A 45-mL sample of H-Cl with an unknown content was used to titrate Na-OH. One mole of phosphoric acid requires three moles of sodium hydroxide to neutralize it.
Three moles of sodium hydroxide are required for every mole of phosphoric acid. The balanced equation reveals the following: 1 mol of H3PO4 and 3 mol of NaOH react chemically. The balanced equation makes it abundantly evident that 2 moles of NaOH react with 1 mole of sulphuric acid to produce the desired products. Number of moles of solute/volume of solution in lit. = 2 moles of Na-OH are needed to thoroughly react with 1.00 mole of sulfuric acid. Therefore, 10g of Na-OH should be used to create a 500 mL 0.5 M solution.
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Methanol, CH3OH, dissolves completely in water to form a solution that does not conduct electricity. Which of the following diagrams best shows the major type of attractive force that exists between the particles in the solution?
C) [the diagram shows Methanol attracted to a water atom with a dashed line; the Oxygen atom from Methanol is attracted to a Hydrogen atom from water]
The diagram that best shows the major type of attractive force that exists between the particles in the solution is diagram B which shows hydrogen bonding.
The coreect ansdwer is B.
What is hydrogen bonding?Hydrogen bonding is a type of intermolecular bonding that occurs between hydrogen atoms that are bonded to strongly electronegative elements like oxygen, chlorine, fluorine, and nitrogen.
Due to the stronger attraction of the electronegative elements to the shared electron pair, the electronegative element acquires a partial negative charge while the hydrogen atom acquires a partial negative charge. This uneven charge distribution results in the atoms of hydrogen being attracted to the atoms of the electronegative elements of neighboring molecules, thus producing hydrogen bonding.
Hydrogen bonding exists in water as well as in methanol. The dissolution of methanol in water is due to the hydrogen bonds formed between the molecules
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including stereoisomers, write structural formulas for all of the compounds that are trichloro derivatives of a) cyclobutane
including stereoisomers, structural formulas for all of the compounds that are trichloro derivatives of cyclobutane Chiral derivates of trichlorocyclobutane are: \textbf{(1R,3R)-cis-[1,2]trans-[1,3]trans-[2,3]-trichlorocyclobutane}(1R,3R)-cis-[1,2]trans-[1,3]trans-[2,3]-trichlorocyclobutane
The organic compounds that can rotate the plane-polarized light either left or towards the right will consist of at least one
C atom that is attached to four different atoms or groups or having any symmetry elements can be called a chiral compound if not it is achiral.
Organic compounds that have one C atom with four different atoms attached, rotate plane polarised light, and have a symmetry element like a plane of symmetry, line of symmetry, or centre of symmetry are known as chiral compounds, whereas compounds without any symmetry element are known as achiral compounds. Light with a plane polarization is not rotated.
The image below shows the trichloro derivative of cyclobutane and cyclopentane, in which the molecules containing the C atom with the symbol * are chiral while the remaining molecules are achiral.
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Complete question
Including stereoisomers, write structural formulas for all of the compounds that are trichloro derivatives of (a) Cyclobutane (b) Cyclopentane Which are chiral? Which are achiral?
Why should the spring festival couplets paste？
Answer:
Explanation:
Sticking couplets is one of Chinese folk spring festival customs, it can increase the festive atmosphere, but also the inheritance of traditional culture. At the sight of spring festival couplets, we will all feel the strong flavor of the year. It is a unique form of Chinese literature, which depicts beautiful images and expresses good wishes with antithesis and neat, concise and exquisite writing. When people put up spring festival couplets on their doors, it means that the spring festival has officially kicked off.
A compound is found to contain 26.73 % phosphorus, 12.09 % nitrogen, and 61.18 % chlorine by mass. What is the molecular
formula for this compound
The Molecular formula for this compound would be [tex]N{6} Cl{12} P{6}[/tex]
What is Molecular formula?The molecular formula is described as an expression that defines the number of atoms of each element in one molecule of a compound
The first step is to find out how many grams of each element are in one mole of the compound.
We do this because we have the molar mass of the compound, as well as the percent mass of each element.
695g * 26.73% = 186g of Phosphorous/mol of compound.
695g * 12.09% = 84g of Nitrogen/mol of compound.
695g * 61.18% = 425g of Chlorine/mol of Compound.
Because we know how many grams of each element are present per mole of compound, we can use the molar masses of each element to find out how many moles of each element are present per mole of the compound.
186g P * (1mole P/30.1g) = 6 moles of Phosphorous.
84g N * (1mole N/14g) = 6 moles of Nitrogen.
425g Cl * (1mole/35g) = 12 moles of Chlorine.
Therefore, the molecular formula for this compound would be [tex]N{6} Cl{12} P{6}[/tex]
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You have two solutions of chemical A.To determine which has the highest concentration of in molarity, what the minimum number of the following you must know?
I. the mass in grams of A in each solution
II. the molar mass of A
Ill., the volume of water added to each solution
IV. the total volume of the solution
a. 3
b. 1
c. You must know all of them.
d. 0
e. 2
c. To determine which has the highest concentration in molarity you must know all of them.
To determine the molarity of a solution, you must know the mass in grams of A in each solution, the molar mass of A, the volume of water added to each solution, as well as the total volume of the solution.
Mass and molar mass gives you the moles of A in each solution, while the volume of water and total volume of the solution gives you the concentration of A in each solution. Therefore, you must know all four pieces of information to determine which solution has the highest concentration of A in molarity.
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Using the following standard reduction potentials,
Fe3+(aq) + e- →Fe2+(aq) E° = +0.77 V
Ni2+(aq) + 2 e- →Ni(s) E° = -0.23 V
calculate the standard cell potential for the galvanic cell reaction given below, and determine whether or not this reaction is spontaneous under standard conditions.
Ni2+(aq) + 2 Fe2+(aq) → 2 Fe3+(aq) + Ni(s)
a) E° = -1.00 V, spontaneous
b) E° = +1.00 V, nonspontaneous
c) E° = +1.00 V, spontaneous
d) E° = -1.00 V, nonspontaneous
d) E° = -1.00 V, nonspontaneous is the correct answer.
Regarding the specified chemical reaction:
[tex]Ni^{2+}(aq.) + 2Fe^{2+}(aq.)[/tex] → [tex]2Fe^{3+} (aq.) + Ni(s)[/tex]
In this case, iron is being oxidized because it is losing electrons, whereas nickel is being reduced because it is receiving electrons.
We know that:
[tex]E^{0}_{(Fe^{3+}/Fe^{2+})} = 0.77V[/tex]
[tex]E^{0}_{(Ni^{2+}/Ni)} = -0.23V[/tex]
The substance that is being oxidized acts as the cathode and the substance that is being reduced acts as the anode.
We use the equation to determine the reaction [tex]E^{0}_{cell}[/tex].
[tex]E^{0}_{cell} = E^{0}_{cathode} - E^{0}_{anode}[/tex]
[tex]E^{0}_{cell} = -0.23-0.77= -1.0 V[/tex]
The following shows how standard electrode potential and standard Gibbs free energy relate:
Δ[tex]G^{0} = -nFE^{0}_{cell}[/tex]
The standard electrode potential of the cell for the mentioned cell is negative. As a result, the reaction's standard Gibbs free energy change will become positive, making it non-spontaneous.
So, the mentioned response is non-spontaneous.
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how many centimeters are in an average hand ?
Answer:
On average, an adult male's hand is about 18-20 centimeters long, while an adult female's hand is usually a bit smaller, at around 16-18 centimeters.
Explanation:
It is difficult to give a precise answer to this question as the size of a person's hand can vary significantly depending on their age, gender, and overall body size. On average, an adult male's hand is about 18-20 centimeters long, while an adult female's hand is usually a bit smaller, at around 16-18 centimeters. Children's hands are also generally smaller than those of adults.
It is also worth noting that the size of a person's hand is not necessarily an accurate indicator of their overall body size or strength. Some people may have larger or smaller hands than others, but this does not necessarily mean that they are taller or shorter, or that they are more or less physically capable.
Adult hands are usually between 15.2 cm and 27.9 cm
wikihow
The normal melting point of acetic acid HC2H3O2 is 16.6 C. For the process of melting acetic acid at 1 atm what is the sign for each of the following . For each choose positive or negative or zero
a. delta H
b. delta S
c. delta G at 16.6 C
d. delta G at 0 C
e. delta G at 25 C
Answer:
Below
Explanation:
For the process of melting acetic acid at 1 atm, the sign for each of the following would be:
a. delta H - positive
b. delta S - positive
c. delta G at 16.6 C - zero
d. delta G at 0 C - positive
e. delta G at 25 C - positive