the following atoms (include the outermost d- electrons): A. Sn ___________________________ B. La___________________________ C. Mn__________________________ D. Zn __________________________ 3. Determine the ground-state electron configuration for each of the following ions:

Answers

In ground-state electron configuration, the principal quantum number (n), the orbital (s, p, d, or f), and the total number of electrons are used to represent electron configurations.

Case 1 Ground-state electron configuration of elements.

A) Chlorine: 1s²2s²2[tex]p^{6}[/tex]3s²3[tex]p^{5}[/tex]

B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹

C) Vanadium: 1s²2s²2p⁶3s²3p⁶3d³4s²

D) Rhenium: 1s² 2s² 2p⁶ 3s² 3p⁶3d¹⁰ 4s²4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁵ 6s²

Case 2 : Number of valence electron in atoms

A) Sn -Tin - Four valence electrons

B) La - Lanthanum - Three valence electrons

C) Mn - Manganese - Seven valence electrons

D) Zn- Zinc - Two valence electrons

Case 3 Ground-state electronic configuration of ions

A) Co⁺³ : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹3d⁵

B) Mo⁺² : 1s² 2s² 2p⁶3s²3p⁶ 4s² 3d¹⁰ 4p⁶5s² 4d²

C) Ra⁺² : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p⁶

D) I⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶

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Consider the following reaction:
3 Br2 + 6 OH¹-5 Br¹ + BrO3¹ + 3 H₂O
If 4.68 moles of Br2 are reacted with 8.12 moles of OH¹, how many moles of Br
can be formed? (Report your answer to two places past the decimal point.
Moodle is looking for a number only, no units.)

Answers

Answer:

Explanation:

I'm assume that 3 Br2 + 6 OH¹-5 Br¹ + BrO3¹ + 3 H₂O is meant to read:

3 Br2 + 6 OH^-1    =   5 Br^-¹ + BrO3^-¹ + 3 H₂O

The balanced equation tells us that 3 moles of Br2 will react with 6 moles of OH^-1 to produce 5 moles of Br^-1.

The first step is to determine whether the Br2 or OH^-1 are limiting reagents.  That is, is there enough of each to complete the reaction, with none left over.

We need 3 moles of Br2 for every 6 moles of OH^-1, a molar ratio of 1/2 (Br2/OH).

We are given 4.68 moles of Br2 and 8.12 moles of OH^-1.  That is a ratio of 4.68/8.12 or 0.5764.  This is higher than the ratio of 1/2 or 0.5 that is required.  That means we have more than enough Br2.  The limiting reagent is the OH^-1.  Once it is consumed, the reaction stops and we are left with some unreacted Br2.

So we need the molar ratio of the OH^-1 to the Br from the balanced equation:  We see that 6 moles of OH^-1 are required to produce 5 moles of Br, a 6/5 molar ratio.

Therefore, we may assume all 8.12 moles of the limiting reagent, OH^-1, will be consumed to produce *6/5) that amount of Br.

(8.12 moles OH^-1)*((6 moles Br)/(5 moles OH^-1)) = 9.75 moles of Br.

For curiosity's sake, we can determine the amount of unreacted Br2.  8.12 moles of OH^-1 would require (8.12 moles OH)*(1/2) = 4.06 moles of Br2.

4.68 moles starting Br2

4.06 moles consumed

0.62 moles remaining Br2

What coefficients are needed to balance the following:

Cu(NO3)2 + GaI3 →CuI2 + Ga(NO3)3


What coefficients are needed to balance the following:

Cu(NO3)2 + GaI3 →CuI2 + Ga(NO3)3


A. 2,3,3,2

B . 1,1,1,1

C. 2,3,2,3

D. 3,2,3,2

Answers

The answer to this question is D. 3,2,3,2

Find the correct mass and the volume calculated from #10 to #13 to
calculate the density. Density = (4.7033 x 104 g/ 2.6540 x 106 mL) =

Answers

The density = 1.77 x [tex]10^{-2}[/tex] where Mass =4.7033 x [tex]10^4[/tex] g and Volume=2.6540 x [tex]10^6[/tex]mL.

What is density?

Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density Symbol: D or ρ Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Given:

Density = (4.7033 x [tex]10^4[/tex] g/ 2.6540 x [tex]10^6[/tex] mL)

Mass =4.7033 x [tex]10^4[/tex] g

Volume=2.6540 x[tex]10^6[/tex] mL

Density = (4.7033 x [tex]10^4[/tex] g/ 2.6540 x [tex]10^6[/tex] mL)

Density = 1.772155237 x [tex]10^{-2}[/tex] = 1.77 x [tex]10^{-2}[/tex]

Hence, the density = 1.77 x [tex]10^{-2}[/tex].

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How does a fire extinguisher works ?​

Answers

Answer:

Most fire extinguishers work by separating the fuel from the oxygen. The oxygen comes from the air. It is the same oxygen we breathe. Since the oxygen has to be in contact with the fuel, if you can coat the fuel with something that keeps the oxygen away, the fire will go out. Some ways of using fire extinguisher are:

Water extinguishers work mainly by cooling (removing heat), but a dense spray of water droplets also helps to cut off oxygen.

Dry powder extinguishers soak up heat, melt on the fuel, and cut off oxygen, but they also neutralize the fuel (cutting it off from the fire) .

Explanation:

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A solution containing 1 mol of a strong electrolyte will have a(n) _____ effect on the colligative properties of the solution than 1 mol of a nonelectrolyte. A strong electrolyte will dissociate or ionize in aqueous solution, and therefore the total number of dissolved solute particles is _____ for 1 mol of a strong electrolyte than for 1 mol of a nonelectrolyte solute.

Answers

A solution containing 1 mol of a strong electrolyte will have a greater effect on the colligative properties of the solution than 1 mol of a nonelectrolyte. A strong electrolyte will dissociate or ionize in an aqueous solution, and therefore the total number of dissolved solute particles is greater for 1 mol of a strong electrolyte than for 1 mol of a nonelectrolyte solute.

How do electrolytes work?

An electrolyte is a material that separates into charged ions when it is in contact with water. Cations are positively charged ions. Anions are ions that are negatively charged. A substance that may conduct an electric current when melted or dissolved in water is known as an electrolyte.

Types of electrolytes:-

A substance is referred to as a strong electrolyte if the physical or chemical process that produces the ions is virtually 100% effective (all of the dissolved molecules give ions). Weak electrolytes are those in which only a very small portion of the dissolved substance goes through the ion-producing process.

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25. An equilibrium mixture of SO2 (g), O2 (g), and SO3 (g) is transferred from a 1.00L flask to a 2.00-L flask. In which direction does the reaction proceed to restore equilibrium

Answers

This chapter deals with chemical equilibrium, or how far chemical reactions proceed. Some reactions convert reactants to products with near 100% efficiency but others do not.

Chemical equilibrium is a dynamic process and occurs when the rates of two opposing processes (reactions) become the same. Unless conditions are somehow changed, the concentrations of both reactants and products remain constant after equilibrium is achieved.

Consider the decomposition reaction in which N2O4 (g) ' 2 NO2(g) What happens to the concentration of each, based upon the rate equations, as the reaction proceeds

Assuming reversible elementary processes, Rate (forward) = k (forward) x [N2O4]  and rate (reverse) = k (reverse) x [NO2]2As [N2O4] decreases, rate forward decreases, and, as [NO2] increases, rate reverse increases, but more quickly.

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The main combustible part of wood is cellulose, a compound of carbon, hydrogen, and oxygen, which, when it burns, breaks down to _____, water, and heat.

Answers

The main combustible part of wood is cellulose, a compound of carbon, hydrogen, and oxygen, which, when it burns, breaks down to carbon dioxide, water, and heat.

What is Combustible Substance ?

The substances which catches fires easily in air and produce heat and light upon burning is known as Combustible Substances.

Example: Wood, Oil, Kerosene, Hydrogen gas, Cloth etc.

When these compounds carbon, hydrogen and oxygen burns completely the carbon oxidizes to carbon dioxide , water and heat.

Thus from the above conclusion we can say that The main combustible part of wood is cellulose, a compound of carbon, hydrogen, and oxygen, which, when it burns, breaks down to carbon dioxide, water, and heat.

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1. How many grams of sodium chloride is produced when 3.4 g of sodium reacts with 8.9 g of chlorine in
this balanced equation?
2Na+ Cl₂ → 2NaCl

Answers

The Answer to the question is 14 grams approximately.

Atomic mass of Na = 23 u

Given mass of Na = 3.4 gm

Moles of Na = given mass of Na / molar mass of Na

Moles of Na = 3.4 / 23 moles = 0.15 moles approximately

So, 0.15 moles of Na approximately

Molar mass of Cl₂ = 35.45 × 2 = 70.9  u

Given mass of Cl₂ = 8.9 gm

Moles of Cl₂ = given mass of Cl₂ / molar mass of Cl₂

Moles of Cl₂ = 8.9 / 70.9 moles = 0.12 moles approximately

So, 0.12 moles of Cl₂ approximately

Balanced chemical equation

2Na   +     Cl₂ → 2NaCl

Ratio of Moles to Stoichiometric coefficients

0.15/2     0.12/1  

0.075  <  0.12

So, as ratio of Na is less then it will be our Limiting reagent.

Which means that Cl₂ will consume complete in the reaction.

It is clear from the reaction that 1 moles of Cl₂ are making 2 mole of NaCl

1 moles of Cl₂ → 2 mole of NaCl

0.12 moles of Cl₂ → 2 × 0.12 mole of NaCl

0.12 moles of Cl₂ → 0.24 mole of NaCl

So, 0.12 moles of Cl₂ will make 0.24 mole of NaCl

0.24 mole NaCl = mass formed NaCl / molar mass of NaCl

mass formed NaCl = 0.24 × molar mass of NaCl

mass formed NaCl = 0.24 × 58.44

mass formed NaCl = 0.24 × 58.44

mass formed NaCl = 14 grams    (approximately)

14 grams of NaCl will be formed.

So, approximately 14 grams NaCl is formed from 3.4 grams of Na and 8.9 grams of Cl.

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Write the balanced molecular equation for the neutralization reaction between HI and Ba(OH)2 in aqueous solution. Include physical states.
molecular equation

Answers

neutralization reaction = acid+base = salt + water

molecular equation = balanced equation

2HI(aq) + Ba(OH)₂(aq) ⇒ BaI₂(aq) + 2H₂O(l)

I2 (s) has a very low solubility in H2O (l) because the weak _____ forces between I2 and H2O are not strong enough to replace the _____ between the H2O molecules.

Answers

I2 (s) has very low solubility in H2O (l) because the weak dipole-induced dipole forces between I2 and H2O are not strong enough to replace the hydrogen bonds between the H2O molecules.

Dipole interactions are susceptible interactions that get up from the close association of permanent or precipitated dipoles. Collectively these forces are called Van der Waals interactions. Proteins incorporate a massive number of these interactions, which vary substantially in energy.

Solubility depends on the solvent's capacity to overcome the intermolecular forces in a solid. Red blood cells have an excessive concentration of dissolved ions. When positioned into pure water they rupture.

Polar species are soluble in water, whilst nonpolar species are soluble in oils and fats. Covalent solubility uses the like dissolves like a rule. This means that materials with an equal form of polarity might be soluble in one another. moreover, compounds with differing polarities might be insoluble in one another.

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How can gamma rays be harmful?
OA. They consist of high-energy radiation that can travel through most
materials.
B. They are large particles that can break apart other particles.
C. They are fast-moving particles that can penetrate the skin.
D. They are small, slow particles that can cause uncontrolled chain
reactions.

Answers

Answer:

option c

Explanation:

They are fast-moving particles that can penetrate the skin.

Polonium-208 is an alpha emitter with a half-life of 2.90 years. How many milligrams of polonium from an original sample of 2.00 mg will remain after 8.00 years

Answers

Answer:

0.296 mg

Explanation:

8.00/2.90 half lives have passed, so this means the remaining mass is

[tex]2.00 {(0.5)}^{8.00 \div 2.90} [/tex]

which is about 0.296 mg.

The amount of polonium remaining after 8.00 years is 0.296 mg. This is obtained by using rate law of first order kinetics.

What is the rate law of first order kinetics and the half-life of the compound?

The expression for the rate law for first order kinetics is

k = [tex]\frac{2.303}{t}log\frac{a}{a-x}[/tex] years⁻¹

Where,

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x  - final amount of the reactant

The expression for the half-life of the compound is

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex] years

Calculating the amount of polonium remained after 8.00 years:

Given that,

A Polonium-208 is an alpha emitter with a half-life of 2.90 years.

I.e., [tex]t_{\frac{1}{2}}[/tex] = 2.90 years

Then,

2.90 = (0.693)/k

⇒ k = (0.693)/(2.90) = 0.2389 years⁻¹

Then,

for t = 8.00 years,

Since we have rate law of first order kinetics as

k =  [tex]\frac{2.303}{t}log\frac{a}{a-x}[/tex]

⇒ k = (2.303/8.00) log(a/a-x)

Where the initial amount of the reactants is a = 2.00 mg

So,

k = 0.287 log (2.00/a-x) (a-x is the final amount of the reactants)

⇒ 0.238 = 0.287 log(2.00/a-x)

⇒ (0.238/0.287) = log(2.00/a-x)

⇒ 0.829 = log(2.00/a-x)

⇒ (2.00/a-x) = [tex]10^{0.829}[/tex] = 6.745

⇒ (a-x) = 2.00/6.745 = 0.296 mg

Therefore, the remaining polonium is 0.296 mg after 8.00 years.

learn more about first order kinetics here:

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