Work done = Froce × distance
Now, keeping this formula in mimd, we can find the distance as follows;
= 1.56 = 300 × distance
= 1.56/300 = distance
= 156/30000 = distance
= 0.0052 m = distance
Lets convert it into cm so that you don't get troubled seeing it :)
= 1 m = 100cm
= 0.0052 × 100
= 0.52 cm
Which of the following measurements has three significant figures
a. 0.0293 kg
b. 0.94 A
c. 5.321 V
d. 10.42 m
Answer:
b. 0.94 i think is the answer
what came first the chicken or the egg
Answer:
The Egg
Explanation:
personally the Chicken who would lay the egg would have to come from an Egg itself, then It would have to grow up and then Produce an egg that will produce a chicken and so on.
A car starts from rest and goes due east reaching a speed of 40 m/s What additional information is needed in order to calculate the acceleration of the car?
O A. the total distance traveled by the car
B. the total time of the car's motion
Cthe car's mass
O D. the car's initial velocity
Answer:leter B the answer
Explanation:
The additional information is needed in order to calculate the acceleration of the car is the total time of the car's motion.
What is acceleration?The acceleration of an object is the rate of change of velocity with time.
a = Δv/t
where;
Δ v is change in velocity = final velocity - initial velocityt is the time of motionWhen the change in velocity of the object and time of motion is known, the acceleration of the object can be determined.
Thus, the additional information is needed in order to calculate the acceleration of the car is the total time of the car's motion.
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(answer only if you know the answer or I'll report) Help me please solve it w steps
X component of force Fx=Fcos45=50×cos×45
Y component of force Fy=Fsin45=50×sin×45
A 0.2 kg hockey puck is sliding along the ice with an initial velocity of -10 m/s when a player strikes with his stick, causing it to reverse it's direction and giving it a velocity of +25 m/s. The impulse the stick applies to the puck is most nearly
I = 7 N-s
Explanation:
Impulse is defined as
I = ∆p = m(vf - vi)
We are given
m = 0.2 kg
vi = -10 m/s (to the left)
vf = +25 m/s (to the right)
Therefore, the impulse imparted on the puck is
I = (0.2 kg)[25 m/s - (-10 m/s)]
= (0.2 kg)(35 m/s)
= 7 N-s
A children's roller coaster is released from the top of a track. If its maximum speed at ground level is 3 m/s, find the height it was released from.
Answer:
h = 0.46 m
Explanation:
According to the law of conservation of energy:
Potential Energy Lost by Roller Coaster = Kinetic Energy Gained by Roller Coaster
[tex]mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\h = \frac{v^2}{2g}[/tex]
where,
h = height = ?
v = speed at bottom = 3 m/s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h = \frac{(3\ m/s)^2}{(2)(9.81\ m/s^2)}[/tex]
h = 0.46 m
Calcium is combined with Nitrogen in a chemical reaction. The formula of the compound created, Calcium Nitride, is
Answerrrrrrrrrrrrrrrrrt
Calcium is a 2+ ion which would be written as Ca^2+
Nitrogen is a 3- ion which is written as N^3-
When combined to create Calcium Nitrate it is Ca3N2
See picture:
Which of the following statements are true about covalent bonding between two atoms? Select all that apply.
A. Electrons are shared.
B. The electronegativities of the two atoms are close to each other.
C. The two atoms can be of the same element.
D. Electrons transfer from one atom to the other.
Answer:
A and C
Explanation:
Covalent bonding involves sharing by the atoms involved
Statements that can be considered as true statement about covalent bonding between two atoms are:
A. Electrons are shared.
B. The electronegativities of the two atoms are close to each other.
C. The two atoms can be of the same element.
Covalent bond can be regarded as chemical bond in which electrons pairs are been shared between atoms, these atoms can be of the same element.These electron pairs are called pairs or bonding pairs.Therefore, option A,B,C are correct.
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A toy mouse has a mass of 2 kg and kinetic energy of 25 J. What is its speed?
A. 4 m/s
B. 3 m/s
C. 6 m/s
D. 5 m/s
Answer:
D 5m/s
Explanation:
A star produces energy by:
A: creating helium from hydrogen in its core.
B: reflecting energy from nearby stars.
C: absorbing and releasing the matter of other stars.
D: rotating quickly on its axis.
Here, the hydrogen atoms are combined to form a helium atom, and during this process of fusion, a significantly large amount of energy is released. Thus, stars produce a large amount of energy by forming helium from the combination of hydrogen in its core. Hence, the correct answer is option (C).
Answer:
A. Creating helium from hydrogen in its core.
Explanation:
Sacrificed my grade for points I hope it helps
if molecule gains heat energy it converts liquid to gas
Answer:
Actually, the substance is the one that changes from liquid to gas.
The molecule just gains energy which overcomes the attraction force between it and neighboring molecule.
Explain why a kangaroo can jump higher as it's speed increases
Answer:
See explanation
Explanation:
The ability of the Kangaroo to jump higher is due to the stretching of its tendons as its speed increases.
As the tendons are being stretched more and more, the elastic potential energy increases with each increasing stretch.
This elastic potential energy is translated into gravitational potential energy hence the Kangaroo jumps higher as it's speed increases.
The kangaroo can jump higher as it's speed increases due to the ability of its tendons to stretch more and more.
The jumping of kangaroo can be related with the concept of spring force and spring potential energy. The spring force is given as,
F = kx
And spring elastic potential energy is,
[tex]U=\dfrac{1}{2}kx^{2}[/tex]
In both the cases, k is the spring constant and x is the stretching distance.
When kangaroo try to jump, the tendons provide extra flexibility to jump higher due to the more stretching. Here, the value of x increases. As value of x increases, ultimately more acceleration is provided to increase its speed.As the tendons are being stretched more and more, the elastic potential energy increases with each increasing stretch.
This elastic potential energy is translated into gravitational potential energy hence the Kangaroo jumps higher as it's speed increases.
Thus, we can conclude that the kangaroo can jump higher as it's speed increases due to the ability of its tendons to stretch more and more, such that more energy conversion of energy takes place.
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Weathering of rocks can occur in many ways. In the western United States, strong winds can erode huge rock formations by blowing millions of tiny grains of sand at these rocks. Which term accurately describes this type of weathering?
Answer: physical or mechanical weathering
Explanation:
Mechanical weathering which is also referred to as the physical weathering occurs when a rock is broken down into smaller pieces. In this case, there will be a physical change of the rock but its composition will not change.
Some examples include ice freezing and expansion of the cracks in the rock, Smstrong winds that carrycpieces of sand which then sandblast surfaces, moving water which causes abrasion etc.
What can a light source emit more than one of?
Answer:
What is Emission of Light? Atoms, molecules, or solids that are excited to high energy levels can decay to lower levels by emitting radiation (emission or luminescence). ... Atomic emission and molecular fluorescence are therefore useful for quantitating emitting species.
Explanation:
correct me if i am wrong
4. What are 3 things that you can think of doing, that would reduce
your electricity bill?
An 85.0-N crate of apples sits at rest on a ramp that runs from the ground to the bed of a truck. The ramp is inclined at 28.0° to the ground. A) The interaction partner of this normal force has what magnitude and direction? B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Answer:
A 75.1 N and a direction of 152° to the vertical.
B 85.0 N at 0° to the vertical.
Explanation:
A) The interaction partner of this normal force has what magnitude and direction?
The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).
B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.
Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.
So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.
Monochromatic light falling on two very narrow slits 0.048mm apart. Successive fringes on a screen 5.00m away are 6.5cm apart near the center of the pattern.What is the wavelength and frequency of the light?
Answer:
λ = 5.85 x 10⁻⁷ m = 585 nm
f = 5.13 x 10¹⁴ Hz
Explanation:
We will use Young's Double Slit Experiment's Formula here:
[tex]Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}[/tex]
where,
λ = wavelength = ?
Y = Fringe Spacing = 6.5 cm = 0.065 m
d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m
L = screen distance = 5 m
Therefore,
[tex]\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}[/tex]
λ = 5.85 x 10⁻⁷ m = 585 nm
Now, the frequency can be given as:
[tex]f = \frac{c}{\lambda}[/tex]
where,
f = frequency = ?
c = speed of light = 3 x 10⁸ m/s
Therefore,
[tex]f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\[/tex]
f = 5.13 x 10¹⁴ Hz
If there are 1,600 meters in a mile, find the speed of sound in this experiment in units of "miles / hour"
Answer:
v = 771.75 mile / h
Explanation:
The speed of sound is v = 343 m / s at T= 20C
the transformation ratios are
1 mile = 1600 m
1 h = 3600 s
Let's reduce
v = 343 m / s (1 mile / 1600 m) (3600 s / 1 h)
v = 771.75 mile / h
Homer Agin leads the Varsity team in home runs. In a recent game, Homer hit a 34.5 m/s sinking curve ball head on, sending it off his bat in the exact opposite direction at 23.9 m/s. The actually contact between ball and bat lasted for 0.00075 seconds. Determine the magnitude of the average acceleration of the ball during the contact with the bat in m/s/s. Do not include units or /- sign. Round your answer to a whole number.
Answer:
–77867 m/s/s.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 34.5 m/s
Final velocity (v) = –23.9 m/s
Time (t) = 0.00075 s
Acceleration (a) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:
Acceleration = (final velocity – Initial velocity) /time
a = (v – u) / t
With the above formula, we can obtain acceleration of the ball as follow:
Initial velocity (u) = 34.5 m/s
Final velocity (v) = –23.9 m/s
Time (t) = 0.00075 s
Acceleration (a) =?
a = (v – u) / t
a = (–23.9 – 34.5) / 0.00075
a = –58.4 / 0.00075
a = –77867 m/s/s
Thus, the acceleration of the ball is –77867 m/s/s.
I will mark you as brainliest
pls ans
a) Name the graph?
b) In first 2 s the object is said to be in ______________ motion.
(uniform motion / uniform acceleration)
c) The portion BC of the graph represents which type of motion?
d) Find out acceleration in first 2 s?
I don't know♀ what is your favorite song
A 8.25-N force is applied to a 2.50 kg object to accelerate it rightwards. The object
encounters 2.19 N of friction. Determine the acceleration of the object. (Neglect air
resistance.)
Answer:
Explanation:
Use F - f = ma since we are on a flat surface. We are given the applied Force as 8.25, the frictional force as 2.19, and a mass of 2.50. Filling in:
8.25 - 2.19 = 2.50a. Doing the subtraction on the left gives us:
6.06 = 2.50a and we divide to 3 sig figs to get
a = 2.42 m/s/s
Shane is riding his bike at a speed of 10m/s. He isn't watching carefully where he is going and almost hit a tree. He abruptly it's the brakes to stop in a time of 4 seconds. What is his acceleration show your work
(NO LINKS PLEASE)
Answer:
2.5m/s²
Explanation:
a = v/t
Where;
V = velocity (m/s)
a = acceleration (m/s²)
t = time (s).
According to the information provided in this question,
a = ?
v = 10m/s
t = 4
a = 10/4
a = 2.5m/s²
Charges of +3 µC and –5 µC are 2 mm from each other. The –5 µC charge is replaced with a +5 µC charge.
How will the electrical force between the charges compare with the original force?
same force, but in the opposite direction
same force, but in the same direction
greater force, but in the opposite direction
greater force, but in the same direction
Answer: same force in opposite direction.
Explanation: Charges of opposite sign attracts each other and charges with same sign repel each other. Because only sign of negative charge changes, and absolute value of charge remains same, value of force is same but is in opposite direction.
Answer:
A) same force, but in the opposite direction
Explanation:
he's right
can someone please help me answer this question ?
Answer:
b 60 N force
Explanation:
The change in the momentum is given by the force•distance from the attached point. We don't have any distance, but apparently, the stick forces are being applied in each quarter of the stick, so let's use fractions of 4 to solve it:
150 N:
150•1/4 = 37.5
30 N:
30•2/4 = 30•1/2 = 15
60 N:
60•3/4 = 45
40 N:
40•4/4 = 40•1 = 40
A 32.0 kg cart is at rest on a frictionless, horizontal surface. The cart experiences an unbalaced force, causing the cart to accelarate at a rate of +5 m/s2.
Calculate the time it takes for the cart to travel 200 meters.
Answer:
t = 8.94 s
Explanation:
We will use the second equation of motion to calculate the time taken by the cart:
[tex]s = v_it + \frac{1}{2} at^2[/tex]
where,
s = distance = 200 m
vi = initial speed = 0 m/s
t = time taken = ?
a = acceleration = 5 m/s²
Therefore,
[tex]200\ m = (0\ m/s)(t)+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(200\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{80\ s^s}[/tex]
t = 8.94 s
The magnetic field 0.100 m from a
wire is 4.20 x 10-5 T. What is the field
0.200 m from the wire (twice as far)?
[?] *10^[?]T
Answer:
Your answer is given below:
Explanation:
A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's
surface. Which of the following is closest the total kinetic energy gained by
the object as it falls?
A. 60. J
B. 590 J
C. 720 J
D. 1200 J
Given :
A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's
surface.
To Find :
The total kinetic energy gained by the object as it falls.
Solution :
Since, only conservative force i.e gravity is applied on the object.
So, its total energy is constant.
Total kinetic energy gained = Total potential energy gained
K.E = mgh ( Here, g is acceleration due to gravity = 9.8 m/s² )
K.E = 10 × 9.8 × 6 J
K.E = 588 J
Hence, this is the required solution.
The kinetic energy of an object is proportional to the product of its mass and the square of the velocity of the object.
The kinetic energy of the object is 588 J. Option B shows the kinetic energy of the object.
What is kinetic energy?The kinetic energy of an object is defined as the energy that it possesses due to the motion of the object.
Given that the mass m of the object is 10 kg and it falls from the height h of 6 meters near the earth's surface. The object falls vertically, so the gravitational acceleration is applied to it.
The potential energy of the object is given below.
[tex]PE = mgh[/tex]
[tex]PE = 10 \times 9.8 \times 6[/tex]
[tex]PE = 588 \;\rm J[/tex]
The total force applied to the object is due to gravity only. Hence the total energy of the object will be constant. Thus the kinetic energy of the object will be equivalent to the potential energy of the object.
Hence we can conclude that the kinetic energy of the object is 588 J. Option B shows the kinetic energy of the object.
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A 75 kg refrigerator is located on the 70th floor of skyscraper (300 meters above ground). What is the potential energy of the refrigerator. (PE=MGH(G=9.8M/S²)
Answer:
220,500 Joules
Explanation:
PE = (75 kg) x (9.8 [tex]m/s^{2}[/tex]) x (300 m)
PE = (735) x (300)
PE = 220,500 Joules
Answer:
googli moogli
Explanation:
A rocket blasts off from Earth with an initial
acceleration of 18.2 m/s2. A 75.0 kg astronaut
is inside. What is the normal force of the
astronaut's chair on the astronaut?
S
[?]N
Explanation:
apparent apparent weight is how hard astronaut pushes against it which is the normal force
n m a y + mgm open parenthesis y + and close parenthesis and = m open parenthesis a y + and so i need the acceleration of the astronaut since initial velocity is 0 and yby over l 45 m per second over 15 x 30.0 m m per second squared
it took 50 joules to push a shopping cart 5 meters.with what face was the shopping cart pushed?