Answer:
a.
Explanation:
draw it that way velocity draw
hope it's helpful
Two objects are sitting 150 meters apart and are not moving. Which best explains why the gravitational force does not cause them to move?
In the above pic question is similar like that only
Answer:
The gravitational force between the two objects is weak because their masses are small
Did the heliocentric model explain the drawbacks of the geocentric model?
Answer:
uuuugggghhhhhhhhggggffffffffffffff
Answer:
The geocentric model could not fully explain these changes in the appearance of the inferior planets (the planets between the Earth and the Sun). Furthermore, Galileo's observations of Jupiter's moons made it clear that celestial bodies do move about centers other than the Earth.
Mark me as the brainlist
A tennis ball is hit straight upwards and undergoes a free fall
motion as it rises towards its highest point and then fall back
downward to the ground. What changes, if any, would be
observed of the velocity and the acceleration of the tennis
ball as it falls downward from its highest point? Pick two
answers.
The velocity increases, decreases, remains constant
The acceleration increases, decreases, remains constant
Answer:velocity - decreases
acceleration remains constant
Explanation:
(Plzzzz help!!!) (50 points!!!)
1. Write the following quantities in scientific notation:
(1) 10130 Pa to 2 decimal places
(2) 978,15 m·s−2
to one decimal place
(3) 0,000001256 A to 3 decimal places
Answer:
YEAH THE PERSON ABOVE ME IS RIGHT MARK
THEM BRAINLIST
A simple pendulum is made of a small blob of mass m=7.000 kg attached to the end of an inextensible wire. The angular amplitude of oscillation is θ=5.730°. Consider that the gravitational acceleration is g=9.807 m/[tex]s^{2}[/tex]. What is the magnitude of the tension in the wire when the blob is directly below its point of support?
Answer:
The tension must be equal to the weight of the bob plus the centripetal force that is provided at eth end of the motion.
h = L (1 - cos theta) where h is the height to which the bob is raised
cos 5.730 = .995
h = .005 L
Also 1/2 m v^2 = m g h speed of the bob at the bottom
v^2 = 2 g h = .01 g L where 2 h = .01 L
v^2 / L = .01 g
m v^2 / L = .010 g m = .07 g since m = 7
Total tension = m g (1 + .07) = 1.07 m g
T = 9.807 * 1.07 * 7 = 73.45 kg m / s^2
Logical thought is based on ____________, while creative problem solving uses ___________.
A.
insight; algorithms
B.
divergent thinking; convergent thinking
C.
convergent thinking; divergent thinking
D.
functional fixedness; mental sets
Answer:
D. and A
Explanation:
logical thought is base on functional fixedness; mental sets while creative problem solving uses insight; algorithms.
when a light ray enters the glass block it:
(a ) speeds up (b) slows down (c ) spreads out
Answer:
If a ray of light hits the surface of a sheet of glass, some light will be reflected by the surface of the glass. However, much of the light will pass through the glass, because glass is transparent. ... This 'bending of a ray of light' when it passes from one substance into another substance is called refraction.
Explanation:
Classify the following as reversible or irreversible changes a) ripening of mango b) evaporation of water c) melting of ice candy d) curdling of milk
c) melting of ice candy is an physical change
hope it helps
what is the radiation?
Answer:
Radiation is the transfer of energy through waves (electromagnetic radiation) or fast traveling particles (particulate radiation). Radiation can be in the form of heat, sound and light. Radiation can be felt or seen like light or detected through special instruments like X-ray. Radiation from a hot object is shorter..
Explanation:
Dato
F=0.0000001245066 N
Answer:
hpqfie
Explanation:
wdq i love math WOOOOO
Show all steps.
1.A cue ball (mass = 0.165 kg) is at rest on a frictionless pool table. The ball is hit dead center by a pool
stick, which applies an impulse of + 1.50 Ns to the ball. The ball then slides along the table and makes
an elastic head-on collision with a second ball of equal mass that is initially at rest. Find the velocity of
the second ball just after it is struck
Answer:
Steps and solution in the attached pictureSteps and solution in the attached picture.
Explanation:
Steps and solution in the attached pictureSteps and solution in the attached picture.
The velocity of the second ball just after it is struck will be 9.091 m/s.
What is an impulse?To quantify the effect of force acting over time to change the momentum of an object is referred to as impulse.
To calculate the velocity in the given scenario,
Given that,
mV=1.5
[tex]V=\frac{impulse}{mass}[/tex]
[tex]V=\frac{1.5}{0.165}[/tex]
V=9.091 m/s
Thus, the velocity will be 9.091 m/s.
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The electric force due to a uniform external electric field causes a torque of magnitude 20.0 × 10−9 N⋅m on an electric dipole oriented at 30∘ from the direction of the external field. The dipole moment of the dipole is 9.0 × 10−12 C⋅m.
What is the magnitude of the external electric field?
If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle?
[tex]\bull\sf Torque=\tau=20.0\times 10^{-9}Nm[/tex]
[tex]\bull\sf \theta=30°[/tex]
[tex]\bull\sf E=9.0\times C.m=9.0\times 10^{-12}N/C[/tex]
Now we know
[tex]\\ \sf\longmapsto \tau=pEsin\theta[/tex]
[tex]\\ \sf\longmapsto p=\dfrac{\tau}{Esin\theta}[/tex]
[tex]\\ \sf\longmapsto p=\dfrac{20\times 10^{-9}}{9\times 10^{-12}\times sin30}[/tex]
[tex]\\ \sf\longmapsto p=\dfrac{20\times 10^{-9}}{9\times 10^{-12}\times \dfrac{1}{2}}[/tex]
[tex]\\ \sf\longmapsto p=\dfrac{20\times 10^{-9}}{9\times 10^{-12}}\times 2[/tex]
[tex]\\ \sf\longmapsto p=4.4\times 10^3N/C[/tex]
The magnitude of the externla electric field is 4,444.44 N/C.
The magnitude of the charge is 3.1 x 10⁻¹² C.
Magnitude of the external electric fieldThe magnitude of the externla electric field is calculated as follows;
EPsinθ = τ
where;
E is the external electric fieldP is dipole momentτ is torque[tex]E = \frac{\tau}{P sin(\theta)} \\\\E = \frac{20 \times 10^{-9}}{9\times 10^{-12} \times sin(30)} \\\\E = 4,444.44 \ N/C[/tex]
Magnitude of the chargeThe magnitude of the charge is calculated as follows;
[tex]E = \frac{kQ}{r^2} \\\\Q = \frac{Er^2}{k} \\\\Q = \frac{(4,444.44) \times (2.5 \times 10^{-3})^2}{(9\times 10^9)} \\\\Q = 3.1 \times 10^{-12} \ C[/tex]
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Calculations, show formula, substitution, and answer with units for full credit:
1. A train travels 150 kilometers in 5 hours. How fast is it traveling?
Answer:
30 km/h
Explanation:
V=S:t
speed=length:time
150:5=30
The scientific method is
.linear or cyclic
the scientific method is described as self-correcting and cyclical therefore it ain't linear but cyclic.
Hope this helped you- have a good day bro cya)
A basketball player throws a ball horizontally toward another player 10 meters away. If the ball is
traveling at a speed of 20 m/s, neglecting air friction, how long does it take for the ball to get to the
other player?
Thank you!!!
Answer:
It will take 0.46 seconds to reach home plate by ball.
Explanation:
The lantern rises due to a change in the _________
the system
A. Average kinetic energy of
B. Matter around
C. State of matter of
D. Size of particles in
Answer:
I think it A. Average kinetic energy of
Explanation:
In solids, the molecules are very close together and the attraction between the molecules are great. This causes a substance to have a structure in which the molecules have little freedom to move, as you would see in the case of ice. In the case of a liquid, the molecules are closely spaced, though not as closely spaced as a solid, they have more freedom to move and the intermolecular forces are weaker that that of a solid. Thus a liquid can flow, unlike a solid. Now in a gas, the molecules are sufficiently far apart that there are little to no attractive forces. Because of this a gas can easily be compressed and take the shape of the container.
Now as you heat a solid turning it into a liquid, you increase the kinetic energy of its molecules, moving them further apart until the forces of attraction are reduced to allow it to flow freely. Keep in mind the forces of attraction still exists. Now as you heat a liquid, turning it into a gas, the kinetic energy of the molecules are increased to a point where there are no forces of attraction between the molecules.
The energy required to completely separate the molecules, moving from liquid to gas, is much greater than if you were just to reduce their separation, solid to liquid. Hence the reason why the latent heat of vapourization is greater that the latent heat of fusion.
Write a scientific explanation to describe where earthquakes and volcanoes most commonly occur and their relation to plate boundaries .
If Janie puts her hand on a cold metal doorknob, how will thermal energy move?
A- Cold moves from the doorknob to her hand.
B - Heat moves from her hand to the doorknob.
C- Heat moves from the doorknob to her hand.
D- Cold moves from her hand to the doorknob.
Answer:
it is b or c
Explanation:
Answer:
The answer is B I did the test.
Explanation:
I hope it helps!
For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Part A but this time using an aluminum cylinder of equal mass? Assume that the initial temperatures of the metals (Tm) and the initial temperatures of the water (Ti) were the same. Specific heat of copper: 0.385 J/g*K Specific heat of aluminum: 0.900 J/g*K Group of answer choices The magnitudes of his q and ∆H for the copper trial would be higher than the aluminum trial. The magnitudes of his q and ∆H for both trials would be the same The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.
The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.
The given parameters;
initial temperature of metals, = [tex]T_m[/tex]initial temperature of water, = [tex]T_i[/tex] specific heat capacity of copper, [tex]C_p[/tex] = 0.385 J/g.Kspecific heat capacity of aluminum, [tex]C_A[/tex] = 0.9 J/g.Kboth metals have equal mass = mThe quantity of heat transferred by each metal is calculated as follows;
Q = mcΔt
For copper metal, the quantity of heat transferred is calculated as;
[tex]Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w ) = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t[/tex]
The change in heat energy for copper metal;
[tex]\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t[/tex]
For aluminum metal, the quantity of heat transferred is calculated as;
[tex]Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w) = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t[/tex]
The change in heat energy for aluminum metal ;
[tex]\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t[/tex]
Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.
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Mass movements occur on slopes because of the pull of gravity.
a. True
b. False
Answer:
true
Explanation:
50 point!! Will mark brainliest!! (Please help)
What variable is impacting demand and is it increasing or decreasing based on the scenario.
With the threat of a blizzard people believe the price of snow blowers will increase.
What is the varaible? _____
What happens to demand? _____
What is the variable?
~the price is the variable.
What happens to demand?
~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.
Hope this helps- have a good day bro cya)
I agree with the other answer
What is the variable?
~the price is the variable.
What happens to demand?
~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.
A 0.56 kg block is suspended from the middle
of a 1.74 m long string. The ends of the string
are attached to the ceiling at points separated
by 1 m, and the block can slip along the long
string
The acceleration of gravity is 9.81 m/s?.
What angle does the string make with the
ceiling?
Notice that both strings have the same length, so they form an isosceles triangle, which means the angles they make with the ceiling are congruent.
If this angle has measure θ, then the angle between the two strings T₁ and T₂ has measure 180° - 2θ. This is because the interior angles of any triangle sum to 180°.
By the law of cosines, we have
(1 m)² = (0.87 m)² + (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)
Solve for θ :
(1 m)² = 2 (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)
(1 m)² / (2 (0.87 m)²) = 1 - cos(180° - 2θ)
cos(180° - 2θ) = 1 - (1 m)² / (2 (0.87 m)²)
cos(180° - 2θ) ≈ 0.3394
180° - 2θ = arccos(0.3394)
180° - 2θ ≈ 70.159°
2θ ≈ 109.841°
θ ≈ 54.9205° ≈ 55°
a___of water a. of bread a. of soap a. of juice a. salt. a. sand a. of glass a. of corn fill in the blanks I follow him but right answer
Answer:
a glass of water. a loaf of bread. a bar of soap.a packet of juice. a pinch of salt.
Explanation:
that's all I know
A car is being driven along a road at 25m/s when the driver suddenly notices that there is a fallen tree blocking the road 65m ahead. The driver immediately applies the brakes giving the car a constant velocity of 5m/s2. How far in front of the tree does the car come to rest?
Hi there!
We can use the following equation to solve for displacement:
vf² = vi² + 2ad, where:
vf = final velocity
vi = initial velocity
a = acceleration
d = displacement
Since the car will come to rest, vf = 0, so:
0 = vi² + 2ad
Plug in the given values:
0 = 25² + 2(-5)d (Breaking is a negative acceleration in this instance)
Solve:
0 = 25² - 10d
10d = 625
d = 62.5m
Subtract from the total distance from the car to the tree:
65 - 62.5 = 2.5m
which of the following is considered the "universal wave formula?"
1.T=1/f
2.v=fλ
3.λ=vf
4.f=vλ
Explanation:
2. v=fλ
HOPE IT HELPS YA_______________________
Two masses m1 13.6 kg and m2 22.9 kg are connected by a rope that hangs over the pulley. The pulley has form of solid cylinder of radius 0.6 m and mass 10.6 kg. Initially m1 is on the ground and m2 rests 8.0 m above the ground. At some moment system is released. Find velocity of m2 just before it hits the ground. Neglect friction in the pulley.
The conservation of energy allows finding the result of the velocity of the body 2 when it reaches the ground is:
v = 6.32 m / s
Given parameters
Body mass 1 m₁ = 13.6 kg body mass 2 m₂ = 22.9 kg height y = 8.0 mTo find
speed.
The conservation of energy is one of the most important principles of physics, it establishes that if there is no friction force, the mechanical energy is conserved at all points, where the mechanical energy is the sum of the kinetic energy plus the different potential energies.
Let's write the energy at two points before we drop the system.
Em₀ = U₁ + U₂
Where potential energy is
U = m g y
They indicate that body 1 is on the ground and body 2 is at a height .
y₂ = 8 m
Em₀ = m₂ g y₂
Let's write the energy of the system for when body 2 is reaching the ground
[tex]Em_f[/tex] = K₂ + K₁ + U₂ + U₁
At this moment body 2 is reaching the ground, its height is zero and the height of body 1 is y₁ = 8 m. Since the two bodies are joined by the rope, they must have the same speed..
[tex]Em_f[/tex] = ½ (m₁ + m₂) v² + m₁ g y₁
As there is no friction, the energy is conserved.
Em₀ = Em_f
m₂ g y₂ = ½ (m₁ + m₂) v² + m₁ g y₁
The rope is inextensible, the heights are equal.
y₁ = y₂ = y = 8.0 m
v² = [tex]\frac{m2-m1}{m2+m1} \ 2g y[/tex]
Let's calculate.
[tex]v^2 =\frac{22.9-13.6}{ 22.9+13.6} \ 2 \ 9.8 \ 8 \\ v = \sqrt{39.95}[/tex]
v = 6.32 m / s
In conclusion using the conservation of energy we can find the result of the velocity when the body 2 reaches the ground is:
v = 6.32 m / s
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a boy pull a toy car with a rope inclined at 60° to the vertical tension in the rope is 100N find the force of the lift car and drag the car along the ground
a body of mass x is raised to a height of 2m above the ground what it's potential energy if the body is allowed to fall what is it's kinetic energy when half way down
Answer:
hey i dont know what it is
Explanation:
What is defined as the isolation and reduction of variables in an experiment in order to understand the impact of a specific variable or variables on the outcome of the study?
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Isolation and reduction of variables in an experiment is a way to reduce administrative efforts, costs and delusions occur.
What is an experiment?An experiment is a technique used to prove or disprove a theory, or to test the efficacy or probability of something that has never been done before.
Experiments reveal cause-and-effect relationships by illustrating what happens when a specific component is changed.
Experiments have a wide range of goals and scales, but they always rely on a repeatable technique and rational interpretation of the outcomes. Natural experimental research is also available.
If you can plan a control group, you will be much better off. It increases the expense of the experiment by a factor of two and may cause delusions.
Furthermore, it doubles the administrative effort. However, it provides the most reliable and straightforward method for calculating significance,
By comparison, taking into consideration the deviations of each of the two groups of data that arise.
In many circumstances, a control group is required for analysis when you wish to look at certain lag periods or increases in addition to the final result.
Hence isolation and reduction of variables in an experiment are much more important to reduce.
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Un rió de 89 m de ancho fluye agua con una velocidad de 4.0 m/s hacia el este . Si el bote tiene una velocidad de 8 m/s con relación al agua.
Que distancia rio abajo se desplaza el bote al cruzar el rió.
6
Explanation:
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La distancia que el bote se desplaza rio abajo es 44.5 metros.
¿Que distancia rio abajo se desplaza el bote?
Debemos recordar que la velocidad en cada eje es independiente de la velocidad en el otro eje. Tambien recordar que:
distancia = velocidad*tiempo.
Esto quiere decir que si el bote se mueve a 8m/s de un extremo al otro del rio, esta velocidad en esta dirección se va a mantener.
Entonces el tiempo que tarda en viajar 89 metros (el ancho del rio) a una velocidad de 8m/s es:
T = (89 m)/(8m/s) = 11.125 segundos.
Ahora notamos que durante esos 11.125 segundos el bote tambien se mueve siguiendo el flujo del rio, a una velocidad de 4.0 m/s, entonces la distancia que el bote se desplaza rio abajo es:
D = 11.125s*4.0m/s = 44.5 metros
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