You are studying a biochemical pathway in the mold Neurospora where enzyme 1 converts the initial substrate into intermediate substrate A; enzyme 2 converts intermediate substrate A into intermediate substrate B; enzyme 3 converts intermediate substrate B into intermediate substrate C; and enzyme 4 converts intermediate substrate C into the end product, an amino acid that is essential for growth. You isolate a mutant that is unable to grow on minimal media. Which data would provide the strongest support for the hypothesis that this mutation occurred in the gene that codes for enzyme 2

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Answer 1

Complete question:

You are studying a biochemical pathway in the mold Neurospora where enzyme 1 converts the initial substrate into intermediate substrate A; enzyme 2 converts intermediate substrate A into intermediate substrate B; enzyme 3 converts intermediate substrate B into intermediate substrate C; and enzyme 4 converts intermediate substrate C into the end product, an amino acid that is essential for growth. You isolate a mutant that is unable to grow on minimal media. Which data would provide the strongest support for the hypothesis that this mutation occurred in the gene that codes for enzyme 2?

a. The mold can grow on rich medium plus intermediate substrate C, but not on rich medium plus intermediate substrate B.

b. The mold can grow on minimal medium plus intermediate substrate B, but not on minimal medium plus the initial substrate.

c. The mold can grow on minimal medium plus intermediate substrate B, but not on minimal medium plus intermediate substrate A.

d. The mold can grow on rich medium plus intermediate substrate D, but not on rich medium plus intermediate substrate C.

e. The mold can grow on minimal medium plus intermediate substrate A, but not on minimal medium plus intermediate substrate C.

Answer:

c. The mold can grow on minimal medium plus intermediate substrate B, but not on minimal medium plus intermediate substrate A.

Explanation:

Let us first diagram the pathway for a better understanding.

The normal organism produces four enzymes that convert substrates in the medium that allow it to survive, grow, and reproduce.  

initial substrate ------------> A ----------------> B ----------------> C ----------------> AA

                           Enzyme 1       Enzyme 2        Enzyme 3         Enzyme 4

Any mutation on the Neurospora´s enzymes will not let the organism grow on the minimal medium because it will not be able to convert the minimal substrate into the following one, because the mutated enzyme will not accomplish its original function.

So if the mutation occurs in enzyme 1, the organism will not be able to convert the initial substrate into intermediate substrate A. And the rest of the reaction will not be possible either because of the lack of substance A.

initial substrate -----X----> A -------X-----> B ------X--------> C ------X-------> AA

          mutated Enzyme 1      Enzyme 2       Enzyme 3        Enzyme 4

If the mutation occurs in enzyme 2, the organism will not be able to convert the intermediate substrate A into intermediate substrate B. And the rest of the reaction will not be possible either because of the lack of substance B.

initial substrate ------------> A -------X--------> B -------X------> C --------X-----> AA

                           Enzyme 1   mutated Enz. 2     Enzyme 3         Enzyme 4

If the mutation occurs in enzyme 3, the organism will not be able to convert the intermediate substrate B into intermediate substrate C. And the last reaction will not be possible either because of the lack of substance C.

initial substrate ------------> A ----------------> B -------X--------> C -------X------> AA

                           Enzyme 1       Enzyme 2     mutated Enz. 3     Enzyme 4

And if the mutation occurs in enzyme 4, the organism will not be able to convert the intermediate substrate C into the essential amino acid.

initial substrate ------------> A ----------------> B ----------------> C -------X-------> AA

                           Enzyme 1       Enzyme 2        Enzyme 3      Mutated Enz. 4

But, if we artificially add to the medium the substrate that should be produced by the original enzyme (and that is not converted because of the mutation), then the organism will grow and survive because the other enzymes will be able to produce the essential amino acid.

So, if enzyme 2 is the only enzyme mutated, the organism will not be able to live in a medium with substrate A because the mutated enzyme will not convert the substrate A into B. There will not be B substrate in the medium, and the other enzymes will not produce the essential amino acid. So if the mutation occurs in enzyme 2, substrate A is useless to the organism because it will not survive.

But if we add the intermediate substrate B to the medium, the organism will survive. In a medium with substrate B, all the other reactions will be possible, and the organism will get the essential amino acid. The artificial addition of B substrate will replace the function of the original enzyme 2 -which is the one that converts A into B-.


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The correct option is (e) i.e. the first two choices are correct. Most of the electrons removed from glucose by cellular respiration are used for the processes listed.

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All animal cells are diploid except

options:



gametes.



muscle cells.



nerve cells.



germ-line cells.



somatic cells.

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Except for gametes, all mammal cells are diploid.

With the exception of the gametes, almost all animal cells are diploid, however some are polyploid (three or more copies of each chromosome, often found in plants). The human genome has 46 diploid chromosomes, which is twice as many as the 23 haploid chromosomes found in human ova and sperm.

From the Greek term meaning "double," a cell or organism with two sets or copies (or homologs), typically one from each parent and so twice the number of haploids, of each somatic chromosome.

The right response is (a) gametes. In contrast to diploid cells, which have two sets of chromosomes, haploid cells only have one set.

Due to the fusing of two haploid gametes, all mammals are diploids genetically. The haploid gamete cells make sure that the amount of chromosomes or genetic material is constant from generation to generation.

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How does the DNA of the 2 sister chromatids of chromosomes compare?

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The genetic sequences of sister chromatids are identical. Sister chromatids occur only after the S (synthesis) phase, when the DNA is replicated in preparation for mitosis or meiosis.

A sister chromatid is a pair of identical copies (chromatids) generated by chromosomal DNA replication, with both copies connected together by a shared centromere.

To put it another way, a sister chromatid is 'one-half' of a duplicated chromosome. A dyad is a pair of sister chromatids.

Because both sisters are the result of semi-conservative DNA replication and so have the same DNA sequence, suitable criteria to identify sister chromatids are not clear.

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by learning to associate a squirt of water with an electric shock, sea snails demonstrate the process of

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By learning to associate a squirt of water with an electric shock, sea snails demonstrate the process of classical conditioning. Merry Christmas and I hope this helped!

Eukaryotic processing of the primary transcript includes __________.

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The main transcript is processed by eukaryotes by splicing out introns and adding a 5 cap and 3 poly-A tail.

The harder part comes first. Termination does not involve stem-loop structures. Three enzymes carry out transcription (RNA polymerases I, II and III).Transcription is more tightly regulated in prokaryotes. In eukaryotes, translation begins when mRNA leaves the nucleus and begins transcription inside the nucleus. RNA polymerase is directed to start producing RNA by a promoter site on the 5' side of the transcriptional start site. The RNA polymerase transcribes the sense (-) strand of the DNA template.

In eukaryotes, the original RNA transcript is converted into mRNA by a process called maturation.

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There are Six distinct levels of structural organization within the body.

The smallest components of matter, such as atoms and molecules, are taken into consideration by scientists while studying the chemical level of organisation. The elements, which include elements like hydrogen, oxygen, carbon, nitrogen, calcium, and iron, are the building blocks of all matter in the universe. Each of these unadulterated substances (elements) has an atom as its smallest unit. Subatomic particles like the proton, electron, and neutron are the building blocks of atoms. Molecules, like the ones found in water, proteins, and carbohydrates in living things, are made up of two or more atoms. All of the components of the human body are composed of molecules.

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The enzyme(s) called peptidases break(s) down the substrate called proteins.

Peptidases are the digestive enzymes that can break down the large proteins into smaller peptides or even single amino acids. This process is known as proteolysis. The enzyme is produced in the small intestine of the digestive system.

Proteins are the biomolecules made up of amino acid as the monomers. These are the functional forms of genes that are involved in every function of the body. The proteins are synthesized in the cytoplasm of the cell where ribosomes are present. Proteins are involved in functions like signaling, enzymatic, transport, etc.

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What are the 3 phases of the Calvin cycle and what happens during each phase?

Answers

Answer: The three phases are carbon fixation, reduction, and regeneration.

Explanation: In stage 1, the enzyme RuBisCO incorporates carbon dioxide into an organic molecule. In stage 2, The 3-PGA molecules created through carbon fixation are converted into molecules of simple sugar–glucose. This stage obtains energy from ATP and NADPH formed during the light-dependent reactions of photosynthesis. The organic molecule is reduced. In stage 3, RuBP, the molecule that starts the cycle, is regenerated so that the cycle can continue.

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