Answer:
Its slope-intercept form
Step-by-step explanation:
The "Y" is the output the "M" is the slope, the "X" is the unknown input and the "B" equals the Y-intercept
Determine whether or not the given set is (a) open, (b) connected, and (c) simply-connected. 31. {(x, y) | 0
This set {(x, y) | 0 is (a) open, (b) connected, and (c) not simply-connected.
(a) Open: This set is open because all points within the set have a neighborhood that is also within the set.
(b) Connected: This set is connected because there is a path between any two points in the set that does not leave the set.
(c) Not simply-connected: This set is not simply-connected because it contains a hole in the center, which is not a simply-connected space.
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Find the volume of the composite solid (STEP BY STEP PLEASE) 15 POINTS
A man buys a car worth 850,000 rupees. He agrees to pay 350,000 rupees immediately and the balance amount in 60 equal monthly installments with 12% p.a. compounded monthly. What is the amount of the monthly installments?
Answer:
The monthly installment amount for this loan is approximately
142956.575 rupees.
Step-by-step explanation:
To determine the amount of the monthly installments, we need to calculate the total interest on the loan and add it to the principal amount. The total interest can be calculated using the formula for compound interest, which is:Total Interest = Principal x (1 + Interest Rate/Compound Frequency)^(Compound Frequency x Number of Years) - PrincipalIn this case, the principal is 850,000 rupees, the interest rate is 12% per year, the compound frequency is monthly (12/1), and the number of years is 5 (60/12). Plugging these values into the formula, we get:Total Interest = 850,000 x (1 + 0.12/12)^(12 x 5) - 850,000
= 850,000 x (1 + 0.01)^60 - 850,000
= 850,000 x 1.01^60 - 850,000
= 850,000 x 1.675837 - 850,000
= 850,000 x 0.675837
= 573569.45
To determine the monthly installment amount, we add the total interest to the principal and divide the result by the number of months in the loan period:Monthly Installment = (Principal + Total Interest) / Number of Months= (850000 + 573569.45) / 60
= 142956.575
Therefore, the monthly installment amount for this loan is approximately 142956.575 rupees.If you have any question let me know.
A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of $27. Option B is a commission rate of 10% on weekly sales. How much does she need to sell this week to earn the same amount with the two options?
Answer:
Step-by-step explanation:
To compare the two options, we need to determine how much the salesperson would earn under each option. Under Option A, the salesperson would earn [tex]40 hours * $27/hour = $ < < 40*27=1080 > > 1080.[/tex]
Under Option B, the salesperson would earn a commission of 10% on her weekly sales. Let S be the amount of sales needed for the two options to be equal. We can set up the following equation:
[tex]0.1S = $1080[/tex]
Solving for S, we get:
[tex]S = $1080 / 0.1= $ < < 1080/0.1=10800 > > 10,800[/tex]
Therefore, the salesperson would need to sell $10,800 worth of products in order to earn the same amount under Option B as she would under Option A.
What is the measure of
A. 116°
B. 25°
C. 62°
D. 54°
Answer:
62 degrees
Step-by-step explanation:
(3x-13)+(2x+4)+(180-116)=180
5x-9+64=180
5x+55=180
-55. -55
5x=125
/5. /5
x=25
3(25)-13
75-13
62
hopes this helps
Calculate the p-value for each of the given hypothesis test scenarios below. Round p-values to four decimal places. • Find the p-value for a left-tailed test of hypothesis for a mean when the test statistic has been calculated as -1.03. Assume the population standard deviation is known. p-value • Find the p-value for a right-tailed test of hypothesis for a mean when the test statistic has been calculated as 2.58. Assume the population standard deviation is known. p-value • Find the p-value for a two-tailed test of hypothesis for a proportion when the test statistic has been calculated as 1.91. p-value = Find the p-value for a two-tailed test of hypothesis for a proportion when the test statistic has been calculated as - 1.16. p-value =
The p-value of ay distribution given can be calculated using the formula P(Z < X) where X is any sample data.
To find the p-value for a left-tailed test of hypothesis for a mean when the test statistic has been calculated as -1.03, you can use the following formula:
p-value = P(Z < -1.03)
Where Z is the standard normal distribution. You can use a z-table or a calculator to find the probability that a standard normal random variable is less than -1.03. The resulting p-value will be the probability that the test statistic is as extreme or more extreme than the observed value, given that the null hypothesis is true.
To find the p-value for a right-tailed test of hypothesis for a mean when the test statistic has been calculated as 2.58, you can use the following formula:
p-value = P(Z > 2.58)
Where Z is the standard normal distribution. You can use a z-table or a calculator to find the probability that a standard normal random variable is greater than 2.58. The resulting p-value will be the probability that the test statistic is as extreme or more extreme than the observed value, given that the null hypothesis is true.
To find the p-value for a two-tailed test of hypothesis for a proportion when the test statistic has been calculated as 1.91, you can use the following formula:
p-value = 2 * P(Z > 1.91)
Where Z is the standard normal distribution. You can use a z-table or a calculator to find the probability that a standard normal random variable is greater than 1.91. The resulting p-value will be twice this probability, since the test is two-tailed and we need to consider both tails of the distribution.
To find the p-value for a two-tailed test of hypothesis for a proportion when the test statistic has been calculated as -1.16, you can use the following formula:
p-value = 2 * P(Z < -1.16)
Where Z is the standard normal distribution. You can use a z-table or a calculator to find the probability that a standard normal random variable is less than -1.16. The resulting p-value will be twice this probability, since the test is two-tailed and we need to consider both tails of the distribution.
Note that in all of these cases, you need to assume that the population standard deviation is known. If the population standard deviation is not known, you will need to use a different test statistic and a different approach to calculate the p-value.
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can someone help me figure out how to solve this problem?
Answer:
B) 7.077
Step-by-step explanation:
From the problem, n = 24
Since n is the number of term.
Just input n into the equation.
[tex]a_n= \frac{n^{2}-n}{4n-18}\\[/tex]
[tex]= \frac{24^{2}-24}{4(24)-18}\\[/tex]
[tex]= 7.0769...[/tex]
≈ [tex]7.077[/tex]
4) Describe the continuity or discontinuity of the graphed function.
GIVING BRAINLIEST & 30 POINTS!
(please do the math and don't use other sources I know answering this question means nothing to you other than points but just think about me and others who might get the question wrong if you other sources.) Ty!
−np − 5 = 4(c − 2)
Which of the following solves for n?
n = the quantity 4 times c minus 3 all over negative p
n = the quantity 4 times c minus 13 all over negative p
n = the quantity 4 times c plus 3 all over p
n = the quantity 4 times c plus 13 all over p
Answer:
n = the quantity 4 times c minus 3 all over negative p
Explanation:
Interpretation of answers to equation
n = the quantity 4 times c minus 3 all over negative p = [tex]\frac{4c-3}{-p}[/tex]
n = the quantity 4 times c minus 13 all over negative p = [tex]\frac{4c-13}{-p}[/tex]
n = the quantity 4 times c plus 3 all over p = [tex]\frac{4c+3}{p}[/tex]
n = the quantity 4 times c plus 13 all over p = [tex]\frac{4c+13}{p}[/tex]
Step-by-step:
[tex]-np-5=4(c-2)[/tex]
[tex]-np-5=4c-4(2)[/tex]
[tex]-np-5=4c-8[/tex]
[tex]-np-5+5=4c-8+5[/tex]
[tex]-np=4c-3[/tex]
Divide both side by -p
[tex]n=\frac{4c-3}{-p}[/tex]
n = the quantity 4 times c minus 3 all over negative p
Answer:
The answer is the option A, which is: A.) n ≥ − the quantity 4 times c minus 3 all over p.
Step-by-step explanation:
You have −np − 5 ≤ 4(c − 2)
When you solve for n, you obtain:
-np-5 ≤ 4(c-2)
-np≤4c-8+5
Therefore, you have:
n≤-(4c-3/p)
Hope it helps :) make me as Brainlest! Or Expert-Verified Answer!
Solve for the missing side. Round to the nearest tenth (one decimal place): #2
The value of x is 17.8.
What are trigonometric identities?There are three commonly used trigonometric identities.
Sin x = 1/ cosec x
Cos x = 1/ sec x
Tan x = 1/ cot x or sin x / cos x
Cot x = cos x / sin x
We have,
Right-angled triangle.
Cos 27° = x / 20
x = 20 x Cos 27°
x = 20 x 0.89
x = 17.8
Thus,
x is 17.8.
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A dolphin dives down into the ocean and resurfaces along a path that is modeled by x2 – 16x – 8y = 0, where the distances are in feet. How many feet is the dolphin from its starting point along the water's surface? (5 points)
Answer:
approx 17 ft
Step-by-step explanation:
You need to find the 'zeroes' of this equation......where the depth is zero
x^2 - 16x - 8 = 0 You will need to use the Quadratic Formula
with a = 1 b= -16 c = -8
to find x = 8 +- 6 sqrt 2
the distance between these zeroes is 12 sqrt2 = 16.97 = ~ 17 feet
A circular pond has a pole standing vertically at its centre. The top of the pole is
30 m above the water surface and the angle of elevation of it from a point on the
circumference is 60°. Find the length of radius of the pond.
Answer:
10[tex]\sqrt{3}[/tex]
Step-by-step explanation:
assumed the radius of the pond was r
∴tan60°=[tex]\sqrt{3}[/tex]= [tex]\frac{30}{r}[/tex]
∴r=[tex]10\sqrt{3}[/tex]
The length of radius of the pond will be 108.76 metres.
Given the values we have,
length of the pole = 30 metres
the angle of elevation of the pole from a point on the circumference = 60°
From this information, we get a right-angled triangle with a perpendicular of 30 m and a base angle of 60°
Therefore we can say that the radius of the pond will be the base of the triangle.
Let the radius of the pond be r
Using the trigonometric ratio of tan, we get,
[tex]tan \alpha = \frac{perpendicular}{base}[/tex]
[tex]tan 60 = \frac{30}{r}[/tex]
The value of tan 60° is [tex]\sqrt{3}[/tex]
[tex]\sqrt{3}=\frac{30}{r}[/tex]
[tex]r= \frac{30}{\sqrt{3}}[/tex]
[tex]r = 17.32[/tex] metres
Therefore the base of the triangle or the radius of the pond is 17.32 metres.
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Find the volume of the composite solid (STEP BY STEP PLEASE) 25 POINTS
The volume of the composite solid is 5770.28ft³
How to determine the volume of the solid?The composite solid is made up of a cylinder and a hemisphere
The volume is the addition of the two solids
Volume=[tex]\pi[/tex]r²h +2/3πr²
The given parameters are
π=22/7
h=22 ft
r=9 ft
Input the values to get
(22/7*9*9*22) + (2/3*22/7*9*9)
Simplifying the terms to get
5600.57+169.71
The volume is = 5770.28c
ft³
In conclusion, the volume of the solid is 5,770.28ft³
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Roll a fair die twice. Let A be the even that the sum of the two rolls equals six, and let B be the even that the same number comes up twice. What is P(A/B)?
The value of P(A/B) will be = 1/4
As per the question,
As a fair six-sided die is rolled twice
So, the total number of outcomes will be N=6^2=36
A: sum of the two rolls is 5
[tex]$$\begin{aligned}& A=\{(1,4),(2,3),(3,2),(4,1)\} \\& n(A)=4 \\& P(A)=\frac{n(A)}{N}=\frac{4}{36}\end{aligned}$$[/tex]
B: The first roll results in a 2
[tex]B=\{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)\}$ \\$n(B)=6$ \\$P(B)=\frac{n(B)}{N}=\frac{6}{36}$ \\$B \cap A=\{(2,3)\}$ \\$\cap(B \cap A)=1$ \\$P(B \cap A)=\frac{n(B \cap A)}{N}=\frac{1}{36}$\\$P(B \mid A)=\frac{P(B \cap A)}{P(A)}=\frac{1 / 36}{4 / 36}=\frac{1}{36} \times \frac{36}{4}$$P(B \mid A)=\frac{1}{4}$[/tex]
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let y1 and y2 are independent random variables that are both uniformly distributed on the interval (0,1). find p(y1 <1
the probability of y1 being less than 1 is 1, regardless of the actual value of y1. P(y1 < 1) = 1
Since y1 and y2 are both uniformly distributed on the interval (0,1), this means that all possible values of y1 and y2 are equally likely. Therefore, the probability of y1 being less than 1 is 1, since any value of y1 between 0 and 1 has the same probability of occurring. This means that the probability of y1 being less than 1 is 1.
Since y1 and y2 are both uniformly distributed on the interval (0,1), this means that all possible values of y1 and y2 between 0 and 1 are equally likely to occur. This means that the probability of y1 being less than 1 is the same as the probability of y1 being equal to any value between 0 and 1. Since this probability is the same for all possible values of y1, the probability of y1 being less than 1 is 1, regardless of the actual value of y1. This is because any value of y1 between 0 and 1 has the same probability of occurring, meaning that the probability of y1 being less than 1 is 1.
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The weight of a medium-size orange selected at random from a large bin of oranges at the local supermarket is a random variable with mean u = 12 ounces and standard deviation 0 = 1.2 ounces. Suppose we independently pick two oranges at random from the bin. The expected value of the sum of the weights of the two oranges, in pounds (1 pound = 16 ounces) is: a. 24. b. 1.5. c. 0.75. 24/16 = 1.5 lb. 4 4
Therefore, the probability that the probability that the difference in the weights of the two oranges exceeds 3 ounces is 0.0385 .
Describe probability.The study of numerical estimates of the likelihood that an event will occur or that a proposition is true is known as probability. The probability of an occurrence is a number between 0 and 1, where 0 often indicates that the event is impossible and 1 typically indicates that it will happen.
Here,
Let X1 and X2 represent the weights of the two oranges.
Let d=X1 - X2 represent the difference in weight.
We're given that
X1 ~ N(12, 1.2^2)
X2 ~ N(12, 1.2^2)
Then,
Then, d N(12-12, 1.22 +1.22) or N (0, 21.22)
So the standard deviation of this √2.1.22 = 1.6971
Let's find
=> P(d>3)
=> 1-(1891)
=> 1-0.9615 = 0.0385
Therefore the probability that the probability that the difference in the weights of the two oranges exceeds 3 ounces is 0.0385 .
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Find f’ (x)
f(x)=7x^e - 5e^x
Answer:
[tex]f'(x)=7ex^{e-1}-5e^x[/tex]
Step-by-step explanation:
Differentiation rules
[tex]\boxed{\begin{minipage}{4.8 cm}\underline{Differentiating $ax^n$}\\\\If $y=ax^n$, then $\dfrac{\text{d}y}{\text{d}x}=nax^{n-1}$\\\end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{4.8 cm}\underline{Differentiating $e^{x}$}\\\\If $y=e^{x}$, then $\dfrac{\text{d}y}{\text{d}x}=e^x$\\\end{minipage}}[/tex]
Given function:
[tex]f(x)=7x^e-5e^x[/tex]
Differentiate with respect to x using the differentiation rules:
[tex]\implies f'(x)=e \cdot 7x^{e-1}-5e^x[/tex]
[tex]\implies f'(x)=7ex^{e-1}-5e^x[/tex]
G(x)=3x^2-2 find the expression for f(x)
PROOF Complete the flow proof to prove that if MN = PQ, MN = 5x - 10, and
PQ = 4x + 10, then MN = 90.
PQ,MN=5x-10 , and PQ=4x+10 , then MN=90. x-10=10 this equation is proved.
What is congruent addition?Congruent Addition is the Substitution segments to have the Property of Equality Given equally lengths; Substitutions Property's of Equality.
As per the given question
MN≈PQ
MN = 5x-10
And PQ=4x+10
Congruent segment have equal lengths:; Substitution property of equality
MN=PQ
5x-10 = 4x+10
Substitution property of equality
X-10=10
Addition property of equality
X=20
Substitution property of equality
MN= 5(20)-10
MN= 90
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WRLD ...Need Help....999
Lillian has a rectangular garden with an area of 10x2 +33x – 7 square feet. Find the expressions that would represent the length and width of the garden. Make sure you show all your work for full credit.
The expressions representing the length and width of the garden is (5x-1)(2x+7)
What are expression?An expression in maths is a sentence with a minimum of two numbers or variables and at least one maths operation.
Given that, Lillian has a rectangular garden with an area of 10x²+33x-7 square feet.
To find the expressions that would represent the length and width of the garden, we will factorize the expression representing the area of the garden,
10x²+33x-7
= 10x²+35x-2x-7
= 5x(2x+7)-1(2x+7)
= (5x-1)(2x+7)
Hence, The expressions representing the length and width of the garden is (5x-1)(2x+7)
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suppose that you want to describe the relationship between operating cost per hour and number of passenger
The operating cost per hour of a plane increases with the number of passengers it carries. More passengers require more fuel, maintenance, and staff, which all increase the overall cost of operating the plane per hour.
Additionally, if the plane is larger and designed to carry more passengers, the operating cost per hour may be higher than for smaller planes.The cost of operating an aircraft per hour is directly related to the number of passengers it carries. As the number of passengers increases, so too does the amount of fuel, maintenance, and personnel needed to safely operate the plane, resulting in a higher operating cost per hour. Additionally, larger planes that can carry more passengers also tend to have higher operating costs per hour than smaller planes.
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Find the value of x:
a)
b)
The value of x in first part = 16
The value of x in second part = 10
Part a
The angle U = angle Z = 54 degrees
Angle V = angle Y = 67 degrees
Therefore angle W = angle X
The sum of the angles in a triangle is 180 degrees
Then, the equation will be
54 + 67 + a = 180
121 + a = 180
a = 180 - 121
a = 59 degrees
Then
4x - 5 = 59
4x = 59 + 5
4x = 64
x = 64/4
x = 16
Part 2
Similarly the unknown angle as b
Sum of the the angles in a triangle is 180 degrees
58 + 74 + b = 180
132 + b = 180
b = 180 - 132
b = 48 degrees
Then the equation will be
5x - 2 = 48
5x = 48 + 2
5x = 50
x = 50/5
x = 10
Therefore, the value of x in the part a and part b are 16 and 10 respectively
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The number 21 is 3.5% of what?
Answer:
The number 21 is 3.5% of 600---------------------------
Let the number be x.
Set equation for x and solve:
3.5% of x is 21x*3.5/100 = 21x = 21*100/3.5x = 600what is 1/9 divided by 7
1/63.
Step-by-step explanation:1. Write the expression.[tex]\frac{\frac{1}{9} }{7}[/tex]
2. Apply the fraction rules.Check the attached image below.
[tex]\frac{1}{9}*\frac{1}{7}[/tex]
3. Simplify.[tex]\frac{1}{9}*\frac{1}{7}=\\\\ \frac{1*1}{9*7} =\\\\ \frac{1}{63}[/tex]
4. Conclude.[tex]\frac{\frac{1}{9} }{7}=\frac{1}{63}[/tex]
It’s number 14 btw, I swear this homework stresses me out so much
Answer:
m∠WYZ = 23°
Step-by-step explanation:
3x-8=14 need help asap
[tex]3x-8=14[/tex]
Add 8 to both sides:
[tex]3x-8+8=14+8[/tex]
[tex]3x=22[/tex]
Divide both sides by 3:
[tex]\dfrac{3x}{3} =\dfrac{22}{3}[/tex]
[tex]\fbox{x = $\dfrac{22}{3} $ or 7.333333}[/tex]
An instructor has given a short quiz consisting of two parts. For a randomly selected student, let X = the number of points earned on the first part and Y = the number of points earned on the second part. The accompanying table shows the number of students who obtained the indicated points for X (rows) and Y (column). The class is composed of 100 students. Y 10 15 6 2 10 15 20 10 10 1 15 14 1 Compute the correlation between the scores of students from the two parts of the quiz.
As per the concept of covariance, the correlation between the scores of students from the two parts of the quiz is 9.6
What is meant by covariance and correlation?
In math, the covariance is a measure of the linear relationship between two random variables where as the correlation is used to measure the linear relationship between two random variables if it is zero then variables are said to be uncorrelated and if one then perfectly correlated.
Here we have given that, instructor has given a short quiz consisting of two parts and the accompanying table shows the number of students who obtained the indicated points for X (rows) and Y (column).
And we need to find the the correlation between the scores of students from the two parts of the quiz.
Let us consider X refers the number of points earned on the first part and Y refers the number of points earned on the second part.
=> E(max(a, x)) = ∑ₐ∑ₓ y max(x, y)p(x, y)
And then when we apply the values on it, then we get,
=> max(0, 0)p(0, 0)+max(0, 5)p(0, 5)+· · ·+max(10, 10)p(10, 10)+max(10, 15)p(10, 15)
When we simplify this one, then we get,
=> 0 ∗ 0.02 + 5 ∗ 0.06 + · · · + 10 ∗ 0.14 + 15 ∗ 0.01 = 9.6.
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two coins are simultaneously tossed until one of them comes up a head and the other a tail. the first coin comes up a head with probability p and the second with probability q. all tosses are assumed independent
(a) Find the PMF, the expected value, and the variance of the number of tosses. P(X=k)=(1−p(1−q)−q(1−p))k−1(p(1−q)+q(1−p)), k=1,2...
And the above is clear for me. Now, we would like determine expected value:
The expected value of the number of tosses is given by:E(X) = E(X) = 1/pq.PMF is (1 - p)(1 - q)^(n-1) for n ≥ 1
We can calculate the expected value of the number of tosses by taking the summation of the PMF from k=1 to k=∞ multiplied by k. The PMF for the number of tosses is given by P(X=k)=(1−p(1−q)−q(1−p))k−1(p(1−q)+q(1−p)). We can then use this to calculate the expected value as (1-p(1-q)-q(1-p))/[p(1-q)+q(1-p)]. For the variance, we can use the formula Var(X) = E(X2) - E(X)2. We can calculate the E(X2) part using the same PMF multiplied by k2 and then subtract the expected value squared from it. The final result is (1-p(1-q)-q(1-p))/[(p(1-q)+q(1-p))^2].
PMF:
Let X be the number of tosses
P(X = n) = (1 - p)(1 - q)^(n-1) for n ≥ 1
Expected Value:
E(X) = 1/pq
Variance:
Var(X) = (1 - pq)/(pq)^2
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If the system of the linear equations above has infinitely many solutions, and c is a constant, what is the value of c?
A) - 6
B) - 3
C) - 2
D) - 1
Option D is the correct answer. The value of 'c' for the given system of linear equations with infinitely many solutions is - 1.
A linear equation is an equation in which the highest power of the variable is always 1 and the equations are the equations of degree 1. It is the equation for the straight line.
The standard form of the linear equation is ax+by+c =0
where a ≠ 0 and b ≠ 0.
Given a system of linear equations are
1. 3x-9y=-6
⇒ x-3y=-2
Therefore,
a1=1, b1=-3, c1=-2
2. [tex]\frac{x}{2} -\frac{3y}{2} =c\\[/tex]
⇒ x-3y=2c
Therefore,
a2=1, b2=-3, c2=2
For the system of linear equations with infinitely many solutions,
compare c1=c2
2c=-2
⇒ c=-1
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The students in a gym class measured the length of their longest jump (in feet). The results were tallied and are reported in the following histogram. How many students jumped greater than 8.5 but less than 11.5 feet?
On solving the provided question we can say that, Number of students jumped greater than 8.5 but less than 11.5 is 7 students.
What is frequency?the frequency or reality that something occurs frequently or a great number of times within a specific time frame. The frequency of buses, for instance, has been the subject of more complaints in recent months.
Number of students jumped greater than 8.5 but less than 11.5= frequency of length of jump greater than 8.5 but less than 11.5
AND,
frequency of length of jump greater than 8.5 but less than 11.5 is -
Number of students jumped greater than 8.5 and less than 9.5 + Number of students jumped greater than 9.5 but less than 10.5 + Number of students jumped greater than 10.5 but less than 11.5=
3+3+1=7 ( since, sum of respective frequencies of the three class)
so, Number of students jumped greater than 8.5 but less than 11.5 is 7 students.
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