Yvette drops her cell phone as she is getting out of the truck one day she noticed that the cell phone fell 1.5m to the ground how fast was the phone moving right before hitting the ground

Answers

Answer 1

Answer:

The speed was 5.42 m/s

Explanation:

The height of fall of the phone s = 1.5 m

The phone was at rest in her hand, so the initial velocity u = 0 m/s

The velocity right before the phone strikes the ground v = ?

Using the equation

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gs

where

g is the acceleration due to gravity = 9.81 m/s^2

substituting values, we have

[tex]v^{2}[/tex] = [tex]0^{2}[/tex] + 2(9.81 x 1.5)

[tex]v^{2}[/tex] = 29.43

v = [tex]\sqrt{29.43}[/tex] = 5.42 m/s


Related Questions

Calculate the de Broglie wavelength of a 4.5-MeV α particle. Explain if a relativistic or non-relativistic approach is required

Answers

Answer:

4.4x10^-32m

Explanation:

Using

Wavelength = hc/E

= 6.63*10^-34 * 3x10^8/ 4.5 x10^ 6ev

= 4.4*10^-32m

Yes a relativistic approach is used because the particle moves at the speed of light

A scientific LAW has been proven and a THEORY has not. True Or False​

Answers

Answer:

true

Explanation:

i did the test its right

Answer:

true

mark mine as brainiest, i could use the points

A body is projected vertically upwards with a velocity of 10m/s from a vertically upward position at height h another body is dropped down at the same instant

Answers

Answer:

0.25 second  

Explanation:

Given :

Velocity, v = 10 m/s

The height,

[tex]$ h = \frac{v^2}{2g} $[/tex]

[tex]$ h = \frac{10^2}{2\times 9.8} $[/tex]

   = 5 m

Therefore the time at which both the bodies meet is

[tex]$ t = \frac{h}{v+v} $[/tex]

[tex]$ t = \frac{5}{10+10} $[/tex]

[tex]$ t = \frac{5}{20} = 0.25$[/tex]

So, time taken is 0.25 seconds

In a walking investigation, Josephine

walked a total distance of 40 feet. At the

halfway point, she had walked for 25

seconds. She stopped for 5 seconds to tie

her shoe and then continued for 25 more

seconds. Sketch a graph that shows

Josephine's distance from the starting point

over time

Answers

Explanation:

She walked 20 feet in the first 25 seconds.  Then she stayed at the 20 foot position for 5 seconds.  Then she walked another 20 feet in 25 seconds.  See attached graph.

A carpenter apprentice was killed when he was struck in the head by a nail that was fired from a powder actuated tool. The tool operator, while attempting to anchor a plywood form in preparation for pouring a concrete wall, fired the gun, causing the nail to pass through the hollow wall. The nail traveled some twenty-seven feet before striking the victim. The tool operator had never received training in the proper use of the tool, and none of the employees in the area were wearing personal protective equipment. What should be recommended to prevent this accident from happening again?

Answers

Answer:

Explanation:

The recommendations that need to be urgently addressed by the workshop and it's employees are

1) Training of all employees (particularly the tool operators) on the safe and proper use of all tools used in the course of the carpentry work.

2) Training of all employees in health, safety and environment (HSE). This training will help them appreciate the importance of always wearing personal protective equipment (PPE) when at the workshop or during the course of a work (because if the apprentice was putting on an engineer's helmet, he could have been safe).

3) Employees who fail to adhere strictly to the use of PPE should be sanctioned or even dismissed from the workplace

HELPPPP PLSSSS A group of students is investigating whether air resistance depends on the size of an object. The students throw two paper pieces each with the same force. One piece of paper is flat and the other is scrunched into a ball. The distance traveled by each paper piece is shown. Experimental Observations Student 1 Student 2 Student 3 Student 4 Distance traveled by flat paper 0.2 m 1.2 m 1.5 m 0.8 m Distance traveled by scrunched paper 1.5 m 2.4 m 3 m 2 m What was the test variable (independent variable) in this experiment? A.Distance traveled by flat paper B.The shape of the paper C.Distance traveled by scrunched paper D.The number of students

Answers

Answer:

Explanation: societal law is A statement about how things act in the natural world. the wire and electro magnet need to touch in question 2. a decrease in spee decreases kinetic energy. the test variable was the distance traveled by the scrunched paper.

Answer:

B

Explanation:

The shape is the only thing that changes.


Determine the acceleration (in m/s) of an object which

A. changes its velocity from 12.1 m/s to 23.5 m/s in 7.81 seconds

B. accelerates from 33.4 m/s to 18.9 m/s over a distance of 109 m

C. accelerates from 21.5 m/s to 8.9 m/s over a distance of 109 m

Please help!

Answers

Explanation:

A=23.5-12.1/7.81

1.46

b)(18.9^2-(33.4)^2)/2(109)

-3.5

c)8.9^2-(21.5)^2/2(109)

-1.76

According to the Newton's second law, which of the following is TRUE about a person pushing a lawn mower? А The net external force applied by the person is the push plus friction exerted on a lawn mower. B The force exerted by the person pushing the mower must be less than the friction opposing the motion. С The direction of the acceleration is the same direction as that of the net force, which is parallel to the ground. D The direction of the acceleration is the same direction as that of the force of friction, which is parallel to the ground.​

Answers

Answer:

The correct option is;

C. The direction of the acceleration is the same direction as that of the net force, which is parallel to the ground

Explanation:

Newton's second law of motion states that the acceleration which a net force on an object  produces has a magnitude that is directly proportional to that of the magnitude of the net force, and the direction of the acceleration is the same as that of the net force that produces it.

Therefore, given that the net force which tends to push the lawn mower across the grass acts parallel to the ground, the direction of the is in the same direction of the net force, moving parallel the ground.

A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time

Answers

Answer:

[tex] \boxed{\sf Distance \ travelled = 44 \ m} [/tex]

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

[tex] \boxed{ \bold{s = (\frac{v + u}{2} )t}}[/tex]

By substituting value of v, u & t in the equation we get:

[tex] \sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\ \\ \sf \implies s = \frac{22}{2} \times 4 \\ \\ \sf \implies s = 11 \times 4 \\ \\ \sf \implies s = 44 \: m[/tex]

[tex] \therefore[/tex]

Distance travelled by car (s) = 44 m

when we increase the exponent 10 to 10 we must

Answers

Answer:

If you say it like this (x^10)^10, then it would be x^100.

A modified Atwood machine is at rest. The hanging block has a mass of 3kg. The black on wheels has unknown mass M1. When released the block m2 falls at 5.88m/s^2. If frictional forces are considered so small they are negligible, the block M1 must have a mass of _______ kg.

Answers

Answer:

From the figure,

The free-body diagrams for  and  are shown in the figures below. The only forces on the blocks are the upward tension  and the downward gravitational forces  and  . Applying Newton’s second law, we obtain:   

which can be solved to yield 

Substituting the result back, we have 

(a) With  and , the acceleration becomes   

(b) Similarly, the tension in the cord is   

Can someone help me with this?

Answers

Answer:

1- origin

2- y coordinate

3- y axis

4- x axis

5- x coordinate

Explanation:

Why is there no ideal time of day when all students should study?

Answers

Answer:because each individual works best at a different time of day. D. because scheduling prevents everyone from studying at a set time. emilleexo818 is waiting for your help.

Explanation:

Answer:

The correct and overall question would be: Because each individual works best at a different time of day

Explanation:

(I'm smart and I took the quiz, I hope this helped guys! :)

When one type of energy changes to another type of energy *
A. constant
B. energy conservation
C. energy transformation
D. Other:

Answers

Answer:

Energy transfer is the movement of energy from one location to another. Energy transformation is when energy changes from one type to another. While energy can be transferred or transformed, the total energy always remains the same.

Explanation:

Energy Transformation

What is the strength of electric field EpEp 0.60 mmmm from a proton? Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

3.99*10^-3N/C

Explanation:

Using

Ep= kq/r²

Where r = 0.6mm = 0.6*10^-3m

K= 8.9*10^9 and q= 1.6*10^-19

So = 8.9*10^9 * 1.6*10^-19/0.6*10^-3)²

= 3.99*10^-3N/C

The height of a model rocket h(t) is a function of the time since it was launched t

Answers

Answer:

0 [tex]\leq[/tex] t [tex]\leq[/tex] 40

Explanation:

Apex :)

I NEED THIS IN AN HOUR! PLEASE PLEASE PLEASE HELP Tim and Jim measured the length of the same piece of board. Using a certain ruler, Tim obtained a length of 0.96 centimeter. Using a different ruler, Jim obtained a length of 0.9662 centimeter. Which measurement is better? Explain the reason for your answer.

Answers

Answer:

Jims is better

Explanation:

His number is more complex which means it is more accurate

Who is the father of nuclear physics?​

Answers

Answer: the father of the nuclear physics is Ernest Rutherford

Explanation:

Two jars are placed on a counter with a McDonald’s French fry inside. One has a lid, the other does not. They are left alone to see which one decays faster. After two days, the fry in the closed jar looks fresher.

The independent variable is?
The dependent variable is?
What should my conclusion be?

Answers

Your conclusion would be that the jar that’s lid is closed will be more fresh then the one with no lid

1. An arrow is shot with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. What is the maximum height it will reach?


a. 23 m

b. 46 m

c. 69 m

d. 92 m


2. A projectile is launched horizontally from a cliff with an initial speed of 40 m/s. The cliff is 125 m high and the projectile travels a horizontal distance of 200 m from the bottom of the cliff. What is the speed of the projectile right before it hits the ground?


a. 48 m/s


b. 52 m/s


c. 56 m/s


d. 60 m/s


e. 64 m/s

Answers

Answer:

46m

Explanation:

Given the following :

Initial Velocity (u) = 60

Angle(θ) = 30°

Maximum height it will reach?

The maximum height if a projection is calculated using the formula :

H = u²sin²θ / 2g

Where H = maximum height, g = acceleration due to gravity = 9.8m/s²

H = (60²sin × 0. 5²) / 2(9.8)

H = 900 / 19.6

H = 45.918m

H = 46m

A hollow plastic sphere is held below the surface of a fresh-water lake by a cord anchored to the bottom of the lake. The sphere has a volume of 0.650 cubic meters and the tension in the cord is 900 N. a) Calculate the buoyant force exerted by the water on the sphere. b) what is the mass of the sphere? c) the cord breaks and the sphere rises to the surface. When the sphere comes to rest, what fraction of its volume will be submerged?

Answers

Answer: a) B = 6811N

              b) m = 603.2kg

              c) 86.8%

Explanation: Buoyant force is a force a fluid exerts on a submerged object.

It can be calculated as:

[tex]B=\rho_{fluid}.V_{obj}.g[/tex]

where:

[tex]\rho_{fluid}[/tex] is density of the fluid the object is in;

[tex]V_{obj}[/tex] is volume of the object;

g is acceleration due to gravity, is constant and equals 9.8m/s²

a) For the hollow plastic sphere, density of water is 1000kg/m³:

[tex]B=10^{3}.0.695.9.8[/tex]

B = 6811N

b) Anchored to the bottom, the forces acting on the sphere are Buoyant, Tension and Force due to gravity:

B = T + [tex]F_{g}[/tex]

B = T + mg

mg = B - T

[tex]m=\frac{B - T}{g}[/tex]

Calculating:

[tex]m=\frac{6811 - 900}{9.8}[/tex]

m = 603.2kg

c) When the shpere comes to rest on the surface of the water, there are only buoyant and gravity acting on it:

B = m.g

[tex]\rho_{w}.V_{sub}.g=m.g[/tex]

[tex]V_{sub}=\frac{m}{\rho_{w}}[/tex]

[tex]V_{sub}=\frac{603.2}{1000}[/tex]

[tex]V_{sub}[/tex] = 0.6032m³

Fraction of the submerged volume is:

[tex]\frac{V_{sub}}{V_{obj}}[/tex] = [tex]\frac{0.6932}{0.695}[/tex] = 0.868

A runner changing speed from 3 meters per second to 5 meters per second is an example of

Answers

Answer: acceleration

Explanation:

he is accelarting from 3 meters per second to 5 meters per second

Answer:

acceleration

Explanation:

A dog runs 300m North and sees the dog catcher and runs 120 m south .Whats the dogs displacement.The same jogger runs 3 miles around the track, starting and finishing in the same time after completing exactly 12 laps. What is the average velocity now

Answers

Answer:

1. 180 m

2. 1.5 miles/hour

3. 0 m/s

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = 180 m

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = 1.5 miles/hour

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = 0 m/s

please anyone help me to answer this questions.plzz... it's very urgent..

Answers

Answer:

1) 3 applications of pressure in daily life are :-

● The area of sharp edge of knife, scissor or handsaws are much less then blunt edge. So, for same total force pressure is more for sharp edges than the blunt one. Hence sharp knife, scissors etc, cuts easily than a blunt one.

●Broad handles in bags and suitcases are provided for the comfort. Broad handles have large area. So, the pressure exerted on hands and shoulders would be small while carrying the bags and the suitcases.

●Trucks carrying heavy loads have more than four tyres. More tyres in case of trucks increase the area of contact with the road. This results in reduced pressure on the tyres.

2) Area of the surface which is on ground = 1.5×1

= 1.5m^2

Mass of the block = 300kg

Force applied by the block = Mass × g = 300×10

= 3000N (where g = acceleration due to gravity )

Pressure = Force applied / Area of the surface

= 3000N / 1.5m^2

= 2000 Pa

3)

a) The above experiment signifies that more the area of the surface of an object , less the pressure an object applies.

b) B exerts the minimum pressure because the area of its surface to ground is greater than others & as it has more area of surface , it exerts less pressure. ( area is inversely proportional to pressure )

c) D exerts the maximum pressure because the area of its surface to ground is lesser than others & as it has less area of surface , it exerts more pressure. ( area is inversely proportional to pressure )

d) It depend upon the way an object is kept on ground. If an object is kept in such a way dat the area of the surface to the ground is more , then pressure will be least exerted .If an object is kept in such a way dat the area of the surface to the ground is less, then pressure will be exerted more .

e) Do it yourself . only i will suggest that make the tip of the cone ( which is to the ground ) more narrower.

Explanation:

Phylis Physics travels a displacement of 2.50 km north followed by 4.30 km south and then 1.40 km north. What is her final displacement? What total distance did she travel?

Answers

Answer:

Her final displacement is 0.4 km North

Her total distance is  8.2 km

Explanation:

Given;

initial position, = 2.5 km north

then 4.3 km south

final position = 1.4 km north

let northward direction = positive direction

let southward direction = negative direction

The final displacement = 2.5 km North - 4.3 km South + 1.4 km North

The final displacement = -0.4 km North

Thus, the magnitude of the final displacement = 0.4 km North

In distance, the direction of the motion is not considered

The total distance = 2.5 km + 4.3 km + 1.4 km

The total distance = 8.2 km

How does online gaming affect the health of the student

Answers

Answer:

because we more see th online gaming and not eat food and playing that game all the time so it effect the health

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The atmospheric pressure at normal conditions is equal to 10.33 m under water. Then 1.0mm mercury equals to
mm water.

Answers

Answer:13.6

Explanation:

Two point charges are separated by a certain distance. How does the strength of the electric field produced by the first charge, at the position of the second charge, change if the second charge is doubled?

Answers

Answer:

The field will remain the same

Explanation:

This is because electric field given as

E1= kq1/r²

And that of second charge

E² = kq2/r²

Is not affected by the size of the second charge q2

Energy flow in an ecosystem is best represented by
a. the predator/prey relationship
b. food chains
C. food webs
d. autotrophs

Answers

Answer:

It's actually C. food webs

Explanation:

took the test

Answer: c

Explanation:

edge 2020

Convert 300 K into the celsius scale
Convert 220 °C into kelvin scale.
Convert 30 °C into fahrenheit scale
Convert 260 °F into °C.​

Answers

Answer:

26.85 Celsius.

493.15 Kelvin

86F

26.85

493.15

Tk=Tc+273.15

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