you are measuring a process, and you are given the following information: overall average: 131 population stdev: 5 sample size: 11 determine the upper control limit if your desired confidence interval is 99.73%. enter your answer to one decimal place. it's ok if you get a negative number; in that case, just enter the minus sign in front of it.

The minimum sample size required to estimate the mean duration time of TR classes is t distribution confidence interval.

The confidence interval is 75.0694 and 76.9306.

Given that

(a) This is t-distribution confidence interval because sample standard deviation is given and also sample size is less than 30.

(b)

CI for 95%

n 28

mean 76

value of 95% CI and df = 27 (using  table) 2.0518

std. dev. 2.4

SE = standard deviation/n² 0.45356

ME = t*SE 0.93062

Lower Limit = Mean - ME 75.06938

Upper Limit = Mean + ME 76.93062

95% CI (75.0694 , 76.9306 )

95% CI=75.0694 , 76.9306

(c)The 95% confidence interval estimate of the population mean is within 75.0694 and 76.9306 (lower bound and upper bound)

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when model building using the build-down method, you want to start with the complete 2nd-order model and build down to the most data model.

when working on a workbook which requires a team of people to work with you on the workbook, it is important you create transparency and also ensure you complete the workbook on time.

one very important way to complete the task on time is to share the workbook with your team so that they can input their own contributions towards the task, this practice ensures speedy completion of the task. and reduces the level of errors which might have occurred if you where working on it alone.

granting access to the workbook is a very good way to create trust and transparency.

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All polynomials of the form p(t) = a + bt2, where a and b are in sets is a subspace of Pn for an appropriate

Consider the following subsets of Pn given by

The 0 vector of V is in W.

- Given v,w in W then v+w is in W.

- Given v in W and a a real number, then av is in W.

So, for us to check if the three subsets are a subset of Pn, we must check the three criteria.

First property:

Hence the first criteria is not met. Then, W2 is not a subspace of Pn.

For W1 and W3, note that if a= 0, then we have p(t) =0, so the zero polynomial is in W1 and W3.

W1 and W3 are subspaces of Pn for n= 2

and W2 is not a subspace of Pn.  

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Answer: This comes out to be 0.1031.

Step-by-step explanation:

in this case, we are given that the rate of power cuts in the city is 3/day, so the rate parameter for our Poisson distribution is $\lambda=3$. We want to find the probability that there are at least 7 cuts but at most 4 cuts in a given day. This means we need to find the probability that $k=7$, $k=8$, $k=9$, ..., $k=4$. We can use the formula for the probability mass function to find the probability for each of these values of $k$ and add them together to get the total probability.

Answer:

x = 15

y = 4

Step-by-step explanation:

18/6 = x/5

3/1 = x/5

x = 15

12/y = 3/1

3y = 12

y = 4

A figure in the flag has rotational symmetry if the figure can be mapped onto itself by a rotation between 0° and 360° about the center of the figure.

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Answer: [tex]6^{\frac{1}{12} }[/tex]

Step-by-step explanation:

The probability that the largest of the three random variables is greater than the sum of the other two is:P(x1 > x2 + x3) = 1/4

The probability of an event occurring is equal to the number of favorable outcomes divided by the total number of outcomes. In this case, the total number of outcomes is 8, since each of the three random variables can take on any value between 0 and 1 independently. The favorable outcomes are those in which x1 is greater than the sum of the other two variables, which is 1/4 of the total number of outcomes. Therefore, the probability that the largest of the three random variables is greater than the sum of the other two is 1/4.

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Answer:

-15

Step-by-step explanation:

As per the concept of hypothesis, the value of p is 0.47 the value of the static hypothesis is 4.3893 and the statistical division when the alpha = 0.05 is 0.1085.

What is meant by hypotheses?

in math, hypotheses refers a an assumption, an idea that is proposed for the sake of argument so that it can be tested to see if it might be true.

Here we have given that, a movie production company is releasing a movie with the hopes of many viewers returning to see the movie in the theater for a 2nd time. The target is to have 40 million viewers and they want more than 40% of the viewers to return to see the movie again.

And they show the movie to a test audience of 140 people.

Of the test audience, 66 people said they would see it again.

And we have to determine, the p-value is, the p-value for the test statistic.

And the statistical division when the alpha = 0.05 and explain the managerial conclusion for this situation.

Based on the question, the null hypothesis is,

H0: P = 3

H1: P > 0.03

Here we know that they show the movie to a test audience of 140 people.

So, n = 140

Here the test audience, 66 people said they would see it again.

So, x = 66

Therefore, the value of p is,

=> 66/140 = 0.47

Then the test hypothesis is,

=> Z = (0.47 - 0.3) / √[(0.3(1 - 0.3))/140]

When we simplify this one, then we get,

=> Z = 4.3893

Therefore, value of the static hypothesis is 4.3893.

Then the p-value = 0.1085 at 5% level of significance.

Here, 0.1085 <  4.3893,

Therefore, the null hypothesis is not rejected.

Therefore, p-value  = 0.1085, and we will not reject the null hypothesis.

So, the value of the static hypothesis is greater than the null hypothesis and the value of p so the value of not rejects the null hypothesis.

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Yes, it is significant evidence of a difference between the age distribution of jurors and the countrywide age distribution.

No, there is no age bias in the selection of jurors.

P             Oi       Ei        ( Oi-Ei) ^2/Ei

0.421     399     421     1.149643705

0.229     231     229     0.017467249

0.157     158     157     0.006369427

0.193     193     193     1.870466321

  1         1000  1000    3.043946702

The above can be represented in graphs.

Now,

Ei = n × pi

TS = 3.04394672

From TS < value

Value (7.81472)

We fail to reject the null hypothesis at 5% value of significance

No, there is no age bias in the selection of jurors.

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Answer:

x = 5

Step-by-step explanation:

assuming you mean the slope of the line id undefined and passes through (5, 0 )

A line with an undefined slope is a vertical line parallel to the y- axis with equation

x = c ( c is the value of the x- coordinates the line passes through )

the line passes through (5, 0 ) with x- coordinate 5 , then

x = 5 ← equation of line

Answer:

Below

Step-by-step explanation:

For the boxes:

   the sum of all three angles = 180     for a triangle

     soooo :      28 +    x-4    + 2x = 180

then x = 52   via  algebra

The manny must do his signature on the deposit ticket in order to get deposited the cashback ticket.

What is cashback?

Cashback is a type of reward program offered by some retailers and online merchants that gives customers money back for making purchases. It is a way for retailers to reward customers for their loyalty and encourage them to keep coming back to their store. Cashback can be offered in the form of a fixed amount, a percentage of the purchase price, or a combination of both. Cashback rewards may be paid in cash or as credits to the customer's account, and they may be used to purchase additional items from the store or to offset future purchases.

When teller sees the deposit ticket he must have seen that it is not signed by manny hence he returned this to manny now manny just have to do one work that to sign that deposit ticket after that teller will accept that deposit ticket and manny will get his required cashback easily in his bank account

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Answer:

a edge

Step-by-step explanation:

The size of the sample after two hours with an initial population of 1000 and a growth rate of 11% is found to be 1246.

A pattern of data that exhibits larger increases over time, forming the curve of an exponential function, is said to exhibit exponential growth. The formula of continuous exponential growth is  P=P₀e^{rt} where P is the population after time t, P₀ is the initial population, and r is the growth rate.

Given P₀ is 1000 bacteria, r is 11% = 0.11, and t is 2 hours. Then, the size of the sample after two hours is,

[tex]\begin{aligned}P&=P_0e^{rt}\\&=1000e^{0.11\times2}\\&=1000e^{0.22}\\&=1000\times1.246\\&=1246\end{aligned}[/tex]

The answer is 1246.

The complete question is -

Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate parameter of 11% per hour. Suppose also that a sample culture of 1000 bacteria is obtained from this population. Find the size of the sample after two hours. Round your answer to the nearest integer.

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Treatment remains the same. Do not Reject.

Test Statistics:

[tex]f = \frac{\text{treatment}}{\text{error}} = 5.37[/tex]

Reject Null Hypothesis if [tex]f > f(a, a-1, N-a)[/tex]

Critical Value [tex]f(0.01, 3, 15) = 5.42 \text{ (From F Table)}[/tex]

[tex]\because 5.37 < 5.417[/tex]

We fail to Reject [tex]H0[/tex]

[tex]\therefore[/tex] Do not Reject.

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Answer:

All natural numbers

Step-by-step explanation:

I'm assuming that you mean 36-(n^2/n^2)

A natural number is a positive integer

n^2/n^2 is always 1 for natural numbers.

so 36-1=35 which is a natural number

The integral for the work required to pump the water out of a spout that rises 2 m above the tank is

w = ∫ lower power (-r) to upper power (r + h) 2pgl (h + r - x) [tex]\sqrt{r^{2} + x^{2} }[/tex]  dx

Integral

An integral in mathematics is either a numerical value equal to the area under the graph of a function for some interval or a new function, the derivative of which is the original function (indefinite integral).

Given that:

r = 2m

l = 5m

sinθ = [tex]\frac{x}{r}[/tex]

dv = 2l  [tex]\sqrt{r^{2} + x^{2} }[/tex]  dx

Let p be the density of water and g be the acceleration due to gravity.

dm = p dv

dw = dmg (h + r - x)

dw = pg (h + r - x) dx

dw = 2l pg  (h + r - x) [tex]\sqrt{r^{2} + x^{2} }[/tex]  dx

w = ∫dw

w = ∫ lower power (-r) to upper power (r + h) 2pgl (h + r - x) [tex]\sqrt{r^{2} + x^{2} }[/tex]  dx

Therefore, the integral for the work required to pump the water out of a spout that rises 2 m above the tank is

w = ∫ lower power (-r) to upper power (r + h) 2pgl (h + r - x) [tex]\sqrt{r^{2} + x^{2} }[/tex]  dx

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Answer:

1/9

Step-by-step explanation:

f(-1)=1/3(3)^-1

f(-1)=1/3(1/3)

f(-1)=1/9

Note that:

For 1) To compute the average rate (AR), divide the change in y-values by the change in x-values. That is:

AR = (5-2)/5-4)

= 3/1

= 3ft/sec.

For 2) we must use the same formula above:
(2-5)/(10-7)

= -1 ft/sec.

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Full Question:

See attached graph

The first four nonzero terms of the series for f(x) from the taylor series is F(x)=5/3-5/9(x-2)+5/27(x-2)²-5/81(x-2)³+....

Given that,

We have to get the first four nonzero terms of the series for f(x), centering at the specified value of a, use the definition of a Taylor series. (Separate your responses into a list using commas.)

f(x)=5/1+x and a=2

We know that,

Take

f(x)=5/1+x and a=2

f(2)=5/1+2=5/3

f'(x)=-5/(1+x)²         f'(2)=-5/(1+2)²=-5/9                  (differentiating)

f''(x)=10/(1+x)³        f''(2)=10/(1+2)³=10/27

f'''(x)=-30/(1+x)⁴     f'''(2)=-30/(1+2)⁴=-30/81=-10/27

Using the taylor series

F(x)=f(a)-(x-a)f'(a)+(x-a)²/2!f''(a)-(x-a)³/3!f'''(a)+....

F(x)=f(2)-(x-2)f'(2)+(x-2)²/2f''(2)-(x-2)³/3!f'''(2)+....

F(x)=5/3-(x-2)(5/9)+(x-2)²/2(10/27)-(x-2)³/6(-10/27)+....

F(x)=5/3-5/9(x-2)+5/27(x-2)²-5/81(x-2)³+....

Therefore, The first four nonzero terms of the series for f(x) from the taylor series is F(x)=5/3-5/9(x-2)+5/27(x-2)²-5/81(x-2)³+....

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The anwer of number of cups of raisins required for 12 recipes needing 223 cups of raisins each are 2676.

Multiplication operation will be required to find the number of cups of raisins. The expression to be formed for calculation is-

Total number of cups = number of recipes × number of cups for one recipe

Keep the values in formula to find the total number of cups

Total number of cups = 12 × 223

Performing multiplication on Right Hand Side of the equation

Total number of cups = 2676

Thus, 2676 cups are required for recipe.

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Answer:

The area of the wall is:

11520 inches²

Step-by-step explanation:

Area of a rectangle = high * long

Then:

Area = 96 inches * 120 inches

Area = 11520 inches²

The given integral is:

∫ ∫ ( x) ×(8 × (√ x)) dx dy

By changing the order in which we integrate with respect to the variables x and y, we can rewrite this integral as an iterative integral of the other five orders. The other five commands are:

a. ∫ ∫ (√ x) ×(8 × (√t x)) dy dx

b. ∫ ∫ (8 × (√ x)) × (√ x) dx dy

c. ∫ ∫ (8 × (√ x)) × (√ x) dy dx

d. ∫ ∫ (√ x) × (√x) dx (8 × y)

e. ∫ ∫ (√ x) × (√ x) (8 * y) dx

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Answer:    [tex]\displaystyle \frac{10}{3}\left(\frac{1}{3}\right)^{n-1}[/tex]

======================================================

Explanation:

a = 10/3 is the first term

r = 1/3 is the common ratio

Multiply each term by r = 1/3 to get the next term.

Example:

(10/3)*(1/3) = 10/9

We then plug those two items into the formula

[tex]a_n = a(r)^{n-1}[/tex]

to end up with the answer shown above.

The value of n is a positive integer.

Answer:

20.0°C

Step-by-step explanation:

To find the final temperature of the water after it has transferred thermal energy to the ice cube, we need to use the equation:

Q = cmΔT

where Q is the amount of thermal energy transferred, c is the specific heat capacity of the substance, m is the mass of the substance, and ΔT is the change in temperature.

In this case, we are given that Q = 4,200 J and m = 200 g. The specific heat capacity of water is 4.184 J/g°C.

Substituting these values into the equation gives us:

4,200 J = (4.184 J/g°C)(200 g)(ΔT)

Solving for ΔT gives us:

ΔT = 4,200 J / [(4.184 J/g°C)(200 g)] = 10°C

Since the initial temperature of the water was 10.0°C, the final temperature of the water is 10.0°C + 10°C = 20.0°C.

Therefore, the temperature of the water in the glass is 20.0°C after it has transferred 4,200 J of thermal energy to the ice cube.

The number of students and adult ticket sold are 988 and 758 respectively .

Students pay $2 per ticket and adults pay $5 per ticket. The stadium is filled to its capacity of 2000 but 254 of those seats are given free of charge to band members, pep squad members, and faculty members.

The total income from the sale of tickets for the current game is $5766.

The number of student and adult tickets that were sold can be calculated as follows:

let

x = number of student ticket sold

y = number of adult ticket sold

Hence, using equation,

Students pay $2 per ticket and adults pay $5 per ticket and the total total sale is 5766.

2x + 5y = 5766

The stadium is filled to its capacity of 2000 but 254 of those seats are given free. This means the actual number of people that paid for the seats is 2000 - 254 = 1746.

x + y = 2000 - 254

x + y = 1746

Combine the equation

2x + 5y = 5766

x + y = 1746

multiply equation(ii) by 2

2x + 5y = 5766

2x + 2y = 3492

subtract equation(ii) from equation(i)

3y = 2274

y = 2274 / 3

y = 758

x = 1746 - 758

x = 988

Therefore,

number of student tickets = 988

number of adult tickets = 758

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The multiplication that will give a value of 12✓6 from the numbers will be:

3✓2 × 4✓3

3 × 4✓6

It should be noted that addition, subtraction, multiplication, and division are all possible mathematical operations. As an illustration, the expression x + y has the terms x and y with an addition operator between them.

In this case, it should be noted that:

3✓2 × 4✓3 = 12✓6

3 × 4✓6 = 12✓6

It should be noted both scenarios highlight the given value of 12✓6.

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If a<0, then there is no x-null lines, the system has no equilibrium points.

If a=0, it has only one equilibrium points.

If a>0, the system has two equilibrium points.

Points are (-√a,0) and (√a,0)

The system changes from no fixed points to two fixed points when it increases through a=0.

a is a bifurcation point.

The Jawbian matrix,

                        J = [tex]\left[\begin{array}{ccc}2x&0\\-2xy&x^{2}-1\\\end{array}\right][/tex]

Now,

      J[0,0] = [tex]\left[\begin{array}{ccc}0&0\\0&-1\\\end{array}\right][/tex] =0

      J[-√a,0] = [tex]\left[\begin{array}{ccc}-2\sqrt{a} &0\\0&-a-1\\\end{array}\right][/tex] = 2a√a + 2√a

If a=0, then it will be a live equilibrium, one of the values are 0, For a>0, the point (-√a,0) is sink and (√a,0) is a saddle points.

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