Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 6.50 M HCl(aq) are required to react with 8.75 g Zn(s)?

Answers

Answer 1

Answer:

41.17

Explanation:

n Zn =  mass / m.wt

      = 8.75 /(65.4) = 0.1338 mole

n HCL = ( from the balanced equation )

     2HCL                  Zn

          2mole   → 1  mole

          x  mole     →             0.1338mole

     n HCL = .268 mole

M= mole/liter

6.50= 0.268/x

so u have0.04117  liter = 41.17 ml

Answer 2

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 41.17 ml of 6.50 M HCl(aq) are required to react with 8.75 g Zn(s).

What is mole?

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

Mathematically,

number of moles of zinc=  mass / molecular mass

                                       = 8.75 /(65.4) = 0.1338 mole

number of moles of HCl ( from the balanced equation )

2 moles of HCl reacts with one mole of Zn

number of moles of HCl = 2×0.1338 =0.268 mole

Molarity = number of mole of HCl/volume occupied by solution

6.50= 0.268/volume

Volume of HCl = 41.17 ml

Therefore, 41.17 ml of 6.50 M HCl(aq) are required to react with 8.75 g Zn(s).

To know more about mole, here:

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Answers

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